a metal oxide with the formula m2o contains 11.18% oxygen by mass. in the box below, type the symbol for the element represented by m. [a]

A crystal of table salt (NaCl) is dissolved in water. Which of the following statements explains why the dissolved salt does not recrystallize as long as the temperature and the amount of water stay constant?

Na+ and Cl- ions lose their charges in the water.

Water molecules surround the Na+ and Cl- ions.

Na+ and Cl- ions leave the water through vaporization.

Water molecules chemically react with the Na+ and Cl- ions.

Your answer: -

Answer: B - Water molecules surround the Na+ and Cl- ions.

Answer:  2205 lb/m^3

Explanation:  

Convert:  (1g/cm^3)*(0.002205lb/g)*(1cm^3/1x10^-6m^3) = 2205 lb/m^3

Answer:

The waves travel in a direction parallel to direction of the vibration of the medium

The waves travel in a direction parallel to direction of the vibration of the medium

A mechanical wave is defined as an oscillation of matter which is responsible for energy transfer via  medium.

The propagation of  wave is limited by the medium of transmission, the oscillating material which revolve around a fixed point with little translational motion.

A surface wave which is an example of  mechanical wave that propagate  along the interface of two different media in physics. other common examples are Gravity waves on the surface of liquids, ocean waves.

Surface wave can be propagated in a slow way through Earth material and are generally lower in frequency than body waves.

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- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

In the given chemical reactions, we need to identify whether the highlighted atom is being oxidized or reduced. Let's analyze each reaction individually:

Reaction 1: 4 HF (g) + SiO₂ (s) → SiF₄ (g) + 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in SiO₂ undergoes a change in oxidation state from -2 to 0 in SiF₄. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 2: 2 Cl (aq) + 2 H₂O (l) → 2 OH (aq) + H₂ (g) + Cl₂ (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in H₂O undergoes a change in oxidation state from -2 to -1 in OH. Therefore, the highlighted atom (oxygen) is reduced.

Reaction 3: H₂S (aq) + 2 NaOH (aq) → Na₂S (aq) + 2 H₂O (l)

In this reaction, the highlighted atom is sulfur (S). Sulfur in H₂S undergoes a change in oxidation state from -2 to -2 in Na₂S. Therefore, the highlighted atom (sulfur) is neither oxidized nor reduced.

Reaction 4: 2 H₂ (g) + O₂ (g) → 2 H₂O (g)

In this reaction, the highlighted atom is oxygen (O). Oxygen in O₂ undergoes a change in oxidation state from 0 to -2 in H₂O. Therefore, the highlighted atom (oxygen) is reduced.

To summarize:

- In reactions 1 and 2, the highlighted atom (oxygen) is reduced.

- In reaction 3, the highlighted atom (sulfur) is neither oxidized nor reduced.

- In reaction 4, the highlighted atom (oxygen) is reduced.

It's important to note that oxidation and reduction involve changes in the oxidation state of atoms, indicating the gain or loss of electrons. The analysis above is based on the change in oxidation state of the highlighted atom in each reaction.

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Answer:

Explanation: 2 C19H34O2(l) + 53 O2(g) ==> 38 CO2(g) + 34 H2O(l) ... balanced equation

∆Hcombustion

∆H = ∑∆Hf products - ∑∆Hf reactants

∆H = [(38 x -393.5) + (34 x -285.8)] - (2 x -645.7) = (-14,953 + -9717) - (-1291)

∆H = -24,670 + 1291

∆H = 25,961 kJ

(be sure to check the math)

Answer:

0.0238 moles NaOH

Explanation:

To find the amount of moles, you need to

(1) convert the volume from mL to L (1,000 mL = 1 L)

(2) calculate the amount of moles (using the molarity equation)

It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs.

 125.0 mL NaOH                  1 L
---------------------------  x  ---------------------  =  0.1250 L NaOH
                                         1,000 mL

Molarity = moles / volume (L)                    <----- Molarity equation

0.190 M = moles / 0.1250 L                       <----- Insert values

0.0238 = moles                                         <----- Multiply both sides by 0.1250

The balanced chemical equation is the representation of the elements with the same proportion of elements on both sides. The balanced equation is, 2CH₃(CH₂)₄CH₃ + 19O₂ → 12CO₂ + 14H₂O.

An equation is said to be balanced if the number of atoms of the element on the right side is the same as that of the left side of the reaction.

CH₃(CH₂)₄ CH₃(g) + O₂(g) → CO₂(g) + H₂O(g)

Here the number of carbon, hydrogen, and oxygen are unbalanced.

Coefficients are added before carbon, oxygen, and a hydrogen atom. First, 2 is added before the carbon on the reactant side and 12 at the carbon of the product side.

After this, the number of hydrogen is balanced by adding 14 on the product side followed by adding 19 on the oxygen of the reactant side.

The balanced equation: 2CH₃(CH₂)₄CH₃ + 19O₂ → 12CO₂ + 14H₂O

Therefore, 2CH₃(CH₂)₄CH₃ + 19O₂ → 12CO₂ + 14H₂O is the balanced equation.

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Answer:

Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO

Explanation:

The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.

The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.

The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.

The methyl groups are non-polar and do not have any significant reactivity.

The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.

The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.

Answer:

3.25 moles

Explanation:

From the equation,   2 moles of Al results in one mole of Al2(so4)3

    6.5 / 2 = 3.25

The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:

Q = nF

Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.

In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.

First, we need to calculate the number of moles of Cl2 produced:

Molar mass of Cl2 = 35.45 g/mol

Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol

Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:

Q = nF

Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)

Q ≈ 1.308 x 10^9 C

The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.

Given that the time is 18 hours, we convert it to seconds:

Time = 18 hours * 60 minutes/hour * 60 seconds/minute

Time = 6.48 x 10^4 seconds

Finally, we can calculate the current:

Current (I) = Q / Time

I = (1.308 x 10^9 C) / (6.48 x 10^4 s)

I ≈ 2.02 x 10^4 Amperes

Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

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Answer:

potential energy to kinetic energy

Explanation:

In this system, the energy transformation is from potential energy to kinetic energy.

Potential energy is the energy due to the position of a body.

Kinetic energy is the energy due to the motion of a body.

When the rubber band is stretched, it stores elastic potential energy. This energy is transformed to kinetic energy as it is release and it begins its motion.

Therefore, potential energy is transformed to kinetic energy.

The concept molarity is used here to determine the pH after adding 12.6 mL of the base. The term molarity is an important method which is used to calculate the concentration of a solution. Here the pH is 1.23.

The term molarity is defined as the number of moles of the solute dissolved per litre of the solution. It is also called the molar concentration. It is represented as 'M' and its unit is mol / L.

Molarity is given as:

M = Number of moles / Volume of solution in liters

'n' of HCN = 20.2 × 1 L / 1000 mL × 0.382 = 0.0077 mol

'n' of Ba(OH)₂ = 13.7 × 1L / 1000 mL × 0.421 = 0.0057 mol

Excess H⁺ = 0.002

Total volume = 20.2 + 13.7 = 33.9 mL = 0.0339 L

Concentration of H⁺ = 0.002 / 0.0339 = 0.058

So pH is:

pH = - log[H⁺]

pH = - log[ 0.058] = 1.23

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Answer

b) 1 mole of atoms

Explanation

Avogadro;s Constant says a mole of any substance contains the same number of atoms (6.022 × 10²³).

Therefore, 1 mole of atoms is correct.

Answer:

10 neutrons

Explanation:

The mass of is made up of the total protons and neutrons in an atom.

Each particle has a mass of 1 amu (atomic mass unit).

All fluorine atoms have 9 protons.

If each proton is 1 amu, the protons must contribute 9 amu to the total mass of the atom (9 x 1 amu = 9 amu).

This means the neutrons must contribute a total mass of 10 amu (18.998 amu - 9 amu = ~10 amu).

If each neutron has a mass of 1 amu, there must be 10 neutrons in a fluorine atom (10 amu / 1 amu = 10 amu).

The name of the salt tells us that:

a) there is just one other element combined with the metal by looking at the suffix of the salt's name.

b) the presence of oxygen in a salt can be indicated by the name of the salt.

a) The name of a salt can tell us that there is just one other element combined with the metal by looking at the suffix of the salt's name. If the salt name ends in "-ide," it indicates that the salt is composed of a metal and a single non-metal element.
For example, sodium chloride (NaCl) and potassium bromide (KBr) are salts where the metal (sodium and potassium) is combined with a single non-metal element (chlorine and bromine, respectively). The "-ide" suffix suggests the presence of only one other element in the salt.

b) The presence of oxygen in a salt can be indicated by the name of the salt. If the salt name includes the element oxygen, it suggests that oxygen is present in the salt compound.
For example, sodium carbonate (Na₂CO₃) and calcium sulfate (CaSO₄) contain the element oxygen in their chemical formulas. The presence of oxygen in the salt is implied by the name and the combination of elements in the compound.

Therefore, the name of salt tells us that there is just one other element combined with the metal and there is oxygen present in the salt

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Answer:

Chemical symbols are abbreviations that are used in chemistry to shorten names of chemical elements and chemical compounds.

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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The amount of energy required to heat the given amount of lead from 18°C to 44°C is 638.976 J.

The specific heat capacity of lead is 0.128 J/g°C.

To calculate the amount of heat energy required to heat 192 grams of lead from 18°C to 44°C, we can use the formula:

Q = m × c × ΔT

where:

Q = heat energy (in Joules)

m = mass of the substance (in grams)

c = specific heat capacity of the substance (in J/g°C)

ΔT = change in temperature (in °C)

Plugging in the given values:

m = 192 g

c = 0.128 J/g°C

ΔT = (44°C - 18°C) = 26°C

Q = 192 g × 0.128 J/g°C × 26°C

Q = 638.976 J

So, the amount of heat energy required to heat 192 grams of lead from 18°C to 44°C is 638.976 Joules.

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Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.

In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.

In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.

Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

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According to the question the reaction enthalpy is thus 10610 J / 0.278 moles = 38.3 kJ/mol.

Enthalpy is a thermodynamic property of a system that measures the total energy content of a system. It is a state function that is expressed in terms of internal energy, pressure, and volume of a system. Enthalpy represents the amount of energy that is associated with a chemical reaction or physical change.

The reaction is exothermic, meaning that heat is released during the reaction. The amount of heat released can be calculated with the equation q = mcΔT, where q is the heat released, m is the mass of the solution, c is the specific heat capacity of the solution, and ΔT is the change in temperature of the solution. Using the given data, the amount of heat released by the reaction can be calculated as q = (250 g)(4.184 J/g-K)(11.1 K) = 10610 J. The enthalpy change for the reaction can then be calculated by dividing the heat released by the number of moles of NaOH, which is 11.1 g / 40.00 g/mol = 0.278 moles. The reaction enthalpy is thus 10610 J / 0.278 moles = 38.3 kJ/mol.

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Answer:

Let it be x

\({ \tt{ (oxidation \: state \: of \: nitrogen) + 2x = overall \: charge}} \\ { \tt{ - 4 - 2 x = 0}} \\ { \tt{2x = - 4}} \\ { \tt{x = - 2}}\)

Answer:

T₂ = 128.19 K

Explanation:

Given that,

The initial volume, V₁ = 12.5 ft³

Initial temperature, T₁ = -173 °C = 100.15 K

Final volume, V₂ = 16 ft³

We need to find the new temperature. The relation between temperature and volume is given by :

\(V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\)

Put all the values,

\(T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{100.15\times 16}{12.5}\\\\T_2=128.19\ K\)

So, the new temperature is 128.19 K.

Taking into account definition of limiting reactant, NO is the limiting reactant.

The balanced reaction is:

2 NO + 2 CO → N₂ + 2 CO₂

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

NO: 2 moles ×30 g/mole= 60 grams

CO: 2 mole ×28 g/mole= 56 grams

N₂: 1 mole ×28 g/mole= 28 grams

CO₂: 2 moles ×44 g/mole= 88 grams

The reactant that is consumed first in a chemical reaction is called the limiting reactant, because the maximum amount of product that is formed depends on the amount of this reactant that was originally present. When this reactant is consumed, no more product can be formed and the reaction stops.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 56 grams of CO reacts with 60 grams of NO, 3 grams of CO reacts with how much mass of NO?

mass of NO= (3 grams of CO× 60 grams of NO)÷ 56 grams of CO

mass of NO= 3.21 grams

But 3.21 grams of CO are not available, 3 grams are available. Since you have less mass than you need to react with 3 grams of CO, NO will be the limiting reagent.

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Answer:

These are the nonmetals.

Answer:

The correct answer would be the use of differential and selective growth medium.

Explanation:

The mixed colonies states of certain species can be developed on the differential and specific media relying on the morphology saw in the general media. These types of selective and differential media will allow certain microorganisms to grow only and not all the rest species present on the media.

It will help in recognizing species present in the mixed colonies present in such a growth medium. Different tests like catalase can be performed to dispose of certain choices not long before the utilization of the differential and particular media.

Thus, the correct answer would be the use of differential and selective growth medium.

Answer: A - Carbon

Explanation: Hope this helps!