A recipe calls for 1/2 cup of ingredient A for every 1 2/3 cups of ingredient B. You use 2 cups of ingredient A. How many cups of ingredient B do you​ need?

Answer:

D: assets.

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

We subtract both sides by 6 (3x=6)

And then we divide by 3 (x=2)

Hey there!

You have 3 x-tiles

+

6 = positive-tiles (+)

=

12 positive-tiles (+)

3x + 6 = 12

SUBTRACT 6 to BOTH SIDES

3x + 6 - 6 = 12 - 6

CANCEL out: 6 - 6 because it gives you 0

KEEP: 12 - 6 because it helps solve for the x-value

NEW EQUATION: 3x = 12 - 6

SIMPLIFY IT!

3x = 6

DIVIDE 3 to BOTH SIDES

3x/3 = 6/3

CANCEL out: 3/3 because it gives you 1

KEEP: 6/3 because it helps solve for the x-value

x = 6/3

SIMPLIFY IT!

x = 2

Therefore, your answer is: x = 2

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

The price the customer has to pay is: $55

If the store marks up the shirt by 10%, then the customer will have to pay 110% of the purchase price. To calculate the final price, we can multiply the purchase price by 110% or 1.1.

Therefore, the price the customer has to pay is:

Price = $50 x 1.1

Price = $55

So the customer has to pay $55 for the shirt. This extra amount of $5 is the markup, which is the profit the store makes from selling the shirt. It is important to note that the markup percentage is calculated based on the purchase price, not the selling price.

This markup strategy is commonly used in retail to ensure that the store covers its expenses and makes a profit. While the markup percentage can vary based on the product and market conditions, it is generally used to cover the costs of production, transportation, storage, and other expenses.

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For a negative answer, subtract the greater number from the smaller number.

What is subtraction?

Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction. For example, in the following image, there are 5-2 peaches, which is 5 peaches with 2 removed, for a total of 3 peaches. As a result, the difference between 5 and 2 is 3; that is, 5-2 = 3. While traditionally linked with natural numbers in mathematics, subtraction may also refer to the removal or reduction of physical and abstract quantities utilizing a variety of objects such as negative integers, fractions, irrational numbers, vectors, decimals, functions, and matrices.

For a negative answer, subtract the greater number from the smaller number.

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There were 357 dogs that were sold that day.

What is least squares regression line?

The line that best matches a linear connection between two variables in data is called a least-squares regression line because it minimizes the vertical distance between the data points and the regression line.

The given equation is,

y = 0.6p + 10.0

The residual for the day when 520 people attended was 35.

So, p = 520.

Plug 520 in the above equation, we get

y = 0.6(520) + 10.0

y = 312 + 10

y = 322

As, people attended was 35

So,

y = 322 + 35

y = 357

Hence, there are 357 dogs are sold that day.

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The rewritten expression using a common factor is:

4x + 16 = 4*(x + 16)

Here we want to rewrite the expression:

4x + 16

Ussing a common factor, so let's factorize the terms.

The first one is simple:

4x = 4*x

The second one is also simple, we can write:

16 = 4*4

Then the common factor is 4, and we can rewrite the expression as:

4x + 16 = 4*(x + 16)

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Answer:

Step-by-step explanation:

45

Answer:

2x(x-3)(-x+1)

Step-by-step explanation:

Factor 2x from everything -> 2x(4x-3-x^2)

Reorder the terms -> 2x(-x^2+4x-3)

Write 4x as a sum -> 2x(-x^2+3x+x-3)

Factor out -x from -x^2+3x looks like -> 2x(-x(x-3)+x-3)

Factor out x-3 from the expression -> 2x(x-3)(-x+1)

Answer:

\( \displaystyle \large \boxed{ - 2x( x - 3)(x - 1)} \)

Step-by-step explanation:

We are given the expression:

\( \displaystyle \large{8 {x}^{2} - 6x - 2 {x}^{3}} \)

Notice how the expression has same x-term but not same degree, we can common factor out the x.

Factor using LCF (Least Common Factor which is 2x because 8 and 6 are multiples of 2.)

Therefore:-

\( \displaystyle \large{2x(4x - 3 - {x}^{2}) } \)

Inside the brackets, we can still factor. First, arrange the expression:-

\( \displaystyle \large{2x( - {x}^{2} + 4x - 3) } \)

Factor -1 or negative sign out of the expression:

\( \displaystyle \large{ - 2x( {x}^{2} - 4x + 3) } \)

Factor x^2-4x+3 using two brackets.

What two numbers add/subtract each others and yield -4? The two numbers must multiply and yield 3 as well.

Thus:-

\( \displaystyle \large{ - 2x( x - 3)(x - 1)} \)

And we're done!

The model F is identifiable, and the true value of μ can be estimated from the observed measurements X1, X2, ..., Xn.

To formulate the constant-mean model for the determinations X1, X2, ..., Xn, we can start by considering the individual measurements and their relationship to the true value of the physical constant μ.

Let's denote the true value of the physical constant as μ. The measurements X1, X2, ..., Xn are biased and overestimate μ on average by 0.1 units. This means that each measurement can be modeled as:

Xi = μ + εi + 0.1

where Xi is the i-th measurement, εi represents the measurement error, and 0.1 represents the bias.

The measurement errors ε1, ε2, ..., εn are assumed to be independent and identically distributed (i.i.d.) normal random variables with variance σ².

Therefore, we can specify the common distribution Gε for the measurement errors as:

Gε ~ N(0, σ²)

Now, let's determine the distribution of the measurements X1, X2, ..., Xn. Using the constant-mean model, we can express each measurement Xi in terms of the true value μ, the measurement error εi, and the bias term 0.1.

Xi = μ + εi + 0.1

The measurements X1, X2, ..., Xn are also assumed to be independent and identically distributed (i.i.d.) random variables.

Therefore, the common distribution F for the measurements can be specified as:

F ~ N(μ + 0.1, σ²)

Here, the parameter of interest is μ, the true value of the physical constant. The parameter space for μ depends on the specific context and constraints of the problem.

Identifiability refers to the property of being able to uniquely determine the parameters of a statistical model from the observed data.

In this case, model F is identifiable because the true value of the physical constant μ can be estimated by subtracting the known bias of 0.1 from the observed measurements. Even if the bias term β (unknown positive bias) is included, it can be absorbed into the estimation of μ as long as it remains constant across all measurements.

Therefore, model F is identifiable, and the true value of μ can be estimated from the observed measurements X1, X2, ..., Xn.

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To determine if a triangle is unique, not a triangle, or more than one triangle, we need to examine the given information about the triangle's side lengths. In a valid triangle, the sum of any two sides must be greater than the third side. Based on this concept, we can evaluate the possibilities.

If the sum of the lengths of the two shorter sides is greater than the length of the longest side, then a unique triangle can be formed. This is known as the Triangle Inequality Theorem. The unique triangle can be constructed by connecting the three given side lengths.

If the sum of the lengths of the two shorter sides is equal to the length of the longest side, then no triangle can be formed. This condition is known as a degenerate triangle or a straight line. In this case, the three sides are collinear and do not form a closed figure.

If the sum of the lengths of the two shorter sides is less than the length of the longest side, then it is not possible to form a triangle. The given side lengths do not satisfy the Triangle Inequality Theorem, and thus, no triangle can be constructed.

By applying the Triangle Inequality Theorem and comparing the side lengths, we can determine whether a unique triangle, no triangle, or more than one triangle can be formed based on the given information.

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The probability of observing the sequence r, b, b, r, r in the given scenario is 1/120.

To find the probability of observing the sequence r, b, b, r, r in the given scenario, we can break it down step by step:

Probability of drawing the first ball as red (r):

Since the urn initially contains one red and one black ball, the probability of drawing a red ball is 1/2.

Probability of drawing the second ball as black (b) after the first ball was red:

After drawing the first red ball, it is returned to the urn along with another red ball, so the urn now contains two red balls and one black ball.

The probability of drawing a black ball is 1/3.

Probability of drawing the third ball as black (b) after the previous sequence was r, b:

After drawing the second black ball, it is returned to the urn along with another black ball, so the urn now contains two red balls and two black balls.

The probability of drawing a black ball is now 2/4 = 1/2.

Probability of drawing the fourth ball as red (r) after the previous sequence was r, b, b:

After drawing the third black ball, it is returned to the urn along with another black ball, so the urn still contains two red balls and two black balls.

The probability of drawing a red ball is 2/4 = 1/2.

Probability of drawing the fifth ball as red (r) after the previous sequence was r, b, b, r:

After drawing the fourth red ball, it is returned to the urn along with another red ball, so the urn now contains three red balls and two black balls.

The probability of drawing a red ball is 3/5.

To find the overall probability of observing the sequence r, b, b, r, r, we multiply the probabilities of each individual step:

\(P(r, b, b, r, r) = (1/2) \times (1/3) \times (1/2) \times (1/2) \times (3/5)\)

= 1/120.

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Answer: -5/6

Step-by-step explanation:

(1 + -2) + (2/3+ -1/2)

-1 + 2 x 2 / 3 x 2 + -1 x 3 / 2 x 3

Simplify:

-1 + 4/6 + -3/6

Turn into a simpler fraction:

1 + 4 + (-3) / 6

Combine like terms:

-1 + 1/6

Add together:

- 5/6

Hope this helps!

The error term is a random variable with an expected value of zero.2. The error term is normally distributed

The assumptions underlying the simple linear regression model `y = Bo + B1x + e` are: 1.

The variance of the error term e is constant across all values of x.Thus, the assumptions that are underlying the simple linear regression model `y = Bo + B1x + e` are the second and the third options, which are "The error term is normally distributed." and "The variance of the error term e is constant across all values of x." respectively.

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(C) $563,700 in cash was received from customers during the year.

Accounting lingo for partial payment of an amount outstanding is "on the account."

The phrase "on account" can also refer to buying or selling anything on credit.

On credit is another way to say "on the account."

Simply changing a sales representative's job title won't make them an account manager.

The needed abilities are varied.

Account managers require abilities in project management, financial control, consultative/value selling, and planning, some of which may require training.

So, gross sales of $560,000.

Accounts receivable decreased ($22,500 - $18,800). $3,700.

Money obtained from clients. $563,700.

Note that the further details provided in the question are not necessary to determine the total amount of money received from customers for the year.

Therefore, (C) $563,700 in cash was received from customers during the year.

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Answer:

yes

Step-by-step explanation:

because it will be easier if the they are like terms

The correct option is c. 0..10

.What are integers?

Integers are a set of numbers that are positive, negative, and zero.

A collection of integers is represented by the letter Z. Z = {...-4, -3, -2, -1, 0, 1, 2, 3, 4...}.

What are values?

Values are numerical quantities or a set of data. It is given that the variable x is an integer.

To find out the possible values of x, we will use the expression below.x ≥ 0.

This expression represents the set of non-negative integers. The smallest non-negative integer is 0.

The possible values that x can evaluate to will be from 0 up to and including 10.

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To ensure the object reaches the ground in 12 seconds, it should be dropped from a height of 2304 feet above sea level.

To determine the height from which the object should be dropped to reach the ground in 12 seconds, we need to use the radical function:
\(h(t) = 16t^2\).

Where h(t) represents the height above sea level in feet,

t represents the time in seconds, and 16 is a constant that relates to Earth's gravitational acceleration.
We are given t = 12 seconds, so we can plug this value into the function to find the height h:
\(h(12) = 16(12)^2\)
h(12) = 16(144)
\(h(12) = 2304 feet\).

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Answer:

4/5

Step-by-step explanation:

Answer:

last one 250t

Step-by-step explanation:

if u pluged in 4 for t to the equation u would get 1000 which is the correct amount

hope this helped!

Answer:

a = 250t or Answer D

Step-by-step explanation:

Y = mx+b

m = (y2-y1)/(x2-x1)

m = (2500-100)/(10-4)

m = 1500/6 = 250

y = 250x+0

y = 250x

Answer:

Slope: -3/5

Step-by-step explanation:

In 139.4 \(\pi\) \(ft^2\)sec rapidly is area of enclosed by the ripple increasing at the end of 6.4 seconds.

What is area of circle?

 For measuring the area occupied by a circular field or plot, use the area of a circle formula. The area formula will allow us to determine how much fabric is required to completely cover a circular table, for example. We can determine the boundary length, or the circle's circumference, using the area formula.

Here area of circle

=> A= π\(r^2\)--------> 1

Differentiating 1 with respect to to time then

=> \(\frac{dA}{dt}= 2\pi r\frac{dr}{dt}\)

If the radius is  increasing at a constant rate 3.3ft/sec then after 6.4 seconds, radius is

=> 6.4*3.3=21.12 ft.

We know \(\frac{dr}{dt}= \frac{3.3ft}{sec}\) and so ,

=> \(\frac{dA}{dt}\) = 2*\(\pi\)*21.12*3.3=139.4 \(\pi\) \(ft^2\)sec.

Hence In 139.4 \(\pi\) \(ft^2\)sec rapidly is area of enclosed by the ripple increasing at the end of 6.4 seconds.

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Answer:

0.009652 or 9.652×\(10^{-3}\)

Step-by-step explanation:

this is how i solved it hopefully its correct

The definite integral is \(& \frac{243}{5}(\ln 3)^2-\frac{2}{5}\left[\ln 3\left(\frac{243}{5}\right)-\frac{243}{25}\right]-\frac{2}{125}\).

The integral is \($\int_1^3 x^4(\ln x)^2 d x$\)

First evaluate indefinite integral, \($\int x^4(\ln x)^2 d x$\)

The definite integral of a real-valued function f(x) with respect to a real variable x on an interval [a, b] is expressed as \(\int_a^b f(x) d x=F(b)-F(a)\)

Here,

∫ = Integration symbol

a = Lower limit

b = Upper limit

f(x) = Integrand

dx = Integrating agent

Thus, ∫ab f(x) dx is read as the definite integral of f(x) with respect to dx from a to b.

Indefinite integrals are implemented when the boundaries of the integrand are not specified.

Use integration by parts:

\($\int u d v=u v-\int v d u$\)

Let \($u=(\ln x)^2$\) and \($a v=x^4 d x$\)

This implies \($d u=\frac{2(\ln x)}{x} d x$\) and \($v=\int x^4 d x=\frac{x^5}{5}$\)

Equation (1) becomes,

\($$\begin{aligned}& \int x^4(\ln x)^2 d x=(\ln x)^2 \frac{x^5}{5}-\int \frac{x^5}{5} \times \frac{2(\ln x)}{x} d x \\& \int x^4(\ln x)^2 d x=(\ln x)^2 \frac{x^5}{5}-\frac{2}{5} \int x^4 \ln x d x\end{aligned}$$\)

Again, use integration by parts to evaluate \($\int x^4 \ln x d x$\)

Let \($u=\ln x, d v=x^4 d x$\)

This implies \($d u=\frac{1}{x}$\) and  \($v=\int x^4 d x=\frac{x^5}{5}$\)

Let \($u=\ln x, d v=x^4 d x$\)

This implies \(d u=\frac{1}{x}$\) and \($v=\int x^4 d x=\frac{x^5}{5}$\)

\($$\begin{aligned}\int x^4 \ln x d x & =\ln x\left(\frac{x^5}{5}\right)-\int\left(\frac{x^5}{5}\right) \frac{1}{x} d x \quad \text { since } \int u d v=u v-\int u d u \\& =\ln x\left(\frac{x^5}{5}\right)-\frac{1}{5} \int x^4 d x \\& =\ln x\left(\frac{x^5}{5}\right)-\frac{x^5}{25}\end{aligned}$$\)

From equation (2),

\($$\int x^4(\ln x)^2 d x=(\ln x)^2 \frac{x^5}{5}-\frac{2}{5}\left[\ln x\left(\frac{x^5}{5}\right)-\frac{x^5}{25}\right]$$\)

The required definite integral is,

\($$\begin{aligned}\int_1^3 x^4(\ln x)^2 d x & =\left[(\ln x)^2 \frac{x^5}{5}-\frac{2}{5}\left[\ln x\left(\frac{x^5}{5}\right)-\frac{x^5}{25}\right]\right]^3 \\& =\left[(\ln 3)^2 \frac{3^5}{5}-\frac{2}{5}\left[\ln 3\left(\frac{3^5}{5}\right)-\frac{3^5}{25}\right]\right]-\left[(\ln 1)^2 \frac{1^5}{5}-\frac{2}{5}\left[\ln 1\left(\frac{1^5}{5}\right)-\frac{1^5}{25}\right]\right] \\& =\frac{243}{5}(\ln 3)^2-\frac{2}{5}\left[\ln 3\left(\frac{243}{5}\right)-\frac{243}{25}\right]-\frac{2}{125}\end{aligned}$$\)

Therefore, the required definite integral is \(& =\frac{243}{5}(\ln 3)^2-\frac{2}{5}\left[\ln 3\left(\frac{243}{5}\right)-\frac{243}{25}\right]-\frac{2}{125}\).

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The amount should be around $130,000 must be invested today at 10 % to be worth $271,000 in 10 years. A = $271,000k = 0.1t = 10 years P = Ae^{-kt}P = $271,000e^{-0.1*10}P ≈ $108,347.39 The closest answer is b. $130,000.

The question is to find out how much must be invested today at 10 %, compounded continuously, to be worth $271,000 in 10 years. Using the formula for continuously compounded interest: A = Pe^{rt}, where A is the amount at the end of the investment period, P is the principal, e is the exponential function, r is the annual interest rate, and t is the number of years.

A = Pekt, where k = 0.10 is the annual interest rate and e is a constant equal to 2.71, is a more straightforward version of the formula.P = Ae-kt, where A = PektWe are informed that the sum will be $271,000 in total. So, A = $271,000,000 = 0.1 trillion = 10 years. P = Ae-kt; P = $271,00e-0.1*10; P $108,347.39;The closest response is b, which is $130,000.

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indeed

Answer:

the solution to 2(x + 10) is 2 + 20

May I have brainliest please? :)

Answer:

first function

Step-by-step explanation:

there is a common difference between consecutive terms , that is

13 - 10 = 16 - 13 = 19 - 16 = 22 - 19 = 3

this indicates the sequence is arithmetic with nth term

\(a_{n}\) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 10 and d = 3 , then

\(a_{n}\) = 10 + 3(n - 1) = 10 + 3n - 3 = 7 + 3n

The conclusion that we now make about the result of adding a rational and an irrational number is that the sum of any rational number and any irrational number will always be an irrational number.

Irrational numbers cannot be stated as a fraction, although rational numbers can be expressed as ratios (such as P/Q and Q). However, both of the numbers are genuine and can be shown on a number line.

It should be noted that the conclusion that we now make about the result of adding a rational and an irrational number is that the sum of any rational number and any irrational number will always be an irrational number.

For example, we can conclude that ½+√2 is irrational.

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