A rock is an
of minerals.

Answer:

True

Explanation:

Neutral solutions maintain a pH of 7. Water and human blood are great examples of neutral solutions. Acids mixed with bases can be neutralized and given a pH of 7.

Answer:

C. Weak nuclear force

Explanation:

The weak force is responsible for radioactive decay and neutrino interactions. It has a very short range and. As its name indicates, it is very weak. The weak force causes Beta-decay ie. the conversion of a neutron into a proton, an electron and an antineutrino.

Answer:

neutral

Explanation:

pH is usually (but not always) between 0 and 14. Knowing the dependence of pH on [H +], we can summarize as follows: If pH < 7, then the solution is acidic. If pH = 7, then the solution is neutral

The equation that relates A and W, considering the desired 15% acetic acid concentration, is 3W = 2.55M.

The equation A = (3/17)W represents the relationship between the mass of acetic acid (A) and the mass of water (W) in the mixture. It states that the mass of acetic acid is equal to three seventeenths (3/17) of the mass of water.

Since the company wants the acetic acid to be 15% of the total mass of the mixture, we can set up another equation to represent this requirement. Let M be the total mass of the mixture. The mass of acetic acid (A) is 15% of the total mass, so we have A = 0.15M.

Now we can substitute A in terms of W from the first equation into the second equation: (3/17)W = 0.15M. We can simplify this equation by multiplying both sides by 17 to get 3W = 2.55M.

This equation allows the company to calculate the mass of water (W) required for a given mass of acetic acid (A) to maintain the desired concentration in the mixture.

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Answer:

Cobalt

Explanation:

From the question given above, the following data were obtained:

Electronic configuration of element => 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d⁷

Name of the Element =?

Next, we shall determine the number of electrons in the atom of the element. This can be obtained as follow:

Number of electron = 2 + 2 + 6 + 2 + 6 + 2 + 7

Number of electron = 27

Next, we shall determine the number protons in the atom of the element. This can be obtained as follow:

For a ground state element,

Number of Proton = number of Electron

Number of electrons = 27

Number of proton = Number of electron = 27

Number of protons = 27

Therefore, the number of protons in the atom of the element is 27

Next, we shall determine the atomic number of the element. This can be obtained as follow:

The atomic number of an element is simply the number of protons in the atom of the element. Mathematically,

Atomic number = proton number

Number of proton = 27

Finally, we shall determine the name of the element as follow:

Comparing the atomic number of the element (i.e 27) with those in the periodic table, the element is Cobalt since no two elements have the same atomic number.

A 50.0 mL solution of 0.250 M HC₂H₃O₂ before and after adding 50 mL of 0.250 M NaOH has a pH of 2.87, the pH changes due to the formation of a buffer solution, which can be calculated using the Henderson-Hasselbalch equation.

This problem requires us to calculate the pH of a buffer solution after the addition of a strong base. A buffer solution is one that resists pH changes when modest amounts of acid or base are added. The buffer system in this case is the weak acid, acetic acid (HC₂H₃O₂) and its conjugate base, acetate ion (C₂H₃O₂-).

Before the addition of NaOH, we have a solution of 0.250 M HC₂H₃O₂, which we can assume to be completely dissociated in water:

HC₂H₃O₂ + H₂O ⇌ H₃O+ + C₂H₃O₂-

HC₂H₃O₂ has a Ka value of 1.8 x 10-5. We can use this Ka value to calculate the equilibrium concentration of H3O+ and C₂H₃O₂- in the solution.

First, we need to calculate the initial concentrations of HC₂H₃O₂ and C₂H₃O₂-.

moles of HC₂H₃O₂ = 0.250 M × 0.0500 L = 0.0125 mol

moles of C₂H₃O₂- = 0 mol (since there is no NaOH added yet)

Since HC₂H₃O₂ is a weak acid, it only partially dissociates in water. The equilibrium concentrations of H₃O+ and C₂H₃O₂- can be calculated using the Ka expression:

Ka = [H₃O+][C₂H₃O₂-]/[HC₂H₃O₂]

We can assume that the initial concentration of H3O+ is negligible compared to the amount that will be produced by the dissociation of HC₂H₃O₂, so we can simplify the expression to:

Ka = [H₃O+]²/[HC₂H₃O₂]

[H₃O+]² = Ka × [HC₂H₃O₂]

[H₃O+]² = 1.8 × 10⁻⁵ × 0.0125

[H₃O+] = 1.34 × 10⁻³ M

Now that we know the equilibrium concentration of H₃O+, we can use the pH formula to calculate the pH:

pH = -log[H₃O+]

pH = -log(1.34 × 10⁻³)

pH = 2.87

This is the pH of the buffer solution before the addition of NaOH.

Next, we add 50 mL of 0.250 M NaOH to the solution. NaOH is a strong base, so it completely dissociates in water to produce OH- ions:

NaOH → Na+ + OH-

The OH- ions will react with the acetate ions in the buffer solution to form water and acetate ions:

OH- + C₂H₃O₂- → H₂O + C₂H₃O₂-

This reaction will consume some of the acetate ions in the buffer solution, causing the equilibrium to shift to the left to produce more acetate ions.

To calculate the new concentrations of H₃O+ and C₂H₃O₂-, we need to use the Henderson-Hasselbalch equation:

pH = pKa + log([C₂H₃O₂-]/[HC₂H₃O₂])

where pKa = -log(Ka), [C₂H₃O₂-] is the equilibrium concentration of acetate ions, and [HC₂H₃O₂] is the equilibrium concentration of acetic acid.

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The observation that compound A releases H2 gas while compound B does not when treated with Na metal can be explained by considering the structural differences between the two compounds and their ability to undergo specific reactions.

Compound A and compound B both have the molecular formula C₂H₆O, which indicates that they both contain two carbon atoms, six hydrogen atoms, and one oxygen atom. However, the difference lies in the arrangement of these atoms within the molecules. One possible explanation for the observed difference is that compound A is an alcohol, specifically ethanol (CH₃CH₂OH), while compound B is an ether, such as dimethyl ether (CH₃OCH₃). The presence of the hydroxyl group (-OH) in ethanol enables it to undergo a reaction with sodium metal, known as the metal-acid reaction. In this reaction, the metal displaces the hydrogen from the hydroxyl group, forming sodium ethoxide (CH₃CH₂ONa) and releasing hydrogen gas (H₂). On the other hand, ethers like dimethyl ether lack the hydroxyl group and therefore cannot undergo the metal-acid reaction. Consequently, when compound B is treated with sodium metal, no hydrogen gas is released. The ability of compound A to release hydrogen gas while compound B does not when treated with sodium metal can be attributed to the presence of a hydroxyl group in compound A (ethanol), enabling it to undergo a metal-acid reaction, whereas compound B (dimethyl ether) lacks the necessary functional group and thus does not undergo this reaction.

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Answer:

Number of replacable H

+

ions in H

2

SO

4

=n=2

Normality =n× Molarity=2×2=4 N

sign of ∆H :-

We know

when methane burns in presence of oxygen heat is released as a form of energy so the reaction is exothermic.∆H must be -ve

#2

Answer:

In increasing order:

Sr, Ca, Mg, Br

Answer:

Ca is a reducing agent and O is the oxidizing agent.

Explanation:

calcium is the reducing agent as it reduces oxygen while it oxidize itself and oxygen is an oxidising agent because it oxidized others and reduces itself. in this equation oxygen is reducing and Calcium is oxidising. and as it is stated in the definition that oxidizing agent is the agent which oxidises others and reduces itself and it is also stated that reducing agent reduces others and oxidize itself. so based on this statement calcium is reducing agent and O is a oxidizing agent.

The statement "All organic compounds contain the element carbon, but not all compounds containing the element 'carbon' are organic" can be justified based on the definition and characteristics of organic compounds.

Organic compounds are compounds primarily composed of carbon and hydrogen atoms, often with other elements like oxygen, nitrogen, sulfur, and phosphorus. These compounds are typically associated with living organisms and are known for their unique properties and behavior, including the ability to form complex structures, exhibit covalent bonding, and undergo organic reactions.

On the other hand, there are compounds that contain carbon but are not classified as organic. One notable example is carbon dioxide (\(CO_{2}\)), which is a simple inorganic compound composed of carbon and oxygen. Carbon dioxide does not possess the characteristic properties of organic compounds, such as the ability to form long chains or undergo organic reactions.

Additionally, there are inorganic compounds like carbonates (such as calcium carbonate) and carbides (such as calcium carbide) that contain carbon but are not considered organic. These compounds have distinct chemical and physical properties different from those of organic compounds.

In summary, while all organic compounds contain carbon, not all compounds containing carbon are organic. The classification of a compound as organic or inorganic depends on its overall molecular structure, bonding, and characteristic properties.

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Answer:

substance A as well as substance B will be at liquid state at 115 degree Celsius.

Both substance A and B will posses kinetic energy because they are now both liquid at 115 degree Celsius.

Explanation

Solid substance A

The melting point of Solid substance A is 100 degrees Celsius. once the temperature increases more than 100 degrees Celsius it becomes liquid, So at 115 degrees Celsius, the substance A is liquid.state.

As a result in increase of thermal energy the substance is subjected to, the particles becomes loose and will become free to the extent that they can be slidding over each other.

Liquid substance B

The freezing point of substance B is 110 degrees Celsius. As the temperature increases to 115 degrees Celsius, substance B will still maintain it's liquid state, there is no change of state at that temperature.

At that temperature the particles are free as it is close to themselves and can also slide over each other.

NOTE:

The melting point of a substance can be defined as the temperature whereby there is change of state from solid to liquid.

The Freezing point is the temperature at which a liquid becomes a solid.

Answer: 3 slowest reaction of the squence

Explanation:

The order of reaction is obtained from the slowest step in the reaction.

An elementary reaction refers to any reaction that takes place in one reactive encounter. On the other hand, a multistep reaction occurs in several steps and involves multiple reactive encounters.

The rate determining step in a multistep reaction is the slowest step in the reaction sequence. The order of reaction is obtained from this slowest step in the reaction.

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9. The number of mole of the argon contained in the tank is 2.39 moles

10. The volume (in liters) of H₂O produced from the reaction is 73.5 liters

The number of mole of the argon contained in the tank can be obtained as follow:

PV = nRT

Inputting the given parameters, we have:

9.4 × 6.25 = n × 0.0821 × 299

Divide both sides by (0.0821 × 299)

n = (9.4 × 6.25) / (0.0821 × 299)

n = 2.39 moles

Thus, the number of mole of the argon gas in the tank is 2.39 moles

The volume of H₂O produced can be obtained as shown below:

4NH₃(g) + 5O₂(g) -> 6H₂O(g) + 4NO(g)

From the balanced equation above,

4 liters of NH₃ reacted to produced 6 liters of H₂O

Therefore,

49 liters of NH₃ will react to produce = (49 × 6) / 4 = 73.5 liters of H₂O

Thus, the volume of H₂O produced is 73.5 liters

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Answer:

phototropism

Explanation:

since photo is (light?

The ideal gas law may be used to determine the volume of oxygen created in the electrolysis that produces 548 litres of hydrogen at STP (Standard Temperature and Pressure). PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature, according to the ideal gas equation.

The pressure is 1 atm, the temperature is 273 K, and the number of moles of hydrogen is 548/22.4 = 24.5 in this example. We may compute the volume of oxygen created by rearranging the ideal gas law: V = nRT/P = 24.5*0.082*273/1 = 483.3 litres.

As a result, the volume of oxygen created in the electrolysis at STP that produces 548 litres of hydrogen is 483.3 litres.

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

+2.

Explanation:

Hello,

In this case, since chromium has six valence electrons in its outer shell, when it loses four electrons it remains with two of them, therefore it charge as chromium ion is +2, so it is written as Cr⁺² and named as chormium (II) or hypochromous ion.

Best regards.

Answer:chlorofluorocarbons (CFCs)

halon.

carbon tetrachloride (CCl4)

methyl chloroform (CH3CCl3)

hydrobromofluorocarbons (HBFCs)

hydrochlorofluorocarbons (HCFCs)

methyl bromide (CH3Br)

bromochloromethane (CH2BrCl)

Explanation:

BRAINLIEST pls

Answer:

i think the answer is b but dont knock me if its not

Explanation:

Answer:

D

Explanation:

i learned this in elementary

Answer:

An acid is any hydrogen-containing substance that is capable of donating a proton (hydrogen ion) to another substance. A base is a molecule or ion able to accept a hydrogen ion from an acid.

Answer:

1.Sour in taste

2. Tum blue litmus into red

3. Acids change methyl orange to red

4.Phenolphthalein remains colourless

5. Acids do not give soapy touch

6. Give hydrogen ions in solution

Bitter in taste

The unknown material with a mass of 25.0g, and the volume is 3.19 cm³ is iron with a density of 7.85g/cm³.

DENSITY:

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The molar enthalpy of a lithium chloride solution containing 9.96 grams of lithium chloride dissolved in 100.0 milliliters of water at 22.2 degrees Celsius, rising to 41.3 degrees Celsius, is 34.0 kilojoules/mole.

The mass of water:

Density(D) = Mass(m) ÷ Volume(v)

1.00 g/ml = m÷100ml

m = 1.00g/ml × 100.0 ml

m = 100g

The amount of energy absorbed by water:

q = m × C × ΔT

q = 100g × 4.189J/g.°C × (41.3°C - 22.3°C)

q = 418 J/°C × 19.1°C

q = 7984J

q = 7.984kJ

The amount of energy absorbed by water is 7.984 kJ. The number of moles of lithium chloride has to be calculated. Then, the lithium chloride solution's molar enthalpy is calculated by dividing the energy absorbed by the lithium chloride solution by the number of moles of lithium chloride.

The molar mass of lithium chloride:

(Molar mass of lithium) + (Molar mass of chlorine)

(6.94g/mol) + (35.5g/mol)

42.4g/mol

The number of moles of lithium chloride:

Number of moles(n) = Mass(m) ÷ Molar Mass(M)

n = 9.96g ÷ (42.4g/mol)

n = 0.235 mol

The molar enthalpy of the lithium chloride solution:

Molar enthalpy = Energy absorbed(q) ÷ Moles of substances(n)

Molar enthalpy = 7.984kJ ÷ 0.235mol

Molar enthalpy = 34.0kJ/mol

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Answer:

The boiling point of n-octanol is 194.8 degree C and the boiling point of n-octane is 125 degrees C. In the case of gum or liquid stationary phase like polysiloxanes, three prime kinds of interactions play an essential role, that is, dipole, dispersion, and hydrogen bonding. Of all these, the prime kind of interaction for all the kinds of polysiloxanes stationary phase is dispersion.  

It is based on the concept that the solute or the analyte, which is more volatile will elute quickly from the column, that is, it is reliant on the concept of volatility, and the volatility is determined based on its boiling point. Of the analytes used, n-octane exhibit less boiling point in comparison to n-octanol. Thus, when the pure polydimethylsiloxane stationary phase is used, one can expect n-octanol to elute at the end, as it is less volatile in comparison to n-octane. Between the n-octanol hydroxyl group and the stationary phase, no intermolecular force takes place.  

On the other hand, when 5 percent phenyl 95 percent polydimethylsiloxane stationary phase is used n-octanol will elute at the end. Due to the presence of 5 percent phenyl, the stationary phase will become more polar in characteristic and will possess the tendency to combine with more polar groups, and as n-octanol is a more polar analyte than n-octane, therefore, it will retain n-octanol for a prolonged time, and thus, will get elute at the end.