A simple Rankine cycle uses water as the working fluid. The boiler operates at 6000 kPa and the condenser at 50 kPa. At the entrance of the turbine the temperature is 450 deg C. The isentropic efficiency of the turbine is 94 percent, pressure and pump losses are negligible, and the water in the condenser is subcooled by 6.3 degC. The boiler is sized for a mass flow rate of 20 kg/s. Determine the rate at which heat is added in the boiler, the power required to operate the pumps, the net power produced by the cycle, and the thermal efficiency.

Answers

Answer 1

Answer:

the rate at which heat is added in the boiler = 59597.4 kW

the power required to operate the pumps = 122.57 kW

The net power produced by the cycle = 17925 kW.

The thermal efficiency = 30%.

Explanation:

The specific enthalpy of saturated liquid is equal to the enthalpy of the first point which is equal to 314 kJ/ kg.

The second enthalpy is calculated from the pump work. Therefore, the second enthalpy = first enthalpy point + specific volume of water [ the pressure of the boiler - the pressure of the condenser].

The second enthalpy = 314  + 0.00103 [ 6000 - 50 ] = 320.13 kJ/kg.

The specific enthalpy for the third point = 3300 kJ/kg.

Therefore, the rate at which heat is added in the boiler = 20 × [3300 - 320.13] = 59597.4 kW.

The rate at which heat is added in the boiler = 59597.4 kW.

Also, the power required to operate the pumps = 20 × 0.00103 [6000 - 50] = 122.57 kW.

The power produced by the turbine = 20 [ 300 - ( the fourth enthalpy value)].

The fourth enthalpy value = 3300 - 0.94 [ 3300 - 2340] = 2397.6 kJ/kg

Thus, the power produced by the turbine = 20 [ 300 - 2397.6] = 18048 kW.

The power produced by the turbine  =  18048 kW.

The net power produced =  18048  + 122.57 = 17925 kW.

The thermal efficiency = [net power produced] / [the rate at which heat is added in the boiler].

The thermal efficiency = 17925/ 59597.4 = 30%.


Related Questions

An organization sets its standards for quality according to the best product it can produce.
True
False

Answers

I believe it’s True, but please correct me if I’m wrong!

Answer:

True!! took the test

Explanation:

Great amounts of electro-magnetic energy from our son and other bodies n space travel through space. Who's is a logical conclusion about these electro-magnetic waves?

Answers

Answer:

Logical conclusion : there are more electromagnetic waves than sunlight

Explanation:

The traveling of electromagnetic energy from the sun and other bodies through space leads to Electromagnetic radiation.

Hence the logical conclusion about Electromagnetic waves is that there are more electromagnetic waves than sunlight

While the travelling of electromagnetic waves through space is described as gliding through space

3. Suppose up to 300 cars per hour can travel between any two of the cities 1, 2, 3, and 4. Formulate a maximum flow problem that can be used to determine how many cars can be sent in the next two hours from city 1 to city 4. Give the network diagram and the LP formulation for your model.

Answers

Let $x ij$ represent the quantity of cars that will be delivered in the following two hours from city I to city j.

Create a maximum flow issue?

Network Diagram:

LP Formulation:

Maximize Z = 150x14 + 150x24

Subject to:

x11 + x12 + x13 + x14 <= 300 (flow from city 1 to other cities)

x21 + x22 + x23 + x24 <= 300 (flow from city 2 to other cities)

x31 + x32 + x33 + x34 <= 300 (flow from city 3 to other cities)

x41 + x42 + x43 + x44 <= 300 (flow from city 4 to other cities)

x11 + x21 + x31 + x41 = 150 (flow into city 1)

x12 + x22 + x32 + x42 = 150 (flow into city 2)

x13 + x23 + x33 + x43 = 150 (flow into city 3)

x14 + x24 + x34 + x44 = 150 (flow into city 4)

xij >= 0 (all variables must be positive)

Where xij represents the number of cars traveling from city i to city j in two hours.

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when a technician is installing a printer, the technician hears a loud clicking noise. should he check the power supply first?

Answers

If a technician is installing a printer and hears a loud clicking noise, it could be an indication of a malfunctioning power supply.

However, it is not necessarily the first thing that should be checked. The technician should start by checking the printer's internal components, such as the ink cartridges, printhead, and paper tray, to ensure they are properly installed and functioning. If the noise persists, the power supply should then be checked to see if there is an issue with the connection or if it needs to be replaced. It is important to address any issues with the printer's hardware before attempting to diagnose or troubleshoot any software-related problems.

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1. The hull of the space shuttle consists of ceramic tiles bonded to an aluminum skin. Discuss the design requirements of the shuttle hull that led to the use of this combination of materials. What problems in producing the hull might the designers and manufacturers have faced

Answers

Answer:

Follows are the solution to the given question:

Explanation:

In the environment of the piles of earth, its spacecraft faces extreme temperatures:

Therefore, to prevent satellite build sustainability, a temperature control system must be used.

Its skin must be rather permeable in physiological terms.

Its shuttle's surface should have adhered to both the material well.

Whether it gets broken, it ought to be easy to repair.

All tile mostly on the cutter is composed of silicon dioxide particles, that are bonded and create a tile of very low density.

Its heat transfer is so small that even a person may hold a burning hot side on one side of the tile.

Skin that uses a rubber resin to ensure that perhaps the powers may not release the cutting that heat-treated will then the internal body.

The design requirements that led to the combination of ceramic tiles and aluminium materials for the hull of shuttle space are; discussed below.

The space shuttle experiences extreme temperatures during re-entry into the earths atmosphere. Thus, as a result, a thermal protection system must be provided to help prevent damage of the shuttle structure.

Therefore, the skin must be made up of material that has an exceptionally low thermal conductivity and also the material must be able to be firmly attached to the skin and also be able to be easily repaired in case of any damage.

Secondly, the tiles used on the space shuttle will have to be composed of silica fibers that are bonded together to generate a ceramic of low density. The thermal conductivity of the ceramic would have to be low such that if you touch one end while the other is very hot, you will not feel the hotness.

Now, the tiles will be attached to the shuttle skin with the aid of a rubbery polymer which ensures that the forces don't break the tile loose which will then expose the underlying skin to high temperatures.

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Non normal data in data science

Answers

A data set might follow a variety of non-normal distributions, depending on the nature of the process, the technique of data collection, the sample size, outliers in the data, etc. Below is a list of some of the most significant non-normal distributions; Alpha Distribution Exponential

What non-normal data represent in data science?

Several tests, including the t-test, ANOVA, Regression, and DOE, are unaffected by the assumption of normality.

Since no attribute (such as height, weight, etc.) will have a perfectly normal distribution, non-normality is a fact of existence. Using a transformation is one way to make non-normal data resemble regular data.

Therefore, The non-normal data can be analysed in two different ways. Use non-parametric tests, which don't make any assumptions about normality, or convert the data with the right function to make it follow a normal distribution.

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What types of materials are best for preventing heat transfer through convection?.

Answers

The types of materials are best for preventing heat transfer through convection include the following:

FiberglassWoolCottonPaper (wood cellulose)StrawFoams

What are the types of energy transmission?

In Science, there are three (3) main types of heat energy transmission and these include the following:

ConvectionRadiationConduction

What is convection?

Convection can be defined as a heat energy transfer process which typically involves the transfer of heat, as a result of the movement of mass.

Based on scientific research and experiments, convection is generally considered to be a more effective and efficient means of heat transport on planet Earth when compared to conduction.

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helppppppp plssss Identifying job responsibilities for staff members is an example of which section of the project charter?


project requirements

project objectives

project team

project description

Answers

The correct answer is project team.

43) According to kinetic-molecular theory, if the temperature of a gas is raised from 100°C to 200°C, the average kinetic energy of the gas will
A) double

B) increase by a factor of 1.27

C) increase by a factor of 100

D) decrease by half

E) decrease by a factor of 100

Answers

A) double

According to the kinetic-molecular theory, the temperature of a gas is a measure of the average kinetic energy of the gas molecules. The kinetic energy of a molecule is the energy it possesses due to its motion. As the temperature of a gas increases, the average kinetic energy of the molecules increases.

If the temperature of a gas is raised from 100°C to 200°C, the average kinetic energy of the molecules will double. This is because the temperature increase is a 100% increase, and the average kinetic energy of the molecules will also increase by 100%.

It is important to note that this is only true if the volume and number of molecules in the gas are held constant. If the volume or number of molecules changes, the relationship between temperature and average kinetic energy may be different.

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a rectangular gasoline tank can hold 50kg of gasoline when full what is the depth of the tank if it is 0.5m wide by 0.9m long ?relative density of gasoline is 0.75 live the answer in centimeters [p(water)=1000kgm -3meter cube

Answers

Given :

Mass of gasoline , m = 50 kg .

Length of tank , l = 0.9 m.

Breadth of tank , b = 0.5 m .

Relative density of gasoline , R.D = 0.75 .

Density of water , \(\rho_{water}=1000\ kg/m^3\) .

To Find :

The depth of tank .

Solution :

We know ,

\(R.D=\dfrac{\rho_{gasoline}}{\rho_{water}}\\\\\rho_{gasoline}=0.75\times 1000 \ kg/m^3\\\\\rho_{gasoline}=750\ kg/m^3\)

Now , volume of gasoline is :

\(V=\dfrac{m}{\rho_{gasoline}}\\\\V=\dfrac{50}{750}\ m^3\\\\V=\dfrac{1}{15}\ m^3\)

Since , the tank is rectangular , volume is given by :

\(V=l\times b\times h\\\\h=\dfrac{V}{l \times b}\\\\h=\dfrac{1}{15\times 0.9\times 0.5}\ m\\\\h=0.148\ m=14.8\ cm\)

Therefore , the answer in centimetres is 14.8 cm .

Hence , this is the required solution .

In a body undergoing deformation, the displacement at point P is given by [i(x 2 −yz)+j(2y−xz)+k(3z−x 2 y 2 )]×10 −3 mm here i,jξK are unit vectors in the cartesran coordinates Calculate "Eij" ε ij ​ (2,3,4)

Answers

Therefore, the strain tensor εij at point P (2, 3, 4) is:

ε11 = 2ε22 = 1ε33 = 3/2ε12 = ε21 = -4ε13 = ε31 = -39ε23 = ε32 = -2

To calculate the strain tensor εij at point P with coordinates (2, 3, 4), we need to differentiate the displacement vector with respect to the Cartesian coordinates. The strain tensor is defined as the symmetric part of the gradient of the displacement vector.

Given the displacement vector:

V = (i(x^2 - yz) + j(2y - xz) + k(3z - x^2y^2)) × 10^(-3) mm

We can calculate the strain tensor εij as follows:

εij = 1/2 * (dVi/dxj + dVj/dxi)

Taking the partial derivatives of V with respect to the Cartesian coordinates, we have:

dVx/dx = d/dx (x^2 - yz) = 2x

dVy/dy = d/dy (2y - xz) = 2

dVz/dz = d/dz (3z - x^2y^2) = 3

dVy/dx = d/dx (2y - xz) = -z

dVz/dx = d/dx (3z - x^2y^2) = -2xy^2

dVx/dy = d/dy (x^2 - yz) = -z

dVz/dy = d/dy (3z - x^2y^2) = -2x^2y

dVx/dz = d/dz (x^2 - yz) = -y

dVy/dz = d/dz (2y - xz) = -x

Substituting these values into the strain tensor equation:

ε11 = 1/2 * (2x + 0) = x

ε22 = 1/2 * (0 + 2) = 1

ε33 = 1/2 * (0 + 3) = 3/2

ε12 = ε21 = 1/2 * (-z - z) = -z

ε13 = ε31 = 1/2 * (-y - 2xy^2) = -y - xy^2

ε23 = ε32 = 1/2 * (-x - x) = -x

Plugging in the coordinates (2, 3, 4) into the strain tensor components:

ε11 = 2

ε22 = 1

ε33 = 3/2

ε12 = ε21 = -4

ε13 = ε31 = -3 - 4(3^2) = -39

ε23 = ε32 = -2

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A nutrunner on the engine assembly line has been faululing for low torque. (A nutrunner is an automated machine that automatically torques bolts to a specified condition.) When the fault odcurs, the line stops until someone can investigate or correct the issue. This has been a problem for the past two weeks, and all employees on the assembly line are having to work overtime each day to make up for the lost time from the nutrunner issues. Please explain and visualize the process you would take to solve or improve this problem.

Answers

A nutrunner on the engine assembly line has been failing for low torque. process includes identifying the root cause of the fault, and optimizing the nut runner's performance.

The first step would be to investigate the cause of the low torque issue in the nut runner. This may involve examining the machine, reviewing maintenance records, and gathering data on when and how the fault occurs. Once the root cause is identified, corrective actions can be taken. This may include repairing or replacing faulty components, recalibrating the nut runner, or updating software/firmware.

To prevent future occurrences, implementing a preventive maintenance program is crucial. Regular inspections, scheduled maintenance tasks, and performance testing can help identify and address potential issues before they lead to line stoppages. Additionally, providing thorough training to operators and maintenance staff on nutrunner operation, maintenance procedures, and troubleshooting techniques can contribute to quicker resolution of faults and reduce downtime.

Continuous monitoring of the nutrunner's performance is essential to ensure it operates within specified tolerances. This can be done through real-time data collection and analysis, including torque measurement and trend analysis. By closely monitoring the nutrunner's performance, any deviations or anomalies can be detected early, allowing for proactive interventions.

Overall, a systematic approach that combines investigation, preventive maintenance, employee training, and continuous monitoring can help solve the problem of the faulty nutrunner and improve the efficiency and productivity of the assembly line.

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A network has three independent file servers, each with 90 percent reliability. The probability that the network will be functioning correctly (at least one server is working) at a given time is:

Answers

Answer:

The correct answer is "99.9%".

Explanation:

According to the information given in the question,

\(P(1 \ fail) = 0.1\)

The probability of all fail will be:

\(P(all \ fail) = (0.1)^3\)

                  \(=0.001\)

hence,

\(P(not \ all \ fail)= 1-P(all \ fail)\)

                        \(=0.999\)

                        \(=99.9\) (%)

Thus the above is the right answer.

What’s the most important reason we should need a mask? Is the ban on removal of the mask requirement being implemented too fast in an area without general consensus (moral, political, cultural, technological)?

Answers

Answer:

What’s the most important reason we should need a mask?

we were because it protects us from germs and viruses.

Is the ban on removal of the mask requirement being implemented too fast in an area without general consensus (moral, political, cultural, technological)?

Face coverings limit the volume and travel distance of expiratory droplets dispersed when talking, breathing, and coughing.

Hope it helps!!!!!brainliest pls!!!!!!!!!

Match the following terms and identifying phrases.
1. Allow maximum operating speeds by reducing back pressure during cylinder extension or retraction.
2. Pneumatic control circuit that will hold an actuator in a selected position after only momentary input signal.
3. Reduce injuries by preventing inappropriate operation.
4. Also called an FRL unit.
5. Maximize system control Choose.
6. Hold circuit actuators momentarily to allow completion of a task.
7. Produce higher pressure needed in a small section of a system

a.Memory circuit b.Trio unit c.Logic functiond circuit d.Quick-exhaust valve e.Booster circuit f.Safety circuit h.Time-delay circuit

Answers

Based on the given terms and identifying phrases, the matching is as follows: Produce higher pressure needed in a small section of a system - e. Booster circuit

Pneumatic control circuit that will hold an actuator in a selected position after only momentary input signal - h. Time-delay circuit

Reduce injuries by preventing inappropriate operation - f. Safety circuit

Also called an FRL unit - b. Trio unit

Maximize system control - c. Logic function circuit

Hold circuit actuators momentarily to allow completion of a task - a. Memory circuit

Allow maximum operating speeds by reducing back pressure during cylinder extension or retraction - d. Quick-exhaust valve

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The Document is automatically shared with support when a ticket is created.

Answers

The following statement of the document is false.

What do you mean by document?

A document is a written, drawn, presented, or documented statement of ideas that frequently includes both non-fictional and fictitious content. The term comes from the Latin Documentum, which means "teaching" or "lesson": the verb doce means "to teach." Historically, the term was used to refer to written proof that may be used as evidence of a truth or reality. "Document" in the computer age usually refers to a mostly textual computer file, including its structure and format, such as fonts, colours, and graphics. Given the existence of electronic documents, the term "document" is no longer defined by its transmission medium, such as paper.

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vital role of maritime english among seaferers

Answers

Answer:

uehgeg7djw7heidiisosowiuisiejei2k

You are suggested to do an individual research collecting information related to
security risks and vulnerabilities associated with cloud computing in terms of data security, data center security, virtualization security and network security.

Answers

The practice of safeguarding company data and avoiding data loss due to illegal access is known as data security.

What is Research?

This entails safeguarding your data from assaults that can alter or damage it, as well as assaults that can encrypt or destroy it, like ransomware. Data security guarantees that data is accessible to everyone who needs it within the company.

For some industries to comply with data protection laws, a high level of data security is necessary. Healthcare businesses in the USA must safeguard private health information (PHI) in accordance with the HIPAA standard, for instance, and organizations that receive payment card information must utilize and retain payment card data securely.

However, even if your business is not bound by a rule or compliance standard, the sustainability of your organization depends on ability.

Therefore, The practice of safeguarding company data and avoiding data loss due to illegal access is known as data security.

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In what ways did electrical switches have to change to progress from the
huge ENIAC to the pocket-sized smartphone?
A. Electrical switches had to become less numerous and harder to
find.
B. Electrical switches had to become thicker and much stronger.
C. Electrical switches had to become less complicated and easier to
use.
D. Electrical switches had to become faster and much smaller.

Answers

Answer:

The answer is D. Electrical switches had to become faster and much smaller.

Explanation:

I just took the test on ~ap.ex and got it right :)

Equipment such as phones, fax machines, and computers are all examples of the_____ element of the business environment.

Answers

The equipment aspect of the corporate environment is exemplified by tools like phones, fax machines, and computers.

Equipment includes items like computers, vehicles, and processing equipment. They are tangible because they have a physical form, as opposed to intangible assets, which don't (such patents, trademarks, or copyrights), which are the things required for a specific activity or purpose. When we say "the set of goods you require for a certain function," we mean "the uncountable noun equipment," such as tools or clothing: New sleeping bags and a small refrigerator are among the camping supplies we've purchased. They are the most fundamental methods for employing leverage (or mechanical advantage) to increase force that are currently understood. Simple machines include the wheel and axle, inclined plane, lever, wedge, pulley, and screw basic machines

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An insulated piston-cylinder device initially contains 300 L of air at 120 kPa and 17°C. Air is now heated for 15 min by a 200 W resistance heater placed inside the cylinder. The pressure of air is maintained constant during this process. Determine the entropy change of air, assuming (a) constant specific heats and (b) variable specific heats.
a) AS sys= ____ kJ/k
b) As sys=____ kJ/K

Answers

The entropy changes in the system when there are constant specific heats and variable specific heats are found out to be

a) ASsys= 2.20 kJ/K

b) ASsys= 1.56 kJ/K respectively.

(a) Constant Specific Heat

To solve the problem, use the following formula:

ASsys = Cv ln(T₂/T₁)+R ln(V₂/V₁)

ASsys = [Cv ln(T₂/T₁)] + [R ln(V₂/V₁)]

where: ASsys= system entropy change

R = 0.287 kJ/kg.K

Cv = 0.717 kJ/kg.K

T₁ = 17 + 273 = 290 K (initial temperature)

P₁ = 120 kPa (constant pressure)

P₂ = 120 kPa (constant pressure)

V₁ = 300 L

= 0.3 m³ (initial volume)

V₂ = V₁ [since V is constant]

= 0.3 m³

T₂ = T₁ + q/Cp

where q= amount of heat added

Cp= specific heat of air at constant pressure

From the given data,

Q= P x V

= 120 kPa x 0.3 m³

= 36 kJ

Q/Δt = 200 W

= 200 J/s

Cp= 1.005 kJ/kg.K

[Table A-2, at 17°C, for air]

T₂ = (q/Cp) Δt + T₁

= (200/1.005) x 900 + 290

= 692 K

Now apply the formula for system entropy change.

ASsys = Cv ln(T₂/T₁)+R ln(V₂/V₁)

= 0.717 x ln(692/290) + 0.287 x ln(0.3/0.3)

= 2.20 kJ/K

(b) Variable Specific Heat

To solve the problem, use the following formula:

ASsys = ∫(Cp/T)dT- R ln(V₂/V₁)

whereASsys= system entropy change

ΔT= T₂ - T₁

= (692-290)

= 402 K

R= 0.287 kJ/kg.K

V₁ = V₂

= 0.3 m³

Using the data from Table A-2, Cps and T can be tabulated as:

Cp (kJ/kg.K)T (K)1.0052731.005284.16 (Note: T₂)1.005692

Apply the trapezoidal rule for the integral to get:

ASsys = ∫(Cp/T)dT- R ln(V₂/V₁)

= 0.287[(1.005273/290) + (1.005284.16/273) + (1.005692/692)]- 0.287 ln(0.3/0.3)

= 1.56 kJ/K

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Which of the following occupations is the most physically dangerous?
O electrician
O Ironworker
O boilermaker
O cement mason

Answers

Answer:Ironworker

Explanation:

Their work is totally physical and lead they get hampered by lead most

Answer:

answer:ironworker

Explanation:

they can be hampered and can also get severely injured.

Tech A says that air tools and equipment require a regular application of a lubricating oil to reduce wear and tear. Tech B says that some compressed air systems use an inline water trap that needs to be drained periodically. Who is correct?

Answers

Incomplete question. The options read;

A. Tech A

B. Tech B

C. Both A and B

D. Neither A nor B.

Answer:

C. Both A and B

Explanation:

Technician B is correct because the technician highlighted valid reasons why draining the compressed air systems is important.

For example, since this system helps to absorb moisture or oil from storage areas they thus need to be drained periodically in other to allow for more absorption space.

Also, the reasons mentioned by Technician A are of course correct because it is generally believed that the application of lubricants such as oil helps to reduce wear and tear.

If, for a particular junction, the acceptor concentration is 1017/cm3 and the donor concentration is 1016/cm3, find the junction built-in voltage. Assume ni = 1.5 × 1010/cm3. Also, find the width of the depletion region (W) and its extent in each of the p and n regions when the junction terminals are left open. Calculate the magnitude of the charge stored on either side of the junction. Assume that the junction area is 10 µm2.

Answers

Answer:

A) V_o = 0.7543 V

B) W = 328.42 nm

C) X_n = 298.56 nm and X_p = 29.86 nm

D) Q_j = 47.767 × 10^(-15)

Explanation:

We are given;

Acceptor concentration; N_A = 10^(17) /cm³

donor concentration; N_D = 10^(16) /cm³

ni = 1.5 × 10^(10) /cm3

A) The formula for the built - in - voltage at the junction is given by;

V_o = V_T(In (N_A × N_D/ni²))

Where V_T is thermal voltage at room temperature with a value from online sources as 25.9 mV

Thus;

V_o = 25.9(In (10^(17) × 10^(16))/(1.5 × 10^(10))²

V_o = 0.7543 V

B) Now, formula for the width of the depletion region (W)is given as;

W = √(2ε_s/q[(1/N_A) + (1/N_D)]V_o)

Where;

ε_s is the permittivity in the semiconductor with a constant value of 1.04 × 10^(-12) F/cm

q is the electron charge = 1.6 × 10^(-19) C

Thus;

W = √(2 × 1.04 × 10^(-12)/(1.6 × 10^(-19)) [(1/10^(17)) + (1/10^(16)]0.7543)

W = 32.842 × 10^(-6) cm

Converting to m gives;

W = 328.42 nm

C) Formula for extent of the n region is;

X_n = W × (N_A/(N_A + N_D))

X_n = 32.842 × 10^(-6) × (10^(17)/(10^(17) + 10^(16))

X_n = 29.856 × 10^(-6) cm

Converting to m gives;

X_n = 298.56 nm

Formula for extent of the p region is;

X_p = W - X_n

X_p = 328.42 nm - 298.56 nm

X_p = 29.86 nm

D) The charge stored on either side of the junction is given by the formula;

Q_j = Aq[(N_A × N_D)/(N_A + N_D)]W

Where A is junction Area and we are given junction area as 10 µm² = 100 × 10^(-8) cm

Thus;

Q_j = (100 × 10^(-8) × 1.6 × 10^(-19))[(10^(17) × 10^(16))/(10^(17) + 10^(16)] × 32.842 × 10^(-6)

Q_j = 47.767 × 10^(-15)

Although not limited by the NEC, if a 15-amp residential circuit is to be loaded only up to its rating, how many outlets can be put on the 120-volt circuit if the outlets are rated at 120 VA per outlet? Select one: a. 15 b. 1 c. 20 d. 8 e. 9

Answers

Although not limited by the NEC, if a 15-amp residential circuit is to be loaded only up to its rating, The number of outlets that can be put on the 120-volt circuit if the outlets are rated at 120 VA per outlet are 15 (Option A).

What is a residential circuit?

These are similar to the wire systems in your home, but they can be as large as the power lines outside. Power circuits are required when a considerable volume of electricity has to be transmitted and managed.

The majority of your home's typical 120-volt domestic circuits are (or should be) parallel circuits. Outlets, switches, and light fixtures are connected such that the hot and neutral wires form a continuous circuit pathway separate from the various devices that consume electricity from the circuit.

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Consider a pendulum system, which is a point mass m swinging on a mass-less rod of length l. For the simulation, use the values m = 1kg and l = 1m. the equation referred to in part b is this: d2ϕ/dt2 = -mg/l * sin(ϕ). (b). Now introduce the following two variables: We clearly have the relation x, -x2. Determine the expression for x using the differential equation you derived before.

Answers

For a pendulum system, which is a point mass m swinging on a mass-less rod of length l, the expression for x using the differential equation is:

x = -(l^2/g) * d^2ϕ/dt^2.

To determine the expression for x using the differential equation for the pendulum system, we'll consider the relation between the variables x and ϕ.

In the pendulum system, the variable x represents the displacement of the pendulum mass along the horizontal axis. We can relate x to the angular displacement ϕ using the length of the pendulum rod (l) and trigonometric relations.

From the geometry of the pendulum, we know that x = l * sin(ϕ). This equation represents the relation between the displacement along the x-axis and the angular displacement ϕ.

To express x in terms of the differential equation for the pendulum system, we can substitute this relation into the equation:

d^2ϕ/dt^2 = -(g/l) * sin(ϕ)

Replacing x with l * sin(ϕ) gives:

d^2ϕ/dt^2 = -(g/l) * x / l

Simplifying, we have:

d^2ϕ/dt^2 = -(g/l^2) * x

So, the expression for x using the differential equation is:

x = -(l^2/g) * d^2ϕ/dt^2

Note that in this expression, x represents the displacement of the pendulum mass along the x-axis, while d^2ϕ/dt^2 represents the second derivative of the angular displacement ϕ with respect to time.

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A compressible fluid flows through a compressor that increases the density from 1 kg/m3 to 5 kg/m3. The cross-sectional area of the inlet pipe is 3 m2 and that of the discharge pipe is 1 m2. The relation between the discharge volume flow rate and the inlet volume flow rate is

Answers

Answer:

The relation between the discharge volume flow rate and the inlet volume flow rate is \(\frac{1}{5}\).

Explanation:

No matter if fluid is compressible or not, mass throughout compressor, a device that works at steady state, must be conserved according to Principle of Mass Conservation:

\(\dot m_{in}-\dot m_{out} = 0\) (Eq. 1)

Where \(\dot m_{in}\) and \(\dot m_{out}\) are mass flows at inlet and outlet, measured in kilograms per second.

After applying Dimensional analysis, we expand the equation above as follows:

\(\rho_{in}\cdot \dot V_{in} - \rho_{out}\cdot \dot V_{out} = 0\) (Eq. 2)

Where:

\(\rho_{in}\), \(\rho_{out}\) - Fluid densities at inlet and outlet, measured in kilograms per cubic meter.

\(\dot V_{in}\), \(\dot V_{out}\) - Volume flow rates at inlet and outlet, measured in cubic meters per second.

After some algebraic handling, we find the following relationship:

\(\rho_{out}\cdot \dot V_{out} = \rho_{in}\cdot \dot V_{in}\)

\(\frac{\dot V_{out}}{V_{in}} = \frac{\rho_{in}}{\rho_{out}}\) (Eq. 3)

If we know that \(\rho_{in} = 1\,\frac{kg}{m^{3}}\) and \(\rho_{out} = 5\,\frac{kg}{m^{3}}\), then the relation between the discharge volume flow rate and the inlet volume flow rate is:

\(\frac{\dot V_{out}}{\dot V_{in}} = \frac{1\,\frac{kg}{m^{2}} }{5\,\frac{kg}{m^{3}} }\)

\(\frac{\dot V_{out}}{\dot V_{in}} = \frac{1}{5}\)

The relation between the discharge volume flow rate and the inlet volume flow rate is \(\frac{1}{5}\).

Which of the following is an example of someone who claims that the media has a shooting blanks effect?

A. "Along with parents, peers, and teachers, the media socializes children about how boys and girls are supposed to behave."

B. "My kid saw a cigarette ad in a magazine and now he's smoking. It's the magazine's fault!"

C. "The media doesn't affect me at all because I'm smart enough to know the difference between right and wrong."

D. "There is no definitive evidence that the media affects our behavior"

Answers

Answer:

the answer would be d its d

Answer:

Pretty sure the answer is "C"

Explanation:

"The media doesn't affect me at all because I'm smart enough to know the difference between right and wrong."

A low-altitude meteorological research balloon, temperature sensor, and radio transmitter together weigh 2.5 lb. When inflated with helium, the balloon is spherical with a diameter of 4 ft. The volume of the transmitter can be neglected when compared to the balloon's size. The balloon is released from ground level and quickly reaches its terminal ascent velocity. Neglecting variations in the atmosphere's density, how long does it take the balloon to reach an altitude of 1000 ft?

Answers

Answer:

12 mins

Explanation:

The summation of the forces in vertical direction

= Fb - Fd - w = 0 ∴ Fd = Fb - w  ----- ( 1 )

Fb ( buoyant force ) = Pair * g * Vballoon ------- ( 2 )

Pair = air density , Vballoon = volume of balloon

Vballoon = \(\frac{\pi D^3}{6}\) ,  where D = 4  ∴  Vballoon = 33.51 ft^3

g = 32.2 ft/s^2

From property tables

Pair = 2.33 * 10^-3 slug/ft^3

μ ( dynamic viscosity ) = 3.8 * 10^-7 slug/ft.s

Insert values into equation 2

Fb = ( 2.33 * 10^-3 ) * ( 32.2 ) *( 33.51 )  = 2.514 Ib

∴ Fd = 2.514 - 2.5 = 0.014 Ib ( equation 1 )

Assuming that flow is Laminar  and  RE < 1

Re = (Pair * vd) / μair   -------- ( 3 )

where:  Pair = 2.33 * 10^-3 slug/ft^3 ,  vd = ( 987 * 4 ) ft^2/s ,   μair = 3.8 * 10^-7 slug/ft.s

Insert values into equation 3

Re = 2.4 * 10^7 (  this means that the assumption above is wrong )

Hence we will use drag force law

Assume Cd = 0.5

Express  Fd using the relation below

Fd = 1/2* Cd * Pair * AV^2

therefore V = 1.39 ft/s

Recalculate  Reynold's number using  v = 1.39 ft/s

Re = 34091

from the figure Cd ≈ 0.5 at Re = 34091  

Finally calculate the rise time ( time taken to reach an altitude of 1000 ft )

t = h/v

  = 1000 / 1.39 = 719 seconds ≈ 12 mins

A low-altitude meteorological research balloon, temperature sensor, and radio transmitter together weigh

be expensed. Required: Conceptual Connection: Classify each cost as part of the overhaul or as an expense. New pump motor Repacking of bearings (performed monthly) New impeller (rotating component of a pump) Painting of pump housing (performed annually) Replacement of pump foundation New wiring (needed every 5 years) Installation labor, motor Installation labor, impeller Installation labor, wiring Paint labor (performed annually) Placement of fence around pump* (

A requirement of the Occupational Safety and Health Administration that will add to maintenance costs over the remaining life of the pump.)

Answers

The classification of each cost as part of an overhaul or as an expense depends on the nature of the cost and its purpose in maintaining or restoring the pump's functionality and efficiency.

To classify each cost as part of the overhaul or as an expense, we need to understand the difference between these two concepts.

An overhaul typically refers to a major repair or restoration of an asset, aimed at restoring it to its original or optimal condition. Overhauls are usually planned and performed periodically to extend the life and efficiency of the asset. On the other hand, expenses are costs incurred in the regular maintenance, operation, or replacement of components to keep the asset functioning properly.

Based on this understanding, let's classify each cost mentioned:

1. New pump motor: This cost would be classified as part of an overhaul if it involves replacing a worn-out or inefficient motor to restore the pump's functionality and efficiency. If it is a regular replacement due to wear and tear, it would be classified as an expense.

2. Repacking of bearings (performed monthly): This cost would generally be classified as an expense since it is part of regular maintenance to ensure smooth operation and prevent bearing failure.

3. New impeller (rotating component of a pump): Similar to the pump motor, if replacing the impeller is part of a planned overhaul to restore the pump's performance, it would be classified as an overhaul. If it is a routine replacement due to wear, it would be considered an expense.

4. Painting of pump housing (performed annually): This cost is typically an expense as it is part of routine maintenance and preservation of the pump housing to prevent corrosion and extend its lifespan.

5. Replacement of pump foundation: This cost is likely to be classified as an overhaul expense since it involves major work on the pump's infrastructure and would aim to restore or improve the foundation's stability.

6. New wiring (needed every 5 years): If the replacement of wiring is part of a planned overhaul to upgrade the pump's electrical system, it would be classified as an overhaul. Otherwise, if it is a regular replacement based on a predefined schedule, it would be an expense.

7. Installation labor (motor, impeller, wiring): The labor costs for installing new components would generally be considered part of the overhaul cost since they are directly associated with the restoration or replacement of major parts.

8. Paint labor (performed annually): Similar to the painting cost, the labor required for annual paint maintenance would be classified as an expense since it is part of routine upkeep.

9. Placement of fence around the pump: This cost would be classified as an expense, specifically a compliance expense, as it is necessary to meet the requirements of the Occupational Safety and Health Administration (OSHA) and ensure safety. It does not directly relate to the overhaul or restoration of the pump.

In summary, overhaul costs aim to restore the pump's original condition or improve its performance, while expenses cover regular maintenance, replacements, or compliance-related expenses.

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