A solid conducting sphere is given a positive charge Q. How is the charge Q distributed in or on the sphere?
(A) It is concentrated at the center of the sphere.
(B) It is uniformly distributed throughout the sphere.
(C) Its density decreases radially outward from the center.
(D) Its density increases radially outward from the center.
(E) It is uniformly distributed on the surface of the sphere only.
The charge Q is uniformly distributed throughout the sphere. The correct answer is (B)
When a solid conducting sphere is given a positive charge Q, the charge will distribute itself evenly throughout the surface of the sphere due to the repulsion of like charges. This is known as the "Faraday's ice pail experiment".
According to the principle of electrostatics, the charge on a conductor always resides on its surface and distributes itself in a way that the electric field inside the conductor is zero. Since the charge on a conductor always resides on its surface, it follows that the charge Q in this case must be uniformly distributed throughout the surface of the sphere.
Option (A) is not true because the charge is not concentrated at the center of the sphere. If the charge was concentrated at the center of the sphere, the electric field would not be zero inside the conductor, which contradicts the principle of electrostatics.
Option (C) and (D) are not true because the density of the charge does not change radially outward from the center. If the density decreased or increased radially outward, the electric field inside the conductor would not be zero, which again contradicts the principle of electrostatics.
Option (E) is not true because the charge is distributed throughout the entire volume of the sphere, not just on its surface. A solid conductor has free charges that can move throughout its entire volume, so the charge will distribute itself throughout the entire volume of the sphere until the electric field inside the conductor is zero.
Therefore, the correct answer is (B) it is uniformly distributed throughout the sphere.
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What capacitor in series with a 100Ω resistor and a 25.0mH inductor will give a resonance frequency of 1000 Hz ? Express your answer in microfarads.
The capacitance of a capacitor in series with a 100 Ω resistor and a 25.0 mH inductor that would generate a resonance frequency of 1000 Hz is 0.399 µF.
Resonant frequency for a series RLC circuit is given by the expression f=1/2π√(LC). The values of C, L and f are given as 25.0 mH, 1000 Hz, and 100 Ω respectively. By substituting these values in the resonant frequency formula, we get 1000 = 1/2π√(C x 25.0 x 10⁻³).
Therefore, the capacitance can be found out as C = 1/[(2π x 1000)² x 25.0 x 10⁻³]C = 0.399 µF. Thus, a capacitor of 0.399 µF in series with a 100 Ω resistor and a 25.0 mH inductor would generate a resonance frequency of 1000 Hz.
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a catalyst lowers the activation energy of a reaction, but does not affect the reaction rate?
The given statement 'A catalyst lowers the activation energy of a reaction, but does not affect the reaction rate' is false.
The positive catalyst alters the rate of reaction by lowering the activation energy of reaction such that the heat of the reaction remains unaffected. This is because it provides a new path for the reaction. However, the heat of the reaction is the same.
A catalyst is a chemical that influences a reaction's rate without being consumed by the final product. This process is known as catalysis.
Lower activation energy catalysts include:
A catalyst decreases the activation energy by changing the transition state of the process.
The reaction then proceeds according to a different mechanism than an un-catalyzed reaction.
The catalyst joins the reactants to produce a complex that offers a different pathway for the reaction with a lower activation energy. Both the forward and backward reflexes are impacted equally.
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Two bowling balls are rolling towards each other at constant velocities. ball one has a velocity of 3 ft/s and ball two has a velocity of 5 ft/s. if they start 30 feet apart, how long (in seconds) will it take for them to collide?
The two balls will collide in 2 seconds if they start 30 feet apart.
To calculate the time it takes for the two balls to collide, we first need to calculate the distance between them. The distance between two objects is equal to their speed multiplied by the time it takes them to travel that distance: velocity × time = distance
In this case, we want our distance formula to be 3 ft/s × 2 seconds = 6 ft
Then, using our formula, we can find how long it would take for the two balls to collide by plugging in our numbers: 6 ft + 5 ft = 11 ft. When we add 11 ft into both sides of our equation, we get 0 seconds, which means that when these two balls collide, they collide at the same time.
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The base unit of length in the international system of units is the:
The base unit of length in the international system of units is the: meter (m)
MeterThe meter, ( symbol: m ) is the SI unit of length. It is derived by taking the fixed numerical value of the speed of light in vacuum c to be 299 792 458 when expressed in the unit m s-1
International system of unit ( SI ) base unitsThe SI base units are the standard units of measurement defined which is defined by the International System of Units (SI) for the seven base quantities of what is now known as the International System of quantities:
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Phineas and Ferb are riding their bikes on Main Street. They begin at 11 Mile Rd at
2:30 and get to 15 Mile Rd at 3:15.
How long, in HOURS, does it take Phineas and Ferb to travel? Show necessary
work for the conversion of minutes to hours.
Answer:
1 hour and 25 minutes
Explanation:
hopefully this helps ,, but like WHY phineas and ferb hshjdshjdhdhdbd im so childish
what are some ways to increase gravitational potential energy?
Answer:
Increase height
Increase mass
A 8.0 µF capacitor is charged by a 11.0 V battery through a resistance R. The capacitor reaches a potential difference of 4.00 V at a time 3.00 s after charging begins. Find R in kO.
I've been usingA 8.0 µF capacitor is charged by a 11.0 V bat, but I'm not sure if that is right since I just CAN'T get the right answer...I keep getting 370.7 kO (incorrect).
Can anyone please help me?
The value of R is 379 kΩ. Answer: R = 379 kΩ.
Given data: Capacitance C = 8.0 µF
Voltage V = 11.0 V Charge q
= CV = 8.0 × 10⁻⁶ F × 11 V
= 88 × 10⁻⁶ C Initial voltage V₀ = 0 V
Final voltage V = 4.00 V Time t = 3.00 s
Let resistance R be x kΩ.
The voltage across the capacitor is given by, V = V₀(1 - e⁻ᵗ/ᵣ)
Where, τ = RC is the time constant of the RC circuit.
Substituting the given values,4.00 V = 0(1 - e⁻³/τ)⇒ 1 - e⁻³/τ
= 0V / 4.00 V = 0 / V₀ - e⁻³/τ⇒ e⁻³/τ
= 4.00 V / 11.0 V⇒ e⁻³/τ = 0.3636
Taking natural logarithm on both sides,
ln e⁻³/τ = ln 0.3636⇒ -³/τ
= -1.0094...⇒ τ = 3.03 s Since τ
= RC = 3.03 s,8.0 × 10⁻⁶ F × x × 10³ Ω
= 3.03 s x
= 378.75 kΩ
≈ 379 kΩ
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The capacitor is charged by an 11.0 V battery through a resistance R is 1.38 kO.
The potential difference across the capacitor reaches 4.00 V at a time 3.00 s after charging begins.
R = (t/0.693) * (Vc/Vb - 1)Where,
R = resistance in ohms
C = capacitance in farad
t = time taken for the potential difference across the capacitor to reach Vc in seconds
Vc = potential difference across the capacitor in volts
Vb = emf of the battery in volts.
R = (3.00 s/0.693) * (4.00 V/11.0 V - 1) = 2.17 * (-0.636) = -1.38 kO
Since resistance cannot be negative, there is an error in the calculations.
We have to change the sign to get the correct value.
Therefore, the value of R is 1.38 kO.
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helpp!! Which of the following statements about the independent variable are correct?
a.The independent variable is mentioned in the hypothesis.
b.Scientists adjust the dependent variable to see its impact in the independent variable.
c.The independent variable is manipulated by the scientist.
d.The independent variable is held constant during an experiment.
e.A hypothesis predicts a relationship between the independent and dependent variable.
The statements about the independent variable that are correct are:
The independent variable is mentioned in the hypothesis.The independent variable is manipulated by the scientist.A hypothesis predicts a relationship between the independent and dependent variables.The correct option are A, C, and E.
What are independent and dependent variables?A variable that is independent is precisely what it sounds like. It is a stand-alone variable that is unaffected by the other variables you are attempting to assess. Age, for instance, could be an independent variable.
The dependent variable is the variable that is being measured in an experiment
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During anomalous expansion of water ,heat transfer is limited to conduction and radiation only ,explain.
Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density
What is anomalous expansion of water?Anomalous expansion of water is a property of water in which water expands instead of contracting.
Anomalous expansion of water makes water less dense. The major effect of this anomalous expansion it will still remain less dense and at the surface of water.Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.Learn more about properties of water:
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A projectile is fired from ground level with a speed of 150 m/s at an angle 30° above the horizontal on an airless planet where g = 10.0 m/s2. What is the horizontal component of its velocity after 4.0 s?
The horizontal component of its velocity after 4.0 s is 129.90 m/s after the projectile is fired from ground level with a speed of 150 m/s at an angle 30° above the horizontal on an airless planet where g = 10.0 m/s2.
What is the horizontal component of its velocity after 4.0 s? To find the horizontal component of its velocity after 4.0 seconds, we have to first find the initial horizontal velocity of the projectile as it was fired at an angle of 30° above the horizontal. We can use trigonometric ratios for that.
Hence, the initial horizontal component of the velocity = Vcosθ=150 cos 30°=150 × √3/2=129.90 m/s.
The vertical component of velocity is given by: Vsinθ=150 sin 30°=75.0 m/s.
Now, we can use the formula for the horizontal displacement of a projectile to find its horizontal velocity after 4 seconds, horizontal displacement of projectile= Vcosθ × t
So, the horizontal displacement of the projectile after 4 seconds= 129.90 × 4= 519.6 m
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(a) A bicycle generator rotates at 183 rad/s, producing an 18.5 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.650 T field. How many turns are in the coil?(b) Is this number of turns of wire practical for a 1.00 by 3.00 cm coil?
A bicycle generator with a rotating speed of 183 rad/s and a rectangular coil of dimensions 1.00 cm by 3.00 cm in a magnetic field of 0.650 T produces an emf of 18.5 V peak. The number of turns in the coil is approximately 248.
To calculate the number of turns in the coil, we can use the formula for the peak emf produced by a generator: emf = NABω, where N is the number of turns, A is the area of the coil, B is the magnetic field, and ω is the angular velocity.
Angular velocity (ω) = 183 rad/s
Peak emf (emf) = 18.5 V
Coil dimensions: length (l) = 3.00 cm = 0.03 m, width (w) = 1.00 cm = 0.01 m
Magnetic field (B) = 0.650 T
We can rearrange the formula to solve for N:
N = emf / (ABω)
Substituting the given values:
N = 18.5 V / (0.01 m * 0.03 m * 0.650 T * 183 rad/s)
N ≈ 248
Therefore, the number of turns in the coil is approximately 248.
The number of turns in the coil can be determined by using the formula for the peak emf produced by a generator. This formula relates the emf to the number of turns, the area of the coil, the magnetic field, and the angular velocity. By rearranging the formula, we can solve for the number of turns.
In this case, we are given the angular velocity, the peak emf, the dimensions of the coil, and the magnetic field. Substituting these values into the formula, we can calculate the number of turns in the coil, which is approximately 248.
It's worth noting that the practicality of the number of turns in the wire depends on various factors such as the intended application, the available space, and the desired output. However, without further information about the specific requirements and constraints, it is difficult to determine if the number of turns in the 1.00 cm by 3.00 cm coil is practical or not.
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Consider an airplane flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. Calculate the pressure at this point. Assume incompressible flow. Given: p _1 =7.01×10^4 N/m^2 and rho=0.909kg/m^3 . The pressure at a point on the wing is ×10 ^4 N/m^2
An airplane is flying with a velocity of 42 m/s at a standard altitude of 3 km. At a point on the wing, the airflow velocity is 88 m/s. The pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\).
To calculate the pressure at a point on the wing, we can use Bernoulli's equation, which relates the pressure, velocity, and density of a fluid in steady, incompressible flow.
The equation is as follows:
P + 1/2 * ρ * \(V^2\) = constant
where P is the pressure, ρ is the density of the fluid, and V is the velocity of the fluid.
Given:
\(P_1 = 7.01 * 10^4 N/m^2\) (pressure at standard altitude)
ρ = \(0.909 kg/m^3\) (density of the fluid)
\(V_1 = 42 m/s\) (velocity of the airplane)
\(V_2 = 88 m/s\) (velocity at the point on the wing)
To find the pressure at the point on the wing, we can use Bernoulli's equation for the standard altitude and the point on the wing, and then solve for P:
\(P_1 + 1/2\) * ρ * \(V_1^2\) = \(P + 1/2\) * ρ * \(V_2^2\)
Substituting the given values:
\(7.01 * 10^4 + 1/2 * 0.909 * 42^2 = P + 1/2 * 0.909 * 88^2\)
Simplifying the equation:
\(7.01 × 10^4 + 1/2 * 0.909 * 1764 = P + 1/2 * 0.909 * 7744\)
7.01 × 10^4 + 804.906 = P + 3526.242
\(P + 4329.148 = 7.01 *10^4\)
\(P = 7.01 * 10^4 - 4329.148\)
\(P = 6.96 * 10^4 N/m^2\)
Therefore, the pressure at the point on the wing is \(P = 6.96 * 10^4 N/m^2\)
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(BRAINLIEST!) Does more momentum mean more force?
Answer:
no.
Explanation:
Which of these sources are used to generate electrical energy in power plants? Check all that apply.
coal
natural gas
biodiesel
nuclear reactions
wind
batteries
water
Answer:
all but biodeisel and batteries
Explanation:
well batteries are used to STORE energy not generate it
True or false: power output can be increased by increasing the rate at which work is done.
By speeding up the process of doing work, power production may be enhanced. The following statement is true.
Description:
Work is completed at a rate determined by power. It is the ratio of work to time. It may be calculated mathematically using the next equation.
Power = Work / Time
or, P = W / T
If the amount of effort/work increases and the amount of time decreases, power will grow. To complete a task in a short amount of time, a lot of force is used.
The Watt is the common metric unit of power. A quantity of power is one unit of labor divided by one unit of time, as the expression for power suggests. As a result, one Watt is equal to one Joule/second. The term "horsepower" is sometimes used to describe a machine's output of power for historical reasons. The equivalence of horsepower is around 750 Watts.Therefore it is concluded that the questioned statement is true.
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A physics teacher is designing a ballistics event for a science competition. The ceiling is 3.00m high, and the maximum velocity of the projectile will be 20m/s.
What is the maximum that the vertical component of the projectiles initial velocity could have?
The launch proyectiles of kinematics allows to find the maximum initial vertical velocity of the body so that it just reaches the ceiling
v_{oy} = 2.56 m / s
Given parameters
The ceiling height y = 3 mTo find
Maximum vertical speed
Projectile launching is an application of kinematics where on the x axis there is no acceleration or and on the y axis the acceleration is the acceleration of gravity (g = 9.8 m / s ^ 2)
In this case, the maximum vertical velocity that the body can have occurs when the velocity on the ceiling is zero.
v_y² = v_{oy}² - 2 g y
where v and v_{oy} are the initial velocity at the ceiling e initial, respectively, g the acceleration of gravity e and the height
0 = v_{oy}² - 2 g y
v_{oy} = \(\sqrt{2gy}\)
v_{oy} = \(\sqrt{2 \ 9.8 \ 3}\)
v_{oy} = 2.56 m / s
In conclusion with the kinematic of launch projectiles we can find the maximum initial vertical velocity of the body so that it just reaches the ceiling
v_{oy} = 2.56 m / s
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Which quote best reveals why sowers was successful in achieving her goal?
The quote which best reveals why Sowers was successful in achieving her goal is "Make sure i'm not the last."
What is a goal?A goal can be defined as an outcome statement and strategic objectives that defines what an individual or a group of people (team) hopes to successfully achieve (accomplish) in the future i.e over a specific period of time.
This ultimately implies that, a goal is simply a futuristic idea or desired result that an individual envision, plan and commit to achieve over a specific period of time.
In this context, Katie Sowers a superbowl coach, set a goal for herself with the quote "Make sure i'm not the last" and she was quite successful in achieving her goal.
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Light travels through space at a speed of 3.0 x 108 m/s. A space probe is
traveling toward Earth at 2.5 * 108 m/s when one of its spotlights is turned
on. What speed would an observer on Earth measure for the light from the
spotlight?
O A. 2.5 * 108 m/s
O B. 3.0 x 108 m/s
O c. 5.5 x 108 m/s
O D. 0.5 x 108 m/s
Explanation:
The answer is (B). The speed of light is the same for all observers regardless of their motion relative to the light source.
The speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.
The given data in the problem is;
The speed of light is, \(\rm C =3 \times 10^8\ m/sec\)
All frames of reference have the same speed of light in a vacuum. Therefore the speed would an observer on Earth measures for the light from the spotlight will be 3×10⁸ m/sec.
Hence option B is correct.
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The difference between starting and ending
positions is
distance
displacement
Answer:
displacement
Explanation:
Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.
This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.
A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.
Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, position, displacement, etc.
Displacement can be defined as the change in the position of a body or an object. It is a vector quantity because it has both magnitude and direction.
This ultimately implies that, the difference between the starting and ending positions of a physical object is generally referred to as displacement
Hey solution that contains all of the salute it can normally hold at a given temperature is
Answer:
A saturated solution
Explanation:
A saturated solution is one that contains the most amount of solute that can be dissolved in it at a given temperature
An example of a saturated solution is carbonated water, which readily gives off bubbles of carbon dioxide gas from areas within the solution to the region above the top surface of the gas in liquid solution
A saturation solution of salt in water can be created by continuing to dissolve salt in a given amount of water until it can no longer dissolve any more salt. However, heating the saturated salt solution, increases the amount of salt that can be dissolved.
Therefore, a solution that contains all of the solute it can normally hold at a given temperature is a saturated solution
which law is described by saying that when the pressure of a gas in a sealed container is cut in half, the gas will double in volume at a steady temperature? boyle’s law charles’s law dalton’s law gay-lussac’s law
The law that describes the relationship between the pressure and volume of a gas in a sealed container is Boyle's law.
Boyle's Law, formulated by the Irish scientist Robert Boyle in the 17th century, describes the relationship between the pressure and volume of a gas at a constant temperature. It states that the pressure of a gas is inversely proportional to its volume when the temperature remains constant.
According to Boyle's law, when the pressure of a gas is cut in half, the volume of the gas will double, as long as the temperature remains constant. This means that if you decrease the pressure exerted on a gas by half, the volume of the gas will increase by a factor of two.
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Do you ever feel so depressed that you cant even cry anymore?
a thin glass rod is submerged in oil. what is the critical angle for light traveling inside the rod?
A thin glass rod submerged in oil. Then the sensitive angle of light propagating inside the rod with a glass refractive index of 1.50 and oil refractive index of 1.46 is 72°.
The critical angle is the angle of incident light from the denser medium to the less dense medium whose angle of refraction is parallel to the boundary between the two media. When the angle of incidence is greater than the critical angle, the light will be reflected completely back into the water. This event is called a perfect reflection.
To find the size of this critical angle, you can use the following Snell's Law:
Φk = sin⁻¹ (n₂ n₁)
Where:
Φk = critical angle (degrees)
n₁ = refractive index of the denser medium
n₂ = refractive index of the less dense medium
In matter
n₁ = 1.50
n₂ = 1.46
So,
Φk = sin⁻¹ (n₂/ n₁)
Φk = sin⁻¹ (1.46/1.50)
Φk = sin⁻¹ (0.923)
Φk = 72°
Your question is incomplete but most probably your full question was:
A thin glass rod is submerged in oil. What is the critical angle for light traveling inside the rod? The index of refraction for glass is 1.50 The index of refraction for oil is 1.46.
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uranus and neptune are like the other jovian planets because they:
Uranus and Neptune are like the other Jovian planets because they have a lot of gaseous composition, they lack a solid surface, and they are situated far from the sun.
The Jovian planets are four planets in the outer solar system that are gas giants, also known as the gas planets. They are Jupiter, Saturn, Uranus, and Neptune. In terms of the composition of Uranus and Neptune, they contain methane, ammonia, water, and other elements that form gas. Like the other Jovian planets, they lack a solid surface, and they are situated far from the sun.
The rings of Uranus and Neptune are fainter and less complex than the rings of Jupiter and Saturn, but they share certain features. Both Uranus and Neptune are thought to have a small rocky core surrounded by a mix of rock and ice, then a thick layer of metallic hydrogen, and an atmosphere mainly of molecular hydrogen and helium. So therefore because gaseous composition, lack a solid surface, and situated far from the sun, Uranus and Neptune are like the other Jovian planets.
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I need help pls. Will mark brainliest.
Ek=kinetic energy (J)
m=mass of object (Kg)
v=speed of object (m/s)
We have the following formula:
Ek=(1/2)mv² ⇒ m=2(Ek)/v²
In this case:
m= mass of the child + mass of the bike
m=30 kg + m₁ (m₁=mass of the bike).
We would have to modify our formula like this:
m=2(Ek)/v²
m=30 kg + m₁
30 kg +m₁=2(Ek)/v²
m₁=2(Ek)/v²-30 kg
We have the following data:
v=0.6 m/s
Ek=12.4J
m=30 Kg + m₁
Therefore:
m₁=2(Ek)/v² - 30 kg
m₁=2(12.4 J)/(0.6 m/s)² - 30 kg
m₁=24.8 J/(0.36 m²/s²) -30 kg
m₁=68.89 Kg - 30 kg
m₁=38.89 Kg
Answer: the mass of the bike is 38.89 Kg.
The drawings show the mass and weight of four objects on different planets:
(see the picture)
(a)
On which of the four planets is the object with the largest mass?
The object with the highest mass is the one on planet D. This is because mass is a measure of the amount of matter an object contains, and is not affected by gravity. Therefore, although the weight of the object on planet D is lower than that of the other planets, its mass remains the same.
Weight, on the other hand, is a measure of the gravitational force acting on an object. Therefore, the weight of an object will vary on different planets due to different gravitational forces. As shown in the drawings, the object on planet A has the greatest weight, but nevertheless the greatest mass.
In summary, the object with the greatest mass is on planet D, while the object with the greatest weight is on planet A.
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a rock is thrown upward with a velocity of 12 meters per second from the top of a 42 meter high cliff, and it misses the cliff on the way back down. when will the rock be 12 meters from ground level?
The rock will be 12 meters from the ground level after it has been thrown upward with a velocity of 12 meters per second from the top of the 42 meter high cliff for a total of 3.5 seconds.
What is the cliff?The cliff is the height that generally has the highest height and it can be mountains, stones, buildings.
This is because the total time taken for the rock to fall back down will be the same as the total time taken for the rock to reach the top of the cliff. The equation used to calculate this is: time = distance / velocity. Therefore:
Time = 42 meters (cliff height) / 12 meters per second (velocity) = 3.5 seconds.
So, the rock will be 12 meters from the ground level after 3.5 seconds.
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A bicycle possesses 1000 units of momentum. What would be the bicycle's momentun if,it's velocity is doubled?
Explanation:
p = mv ---> let v --> 2v (velocity is doubled) then
p' = m(2v)
= 2(mv)
= 2p
so the momentum also doubled
What are ways that Iron Man's repulsor technology doesn't break Newton's third law of motion?
The concept of the arc reactor doesn't work in real life because it violates the Law of Conservation of Energy. Energy can't be created or destroyed, only transferred. The arc reactors in the MCU are essentially perpetual motion machines, which don't work.
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