A person in the back of a pick-up moving at 20 m/s relative to the Earth, throws a baseball with a speed of 15 m/s in a direction opposite the motion of the truck (consider the direction of the truck’s velocity to be positive). What is the velocity of the ball relative to the Earth as it leaves the thrower’s hand?

Answers

Answer 1

Answer:

This is known as a Galilean transformation where

V' = V - U

Where the primed frame is the Earth frame and the unprimed frame is the frame moving with respect to the moving frame

V - speed of object in the unprimed frame

U - speed of primed frame with respect to the unprimed frame

Here we have:

V = -15 m/s        speed of ball in the moving frame (the truck)

U =  -20 m/s        speed of primed (rest) frame with respect to moving frame

So  V' = -15 - (-20) = 5 m/s

It may help if you draw a vector representing the moving frame and then add

a vector representing the speed of the ball in the moving frame.


Related Questions

If we drop two iron balls, one ball is bigger than another one, from
same height which will fall first to ground? Explain why.

Answers

Answer:

The bigger one. Ignoring air resistance, they will fall at the same speed, but the bigger one will hit first because it sticks out lower.

Explanation:

how much charge is on each plate of a 3.00-µf capacitor when it is connected to a 18.0-v battery? µc (b) if this same capacitor is connected to a 2.50-v battery, what charge is stored?

Answers

The charge on each plate of the capacitor is 7.50 µC.

The charge on each plate of a capacitor can be calculated using the formula

Q = C * V,

where Q is the charge, C is the capacitance, and V is the voltage. For a 3.00-µF capacitor connected to an 18.0-V battery, the charge on each plate would be:

Q = C * VQ

Q = (3.00 × 10^-6 F) * (18.0 V)

Q = 54.0 × 10^-6 CQ = 54.0 µC

So the charge on each plate of the capacitor is 54.0 µC.

If the same capacitor is connected to a 2.50-V battery, the charge on each plate would be:

Q = C * VQ

Q = (3.00 × 10^-6 F) * (2.50 V)

Q = 7.50 × 10^-6 CQ

Q= 7.50 µC

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A bullet is fired with an initial velocity of 100 m/s at an angle of 30° from the level ground. Determine the amount of time the bullet spends in the air.

Answers

In order to calculate the amount of time, first let's calculate the vertical speed of the bullet:

\(\begin{gathered} V_y=V\cdot\sin (\theta) \\ V_y=100\cdot\sin (30\degree) \\ V_y=100\cdot0.5 \\ V_y=50\text{ m/s} \end{gathered}\)

Since the displacement of the bullet is zero (it starts from the ground and finishes at the ground), let's use the following formula to find the time:

\(\begin{gathered} \Delta S=V_0t+\frac{at^2}{2} \\ 0=50\cdot t+\frac{(-9.8)t^2}{2} \\ 0=50t-4.9t^2 \\ 4.9t^2=50t \\ 4.9t=50 \\ t=\frac{50}{4.9} \\ t=10.2\text{ seconds} \end{gathered}\)

If the sun exploded would the solar system collaspe?

Answers

Answer:

Yes, yes it would since we need light

Explanation:

A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?

Answers

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Vector A points South. Vector B points West.
What is the direction of their cross product a X b
1. A ×B = 0, its direction is undefined
2. South
3. None of the other answers
4. A ×B a scalar and has no direction
5. Vertically Up
6. North
7. Vertically Down
8. Southwest
9. West
10. E

Answers

Therefore, the direction of their cross product A × B is vertically up, which is option 5: Vertically Up.

Given that the vector A points South and the vector B points West.

What is the direction of their cross product A × B?

We know that the cross product A × B is a vector perpendicular to both A and B. Also, the direction of the cross product is given by the right-hand rule.

Moreover, the right-hand rule is used to find the direction of the cross product.

This rule states that when the thumb, the index finger, and the middle finger of the right hand are oriented according to the first, second, and third vectors, respectively, the direction of the curled fingers represents the direction of the cross product.

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An airport screens bags for forbidden items, and an alarm is supposed to be triggered when a forbidden item is detected. Suppose 5% of bags contain forbidden items. If a bag contains a forbidden item, there is a 98% chance that it triggers the alarm. If it doesn't contain a forbidden item, there is an 8 % chance that it triggers the alarm. Given a randomly chosen bag triggers the alarm, what is the probability that it contains a forbidden item

Answers

A randomly chosen bag triggers the alarm, the probability that it contains a forbidden item can be calculated using Bayes' theorem. The probability is approximately 80.56%.

What is the probability that a bag contains a forbidden item if it triggers the alarm?

To determine the probability that a bag contains a forbidden item given that it triggers the alarm, we can use Bayes' theorem. Let's denote event A as "bag contains a forbidden item" and event B as "bag triggers the alarm." We are given that the probability of event A is 5% (0.05) and the probability of event B given A is 98% (0.98). Additionally, the probability of event B given not A (i.e., the alarm being triggered by a bag without a forbidden item) is 8% (0.08). Using these probabilities, we can apply Bayes' theorem:

\(P(A|B) = (P(B|A) * P(A)) / (P(B|A) * P(A) + P(B|not A) * P(not A))\)

Substituting the given values, we get:

\(P(A|B) = (0.98 * 0.05) / (0.98 * 0.05 + 0.08 * 0.95) = 0.8056\)

Therefore, the probability that a bag contains a forbidden item, given that it triggers the alarm, is approximately 80.56%.

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a strong lightning bolt transfers about 25 C to earth. how many electrons are transferred?

Answers

Answer:

\(n = 1.563x {10}^{20} \)

A sphere of diameter 3.0cm is mounted into a thin uniform 0.2mm calculate the length of wire in metres

Answers

Answer:

45000cm

Explanation:

volume of sphere= volume of cylanders wire

4/3^2 x 22/7^11 x 15/10^5 x 15/10 x 15/10 = 22/7^2 x 0.1/10 x 0.1/10 x h

---> 2 x 15 x 15/ 0.1 x 0.1 = h

---> h = 450 x 10 x 10

                    =

               45000cm

A 3.000 u object moving to the light through a laboratory at 0.8c collides with a 4.000 u object moving to the left through the laboratory at 0.6c. Afterward, there are two objects, one of which is a 6.000 u mass at rest.(a) What are the mass and speed of the other object?(b) Determine the change in kinetic energy in this collision.

Answers

The speed of the other object formed is 4.8 m/s.

The change in kinetic energy is 9.84 J.

Mass of the first object, m₁ = 3 u

Velocity of the first object, v₁ = 0.8 c

Mass of the second object, m₂ = 4 u

Velocity of the second object, v₂ = 0.6 c

Mass of the object at rest, m' = 6 u

a) According to the conservation of momentum,

m₁ + m₂ = m'+ m

So, m = (3 + 4) - 6

m = 7 - 6 = 1 u

m₁v₁ + m₂v₂ = (m x v) + (m' x v')

(3 x 0.8) + (4 x 0.6) + (1 x v) + (6 x 0)

Therefore, the speed of the other object formed is,

v = 2.4 + 2.4

v = 4.8 m/s

b) The change in kinetic energy is given by,

E = KE - (KE₁ + KE₂)

E = 1/2mv² - (1/2m₁v₁² + 1/2m₂v₂²)

E = 1/2(mv² - m₁v₁² - m₂v₂²)

E = 1/2[(1 x (4.8)² - 3 x (0.8)² - 4 x (0.6)²]

E = 1/2(23.04 - 1.92 - 1.44)

E = 1/2 x 19.68

E = 9.84 J

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consider the following fluids at a film temperature of 300 k in parallel flow over a flat plate with velocity of 1 m/s: atmospheric air, water, engine oil, and mercury. (a) for each fluid, determine the velocity and thermal boundary layer thicknesses at a distance of 40 mm from the leading edge.

Answers

The velocity and thermal boundary layer thicknesses at a distance of 40 mm from the leading edge for each fluid are as follows: atmospheric air (velocity: 1 m/s, thermal boundary layer thickness: X mm), water (velocity: 1 m/s, thermal boundary layer thickness: Y mm), engine oil (velocity: 1 m/s, thermal boundary layer thickness: Z mm), and mercury (velocity: 1 m/s, thermal boundary layer thickness: W mm).

What are the velocity and thermal boundary layer thicknesses of atmospheric air, water, engine oil, and mercury at 40 mm from the leading edge?

At a film temperature of 300 K, the velocity and thermal boundary layer thicknesses for each fluid at a distance of 40 mm from the leading edge can be determined.

For atmospheric air, the velocity is 1 m/s, and the thermal boundary layer thickness is represented as X mm. Similarly, for water, engine oil, and mercury, the velocity remains at 1 m/s, with thermal boundary layer thicknesses of Y mm, Z mm, and W mm, respectively.

The velocity and thermal boundary layer thickness are significant parameters in the study of fluid dynamics and heat transfer over a flat plate. The velocity represents the speed of the fluid flow, while the thermal boundary layer thickness indicates the distance from the surface where heat transfer occurs predominantly due to conduction.

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A 30 kg block is hung from the roof. How strong is the tension force?

Answers

since block is in equilibrium and there are no horizontal forces, Tension, T = Mg = 30x9.81=294.3N

if 5ev of energy is supplied to an electron with a binding energy of 2.3ev, with what kinetic energy will the electron be launched?

Answers

if 5ev of energy is supplied to an electron with a binding energy of 2.3ev, with what kinetic energy is \(\Rightarrow \mathrm{KE}=5-2.3=\mathbf{2 . 7} \mathrm{eV}\)

What is kinetic energy?

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Photoelectric effect: The photoelectric effect is a phenomenon where electrons are ejected from a metal surface when the light of sufficient frequency is incident on it. These ejected electrons are called photoelectrons.

- When a photon falls on the metal surface, the photon's energy is transferred to the electron.

- Some part of the energy gets utilized in removing the electron from the metal surface, and the remaining goes into giving kinetic energy for the ejected electron.

- Work function \((\phi)\): It is the minimum amount of energy required to cause photo-emission of electrons from a metal surface when light is incident on it.

- Einstein's Photoelectric Equation gives the relationship between work function\((\phi)\), the kinetic energy of the emitted electron, and the energy of the photon \((E)\)

\($$E=\phi+K E$$\)

Given that:

Energy of incident light, \(E=5 \mathrm{eV}\)

Work function,\($\phi=2.3 \mathrm{eV}$\)

Using Einstein's Photoelectric Equation,

\($$\begin{aligned}& \mathrm{E}=\phi+\mathrm{KE} \\& 5=2.3+\mathrm{KE} \\& \Rightarrow \mathrm{KE}=5-2.3=\mathbf{2 . 7} \mathrm{eV}\end{aligned}$$\)

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If y = a + by + c(t)^2 where y = distance , t = time , find the dimension and unit of c.

Please help!!:)​

Answers

\( \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star\)

\(\textsf{ \underline{\underline{Steps to solve the problem} }:}\)

In the given equation :

\( \qquad❖ \: \sf \:y = a + b + c( {t}^{2} )\)

If three physical quantities is to be added or subtracted, they must have same dimensions.

So, dimension of y = dimension of c(t²)

And we already know,

y = M⁰L¹T⁰ [ since it represents distance/length ]

t = M⁰L⁰T¹ [ since it represents time ]

t² = M⁰L⁰T²

( by squaring )

Now, we need to calculate dimension and unit of c :

\( \qquad❖ \: \sf \:dim(y) = dim(c {t}^{2} )\)

\( \qquad❖ \: \sf \:M⁰L¹T⁰ = dim(c) \sdot M⁰L⁰T²\)

\( \qquad❖ \: \sf dim(c) = \frac{M⁰L¹T⁰}{ M⁰L⁰T²} \)

\( \qquad❖ \: \sf dim(c) = {M⁰L¹T {}^{ - 2} }\)

Now, we got the dimension of c as :

M⁰L¹T-²

So, it's SI unit will be :

m/s²

[ since SI unit of length/distance = m, and SI unit of Time = sec, hence SI unit of T² = s² ]

Question

If y = a + by + c(t)^2 where y = distance , t = time , find the dimension and unit of c.

\(\boxed{\green{c=M^0L^1T^{-2}}}\)

Solution Given:

We know that

Law of Homogeneity of Dimensions In any correct equation representing the relation between physical quantities, the dimensions of all the terms must be the same on both sides.

Dimension of Time is denoted by [T]

Dimension of distance is denoted by [L]

Dimension of mass is denoted by [M]

So,

Dimension of a, by, c(t)^2  should be equal to y.

y=[L] .......[1]

a=[L].......[2]

by=[L].......[3]

c(t)^2=[L].....[4]

Now

The dimension of c can be obtained as:

c(t)^2=[L]

c= \( \frac{[L]}{[T^2]}\)

\(\boxed{\green{c=M^0L^1T^{-2}}}\)

Sry for late!!

Using a material that is ‘Ohmic’ (it follows Ohm’s Law), you make a circuit using wire, a battery, and a resistor. After measuring V, I, and R across the circuit, you switch out the original resistor with one 3 times more resistive. When you measure V, I, and R again, how will the new values compare to the old?

Answers

When the original resistor is replaced with 3 times more resistive material, the resistance of the circuit increases by factor of 3 and  the current flowing in the cirucit decreases by a factor 3.

Ohm's law

Ohm's law states that, the current flowing in a conductor is directly proportional to the potential across the conductor.

V = IR

where;

I is the current in the circuitV is voltageR is the resistance

When the resistance increases, the current flowing in the circuit decreases.

When the original resistor is replaced with 3 times more resistive material, the resistance of the circuit increases by factor of 3 and  the current flowing in the cirucit decreases by a factor 3.

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Which are properties of both a gas and a plasma? Check all that apply.

A. Can change shape to conform to a container
B. Has a rigid shape that does not change easily
C. Is made up of free-moving ions and electrons
D. Is compressed more easily than other states
E. Has particles that move freely from place to place
F. Will expand to completely fill a closed container

Answers

Answer:

D, E, and F

Explanation:

Like a gas, plasma lacks a fixed volume and shape. Unlike a gas, plasma can conduct electricity and respond to magnetism. That's because plasma contains charged particles called ions. The particles that make up matter are also constantly moving.

The properties of both a gas and a plasma are:

Is compressed more easily than other states.Has particles that move freely from place to place.Will expand to completely fill a closed container.

What are the properties of gas and plasma?

A gas lacks both a fixed volume and a fixed shape. While certain gases are palpable to humans and can be seen and felt, others are not. The gases oxygen, helium, and air are a few examples. N2, O2, and CO2 are among the gases that make up the Earth's atmosphere.

Both the volume and shape of plasma are illusive. Ionized gases frequently contain plasma, yet plasma differs from a gas in that it has special characteristics. The plasma is electrically conductive because it contains free electrical charges that aren't attached to atoms or ions. A gas can be heated and ionized to create plasma. Stars, lightning, fluorescent lights, and neon signs are a few examples of plasma.

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When a 45 kg cannon ball leaves a barrel it has a momentum of 14000 kg.m/s. What
is the speed of the ball at the end of the barrel?

Answers

The speed of the ball at the end of the barrel would be 311 m/s

What is the difference between a fact witness and an expert witness?

Answers

Answer:

Unlike a fact witness, an expert is entitled to compensation for participation in the case. A key distinction between a fact witness and an expert witness is that an expert witness may provide an opinion. Fact witnesses must limit their testimony to facts in regard to evidence they may have observed or been involved.

Explanation:

there

Answer:

Unlike a fact witness, an expert is entitled to compensation for participation in the case. A key distinction between a fact witness and an expert witness is that an expert witness may provide an opinion. Fact witnesses must limit their testimony to facts in regard to evidence they may have observed or been involved.

Explanation:

E2020

You run to your girlfriend's house and announce that you were running at a rate of 15 miles per hour. She knows this is not true because she knows

Answers

Answer:how long it took you to get there and the distance between your house and her house

Explanation:

There is a 5mA flowing through an 18k register. What is the voltage drop?

Answers

The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.

Given:

Current (I) = 5 mA = 5 * 10^(-3) A

Resistance (R) = 18 kΩ = 18 * 10^(3) Ω

Using Ohm's Law, we can calculate the voltage drop (V):

V = I * R

= (5 * 10^(-3) A) * (18 * 10^(3) Ω)

= 90 V

Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

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Under what condition will a glass lens placed in a transparent medium becomes invisible??

Answers

Answer:

A lens placed in a transparent liquid becomes invisible because when refractive index of the material of the lens is equal to the refractive index of the liquid in which lens is placed under this condition no bending of light takes place when it travels from liquid to the lens, so both will start behaving like both are same things.

Explanation:

hope it helps :))

What is the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air?

A. 30. 2°F

B. 35. 1°F

C. 40. 4°F

D. 45. 6°F

Answers

The answer to the given question is option C: 40.4°F. Let's see the explanation below.How to find the temperature difference across a properly operating electric furnace?

]We know that the temperature difference across a properly operating electric furnace is given by:ΔT = (Q / (1.08 * CFM))where,Q is the rate of heat input in BTU/hr,1.08 is the factor to convert CFM to lb/min,and CFM is the rate of air flow in cubic feet per minute.So, here,ΔT = (Q / (1.08 * CFM))

Given,The rate of heat input = 10 kW = 34,120 BTU/hrThe rate of air flow = 900 CFMPlugging these values in the above equation, we get:ΔT = (34,120 / (1.08 × 900))ΔT = 40.4°FTherefore, the temperature difference across a properly operating electric furnace that is using a 10-kW electric heater and is moving 900 cfm of air is 40.4°F. Hence, the main answer is option C.

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The temperature difference across the electric furnace is approximately 30.2°F (option A).

To calculate the temperature difference across the electric furnace, we can use the formula:

Temperature difference (ΔT) = Heat (Q) / (Airflow rate * Specific heat capacity * Density)

First, let's convert the power of the electric heater from kilowatts (kW) to watts (W):

10 kW = 10,000 W

Next, we need to determine the specific heat capacity of air. Typically, it is around 0.24 BTU/lb°F.

Since the given airflow rate is in cubic feet per minute (cfm), we need to convert it to pounds per minute (lb/min) using the density of air. The density of air at standard conditions is approximately 0.075 lb/ft³.

Converting 900 cfm to lb/min:

900 cfm * 0.075 lb/ft³ = 67.5 lb/min

Now we can substitute the values into the formula:

ΔT = 10,000 W / (67.5 lb/min * 0.24 BTU/lb°F * 0.075 lb/ft³)

Simplifying the equation:

ΔT = 10,000 W / (67.5 * 0.24 * 0.075) (lb/min * BTU/lb°F * lb/ft³)

Calculating the result:

ΔT ≈ 30.2°F

Therefore, the temperature difference across the electric furnace is approximately 30.2°F, which corresponds to option A.

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What is the range of the electronegativity scale?.

Answers

The most electronegative element is fluorine, which has a value of 4, while the least electronegative element is francium, which has a value of 0.07.

Additionally, if there is a significant difference in electronegativity between two atoms, the bond type tends to be more ionic; on the other hand, if the difference is minimal, the bond type is a nonpolar covalent connection.

It essentially represents the final consequence of atoms' propensities to attract electron pairs that form bonds in various elements. On several scales, we quantify electronegativity. Linus Pauling created the most widely used scale.

Based on studies of the strengths of covalent connections between various elements, Linus Pauling (1901–1994) created the initial electronegativity scale in the 1930s.

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the optical effect known as doubling can separate diamond from

Answers

The optical effect known as doubling, specifically double refraction, can help separate diamond from other gemstones.

The optical effect known as doubling, specifically double refraction, can help separate diamond from other gemstones. Double refraction is a property exhibited by certain transparent minerals, including diamond, where light passing through the material is split into two rays, each following a slightly different path.

When a gemstone such as diamond is viewed through a polarizing filter, the double refraction effect becomes apparent. By rotating the gemstone and observing how the light interacts with the filter, gemologists can distinguish diamond from other gemstones that do not exhibit double refraction.

Diamonds have a higher refractive index compared to most other gemstones, meaning they refract light more intensely. As a result, the double refraction effect in diamonds is typically more pronounced. This optical property, along with other characteristics like high dispersion (which creates the "fire" in diamonds) and hardness, is a useful diagnostic tool for gem identification.

However, it's important to note that double refraction alone is not a definitive test for determining if a gemstone is a diamond. Other gemstones, such as some varieties of zircon or garnet, can also display double refraction to a certain extent. Therefore, a combination of various gemological tests and analyses is necessary to accurately identify a gemstone, including diamond, in a comprehensive manner.

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A body having uniform velocity has zero acceleration

Answers

Acceleration means change in velocity with respect to time If the body is moving with uniform velocity then there will be no change in velocity which means acceleration will be 0.

Answer:

a = (V2 - V1) / t = 0 if V2 = V1

True

Note: an object moving in a circular path with a uniform speed does not have a uniform velocity

explain why an astronaut on moon seems to be attracted only to the moon

Answers

Answer: the gravitational attraction on the Moon is much less than it is here on Earth, and a person weighs less on the Moon.

Explanation:

On the planet Gravitus Excelsius, a projectile is fired with speed v0 at an angle θ above the horizontal flat ground. This planet is a strange one, in that the acceleration due to gravity increases linearly with time, starting with a value of zero when the projectile is fired. That is, g(t) = βt, where β is some given constant. What horizontal distance does the projectile travel? What should θ be to maximize this distance?

Answers

The angle of projection should be 45° to maximize the horizontal displacement of the projectile.

Calculation of horizontal distance the projectile will travel: Since we know the acceleration due to gravity increases linearly with time and starts from zero at t=0 when the projectile is fired, we can integrate the acceleration to obtain the velocity and the velocity to obtain the displacement in the x direction.

The horizontal velocity of the projectile is given by: vx = v0 cosθwhere θ is the angle above the horizontal flat ground. We know the horizontal velocity of the projectile is constant, therefore the displacement of the projectile in the x direction is given by:

Sx = vx t= v0 cosθ(t) [where t is the time taken to reach the ground]

Now, we know that the projectile will reach the ground when:

y = v0 sinθt - 0.5(βt^2) = 0 ⇒ t = (2v0 sinθ)/β

Using this value of time in the displacement equation:

Sx = v0 cosθ(2v0 sinθ)/β= 2v0^2 sinθ cosθ/β

Maximization of horizontal distance: The horizontal distance will be maximum when the angle of projection maximizes the horizontal displacement. That is, when d(Sx)/d(θ) = 0.

At this maximum,

d^2(Sx)/d(θ^2) < 0.

Therefore, the maximum is a point of inflection. Differentiating the equation for Sx with respect to θ, we obtain:

d(Sx)/d(θ) = 2v0^2(cos^2θ - sin^2θ)/β= (v0^2/β)cos2θ

cos2θ = 0 ⇒ θ = 45°

The angle of projection should be 45° to maximize the horizontal displacement of the projectile.

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write a nuclear equation to describe the neutron induced fission of pu to form kr and ce. determine how many neutrons are produced in the reaction.

Answers

Nuclear fission is used by all nuclear power plants, and uranium atoms are typically used in nuclear power plants.In nuclear fission, an neutron splits an atom of uranium by slamming against it; two neutrons are created in the process.

How do neutrons behave during fission?

A U-235 nucleus immediately splits in half after taking in an additional neutron.Fission is the term for this action (see diagram below).A split U-235 nucleus releases two to three neutrons each time it divides.As a result, starting a chain reaction is possible.

Why can't fission be caused by fast neutrons?

Continuous fission was achieved as more neutrons are successively emitted.Fission-generated neutrons have tremendous energy and move very swiftly.The procedure of moderation is used in most reactors to slow down these so-called rapid neutrons because they do not promote fission as effectively as slower-moving ones do.

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Why is air pressure lower on top of the airplane wing?

Answers

Answer:

Explanation:

Airplane wings are shaped to make air move faster over the top of the wing. When air moves faster, the pressure of the air decreases. So the pressure on the top of the wing is less than the pressure on the bottom of the wing.

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A capoeira é muito mais que uma luta, por isso os campeonatos internos tem o objetivo de: 1 ponto Testar a força dos participantes. Criar lutadores profissionais. Avaliar o indivíduo como um todo. Competir quem faz mais golpes.

Answers

Answer:

Avaliar o indivíduo como um todo.

Explanation:

O graduado na capoeira, é uma pessoa que recebe mais respeito pelo grupo. Sendo portanto o objetivo de cada exame interno, ou pelo menos deveria ser em sua vasta maioria avaliar o indivíduo como um todo.

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