A car starts from rest it grains acceleration
20m/s?after covering 50 meter distance. Then
Find time taken.​

The student's claim is untrue. When the rod is brought closer, sphere A is polarized, and sphere B acquires a net negative charge. When the rod is removed, sphere B remains charged but sphere A does not remain polarized.

An uncharged object has a neutral charge because it has the same number of protons and electrons. An object is said to be positively charged if it lacks electrons and negatively charged if it has an excess of electrons.

The nature of electric charges is that if the charges are the same, they will repel each other, and if the charges are different, they will attract. So a charged object can attract other charged objects that have a different charge or attract one type of charge on an uncharged object.

When the positively charged rods are brought closer but do not touch ball A. Then sphere A, sphere A is polarized, and sphere B is negatively charged. When the rod is removed, sphere B remains charged but sphere A does not remain polarized.

Complete the question, see the picture.

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a. The condition for over modulation in amplitude modulation is that the amplitude of the message signal must be more significant than the amplitude of the carrier wave.

b. In the output of an Amplitude Modulator, the frequencies generated are the Carrier frequency, Upper sideband (USB) frequency, and Lower sideband (LSB) frequency.

a. Condition for over modulation

The condition for over modulation in amplitude modulation is that the amplitude of the message signal must be more significant than the amplitude of the carrier wave.

Overmodulation causes distortion, noise, or harmonic distortion in the modulated signal. This distortion arises since the amplitude of the carrier wave must not surpass the amplitude of the modulating signal. This results in the amplifier's saturation, causing overmodulation, which degrades the quality of the transmitted signal.The effects of overmodulation include:

Signal distortion

Additional noise

Unwanted frequency content

Limited coverage area

Polarization fading

Unequal sidebands

Ratio of sidebands reduced

Increased power requirements

b. Frequencies generated in the output of an Amplitude Modulator

In the output of an Amplitude Modulator, the frequencies generated are the Carrier frequency, Upper sideband (USB) frequency, and Lower sideband (LSB) frequency. The sum of the carrier frequency and the modulating signal produces the upper sideband, while the difference between the carrier frequency and the modulating signal produces the lower sideband.Thus, the frequencies produced in the output of an Amplitude Modulator include:

Carrier frequency

Upper sideband (USB) frequency

Lower sideband (LSB) frequency

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Yes, the forced oscillations of a system will depend on their natural frequency.

This is because the natural frequency represents the frequency at which the system will oscillate with maximum amplitude when subjected to a disturbance. When a system is subjected to a forcing function, such as an external periodic force, the amplitude of the system's oscillations will depend on the frequency of the forcing function relative to the system's natural frequency.

If the frequency of the forcing function is close to the natural frequency of the system, the amplitude of the oscillations will be large, and the system will experience resonance. On the other hand, if the frequency of the forcing function is significantly different from the natural frequency of the system, the amplitude of the oscillations will be smaller.

Therefore, the forced oscillations of a system are highly dependent on their natural frequency.

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Answer:

here's your answer below

Explanation:

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Answer:

Below are some of the important dates that led to the creation of the Constitution: 1775 — The Revolutionary War between the Colonies and Britain begins. ... 1781 — The last battle of the Revolutionary War takes place; the 13 states set up a federal government under laws called the Articles of Confederation.

Explanation:

please give me a heart

Answer:

top to 2\

next to top

then to up one

next to up

Explanation:

If V is a finite-dimensional inner product space over C and T is a normal transformation on V. Then im(T) ker(T) = 0 and for every generalized eigenvector of T is actually an eigenvector, therefore T is diagonalizable.

The v be an element such that  im(T) ∩ ker(T)

Since v ∈ im(T),

x in V such that T(x) = v

v ∈  ker(T), T(v) = 0

The inner product of v with itself,

⟨v, v⟩ = ⟨T(x), v⟩

The adjoint property of normal transformations,

⟨v, v⟩ = ⟨x, T(v)⟩

Since,  T(v) = 0

⟨v, v⟩ = ⟨x, T(0)⟩ = ⟨x, 0⟩ = 0

Therefore, V must equal zero, since its inner product with itself is zero. Hence,  im(T) ∩ ker(T) = {0}.

Suppose λ is an eigenvalue of T,

v is a generalized eigenvector corresponding to λ,

(T - λI)ˣ  = 0 for some positive integer x,  

and, I represent the identity transformation.

S = T - λI.

Applying S on both sides of the given equation:

S((T - λIˣ) = S(0)

(S(T - λI)ˣ) = 0

Since T is normal,

Therefore, S and (T - λI) commute:

((T - λI)ˣ)(S(v)) = 0

(T - λI)ˣ is a polynomial in T,

T is given as p(T),

p(T)(S(v)) = 0.

This shows that S(v) is a generalized eigenvector of T corresponding to eigenvalue 0.

If S(v) = 0, then,

T(v) = λv,

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of T

Hence, every generalized eigenvector of T is actually an eigenvector, showing that T is diagonalizable.

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The acceleration of the 12-kg box which push up a ramp is 4.96 m/s²

To solve this problem, we need to use the formula for the acceleration of an object on an inclined plane:

a = g(sin θ - μcos θ), where g is the acceleration due to gravity (9.81 m/s²), θ is the angle of the ramp, and μ is the coefficient of friction (which is 0 in this case since the surface is frictionless).

First, we need to find the angle of the ramp. We can use the fact that for each 5.00 m along the ramp, the box gains 3.00 m of height.

This means that the slope of the ramp is given by:

slope = rise/run = 3.00 m / 5.00 m = 0.6 To find the angle of the ramp, we can use the inverse tangent function:

θ = tan⁻¹(slope) = tan⁻¹(0.6) = 31.0°

Now we can plug in the values into the formula for acceleration:

a = g(sin θ - μcos θ) a = 9.81 m/s²(sin 31.0° - 0cos 31.0°) a = 4.96 m/s²

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Answer:

Meat, cereals, milk, fish, fruits and nuts

Answer:

Green leafy vegetables too

Explanation:

hope it helps

A student ties a lead cube to an oval-shaped block to prevent it from floating and immerses it in water density as part of a study to identify the sort of wood it is composed of.

The term "density" (also known as "volumetric mass density" or "specific mass") refers to a substance's mass per unit of volume. Although the Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho).

According to legend, Archimedes shouted "Eureka!" as he rushed through the Sicilian streets. ("I've discovered it!") He had figured out what density was. Everyone has spent a significant amount of time in water during their life. The second thing Archimedes noticed was that he felt lighter floating.

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The constant for the permeability of the of the medium (air) is. This number can be reduced to 1.256x10⁻⁶ tm/a. Option b is correct.

The constant for the permeability of air is typically represented by the symbol "μ" and has a value of approximately 4π x 10⁻⁷ T·m/A. This value is also known as the "permeability of free space" or "vacuum permeability". While the value cannot be reduced to zero, it can be reduced to a lower value in certain materials.

For example, the permeability of ferromagnetic materials can be much higher than the permeability of air, while non-magnetic materials may have a permeability that is very close to that of free space. However, none of the options provided correspond to these values. The closest option is b. 1.256x10⁻⁶ tm/a, which is the permeability of free space divided by 4π. Hence Option b is correct.

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To find the distance traveled in 50 seconds by an object traveling at a velocity of v(t), you need to integrate the velocity function over the given time interval.

Let's assume that the velocity function is denoted by v(t) and represents the velocity of the object at any given time t.

To find the distance traveled, we need to integrate this velocity function over the interval [0, 50] seconds.

The definite integral of the velocity function v(t) with respect to time t will give us the displacement or distance traveled.

The integral of v(t) from 0 to 50 is represented as:

\int_{0}^{50} v(t) dt

To compute this integral, you will need the specific function v(t) that describes the object's velocity at any given time. After evaluating the definite integral, you will get the distance traveled by the object in the given time interval.

Note that without knowing the specific velocity function, it is not possible to provide a numerical value for the distance traveled.

In summary, to find the distance traveled in 50 seconds by an object with a velocity function v(t), you need to integrate the velocity function over the given time interval [0, 50].

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Answer:

32

Explanation:

the atomic mass is the number of protons and neutrons in the nucleus of an atom

so we will add 16 + 16 = 32

After the Big Bang, it took the universe 3 minutes to become cool enough for neutral atoms to form.

During the first moment, immediately after the Big Bang, the universe was too hot for nuclei and electrons to combine into the kinds of neutral atoms that are familiar to us today.

In the first three minutes after the Big Bang, these protons and neutrons began fusing together, forming deuterium also known as heavy hydrogen.

Thus, after the Big Bang, it took the universe 3 minutes to become cool enough for neutral atoms to form.

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Answer:

The spring constant will be "1333.33 N/m".

Explanation:

The given values are:

Mass,

m = 1.2 kg

Displacement compression,

x = 0.15 m

Block's velocity,

\(v_i=5 \ m/s\)

As we know,

⇒  \(E_i=E_f\)

or,

⇒  \(K_i+v_i=K_f+v_f\)

⇒  \(\frac{1}{2}mv_i^2+0=0+ \frac{1}{2}Kx^2\)

So,

⇒  \(K=\frac{mv_i^2}{x_2}\)

On substituting the values, we get

⇒       \(=\frac{1.2\times 5\times 5}{0.15\times 0.15}\)

⇒       \(=\frac{30}{0.0225}\)

⇒       \(=1333.33 \ N/m\)

Input is the variable that has the biggest impact on the group's ability to function smoothly.

A social group is described in the social lores as two or further individualities who interact with one another, have a sense of concinnity among themselves, and share traits in common. Social groupings come in a wide range of shapes and sizes, however.

A society, for case, can be allowed of as a sizable social group. Group dynamics refers to the set of behavioral and cerebral processes that take place outside or between social groups.

A social group is further than a bare assembly of people, similar as those standing in line or staying at a machine stop, and it has some degree of social consonance.

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The quantity of electrical energy in an object determined by the presence or absence of protons or electrons is described by its electrical charge, which is a fundamental feature of matter.

An object's electrical charge, which describes whether it contains electrons or protons and the amount of electrical energy associated with it as a result, is a fundamental feature of matter. All matter is formed of atoms, which contain positively charged protons, negatively charged electrons, and neutral particles called neutrons. The distribution of these particles determines an object's electrical charge.

Depending on whether an object has a shortage or an abundance of electrons, electrical charge can either be positive or negative. A substance that contains more protons than electrons is positively charged, whereas a substance with more electrons than protons is negatively charged.

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The Carnot refrigerator operates on the principle of transferring heat from a cooler region to a hotter region with the help of external work. The amount of heat that the refrigerator can remove from its inside compartment can be determined using the equation:

QC = W*(TC/TH - 1)



Efficiency (η) = (Tc / (Th - Tc))

Where Tc is the cold temperature (inside the refrigerator) and Th is the hot temperature (kitchen temperature). In this case, Tc = 277 K and Th = 287 K.

First, calculate the efficiency:

η = 277 / (287 - 277) = 277 / 10 = 0.277

Next, we can use the formula for the heat removed from the inside compartment, which is given by:

Qc = W / η

Where Qc is the heat removed and W is the work done. In this case, W = 2250 J.

Finally, calculate the heat removed:

Qc = 2250 / 0.277 ≈ 8103 J

So, the refrigerator can remove approximately 8103 Joules of heat from its inside compartment using 2250 Joules of work.

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Answer:

Percentage of solution= 5

Mass of solution= 250g

% of solution=

Mass of solution

Mass of solute

×100

∴ Mass of solute=

100

5×250

=12.5g

Explanation:

hope it's help

Answer:

organism

Explanation:

In the systems

First is

1.cell

group of cells is

2. Tissue

group of tissues

3. Organ

group of organs

4. Organ system

group of organ systems

5.Organism

The strength of an electric field in which a charged particle of 3.0 X 10-9 C is 0.05m from the test charge is \(\[3.6 \times 10^8 \, \text{N/C}\]\).

The strength of an electric field can be calculated using the formula:

Electric field strength (E) = Force (F) / Test charge (q)

In this case, we are given the charge of the test particle (\(\[q = 3.0 \times 10^{-9} \, \text{C}\]\)) and the distance from the test particle to the charge creating the electric field (r = 0.05 m).

The force between two charges can be calculated using Coulomb's Law:

Force \(\[(F) = \frac{{k \cdot q_1 \cdot q_2}}{{r^2}}\]\)

where k is the electrostatic constant \(\[(k \approx 8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2)\]\), q1 and q2 are the charges, and r is the distance between them.

In this scenario, we have a single charge creating the electric field, so q2 = 1 C (unit test charge). Substituting the given values into the formula, we get:

\(\[(F) = \frac{{k \cdot q_1 \cdot q_2}}{{r^2}}\]\)

\(\[F = \frac{{(8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2) \cdot (3.0 \times 10^{-9} \, \text{C}) \cdot (1 \, \text{C})}}{{(0.05 \, \text{m})^2}}\]\)

Simplifying the equation gives us:

F ≈ 1.0792 N

Now, we can calculate the electric field strength:

E = F / q

\(\[E = \frac{{1.0792 \, \text{N}}}{{3.0 \times 10^{-9} \, \text{C}}}\]\)

E ≈ 359,733,333 N/C

Rounded to the appropriate number of significant figures, the strength of the electric field is approximately\(\[3.6 \times 10^8 \, \text{N/C}\]\).

Therefore, the correct answer is \(\[3.6 \times 10^8 \, \text{N/C}\]\)

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Answer:

New volume (V2) = 60 liter

Explanation:

Given:

Amount of helium (V1) = 20 Liter

Temperature (T1) = 100°K

Temperature (T2) = 300°K

Find:

New volume (V2)

Computation:

According to Gas Law:

V1 / T1 = V2 / T2

20 / 100°K = V2 / 300°K

V2 = 60 liter

New volume (V2) = 60 liter

Answer:

what does it mean for a plate to subduct?

Explanation:

Subduction is a geological process in which the oceanic lithosphere is recycled into the Earth's mantle at convergent boundaries. Where the oceanic lithosphere of a tectonic plate converges with the less dense lithosphere of a second plate, the heavier plate dives beneath the second plate and sinks into the mantle.

Answer:

The  correct option is  A

Explanation:

From the question we are told that

   The  velocity of the spy relative  to the carrier is  \(v_s = -4 \ m/s\)

    The  velocity of  the aircraft carrier is  \(v_a = 12 \ m/s\)

Generally the velocity of the spy according to the person standing stationary on the beach is mathematically represented as

         \(v = v_s + v_a\)

          \(v = -4 + 12\)

         \(v = 8 \ m/s\)

When the Earth was primarily liquid, it separated into layers. The density of Earth's different layers may be predicted. For instance, it is assumed that the outermost layer, or crust, is less dense than the inner layers.

The Earth's crust is mostly composed of silicates (such as quartz, feldspar, and mica) and rocks, which are less dense than the mantle, core, or outer core.

The mantle is composed of solid rock, which is denser than the Earth's crust.

The core is the most dense layer, and it is composed of a liquid outer core and a solid inner core.

Most of the Earth's layers are composed of different types of rock and minerals.

The layers were formed from the molten material that cooled and solidified.

The Earth's layers are divided into four groups, or spheres, that represent different levels of density.

The lithosphere is the outermost layer, which includes the crust and upper mantle.

The asthenosphere is the soft layer beneath the lithosphere.

The mantle is a solid layer that surrounds the core.

The core is the Earth's central layer, consisting of a liquid outer core and a solid inner core.

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Answer:

When a solid reaches the temperature of its melting point, it can become a liquid. For water, the temperature needs to be a little over zero degrees Celsius (0oC) for you to melt.

Explanation:

The surface area of the plates is 5.14 × \(10^{-10}\)  square meters.

The energy density (u) of a capacitor is given by:

u = (1/2) * ε * E^2

where ε is the permittivity of free space and E is the electric field between the plates of the capacitor.

The electric field is related to the voltage (V) across the capacitor and the distance (d) between the plates by:

E = V / d

The capacitance (C) of a parallel-plate capacitor is given by:

C = ε * A / d

where A is the surface area of each plate.

Using these equations, we can solve for the surface area of the plates:

First, we calculate the electric field:

E = V / d = (4.00 nC) / (ε * A / d) = (4.00 nC * d) / (ε * A)

Next, we can use the energy density equation to solve for ε:

u = (1/2) * ε * E^2

ε = 2 * u / E^2 = 2 * (3.62 × 10^-4 J/m^3) / [(4.00 nC * d / A)^2]

We can substitute this expression for ε into the capacitance equation:

C = ε * A / d = [2 * (3.62 × 10^-4 J/m^3) / [(4.00 nC * d / A)^2]] * A / d

Simplifying this expression, we get:

C = 2 * (3.62 × 10^-4 J/m^3) * A / [(4.00 nC)^2 * d^3]

Finally, we can solve for the surface area of the plates:

A = (C * (4.00 nC)^2 * d^3) / [2 * (3.62 × 10^-4 J/m^3)]

Substituting the given values, we get:

A = [(8.85 × 10^-12 F/m) * (4.00 × 10^-9 C)^2 * d^3] / [2 * (3.62 × 10^-4 J/m^3)]

A = 5.14 × \(10^{-10} m^2\)

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The final image is formed by two converging lenses at 15.3 cm in front of the second lens and the magnification of the system is -0.99.

To find the location of the final image, we can use the lens formula:

1/f = 1/do + 1/di

where f is the focal length of the lens, do is the object distance, and di are the image distance.

For the first lens, f = 14.8 cm and do = 30.0 cm. Plugging these values into the lens formula gives:

1/14.8 = 1/30 + 1/di

Solving for di, we get:

di = 20.1 cm

This means that the first lens forms an image 20.1 cm behind it, which serves as the object for the second lens.

Using the lens formula again for the second lens, f = 14.8 cm and do = 39.7 - 20.1 = 19.6 cm. Plugging these values into the lens formula gives:

1/14.8 = 1/19.6 + 1/di

Solving for di, we get:

di = 9.1 cm

Therefore, the final image is formed 9.1 cm behind the second lens.

To find the magnification of the system, we can use the formula:

m = - di/do

where m is the magnification, di is the image distance, and do is the object distance.

Plugging in the values we found, we get:

m = -9.1/30.0 = -0.303

Therefore, the magnification of the system is -0.303, which indicates that the image is inverted and smaller than the object.

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Answer and Explanation:

Given that

v_f = 5 km/s = 5,000 m/s

d = 4 m

v_i = 0 m/s

The computation is shown below:

1. The acceleration in m/s is

Here we use the motio third equation which is

\(v_f^2 = v_i^2 + 2ad\)

5000^2 = 0^2 + 2 (a) (4)

So

\(a = 3.125 \times 10^{6} m/s^2\)

2. Now acceleration in g is

\(= \frac{3.125 \times 10^{6} m/s^2}{9.81}\)

\(= 3.18 \times 10^{5}g\)

3. The long of acceleration last is

\(t = \frac{v-u}{a}\)

\(= \frac{5000 - 0}{3.125 \times 10^{6}}\)

\(= 1.6 \times 10^{-3}s\)

4.As we can see that

\(3.18 \times 10^{5}\) is smaller than the \(4.5 \times 10^{5}g\)

So, it should not be ruled out

Maria determines that the wavelength of a legitimate wave is 2.50 meters and that the wave is travelling at 340 m/s the frequency is mu = 136hz.

SO, the frequency of the sound wave is 136hz.Sound waves fall into 3 categories: longitudinal waves, mechanical waves, and strain waves. Keep studying to discover what qualifies them as such. Longitudinal Sound Waves - A longitudinal wave is a wave wherein the movement of the medium's debris is parallel to the path of the strength.

Here We have:

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