A soccer ball rolls across a field with
an initial velocity of 14.9. Due to friction, it slows down at a rate of .5 until eventually coming to a stop. How far did it roll AND how long did it take to get there?​

Fans circulate the air.

Due to the circulation of air, the warm air gets replaced by cold air.

The weight is 1300 N of a probe of mass 50 kg at Jupiter's surface

The weight of an object is the force exerted on it by gravity, which is given by the product of its mass and the acceleration due to gravity.

At Jupiter's surface, the surface gravity is about 26 newtons per kilogram. So, the weight of a probe of mass 50 kg at Jupiter's surface would be:

Weight = Mass x Acceleration due to gravity

Weight = 50 kg x 26 N/kg

Weight = 1300 N

Therefore, the weight of a probe of mass 50 kg at Jupiter's surface would be 1300 Newtons.

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(a) The equilibrium temperature of the system is 0°C.

(b) There is no unmelted ice when the system reaches equilibrium.

The three ice cubes have a total mass of 3 * 111.0 g = 333 g. The water has a mass of 0.840 kg = 840 g. The specific heat capacity of water is 4.184 J/g°C. The latent heat of fusion of water is 333.55 J/g.

When the ice cubes are added to the water, the ice cubes will absorb heat from the water until they reach 0°C. Once the ice cubes reach 0°C, they will begin to melt. The heat required to melt the ice cubes will come from the water.

The water will continue to lose heat until all of the ice cubes have melted. The total heat required to melt the ice cubes is:

Q = m * Lf

Q = 333 g * 333.55 J/g

Q = 111,476 J

The total heat lost by the water is:

Q = m * c * ΔT

Q = 840 g * 4.184 J/g°C * (21.0°C - 0°C)

Q = 75,056 J

Since the heat lost by the water is equal to the heat required to melt the ice cubes, the equilibrium temperature of the system is 0°C. At 0°C, the water will be in equilibrium with the ice. There will be no unmelted ice when the system reaches equilibrium.

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Answer:

Peters image will grow bigger

Explanation:

In this situation, only Peter is at rest and the mirror is in motion at 1.5m/s heading towards Peter.

From afar, Peter will look small in the mirror that is his image will be small When the mirror is moved at 1.5m/s Peter being the observer will notice that his image grows bigger and bigger.

When the car moves 4km east and then turns 3km  north then the resultant displacement of car will be :

5km

Here initially the car moves 4km east , that is a straight line  towards east direction with a value of 4kms (let the point be A).

then,  from the point A it turns 3km towards north direction. here

North and east are perpendicular to one another.

ie, it forms 90° that means it is a right angle.

The displacement of a car is the distance between its initial and final positions.

The displacement is

S = \(\sqrt{3^{2} + 4^{2} }\)  

S = \(\sqrt{25}\)

  = 5

so the resultant displcement is 5km

the resultant graph is attached below:

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Answer:

False.

Explanation:

A good health can be defined as the state of well-being in which all of the components of an individual's health are in balance. These state of well-being comprises of six (6) important components and they are;

1. Physical: this is a measure of the state of an individual's body or the way the body functions. It is enhanced by eating right, working out or exercising, avoiding drugs and alcohol, maintaining a good body mass index etc.

2. Emotional: this deals with the state of an individual's mind being void of worries, negativity etc.

3. Social: this involves keeping a good relationship with friends, family and many others around.

4. Environmental: it deals with maintaining a hygienic surrounding, that is devoid of pollutants.

5. Mental or intellectual: avoiding unnecessary stress and anxiety while dealing or coping with the realities of life.

6. Spiritual: it encompasses belief systems, values, ideals, morality etc.

When an individual is able to balance all of these above mentioned components, then he or she is said to be healthy.

Hence, making good lifestyle choices will not and cannot prevent all diseases because some diseases are hereditary in nature i.e they can be transferred from a parent to their offspring or generation to another through genetics. Some examples of hereditary diseases are haemophilia, sickle-cell anaemia, thalassemia, cystic fibrosis, etc.

Answer:

false on edge

Explanation:

The final answer are gravity has a more significant effect on an object's motion than air resistance does.

When forces are supplied by gravity, changing the mass has a different effect on velocity than when forces are supplied by a rubber band. why changing the mass has a different effect on the speed when gravity provides the forces compared to when the force is provided by a rubber band?

When a force is supplied by a rubber band, the motion of the object can be observed. When an object is propelled using rubber bands, the effect of changing mass on the speed is almost constant. When a force is supplied by gravity, changing the mass has a different effect on velocity.

When an object is dropped, it will accelerate at a constant rate regardless of its mass because it is not impeded by air resistance. This constant rate of acceleration is known as the acceleration due to gravity. Furthermore, the mass of the object would not affect the force of gravity acting on it.

Therefore, the mass of an object does not have an impact on its acceleration due to gravity.However, the mass of the object would affect how it interacts with the force of air resistance, which opposes its motion and slows it down.

Air resistance is proportional to the cross-sectional area of the object and the density of the medium through which it travels. As a result, an object with a greater mass would have a greater surface area, which would result in more air resistance.

This implies that a heavier object would have a lower terminal velocity than a lighter object with the same surface area. When an object is dropped, it accelerates until it reaches its terminal velocity, which is the maximum velocity it can reach while falling, and then it falls at a steady rate because it is not impeded by air resistance.

So, gravity has a more significant effect on an object's motion than air resistance does.

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Answer:

they have same acceleration 2m/s^2

Explanation:

a =v-u/t

65-60/2.5

2m/s^2

a) The acceleration of the car and the bicycle are equal since \(\delta V\) for both vehicle is 5km/h and the time taken for both vehicle is also the same 2.5s.

b) The acceleration of the bicycle is 0.556m/s²

Given the data in the question;

Since the bicycle starts from rest

a)

The acceleration of the car and the bicycle are equal since \(\delta V\) for both vehicle is 5km/h time taken for both vehicle is also the same 2.5s.

b)

The acceleration of each vehicle

To determine the acceleration for car and the bicycle, we use the first equation of motion:

\(v = u + at\)

Where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Now, For the car;

\(18.0556m/s = 16.667m/s + ( a + 2.5s )\\\\a = \frac{18.0556m/s - 16.667m/s }{2.5} \\\\a = \frac{1.3886m/s}{2.5s} \\\\a = 0.556 m/s^2\)

Hence, the acceleration of the car is 0.556m/s²

For the bicycle;

\(1.38889m/s = 0 + ( a * 2.5s )\\\\a = \frac{1.38889m/s}{2.5s}\\\\a = 0.556m/s\)

Hence, the acceleration of the bicycle is 0.556m/s²

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The net capacitance of the combination of capacitors is 3.44 μF.

We can use the formula for the total capacitance of capacitors connected in series and parallel to find the net capacitance of this combination.

When capacitors are connected in series, their total capacitance is given by: 1/C_series = 1/C_1 + 1/C_2 + 1/C_3 + ...

For the 3.00 μF and 4.00 μF capacitors connected in series, their equivalent capacitance is:

1/C_series = 1/3.00 μF + 1/4.00 μF

= 0.4444 + 0.25

= 0.6944 μF

Taking the reciprocal of both sides, we find the equivalent capacitance:

C_series = 1/0.6944 μF

≈ 1.44 μF

This equivalent capacitance is then connected in parallel with the 2.00 μF capacitor, and the total capacitance of the combination is given by:

C_total = C_series + C_parallel

= 1.44 μF + 2.00 μF

= 3.44 μF

Therefore, the net capacitance of the combination of capacitors is 3.44 μF.

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Answer:

16.77 m/s, 26.57° south of west

Explanation:

The two velocities form a right triangle.  Use Pythagorean theorem to find the magnitude of the resultant velocity.

v² = (-15 m/s)² + (-7.5 m/s)²

v = 16.77 m/s

Use trig to find the angle.

tan θ = ((-7.5 m/s) / (-15 m/s))

θ = 26.57° south of west

The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes

The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:

T² = (4π² / GM) × a³

T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³

Take the square root of both sides

T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]

T = 9789.15 s

Divide by 60 to express in minutes

T = 9789.15 / 60

T = 163 minutes

Thus, we can conclude that the orbital period of the satellite is 163 minutes

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Answer:

200 million electric light bulbs.

Explanation:

First, we must calculate the power of the electric bulb, for this, we use the following equation that relates the energy as a function of time.

\(P=E/t\)

where:

P = power [W] (units of watts)

E = energy = 360000 [J] (units of Joules)

t = time = 1 [h] = 3600 [s]

\(P = 360000/3600\\P= 100[W]\)

In 1 hour 1 electric lightbulb produces 100 [W], now we need to know the amount of energy produced by the Hiroshima bomb. A search made by the internet give us the data of 20 [GW] or [Gigawatts].

We need to remember that 1 Giga = 1 x10⁹

Energy Hiroshima explosion= 20*10⁹[W]

Amount = (20x10⁹)/100

Amount = 200 x10⁶ [bulbs]

That is, we would need an amount of 200 million electric light bulbs.

Answer:

They are all units of pressure

Purpose, accuracy, and authority.

The first paragraph of your essay should outline your topic provide the background information you need to understand your claim, outline the evidence you present, and state your thesis. dissertation statement. This is part of the first paragraph. The five parts include a strong introductory paragraph with a clear thesis, three main paragraphs supported by detailed evidence, and a compelling conclusion.

Students should also use transition words and phrases to help readers explain their points of view. Developed by philosopher Stephen E. Toulmin, his Toulmin Method is a style of reasoning in which he decomposes claims into six components Claim Inference Warrant Limitation Refutation and Support. In Toulmin's method, each argument begins with three basic parts assertion justification and justification. These are the thesis statement the target audience needs, and support.

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Answer:

Three (3).

Explanation:

The octet rule is a rule in chemistry that states that, chemical elements would either gain or loss electrons in their outermost shell in order to attain a stable electronic configuration i.e having eight (8) valence electrons in their outermost shell such as chemical elements found in group 8 (2-8-8) known as noble gas.

A phosphorus atom needs to gain three (3) electrons to achieve a full octet because the atomic number of phosphorus is 15 and as such it has the electronic configuration of 2-8-5 and needs three electron in order to become a stable element.

(8 and 2/3) millimeters per second.

That's about 0.02 mile per hour.

The average velocity of the boat given the data from the question is 6.32 Km/h

Velocity is defined as the rate of change of displacement with time. Mathematically, it is expressed as

Velocity = displacement / time

D² = d₁² + d₂²

D² = 3² + 1²

D² = 9 + 1

D² = 10

Take the square root of both sides

D = √10

D = 3.16 Km

Average velocity = resultant displacement / time

Average velocity = 3.16 / 0.5

Average velocity = 6.32 Km/h

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The acceleration of the cart is 1.962 m/s^2, and the angular velocity of the wheel after 3 seconds is 11.772 rad/s.

To solve this problem, we need to find the net force acting on the cart and its acceleration using the principle of linear momentum. Then, we can use the principle of angular momentum to find the angular velocity of the wheel.

First, we find the center of mass of the cart and its load. Using the formula for the center of mass,

xG = (m1*x1 + m2*x2 + m3*x3 + m4*x4 + m5*x5) / (m1 + m2 + m3 + m4 + m5)

  = (100*0 + 100*1.2 + 100*0.5 + 50*0.3 + 50*0.4) / 300

  = 0.7 m

Next, we can find the net force acting on the cart by analyzing the forces acting on it. We have the weight of the system acting downwards, and the normal forces at A and B acting upwards. Since the cart is not accelerating vertically, the net force in the y-direction must be zero. Therefore, the normal forces at A and B are equal to the weight of the system, which is:

N = 1000 N

To find the net force in the x-direction, we use the principle of linear momentum:

F_net = m*a_G

     = 100*a_G

where a_G is the acceleration of the center of mass. Since the forces acting in the x-direction are the force of friction acting backwards, and the force of tension in the rope acting forwards, we have:

F_net = T - f

where T is the tension in the rope, and f is the force of friction. Since the wheel is rolling without slipping, we have:

f = (1/2)*m*g

where g is the acceleration due to gravity. Also, the tension T is equal to:

T = m*a

where a is the linear acceleration of the wheel.

Using the principle of rotation, we have:

I*alpha = T*r

where I is the moment of inertia of the wheel about its center of mass, alpha is the angular acceleration, and r is the radius of the wheel. Since the wheel starts from rest, its initial angular velocity is zero, and we can use the equation:

omega = alpha*t

to find the angular velocity after time t.

Substituting the given values, we have:

I = m*k^2

 = 100*(0.5)^2

 = 25 kg*m^2

r = 0.5 m

f = (1/2)*m*g

 = (1/2)*100*9.81

 = 490.5 N

T = m*a

F_net = T - f

     = m*a - (1/2)*m*g

F_net = m*a_G

     = 100*a_G

I*alpha = T*r

omega = alpha*t

Substituting T and alpha from the above equations, we get:

m*a*r = m*a - (1/2)*m*g

I*alpha = m*a*r

omega = alpha*t

Solving these equations, we get:

a = 1.962 m/s^2

alpha = a/r = 3.924 rad/s^2

omega = alpha*t = 11.772 rad/s

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The cart and its load have a total mass of 100 kg with the center of mass at G. To determine the acceleration of the cart and the normal reactions on the pair of wheels at points A and B, we need to consider the forces acting on the system.

Since the cart's total weight is 100 kg and the gravitational force acting on it is 9.81 m/s², the weight W can be calculated as W = mass × gravity, which is W = 100 kg × 9.81 m/s² = 981 N. This force is acting vertically downwards at the center of mass G. Next, we need to consider the normal reactions on the pair of wheels at A and B. Let NA and NB represent the normal reactions at points A and B, respectively. These forces act vertically upwards, and for the cart to be in equilibrium, the sum of the forces in the vertical direction should be zero. Thus, NA + NB = W = 981 N. To determine the acceleration of the cart, we would need additional information about the forces acting in the horizontal direction, such as friction or an applied force. Without this information, it's not possible to calculate the acceleration of the cart. Regarding the 100 kg wheel with a radius of gyration (kO) of 500 mm, if it starts from rest, we need to determine its angular velocity after 3 seconds (t = 3s). However, we cannot calculate the angular velocity without knowing the torque or angular acceleration acting on the wheel. Additional information is needed to solve this part of the problem.

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Tencent Corporation's target capital structure is 70 percent common stock, 5 percent preferred stock, and 25 percent debt. This means that for every $100 of capital, $70 will come from common stock, $5 will come from preferred stock, and $25 will come from debt.

Tencent's cost of equity is 11 percent, which means that investors expect to earn an 11 percent return on their investment in the company's common stock.

The cost of preferred stock is 5 percent, which means that investors expect to earn a 5 percent return on their investment in the company's preferred stock. The pretax cost of debt is 6 percent, which means that the company must pay an interest rate of 6 percent on its borrowed funds.

The relevant tax rate is 23 percent, which means that the company will have to pay 23 percent of its income in taxes. This will affect the cost of its borrowed funds, since the interest paid on debt is tax-deductible.

The after-tax cost of debt is equal to the pretax cost of debt multiplied by (1 - tax rate), which in this case is 6 percent * (1 - 0.23) = 4.62 percent.

To calculate the company's weighted average cost of capital (WACC), we need to determine the proportion of each type of capital in the company's target capital structure and multiply it by the cost of that type of capital.

The proportion of common stock is 70 percent, and the cost of common stock is 11 percent, so the weighted cost of common stock is 70 percent * 11 percent = 7.7 percent.

The proportion of preferred stock is 5 percent, and the cost of preferred stock is 5 percent, so the weighted cost of preferred stock is 5 percent * 5 percent = 0.25 percent. The proportion of debt is 25 percent, and the after-tax cost of debt is 4.62 percent, so the weighted cost of debt is 25 percent * 4.62 percent = 1.155 percent.

Finally, we can add up the weighted cost of each type of capital to get the company's WACC:

WACC = 7.7 percent + 0.25 percent + 1.155 percent = 9.115 percent

This means that, on average, investors expect to earn a 9.115 percent return on their investment in Tencent Corporation.

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Option 4. The same charge - repulsion describes the charge on the strips after rubbing.

Static charge or an electrostatic charge is a deficiency or extra of electrons that occurs on ungrounded or insulating surfaces. it's miles produced by way of triboelectric costs, expenses which can be generated by friction among surfaces, including the motion of paper thru a copier or printer.

An electrical charge is created when two materials come into contact or are rubbed collectively. when the substances are in touch, electrons can be actually rubbed off of one object and onto the alternative.

Static power is an imbalance of electric fees within or on the floor of a material. The fee stays till it could pass away by way of an electric present-day or electric-powered discharge.

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Answer:

A plane mirror is a mirror with a flat (planar) reflective surface. For light rays striking a plane mirror, the angle of reflection equals the angle of incidence. The angle of the incidence is the angle between the incident ray and the surface normal (an imaginary line perpendicular to the surface).

The torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0.02 N on the ball is 0.024 N.m.

A small 1.25 kg ball on the end of a light rod is rotated in a horizontal circle of radius 1.2 m.

The moment of inertia of the system about the axis of rotation and the torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0.02 N on the ball can be calculated as follows:

Part (a)The moment of inertia, I of a solid ball is given by I = 2/5mr².

Here, m is the mass of the ball, and r is the radius of the ball.

We have to find the moment of inertia of the system about the axis of rotation.

Since the axis of rotation passes through the center of the ball, the moment of inertia of the ball is given by Iball = 2/5mr².

Thus, the moment of inertia of the system about the axis of rotation is given by I = Iball + mR²I = 2/5mr² + mR²I = m(2/5r² + R²)I = 1.25(2/5(0.06)² + (1.2)²)I = 0.026 kg.m²

Part (b)The torque required to keep the ball rotating at constant angular velocity can be calculated as follows:

τ = Iα

Here, τ is the torque,

I is the moment of inertia of the system, and

α is the angular acceleration.

At constant angular velocity, α = 0.

Since air resistance exerts a force of 0.02 N on the ball, the torque required to keep the ball rotating at constant angular velocity is

τ = Frτ = F × Rτ = 0.02 × 1.2τ = 0.024 N.m

Therefore, the torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0.02 N on the ball is 0.024 N.m.

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Answer:

F=ma

5N=0.3a

a=5/0.3=16.66m/s²

PLEASE GIVE BRAINLIEST

Answer:

16.7

Explanation:

acceleration=force/mass

Answer:

B

Explanation:

Answer:

C

Explanation:

That is where the most heat and light is showing on this diagram.

The sun on this HR diagram is placed at region A. The correct option is A.

The Hertzsprung-Russell (HR) diagram is a plot of stars that shows their luminosity (or brightness) versus their temperature or spectral type. The HR diagram is divided into several main parts:

Main sequence: This is the prominent diagonal band that extends from the upper left (hot, bright stars) to the lower right (cool, dim stars). The main sequence represents stars that are fusing hydrogen in their cores and is where most stars, including the Sun, spend the majority of their lives.

Giants and supergiants: These are stars that are much larger and more luminous than main-sequence stars, and are found above and to the right of the main sequence. Giants and supergiants are typically older stars that have exhausted the hydrogen fuel in their cores and are in the later stages of their evolution.

White dwarfs: These are the small, dense remnants of stars that have exhausted their nuclear fuel and have shed their outer layers. White dwarfs are found at the lower left of the HR diagram and are the final stage of evolution for stars like the Sun.

Instability strip: This is a narrow region of the HR diagram that includes some of the most variable stars, such as Cepheid variables and RR Lyrae variables. These stars pulsate in size and brightness over a regular period of time, making them useful for measuring distances to other galaxies.

By studying the position of stars on the HR diagram, astronomers can learn about their size, age, temperature, and luminosity, and use this information to develop models of stellar evolution and the history of the universe.

In this question,

The Sun is a main-sequence star, meaning it is in the phase of its life cycle where it is fusing hydrogen in its core to form helium.

On an HR diagram, the Sun falls near the center of the main sequence, which is a diagonal band that extends from the upper left (hot, bright stars) to the lower right (cool, dim stars). The temperature of the Sun is about 5,500°C, which places it in the spectral class G2V.

Therefore, The sun resides in the region of A.

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The Paschen series is a spectral series of hydrogen-like atoms that is similar to the Balmer series, but with a different value of the principal quantum number.

Specifically, the Paschen series corresponds to transitions between an excited state with principal quantum number n greater than or equal to 3, and the n=3 energy level in hydrogen-like atoms.

Like the Balmer series, the Paschen series also produces a series of spectral lines, which are the result of the emission of electromagnetic radiation as the electrons in the atom transition from higher energy levels to lower energy levels.

However, the wavelengths of the spectral lines in the Paschen series are longer than those in the Balmer series, due to the higher energy levels involved.

Overall, the Paschen series is an important aspect of the study of atomic physics, and provides valuable insights into the behavior of hydrogen-like atoms and their spectral emissions.

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Answer:

p2=28.12KPa

Explanation:

Given data:

Initial temperature = 295 K

Final temperature= 395 K

Initial pressure = 21.0 KPa

Final pressure = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

21.0 KPa / 295 K = P₂/395 K

P₂ = 21.0 KPa× 395 K / 295 K

P₂ = 8295 KPa. K /295 K

P₂ = 28.12 KPa

Assuming that  average speed are in kilo-metres per hour, the typical trip takes 2 hours and 20 minutes to complete.

Apply the following formula to this issue:

Total distance travelled minus total time taken equals average speed.

You must first determine the length of the trip travelled.

Total distance travelled minus total time taken equals average speed.

Therefore : d = average speed x time spent overall - rearranging

In other words, d = vt = 105 km/hr x 2.3333... hrs = 245 km

Find out how long the typical journey takes on Friday afternoon.

t = d/v - equation rearranged equals 245 km/67 km/h = 3.6567164.

18 hours equals 3 hours, 39 minutes (rounded to nearest whole minute)

You must now determine how much longer the Friday trip takes.

Duration: (3 hours and 39 minutes) - (2 hours and 20 minutes)

= 1 hour and 19 minutes

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Answer:

Explanation:

a). Find the graph attached for the motion.

b). If a shopper walk 5.4 m westwards then 7.8 m eastwards,

   Distance traveled by the shopper = Distance traveled in eastwards + Distance traveled westwards

                                                            = 5.4 + 7.8

                                                            = 13.2 m

c). Displacement of the shopper = Distance walked westwards - Distance traveled eastwards

                                                      = 5.4 - 7.8

                                                      = -2.4 m

Therefore, magnitude of the displacement of the shopper is = 2.4 m

And the direction of the displacement is eastwards.