Answer:
v = 37.59 km/h
Explanation:
The question says, "how fast in km / h did usain bolt run at the berlin world championship in 2009 to break the world record for the 100m sprint in 9.58".
Distance, d = 100 m = 0.1 km
Time, t = 9.58 s = 0.00266 h
We need to find the speed of the Usain Bolt. We know that,
Speed = distance/time
So,
\(v=\dfrac{0.1}{0.00266}\\\\v=37.59\ km/h\)
So, the required speed is equal to 37.59 km/h.
As a light wave strikes a shiny surface like a piece of polished metal, it will be
refracted
reflected
absorbed
Please help!!!!!
given the reactions, x(s) 12o2(g)⟶xo(s) δ=−883.5 kj xco3(s)⟶xo(s) co2(g)δ= 327.1 kj what is δ for this reaction? x(s) 12o2(g) co2(g)⟶xco3(s)
The enthalpy change for the reaction x(s) + 12O2(g) + CO2(g) ⟶ xCO3(s) is 212.45 kJ.
Reaction 1: x(s) + 12O2(g) ⟶ xo(s); Δ = -883.5 kJ
Reaction 2: xCO3(s) ⟶ xo(s) + CO2(g); Δ = 327.1 kJ
To find: Δ for the reaction: x(s) + 12O2(g) + CO2(g) ⟶ xCO3(s)
Solution: To get the Δ for the given reaction, we need to add the Δ for both the given reactions:
Reaction 1: x(s) + 12O2(g) ⟶ xo(s); Δ = -883.5 kJ Multiplying this reaction by 1/2 to balance the number of oxygen atoms: 1/2x(s) + 6O2(g) ⟶ 1/2xo(s); Δ = -883.5/2 kJ
Reaction 2: xCO3(s) ⟶ xo(s) + CO2(g); Δ = 327.1 kJ Multiplying this reaction by 2 to balance the number of carbon atoms: 2xCO3(s) ⟶ 2xo(s) + 2CO2(g); Δ = 2 × 327.1 kJ
Adding both the above reactions: 1/2x(s) + 6O2(g) + 2xCO3(s) ⟶ 2xo(s) + 2CO2(g) + 1/2x(s)Δ = -883.5/2 + 2 × 327.1= -441.75 + 654.2= 212.45 kJ
Therefore, the value of Δ for the reaction: x(s) + 12O2(g) + CO2(g) ⟶ xCO3(s) is 212.45 kJ.
Explanation: To get the net enthalpy change for a given reaction, we add the enthalpies of the individual reactions, taking care to adjust the coefficients to balance the stoichiometry of the reactants and products.
The given reactions are: x(s) + 12O2(g) ⟶ xo(s) Δ = -883.5 kJ xCO3(s) ⟶ xo(s) + CO2(g) Δ = 327.1 kJ We need to find the enthalpy change for the reaction: x(s) + 12O2(g) + CO2(g) ⟶ xCO3(s)
To do this, we can add the given reactions together, taking care to balance the coefficients for the reactants and products. Let's multiply the first reaction by 1/2 to balance the number of oxygen atoms: 1/2 x(s) + 6 O2(g) ⟶ 1/2 xo(s) Δ = -883.5/2 kJ
Next, we'll multiply the second reaction by 2 to balance the number of carbon atoms: 2 x CO3(s) ⟶ 2 xo(s) + 2 CO2(g) Δ = 2 × 327.1 kJ Now we can add the two balanced reactions together to get the enthalpy change for the overall reaction:1/2 x(s) + 6 O2(g) + 2 x CO3(s) ⟶ 2 xo(s) + 2 CO2(g) + 1/2 x(s)Δ = -441.75 + 654.2= 212.45 kJ
Therefore, the enthalpy change for the reaction x(s) + 12O2(g) + CO2(g) ⟶ xCO3(s) is 212.45 kJ.
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4. A point charge of 1 μC experiences an electric force of 0.02 N. What is the magnitude of electric field at that point?
The magnitude of the electric field at that point is 2 × 10⁷ N/C.
What is the magnitude of electric field at that point?
The electric field at a point can be determined from the force experienced by a charge at that point, using the equation:
E = F/q
where;
E is the electric field, F is the force experienced by a charge, and q is the charge.In this case, the force experienced by a charge of 1 μC (or 1 × 10^-6 Coulombs) is 0.02 N, so the electric field can be calculated as follows:
E = F/q = 0.02 N / (1 × 10^-6 C)
E = 2 × 10⁷ N/C
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Why does calcium chloride have a greater affect on colligative properties verses sodium
chloride?
Answer:
Calcium chloride is very effective, working at temperatures below most products, and is significantly more effective than sodium chloride because of its ability to extract moisture from its surroundings and to cause exothermic or heat generating reactions.
Explanation:
Hope this helps
we calibrated the gaussmeter before using it to measure the magnetic field and it should be calibrated every time before usage. without doing so, the data will likely deviate slightly from the expected values. can you think of the reason why the calibration should be done before every measurement?
For our delicate measurement equipment to continue to operate accurately, gaussmeter calibration is necessary. In order to achieve this, we compare the instrument to one with a standard or greater accuracy. Then, if there is a deviation from the actual reading, we find it and fix it.
How is a magnetic field calibrated?By delivering a reverse field to the magnet that is strong enough to bring the output (of flux) down to a reasonable level, magnetic calibration is accomplished.
Using a Tesla or Gauss metre, one may determine the intensity of a magnet's magnetic field. Many people who utilise magnets today possess their own Gauss metres and decide what magnetic field strengths are acceptable. The magnet analyzer will measure the magnetic field strength for multi-polar magnets.
The Hall Effect in semiconductors is the basis for how a digital Gauss metre functions. A voltage is created at a right angle to the current route when a semiconductor with current flowing in one direction is introduced perpendicular to a magnetic field.
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Calculate the density of a substance in a sealed 2,500 cm 3 flask that is full to capacity with 0.36 g of a substance.
Answer:
Simple chemical tests can be used to identify the presence of various elements or classes of molecules (Tollen's test). ... Electron spin resonance (ESR): Also referred to as electron paramagnetic resonance (EPR), this method uses the spins of unpaired electrons in molecules to determine structure.
Considering the definition of density, the density of the substance is 1.44×10⁻⁴ \(\frac{g}{cm^{3} }\).
First, you have to know that density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space. In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.
The expression for the calculation of density is:
\(density=\frac{mass}{volume}\)
From this expression it can be deduced that density is inversely proportional to volume.
Also, higher density substances have a greater amount of matter in a certain volume than lower density substances.
In this case, you know that:
mass= 0.36 gvolume= 2500 cm³Replacing in the definition of density:
\(density=\frac{0.36 g}{2500 cm^{3} }\)
Solving:
density= 1.44×10⁻⁴ \(\frac{g}{cm^{3} }\)
Finally, the density of the substance is 1.44×10⁻⁴ \(\frac{g}{cm^{3} }\).
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brainly.com/question/952755?referrer=searchResults brainly.com/question/1462554?referrer=searchResultsCalculate the first and second velocities of the car with four washers attached to the pulley, using the formulas v1 = 0. 25 m / t1 , and v2 = 0. 25 m / (t2 â€" t1) where t1 and t2 are the average times the car took to reach the 0. 25 and the 0. 50 meter marks. Record these velocities, to two decimal places, in Table E. What is the first velocity of the car with four washers at the 0. 25 meter mark? m/s What is the second velocity of the car with four washers at the 0. 50 meter mark? m/s.
The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.
Given data:
The value of the first distance is, d1 = 0.25 m.
The value of the second distance is, d2 = 0.50 m.
The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,
v = d/t
Here,
d is the distance covered.
t is the average time taken to cover the distance.
Then the first velocity of the car at 0.25 m is,
v1 = d1/t1
v1 = 0.25 / t1
here, t1 is the average time for first distance.
And the second velocity of the car with four washers at the 0. 50 m mark is,
v2 = d2/t2
v2 = 0.50 /t2
here, t2 is the average time for the second distance.
Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.
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xercises 9–12 give the position vectors of particles moving along various curves in the xy-plane. in each case, find the particle’s velocity and acceleration vectors at the stated times and sketch them as vectors on the curve.
The velocity and acceleration vectors at specific times for particles moving along curves in the xy-plane, we differentiate the position vector to find the velocity vector, and then differentiate the velocity vector to find the acceleration vector. Substituting the given values of time into the equations allows us to find the vectors at the specified times. Sketching the vectors on the curve helps visualize their direction and magnitude.
Exercise 9-12 involves finding the velocity and acceleration vectors of particles moving along curves in the xy-plane at specific times. To find the velocity vector, we need to differentiate the position vector with respect to time.
The velocity vector represents the rate of change of position. To find the acceleration vector, we differentiate the velocity vector with respect to time. The acceleration vector represents the rate of change of velocity.
To find the velocity and acceleration vectors at the stated times, we can follow these steps:
1. Substitute the given values of time into the position vector equation.
2. Differentiate the position vector equation with respect to time to find the velocity vector.
3. Differentiate the velocity vector equation with respect to time to find the acceleration vector.
4. Substitute the values of time back into the velocity and acceleration vector equations to find the vectors at the specified times.
5. Sketch the velocity and acceleration vectors as arrows on the curve, representing their direction and magnitude.
Remember to use appropriate units and ensure that the direction and magnitude of the vectors are accurately represented in the sketches.
In summary, to find the velocity and acceleration vectors at specific times for particles moving along curves in the xy-plane, we differentiate the position vector to find the velocity vector, and then differentiate the velocity vector to find the acceleration vector.
Substituting the given values of time into the equations allows us to find the vectors at the specified times.
Sketching the vectors on the curve helps visualize their direction and magnitude.
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Three questions about air resistance Help ASAP
Answer:
questions
Explanation:
1. what type of friction is air resistance
2. what two factors affect air resistance
3.what does it mean when an object is in free fall
State the career function of chemical engineering
Answer:
Chemical engineers develop and design chemical manufacturing processes. They apply the principles of chemistry, biology, physics, and math to answer problems that involve the production of chemicals, fuel, drugs, food, and many products
Explanation:
Answer:
The main role of chemical engineers is to design and troubleshoot processes for the production of chemicals, fuels, foods, pharmaceuticals, and biologicals, just to name a few. They are most often employed by large-scale manufacturing plants to maximize productivity and product quality while minimizing costs
Explanation:
1. A race car accelerates uniformly from 19.5 m/s to 50.1 m/s in
2.47 seconds. Determine the acceleration of the car.
The acceleration of the car is 79.8.
Answer:
12.39m/s²
Explanation:
use the formula a=v-u
t
One of the frequencies used to transmit and receive cellular telephone signals in the united states is 850 mhz. What is the wavelength in meters of these radio waves?.
One of the frequencies used to transmit and receive cellular telephone signals in the United States is 850 MHz. 0.353m or 35.3cm is the wavelength in meters of these radio waves.
A waveform signal that’s carried in space or down a wire has a wavelength, which is that, the separation between two identical places (adjacent crests) in the consecutive cycles. This length is usually defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm). The meter, commonly abbreviated as m, is that the SI unit for wavelength. The multiples or fractions of a meter are also used to measure wavelength.
The wavelength of sunshine is a crucial characteristic since it establishes the nature of the light. Green light features a wavelength that is different from both of them, while red light features a wavelength that is different from blue light. The longest wavelengths are found in gamma rays. The light with the longest wavelength is red, which is at one extreme of the spectrum. The wavelength of blue or violet light is that the shortest. All of the colors in the color spectrum are combined to create white light.
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Think about a situation at school where you or someone you know
has demonstrated grit. Describe the situation. Pls help me
Answer:
to have courage and show the strength of your character. ... A person with true grit has passion and perseverance. Goals are set and followed through.
Explanation:
for example: i had the passion and the courage to finish my school work and chores for i can go out with my friends and to get out of the house for a bit and have fun so i had the courage to finish chores from the house and do some schoolwork for i can finish ad hang out with some friends. so i had the strength to finish everything because i didn't want to be doing school work and chores any more so i had the passion to finish up quickly
why weren't horizontally opposed engines used in combat fighters during wwii? wouldn't they solve problems of visibility, center of gravity, etc.? i 'm not referring to light aircraft like the piper cub.
Superior forward visibility compared to radial or V-type engines is a benefit of horizontally opposed engines. For a variety of reasons, including fewer cylinders for equivalent power and smooth operation, opposed engines have today supplanted all previous forms of piston engines.
What World War II fighter plane was the most successful?The American F4U-4 Corsair carrier-based fighter-bomber, created and manufactured by Chance Vought, was the most effective fighter of World War II. More than 12,500 aircraft were produced between 1942 and 1953. The fighter had an extremely lethal arsenal and outstanding mobility.
What drawback does an opposing engine have?The requirement to gear the power from the two opposing pistons together was the biggest disadvantage. Compared to traditional piston engines, these extra weight and complexity
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A small candle is 35 cm from a concave mirror having a radius of curvature of 24 cm. (a) What is the focal length of the mirror? (b) Where will the image of the candle be located? (c) Will the image be upright or inverted?
(a) To find the focal length of the concave mirror, we can use the mirror formula:
1/f = 1/v - 1/u
1/f = 1/v - 1/-35
1/f = 1/v + 1/35
1/f = (35 + v) / (35v)
where f is the focal length, v is the image distance, and u is the object distance. In this case, the object distance u is given as 35 cm (negative since it is in front of the mirror) and the radius of curvature R is given as 24 cm (positive for a concave mirror).
Using the formula, we can calculate the focal length:
1/f = 1/v - 1/u
1/f = 1/v - 1/-35
1/f = 1/v + 1/35
1/f = (35 + v) / (35v)
Since the mirror is concave, the focal length will be positive. Thus, we can set up the equation: 1/f = (35 + v) / (35v)
f = (35v) / (35 + v)
(b) The location of the image can be found using the mirror equation:
1/f = 1/v - 1/u
We already know the focal length f and the object distance u. Solving for v: 1/v = 1/f + 1/u
v = 1 / (1/f + 1/u)
Substituting the values, we get:
v = 1 / (1/f + 1/-35)
(c) To determine if the image will be upright or inverted, we need to determine the nature of the image formed by the concave mirror. For an object placed beyond the focal point of a concave mirror, the image formed will be real, inverted, and located between the focal point and the center of curvature.
Therefore, the image of the candle will be real, inverted, and located between the focal point and the center of curvature of the concave mirror.
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A state government wants to increase the taxes on cigarettes to increase tax revenue. Because cigarettes are addictive, we would expect its demand to be: ______________
a. Elastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
b. Elastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
c. Inelastic, Thus, the government's cigarette-tax revenues would rise with a tax increase.
d. Inelastic, Thus, the government's cigarette-tax revenues would fall with a tax increase.
The demand of cigarette is elastic so the government's cigarette-tax revenues would rise with a tax increase.
The demand of cigarette is elastic because of the addiction the people can buy the cigarette even at high prices and the government's cigarette-tax revenues would rise.
The demand for cigarettes is unitary elastic (−1.06) means that a 1% increase in the price of cigarette would reduce its consumption by 1.06% so we can conclude that the demand of the cigarette is elastic and the government revenues increases.
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The leading explanation for the existence of spiral arms are:
The leading explanation for the existence of spiral arms in galaxies is the **density wave theory**.
According to the density wave theory, spiral arms are not fixed structures but rather dynamic patterns that result from density waves propagating through the galactic disk. These waves cause regions of higher density and compression, leading to the formation of the spiral arms.
The theory suggests that as gas and stars move through the galactic disk, they are subjected to gravitational perturbations from neighboring objects or asymmetries in the gravitational field. These perturbations create wave-like patterns that move through the disk, causing regions of compression and enhanced star formation, which manifest as the bright arms we observe.
The density wave theory explains the persistence and relatively stable appearance of spiral arms over long periods. It also accounts for the observed differential rotation of stars within a galaxy, with stars moving faster or slower as they pass through the spiral arms.
While the density wave theory is the leading explanation, other factors such as interactions between galaxies and the effects of magnetic fields can also play a role in shaping and maintaining spiral arms. Ongoing research continues to refine our understanding of the mechanisms behind the formation and dynamics of these beautiful structures in galaxies.
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am i pertty and who do think is going to win the presidential election who do u want to win and why
Answer: i think biden will win
Explanation:
because people throw away donald trump's votes
a coin is released into the air what force acts on it when it reaches its highest point
Answer:
Gravity
Explanation:
After it reaches it's highest point, it falls back down because of gravity.
A solar cell has a short circuit current density of 30 mA-cm2 and open circuit voltage of 0.60 V under one-sun illumination at room temperature. a. Assuming the solar cell is ideal diode, then use the ideal diode equation for solar cell J=Jse -Jo[exp(qV/kT)-1] to calculate the open circuit voltage Voc, which is expected under illumination by 100 suns. Stating any assumptions made. b. In practice, an open-circuit voltage of 0.66 V is measured. Compare this with your result and suggest reasons for any discrepancy.
The measured open-circuit voltage of 0.66 V is lower than the expected value of 0.706 V due to non-ideal effects such as series resistance, shunt resistance, and recombination losses.
What is Circuit?
A circuit is a closed loop through which electric current can flow. It consists of a network of interconnected components, such as resistors, capacitors, inductors, diodes, transistors, and other electronic components, that are designed to perform a specific function.
Solving for Voc, we get:
Voc = (kT/q)ln(Jse/Jo + 1)
For one-sun illumination at room temperature, J = 30 mA/cm2. Therefore, we can find Jo and Jse using the given values of J and Voc:
J = Jse - Jo[exp(qVoc/kT)-1]
30 = Jse - Jo[exp(0.6/q)-1]
Jo = 8.73×10-10 A/cm2
Jse = 34.9 mA/cm2
Using these values, we can find the open circuit voltage Voc under illumination by 100 suns:
Voc = (kT/q)ln(Jse/Jo + 1) ≈ 0.706 V
The ideal diode equation for solar cells assumes that the solar cell is an ideal diode with zero series resistance and shunt resistance, and no recombination losses. In practice, solar cells exhibit non-ideal behavior, which can result in a discrepancy between the measured and expected values of the open circuit voltage.
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What happens when a star can no longer fuse hydrogen to helium in its core?
-the core cools off
-the core shrinks and heats up
-the core expands and heats up
-helium fusion immediately begins
When a star can no longer fuse hydrogen to helium in its core, the core shrinks and heats up. This is because the core is no longer able to generate enough energy through hydrogen fusion to support its own weight against the force of gravity. So the correct option is B .
As a result, the core contracts and becomes denser, which causes an increase in temperature and pressure. This increased temperature and pressure eventually become high enough to ignite hydrogen fusion in a shell surrounding the core, and the star begins to expand and brighten. This phase of a star's life is called the subgiant or red giant branch, depending on its initial mass. Helium fusion does not begin until the core temperature and pressure are high enough to fuse helium, which occurs later in the star's evolution.
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A block of mass M is sliding with an initial speed vi along a horizontal surface with negligible friction. A constant force of magnitude FA is exerted on the object at an angle θ above the horizontal, causing the object to speed up. Derive an equation for the change in the block’s kinetic energy as it moves a horizontal distance Δx. The block remains in contact with the surface the entire time.
This equation describes the change in kinetic energy of the block due to the force exerted on it as it moves a horizontal distance Δx.
What is kinetic energy?Kinetic energy is the energy an object has due to its motion. It is the energy that an object has because of its mass and velocity. Kinetic energy is measured in joules (J). Kinetic energy increases as the mass of the object increases and as the velocity of the object increases. For example, a car moving at 30 miles per hour has more kinetic energy than a car moving at 10 miles per hour.
The change in kinetic energy of the block can be calculated using the following equation:
ΔKE = (1/2)Mv2f - (1/2)Mv2i
Where M is the mass of the block, v2f is the final speed of the block, and v2i is the initial speed of the block.
To calculate the final speed of the block, we can use the equation below.
v2f = v2i + (2FAcosθΔx / M)
Where FA is the magnitude of the force, θ is the angle of the force, and Δx is the horizontal displacement of the block.
Using this equation and the equation for the change in kinetic energy, we can derive an equation for the change in the block’s kinetic energy as it moves a horizontal distance Δx.
ΔKE = (1/2)M[v2i+(2FAcosθΔx/M)]2 - (1/2)Mv2i
This equation can be simplified to:
ΔKE = (FAcosθΔx)v2i + (FAcosθΔx)2/2M
This equation describes the change in kinetic energy of the block due to the force exerted on it as it moves a horizontal distance Δx. The first term of this equation represents the increase in kinetic energy due to the increase in speed, while the second term represents the increase in kinetic energy due to the work done by the force.
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The electric potential at a certain point is space is 12 V. What is the electric potential energy of a -3.0 μC charge placed at that point?A) +4 mJB) -4 mJC) +36 mJD) -36 mJE) zero µJ
The energy is negative and in the order of\(10^-6\) J, we can express it as -36 µJ.
Therefore, the correct answer is D) -36 µJ.
We need to find the electric potential energy of a -3.0 µC charge placed at a point with an electric potential of 12 V.
We can use the formula:
Electric potential energy (U) = Charge (q) × Electric potential (V)
First, we need to convert the charge from µC to C:
\(-3.0 \mu C = -3.0 * 10^-6 C\)
Now we can plug the values into the formula:
\(U = (-3.0 * 10^-6 C) * (12 V)\)
\(U = -36 * 10^-6 J.\)
Therefore, the correct answer is D) -36 µJ.
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do you believe that the universe is expanding?
Answer:
Yes
Explanation:
Many scientists believe that the universe is expanding at an increasing rate. Scientists cannot explain how the universe is expanding at an increasing rate because by law of conservation of energy, there is only a finite amount of energy. Thus, scientists have called this new source of energy dark matter and it is all around the universe helping shape and form the universe.
Filtration in a conventional treatment plant is classified as a
Filtration in a conventional water treatment plant is classified as a physical treatment process that removes particles, including sediment, algae, bacteria, and viruses, from water.
It involves passing water through a porous medium, such as sand or gravel, to trap suspended particles and create a clear effluent.
This process typically follows chemical treatments, such as coagulation and flocculation, that help to clump particles together and facilitate their removal.
The filtered water is then disinfected and sent to a distribution system for consumption. Filtration is a critical step in ensuring the safety and quality of drinking water for communities.
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If four grams of matter are converted to their equivalent amount of energy, how much energy is released? Show your work.
Answer:
Equation of Special Relativity
\(E=mc^2\)
where:
E = energy (measured in Joules)m = mass (measured in kilograms)c = speed of light where \(c \approx 3 \times 10^8 \: \sf ms^{-1}\)First, convert 4 g into kilograms as mass is measured in kg:
\(\implies \sf 4\:g = 0.004\:kg=4 \times 10^{-3}\:kg\)
Substitute the given values into the equation and solve for E:
\(\begin{aligned}E & = mc^2\\\implies E & = \sf (4 \times 10^{-3}) \cdot(3 \times 10^8)^2\\& = \sf (4 \times 10^{-3}) \cdot (3^2 \times 10^{8(2)})\\& = \sf (4 \times 10^{-3}) \cdot (9 \times 10^{16})\\& = \sf 4 \cdot9 \times 10^{-3} \cdot10^{16}\\& = \sf 36 \times 10^{(-3+16)}\\& = \sf 36 \times 10^{13}\\& = \sf 3.6 \times 10^{14}\: \sf J \end{aligned}\)
Use Albert Einstein's equation
E=mc²m=0.004kg
E=(0.004)(3×10⁸)²E=0.004(9×10¹⁶)E=3.6×10¹⁴JMark is doing a pass to his teammate Dan. Mark is square to Dan; his thumbs are against
his chest and his elbows bent and out. Mark steps toward Dan and releases the ball
towards Dan without fully extending his arms. What type of pass is Mark doing and does
he do the pass correctly?
O Overhead pass: No, he did not bring the ball to his forehead
O Push pass: Yes, he did the pass correctly
O Chest pass: No, he should have fully extended his arms when passing to Dan
O Bounce pass: Yes, he did the pass correctly
Bounce pass: Yes, he did the pass correctly
What is Bounce passing?The bounce pass is thrown in the same motion, but it is directed at the ground instead of the air. The throw should be made so that the ball lands at the receiver's waist. Some advise trying to toss it 3/4 of the way to the receiver, and it would be a decent starting point. However, each player must experiment to determine the right distance to throw it so that it bounces to the receiver. The distance will be simpler to determine if the pass has a decent and consistent backspin.To learn more about bounce passing refer to:
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How are electrical charges similar to magnets?
Answer:
The two types of forces are related; a moving magnet can make electrical charges move, cause an electric current, and in turn cause magnetism. ... Objects that have the same charge, both positive or both negative, repel each other, and those with opposite charges attract each other.
Explanation:
Why does a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s?
A dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.
s = vt - 1 / 2 at²
s = Displacement
v = Final velocity
t = Time
a = Acceleration
s = 5 m
t = 1 s
a = 10 m / s²
5 = ( v * 1 ) - ( 1 / 2 * 10 * 1 * 1 )
5 = v - 5
v = 10 m / s
The equation used to solve the given problem is an equation of motion. In a free fall motion, usually air resistance is not considered for easier calculation. If air resistance is considered acceleration cannot be constant throughout the entire motion.
Therefore, a dropped object only fall 5 meters down after 1 second of freefall, yet achieve a speed of 10m/s due to acceleration due to gravity.
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What is the net force EF?
Answer:
Physics Net Force
Explanation:
Physics Net Force
The net force is the combined force of all individual forces acting on an object. Newton's First Law can be seen to be the special case in the Second Law when F, the net force, is zero. When that happens, the acceleration a must also be zero.
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