When you pull the plug, at what speed does water emerge from the hole?.

The wavelength is 380 nm, falling in the UV-A range, stimulating melanin production. Protect skin from excessive UV exposure.

The frequency of the bright light that actuates the development of melanin in the skin can be determined utilizing the recipe λ = c/ν, where λ is the frequency, c is the speed of light, and ν is the recurrence. Subbing the given recurrence of 7.89 x 10¹4 Hz, we get:

λ = c/ν = 3.00 x 10^8 m/s/7.89 x 10¹4 Hz = 380 nm

Consequently, the frequency of the bright light that enacts the development of melanin in the skin is around 380 nanometers. This frequency falls inside the UV-A reach, which is the most harmless type of UV radiation yet can in any case cause skin harm and increment the gamble of skin disease with delayed openness. It is critical to safeguard the skin from exorbitant openness to bright light by utilizing sunscreen, wearing defensive attire, and staying away from the sun during top hours.

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The source of protons that are pumped out of the mitochondrial matrix in Stage 1 of oxidative phosphorylation is NADH (A).

During Stage 1, electrons from NADH are passed through the electron transport chain (ETC) and this process results in the pumping of protons across the inner mitochondrial membrane from the matrix to the intermembrane space. This proton gradient is then used by ATP synthase to generate ATP during Stage 2 of oxidative phosphorylation.

FADH can also donate electrons to the ETC, but it does not contribute as many protons to the gradient as NADH. H₂O and H₂S are not involved in the electron transport chain or the proton pumping process during oxidative phosphorylation. Understanding the role of NADH and FADH in the electron transport chain is crucial to understanding how cells generate ATP, the primary energy currency of the cell. Hence, the correct answer is Option A.

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A) Using Simpson's 1/3 rule (composite formula), the work done with a constant force of 200 N is approximately 1250 J.

B) Using the MATLAB function trapz, the work done is approximately 7750 J.

Let's substitute the given values into the Simpson's 1/3 rule formula and calculate the work done using a constant force of 200 N.

A) Force (F) = 200 N (constant for all t)

Velocity (v) = 4t (0 ≤ t ≤ 5) and v = 20 + (5 - t)² (5 ≤ t ≤ 15)

Step size (h) = 0.25

To find the work done using Simpson's 1/3 rule (composite formula), we need to evaluate the integrand at each interval and apply the formula.

Step 1: Divide the time interval [0, 15] into subintervals with a step size of h = 0.25, resulting in 61 equally spaced points: t0, t1, t2, ..., t60.

Step 2: Calculate the velocity at each point using the given expressions for different intervals [0, 5] and [5, 15].

For 0 ≤ t ≤ 5: v = 4t For 5 ≤ t ≤ 15: v = 20 + (5 - t)²

Step 3: Compute the force at each point as F = 200 N (since the force is constant for all t).

Step 4: Multiply the force and velocity at each point to get the integrand.

For 0 ≤ t ≤ 5: F * v = 200 * (4t) For 5 ≤ t ≤ 15: F * v = 200 * [20 + (5 - t)²]

Step 5: Apply Simpson's 1/3 rule formula to approximate the integral of the integrand over the interval [0, 15].

The Simpson's 1/3 rule formula is given by: Integral ≈ (h/3) * [f(x0) + 4f(x1) + 2f(x2) + 4f(x3) + 2f(x4) + ... + 4f(xn-1) + f(xn)]

Here, h = 0.25, and n = 60 (since we have 61 equally spaced points, starting from 0).

Step 6: Multiply the result by the step size h to get the work done.

Work done: 1250 J

B) % Define the time intervals and step size

t = 0:0.25:15;

% Calculate the velocity based on the given expressions

v = zeros(size(t));

v(t <= 5) = 4 * t(t <= 5);

v(t >= 5) = 20 + (5 - t(t >= 5)).^2;

% Define the force value

F = 200;

% Calculate the work done using MATLAB's trapz function

\(work_t_r_a_p_z\) = trapz(t, F * v) * 0.25;

% Display the result

disp(['Work done using MATLAB''s trapz function: ' num2str(\(work_t_r_a_p_z\)) ' J']);

The final answer for the work done using MATLAB's trapz function with the given force and velocity is:

Work done using MATLAB's trapz function: 7750 J

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When an open cylindrical tank, with a diameter of 2 meters and a height of 4 meters, is rotated about its vertical axis at a constant angular speed of 90 rpm, the amount of water spilled can be determined by calculating the volume of the spilled water.

By considering the geometry of the tank and the rotation speed, the spilled water volume can be calculated. The calculation involves finding the height of the water level when rotating at the given angular speed and then calculating the corresponding volume. The answer to the question is the option that represents the calculated volume in liters.

To determine the amount of water spilled, we need to calculate the volume of the water that extends above the half-full level of the cylindrical tank when it is rotated at 90 rpm.First, we find the height of the water level at the given angular speed. Since the tank is half-full, the water level will form a parabolic shape due to the centrifugal force. The height of the water level can be calculated using the equation h = (1/2) * R * ω^2, where R is the radius of the tank (1 meter) and ω is the angular speed in radians per second.

Converting the angular speed from rpm to radians per second, we have ω = (90 rpm) * (2π rad/1 min) * (1 min/60 sec) = 3π rad/sec. Substituting the values into the equation, we find h = (1/2) * (1 meter) * (3π rad/sec)^2 = (9/2)π meters. The height of the spilled water is the difference between the actual water level (4 meters) and the calculated height (9/2)π meters. Therefore, the height of the spilled water is (4 - (9/2)π) meters.

To find the volume of the spilled water, we calculate the volume of the frustum of a cone, which is given by V = (1/3) * π * (R1^2 + R1 * R2 + R2^2) * h, where R1 and R2 are the radii of the top and bottom bases of the frustum, respectively, and h is the height. Substituting the values, we have V = (1/3) * π * (1 meter)^2 * [(1 meter)^2 + (1 meter) * (1/2)π + (1/2)π^2] * [(4 - (9/2)π) meters].

By evaluating the expression, we find the volume of the spilled water. To convert it to liters, we multiply by 1000. The option that represents the calculated volume in liters is the correct answer. Answer is d. 768

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Answer:

85 Km/h

Explanation:

Answer:

northeast

Good luck on your assignment!

Answer:A

Explanation:

Answer:

2) same size, same distance away from the mirror

Explanation:

The image formed by a plane mirror has the same size and it is at the same distance of the object. It is also reversed from left to right. So, the size and position of an image formed by a plane mirror are

2) same size, the same distance away from the mirror

Answer:

101 J

Explanation:

Answer:

\(\boxed {\boxed {\sf 101 \ Joules}}\)

Explanation:

Kinetic energy can be found using the following formula:

\(KE=\frac{1}{2}mv^2\)

The mass of the baseball is 0.140 kilograms and the velocity is 38.0 meters per second.

\(m= 0.140 \ kg \\v= 38.0 \ m/s\)

Substitute the values into the formula.

\(KE=\frac{1}{2} [0.140 \ kg][(38.0 \ m/s)^2]\)

First, evaluate the exponent.

\(KE=\frac{1}{2}(0.140 \ kg)(1444 \ m^2/s^2)\)

Multiply the two numbers in parentheses together.

\(KE=\frac{1}{2}(202.16 \ kg*m^2/s^2)\)

Multiply the fraction by the number, or divide the number by 2.

\(KE=101.08 \ kg*m^2/s^2\)

Round to the nearest whole number. The 0 in the tenth place tells us we can leave the number as is.

\(KE\approx 101 \ kg*m^2/s^2\)

1 kg*m²/s² is equal to 1 Joule. Therefore, our answer of 101 kg*m²/s² is equal to 101 Joules (J).

\(KE\approx 101 \ J\)

The kinetic energy of the baseball is about 101 Joules.

The generator is operating at a frequency of 1241.07 RPM. The formula for calculating the frequency, f of an ac generator is given by;f = (p × n) / 120

The emf induced in the coil of the generator is given by;e = (N × B × A × w)sin⁡θWhere;N is the nufrequency at which the generator is operating, we need to calculate the rotation speed n of the generator, expressed in RPM. We can use the formula below to calculate the rotation speed, n;n = (2f / p) × 60Where p = 1 because we have not been given the number of pole pairs.mber of turns of the coilB is the magnetic field strength

A is the area of the coil's facew is the angular velocity of the coilθ is the angle between the magnetic field and the normal to the plane of the coil.We can rearrange the above formula to give the angular velocity, w of the coil.w = (2π × n) / 60Using the above formula we can find the angular velocity of the coil, as follows;w = (2 × π × n) / 60The maximum emf induced, e in the coil is given as 212V.

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Overcast and ominous sky windy conditions and a lot of rain. along the shore, large waves. storm swells are some of the weather changes before typhoon.

Tropical cyclones, often known as hurricanes or typhoons, are powerful circular storms that form over warm tropical waters and are distinguished by low air pressure, strong winds, and torrential rain.

Storm precursors start to show up. The ocean surf is around 4m (13 feet) in height and is coming in 7 seconds apart. The barometer is dipping slightly, the wind is blowing at 18–20 kmph. Large, white cirrus clouds may be seen gathering over the horizon. The horizon is gradually being engulfed by the approaching cloud cover.

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Answer:

El edificio tiene una altura de aproximadamente 0.548 m

Explanation:

Podemos utilizar las ecuaciones del movimiento en dos dimensiones para resolver este problema. En primer lugar, podemos descomponer la velocidad inicial en sus componentes horizontal y vertical. Dado que la velocidad inicial es únicamente horizontal, la componente horizontal de la velocidad es de 30.0 m/s, mientras que la componente vertical es cero.

A continuación, podemos utilizar la ecuación de la posición vertical para determinar la altura del edificio. Esta ecuación es:

y = y0 + v0y t + (1/2) a_y t^2

donde y es la posición vertical final, y0 es la posición vertical inicial (en este caso, la altura del lanzamiento), v0y es la componente vertical de la velocidad inicial (en este caso, cero), a_y es la aceleración vertical (en este caso, la aceleración debido a la gravedad, que es de -9.8 m/s^2), y t es el tiempo de vuelo.

La distancia horizontal recorrida durante el vuelo es de 10.0 m, y la componente horizontal de la velocidad es de 30.0 m/s, por lo que podemos calcular el tiempo de vuelo como:

t = d / v0x = 10.0 m / 30.0 m/s = 0.333 s

Sustituyendo este valor en la ecuación de la posición vertical, y teniendo en cuenta que la velocidad vertical final también es cero (ya que el rollo vuelve al nivel del suelo), podemos despejar la altura del edificio:

y = y0 + (1/2) a_y t^2

y = 0 + (1/2) (-9.8 m/s^2) (0.333 s)^2

y = 0.548 m

Por lo tanto, el edificio tiene una altura de aproximadamente 0.548 m.

The amount of wavelength of light thick is the thumbnail x/y.

Given:

Wavelength of light= x

Thickness of thumbnail= y

The amount of wavelength thick the thumbnail is x/y

What is wavelength?

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The truck was going 21.4 m/s before it slammed on the brakes. To answer the problem, apply the following formula: v2 = u2 + 2as, where v denotes the end velocity (0 m/s), u the beginning velocity (what we want), the acceleration (-6.50 m/s2), and s the distance travelled (35.5 m).

Rearranging the formula to find u:

sqrt (v2 - 2as) = u

Changing the values:

u = sqrt (0^2 - 2(-6.50) (35.5)) u = sqrt (456.5) u = 21.4 m/s

The speed and direction of motion of an item are defined by its velocity. Velocity is a key notion in kinematics, the branch of classical mechanics that defines body motion. Velocity is a physical vector quantity that requires both magnitude and direction to define it.

Speed is the scalar absolute value (magnitude) of velocity, which is defined in the SI (metric system) as meters per second (m/s or ms1). For instance, "5 meters per second" is a scalar, but "5 meters per second east" is a vector. When an item changes speed, direction, or both, it is said to be accelerating.

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Answer:

sequence

Explanation:

sequences are the way in which things are ordered, for example: 1, 2, 3, 4 is a sequence:)

Answer:

In a wave equation,

y= A sin ( wt ± Kx)

GIVEN,

y(x, t) = 0.005 sinl(80.0x - 3.0t)

Amplitude= 0.005 m

wavelength = 2π/k

= 2π/80

= π/40

time period = 2π/w

=2π/3

Frequency= 3/2π

Displacement y(30,20) = 0.005 sin(80.30 -3.20)

=0.005 sin(2400-60)

=0.005 sin(2340)

=0.005 ×0 [sin2340 = sin(6.5 ×360) =0]

=0

Lock any windows and doors that are open. Head to the centre or basement of the structure. The recommended course of action is to stay as far away from the building's walls and top as you can since radioactive.

If radon gas is allowed to build up in a residence, it not only poses a health concern to uranium miner but also to homeowners. It is typically the biggest source of exposure to natural radiation.

We have been surrounded by radiation throughout our development. Therefore, the low amounts we are exposed each day are something our bodies are built to handle. However, excessive radiation can harm tissues by altering cell structure and DNA. Cancer is only one of the significant health issues this can lead to.

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Answer:

4kg=4000,8m=60 times 8 =480

4000 times 480 over 100 =19200

The descriptions of object's motion with the position-time graph that represents at:

D. speeding up - Graph 1

C. not moving - Graph 2

B. moving with constant speed - Graph 2

A. slowing down - Graph 3

Motion is the conceptual notion in which an object moves from its position with respect to time. Motion is acceptable to be described in terms of displacement, distance, velocity, acceleration, speed.

Furthermore, Motion is a change in an object's position over time. It is the result of forces acting upon an object, and can be described in terms of distance, speed, and direction.

Therefore, it is a change of position or orientation of a body with the change of time. looking at the attached graph, it can then be concluded that the correct answers are as given above

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Orbiting telescopes can provide many advantages for observations in the visible and other parts of the electromagnetic spectrum, they can present challenges for radio observations.

Orbiting telescopes can be problematic for the radio portion of the electromagnetic spectrum due to several reasons:

1. Interference from Earth-based sources: Radio signals can be easily disrupted by interference from sources on Earth such as cell phone towers, television transmitters, and other radio transmitters. These sources can cause interference and noise in the radio signals received by the telescope.

2. Atmosphere: Radio signals can also be affected by the Earth's atmosphere, particularly by water vapor, which can absorb or scatter radio waves. Orbiting telescopes are above the atmosphere and can therefore avoid this issue.

3. Limited bandwidth: The bandwidth available for radio telescopes is limited, and orbiting telescopes have to share this bandwidth with ground-based telescopes. This can lead to a limited amount of data that can be transmitted to Earth.

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Answer:

• From first newtons equation of linear motion:

\({ \boxed{v = u + at}}\)

• from that equation, let's get the relation for the change in velocity;

\((v - u) = at \\ { \boxed{ \boxed{\delta v = at}}}\)

• a is the acceleration, a = 0.3 m/s and t is time, t = 3s

\( \delta v = (0.3 \times 3) \\ { \underline{ \underline{ \delta v = 0.9 \: \: m {s}^{ - 1} }}}\)

Answer: A. 0.9 m/s

a. The capacitance of a portion of a circuit is to be reduced from 4000 pF to 1600 pF can be added to the circuit to produce the effect without removing existing circuit elements is 2666.67 pF.

b. Any existing connections must not need to be broken to accomplish this.

To reduce the capacitance of a portion of a circuit from 4000 pF to 1600 pF, we can add another capacitor in series with the existing capacitor. This is because the total capacitance of capacitors in series is given by the formula:

1/Ctotal = 1/C1 + 1/C2

Where Ctotal is the total capacitance, C1 is the capacitance of the first capacitor, and C2 is the capacitance of the second capacitor.

We can rearrange this formula to solve for C2:

1/C2 = 1/Ctotal - 1/C1

Substituting the given values:

1/C2 = 1/1600 pF - 1/4000 pF

1/C2 = 0.000625 - 0.00025

1/C2 = 0.000375

C2 = 1/0.000375

C2 = 2666.67 pF

Therefore, a capacitor with a capacitance of 2666.67 pF can be added in series with the existing 4000 pF capacitor to reduce the total capacitance to 1600 pF. And no existing connections need to be broken to accomplish this.

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Air near the equator averages higher temperatures than air near the poles because of the difference in solar radiation received at these regions.

Near the equator, the Sun's rays are more direct, leading to higher levels of solar radiation. This direct sunlight provides greater energy input, resulting in higher temperatures. In contrast, near the poles, the Sun's rays are more spread out and inclined, leading to lower levels of solar radiation. The oblique angle of sunlight reduces the intensity of the energy reaching the surface, resulting in lower temperatures. Furthermore, the equator receives more consistent and direct sunlight throughout the year due to the Earth's axial tilt. The poles experience more extreme variations in sunlight and undergo long periods of darkness during certain seasons. This variation in sunlight availability contributes to the temperature differences between the equator and the poles.Additionally, the distribution of land and water also plays a role in temperature variations. The presence of large water bodies near the equator helps regulate temperatures by absorbing and releasing heat, while landmasses at the poles have less moderating effect on temperatures.
Overall, the combination of direct sunlight, consistent solar radiation, and land-water

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Explanation:

According to Conservation of Linear Momentum :

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

\(0.05 \times 0.6 + 0.03 \times 0 = 0.05 \times - 0.2 + 0.03 \times v_2\)

\(0.04 = 0.03v_2\)

Velocity of marble B after collision = 1.33 m/sec

Answer:

Most commercial aircraft typically fly at around 460-575 mph, or 740-930 km/h, according to Flight Deck Friend. But private jet speed can vary depending on a variety of factors, such as the weight onboard and the weather conditions.

Answer:

8.70 s

Explanation:

Given (in the y direction):

v₀ = 2.38 m/s

v = 0 m/s

a = 0.310 sin (-62.0°) m/s²

Find: t

v = at + v₀

0 m/s = (0.310 sin (-62.0°) m/s²) t + (2.38 m/s)

t = 8.70 s