X = 6{2 + 3[2(7 − 3) + (4 + 1) − 3]}

When rotated 90 degrees, counterclockwise direction the new coordinates will result in the attached image.

The old coordinate where were rotated are:

A(-5,8)

B (-1, 7)

C(-3, 5)

D(-4, 2)

To rotate a point counterclockwise about the origin, we switch the x and y coordinates and change the sign of the new x  -coordinate.

The new coordinates are after 90 degrees, counterclockwise  are

A' = (-8, -5)

B' = (-7, -1)

C' = (-5, -3)

D' = (-2, -4)

See attached image.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

See attached image.

Answer:

A.

Step-by-step explanation:

The vertical line test is a way of finding out if a relation is a function.

Graph the relation.

Then imagine a vertical line moving from left to right over the graph of the relation.

If the vertical line intersects at most one point of the graph in any position you place the vertical line, then the relation is a function.

This function passes the vertical test since it never intersects more than one point on the vertical line at a time.

Answer: A.

The solution of the triangle have been shown below.

To solve a triangle means to find the values of all its angles and sides. The method for solving a triangle depends on the given information.

Given that;

a/Sin A = b/SinB

Sin B = bSin A/a

B = Sin-1(bSin A/a)

B = Sin-1 (23Sin 40/17)

B = 60.4 degrees

Then we have that

C = 180 - (40 + 60.4)

= 79.4 degrees

Then;

a/sinA = c/Sin C

c= aSin C/Sin A

c = 17 * Sin 79.4/Sin 40

c =   16.71/0.643

c = 25.9

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Answer:

\(\$1125\)

Step-by-step explanation:

The equations of the system are

\(2x+4y\leq 12\)

\(y\geq 0\)

\(0<x\leq 3\)

From the graph it can be seen that points \((3,1.5)\) and \((3,0)\) falls in the bounded region.

The income will be

\(125x+500y=125\times 3+500\times 1.5\\ =\$1125\)

\(125\times 3+500\times 0=\$375\)

So, the person can do 3 small jobs and build 1 and a half cabinets per day.

The maximum income will be \(\$1125\).

Answer:

a number ending in 0 or 5 has a factor of 5

Step-by-step explanation:

5 is a factor of

5, 10, 15, 20, 25...

any number that ends in 0 or 5 would qualify

Answer:

Open circle at -1 and shading to the left

Step-by-step explanation:

Given the question :

Which number line shows the solution to the inequality −2(3x − 1) < 8? Group of answer choices Open circle at 2 and shading to the right Open circle at 2 and shading to the left Open circle at -1 and shading to the right Open circle at -1 and shading to the left.

−2(3x − 1) < 8

Open the bracket and simplify :

-2(3x - 1) < 8

-6x + 2 < 8

-6x < 8 - 2

-6x < 6

Divide both sides by - 6

-6x/-6 < 6/-6

x > - 1

Or - 1 < x

Since - 1 is less than x, from - 1 we draw to the left

The solutions to the system of equations are x = 2 and 4

From the question, we have the following parameters that can be used in our computation:

f(x) = x - 3

g(x) = 1/(x - 3)

The solution to the system of equations implies that

f(x) = g(x)

So, we have

x - 3 = 1/(x - 3)

Cross multiply the equation

This gives

(x - 3)² = 1

So, we have

x - 3 = ±1

Add 3 to both sides

x = 3 ± 1

So, we have

x = 2 and 4

Hence, the solutions to the system of equations are x = 2 and 4

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The biker needs to travel 45 km more to complete his journey.

Given that, a biker traveled 2/5 of the road on the first day, then traveled 5 kilometers less on the next day, which is equal to 3/8 of the road, we need to find how much he need to cover more,

Let the total distance of the road be x,
So,

2x/5 - 5 = 3x/8

2x/5 - 3x/8 = 5

Solving for x,

Multiply by 40 to both sides,

16x-15x = 200

x = 200

Therefore, the total distance of the road is 200 km.

Since, he travelled =

200 (2/5) = 80 km + 200 (3/8) = 75 km = 155 km

Therefore, he needs to travel 200-155 = 45 km more.

Hence, the biker needs to travel 45 km more to complete his journey.

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The simplified form of the expression (2 1/6 ) × (1 1/3) is 26/9.

Given the expression in the question;

(2 1/6 ) × (1 1/3)

To simplify, first convert from mixed to improper fraction.

(2 1/6 ) × (1 1/3)

( (2×6 + 1)/6 ) × (1 1/3)

( (12 + 1)/6 ) × (1 1/3)

( 13/6 ) × (1 1/3)

( 13/6 ) × (1×3 + 1/3)

( 13/6 ) × (3 + 1/3)

( 13/6 ) × (4/3)

Now, cancel the common factor 2.

13/6 × 4/3

13/3 × 2/3

( 13 × 2 ) / ( 3 × 3 )

( 26 ) / ( 9 )

26/9

Therefore, the simplified form is 26/9.

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Rate of change is:

Choose any two point and hours represent x and miles represent y so :

So rate of change is:

The rate of change is 15.

The area of the shaded region is 294.5 m².

The area of the entire circle is calculated as follows;

A = πr²

where;

A = π ( 11.1² )

A = 387.1 m²

The area of the sector is calculated as follows;

A = ( θ/360 ) πr²

A = ( 130/360 ) x π ( 11.1² )

A = 139.8 m²

The area of the triangle is calculated as follows;

A = ¹/₂ ( sinθ )r²

A = ¹/₂ ( sin 130 ) (11.1²)

A = 47.2 m²

Area of the unshaded region is calculated as;

A' = 139.8 m²  -  47.2 m²

A' = 92.6 m²

The area of the shaded region is calculated as follow;

A'' = 387.1 m² - 92.6 m²

A'' = 294.5 m²

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Answer:

m = 8

Step-by-step explanation:

m + 4 = 12

Group like terms

m = 12 - 4

m = 8

The equivalent value of the expression is m = 8

Given data ,

Let the expression be represented as A

Now , the value of A is

m + 4 = 12

From the law of subtraction of two numbers , we get

So , the value of m plus 4 is equal to 12

Subtracting 4 on both sides of the equation , we get

m = 12 - 4

On simplifying the equation , we get

m = 8

So , the value of the variable m is 8

Therefore , m = 8

Hence , the expression is m = 8

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Lets find f(n) formula

\(\boxed{\sf f(n)=\dfrac{1680}{n}}\)

Now

\(\\ \sf\longmapsto f(10)=\dfrac{1680}{10}=168\)

\(\\ \sf\longmapsto f(12)=\dfrac{1680}{12}=140\)

\(\\ \sf\longmapsto f(16)=\dfrac{1680}{16}=105\)

\(\\ \sf\longmapsto f(14)=\dfrac{1680}{14}=120\)

Answer:

b = 8.89, c = 11.96 and m∠B = 48°

Step-by-step explanation:

From the given triangle ABC,

We will apply sine ratio for angle A,

sin(A) = \(\frac{\text{Opposite side}}{\text{Hypotenuse}}\)

sin(42)° = \(\frac{BC}{AB}\)

sin(42)° = \(\frac{8}{AB}\)

AB = \(\frac{8}{\text{sin}(42)}\)

AB = 11.96

c = 11.96

By triangle sum theorem,

m∠A + m∠B + m∠C = 180°

42° + m∠B + 90° = 180°

m∠B = 180 - 132

m∠B = 48°

By cosine ratio of angle A,

cos(A) = \(\frac{\text{Adjacent side}}{\text{Hypotenuse}}\)

cos(42)° = \(\frac{AC}{AB}\)

AC = AB.cos(42)°

AC = (11.96)cos(42)°

AC = 8.89

b = 8.89

The correct answers are 1st and 4th i.e translate 2 units down and reflect the triangle.

We can easily deduce that the triangle A'B'C' is 2 units higher than the triangle ABC so if we want to map the both the triangles we have to make the triangle A'B'C' lower in the graph.

So, both the 1st and 4th points translate and reflect down the triangle A'B'C'  which will be mapped according to the triangle ABC.

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Answer:

-36

Step-by-step explanation:

How are you in college lol

Answer:

Multiply  

4  by  − 9 .

− 36

Step-by-step explanation:

Step-by-step explanation:

I hope this answer is helpful ):

The percent change in Pilar's shell collection from the beginning of the day to the end is,  22.5%

Percentage is a way to express a number as a fraction of 100. It is often used to represent ratios and proportions in a more convenient and understandable form, especially in financial and statistical contexts. For example, 50% means 50 per 100, or half of a given quantity. It is denoted using the symbol "%".

Given that,

Pilar has 40 shells in her collection.

She collects 6 more shells in the morning and 3 more shells in the afternoon.

The percent change in Pilar's shell collection from the beginning of the day to the end = ?

At the beginning of the day, Pilar has 40 shells.

In the morning, she collects 6 more shells, bringing her total to

= 40 + 6

= 46 shells.

Then, in the afternoon, she collects 3 more shells, bringing her total to

=46 + 3

= 49 shells.

To find the percent change in Pilar's shell collection from the beginning of the day to the end, we can use the formula:

percent change = (final value - initial value) / initial value * 100%

Plugging in the values we have:

percent change = (49 - 40) / 40 x 100%

percent change = 9 / 40 x 100%

percent change = 22.5%

Therefore, there is a 22.5% increase in Pilar's shell collection from the beginning of the day to the end.

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Answer:

x = 6/5

Step-by-step explanation:

-5(x-2)+9=13

To find x, subtract 9 from each side

-5(x-2)+9-9=13-9

-5(x-2)=4

Distribute -5

-5x +10 = 4

Subtract 10 from each side

-5x+10-10 = 4-10

-5x = -6

Divide each side by -5

-5x/-5 = -6/-5

x = 6/5

Answer:

\(x = \pink{1.2}\)

Step-by-step explanation:

\( - 5(x - 2) + 9 = 13\)

First, solve the brackets.

\( - 5x + 10 + 9 = 13\)

Combine like terms.

\( - 5x + 19 = 13\)

Take 19 to the right side.

\( - 5x = 13 - 19 \\ - 5x = - 6\)

Divide both sides by 5.

\( \frac{ - 5x}{ - 5} = \frac{ - 6}{ - 5} \\ x = \frac{6}{5 } \\ x = 1.2\)

1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)

2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)

3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)

4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)

5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)

6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)

7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)

8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)

9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)

10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)

11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)

12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)

13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)

14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)

Here are the journal entries for the given transactions:

1. Bricks and timber purchased for construction:

Debit: Bricks (Asset) - Rs 60,000

Debit: Timber (Asset) - Rs 35,000

Credit: Bank (Liability) - Rs 95,000

2. Transfer to fixed deposit account:

Debit: Fixed Deposit (Asset) - Rs 13,000

Credit: Current Account (Asset) - Rs 13,000

3. Appointment of Mr. S.N. Rao as Accountant:

Debit: Salary Expense (Expense) - Rs 300

Debit: Security Deposit (Asset) - Rs 1,000

Credit: Accountant (Liability) - Rs 300

4. Goods sold to Shruti:

Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000

Credit: Sales (Income) - Rs 80,000

5. Goods purchased from Richa:

Debit: Purchases (Expense) - Rs 60,000

Credit: Accounts Payable - Richa (Liability) - Rs 60,000

6. Goods sold to Shilpa:

Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000

Credit: Sales (Income) - Rs 50,000

7. Goods sold to Garima:

Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000

Credit: Sales (Income) - Rs 1,00,000

8.Purchase of land:

Debit: Land (Asset) - Rs 2,00,000

Debit: Brokerage Expense (Expense) - Rs 2,000

Debit: Registration Charges (Expense) - Rs 15,000

Credit: Bank (Liability) - Rs 2,17,000

9. Goods and cash taken away by proprietor:

Debit: Proprietor's Drawings (Equity) - Rs 65,000

Credit: Goods (Asset) - Rs 25,000

Credit: Cash (Asset) - Rs 40,000

10. Goods sold to Charu:

Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000

Credit: Sales (Income) - Rs 1,20,000

Credit: Cost of Goods Sold (Expense) - Rs 80,000

Credit: Profit on Sales (Income) - Rs 40,000

11. Rent paid for the building:

Debit: Rent Expense (Expense) - Rs 60,000

Credit: Bank (Liability) - Rs 60,000

12. Goods sold to Sunil:

Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000

Credit: Sales (Income) - Rs 24,000

Credit: Cost of Goods Sold (Expense) - Rs 20,000

Credit: Profit on Sales (Income) - Rs 4,000

13. Goods purchased from Nanda and supplied to Helen:

Debit: Purchases (Expense) - Rs 1,000

Debit: Accounts Payable - Nanda (Liability) - Rs 1,000

Credit: Accounts Receivable - Helen (Asset) - Rs 1,300

Credit: Sales (Income) - Rs 1,300

14. Goods received from Rohit and Sons and supplied to Madan:

Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)

Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700

Debit: Accounts Receivable - Madan (Asset) - Rs 3,000

Credit: Sales (Income) - Rs 3,000

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Answer: 3.5

Step-by-step explanation:

Answer:

C x = 28°

Step-by-step explanation:

(x +30)° + (3x +10)° + x° = 180°

x +30 + 3x + 10 + x = 180

5x + 40 = 180

5x = 140

x = 28°

Answer:

p = 8

Step-by-step explanation:

Divide -5 to both sides

-5p = -40

5p = 40

p = 8

So p = 8

Answer:

9+18x

Step-by-step explanation:

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The constant differences between the consecutive terms are 2 (a); 2 (b), -3 (c), 7 (d), 1(e), and 6(f).

In math, the constant difference can be defined as the number that defines the pattern of a sequence of numbers. This means that number that should be added or subtracted to continue with the sequence.

Due to this, to determine the constant difference it is important to observe the pattern and find out the number that should be added. For example, if the sequence is 2, 4, 6, 8, there is a difference of 2 between each of the numbers and this is the constant difference.

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Answer:

The circumference of a circle is calculated using the formula: C = πd, where C represents the circumference and d represents the diameter of the circle.

In this case, the diameter of the circle is given as 24 inches.

Using the formula, we can substitute the values:

C = πd

C = 3.14 * 24

C ≈ 75.36 inches

Therefore, the circumference of a circle with a diameter of 24 inches (and using π = 3.14) is approximately 75.36 inches.

Step-by-step explanation:

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Temperature (∘C) 29.55 29.96 30.04 30.28 30.34 30.47 30.81

Growth (mm/y) 2.64 2.37 2.74 2.52 2.34 2.46 2.31

Using calculator and treating temperature and growth data as samples :

Temperature :

Mean : ΣX/n

n = sample size

Mean temperature (m) = 211.45 / 7

Mean temperature = 30.21°C

Standard deviation (s) :

Sqrt(Σ(X - m)²/n - 1)

s = 0.403

Growth:

Mean : ΣX/n

n = sample size

Mean growth (m) = 17.38 / 7

Mean growth = 2.483 mm/yr

Standard deviation (s) :

Sqrt(Σ(X - m)²/n - 1)

s = 0.161

Using the correlation Coefficient a calculator : the correlation Coefficient is - 0.6278, This shows that a negative relationship exists between both variables.

The intercept of the graph = 17.812

The slope of the relationship : -0.504