a sustained measured exposure dose of 280 msv/hr was measured 100 m from a source. the evacuation zone was set at 35 km from the source. estimate the exposure rate at 35 km from the source.

Answer:

1.8m/s2

Explanation:

force=mass x acceleration

so,

acceleration=force /mass

=45/25

=1.8

The effect of weather and climate on the picture is erosion. The 3 potential solutions to the erosion are Planting of a cover crop, Build Terraces, and Create diversions to Help Drainage.

Erosion is defined as the washing away of the topmost portion of the soil which can occur due to natural causes or through the activities of man.

The natural causes of erosion is related to changes in weather and climate through rain, rivers, floods, lakes, and the ocean.

The three potential solutions to the problem of erosion include the following:

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Answer:

Fossil fuels store energy from the sun as

Explanation:

Answer:

Yes

Explanation:

Since an ammeter is meant to measure current and is a low resistance device, it is always connected in series with the circuit element through which current is to be measured.

Current of a system is defined as the rate at which the electrons flow from a given point in the absolute electrical circuit.

a. Since, Current in two or more components connected in series is always the same. So circuit (a) will be used.

b. As per manufacturer's claim, resistance of bulb r = V /I.

= 12 /6 = 2 Ω.

Total resistance in circuit a,  R = 2 +0.1 = 2.1 A

Ammeter reading I' = V /R

= 12 /2.1 = 5.71 A

Which is close enough to claimed value of 6 A.

c. Now the bulb and ammeter are connected in parallel, so the voltage across both will be the same.

Current through ammeter I' = V /Ra = 12 /0.1 = 120 A

Which is 20 times greater than claimed value.

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The question is incomplete, but most probably the complete question is,

The manufacturer of a 12V car headlight specifies it will draw a current of 6A. You would like to check this claim with an ammeter designed to measure currents up to 10Aand having a resistance of 0.1 Ohms.

a)Which of the two figures represents a circuit where the ammeter correctly measures the current in the headlight?

b) How much current (in A) would flow in the ammeter for Circuit a?

c) How much current (in A) flows through the ammeter for Circuit b?

Explanation: Research highlights the individuals with ASDS are nutritionally vulnerable because they exhibit a selective or pick eating pattern and sensory sensitivity that predisposes them to restricted intakes.

I hope this helps!

Answer:

According to Newton's Second Law of Motion :    

Where,

F = Force Applied

m = Mass of the object

a = Acceleration

Now, we will use this law to solve this question.

Given :

Acceleration or a = 15.3 m/s²

Force = 44 N

Mass = ?

Substitute, the given values in the formula.

F = ma

⇒ m = F/a

   m = 44/15.3

m = 2.9 kg

Answer:

7.0 n

Explanation:

Answer:

direction should be the answer

Answer:

B. Gravity

Explanation:

Earth pulling on an object is known as gravity.

Answer:

Good conducters of heat and electricity. High melting points. high density. malleable. Ductile.

Explanation:

Answer:

hhmmmmmhmmmm hmhmmmm hmmm yeah i got nothing

Explanation:

Answer:t would be 17 m/s

If we use V2 = V1 + a*t

Sub in 5 for v1

2m/s*2 for a

And

6 for t

That should give you the answer.

Answer: Friction

Explanation:

Answer:

The first law is an object won’t change its place unless a force hits it

The second law is the force on an object equivalent to the mass times its acceleration

The third law is when two object meet, they both apply forces on each other making them go in opposite directions

Explanation:

The Bessel lowpass filter is a filter that has a transfer function of H(s) = 3/(s² + 3s + 3). In this problem, we are going to use the bilinear transform to convert this analog filter into a digital filter, H(z), with a sampling rate of 2 Hz.

A digital filter is obtained from an analog filter by replacing 's' with the appropriate expression in 'z' which is given by the bilinear transformation. We'll use the following bilinear transformation formula:z = (2/T)(1-sqrt(1-T²s²/4))where T = 1/fS is the sampling period and fS is the sampling frequency.

Substituting the expression for z into the transfer function of H(s), we get:H(s) = 3/(s² + 3s + 3)  ----> H(z) = 3/(1 + 1.5(1-z⁻¹)/(1+z⁻¹) + 0.5(1-z⁻¹)²/(1+z⁻¹)²)Therefore, the digital filter is given by the transfer function:H(z) = 3/(1 + 1.5(1-z⁻¹)/(1+z⁻¹) + 0.5(1-z⁻¹)²/(1+z⁻¹)²).

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Answer:

Explanation:

Newton's 2nd Law say that F = ma which is the sum of the forces acting on an object is equal to the object's mass times the acceleration at which it is moving. That means that the forces acting on this tree are F which is the Force the man needs to exert to move the tree, and f which is the force the tree is exerting in an effort to stay right where it is. That alters our 2nd Law equation to F - f = ma. BUT if the tree isn't moving, the acceleration is 0, making the whole right side of that equation go to 0. That means that F = f. Phew! Let's do that.

f = μ\(F_n\) where f is the frictional force, μ is the coefficient of static friction, and \(F_n\) is the weight of the object, which are given as 670 N. Filling in:

f = .5(670) so

f = 335 N (that is not using the rules of significant digits properly, but if you use them properly, the answer is not one of the choices, so...)

C is the one you want.

The final image is formed 30.0 cm (or 0.3 m) from the opposite end of the tube, where two thin lenses with 10.0-cm focal lengths are mounted at opposite ends of a 30.0-cm long tube and an object is located 45.0 cm from one end of the tube.

To solve this problem, we need to find the position of the final image using the lens formula and the given information. The lens formula is:

1/f = 1/do + 1/di

Where f is the focal length, do is the object distance, and di is the image distance. Since there are two lenses, we'll have to use this formula twice.

For the first lens (f1 = 10.0 cm), the object is located 45.0 cm away (do1 = 45.0 cm). Using the lens formula:

1/10 = 1/45 + 1/di1
Solving for di1, we get di1 = 18.0 cm.

Now, the second lens (f2 = 10.0 cm) is mounted at the opposite end of the 30.0 cm long tube, so the distance between the lenses is 30.0 cm. Since the image distance of the first lens is 18.0 cm, the object distance for the second lens (do2) is 30.0 - 18.0 = 12.0 cm.

Using the lens formula for the second lens:

1/10 = 1/12 + 1/di2
Solving for di2, we get di2 = 60.0 cm.

The final image is 60.0 cm from the second lens, which is at the opposite end of the 30.0 cm tube. Therefore, the final image is 60.0 - 30.0 = 30.0 cm from the opposite end of the tube.

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The simple evaluation technique of VT is based on the idea that threshold voltage (VT) is equal to the gate voltage at which the inversion layer charge density is zero.

Explanation:

The simple evaluation technique of VT is based on the idea that threshold voltage (VT) is equal to the gate voltage at which the inversion layer charge density is zero. When measuring the threshold voltage of a PMOS device using the VTP method, a positive voltage is applied to the drain terminal and a negative voltage is applied to the source terminal. This causes the transistor to be turned off since the body is positively biased and the PMOS channel will not conduct current. A negative voltage is then applied to the gate, which is gradually increased.

The device is turned on when the threshold voltage is reached, and the inversion layer charge density is no longer zero. Therefore, the gate voltage at which the device is turned on is equal to the threshold voltage (VT). Thus, the VTP measurement technique for PMOS devices is based on the simple evaluation technique of VT, which is the gate voltage at which the inversion layer charge density is zero.

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Answer:   The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground ... hope this helps have a good day :P

The angular momentum of the satellite remains constant at the labeled locations (A, B, C, D).

How do quantities change in orbit?

Let's analyze the quantities that remain constant at the labeled locations (A, B, C, D):

A. The tidal force on the satellite: This force depends on the gravitational gradient and the satellite's position relative to the primary. Since the position changes along the elliptical orbit, the tidal force is not constant. Therefore, it does not remain constant at any labeled location.

B. The kinetic energy of the satellite: The kinetic energy of the satellite changes as it moves along its elliptical orbit. It is highest at the perigee (closest point to the primary) and lowest at the apogee (farthest point from the primary). Therefore, it does not remain constant at any labeled location.

C. The mechanical energy of the satellite: The mechanical energy of the satellite is the sum of its kinetic energy and gravitational potential energy. Since both of these quantities change along the elliptical orbit, the mechanical energy is not constant at any labeled location.

D. The work done by the force of gravitational attraction on the satellite: The work done by the force of gravitational attraction is given by the change in gravitational potential energy. As the satellite moves along its elliptical orbit, the distance from the primary changes, causing the gravitational potential energy to vary.

Therefore, the work done by the force of gravitational attraction is not constant at any labeled location.

E. The angular momentum of the satellite: The angular momentum of the satellite remains constant throughout its motion if no external torques act upon it. This is known as the conservation of angular momentum. Therefore, the angular momentum remains constant at all labeled locations (A, B, C, D).

F. The gravitational potential energy of the satellite: The gravitational potential energy of the satellite changes as it moves along its elliptical orbit. It is highest at the apogee and lowest at the perigee. Therefore, it does not remain constant at any labeled location.

In summary, the quantities that remain constant at the labeled locations (A, B, C, D) are:

The angular momentum of the satellite.

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The term that best describes the landform "dip in a mountain range" is C. Syncline.

Syncline is a term to refer to a fold of the Earth's crust caused by the tectonic effects of the earth's dynamics. A synclinal fold is characterized by being a concave fold, that is, in the shape of a U.

According to the above, answers A, B and D are not correct options because they refer to different shapes of the Earth. Therefore, the landform shown is syncline.

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Answer: C

Explanation: E2022

The three basic types of three-phase motors are :

1. Synchronous Motors

2. Induction Motors

3. Brushless DC Motors

Explanation:

Synchronous Motors: These motors rotate at a constant speed that is synchronized with the frequency of the power supply. They are used in applications where precise speed control is required, such as in electric clocks, timers, and other similar devices.

Induction Motors: These motors are the most common type of three-phase motor used in industrial and commercial applications. They work on the principle of electromagnetic induction and are robust, efficient, and relatively low-cost. Induction motors come in various types, including squirrel-cage, wound-rotor, and double-fed induction motors.

Brushless DC Motors: Also known as electronically commutated motors (ECMs), these motors have a permanent magnet rotor and a stator with multiple windings. They are highly efficient, have low maintenance requirements, and are used in a wide range of applications, including electric vehicles, industrial automation, and robotics.

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Answer:

Pascal's law states that a change in pressure at any point in an enclosed fluid is transmitted equally throughout the fluid.

Explanation:

Applications of Pascal's law include

>The hidden standard of the water powered jack and pressure driven press.  

>Power intensification in the slowing mechanism of most engine vehicles.  

>Utilized in artesian wells, water pinnacles, and dams.  

>Scuba jumpers must comprehend this rule. At a profundity of 10 meters submerged, pressure is double the environmental weight adrift level, and increments by around 100 kPa for each expansion of 10 m depth.[5]  

>Generally Pascal's standard is applied to bound space (static flow), however because of the consistent flow process, Pascal's rule can be applied to the lift oil instrument (which can be represented as a U tube with pistons on either end).

Without Pascal's law, none of the above could be possible.

By integrating the given equation, we can find the potential ϕ as a function of z.

Let's consider a point P along the positive z-axis with coordinates (0, 0, z). To find the potential at point P, we integrate the Green function G_D(r, r') with respect to the charge distribution over the surface of the conducting sphere.

The potential ϕ at point P can be calculated using the following integral:

ϕ(P) = ∫∫ G_D(r, r') σ(r') dS

Here, σ(r') represents the charge density on the surface of the sphere, and dS represents the differential surface element.

Since we are interested in the potential along the positive z-axis, we can simplify the integral by considering the symmetry of the problem. Due to symmetry, the potential ϕ will only depend on the radial distance r from the z-axis. Thus, we can rewrite the integral as:

ϕ(P) = 2π∫ G_D(r, r') σ(r') r' dr'

Now, we need to express the charge density σ(r') in terms of the potential difference V and the radius R. The charge density on the upper hemisphere is V/(4πR^2), and on the lower hemisphere, it is -V/(4πR^2). Therefore, we can write:

ϕ(P) = (V/R^2) ∫ (r^2 + r'^2 - 2rr')/(r-r')^2 r' dr'

This integral can be evaluated using appropriate techniques of integration.

By integrating the above equation, we can find the potential ϕ as a function of z.

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Answer:

i have no clue

Explanation:

Answer:

the heart

Explanation:

Daily the heart pumps at least 2,500 gallons (9,450 liters) of blood. The heart has the ability to beat over 3 billion times in a person's life.

Answer: depth, shade, fragrance

Explanation:

Answer: Some elements like potassium, uranium, and thorium are naturally radioactive and give off gamma rays as they decay, but all elements can be excited by collisions with cosmic rays to produce gamma rays. The HEND and Neutron Spectrometers on GRS directly detect scattered neutrons, and the Gamma Sensor detects the gamma rays.

Explanation: searching