2. A woman lifts up a laundry basket 1. 5m and carries it 20m across the room. This takes 15s.


Work is done on the laundry basket_*


(20 Points)


in walking across the room


during the entire 15s


work is not done


in lifting the basket

Answer:

\(16 * 10^{-7}\) F

Explanation:

The ability of a capacitor to store an electric charge (Q) per unit of voltage (V) across its plates of a capacitor is called capacitance. SI unit of capacitance is Farad.

It can be measured by using the formula C=Q/V.

Q = 4.0 x 10^-10 C

V = 250.0 V

C = Q / V

   = \(\frac{4.0 * 10^{-10} }{250}\)

   = \(16 * 10^{-7}\) F

Hence, the capacitance is \(16 * 10^{-7}\) F.

Answer:

Explanation:

1.6 X 10^-12 F

Answer:

The distance between the object and the mirror is X/2

Explanation:

If we look into a plane mirror, we see the image of our face situated behind the mirror. Now, if we move backwards, the image also moves backwards in the mirror so that it is always at the same distance behind the mirror as our face is in front of the mirror. Thus, the image I in a plane mirror is as far behind the mirror as the object O is in front of it. In other words, the distance of the image from the plane mirror is equal to the distance of the object from the plane mirror. We will prove this fact by using the laws of reflection and simple geometry.

From the second law of reflection, we have:Angle of incidence = Angle of reflection

So, NAO =  NAX       (angle i = angle r)

It is clear that the triangles MIA and MOA are congruent triangles and, therefore, their corresponding sides should be equal. Thus :

IM = OM

MA is a common side to both triangles  

Now, OM represents the distance of object from the mirror, and  IM represents the distance of image from the mirror .  

So, we can now say that:

Distance of image from mirror = Distance of object from mirror

To determine whether the total energy of system B increases, decreases, or stays the same as the ball falls from height h to hf, consider the net external work on system B.

The net external work on system B is given by the work-energy theorem, which states that the net work done on an object is equal to the change in its kinetic energy:

Net work = ΔKE

If the net work done on system B is positive, it means that work is being done on the system, resulting in an increase in its kinetic energy and thus total energy. If the net work is negative, work is being done by the system, resulting in a decrease in its kinetic energy and total energy. If the net work is zero, there is no change in the total energy of the system.

Now, as the ball falls from height h to hf, gravity is the only external force acting on the ball. The work done by gravity can be expressed as:

Work_gravity = -mghf + mgh

where m = mass of the ball, g = acceleration due to gravity, and hf and h = final and initial heights, respectively.

Substituting this into the net work equation:

Net work = Work_gravity = -mghf + mgh

Now, consider the possible cases:

If hf < h: In this case, the final height is lower than the initial height. Therefore, hf < h, and the net work becomes:

Net work = -mghf + mgh < 0

This means that work is being done by the ball as it falls, resulting in a decrease in its kinetic energy and total energy. Hence, the total energy of system B decreases.

If hf = h: In this case, the final height is equal to the initial height. Therefore, hf = h, and the net work becomes:

Net work = -mghf + mgh = 0

The net work is zero, indicating that there is no change in the total energy of system B. The total energy stays the same.

If hf > h: In this case, the final height is higher than the initial height. Therefore, hf > h, and the net work becomes:

Net work = -mghf + mgh > 0

This means that work is being done on the ball as it falls, resulting in an increase in its kinetic energy and total energy. Hence, the total energy of system B increases.

In summary, if the final height (hf) is lower than the initial height (h), the total energy of system B decreases. If the final height is equal to the initial height, the total energy stays the same. And if the final height is higher than the initial height, the total energy of system B increases.

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The length of time (in seconds) that the train blocks the crossing are 29.15 s.

Velocity is defined as the trade in position or displacement (∆x) divided by the time durations (∆t) wherein the displacement takes place. The common velocity can be effective or negative depending upon the sign of the displacement. The SI unit of average velocity is meters per second (m/s or ms-1).

Average velocity is calculated by means of dividing your displacement (a vector pointing out of your initial role in your final position) through the entire time; the average pace is calculated by way of dividing the overall distance you traveled by means of the total time.

Calculation:-

the average velocity =(82.4+16.4)/2

                             =49.4 km/h

the distance travelled =length of the train =400 m=0.4km

 time taken =distance /average speed

                =0.4/49.4

                 =0.00809 h

                  =29.15 s

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Given :

A motorcycle weighing 7300 N is parked on an 8.2 degree slope.

To Find :

The magnitude of the acceleration at which the motorcycle will roll downhill if its brake is released.

Solution :

We know, the acceleration due to gravity in the motorcycle is :

g = 9.8 m/s²

Now, component of acceleration along the slope is given by :

\(g'= g \times sin \ 8.2^o\\\\g'= 9.8 \times sin \ 8.2^o\\\\g' = 9.8 \times 0.143\\\\g'= 1.40\ m/s^2\)

Therefore, the magnitude of the acceleration at which the motorcycle will roll downhill if its brake is released .

The length of the rubber band that the boy must use is 0.024 m or 24 mm.

To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:

where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.

Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.

We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):

where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:

k = (v² M) / (2 m)

We can now combine the two equations to solve for the length of the rubber band, L:

U = 1/2 k x²

U = 1/2 ((v² M) / (2 m)) (0.25 L)²

U = (v² M L²) / (32 m)

The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:

U = 1/2 M v²

(v² M L²) / (32 m) = 1/2 M v²

L = ((16 m v²) / (k M))

L = ((16 m v²) / ((v² M) / (2 m) M))

L = √(32 m^2 / M)

L = (0.032 M)

Substituting the given values, we get:

L = √(0.032 * 0.006)

L = 0.024 m

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The number of moles in 38.7 g of phosphorus pentachloride is approximately 0.1857 mol.

Phosphorus pentachloride (\(PCl_5\)) is a white solid that is commonly used as a catalyst in certain organic reactions. To calculate the number of moles in 38.7 g of phosphorus pentachloride, we can use the formula:

Number of moles = Mass / Molar mass

The molar mass of phosphorus pentachloride can be calculated by adding up the atomic masses of its constituent elements. Phosphorus (P) has an atomic mass of 31.0 g/mol, and chlorine (Cl) has an atomic mass of 35.5 g/mol. Since there are five chlorine atoms in phosphorus pentachloride, we multiply the atomic mass of chlorine by 5.

Molar mass of \(PCl_5\) = (31.0 g/mol) + (35.5 g/mol x 5) = 208.5 g/mol

Now we can plug in the values into the formula:

Number of moles = 38.7 g / 208.5 g/mol

Calculating this, we find:

Number of moles ≈ 0.1857 mol

Therefore, there are approximately 0.1857 moles of phosphorus pentachloride in 38.7 g of the compound.

In summary:
- Phosphorus pentachloride (\(PCl_5\)) is a white solid used as a catalyst in organic reactions.
- To calculate the number of moles, we divide the mass of the compound (38.7 g) by its molar mass (208.5 g/mol).
- The molar mass is calculated by summing the atomic masses of phosphorus and chlorine.
- The number of moles in 38.7 g of phosphorus pentachloride is approximately 0.1857 mol.

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Answer:

a

Explanation:

............

..............option A

Answer:

A is the answer as electromagnetic and strong nuclear forces influence the interaction between charged particles within an atom the only difference being their intensity! Hope this helps :) and if you dont mind, mark me brainliest so i can get to the next rank :(

Answer:

It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.

The frequency of the violet light is\(7.5 x 10^14 Hz (Hertz).\)

The frequency of the wave is determined by dividing the velocity of light by its wavelength.

\(v=f/λWhere:v = velocity of light f = frequency λ = wavelength of the light\)

The speed of light is\(3.00 x 10^8\) meters per second (m/s).

To convert 400 cm into meters, divide 400 by 100. 400 cm = 4 m

Therefore,λ = 4 meters

Plugging these values into the formula, \(v = (3.00 x 10^8 m/s) / (4 m) = 7.5 x 10^14 Hz\)

So, the frequency of the violet light with a wavelength of \(400 cm is 7.5 x 10^14 Hz.\)

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The amount of energy needed to raise the temperature of 1 gram of a substance by 1 degree Celsius

This is most like Fixed-interval reinforcement schedule.

Therefore the answer is Fixed-interval

The scenario described in the question is most similar to a fixed-interval reinforcement schedule, in which reinforcement is delivered after a fixed period of time, such as every two weeks, as long as the behavior occurs.

This type of reinforcement schedule is often used in the workplace to encourage reliable attendance and work performance.

Option variable-ratio, involves reinforcement after a variable number of responses and is often associated with gambling behavior. Option fixed-ratio, involves reinforcement after a fixed number of responses, while option variable-interval, involves reinforcement after a variable amount of time has elapsed.

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It will take 0.82sec to reach the edge of the table if the system is free to move. If mB=1.0 kg, 99 kg mA must be used if the system's acceleration is to be kept above 1/100 g.

(a) mA = 11 kg

mB = 7 kg

T = mA mB g / (mA+mB) = 77*9.8 / 18 = 41.92 N is the formula for cord tension.

In the case of mA, we have T = mA*a

acceleration of mA, a = T / mA = 41.92 / 11 = 3.81 m/s²

For mB, we have mB*a = mB*g - T a = (mB*g - T) / mB

                                  a = (7*9.8 - 41.92) / 7 = 3.81 m/s²

(b) Initial velocity of mA, u = 0

The distance traveled by mA, s = 1.3 m

We have,

\(s = u t + (1/2) a t^2\\ s = at^2 / 2\\ t = (2s / a)^(1/2) = (2*1.3 / 3.81) (1/2) = 0.82 sec\)

(c) mB = 1 kg

The system's acceleration, a = g/100

The system's acceleration is given by the formula a = mB*g / (mA+mB).

mA = [mB*g / a] - mB = [ 1*9.8*100/9.8 ] - 1 = 99 kg

Acceleration is the rate at which velocity changes with respect to time. It is a vector quantity whose magnitude denotes the amount of change in velocity per unit of time.

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Answer:

microwave because it will heat it very well

Answer:

Produce energy, or make carbohydrates or fats.

Explanation:

Answer:

amplitude

Explanation:

sound travel and it amplifies

Answer:

False. Not everything can turn into a black hole. The formation of a black hole requires a massive object, typically a star, to collapse under its own gravity. This collapse causes the object to become so dense that it creates a singularity, a point of infinite density at the center of the black hole, which is surrounded by an event horizon, the point of no return beyond which nothing, not even light, can escape. So, only objects with sufficient mass and gravity can become black holes.

Explanation:

Answer:

x = 4.32 [m]

Explanation:

We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 700 [N]

m = mass = 2030 [kg]

a = acceleration [m/s²]

Now replacing:

\(F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]\)

Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

\((m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})\)

where:

m₁ = mass of the car = 2030 [kg]

v₁ = velocity at the initial moment = 0 (the car starts from rest)

Imp₁₋₂ = The impulse or momentum (force by the time)

v₂ = final velocity after the impulse [m/s]

\((2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]\)

Now using the following equation of kinematics, we can determine the distance traveled.

\(v_{2}^{2} =v_{1}^{2}+2*a*x\)

where:

v₂ = final velocity = 1.72 [m/s]

v₁ = initial velocity = 0

a = acceleration = 0.344 [m/s²]

x = distance [m]

\(1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]\)

False. In igneous rocks like granite, S-waves (secondary waves) travel slower than P-waves (primary waves), not faster.

P-waves are compressional waves that can propagate through both solids and liquids, including granite. On the other hand, S-waves are shear waves that can only travel through solids.

Due to the difference in the way they propagate, P-waves have a higher velocity than S-waves in most materials, including igneous rocks.

Therefore, the statement that S-waves travel about 1.7 times faster than P-waves in granite is incorrect. It is the P-waves that typically exhibit higher speeds compared to S-waves in such geological formations.

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Answer:

The answer is . A 46.2g

Answer:

true

Explanation:

PLS MAKE ME AS BRAINLIST

The statement B) They consist of concentrations of particles generally smaller than 10 meters in diameter is correct about statements concerning ring satellites of the planets.

Statement A is incorrect. Ring satellites of the planets are not thin, solid disks revolving around the parent planets in polar orbits. Instead, they are made up of numerous particles, such as dust, rocks, and ice, that collectively form the rings. Statement C is incorrect. The orbits of ring satellites do coincide with the equatorial planes of the parent planets. They are generally located in the same plane as the planet’s equator. Statement D is incorrect.

Ring systems are present around Saturn, Jupiter, Uranus, and Neptune. All four of these planets have ring systems, although the characteristics and composition of the rings may differ between them. The only statement that is true is B) They consist of concentrations of particles generally smaller than 10 meters in diameter. The particles in planetary ring systems can range in size from micrometers to larger objects, but they are generally smaller than 10 meters in diameter..

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Answer:

7...is mitochondria :- mitochondria are known as the power house of the cell.

Answer:

1) cell wall

you know cell wall is a made up cellulose

it's present in plant cell

it surface are very hard

it protects high temperature, moisture of air, pressure of air etc

Answer:

3×10^6

Explanation:

frequency is the speed of light ( c) which is a constant number divided the wavelength

f = 3×10^6 / 1.0

The length of the pendulum (in m) is : 0.99m

Time period to reach from left most position to equilibrium position = 0.5s =t

Time period is defined as the time taken to complete one full oscillation

T = 0.5*4 = 2s

for sample pendulum

T = 2π\(\sqrt{\frac{l}{g} }\)

2 = 2π\(\sqrt{\frac{l}{9.81} }\)

l = 0.99m

The period of the pendulum does not depend on the mass of the sphere, only on the length of the chord. Two pendulums with different masses but the same length have the same period. Two pendulums of different lengths have different periods. A pendulum with a long string has a long period

A simple pendulum consists of a sphere (mass point) m suspended from a (massless) cord of length L and fixed at a pivot point P. When shifted to the initial angle and released, the pendulum swings back and forth in a periodic motion. Applying Newton's second law to a rotating system gives the equation of motion for a pendulum.

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The speed of the 1.2 kg block after the spring is released is 3 m/s to the left.

According to the question, a 1.2 kg block and a 1.8 kg block are initially at rest on a frictionless, horizontal surface. When a compressed spring between the blocks is released, the 1.8 kg block moves to the right at 2.0 m/s as shown. We need to determine the speed of the 1.2 kg block after the spring is released.The system's initial momentum is zero since the blocks are at rest. The system's final momentum is made up of the 1.2 kg and 1.8 kg blocks' respective momenta. As a result, the conservation of momentum equation becomes:m1i * v1i + m2i * v2i = m1f * v1f + m2f * v2fWhere m1i * v1i is the 1.2 kg block's initial momentum, m2i * v2i is the 1.8 kg block's initial momentum, m1f * v1f is the 1.2 kg block's final momentum, and m2f * v2f is the 1.8 kg block's final momentum.

As the 1.8 kg block moves to the right at 2.0 m/s after the spring is released, its momentum is:m2i * v2i = 1.8 kg * 0 m/s = 0 kg * m/sm2f * v2f = 1.8 kg * 2 m/s = 3.6 kg * m/sTo calculate the final momentum of the 1.2 kg block, we must first determine its final velocity. We can rearrange the conservation of momentum equation above to solve for v1f:m1f * v1f = m1i * v1i + m2i * v2i - m2f * v2fv1f = (m1i * v1i + m2i * v2i - m2f * v2f) / m1fPlugging in the values:v1f = (1.2 kg * 0 m/s + 1.8 kg * 0 m/s - 1.8 kg * 2 m/s) / 1.2 kgv1f = -3 m/s. Therefore, the speed of the 1.2 kg block after the spring is released is 3 m/s to the left.

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a. classify objects in space.The function of space observatory technology is to classify objects in space.

An astronomical observatory, especially a satellite, that observes celestial objects outside Earth's atmosphere is referred to as a space observatory. A space observatory is a telescope placed in outer space to observe planets, stars, and other objects in the universe.What are the functions of space observatory technology?The function of space observatory technology is to classify objects in space. This function is achieved by collecting and analyzing data on celestial bodies like planets, stars, and other objects, which helps astronomers determine their composition, structure, and other physical properties. This helps to advance our understanding of the universe, from studying star formation to examining the atmospheres of exoplanets, which could be habitable. Some of the space observatory technologies that perform this function include the Hubble Space Telescope, the Chandra X-Ray Observatory, and the Spitzer Space Telescope.

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Apparent magnitude refers to the properties which best measures a star's brightness and is denoted as option D.

This is a term commonly used in astronomical system which talks about the brightness of a star based on its composition such as hydrogen and helium.

it is also determined by how far or bright it is from the planet such as earth when they are viewed by individuals which is regarded as the property in which astronomers use to define its brightness.

This is therefore the reason why apparent magnitude was chosen as the correct choice.

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Answer:

A: Absolute magnitude

Explanation:

I Just did it and the correct answer is ABSOLUTE MAGNITUDE

Answer:

The volume of the object is 3.5cm³