Answers
Answer:
Speed, Vfx = 7.619 m/s
Explanation:
Vertical distance, Dx = 5.4m
Horizontal distance, Dy = 8m
Acceleration due to gravity, g = 9.8m/s²
Initial speed, Vix = 0m/s²
To find the speed, we would use the second equation of motion to find the time, t;
Dx = Vixt + ½gt²
Substituting into the equation, we have;
5.4 = 0(t) + ½(9.8)*t²
5.4 = 0 + 4.9t²
Rearranging the equation, we have;
4.9t² = 5.4
t² = 5.4/4.9
t² = 1.1020
Taking the square root of both sides;
t = 1.050 secs.
For the speed;
Dy = Vfxt
Vfx = Dy/t
Vfx = 8/1.050
Vfx = 7.619 m/s
Therefore, the speed of the pelican is 7.619 m/s
Related Questions
A storm is expected to hit 8 miles in every direction from a small town. what is the area that the storm will affect:)
Answers
We are asked to determine the area of a circle that has 8 miles of radius since we are told that the storm is expected to hit 8 miles in every direction. The area of the circle is:
\(A=\pi r^2\)Now, we plug in the value of the radius:
\(A=\pi(8mi)^2\)Solving the operations:
\(A=201.1mi^2\)Therefore, the area that will be affected is 201.1 square miles.
Question 1 An object of mass 20kg accelerates from rest to a velocity of 10m/s in 5 sec. calculate the distance covered by the object
Answers
Answer:
25 m
Explanation:
Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition
\(a= \frac{\Delta v}{\Delta t} = \frac{10-0(\frac ms)}{5 s} = 2 \frac m{s^2}\)
Now we can write the equation of motion
\(s(t)= s_0 + v_0t + \frac12at^2\)
where, the two terms \(s_0\ v_0\) represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)
\(s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m\)
g The Trans-Alaskan pipeline is 1,300 km long, reaching from Prudhoe Bay to the port of Valdez, and is subject to temperatures ranging from -71°C to +35°C. How much does the steel pipeline expand due to the difference in temperature?
Answers
Answer:
ΔL = 1.653 km
Explanation:
The linear expansion of any object due to change in temperature is given by the following formula:
ΔL = αLΔT
where,
ΔL = Change in length or expansion of steel pipe line = ?
α = coefficient of linear expansion of steel = 12 x 10⁻⁶ /°C
L = Original Length of the steel pipe = 1300 km
ΔT = Change in temperature = 35°C - (- 71°C) = 35°C + 71°C = 106°C
Therefore,
ΔL = (12 x 10⁻⁶ /°C)(1300 km)(106°C)
ΔL = 1.653 km
100 g of water at 25 °C is poured into an insulating cup. 50 g of ice at 0 °C is added to the water. The water is stirred until the temperature of the water has fallen to 0 °C. 18 g of ice remains unmelted. The specific heat capacity of water is 4.2 J / g °C. Which value does this experiment give for the specific latent heat of fusion of ice?
Answers
The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.
To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:
Q1 = m1 * c * ΔT1
Where:
m1 = mass of water = 100 g
c = specific heat capacity of water = 4.2 J/g °C
ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C
Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J
Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:
Q2 = m2 * Lf
Where:
m2 = mass of ice = 18 g
Lf = specific latent heat of fusion of ice (to be determined)
Q2 = 18 g * Lf
Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):
-10,500 J = 18 g * Lf
Solving for Lf:
Lf = -10,500 J / 18 g = -583.33 J/g
The negative sign indicates that energy is being released during the process of freezing.
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What were the quartering acts
Answers
Answer:
The quartering act of 1765 required the colonies to house British soldiers in barracks provided by the colonies.
PROBLEMS Q2/ In the cct shown in Figure, find: 1) Rt 2) Ibe Iaf
Answers
The circuit consists of a series of number of pairs of parallel and series
arranged resistors.
Correct responses:
\(R_T\) = 12 Ω\(I_{BE}\) = 0.5 A\(I_{A_F}\) = 2 AMethods used for calculations to obtain the above responsesThe total resistance can be calculated as follows;
Resistance between point C to D and from D to E are in series, therefore;
We have;
\(R_{CD}\) = 5 Ω and \(R_{DE}\) = 9 Ω are parallel
Therefore;
\(R_{TCE} = \mathbf{ \dfrac{1}{\dfrac{1}{R_{CE}} + \dfrac{1}{R_{CD} +R_{DE}} }}\)
\(R_{TCE} = \dfrac{1}{\dfrac{1}{14} + \dfrac{1}{5+9} } = 7\)
\(R_{TCE}\) = 7 Ω
\(R_{BC}\) = 11 Ω is in series with \(R_{CE}\) both of which are parallel to \(R_{BE}\) = 18 Ω
\(R_{TBE} = \mathbf{\dfrac{1}{\dfrac{1}{R_{BE}} + \dfrac{1}{R_{BC} + R_{TCE}} }}\)
Therefore;
\(R_{TBE} = \mathbf{\dfrac{1}{\dfrac{1}{18} + \dfrac{1}{11 + 7} }} = 9\)
\(R_{TBE}\) = 9 Ω
\(R_{TAE} = \mathbf{\dfrac{1}{\dfrac{1}{R_{AE}} + \dfrac{1}{R_{AB} + R_{TBE}} }}\)
Therefore;
\(R_{TAE} = \dfrac{1}{\dfrac{1}{22} + \dfrac{1}{13 + 9} } = 11\)
\(R_{TAE}\) = 11 Ω
\(R_T = \mathbf{R_{TAE} + R_{A_F}}\)
Therefore;
\(R_T\) = 11 Ω + 1 Ω = 12 ΩThe current in the circuit, I, is therefore;
\(\displaystyle I = \frac{24 \ v}{12 \ \Omega} = \mathbf{2 \ A}\)
By current divider rule, due to the equality of the parallel resistances we have;
Current through AB, \(I_{AB}\) = \(\frac{1}{2} \times 2 \ A\) = 1 A
Similarly;
Current through BE, \(\mathbf{I_{BE}}\) = \(\frac{1}{2}\) × 1 A = 0.5 ACurrent through \(\mathbf{I_{A_F}}\) = The circuit current, I = 2 A
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Using atleast 4 sentences. Please share three facts you have learned this year in Physical Education and how you will adapt what you have learned to your everyday life.
Answers
Three facts I have learned this year in Physical Education are:
a) The importance of stretching before and after exercising.
b) The benefits of cardiovascular exercise.
c) The importance of staying hydrated during exercise.
Firstly, I have learned the importance of stretching before and after exercising. Stretching helps prevent injury and improves flexibility. I will make sure to incorporate stretching into my daily routine, whether it's through a short stretching session in the morning or by taking a few minutes to stretch before and after a workout.
Secondly, I have learned the benefits of cardiovascular exercise. Cardiovascular exercise, such as running or cycling, helps improve heart health and endurance. I will try to incorporate more cardiovascular exercise into my daily routine, such as going for a run or bike ride after work.
Lastly, I have learned the importance of staying hydrated during exercise. Dehydration can lead to fatigue and muscle cramps, so it's important to drink plenty of water before, during, and after exercise. I will make sure to carry a water bottle with me throughout the day and refill it regularly to ensure that I am staying hydrated.
In summary, by incorporating stretching, cardiovascular exercise, and staying hydrated into my daily routine, I hope to improve my overall physical health and well-being.
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which instrument fan be used to measure heat
Answers
for sure thermometers and pryometers as I just learned and did some search ing. so these are. two classes of the heat measure measurement s! your welcomes!!
you can probably find out more of this and other stuff on here for more information scientificamerican
A baton twirler throws a spinning baton directly upward. As it goes up and returns to the twirler’s hand, the baton turns through four revolutions. Ignoring air resistance and assuming that the average angular speed of the baton is 1.90 rev/s, determine the height to which the center of the baton travels above the point of release.
Answers
the answer is in the photo.
earth energy budget is the relationship between how much energy the earth _______ and energy the earth _________
Answers
earth energy budget is the relationship between how much energy the earth receive from the sun and energy the earth radiates out.
What is energy?Energy is described as the quantitative property that is displaced to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
The term earth's energy budget is also described as the balance between of the amount of energy, that gets to the earth. from the Sun and the energy that leaves Earth and returns to the universe.
The earth's energy budget was mainly three types as shown:
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3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?
Answers
The car is moving at approximately 12.5 meters per second.
The kinetic energy (KE) of an object can be calculated using the formula:
KE = 1/2 * m * \(v^2\)
where
KE = kinetic energy,
m =Mass of the object, and
v = velocity.
In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .
Substituting the values , we have:
125,000 J = 1/2 * 1600 kg *\(v^2\)
Now, we can solve for v by rearranging the equation:
\(v^2\) = (2 * 125,000 J) / 1600 kg
\(v^2\) = 156.25 \(m^2/s^2\)
Taking the square root, we find:
v = √156.25\(m^2/s^2\)
v ≈ 12.5 m/s
Therefore, the car is moving at approximately 12.5 meters per second.
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Grains (pounds)
Nonfat/1% milk (gallons)
Poultry (pounds)
Seafood (pounds)
12
Vegetables (pounds)
271
1
Yogurt (pounds)
Fats and oils (pounds)
55
24
52
Soft drinks (gallons)
123
150
Sugars (pounds)
Source: U.S. Department of Agriculture, Hope Health Letter, April 1999
135
2
34
More people are:
What assumption can be made about the eating habits over the years?
6
63
15
320
4
67
O
A. becoming vegetarians
OB. eating more beef than chicken
OC. consuming whole milk dairy products
D. trying to eat healthier foods
E. eliminating soft drinks from their diets
Answers
Answer:
D. trying to eat healthier foods
Explanation:
Two Blocks are connected by a massless rope. The mass of the first block is 20kg while the mass of the second block is 14kg. There is an applied force of 100N pulling on the the first block. The applied force is at an angle of 30 degrees with respect to the horizontal. The coefficient of sliding friction for block 1 is .17 and the coefficient of block 2 is .22. Calculate the following
a) Acceleration of the system(blocks).
b) The tension in the massless rope.
Answers
The system acceleration at 1.616 m/s2.
How can you determine a system's acceleration?Acceleration (a) is defined as the product of the change in velocity (v) and the change in time (t) in the equation a = v/t. (t).
By dividing the applied force into its horizontal and vertical components, we may achieve this:
F_horizontal = F_applied * cos(30°) = 100 N * cos(30°) = 86.6 N
F_vertical = F_applied * sin(30°) = 100 N * sin(30°) = 50 N
The weight of each block is given by:
W1 = m1 * g
= 20 kg * 9.81 m/s²
= 196.2 N
W2 = m2 * g
= 14 kg * 9.81 m/s²
= 137.34 N
The frictional force acting on block 1 is given by:
f_friction1 = μ1 * N1
= μ1 * (W1 - F_vertical)
= 0.17 * (196.2 - 50)
= 27.574 N
Similarly, the frictional force acting on block 2 is given by:
f_friction2 = μ2 * N2
= μ2 * (W2)
= 0.22 * (137.34)
= 30.2148 N
The net force acting on the system in the horizontal direction is given by:
F_net = F_horizontal - f_friction1 = 86.6 N - 27.574 N = 59.026 N
Now we can calculate the acceleration of the system using Newton's Second Law:
a = F_net / (m1 + m2)
= 59.026 N / (20 kg + 14 kg)
= 1.616 m/s².
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Write 3 – 4 sentences evaluating the use of nuclear fission to generate electric energy. Provide at least one point in favor of and two points against using fission.
Answers
Answer:
One point in favor of using nuclear fission to generate electric energy is that it is a relatively low-carbon option, producing fewer greenhouse gas emissions than fossil fuels. However, there are several points against using fission as an energy source. One is that it produces radioactive waste that can be difficult and costly to dispose of safely. Another is that there is the risk of accidents or leaks, which can have serious consequences for both people and the environment. Additionally, the construction of nuclear power plants is expensive and time-consuming, and the plants themselves have a limited lifespan.
At an airport, two business partners both walk at 1.5 m/sm/s from the gate to the main terminal, one on a moving sidewalk and the other on the floor next to it. The partner on the moving sidewalk gets to the end in 60 ss, and the partner on the floor reaches the end of the sidewalk in 90s.
Required:
What is the speed of the sidewalk in the Earth reference frame?
Answers
Answer:
\(v=0.8m/s\)
Explanation:
From the question we are told that
Distance \(d=1.5m/sm/s\)
Time \(t_1=60s\)
Time \(t_2=90s\)
Generally the the equation for the distance traveled is mathematically given as
\(d=vt\)
\(d=1.5*90\)
\(d=138m\)
Generally equation for speed of side walk is mathematically given as
\(d=(v+u)t\)
\(v=\frac{d}{t}-u\)
\(v=\frac{138}{60}-1.5\)
\(v=0.8m/s\)
How does the energy stored in an isolated capacitor change if the potential difference is increased by a factor of six
Answers
Answer:
Energy will be reduced by 0.3
Explanation:
Given that E = 1/2 QV
So if V is increased by 6
=> V = E/ 3Q
So the energy will be divided by a factor 1/3 of be reduced by 0.3
Suppose your bicycle tire is fully inflated, with an absolute pressure 4.00 x 10^5 Pa at a temperature of 15.0 °C. What is the pressure after its temperature has risen to 40.0 °C? Assume that there are no appreciable leaks or changes in volume.
Answers
The pressure after the temperature has risen to 40.0 °C, assuming that there are no appreciable leaks or changes in volume is 4.35×10⁵ Pa
How do I determine the pressure at 40.0 °C?From the question given above, the following data were obtained:
Initial pressure (P₁) = 4.00×10⁵ Pa Initial temperature (T₁) = 15 °C = 15 + 273 = 288 K New temperature (T₂) = 40 °C = 40 + 273 = 313 KVolume = ConstantNew pressure (P₂) = ?The pressure the temperature has risen to 40 °C can be obtained as follow:
P₁V₁ / T₁ = P₂V₂ / T₂
Volume = contant
P₁ / T₁ = P₂ / T₂
4.00×10⁵ / 288 = P₂ / 313
Cross multiply
P₂ × 288 = 4.00×10⁵ × 313
Divide both sides by 288
P₂ = (4.00×10⁵ × 313) / 288
P₂ = 4.35×10⁵ Pa
Thus, the pressure at 40 °C is 4.35×10⁵ Pa
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Numerical Problems
A bus covers a distance of 600 metres in 30 seconds. Calculate the speed of
the bus.
Answers
Answer:
20 m/s.
Explanation:
From the question given above, the following data were obtained:
Distance travelled = 600 m
Time taken = 30 s
Speed =?
Speed can be defined as the distance travelled per unit time. Mathematically, it is expressed as:
Speed = Distance /time
With the above formula, we can easily calculate the speed of the bus as follow:
Distance travelled = 600 m
Time taken = 30 s
Speed =?
Speed = Distance /time
Speed = 600 / 30
Speed = 20 m/s
Therefore, the speed of the bus is 20 m/s.
An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target?
Answers
The speed of the artillery shell when it hits its target is 100 m/s.
Given:
Initial vertical displacement (y) = 200 m
Vertical displacement at 100 m in the air (y') = 100 m
Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)
Using the equation for vertical displacement in projectile motion:
y' = vy^2 / (2g),
where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).
100 m = vy^2 / (2 * 9.8 m/s^2),
vy^2 = 100 m * 2 * 9.8 m/s^2,
vy^2 = 1960 m^2/s^2,
vy = sqrt(1960) m/s,
vy ≈ 44.27 m/s.
Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.
Hence, the speed of the artillery shell when it hits its target is 100 m/s.
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Somebody, please help me with these by April 6 I'm about to fail my class
1. Describe specific heat capacity and its use in calorimetry.
2. Define latent heat and how it is different than specific heat capacity.
3. Describe how a phase diagram changes when changing from a solid to a liquid.
4. Describe how work is done is related to a change in the volume of a fluid.
—Continue on the next page—
5. What is the relationship of change in internal energy, work, and heat? Explain the significance in terms of energy.
6. As succinctly as possible, explain why it is impossible to have an engine that is 100% efficient.
7. Describe the application of Archimedes principle in everyday terms.
Practice
8. 50 grams of a substance increases its temperature by 10 degrees when 100 J of heat is added. What is the specific heat capacity of the substance?
9. Ten kilograms of a substance has a latent heat of 1000 J/kg. How much energy does it take to change the phase of this substance?
—Continue on the next page—
10. The work done by a piston is measured to be 1000 J. If the pressure is a constant 1000 Pa, what is the change in volume of the piston?
11. Is the process described in #10 isovolumetric? Explain.
12. Is it possible for a substance to change the temperature in an isovolumetric and adiabatic process? Explain.
13. A substance is heated with 1000 J and does 700 J of work on the atmosphere. What is the change in the internal energy of the substance?
14. An engine causes a car to move 10 meters with a force of 100 N. The engine produces 10,000 J of energy. What is the efficiency of this engine?
—Continue on the next page—
15. If a ball of radius 0.1 m is suspended in water, density = 997 kg/m^3, what is the volume of water displaced and the buoyant force?
16. A 10 kg ball of volume = 0.005 m3 is set on a lake. Describe what will happen to the ball.
Application
A group of physics students heats a vial of water, which has a balloon at the top that traps the water vapor and air.
17. Describe how much the internal energy is changed if the students are adding heat to the water via a Bunsen burner. No need to calculate anything.
18. If 50 grams of water start to boil, then how much heat must be added to completely boil off the water? The latent heat of vaporization is 2,260,000 J/kg
—Continue on the next page—
19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
20. Assuming the atmospheric pressure to be constant at 101,325 Pa, by what amount does the volume of the balloon change?
Answers
Answer:
im sorry i would help but thats too much
Sources of error could have come from friction that may result in energy losses during the collision, The gliders may not be perfectly elastic, which means that some energy may be lost during the collision
are these errors random or systematic errors?
Sources of error could have come from small amounts of friction, and glider 2 could have not been totally at rest. These errors are systematic errors.
Are these errors random or systematic?
Answers
Answer:
The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.
The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.
Explanation:
Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
Answers
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
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find the solid angle made by the part of surface area 2 cm square of square and radius 4 centimetre
Answers
4. A gas's solubility is best in a liquid solvent when the solution is under high or low pressure
Answers
Answer:
low pressure
Explanation:
Please help me
Explain why driver age 16-18 are most likely to be involved in traffic accidents
Answers
Answer:Lack of experience.
Explanation:
Research from the CDC points to a few key reasons teen drivers are likely to be involved in car accidents: Lack of experience. Teen drivers have triple the fatal crash risk of older drivers, in part because they do not have the skills to recognize and avoid road hazards.
The vertical position of the 100-kg block is adjusted by the screw activated wedge. Calculate the moment which must be applied to the handle of the screw to raise the block. The single thread screw has square threads with a mean diameter of 30 mm and advances 10 mm each complete turn. The coefficient of friction for the screw threads is 0.24, and the coefficient of friction for all the mating surfaces of the block and the wedge is 0.40. Neglect friction at the ball joint A
Answers
We have that for the Question "" it can be said that Calculate the moment which must be applied to the handle of the screw to raise the block is
M = 7.30 N.mFrom the question we are told
The vertical position of the 100-kg block is adjusted by the screw activated wedge. Calculate the moment which must be applied to the handle of the screw to raise the block. The single thread screw has square threads with a mean diameter of 30 mm and advances 10 mm each complete turn. The coefficient of friction for the screw threads is 0.24, and the coefficient of friction for all the mating surfaces of the block and the wedge is 0.40. Neglect friction at the ball joint A
Generally the equation for the Block is mathematically given as
\(\sum Fy=0\)
\(981cos21.80 = R_2cos53.6\\\\R_2=1535N\)
the equation for the Wedge is mathematically given as
\(\sum Fx=0\\\\1535cos36.4=Pcos21.8\\\\P=1331N\)
the equation for the Screw is mathematically given as
\(\beta = tan^{-1}*\frac{L}{2*\pi*r} \\\\\beta = tan^{-1}*\frac{10}{2*\pi*(15)} \\\\\\beta = 6.06\\\\\theta = tan^{-1}*0.25 \\\\\theta = 14.04\\\\\\Therefore\\\\\theta + \beta = 20.1\\\\\)
Therefore
\(M = Pr tan (\theta + \beta)\\\\M = 1331(0.015) tan20.09\\\\M = 7.30 N.m\)
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A certain satellite travels in an approximately circular orbit of radius 8.8 × 10^6 m with a period of 6 h 12 min. Calculate the mass of its planet from this information.
Answers
The mass of the planet is 5.98 × 10^24 kg.
To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.
First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.
Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.
Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.
Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2
Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2
Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.
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The smallest shift you can reliably measure on the screen is about 0.2 grid units. This shift corresponds to the precision of positions measured with the best Earth-based optical telescopes. If you cannot measure an angle smaller than this, what is the maximum distance at which a star can be located and still have a measurable parallax
Answers
Answer:
The distance is \(d = 1.5 *10^{15} \ km\)
Explanation:
From the question we are told that
The smallest shift is \(d = 0.2 \ grid \ units\)
Generally a grid unit is \(\frac{1}{10}\) of an arcsec
This implies that 0.2 grid unit is \(k = \frac{0.2}{10} = 0.02 \ arc sec\)
The maximum distance at which a star can be located and still have a measurable parallax is mathematically represented as
\(d = \frac{1}{k}\)
substituting values
\(d = \frac{1}{0.02}\)
\(d = 50 \ parsec\)
Note \(1 \ parsec \ \to 3.26 \ light \ year \ \to 3.086*10^{13} \ km\)
So \(d = 50 * 3.08 *10^{13}\)
\(d = 1.5 *10^{15} \ km\)
Part B
Enter into the table your calculated value for the spring constant, then play with different values of mk
until you get a close match to the motion. (Note: It will never be perfect. Remember that there are two
kinds of spring damping. Both are at work here, but we are not going to model both.) Once you're
satisfied with your model, record your model values in the table below.
Answers
The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.
What is Spring constant?The stiffer the spring is and the harder it is to stretch, the larger the spring constant.
Springs are pliable mechanical devices that regain their previous shape after deforming, i.e. after being stretched or compressed. They are an essential part of many different mechanical devices.
The well-known metal coil has evolved into an essential element in the modern world, appearing in everything from engines to appliances to tools to automobiles to medical equipment and even basic ball-point pens. The spring's ability to store mechanical energy accounts for its widespread use and applications.
Therefore, The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.
To learn more about Spring constant, refer to the link:
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