A student releases the 4kg bob of a 0.47m long
pendulum from the position shown.
What is the period of the harmonic motion?
S
What is the frequency of the harmonic motion?
Hz
How many cycles would the pendulum make in
45s?
6
(You may answer with a decimal)
6°

Answer:

a = 2.85714 m/s^2

Explanation:

Fnet=ma

eaqual and oppisate forces means that the 100N pushed on the ball comes back to the child.

100 = 35*a

a= 100/35

Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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The statement best describes the primary difference between scientific investigation and technological design is Scientific investigation involves experiments, and technological design involves products. Option D

It can be said that both scientific investigation and technolgical design require problem-solving, creativity, and rigorous methods.

However, both of them have different objectives. While Scientific investigation seeks to expand knowledge and understanding of the natural world. Research involvs hypothesis testing and different experiments;

on the other hand, Technological design, wants to create or improve products, processes, or systems to meet specific needs or solve particular problems.

It can then be defined as the application of scientific knowledge for practical purposes.

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The required,

(a) magnitude net electric field at the origin 14.24 x 10¹²  N/C

(b) the required direction of the net electric field at the origin is 90°.

The electric field is a physical quantity that describes the force exerted on a charged particle by other charged particles in the vicinity.

The electric field due to a point charge q at a distance r from the charge is given by:

E = k * q / r²

The electric field vector points radially away from a positive charge and radially towards a negative charge.

Electric field due to q₁,

E₁ = k * q₁ / r₁²

where r₁ is the distance from q₁ to the origin, which is:

r₁ = x₁ = 3.9 cm = 0.039 m

Substituting in the values,

E1 = (9 x 10⁹ Nm/C²) * (5.5 C) / (0.039 m)²

E1 = 3.25x 10¹³ N/C

Similarly,

The electric field due to q₁ points to the right along the x-axis.

Electric field due to q₂,

E₂ = -3.25x 10¹³ N/C

Electric field due to q₃:

E₃ = 3.79 x 10¹² N/C

Electric field due to q₄
E4 = -1.8 x 10¹³ N/C

The electric field due to q4 points upwards along the y-axis.

To find the net electric field at the origin, we add up the electric field vectors from each charge vectorially. Since the electric fields due to q1 and q2 are along the x-axis, they add up to give a net electric field along the x-axis

Ex = E₁ + E₂ = 0 N/C

Since the electric fields due to q3 and q4 are along the y-axis, they add up to give a net electric field along the y-axis:

Ey = E₃ + E₄
Ey = 3.79 x 10¹² -1.8 x 10¹³
Ey = -14.24 x 10¹²

Total net = √Ex² + Ey²²
Total net = 14.24 x 10¹²

(b)
The angle is found by

tanθ = -14.24 x 10¹²/0

θ = 90

Thus the angle from the positive x-axis is 90.

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To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

The equation can be used to determine the average force the nail applies to the hammer.

\(F = \frac{mv}{t}\), where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:

\(F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.\)

To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

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Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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This question involves the concepts of wave speed, wavelength, and frequency.

The frequency of the wave in seawater will be "2.68 Hz".

The relationship between speed, wavelength, and frequency of the wave can be given by the following formula:

\(v=f\lambda\\\\\lambda =\frac{v}{f}\)

Here, the wavelength of the wave is a constant property. Therefore,

\(\frac{v_1}{f_1}=\frac{v_2}{f_2}\)

where,

Therefore,

\(\frac{3950\ m/s}{7.05\ Hz}=\frac{1500\ m/s}{f_2}\\\\f_2=\frac{(1500\ m/s)(7.05\ Hz)}{3950\ m/s}\)

f₂ = 2.68 Hz

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Answer:

Explanation:

\(a_{x}=0\) \(v_{xo}= v_{o}cos(delta)t\) \(a_{y}=-g\) \(v_{yo}=sin\)θ

X-direction                                     | Y-direction

\(x=x_o+v_{xo}t\) ⇒ \(x=v_{xo}cos(delta)t\) |

Answer:

It's a scalar but will be positive or negative depending on the sign of the charge.

Explanation:

Answer:

Tell me why you cried, and why you lied to me

Tell me why you cried, and why you lied to me

Well I gave you everything I had

But you left me sitting on my own

Did you have to treat me, oh, so bad

All I do is hang my head and moan

Tell me why you cried, and why

Explanation:

The apparent weight of the astronaut of mass 65.1 kg moving with a speed of 33.9 m/s in 2.7 s is 811.797 N.

Weight is the force with which a body is attracted toward the earth or a celestial body by gravitation and which is equal to the product of the mass and the local gravitational acceleration.

To calculate the astronaut's apparent weight, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the apparent weight of the astronaut is 811.797 N.

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Answer:

Speed can be thought of as the Rate at which an object covers a Distance

Rate and Distance

Explanation:

Answer: 100km/h

Explanation: This is because the road isn't moving. If you drew the roads velocity and the bus velocity you would find a 100km/h difference. Thus an object inside the bus would experience the same differential.

If you drag a bag across floor, you are experiencing a friction force

if you throw a paper or feather up, it floats side ways slowly. It is called air Resistance.

if you push or pull a Door, it is Normal force.

I hope this helped!

have an amazing Day!!

Answer:

The velocity is  \(v = 2.84 1 \ m/s\)

Explanation:

The  diagram showing this set up is shown on the first uploaded image (reference Physics website )

From the question we are told that

    The mass is  m =  4 kg

    The  length of the string is \(L = 2.0 \ m\)

    The constant angle is  \(\theta = 35.4 ^o\)

Generally the vertical forces acting on the mass to keep it at equilibrium vertically is mathematically represented as

           \(Tcos (\theta ) - mg = 0\)

=>        \(mg = Tcos (\theta )\)

Now let the force acting on mass horizontally be k  so from SOHCAHTOA rule

         \(sin (\theta ) = \frac{k }{T}\)

=>      \(k = T sin \theta\)

Now this k is also equivalent to the centripetal force acting on the mass which is mathematically represented as

          \(F_v = \frac{m v^2}{r}\)

So

          \(k = F_v\)

Which

=>       \(T sin \theta= \frac{ m v^2}{ r }\)

So

        \(\frac{Tsin (\theta )}{Tcos (\theta )} = \frac{mg}{ \frac{mv^2}{r} }\)

=>      \(Tan (\theta ) = \frac{v^2}{ r * g }\)

=>      \(v = \sqrt{r * g * tan (\theta )}\)

Now the radius is evaluated using SOHCAHTOA rule as

       \(sin (\theta) = \frac{ r}{L}\)

=>    \(r = L sin (\theta)\)

substituting values

       \(r = 2 sin ( 35.4 )\)

       \(r = 1.1586 \ m\)

So

       \(v = \sqrt{1.1586* 9.8 * tan (35.4 )}\)

       \(v = 2.84 1 \ m/s\)

Answer:

To find the net charge on the sphere using electric flux, we can use the formula:  

Φ = Q/ε0

Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.  

Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:

E = kQ/r^2  

Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.  

Substituting the given values, we get:  

20 = (1/4πε0)(Q)/(0.2)^2  

Solving for Q, we get:  

Q = (20)(0.2)^2(4πε0)  

Q = 0.64πε0 C  

Now, substituting this value of Q in the formula for electric flux, we get:  Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C  

Therefore, the net charge on the sphere is 0.64π C.

Answer:

Explanation:

Isaac Newton argued that the geometric nature of reflection and refraction of light could only be explained if light were made of particles, referred to as corpuscles, because waves do not tend to travel in straight lines.

Answer:

force

Explanation:

Answer:

Force

Explanation:

Force includes gravity and friction and applied force hence push a pulling

Why the ocean near Christchurch is a different temperature than we'd expect for its latitude (distance from the equator)? Water moving from the equator is warmer than would be expected based on latitude, and so is warmer than the air it passes.

Changes to prevailing winds affect ocean currents. Changes to ocean currents affect how much energy is brought to (or taken away from) a location. In El Niño years, the prevailing winds that normally drive a warm current from the Equator past New Zealand are disrupted and may stop or even reverse.

Answer:

On the way to the Moon the Apollo astronauts reached a point where the. Moon's gravitational pull became stronger, than the Earth's. (a) Determine the distance of ...

Explanation:

Complete question:

A 16-V battery powers a series circuit that contains two lightbulbs. The voltage across the first lightbulb is 12-V.

a. What fractional part of the circuit's total energy is transformed in the first lightbulb? Simply your answer.

b. What fractional part of the circuit's total energy is transformed in the second lightbulb? Simply your answer.

Answer:

(a) Fraction of energy of the first bulb in the total energy of circuit is 3/4

(b) Fraction of energy of the second bulb in the total energy of circuit is 1/4

Explanation:

Given;

total voltage across the series circuit, \(V_T\) = 16 V

voltage across the first light bulb, V₁ = 12 V

The voltage across the second light bulb is given by;

V₂ = \(V_T\) - V₁

V₂ = 16 V - 12 V

V₂ = 4 V

The total power across the circuit is given by;

P = I\(V_T\)

P = 16I

Where;

I is the constant current in the circuit

(a)

power in the first light bulb is given by;

P₁ = 12I

Fraction of this power in the total energy of circuit is given by;

\(\frac{P_1}{P} = \frac{12I}{16I} = \frac{3}{4}\)

(b)

power in the second light bulb is given by;

P₂ = 4I

Fraction of this power in the total energy of circuit is given by;

\(\frac{P_2}{P} = \frac{4I}{16I} = \frac{1}{4}\)

The precise way a researcher measures and defines a variable is known as the operational definition.

The researcher measures the dependent variable and the independent variable is manipulated and controlled by the researcher ( Experimenter ). The concept of operational definition is applied in various fields such as Philosophy, Science, Business, computing etc.

To explain this clearly, let's consider an example in which the researcher tries to define sleep deprivation. In this sleep deprivation is the independent variable and factors causing sleep deprivation such as food, lifestyle, etc are dependent variables.

Therefore, the precise way a researcher measures and defines a variable is known as the operational definition.

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We are given:

Mass of the rocket = 10 kg

Weight of the Rocket = 100 N

Upward thrust applied by the rocket = 400 N

Net upward force on the rocket:

We are given that gravity pulls the rocket with a force of 100 N

Also, the rocket applied a force of 400N against gravity

Net upward force = Upward thrust - Force applied by gravity

Net upward force = 400 - 100

Net upward force = 300 N

Upward Acceleration of the Rocket:

From newton's second law:

F = ma

replacing the variables

300 = 10 * a

a = 30 m/s²

Answer:

3.456 × 10^(8) m

Explanation:

We are given;

Mass of earth; m_e = 5.98 × 10^(24) kg

Mass of moon; m_m = 7.36 × 10^(22) kg

Distance from earth to moon; L = 3.84 × 10^(8) m.

We are told that the Moon’s gravitational pull is stronger than that of Earth’s.

Thus;

F_EA ≤ F_MA

Formula for force due to gravity is;

F = GMm/r²

Applying to this question, we have;

(Gm_e•m_a)/x² ≤ (Gm_m•m_a)/(l - x)²

Where x is his distance from the center of the Earth

Now, G and m_a will cancel out from both sides and we plug on other values to get;

(5.98 × 10^(24))/x² ≤ (7.36 × 10^(22))/(3.84 × 10^(8) - x)²

Taking square root of both sides gives;

2445403852127.4966/x ≤ 271293199325.0107/(3.84 × 10^(8) - x)

Rearranging gives;

2445403852127.4966(3.84 × 10^(8) - x) ≤ 271293199325.0107x

Simplifying this gives;

9.0139(3.84 × 10^(8) - x) ≤ x

(34.613 × 10^(8)) - 9.0139x ≤ x

(34.613 × 10^(8)) ≤ x + 9.0139x

(34.613 × 10^(8)) ≤ 10.0139x

x ≥ (34.613 × 10^(8))/10.0139

x ≥ 3.456 × 10^(8)

The velocity in the first and the second case will be 1.8028 and 5.408 m/sec.

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

Given data:

Kinetic energy, KE=26 J

Mass,m=16 kg

The velocity is obtained as;

\(\rm KE= \frac{1}{2}mv^2 \\\\ v=\sqrt{\frac{2KE}{m} } \\\\ v=\sqrt{\frac{2 \times 26}{16} } \\\\v=1.8028 \ m/sec\)

The second stone has mass and nine times the kinetic energy:

\(\rm KE= \frac{1}{2}mv^2 \\\\ v'=\sqrt{\frac{9\times 2KE}{m} } \\\\ v=\sqrt{9 \times \frac{2 \times 26}{16} } \\\\v=5.408 \ m/sec\)

Hence the velocity in the first and the second case will be 1.8028 and 5.408 m/sec.

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Scientifically painting finished components might be given as, W = F * d. In this example, the pressure exerted at the block is regular, however, the path of force and the direction of displacement encouraged by using this pressure is one-of-a-kind. right here, force F reacts at an attitude θ to the displacement d.

The work accomplished through pressure is defined to be the product of the aspect of the force in the path of the displacement and the importance of this displacement. formulation. work may be calculated by multiplying force and Distance inside the route of force as follows. W = F × d.

The work W is equal to the pressure f instances the distance d, or W = fd. If the force is being exerted at a perspective θ to the displacement, the work accomplished is W = FD cos θ.

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Answer:

A force can speed up or slow down an object. A force can change the direction in which an object is moving. A bigger force on an object will produce a bigger change in the motion. A heavier object requires a larger force than a lighter object in order to undergo the same change in motion.

Answer:

is that 4 question each one of them we have to solve