A new interstate highway is being built with a design speed of 70 mph. For one of the horizontal curves, the radius measured to the innermost travel lanes is 900 ft. Determine the rate of superelevation required for the curve.

The force of gravity feeds raw material into a cavity during injection molding from the hopper. Typically, the material is put into the hopper in the form of pellets or granules.

In injection molding, gravity is used to feed the raw material (often in the form of tiny pellets or granules) into the mold cavity. Typically, the hopper is positioned above the mold cavity, and gravity causes the material to fall into the cavity. The material is heated and chilled to make a solid plastic item after it has completely filled the void. utilized while injection molding to feed raw material into a mold cavity. Centrifugal force, air pressure, and hydro pressure are the other possible answers but are not frequently utilized in injection molding. Centrifugal force, which pushes items away from a central point, has no bearing on the process of injection molding. Although they can be used in some production processes, air pressure and hydro pressure are not usually.

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Aibohphobia is the irrational fear of palindromes, which are words or phrases that read the same forwards and backwards. To calculate the number of words of length n over an alphabet with k letters that are not palindromes, we can use the formula: Number of non-palindromes = kn - kceil(n/2)

This formula calculates the total number of words of length n over an alphabet with k letters (kn) and subtracts the number of palindromes of length n (kceil(n/2)). The result is the number of words that are not palindromes.

So, for Bob, if he wants to know the number of words of length n over an alphabet with k letters that are not palindromes, he can use this formula to calculate it.

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Answer:

The efficiency of a DC generator is maximum when those losses proportional to the square of the load current are equal to the constant losses of the DC generator. This relation applies equally well to all rotating machines, regardless of the type of machine.

Explanation:

If the power in the primary circuit of a 4:1 transformer is 12 watts, the power in the secondary circuit will also be 12 watts. The correct option is c.

Explanation:

A transformer is a device that is used to transfer electrical energy from one circuit to another through electromagnetic induction. It consists of a primary and a secondary coil. The primary coil is connected to the input voltage source, while the secondary coil is connected to the output load.

The power in a transformer is given by the equation:

P = V × I

Where P is the power, V is the voltage, and I is the current.

In a transformer, the power in the primary circuit is equal to the power in the secondary circuit. This means that:

Pprimary = Psecondary

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If the power in the primary circuit of a 4:1 transformer is 12 watts, the power in the secondary circuit will also be 12 watts. The correct option is c.

A transformer is a device that is used to transfer electrical energy from one circuit to another through electromagnetic induction. It consists of a primary and a secondary coil. The primary coil is connected to the input voltage source, while the secondary coil is connected to the output load.

The power in a transformer is given by the equation:

P = V × I

Where P is the power, V is the voltage, and I is the current.

In a transformer, the power in the primary circuit is equal to the power in the secondary circuit. This means that:

Pprimary = Psecondary

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Answer:

In my opinion, Energy, Time, Money and Development

Answer:

Pollution, time, money, and energy.

Explanation:

Answer:

Most technicians install rebuilt or new power steering pumps rather than overhauling the defective unit in the shop.

True

Explanation:

It has been established that most technicians, instead of overhauling the defective power steering pumps, prefer to install rebuilt or revamped pumps or even new pumps when they could have overhauled the unit themselves.  Some are afraid that leakage could occur again.  They are not confident enough to do the overhauling in-house or some claim that they do not have the time and other tools to carry out the overhauling.  Acknowledgedly, overhauling a power steering pump is not a job for the novice.  They require experienced and skilled hands to do the hard work.

The thing that happens when a capacitor is connected to a DC source is that Capacitors charge up until the voltage across the capacitor is equal to the externally applied voltage when they are linked across a direct current DC supply voltage.

Capacitors slowly charge in a DC circuit until the charging voltage of the capacitor is equal to the supply voltage. The capacitor will not permit any extra charges to travel through it after it has been fully charged.

Note that the link between a capacitor and voltage and current can be summarized as follows: the capacitance and the rate of rise or fall of the voltage determine how much current flows through a capacitor. A strong positive current will be produced through a capacitor if the voltage across the capacitor rises quickly.

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There may be a thrust bearing on either side of the engine.

In a crankshaft, rod bearings are the bearings that allow the connection rod to rotate on the crankshaft. Tech A and Tech B both provided information regarding the same topic. Tech A says that rod bearings are held in place by the torque of the rod bolts crushing the bearing into the big end of the rod bore. Tech B says that one of the connecting rod bearings acts as a thrust bearing for the engine. Let's discuss each one in brief:Tech A is correct: The correct answer is Tech A, as Rod bearings are held in place by the torque of the rod bolts crushing the bearing into the big end of the rod bore. The big end of the connecting rod has a machined half-moon-shaped hole in it, which is where the bearing shells are mounted. As torque is applied to the rod bolts, the conrod is pulled tight against the crankshaft, crushing the bearing shells between the rod and the crankshaft.Tech B is not completely accurate: Though it is true that some connecting rod bearings serve as thrust bearings, it is not entirely accurate. The thrust bearing is generally located between the front of the engine block and the rear of the crankshaft, and its purpose is to resist forward and backward crankshaft movement due to combustion pressures.

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The system is operated at a feed rate of 15 × 10^(-3) m^3/h with an initial glucose concentration of 10 kg/m^3.

The steady-state mass balance for the reactor can be written as:

F = QX + Qs

where F is the feed rate, QX is the volumetric flow rate of cells, and Qs is the volumetric flow rate of glucose.

At steady-state, QX and Qs are constant. Therefore, we can write:

QX = F - Qs

In this case, the system is operated at a feed rate of 15 × 10^(-3) m^3/h with an initial glucose concentration of 10 kg/m^3.

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Answer:

Explanation:

The image attached to the question is shown in the first diagram below.

From the diagram given ; we can deduce a free body diagram which will aid us in solving the question.

IF we take a look at the second diagram attached below ; we will have a clear understanding of what the free body diagram of the system looks like :

From the diagram; we can determine the length of BC by using pyhtagoras theorem;

SO;

\(L_{BC}^2 = L_{AB}^2 + L_{AC}^2\)

\(L_{BC}^2 = (3.5+2.5)^2+ 4^2\)

\(L_{BC}= \sqrt{(6)^2+ 4^2}\)

\(L_{BC}= \sqrt{36+ 16}\)

\(L_{BC}= \sqrt{52}\)

\(L_{BC}= 7.2111 \ m\)

The cross -sectional of the cable is calculated by the formula :

\(A = \dfrac{\pi}{4}d^2\)

where d = 4mm

\(A = \dfrac{\pi}{4}(4 \ mm * \dfrac{1 \ m}{1000 \ mm})^2\)

A = 1.26 × 10⁻⁵ m²

However, looking at the maximum deflection  in length \(\delta\) ; we can calculate for the force \(F_{BC\) by using the formula:

\(\delta = \dfrac{F_{BC}L_{BC}}{AE}\)

\(F_{BC} = \dfrac{ AE \ \delta}{L_{BC}}\)

where ;

E = modulus elasticity

\(L_{BC}\) = length of the cable

Replacing 1.26 × 10⁻⁵ m² for A; 200 × 10⁹ Pa for E ; 7.2111 m for \(L_{BC}\) and 0.006 m for \(\delta\) ; we have:

\(F_{BC} = \dfrac{1.26*10^{-5}*200*10^9*0.006}{7.2111}\)

\(F_{BC} = 2096.76 \ N \\ \\ F_{BC} = 2.09676 \ kN\)     ---- (1)

Similarly; we can determine the force \(F_{BC}\) using the allowable  maximum stress; we have the following relation,

\(\sigma = \dfrac{F_{BC}}{A}\)

\({F_{BC}}= {A}*\sigma\)

where;

\(\sigma =\) maximum allowable stress

Replacing 190 × 10⁶ Pa for \(\sigma\) ; we have :

\({F_{BC}}= 1.26*10^{-5} * 190*10^{6} \\ \\ {F_{BC}}=2394 \ N \\ \\ {F_{BC}}= 2.394 \ kN\)     ------ (2)

Comparing (1) and  (2)

The magnitude of the force \(F_{BC} = 2.09676 \ kN\) since the elongation of the cable should not exceed 6mm

Finally applying the moment equilibrium condition about point A

\(\sum M_A = 0\)

\(3.5 P - (6) ( \dfrac{4}{7.2111}F_{BC}) = 0\)

\(3.5 P - 3.328 F_{BC} = 0\)

\(3.5 P = 3.328 F_{BC}\)

\(3.5 P = 3.328 *2.09676 \ kN\)

\(P =\dfrac{ 3.328 *2.09676 \ kN}{3.5 }\)

P = 1.9937 kN

Hence; the maximum load P that can be applied is 1.9937 kN

Answer:

The answer to this question can be defined as follows:

Explanation:

The sky driver began his sky journey from Arkansas, drove across the Tennessee River then landed in North Carolina. He returned to both the north in the very same direction. He began with NC, traveled through Tennessee, eventually lands in Arkansas. But North Carolina has been in the third state on which skydiver was traveling over, and It's also more than 700 miles from Arkansas to the NC.

Answer: Why is even here then.

Explanation:

Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

A 12 V battery is connected to a 100 Ω resistor and a capacitor. We have to determine the capacitance needed so that the voltage across the capacitor does not exceed a certain value.

Let us solve each part of the question separately. To determine the value of capacitance needed so that the voltage across the capacitor never exceeds 200 V, we can use the formula. I is the current in the circuit, t is the time interval, V is the maximum voltage, and C is the capacitance.

Here, we need to find the maximum current that can flow in the circuit without exceeding 200 V. We can use Ohm's law to find V = IR => I = V/R = 12/100 = 0.12 Therefore, the capacitance needed C = (It) / V = (0.12 × t) / 200For example, if we want the voltage across the capacitor to never exceed 200 V for 0.1 second, the capacitance required would C = (0.12 × 0.1) / 200 = 6 × 10^-5 F or 60 μF(b) To determine the value of capacitance needed so that the voltage across the capacitor never exceeds 20 V.

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Answer:

Explanation:

Formula

Voltage_p * Current_p = Voltage_s * Current_s

Comment

What the formula means is the voltage multiplied by the current in the primary = voltage multiplied by the current in the secondary.

Givens

Vp =100 v

Ip = 6 amps

Vs = x

Is = 0.75 amps

Solution

100 * 6 = 0.75* x

600 = 0.75 x                  Divide both sides by 0.75

600/0,75 = 0.75x/0.75

800v = x

What you have here is a step up transformer. It has a relatively small voltage (100 volts ) on the primary which the transformer changes to 800 volts in the secondary.

Answer

800 volts.

The thread is crucial for ensuring the quality and durability of the garment. It is formed by spinning and twisting fibers together, creating a continuous strand that is used to hold the various components of the garment together.

The quality of the thread directly affects the overall quality of the garment. A strong and well-constructed thread is essential for providing structural integrity and preventing the garment from unraveling or falling apart over time. It must be able to withstand the stresses and strains that occur during regular use, including stretching, pulling, and washing.

When choosing the appropriate thread for a garment, several factors are considered, including the type of fabric, the intended use of the garment, and the desired aesthetic. Different threads have varying levels of strength, elasticity, and resistance to abrasion. For example, a heavier fabric might require a thicker and more robust thread, while a delicate fabric may require a finer and more delicate thread to prevent damage.

The quality of the thread also relates to its consistency and uniformity. Irregularities in the thread's thickness or tension can result in uneven stitches, which may compromise the appearance and functionality of the garment. In addition, the thread's color and texture should be chosen carefully to complement the fabric and enhance the overall aesthetic appeal.

In the manufacturing process, quality control measures are implemented to ensure that the thread meets the required standards. This involves testing the thread for strength, colorfastness, and resistance to abrasion. By using high-quality thread and maintaining strict quality control, garment manufacturers can ensure that the final product meets or exceeds the expectations of customers in terms of both appearance and durability.

In summary, the thread plays a vital role in holding a garment together and contributes significantly to its quality and longevity. Choosing the right thread and ensuring its consistent quality throughout the manufacturing process are essential for creating garments that are durable, aesthetically pleasing, and able to withstand regular use.

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The combined design water capacity of the water treatment facility and distribution system should be 19,221,000 litres per day.

Maximum Day Demand (MDD) x 1.80 W3-01.3 System Parameters = Peak Hour Demand (PHD). A. Average Day Demand (ADD) multiplied by 2.25 to get Maximum Day Demand (MDD).

Average water demand = Population x Average water demand per capita

Average water demand = 55,000 x 170 liters per capita per day

Average water demand = 9,350,000 liters per day

Maximum day water demand = 1.5 x 9,350,000 liters per day

Maximum day water demand = 14,025,000 liters per day

Peak hour water demand = 170 liters per capita per day x 55,000 people x 2 / 24 hours x 4 peak hours

Peak hour water demand = 9,067 liters per hour

Fire demand = 3 liters per second x 60 seconds per minute x 24 hours

Fire demand = 5,400 liters per day

Design water capacity = 14,025,000 liters per day + 5,400 liters per day + (0.2 x 9,350,000 liters per day)

Design water capacity = 19,221,000 liters per day

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Answer:

The advantages of using a pure sine wave for your appliances and machinery are as follows: Reduces electrical noise in your machinery.

translates to no TV lines and no sound system hum.

Cooking in microwaves is quicker.

Explanation:

The smoothest signal is a sine wave, and sine waves are the basis of all functions.

Every other continuous periodic function is a basis function, which means that it can be described in terms of sines and cosines.

For instance, using the Fourier series, I can describe the fundamental Sinusoidal frequency and its multiples in terms of the triangle and square waves.

Based on the image attached, the reading of micrometer is= 15.20.

You will see a line of numbers running down the barrel of your micrometer, starting with the barrel scale. On the barrel scale, each number corresponds to 0.100. Looking at the barrel, 1 equals 0.100, 2 equals 0.200, 3 equals 300, and so on. The distance between each tick mark and the larger numbers on the barrel is 0.025, or 25 thousandths. 

Note that micrometer is one that is also referred to as a micrometer screw gauge—is a tool with a calibrated screw that is frequently used for precise measurement of components in mechanical engineering, and others.

Looking at the image, you will see the stop ends at 15 and  and 20 so adding them together will be option A. 15.20.

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Answer:

Because the shunt winding consist of a large number of turns,

Explanation:

It is nearly impossible to obtain satisfactory performance from a shunt motor connected to an ac power source because the shunt winding consist of a large number of turns, due to the high number of turns that the DC shunt motor has it develops a high impedance when connected to an ac power source. and due  to this high impedance the amount of current that flows through the field will be very low making it nearly impossible for the shunt motor to operate properly

As a civil engineer, when comparing two potential locations for a project, it is essential to evaluate the cost-benefit analysis using various techniques. One of the popular techniques is the Annual Worth/Uniform Series approach to incremental BC analysis.

To determine which project to select, we need to analyze the incremental cost and benefits of each project. In this approach, we calculate the present value of the annual cost and benefit streams for both projects and then determine the net present value of the incremental benefits.

Let's assume that Project A has an annual benefit of $100,000 and an annual cost of $70,000. On the other hand, Project B has an annual benefit of $120,000 and an annual cost of $90,000. The time horizon for both projects is 5 years, and the discount rate is 10%.

Using the Annual Worth/Uniform Series approach to incremental BC, we can calculate the net present value of the incremental benefit of Project B over Project A, which is $82,251. This means that Project B generates a higher benefit than Project A, and thus, we should select Project B.

In conclusion, the Annual Worth/Uniform Series approach to incremental BC analysis is an effective tool for comparing two potential projects' cost-benefit analysis. This approach enables civil engineers to make informed decisions based on financial and economic considerations.

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The input resistance of an ideal amplifier is infinite and not zero and the input resistance is infinite but not zero.

Option c,d are not true.

What are the statements true for an ideal amplifier?

At all frequencies, an ideal amplifier has infinite input impedance, zero output impedance, and a constant gain. The input impedance of an ideal op amp is infinite, and the output impedance is zero, but the gain is infinite.

An ideal opamp has an infinite input impedance, which results in zero current flow. As a result, there is no voltage across the terminals.

Ideal amplifier : Zero (infinite decimal places) is not possible; an "ideal" would have no distortion, output impedance, etc.

Hence to conclude the ideal amplifier has the good characteristics

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Answer:

Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.

Explanation:

The combination of the preferred crystallographic plane and directions on that plane along which dislocation motion typically occurs is known as the slip system

What is slip system?

When applied forces cause deformation planes to form on a metal's surface or its intergranular boundaries, this metallurgical phenomenon is referred to as a slip system. It is the main criterion for a material to undergo plastic deformation, which could increase its susceptibility to failure or corrosion.

For metal deformation to take place, slip systems are essential. Crystal lattices slide past one another to form slip systems when shear stress is applied along an object's length. The lattice in which slip systems exist is specific to that structure.

The atomic density that is highest is found in slip planes. Also unidirectional are slip systems. The system's smallest lattice translation vectors line up with the direction that slip planes exhibit.

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An airplane flying across the sky experience drag force determined by the factors including the speed of flight, coefficient of skin friction and the reference surface area

The boundary layer thickness is approximately 0.233 cm

The total skin friction drag, is approximately 265 N

Reason:

First part:

Given parameters are;

Chord length, L = 3 m

Velocity of the plane, V = 200 m/s

Density of the air, ρ = 1.225 kg/m³

Viscosity of the air, μ = 1.81 × 10⁻⁵ kg/(m·s)

The Reynolds number is given as follows;

\(R_{eL} = \dfrac{\rho \times V \times L}{\mu}\)

Therefore;

\(R_{eL} = \dfrac{1.255 \times 200 \times 3}{1.81 \times 10^{-5}} = 4.16022099448 \times 10^7 \approx 4.16 \times 10^7\)

Boundary layer thickness, \(\delta_L\), for laminar flow, is given as follows;

\(\dfrac{ \delta_L }{L}=\dfrac{5.0}{\sqrt{R_{eL} } }\)

\({ \delta_L }=\dfrac{5.0 \times L}{\sqrt{R_{eL} } }\)

Which gives;

\({ \delta_L }=\dfrac{5.0 \times 3}{\sqrt{4.16 \times 10^{7}} } \approx 2.33 \times 10^{-3 }\)

The boundary layer thickness, \(\delta_L\) ≈ 2.33 × 10⁻³ m = 0.233 cm

Second Part

The total skin friction is given as follows;

\(Dynamic \ pressure, q = \dfrac{1}{2} \cdot \rho \cdot V^2\)

Therefore;

\(q = \dfrac{1}{2} \times 1.225 \times 200^2 = 24,500\)

The dynamic pressure, q = 24,500 N/m²

Skin friction drag coefficient, \(C_D\), is given as follows;

\(C_D = \dfrac{1.328}{\sqrt{R_{eL} } }\)

Therefore;

\(C_D = \dfrac{1.328}{\sqrt{4.16 \times 10^7 } } \approx 2.06 \times 10^{-4}\)

Skin friction drag, \(D_f\), is given as follows;

\(D_f\) = q × \(C_D\) × A

Where;

A = The reference area

∴ \(D_f\) = 24,500 N/m² × 2.06 × 10⁻⁴ × 3 m × 17.5 m = 264.9675 N ≈ 265 N

The total skin friction drag, \(D_f\) ≈ 265 N

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Answer:

The idea is to protect the puddle while it cools

Explanation:

The percent crystallinity of the specimen with a density of 1.382 g/cm^3 is approximately 85.5%.

To compute the density of totally crystalline poly(ethylene terephthalate) (PET), we can use the density and percent crystallinity values given for the material.

(a) Compute the density of totally crystalline PET:

Density of totally crystalline PET = Density / (1 - Percent Crystallinity / 100)

Density = 1.408 g/cm^3

Percent Crystallinity = 74.3%

Density of totally crystalline PET = 1.408 / (1 - 74.3 / 100)

Density of totally crystalline PET = 1.408 / (1 - 0.743)

Density of totally crystalline PET = 1.408 / 0.257

Density of totally crystalline PET ≈ 5.484 g/cm^3

(b) Compute the density of totally amorphous PET:

Density of totally amorphous PET = Density / (1 + Percent Crystallinity / 100)

Density = 1.343 g/cm^3

Percent Crystallinity = 31.2%

Density of totally amorphous PET = 1.343 / (1 + 31.2 / 100)

Density of totally amorphous PET = 1.343 / (1 + 0.312)

Density of totally amorphous PET = 1.343 / 1.312

Density of totally amorphous PET ≈ 1.023 g/cm^3

(c) Determine the percent crystallinity of a specimen having a density of 1.382 g/cm^3:

Percent Crystallinity = (Density of totally crystalline PET - Density of the specimen) / (Density of totally crystalline PET - Density of totally amorphous PET) * 100

Density of the specimen = 1.382 g/cm^3

Density of totally crystalline PET = 5.484 g/cm^3

Density of totally amorphous PET = 1.023 g/cm^3

Percent Crystallinity = (5.484 - 1.382) / (5.484 - 1.023) * 100

Percent Crystallinity ≈ 85.5%

Therefore, the percent crystallinity of the specimen with a density of 1.382 g/cm^3 is approximately 85.5%.

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Answer:

i) 0.610 m or 610 mm

ii) 0.4 m or 400 mm

Explanation:

The pressure difference between the pipes is

a) Air

Pa + πha +Ha = Pb + πhb +Hb

Pa - Pb = π(hb-ha) + Hb-Ha

Relative density of air = 1.2754 kg /m3

Pa - Pb = 1.2754 * 0.4 + (0.3-0.2) = 0.610 m or 610 mm

b) paraffin of relative density of 0.75

Pa - Pb = π(hb-ha) + Hb-Ha

Pa - Pb = 0.75 * 0.4 + (0.3-0.2) = 0.4 m or 400 mm