a planet has 1/2 the mass of earth and 2 times the radius of earth. what is the acceleration due to gravity?

Answer:

29.4 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 3 s

Find: v

v = at + v₀

v = (9.8 m/s²) (3 s) + 0 m/s

v = 29.4 m/s

Well, the lines of workings are cut off in the middle, and there's no 2nd image.

But I think it must have to do with the "cos" terms at the right end of the picture.

I'm guessing now, because the part I'm interested in would be just past the edge, where we can't see it.

I think that the first line says "cos(some angle)", and at the same place in the second line it says "cos(180 - the same angle)".

If that's what it says, then that's your answer, because cos(anything) is equal to the negative of cos(180 - the same thing).

That's the best I can do for you just now.  Honestly, I don't see the connection yet between the question Dave is working on and the two lines I see in the picture.

The measured frequency rises as the observation gets closer to the static source, exceeding the source rate. The frequency difference between the perceived and source frequencies occurs when an observation is moving further away from a stationary source.

When measuring noise out of a source, the spectator's movement may modify the frequency: A greater frequency is measured by an observation who is traveling to the source. Reduced frequency is measured by an observer who is progressing away from the source. A stationary wavelength is not affected while a source is travelling in its direction.

The observer's velocity will be zero as the source arrives; as both a result, variations in frequency and wavelength will occur. Due to their inverse relationship, when wavelength is increased, frequency drops and conversely. Inquiry shows that 1=[VV5V+O]. Contains a detailed prevalence has nevertheless grown. This also happens when waves constrict across shorter distances, that reduces effective wave length and raises frequency.

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The weight of the board influences the amount of effort required to move it because if it were too heavy, it would just sink, and if it were too light, it would simply float away.

The gravitational pull of a second, significantly bigger object, like the Earth or Moon, on a first object is known as weight. According to the universal law of gravity, any two objects will gravitate toward one another due to their masses with a force that is inversely proportional to the square of the distance between them and precisely proportional to the product of their masses. The source of weight is this law. Because of this, larger objects naturally weigh more when placed in the same location. However, the further an object is from the Earth, the less weight it has. An object's weight at the South Pole is somewhat higher than its weight at the North Pole because the Earth's polar radius is slightly less than its equatorial radius.

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The output force on the piece of food the chopsticks pick up is mechanical advantage times 3 N.

The force amplified by utilising a tool, mechanical device, or machine system is known as mechanical advantage. To achieve the desired output force amplification, the gadget trades off input forces against movement.

Mathematically:

mechanical advantage = output force/input force

Given that input force = 3 N.

Hence, output force = mechanical advantage × 3 N.

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Answer:

870 m

Explanation:

d = Vit + 1/2at²

a = ΔV/Δt = (85 m/s - 60 m/s) / (12 s) = (25 m/s) / 12 s = 2.08 m/s²

d = (60 m/s)(12 s) + 1/2 (2.08 m/s²)(12 s)² = 870 m

Answer:

The automobile traveled 870 meters during the 12 second interval.

Explanation:

We can use this kinematics equation to evaluate how far the automobile traveled.

\(\overline v=\frac{\Delta x}{\Delta t}\)

Note

\(\overline v\) is the average velocity

\(\Delta x\) is the change in position (displacement)

\(\Delta t\) is the change in time (time interval)

The formula for average velocity is

\(\overline v=\frac{V_f-V_o}{2}\)

We are given

\(V_f=85\\V_o=60\\\Delta t=12\)

First lets evaluate the average velocity.

\(\overline v=\frac{85-60}{2}\)

\(\overline v=72.5\)

Rearranging our kinematics equation to isolate \(\Delta x\) we get

\(\Delta x=\overline v \Delta t\)

Now lets evaluate \(\Delta x\).

\(\Delta x=72.5*12\\\Delta x=870\)

There are many different ways you can solve this; I could have used a different equation.

The distance covered by the truck would be 188.4 meters.

Initial velocity, u = 63 km/h = (63 x 1000 m) / (3600 s) = 17.5 m/s

Final velocity, v = 84 km/h = (84 x 1000 m) / (3600 s) = 23.3 m/s

We can use the equation:

v^2 = u^2 + 2as

where v is the final velocity, u is the initial velocity, a is the acceleration, s is the distance traveled.

Substituting the values we get:

(23.3)^2 = (17.5)^2 + 2(1.25)s

Simplifying and solving for s, we get:

s = [(23.3)^2 - (17.5)^2] / (2 x 1.25) = 188.4 meters (rounded to one decimal place)

Therefore, the truck travels a distance of 188.4 meters as it accelerates uniformly from 63 km/h to 84 km/h with an acceleration of 1.25 m/s^2.

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When viewed straight down (90° to the surface), an incident light ray moving from water to air does not undergo refraction as it passes through the interface.

When viewed straight down (90° to the surface), the incident light ray moving from water to air does not undergo refraction as it passes through the interface. Refraction occurs when light passes from one medium to another at an angle. At 90°, the light ray travels perpendicular to the surface, resulting in a normal incidence. In this case, the light ray does not change its direction as it transitions from water to air. The refractive index governs the bending of light at the interface, but at 90°, the change in direction is negligible. Therefore, the incident light ray appears to continue in a straight line without deviation when observed directly from above.

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Answer:

Anther....

My answers

The therapeutic method of free association is a form of psychoanalytic therapy that involves patients spontaneously expressing their thoughts, feelings, and impulses without censorship or guidance.

The therapeutic method of free association was developed by Sigmund Freud, the founder of psychoanalysis, to help patients uncover unconscious thoughts and emotions that may be causing psychological distress or contributing to problematic behaviors and relationships. Free association is a technique that allows patients to express themselves spontaneously, without censoring or filtering their thoughts or feelings. During therapy, patients are encouraged to report whatever comes to mind, whether it is an image, memory, feeling, or thought. The therapist listens attentively and may prompt the patient to explore a particular topic or issue if it seems relevant to the patient's symptoms or goals. The goal of free association is to access the unconscious mind, which is believed to contain repressed or forgotten memories, wishes, and conflicts that may be influencing the patient's current thoughts, feelings, and behaviors.

By exploring and processing these hidden contents of the mind, patients can gain insight into their unconscious motivations and resolve conflicts that may be causing distress or interfering with their ability to function effectively in the world. Free association is a long-term approach to therapy that requires a significant commitment of time and effort on the part of the patient. Therapy sessions may occur multiple times per week, and treatment may last for several years. However, free association is not appropriate for everyone, and some people may find it difficult to engage with the process. Additionally, some critics argue that free association lacks scientific support and is based on unproven assumptions about the unconscious mind and human behavior.

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If you decrease the atmospheric pressure around water at room temperature, it will result in a decrease in its boiling point. Here's an explanation of why this happens:

Relationship between Pressure and Boiling Point: The boiling point of a substance is the temperature at which its vapor pressure equals the atmospheric pressure.

At higher pressures, the vapor pressure required for boiling is also higher, resulting in a higher boiling point. Conversely, if you decrease the atmospheric pressure, the vapor pressure needed for boiling decreases, leading to a lower boiling point.

Effect of Decreased Pressure on Water: Normally, at standard atmospheric pressure (1 atm or 101.3 kPa), water boils at 100 degrees Celsius (212 degrees Fahrenheit).

However, if the atmospheric pressure is reduced, such as at higher altitudes or in a vacuum, the boiling point of water decreases. For example, at the top of a mountain with lower atmospheric pressure, water can boil at temperatures lower than 100 degrees Celsius.

Intermolecular Forces: The boiling point of water is primarily determined by intermolecular forces between water molecules. These forces, known as hydrogen bonding, are relatively strong and require a certain amount of energy to break for the liquid water to turn into vapor during boiling.

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When attempting to measure current flow, the ammeter should be inserted directly into the circuit so as to force each and every charge through the meter itself. This statement is False.

An ammeter is a device used to measure the current.

Ammeter is the necessary component must be inserted to the circuit. An ammeter is placed in series in the circuit in order to add its resistance. Ammeter doesn't force any charge to pass through it. It just measure the amount of charge passing through it.

Thus, the statement when attempting to measure current flow, the ammeter should be inserted directly into the circuit so as to force each and every charge through the meter itself is False.

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Answer:

follows are the responses to the given question:

Explanation:

The kinetic energy of every object moving.  \(PK=m \times v^2\) any entity lifted against the strength of gravity stores elastic potential of gravity.

\(PE = height \times mass \times g\)

Its total power of an independent device stays constant underneath the Mass conservation on Energy and it is, the kinetic energy plus potential energy is just like a fixed \((KE+PE=Standard)\). So, if KE improves, it is valid that PE declines.

If the PE is now at least then KE has been at the highest. It is also valid that KE is reduced as PE is increased as well as the maximum PE, the minimum KE.

Answer:

The variable that impacts kinetic energy is velocity, not mass.

The kinetic energy of an object is given by the formula KE = (1/2)mv^2, where m is the mass of the object and v is its velocity. From the given information, we can calculate the kinetic energy of each object as follows:

Object 1: KE = (1/2) x 2 kg x (2 m/s)^2 = 4 J

Object 2: KE = (1/2) x 4 kg x (3 m/s)^2 = 18 J

Comparing the two objects, we can see that the kinetic energy of the second object is greater than that of the first, even though its mass is greater. This is because the second object is being lifted at a faster rate (i.e., greater velocity) than the first object. Therefore, the variable that impacts kinetic energy in this scenario is velocity, not mass.

Explanation:

.

Answer:

142.7650889

Explanation:

I think the answer above is correct. So to find the velocity of the wave you can do: frequency*wavelength = velocity

in your case, the velocity is equal to 403.5m/s

so we know that the 403.52 is the total velocity of the wave

and the equation: velocity at 0 degrees Celsius * \(\sqrt{{T}/{273}}\) where T represents temperature in Kelvins = veloctity

so we set 403.52 = 327*\(\sqrt{{T}/{273}}\) and solve for T

T will then equal the degree in Kelvins

so to convert from Kelvins to degrees celsius you subtract 273 from the Kelvins value and you are left with the degrees in Celsius which equals 142.7650889 degrees Celsius

70 N force will the ball apply to a car if it hits a parked car at the bottom of the hill.

Push or pull on an object is called force and is unit is kg/ms⁻² or newton and is shown as N.

Force, F = ma

m = mass of an object, given = 10 kg

a = acceleration of an object, given = 7 ms⁻²

Put these values in the formula, F = ma

F = 10 × 7

F = 70 N

Hence, 70 N force will the ball apply to a car if it hits a parked car at the bottom of the hill.

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All the vectors would all be the same length.​

option D is the correct answer.

The magnitude of a vector is the length of the vector. This is the absolute value of the vector.

The length of a vector describes its magnitude, so the magnitude or length of the given vectors is determined as follows;

A vector representing 100 miles/hour north ⇒ magnitude = 100 miles / hour

A vector representing 100 miles/hour east ⇒ magnitude = 100 miles / hour

A vector representing 100 miles/hour south ⇒ magnitude = 100 miles / hour

Thus, all the given vectors have equal magnitude but different directions.

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The result is ,(a)  Z = sqrt((10^2) + (15^2)) = 18.03 ohms.
                    (b) the apparent power would be S = (120 V) x (1 A) = 120 VA.

To find the apparent power (total volt-amps) of a series circuit with a 10 ohm resistor and 15 ohms of inductive reactance in a single inductor, we first need to calculate the impedance of the circuit.

Impedance is the total opposition to current flow in an AC circuit and is a combination of resistance and reactance. In this case, we can use the formula Z = sqrt(R^2 + XL^2), where R is the resistance and XL is the inductive reactance.

To find the apparent power (S) of the circuit, we use the formula S = Vrms x Irms, where Vrms is the root mean square voltage and Irms is the root mean square current. Since we are not given any values for voltage or current, we cannot find the exact value of apparent power.

However, we can make some assumptions based on typical values for household circuits. For example, if the voltage is 120 volts (typical in the US) and the current is 1 amp,

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Answer: a!! Bc 10x2=20!

Explanation:

Answer:

20N

Explanation:

F=m*a

F=10*2

F=20N

.....

We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)

(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.

The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.

Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).

(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).

(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.

(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.

(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.

As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.

This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.

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The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

The height of the player above the ground can be calculated using the formula below.

Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

⇒ Solve for s.

Hence, The height at which the diver must jump in other to hit the water with a speed of 24 m/s is 29.4 m.

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Answer:

fif = 0.01 x 5000 = 50 N

Explanation:

u=150 m/s

v=0

m-10 y =0.01 kg

t=0.03s

s

v=utat

o= 150+a (0.03)

therefore a= -5000 m/s power 2

v power 2 = u power 2 + 2as

0=150 power 2+ 2 x (-5000) x s

therefore f=2.25 m

Answer:

Based on the properties electrically charged particles, we have that unlike charges attract and like charges repel each other. In order for proper application of an electrostatically negatively charged paint to be properly applied on the metal body surface of a vehicle, require that for attraction, the surface of the vehicle should be grounded and positively charged so as to effectively attract the negatively charged paint particles as it exits the nozzle, to form a strong attachment with the positively charged surface of the vehicle

Explanation:

In a beam subjected to pure bending, the maximum bending stress σmax could occur at the top surface of the beam and the outer edges of the beam. Therefore, the correct options are (a) Top surface of the beam and (d) Outer edges of the beam.

A beam is a structural element that is capable of withstanding loads primarily by resisting against bending.

Bending stress is the stress induced in a beam when it is subjected to a transverse load. Bending stress is maximum at the top surface of the beam and the outer edges of the beam. The neutral axis is the line along the beam where no stress is induced.

So the maximum bending stress σmax can not occur at the neutral axis of the beam.Therefore, the correct options are (a) Top surface of the beam and (d) Outer edges of the beam.

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The atomic mass number of the element is approximately 70. The mass density of a substance is defined as the mass per unit volume, while the number density is defined as the number of atoms per unit volume.

In order to determine the atomic mass number of the element, we need to understand the relationship between these two quantities. The mass density can be calculated using the formula:

\(\[ \text{Mass density} = \text{Atomic mass} \times \text{Number density} \times \text{Atomic mass unit} \]\)

Where the atomic mass unit is equal to the mass of one atom. Rearranging the formula, we can solve for the atomic mass:

\(\[ \text{Atomic mass} = \frac{\text{Mass density}}{\text{Number density} \times \text{Atomic mass unit}} \]\)

Substituting the given values, we find:

\(\[ \text{Atomic mass} = \frac{1750 \, \text{kg/m}^3}{4.39 \times 10^{28} \, \text{atoms/m}^3 \times \text{Atomic mass unit}} \]\)

The atomic mass unit is defined as one-twelfth the mass of a carbon-12 atom, which is approximately \(\(1.66 \times 10^{-27}\) kg\). Plugging in this value, we can solve for the atomic mass:

\(\[ \text{Atomic mass} = \frac{1750 \, \text{kg/m}^3}{4.39 \times 10^{28} \, \text{atoms/m}^3 \times 1.66 \times 10^{-27} \, \text{kg}} \]\)

Calculating this expression gives us the atomic mass number of approximately 70 for the given element.

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Answer:

speed :m/s

velocity:m/s-¹

acceleration:m/s²

force:kgms-²

Explanation:

I hope May be correct

Speed: It is the rate at which object covers or travelled particular distance or rate at which objects changes its position. S.I. unit for speed is metre per second (m/s).

Speed (s) = distance (d) / time (t)

Velocity: Distance covered by a moving object in a particular direction per unit time. S.I. unit of velocity is m s-1 or m/s.

Velocity (v) = Total displacement (d) / time take(t)

Momentum: It is quanity of motion of the object. S.I. Unit is Kg.m.s-1

Momentum (p) = Mass (m) X Velocity (v)

Acceleration: Rate at which an object velocity changes with respect to time. S.I. unit is metres/second2 (m/s2) Acceleration (a) = Change in velocity/ time taken

Force: When an object changes it position or direction due to external agent. S.I. unit of force is (Kg m/s2).

Force (F) = Mass(m) × Acceleration (a)

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In order to use the efficiency of a car engine in an optimal way, a maximum engine speed of 2500 RPM for shifting is recommended for gas engines.

A car's fuel efficiency is determined by how well it converts the energy in its fuel into kinetic energy for movement.

Most of the time, it's advisable to maintain a speed below 2500 rpm for economic reasons.

Range of 2000-2500 rpm is the best for shifting as

1) It is the most favorable range for the engine due to economic reasons.

2) It saves fuel.

3) It also keeps the engine heavy.

After this range, the economy usually declines.

Even though moving gears doesn't significantly affect engine life due to technological developments, but shifting for gas engines is recommended at 2000-2500 rpm.

Hence, 2500 rpm is the maximum engine speed recommended for gas engines for shifting.

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The law of conservation of energy

Energy cannot be created or destroyed, but it can be changed from one form to another.

KE + PE = constant