A researcher is trying to find the average atomic mass of a sample of an unknown element. The relative abundances and masses of the three isotopes of the element are found in the table below. What is the average atomic mass of the element? Round your answer to the nearest 0.01 and include units.

Isotope Mass Abundance
A-68 68.43 amu 23.65%
A-70 70.32 amu 26.01%
A-71 71.40 amu 50.34%

The profit or loss on the transaction would be a loss of $50. Option C is correct.

To calculate the profit or loss on the transaction, we need to determine the difference between the selling price and the buying price, and then multiply it by the number of shares.

Buying price per share: $110

Selling price per share: $105

Number of shares: 10

Profit/Loss = (Selling Price per Share - Buying Price per Share) × Number of Shares

Profit/Loss = ($105 - $110) × 10

Profit/Loss = (-$5) × 10

Profit/Loss = -$50

The profit or loss on the transaction would be a loss of $50.

This means that the investor would incur a loss of $50 from selling the shares at a lower price than the buying price.

Hence, C. is the correct option.

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--The given question is incomplete, the complete question is

"If an investor buys 10 shares of stock XYZ at $110/share, then sells them at$105/share, what would the profit or loss be on the transaction? A) Gain of $105 B) Loss of $105 C) Loss of $50 D) Gain of $50."--

The profit or loss on the transaction would be a loss of $50.

To calculate the profit or loss on the transaction, we need to find the difference between the selling price and the buying price, multiplied by the number of shares.

Buying price per share = $110

Selling price per share = $105

Number of shares = 10

Profit or loss = (Selling price per share - Buying price per share) × Number of shares

Profit or loss = ($105 - $110) × 10

Profit or loss = (-$5) × 10

Profit or loss = -$50

Therefore, the profit or loss on the transaction would be a loss of $50. The investor would experience a loss of $50 from selling the shares at a lower price than they were bought for.

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The half life is the time taken for only one of the half  of the radioactive substance to remain.

The half life is the time taken for only one of the half  of the radioactive substance to remain. We can see the half life by looking at the graph and observing the point at which the sample decreases to half its original number.

Since the half life of carbon-14 is 5700 years, after ten half lives, almost 60000 years has elapsed thus there is little or no carbon-14 left. As a result of this carbon-14 can not be used if the sample is over 60000 years old.

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Answer:

1.20 mole

Explanation:

1 Mole of Cu reacts to form  =  1 Mole of Hg

(1.20 mol × 1 mol) ÷ 1 mol

1.20 mol of Hg

Several factors affect how bright a star appears when observed from Earth are;  Intrinsic luminosity, Distance, Interstellar absorption, Atmospheric conditions, and Observational equipment.

The intrinsic luminosity, or absolute magnitude, of a star is a measure of its actual brightness. Stars with higher intrinsic luminosity appear brighter than those with lower intrinsic luminosity.

The distance between a star and Earth is a significant factor in determining its apparent brightness. Stars that are closer to Earth will generally appear brighter, while stars that are farther away will appear dimmer.

As starlight passes through interstellar space, it can encounter interstellar dust and gas, which can absorb or scatter some of the light. This can reduce the apparent brightness of the star as observed from Earth.

The Earth's atmosphere can affect the apparent brightness of stars. Atmospheric turbulence, light pollution, and weather conditions such as clouds or atmospheric scattering can impact the perceived brightness of stars.

The type and quality of the observational equipment used, such as telescopes or binoculars, can also affect the perceived brightness of a star. Different instruments have varying capabilities to gather and amplify light, which can impact the apparent brightness.

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According to the relation of variables in the electromagnetic spectrum the maximum wavelength of light is 36.3 ×10\(^-\)³¹ m.

The  electromagnetic spectrum consists of electromagnetic radiation consists of waves made up of electromagnetic field which are capable of propogating through space and carry the radiant electromagnetic energy.

The radiation are composed of electromagnetic waves which are synchronized oscillations of electric and magnetic fields . They are created due to change which is periodic in electric as well as magnetic fields.

In the given problem,energy is related to wavelength by the formula, λ=hc/E,λ=6.626×10\(^-34\)×3×10⁸/547×1000=36.3×10\(^-31\) m.

Thus, the maximum wavelength of light is 36.3×10\(^-31\) m.

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Answer:

1. 16.9.

2. 33.20

3. 33

Explanation:

In the sum, significant figures are determined by the number with the lower number of decimal places.

In the multiplication, significant figures are equal to the significant figures of the number with the low amount of significant figures

1. 3.41 + 5.3 + 8.2010 = 16.9

2. 19.22 + 11.000 + 2.979 = 33.20

3. 2.222 * 3.33 * 4.4 = 33

The energy of the photon is 5.6321×10^−19 J.

Given,

Frequency (f) = 8.5 x 10^14Hz

Planck's constant (h) = 6.626×10^34Js

Energy (E) =?

Formula:

E = hf

E = 6.626×10^34 × 8.5 x 10^14

E = 5.6321×10^−19 J

Therefore, the energy of the photon is 5.6321×10^−19 J.

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Two common methods scientists use to obtain empirical evidence in science are observation and experimentation.

In science, empirical evidence refers to the data or information that is obtained through observation and experimentation. scientists use various methods to gather empirical evidence, and two common methods are observation and experimentation.

Observation involves using the senses to gather information about the natural world. It can be done through direct observation, where scientists directly observe and record data, or through indirect observation, where they use tools and instruments to gather data. For example, a biologist may observe the behavior of animals in their natural habitat to gather empirical evidence about their social interactions.

Experimentation, on the other hand, involves designing and conducting controlled experiments to test hypotheses and gather data. Scientists manipulate variables and compare the results to draw conclusions. For instance, a chemist may conduct experiments to determine the effect of temperature on the rate of a chemical reaction.

These two methods, observation and experimentation, are essential in the scientific process as they allow scientists to gather reliable and objective empirical evidence to support or refute their hypotheses.

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Observational studies and experimental studies are two methods scientists use to obtain empirical evidence by observing natural phenomena and conducting controlled experiments, respectively.

Scientists use various methods to obtain empirical evidence, which refers to evidence collected through direct observation or experimentation. Two common methods are:

Observational Studies: Scientists observe and record phenomena in their natural settings. This method involves careful observation, documentation, and analysis of data gathered from real-world observations. It allows researchers to identify patterns, correlations, and relationships between variables.

Experimental Studies: Scientists design controlled experiments to investigate cause-and-effect relationships between variables.

They manipulate one variable (independent variable) while keeping other factors constant, and observe the effect on another variable (dependent variable). By controlling variables and using randomization, researchers can establish causal relationships and gather empirical evidence supporting their hypotheses.

Both methods contribute to the accumulation of empirical evidence, enabling scientists to make informed conclusions and advancements in various fields of study.

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Answer: I belive it is HH to h-c-n

Explanation: yea

Explanation:

charged particles=8 which is proton and proton=no.of electron. That's why 8 particles are revolving round this center. And this atom structure is of oxygen

If the center of an atom has 8 charged particles that are protons as the neutrons are neutral there will be 8 negative charges that are electrons revolving around the center nucleus.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether it is  solid,liquid or  gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged particles  and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged  particles and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer:

1.48×10²⁴ Cu atoms

Explanation:

For this question you need to use Avogadro's number 6.022×10²³atoms.

2.45 moles of Cu ×\(\frac{6.022x10x^{23} atoms }{1 mole}\)= 1.47539×10²⁴ atoms.

The moles cancel out so you are left with atoms.

Since there are 3 significant figures in the question there should be 3 significant figures in your answer, which is 1.48×10²⁴ Cu atoms.

The data can show us that X ,Y and Z are all esters

The law of definite proportions, also known as Proust's Law, states that a given chemical compound always contains the same elements in the same proportion by mass.

This means that no matter how a compound is obtained or prepared, its elemental composition will always be the same. For example, water is always composed of hydrogen and oxygen in a ratio of 2:1, regardless of its source or method of preparation.

The law of definite proportions is a fundamental principle of chemistry and provides evidence for the atomic theory of matter.

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Answer:

D: 4, 5

Explanation:

The molar mass of SnF2 is 156.69 g/mol, and the mass percent of F in SnF2 is 66.39%. Therefore, F weighs 10.8 g in 24.6 g of SnF2.

The molar mass of SnF2 can be calculated as follows:

Molar mass of SnF2 = Molar mass of Sn + 2(Molar mass of F)

                                = 118.71 g/mol + 2(18.99 g/mol)

                                = 156.69 g/mol

The mass percent of F in SnF2 can be calculated as follows:

Mass percent of F = (2 x Molar mass of F) / Molar mass of SnF2 x 100%

                              = (2 x 18.99 g/mol) / 156.69 g/mol x 100%

                              = 66.39%

To find the mass of F in 24.6 g of SnF2, we can use the mass percent of F:

Mass of F = Mass percent of F x Mass of SnF2

               = 66.39% x 24.6 g

               = 10.8 g

Therefore, the mass of F in 24.6 g of SnF2 is 10.8 g.

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Answer:

January = 45

May = 80

Explanation:

45 + 8 = 53

53 + 8 = 61

61 + 8 = 69 Round 70

70 + 8 = 78 Round 80

[RevyBreeze]

 Answer:     i might 45 and 110 because i think that it is adding or something

Explanation:

Answer:

they explain the properties and structure of the compound which empirical molecular formulars cannot explain

The structural formulas are good for depicting polymers because polymers are the chemical compounds attached to the long chain with ac other which is impossible to represent other than the structural formula.

The structural formulas are the graphic representation or diagrammatical representation of the structure of any chemical formula in organic and inorganic chemistry they are mostly used.

In Polymers, they are long chains of chemicals compound can be shown diagrammatically or graphically to understand the attachment t of the bonds within them which signifies the physical properties too.

Therefore, polymers are the chemical compounds attached to the long chain with ac other which is impossible to represent other than the structural formula which is why structural formulas are good for depicting polymers.

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Answer:

c: low melting point

Explanation:

melting point is dependent on intermolecular forces. in covalent compounds, electrons are shared more equally. this means there is less separation of positive and negative charges within the molecules.

Answer: In a transverse wave, particles of the medium vibrate up and down perpendicular to the direction of the wave. ... In a surface wave, particles of the medium vibrate both up and down and back and forth, so they end up moving in a circle.

Explanation:

Hope this helps :)

The half life of the gold isotope can be obtained as 2.5 days

The duration it takes for half of the atoms in a sample of a radioactive substance to decay is known as the half-life. It is a gauge of how quickly a chemical decays radioactively. For describing the decay of isotopes, which are various forms of an element with the same number of protons but differing numbers of neutrons in their atomic nuclei, we utilize the idea of half-life.

By the use of the formula;

N/No = (1/2)^t/t1/2

6.25/100 = (1/2)^10/t1/2

0.0625 =  (1/2)^10/t1/2

(1/2)^4 =  (1/2)^10/t1/2

4 = 10/t1/2

t1/2 = 10/4

t1/2 = 2.5 days

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The weight percent of copper in bornite is approximately 63.316%.

The weight percent of copper (Cu) in bornite (Cu5FeS4) can be calculated by considering the atomic masses of copper (Cu), iron (Fe), and sulfur (S) and using the formula:

\(\[\text{{Weight percent of Cu}} = \frac{{\text{{Atomic mass of Cu}} \times \text{{Number of Cu atoms}}}}{{\text{{Formula mass of Cu5FeS4}}}} \times 100\%\]\)

Given that the atomic mass of Cu is 63.546 g/mol, the atomic mass of Fe is 55.845 g/mol, the atomic mass of S is 32.065 g/mol, and the formula mass of Cu5FeS4 is 501.849 g/mol, we can substitute these values into the formula:

\(\[\text{{Weight percent of Cu}} = \frac{{5 \times 63.546}}{{501.849}} \times 100\%\]\)

Simplifying the calculation gives:

\(\[\text{{Weight percent of Cu}} = 63.316\%\]\)

Therefore, the weight percent of copper in bornite is approximately 63.316%.

To calculate the gross value of the mining operation, we multiply the weight of the ore body (20,000,000 tons) by the cost per ton ($85):

\(\[\text{{Gross value}} = \text{{Weight of ore body}} \times \text{{Cost per ton}}\]\)

\(\[\text{{Gross value}} = 20,000,000 \times 85 = \$1,700,000,000\]\)

The expenses for the mining operation can be calculated by multiplying the weight of the ore body (20,000,000 tons) by the cost per ton ($85):

\(\[\text{{Expenses}} = \text{{Weight of ore body}} \times \text{{Cost per ton}}\]\)

\(\[\text{{Expenses}} = 20,000,000 \times 85 = \$1,700,000,000\]\)

The net value (profit or loss) of the mining operation can be obtained by subtracting the expenses from the gross value:

\(\[\text{{Net value}} = \text{{Gross value}} - \text{{Expenses}}\]\)\(\[\text{{Net value}} = \$1,700,000,000 - \$1,700,000,000 = \$0\]\)

Therefore, the net value of this mining operation is zero, indicating that there is neither profit nor loss.

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Answer: B: a solvent

Explanation: I hope this helps!

Answer:

The girl is 300N as she is staying still, and not buried in the ground or flying, hence, it has to be the same as the force pushing down. Sorry, can't answer about the rocket one.

Explanation:

Empirical formula tells us the relative ratios of different atoms in a compound.

The chemical formula for a compound obtained by composition analysis is always the empirical formula.

How to calculate Empirical formula:

Linalyl acetate (bergamot oil):

              Carbon               Hydrogen                  Oxygen

                73.41 %                   10.29 %                  16.30 %

             73.41 / 12               10.29 / 1                   16.30 / 16

               6.11                          10.29                        1.01

            6.11 / 1.01                10.29 / 1.01                1.01 / 1.01

                 6                            10                                1

          Empirical formula : C₆H₁₀O

Thus we can conclude that empirical formula of linalyl acetate is  C₆H₁₀O

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The empirical formula for Linalyl acetate expresses the relative proportions of different atoms in a compound.

Linalyl acetate is a phytochemical found in a variety of flowers and spice plants. It is an important component of bergamot and lavender essential oils. It is the linalool acetate ester, and the two are frequently found together.

Hence, the empirical formula describes the relative proportions of different atoms in a compound. The chemical formula for a compound obtained through composition analysis is always the empirical formula.

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To solve this problem, let's use the definition for molarity:

Replacing the values of the problem:

Now, to find the mass, we multiply by the molecular weight of NaCl. (Which is about 58.44g/mol)

The answer is approximately 22.2g of NaCl

The radioactive isotope Technium-99 decays most likely through alpha decay (99tc). An atomic nucleus emits an alpha particle during the radioactive decay process known as "alpha decay".

and then changes or "decays" into a separate atomic nucleus with a mass number that is decreased by four and an atomic number that is decreased by two. The nucleus of an atom of helium-4 is the same as an alpha particle. Radioisotopes are an element's radioactive isotopes. They are the atoms with unstable neutron-proton combinations or excess energy in their nuclei. During those processes, the radionuclide is said to experience radioactive decay, albeit the surplus energy may be put to use in any number of ways.

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Answer:

45.6 degrees Celsius

Explanation:

Answer:

file link http/www.openfree

The unknown substance is likely ethanol. We can use the formula for the amount of heat absorbed by a substance to calculate its specific heat capacity.

Here is the formula of the heat

q = m·c·ΔT

where q is the amount of heat absorbed, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

Plugging in the known values, we get:

141.75 J = 45 g · c · (40.0°C - 25.0°C)

Solving for c, we get:

c = 141.75 J / (45 g · 15.0°C) = 0.209 J/(g·°C)

Now, we can use the provided chart to identify the substance based on its specific heat capacity. From the chart, we see that the specific heat capacity of the substance is closest to that of ethanol (0.244 J/(g·°C)).

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