A person slides a box down a ramp. The box starts from rest 2m above the lowest point. The ramp is frictionless. Once the box reaches the bottom there is friction. For every 1m the box travels on the flat part increases by 100 J. Where does the box stop? The box has mass of 5 kg.

Answers

Answer 1

Answer:

.98m

Explanation:

Vf=Vi+2at

(V F)^2+2 ( change in distance )

X f= i ( change in V & T )

EK=1/2Mv^2,EG=mgh

Answer 2

This question involves the concepts of the law of conservation of energy, work done, Newton's Second law of motion, and equation of motion.

The box stops at a distance of "1.02 m".

First, we will use the law of conservation of energy to find out the final velocity when the box reaches the flat part.

\(Loss\ of\ Potential\ Energy=Gain\ in\ Potential\ Energy\\mgh=\frac{1}{2}mv^2\\\\2gh=v\\v=\sqrt{2gh}\)

where,

v = speed = ?

g = 9.81 m/s²

h = height = 2 m

Therefore,

\(v=\sqrt{(2)(9.81\ m/s^2)(2\ m)}\)

v = 6.26 m/s

Now, we will use the formula of work done to find out the force applied to the box to stop the motion:

\(W = Fd\)

where,

W = Work Done = 100 J

F = Force applied = ?

d = displacement = 1 m

Therefore,

\(100\ J = F(1\ m)\\F = 100\ N\\\)

Now, we will use Newton's Second Law of Motion to find out the deceleration of the person:

\(F=ma\)

where,

m = mass = 5 kg

a = decceleration =?

Therefore,

\(100\ N = (5\ kg)a\\\\a=\frac{100\ N}{5\ kg}\\\\a = - 20\ m/s^2\)

negative sign shows deceleration.

Now, we will use the third equation of motion to find the distance at which the box stops.

\(2as=v_f^2-v_i^2\\2(-20\ m/s^2)s=(0\ m/s)^2-(6.26\ m/s)^2\\\\s=\frac{40\ m/s^2}{39.24\ m^2/s^2}\)

s = 1.02 m

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The attached picture shows the equations of motion in the horizontal and vertical directions.

A Person Slides A Box Down A Ramp. The Box Starts From Rest 2m Above The Lowest Point. The Ramp Is Frictionless.

Related Questions

A ball is moving with a velocity of 0.5m/s. It’s velocity is decreasing at the rate of 0.05m/s. What is its velocity after 5 seconds?

Answers

Given,

u = 0.5 m/s

a=0.05 m/s²

and v=0

Now, v = u − at

=> 0 = 0.5−(0.05×t)

=> t = 10 s

after 10s it will stop

velocity after 5s is

v = 0.5-(0.05×5) = 0.25 m/s

Answer:

0.25 meter per second

Explanation:

I hope this helps and study well

In the long run, people who practice self-regulation through physical exercise and time-managed programs experience an increase in

Answers

Answer:

Self control

Explanation:

Self control involves individuals having a strong discipline towards certain conditions. The conditions could be cravings for something or other forms of activities.

Self control is usually developed by people who practice self-regulation through physical exercise and time-managed programs experience as they have been known to bring about an increase in it.

When a hot object makes a cold object warmer what is it called

Answers

Its called heat transfers

how do the sun and moon work together to create a neap tide?

Answers

Answer:

Neap tide, which also occour twice a month. It happens when sun and moon are right angle to each other.

Explanation:

In both cases, the gravitational pull of the sun is addedto the gravational pull of the moon on the Earth.

outward from a wall just above floor level. A 1.5 kg box sliding across a frictionless floor hits the end of the spring and compresses it 6.5 cm before the spring expands and shoots the box back out. How fast was the box going when it hit the spring?

Answers

Answer:

v = 0.489 m/s

Explanation:

It is given that,

Mass of a box, m = 1.5 kg

The compression in the spring, x = 6.5 cm = 0.065 m

Let the spring constant of the spring is 85 N/m

We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.

\(\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2\)

\(v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{85\times (0.065)^2}{1.5}} \\\\v=0.489\ m/s\)

So, the speed of the box is 0.489 m/s.

technician a says the charging system is needed to keep the battery fully charged and recharge the battery after starting. technician b say the charging system supplies all the vehicle's electrical current needs after the engine starts. who is correct?

Answers

Answer:

Technician A is correct

Explanation:

The statement "charging system is needed to keep the battery fully charged and recharge the battery after starting" is correct

from technician's B point of view, that the charging system supplies electrical current needs after engine start is incorrect.

In-fact the charging system is dedicated to the battery alone, the electrical needs of the system is gotten from the battery.

what is the unit scientist use to measure energy?

Answers

answer:

scientists use a measurement called BTU to measure energy

A 0.187 A current flows through a wire. How much time will it take for 2.00 C of charge to flow past a point in the wire?
A. 10.7 s
B. 2.18 s
C. 0.374 s
D. 0.0935 s​

Answers

The time taken for the given charge to flow past a point in the wire is 10.7s

Hence, option A)10.7s is the correct answer.

What is Current?

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = Q/t

Where Q is the charge and t is time elapsed.

Given that;

Current I = 0.187ACharge Q = 2.00CTime elapsed t = ?

I = Q/t

0.187A = 2.00C / t

t = 2.00C / 0.187A

t = 10.7s

The time taken for the given charge to flow past a point in the wire is 10.7s

Hence, option A)10.7s is the correct answer.

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TRUE OR FALSE most astronomers now believe the demise of the dinosaurs 65 million years ago was caused by a large asteroid impacting the yucatan peninsula area.

Answers

True. Most astronomers believe that the demise of the dinosaurs 65 million years ago was caused by a large asteroid impact in the Yucatan Peninsula area, based on extensive evidence from geology, palaeontology, and impact crater studies.

True. The majority of astronomers and scientists support the theory that the extinction event leading to the demise of the dinosaurs 65 million years ago was caused by a large asteroid impact in the Yucatan Peninsula area. Extensive evidence, including the discovery of the Chicxulub impact crater, supports this hypothesis. Geological studies reveal a layer of sediment rich in iridium, a rare element found in higher concentrations in asteroids. Additionally, the discovery of shocked quartz and tektites, along with the global distribution of the debris layer, further supports the impact theory. This widely accepted explanation combines astronomical, geological, and paleontological evidence to attribute the extinction event to a significant asteroid impact.

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express the internal shear and moment in terms of x and then draw the shear and moment diagrams

Answers

To express the internal shear and moment in terms of x, we first need to understand the concept of shear and moment. Shear refers to the force that acts perpendicular to the axis of a beam, while moment refers to the twisting force that occurs when a beam is loaded.

Assuming that we are dealing with a simply supported beam, we can start by analyzing the reactions at the supports. From there, we can use the equations of equilibrium to calculate the internal shear and moment at any point x along the beam.

The internal shear at a given point x can be calculated by summing up all the forces acting to the left or right of that point. The internal moment, on the other hand, can be calculated by summing up the moments of all the forces acting to the left or right of that point.

Once we have determined the internal shear and moment at different points along the beam, we can plot them on a shear and moment diagram. The shear diagram shows how the internal shear varies along the length of the beam, while the moment diagram shows how the internal moment varies. These diagrams are useful for understanding how a beam will behave under different loading conditions and can help engineers design more efficient structures.

In summary, to express the internal shear and moment in terms of x and draw the shear and moment diagrams, we need to analyze the reactions at the supports, calculate the internal shear and moment at different points along the beam using the equations of equilibrium, and plot them on the diagrams. This process helps us understand the behavior of a beam under different loading conditions and design more efficient structures.

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express the internal shear and moment in terms of x and then draw the shear and moment diagrams

A circuit carries a current of 0.64 A when there is a resistance of 50.0 Ω. The voltage applied to the circuit, to the nearest whole number, is ___ V.

Answers

V = I • R

V = 32 volts

Answer:

32v

Explanation:

edge 2023

What could you do to find the density of a fork, knife, and a spoon?

Answers

Answer:

Density is equal to mass divided by volume.

Explanation:

Density = mass / volume

or

p=m/v

Answer:

Use the formula D=m/v

Explanation: In order to find the volume for these objects, use a ruler and measure the length, width, and height. Proceed to multiply them all together, L*W*H. To find the mass of an object, I would say to use a triple beam balance. After finding both the mass and volume of you object, use the formula D = m/v and you'll get your answer.

A ring galaxy such asHoag's Object that is the result of a collision would be classified as a

a. type Irr I.
d. type Irr II.
c. type Sc.
d. type SBc.
e. peculiar galaxy.

Answers

A ring galaxy such as Hoag's Object that is the result of a collision would be classified as a e. peculiar galaxy.

What is a peculiar galaxy ?

A peculiar galaxy is a type of galaxy that does not fit into any of the traditional classifications. Peculiar galaxies can have a variety of different shapes and sizes, and they are often the result of collisions or mergers between galaxies.

Hoag's Object is a ring galaxy, which means that it has a ring of stars and gas surrounding a central nucleus. The ring is thought to have formed when a smaller galaxy collided with Hoag's Object and was absorbed.

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Use equations and physical relations to calculate the following variables for a parcel with the same starting conditions as done in class: a temperature of 30

C and a dewpoint of 20

C at 1000mb. Show your work or explain why you don't need an equation to solve for a particular variable. You may not use the skew-T to calculate the variables in this question. Assume adiabatic motion with no loss of water due to precipitation. c. At 500mb:T=−3.75

C i. Actual vapor pressure (e) ii. Saturation vapor pressure (e
s

) iii. Actual mixing ratio (r) iv. Saturation mixing ratio (r
5

) v. Total water mixing ratio (r
T

) vi. Available supersaturation (S
A

) vii. Excess water mixing ratio (r
F

)

Answers

The variables for the given parcel with a temperature of 30°C and a dewpoint of 20°C at 1000mb are as follows:

i. Actual vapor pressure (e)

ii. Saturation vapor pressure (es)

iii. Actual mixing ratio (r)

iv. Saturation mixing ratio (r5)

v. Total water mixing ratio (rT)

vi. Available supersaturation (SA)

vii. Excess water mixing ratio (rF)

To calculate the variables, we can use the following equations and physical relations:

i. Actual vapor pressure (e):

We can use the Clausius-Clapeyron equation to calculate the actual vapor pressure:

e = es(T) * (rh/100)

where es(T) is the saturation vapor pressure at temperature T, and rh is the relative humidity.

ii. Saturation vapor pressure (es):

We can use the Arden Buck equation to calculate the saturation vapor pressure:

es = 6.112 * exp((17.67 * T)/(T + 243.5))

where T is the temperature in °C.

iii. Actual mixing ratio (r):

The actual mixing ratio can be calculated using the following equation:

r = (0.622 * e)/(p - e)

where e is the actual vapor pressure and p is the atmospheric pressure.

iv. Saturation mixing ratio (r5):

The saturation mixing ratio can be calculated using the following equation:

r5 = (0.622 * es)/(p - es)

v. Total water mixing ratio (rT):

The total water mixing ratio can be calculated by summing the actual mixing ratio and the excess water mixing ratio:

rT = r + rF

vi. Available supersaturation (SA):

The available supersaturation can be calculated using the following equation:

SA = (rT - r5)/r5 * 100

vii. Excess water mixing ratio (rF):

The excess water mixing ratio can be calculated by subtracting the saturation mixing ratio from the actual mixing ratio:

rF = r - r5

By using these equations and the given starting conditions, we can calculate the values of the variables mentioned above.

The calculations for the variables mentioned involve utilizing several equations and physical relations related to atmospheric thermodynamics. These equations are derived from fundamental principles and empirical relationships that describe the behavior of water vapor in the atmosphere. By applying these equations to the given conditions, we can determine values such as actual vapor pressure, saturation vapor pressure, actual mixing ratio, saturation mixing ratio, total water mixing ratio, available supersaturation, and excess water mixing ratio. These variables provide valuable information about the moisture content and saturation levels of the parcel of air being analyzed. Each equation serves a specific purpose in quantifying these properties and allows for a comprehensive understanding of the thermodynamic state of the parcel.

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What is the main function of the mitochondria in a cell?

Answers

Answer:

Below :)

Explanation:

It is the powerhouse of the cell and creates chemical energy.

Answer: Mitochondria are organelles that provide energy to the cell. A mitochondrion is an organelle that contains a nucleus and a small number of mitochondria. Mitochondria are made up of an inner mitochondrial membrane and an outer membrane. A cell contains a number of different types of mitochondria, each with a unique function. Some mitochondria are used to produce

Explanation:

why should you terminate coaxial cable with connectors that are rated for the exact cable type?

Answers

It's essential to terminate coaxial cables with connectors rated for the exact cable type because it ensures optimal performance, signal integrity, and impedance matching.

Terminating a coaxial cable with connectors that are rated for the exact cable type is important because it ensures optimal performance and signal integrity. Coaxial cable is designed to carry high-frequency signals, and the connectors play a crucial role in maintaining the quality of those signals. Different cable types have different electrical characteristics, such as impedance, capacitance, and attenuation, and using the wrong connectors can lead to impedance mismatches, signal loss, interference, and other issues. For example, if you use connectors with a higher impedance rating than the cable, it can cause reflections and reduce the amount of power that reaches the destination. On the other hand, if you use connectors with a lower impedance rating, it can cause signal distortion and reduce the signal-to-noise ratio. Therefore, it is important to choose connectors that match the cable type and meet industry standards to ensure reliable and consistent performance.
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A car accelerates by 4 m/s^2 and travels for 2.5 mins with an initial velocity of 20m/s. Find the final velocity.

Answers

Answer:

540m/s

Explanation:

v= u + at

u change t to seconds

A box of mass 50kg is pulled up from the hold of a ship with an acceleration of 1 meter per second square by a vertical rope attached to it. Find the tension in the rope.

Answers

The tension in the rope that has a box of 50 kg tied to it is 540 N.

What is tension?

Tension is described as the pulling force transmitted axially by the means of a string, a rope, chain, or similar object.

To calculate the tension in the rope, we use the formula below.

Formula:

T = m(a+g)..................... Equation 1

Where:

T = Tension of the ropem = Mass of the boxa = Accelerationg = Acceleration due to gravity

From the question,

Given:

m = 50 kga = 1 m/s²g = 9.8 m/s²

Substitute these values into equation 1

T = 50(9.8+1)T = 50(10.8)
T = 540 N

Hence the tension is 540 N.

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A capacitor is discharged through a 20.0 Ω resistor. The discharge current decreases to 22.0% of its initial value in 1.50 ms.
What is the time constant (in ms) of the RC circuit?
a) 0.33 ms
b) 0.67 ms
c) 1.50 ms
d) 3.75 ms

Answers

The time constant (in ms) of the RC circuit is 3.75 ms. Hence, the correct option is  (d) 3.75 ms.


The rate of decay of the current in a charging capacitor is proportional to the current in the circuit at that time. Therefore, it takes longer for a larger current to decay than for a smaller current to decay in a charging capacitor.A capacitor is discharged through a 20.0 Ω resistor.

The discharge current decreases to 22.0% of its initial value in 1.50 ms. We can obtain the time constant of the RC circuit using the following formula:$$I=I_{o} e^{-t / \tau}$$Where, I = instantaneous current Io = initial current t = time constant R = resistance of the circuit C = capacitance of the circuit

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The time constant of the RC circuit is approximately 0.674 m s.

To determine the time constant (τ) of an RC circuit, we can use the formula:

τ = RC

Given that the discharge current decreases to 22.0% of its initial value in 1.50 m s, we can calculate the time constant as follows:

The percentage of the initial current remaining after time t is given by the equation:

I(t) =\(I_oe^{(-t/\tau)\)

Where:

I(t) = current at time t

I₀ = initial current

e = Euler's number (approximately 2.71828)

t = time

τ = time constant

We are given that the discharge current decreases to 22.0% of its initial value. Therefore, we can set up the following equation:

0.22 =\(e^{(-1.50/\tau)\)

To solve for τ, we can take the natural logarithm (ln) of both sides:

ln(0.22) = \(\frac{-1.50}{\tau}\)

Rearranging the equation to solve for τ:

τ = \(\frac{-1.50 }{ ln(0.22)}\)

Calculating this expression:

τ ≈ 0.674 m s

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Howard i moving a 90 kg wooden crate from one ide of hi office to the other. To accomplih thi, he tie a rope around hi wait and begin to walk, o that the crate i dragged horizontally acro the floor. If the coefficient of friction between the crate and the floor i 0. 159, what force mut Howard apply to to the rope to move at a contant peed?

Answers

The force exerted by Howard on the rope to make it move at a constant speed is 140.24 N.

The force that Howard must exert on the rope to move at a constant speed is calculated by applying Newton's second law of motion as follows:

F - Ff = ma

F: the applied force

Ff: the frictional force

m: the mass of the crate's mass

a: the acceleration of the crate (at a constant speed, acceleration: a = 0)

F = Ff

F = μmg

Given in question

Friction coefficient: μ = 0.159Gravity speed: g = 9.8 m/sCrate mass : m = 90 kg

F = μmg

F = 0.159 x 90 x 9.8

F = 140.24 N

Then the force Howard exerts on the rope to move at a constant speed is 140.24 N

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What is the strength of the electric field 0. 020 m from a 12 µC charge? (Use k=) 5. 4 × 106 N/C 2. 7 × 108 N/C 5. 4 × 1012 N/C 2. 7 × 1014 N/C.

Answers

The correct answer is 3. 2.7 × 106 N/C.

To determine the strength of the electric field at a certain distance from a charged object, we can use Coulomb's law and the formula for electric field intensity. Coulomb's law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

The formula for the electric field intensity (E) due to a point charge is given by:

E = k * (Q / \(r^2\))

Where:

E is the electric field intensity

k is Coulomb's constant (k = 9 x \(10^9\) Nm²/C²)

Q is the charge

r is the distance from the charge

In this case, we are given a charge of 12 µC (microcoulombs) and a distance of 0.020 m. Plugging these values into the formula, we get:

E = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.020 m)²

Simplifying the calculation, we find:

E = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.020 m)²

  = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.0004 m²)

  = 108 N/C * 12 x \(10^{-6}\) C / 0.0004 m²

  = 108 N/C * 0.012 C / 0.0004 m²

  = 1296 N/C / 0.0004 m²

  = 3240000 N/C

Therefore, the strength of the electric field at a distance of 0.020 m from a 12 µC charge is 3,240,000 N/C.

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a ceiling fan is turned on and a net torque of 1.6 n·m applied to the blades. the blades have a total moment of inertia of 0.60 kg·m2. what is the angular acceleration of the blades?

Answers

If a net torque of 1.6 n·m is applied to the blades of a fan having a moment of inertia of 0.6 kg.m² then the angular acceleration of the blades is 2.67 rad/s².

The relationship between torque, moment of inertia, and angular acceleration is given by the equation:

Net torque = moment of inertia x angular acceleration

We are given the net torque as 1.6 n·m and the moment of inertia as 0.60 kg·m².

1.6 n·m = 0.60 kg·m² x angular acceleration

Angular acceleration = 1.6 n·m / 0.60 kg·m²
Angular acceleration = 2.67 rad/s²
Therefore, the angular acceleration of the blades is 2.67 rad/s².

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please help will give brainlyest

please help will give brainlyest

Answers

16.34 km/2.34 h = 6.98 km/h

In a 92 s interval, 562 hailstones strike a glasswindow of area 1.216 m² at an angle 64° to thewindow surface. Each hailstone has a mass of2 g and speed of 5.8 m/s.If the collisions are elastic, find the averageforce on the window.Answer in units of N.

Answers

Given that the number of hailstones is n = 562

The mass of hailstone is m = 2 g = 0.002 kg

The speed of hailstone is v = 5.8 m/s

The time taken will be t = 92 s

The angle is

\(\theta=64^{\circ}\)

We have to calculate the force.

The force can be calculated by the formula

\(\begin{gathered} F=\text{ force due to one hailstone }\times numberofhailstones\text{ } \\ =m\frac{v}{t}\sin \theta\times n \end{gathered}\)

Substituting the values, the force will be

\(\begin{gathered} F=\text{ }\frac{\text{0.002}\times5.8\times\sin 64^{\circ}\times562}{92} \\ =0.063\text{ N} \end{gathered}\)

Two people try to lift a heavy box. Jack pulls upward with a 100-newton
force. Jill pulls upward with a 50-newton force, but neither person moves the
box.
Compare the amount of work done on the box by Jack and Jill.
OA) Jack did twice as much work as Jill.
OB) Jack did fifty times more work than Jill.
OC) Jack and Jill did the same amount of work.​

Answers

Answer:

A ( Jack did twice as much work as Jill

Explanation:

A small dog walks 12 meters east and then 5 meters north. How many meters is the dog from her starting position?

Answers

Answer:

17 meters

Explanation:

because 12 meters +5 meters =17 meters

6th grade science I mark as brainliest.​

6th grade science I mark as brainliest.

Answers

Answer:

\(\huge\boxed{\sf Speed = 2 \ m/s}\)

Explanation:

Given:

Time = t = 45 seconds

Distance = S = 90 meters

Required:

Speed = v = ?

Formula:

v = S / t

Solution:

v = 90 / 45

Speed = 2 m/s

\(\rule[225]{225}{2}\)

Hope this helped!

~AnonymousHelper1807

Which of the following careers is most likely to require business skills?
Systems Analyst
Hardware Engineer
Software Engineer
Database Administrator

Answers

Answer:  

C. Software Engineer

What happens to the structure of an atom when the atom is ionised?​

Answers

Answer: Explanation:

If the number of electrons is equal to the number of protons then the atom is uncharged and is electrically neutral. However, atoms can gain or lose electrons: increasing or decreasing the negative charge. Ionisation is the addition or removal of an electron to create an ion. ..Gaining an electron creates a negative ion.

A body fell freely for 6s.From what height did it start to fall and what was it's speed at the end of the fall?​

Answers

Answer:

Free fall / falling speed equations

1. The force of gravity, g = 9.8 m/s2 Gravity accelerates you at 9.8 meters per second per second. ...

2. Time to splat: sqrt ( 2 * height / 9.8 ) ...

3. Velocity at splat time: sqrt( 2 * g * height ) ...

4. Energy at splat time: 1/2 * mass * velocity2 = mass * g * height.

Explanation:

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