A liquid solution that contains a nonvolatile solute has a higher boiling point than the solvent alone. Select one: True False

The mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.

The equation of the synthesis of water from hydrogen and oxygen is given as follows:

The grams of oxygen required is given below:

\(19.2 g\:of H_{2} \times\frac{1\:mol H_{2}}{18 g\:H_{2}} \times\frac{1mol\:O_{2}}{2 mol\:H_{2}}\times\frac{32g\:O_{2}}{1 mol\:O_{2}} = 17.06 g\: O_{2}\)

The equation of the combustion of propane is given as follows:

\(C_{3}H_{8} + 5\:O_{2}\rightarrow3\:CO_{2}+4\:H_{2}O\)

The mass of carbon dioxide produced is given below:

\(100 g\:of\:C_{3}H_{8} \times\frac{1\:mol\:C_{3}H_{8}}{44 g\:C_{3}H_{8}} \times\frac{3\:mol\:CO_{2}}{1\:mol\:C_{3}H_{8}}\times\frac{44g\:CO_{2}}{1 mol\:CO_{2}} = 300 g\:CO_{2}\)

The equation of the reaction of copper and silver nitrate is given as follows:

\(Cu + 2\:AgNO_{3}\rightarrow Cu(NO_{3})_{2} + 2\:Ag\)

\(5.7 g\:Cu \times\frac{1\:mol\:Cu}{64 g\:Cu} \times\frac{1mol\:Cu(NO_{3})_{2}}{1mol\:Cu}\times\frac{188g\:Cu(NO_{3})_{2}}{1 mol\:Cu(NO_{3})_{2}} = 16.7 g\:Cu(NO_{3})_{2}\)

Therefore, the mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.

Learn more about mass and mole ratio at: https://brainly.com/question/16806688

#SPJ1

Answer:

what you've asked so I guess the answer will be 10 days

Answer:

The number of electron shells is therefore the same across a period but increases when moving down a column.

Explanation:

Answer:

The water is impure

Explanation:

Impurities raises the boiling points and lowers the melting point

Answer:

5.27 g of NaCl

Explanation:

The balanced equation for the reaction is given below:

Na₂CO₃ + CaCl₂ —> 2NaCl + CaCO₃

Next, we shall determine the mass of CaCl₂ that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:

Molar mass of CaCl₂ = 40 + (35.5×2)

= 40 + 71

= 111 g/mol

Mass of CaCl₂ from the balanced equation = 1 × 111 = 111 g

Molar mass of NaCl = 23 + 35.5

= 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g

Summary:

From the balanced equation above,

111 g of CaCl₂ reacted to produce 117 g of NaCl.

Finally, we shall determine the theoretical yield of NaCl. This can be obtained as follow:

From the balanced equation above,

111 g of CaCl₂ reacted to produce 117 g of NaCl.

Therefore, 5 g of CaCl₂ will react to produce = (5 × 117)/111 = 5.27 g of NaCl.

Thus, the theoretical yield of NaCl is 5.27 g.

Answer:

12

Explanation:

the 4 by the element symbol O multiplied by the 3 on the outside of the parentheses

Answer:

\(\boxed {\boxed {\sf C. \ 12 \ oxygen \ atoms }}\)

Explanation:

We are given the chemical formula:

\(Fe(ClO_4)_3\)

There are 3 elements here:

The question asks for the number of oxygen atoms, so we can just focus on the O in the formula.

The O has a subscript of 4, indicating there are 4 oxygen atoms in the compound. But the compound is also enclosed in parentheses with a subscript of 3. Therefore, there are 3 of the compounds with 4 oxygen atoms.

We can multiply 3 and 4.

There are 12 oxygen atoms.

Explanation:

Bohr built on Nicholson's idea by adopting the requirement that the angular momentum can have only certain discrete values related to Planck's constant. However Bohr's atom has many orbits for the electrons.

The correct order is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f. The correct option is B.

The correct order of energy sublevel is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.

Thus, with the exclusion of 5s, 5p, 6s, 5d, 6p, 7s, 5f, 6d, and 7p, what we have left in order of increasing energy is 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f.

More on energy sublevels can be found here: energy sublevels

#SPJ1

The correct order from least to greatest energy for the energy sublevels is;  1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f (Option B).

The Aufbau principle offers a method in which the energy levels in an atoms are arranged from the least to the greatest. We know that electrons are filled into orbitals in order of increasing energy.

Thus, the correct order from least to greatest energy for the energy sublevels is;  1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 4d, 4f (Option B).

Learn more about the  Aufbau principle:https://brainly.com/question/13393709

#SPJ1

The mass of water  produced in the oxidation reaction is 2.5 g.

Oxidation reaction of ethanol occurs when ethanol comes in contact with oxygen, producing water and acetic acid. This type of reaction can also produce carbon dioxide and water.

The oxidation reaction of ethanol and oxygen is given as;

CH₃CH₂OH  + O₂  -----------> H₂O  +  CH₃COOH

Molecular mass of ethanol;

CH₃CH₂OH = (12) + (3 x 1) + (12) + (2 x 1) + (16) + (1) = 46 g/mol

Molecular mass of water;

H₂O  = (2 x 1) + (16) = 18 g/mol

From the reaction above, we can infer the following;

46 g of ethanol ---------> 18 g of water

6.5 g of ethanol ---------?

= (6.5 x 18) / 46

= 2.54 g of water

Thus, the mass of water that is produced by the reaction of 6.5g of ethanol is 2.5 g.

Learn more about oxidation reaction here: https://brainly.com/question/27239694

#SPJ1

Answer:   The van’t Hoff factor applies to colligative properties and appears in the formulas for osmotic pressure, vapor pressure, freezing point depression, and boiling point elevation. The factor is named for Dutch chemist Jacobus Henricus van’t Hoff, a founder of the field of physical chemistry and the first winner of the Nobel Prize in Chemistry.

Explanation: I HOPE THIS HELPS AND ANSWERS YOUR QUESTION HAVE A GOOD DAY

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

The van 't Hoff factor i is a measure of the effect of a solute on colligative properties such as osmotic pressure, relative lowering in vapor pressure, boiling-point elevation and freezing-point depression.

Learn more about van't Hoff factor:

https://brainly.com/question/24100697

The concentration of the standard naoh solution after dilution is 0.1 M.

The concentration of a standard NaOH solution after dilution can be calculated using the formula:

M1V1 = M2V2.

This formula is used when a certain volume of a stock solution of known concentration (M1) is diluted with a certain volume of water to obtain a new solution of a lower concentration (M2).

Let's assume that we have a 1 M NaOH stock solution and we want to dilute it to a concentration of 0.1 M.

The volume of the diluted solution we want to obtain is 500 mL.

Using the formula M1V1 = M2V2, we can calculate the volume of the stock solution required to obtain the desired concentration of the diluted solution:

M1V1 = M2V2

=> V1 = M2V2/M1V1

= (0.1 M) (500 mL) / (1 M)

= 5 mL.

So, we need to take 5 mL of the 1 M NaOH solution and dilute it to 500 mL with water to obtain a 0.1 M NaOH solution.

To verify the result, we can calculate the concentration of the diluted solution using the formula:

C = n/V,

where C is the concentration of the solution in units of moles per liter

n is the number of moles of solute

V is the volume of the solution in liters

The number of moles of NaOH in the diluted solution can be calculated using the formula:

n = C x V.

The volume of the diluted solution is 0.5 L, since we diluted the 5 mL stock solution to a total volume of 500 mL or 0.5 L.

The concentration of the diluted solution is 0.1 M.

So, we have:

n = C x V

= (0.1 M) (0.5 L)

= 0.05 moles of NaOH in the 0.5 L diluted solution.

The concentration of the diluted solution is therefore:

C = n/V

= 0.05 moles / 0.5 L

= 0.1 M, which is the desired concentration.

For such more questions on concentration

https://brainly.com/question/30273212

#SPJ8

Approximately 90.6 g of K₂Cr₂O₇ would precipitate out of the solution when cooled from 80°C to 20°C.

To determine how much solute will precipitate out of a solution of potassium dichromate (K₂Cr₂O₇) when cooled from 80°C to 20°C, we apply the following method:

At 80°C:

Initial amount of K₂Cr₂O₇ = 100 g/L

At 20°C:

Solubility of K₂Cr₂O₇ = 9.4 g/L

Amount of K₂Cr₂O₇ that would remain in solution at 20°C = 9.4 g/L x 1 L = 9.4 g

Therefore, the amount of K₂Cr₂O₇ that would precipitate out of the solution when cooled from 80°C to 20°C would be:

Amount of K₂Cr₂O₇ that precipitates out = Initial amount - Amount that remains in solution at 20°C

Amount that precipitates out = 100 g - 9.4 g = 90.6 g

Learn more about solute precipitation here: https://brainly.com/question/11194650

#SPJ1

The complete question is below:

When 100 g of k2cr2o7 in 1 liter of water is cooled from 80oc to 20oc, how much solute will precipitate out of the solution?.

The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A

In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).

When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.

Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.

In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.

The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A

For more such questions on entropy visit:

https://brainly.com/question/30481619

#SPJ8

Answer:

In the middle of every atom is the nucleus. The nucleus contains two types of subatomic particles, protons and neutrons. The protons have a positive electrical charge and the neutrons have no electrical charge. D. No Charge

Explanation:

Answer:

C & D

Explanation:

Just took quiz and got it right! Hope this helps! <3

Answer:

negative charge

Explanation:

Neutrons have no charge, protons have positive charge, and electrons have a negative charge

The empirical formula of the compound is C₂H₁₆S₂N₃O.

The moles of each element is as follows::

For CO₂:

Carbon (C) has a molar mass of 12.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of C in CO₂ = 2.08 g / 12.01 g/mol = 0.173 moles

Moles of O in CO₂ = 2.08 g / 16.00 g/mol = 0.130 moles

For H₂O:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in H₂O = 1.28 g / 1.01 g/mol = 1.27 moles

Moles of O in H₂O = 1.28 g / 16.00 g/mol = 0.080 moles

For SO₃:

Sulfur (S) has a molar mass of 32.06 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of S in SO₃ = 4.77 g / 32.06 g/mol = 0.149 moles

Moles of O in SO₃ = 4.77 g / 16.00 g/mol = 0.298 moles

For HNO₃:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Nitrogen (N) has a molar mass of 14.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in HNO₃ = 3.48 g / 1.01 g/mol = 3.45 moles

Moles of N in HNO₃ = 3.48 g / 14.01 g/mol = 0.248 moles

Moles of O in HNO₃ = 3.48 g / 16.00 g/mol = 0.217 moles

The simplest whole-number ratio of the elements will be:

Carbon: 0.173 moles / 0.080 moles ≈ 2.16

Hydrogen: 1.27 moles / 0.080 moles ≈ 15.88

Sulfur: 0.149 moles / 0.080 moles ≈ 1.86

Nitrogen: 0.248 moles / 0.080 moles ≈ 3.10

Oxygen: 0.080 moles / 0.080 moles = 1

Therefore, the empirical formula is C₂H₁₆S₂N₃O.

Learn more about empirical formulas at: https://brainly.com/question/1603500

#SPJ1

Answer:

space telescope I assume

Explanation:

all other tools can be made and used very easily but a telescope took years and years to invent

Answer:

\(V_2=8L\)

Explanation:

Hello there!

In this case, considering the Avogadro's gas law, which treats the volume and moles in a directly proportional way via:

\(\frac{V_1}{n_1}=\frac{V_2}{n_2}\)

Which can be solved for the final volume, V2, as shown below:

\(V_2=\frac{V_1n_2}{n_1}\)

Thus, by plugging in the given data, we obtain:

\(V_2=\frac{4L*(0.250mol+0.250mol)}{0.250mol}\\\\V_2=8L\)

Regards!

The final total volume of gas is equal to 8 Liters.

Given the following data:

To determine the final total volume of gas, we would apply the Avogadro's equation for an ideal gas:

At constant temperature and pressure, Avogadro's equation for an ideal gas is given by this formula:

\(\frac{V_1}{n_1} = \frac{V_2}{n_2}\)

For the final total moles:

\(n_2=n_1+n_1\\\\n_2 = 0.250+0.250\\\\n_2=0.50\;mol\)

Making \(V_2\) the subject of formula, we have:

\(V_2 = \frac{V_1n_2}{n_1}\)

Substituting the given parameters into the formula, we have;

\(V_2 = \frac{4 \times 0.5}{0.25}\)

Final total volume = 8 Liters.

Read more on ideal gas here: brainly.com/question/3173452

Answer: The number of atoms in 1.65 moles of  Germanium is 9.9433 * 10^23 atoms of Ge.

Explanation:

The number of atoms or molecules in one mole of a substance, is 6.022 * 10^23 which is Avogadro's number.

1 mole of Ge = 6.022 * 10^23 atoms of Ge.

1.65 moles of Ge =1.65*6.022*10^23 atoms of Ge .

Therefore, The number of atoms in 1.65 moles of  Germanium is 9.9433 * 10^23 atoms of Ge.

To learn more about the number of atoms of ge in 1.65 moles.

https://brainly.com/question/28029386

Answer:

1.75 moles

Explanation:

According to CaC₂(s) + 2 H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)

2 moles of H20 will produce 1 mole of Ca(OH)2

therefore 3.5 moles of H2O will produce 3.5 x (1/2) = 1.75 moles of Ca(OH)2

Answer:

its actually c

Explanation:

Answer:

The nucleus ............

1a. The theoretical percentage of water in nickel(II) sulfate heptahydrate is 44.9%

1b. The theoretical percentage of water in aluminum chloride hexahydrate is 44.7%

The percentage of water in nickel(II) sulfate heptahydrate, NiSO₄.7H₂O can be obtained as follow:

Percentage of water, H₂O = (mass of H₂O / mass of NiSO₄.7H₂O) × 100

Percentage of water, H₂O = (126 / 280.7) × 100

Percentage of water, H₂O = 44.9%

The percentage of water in aluminum chloride hexahydrate, AlCl₃.6H₂O can be obtained as follow:

Percentage of water, H₂O = (mass of H₂O / mass of AlCl₃.6H₂O) × 100

Percentage of water, H₂O = (108 / 241.5) × 100

Percentage of water, H₂O = 44.7%

Learn more about percentage composition:

https://brainly.com/question/11952337

#SPJ1

I wrote it down for you these are 100% right answer i hope it helped.

Answer:

2024.70 J

Explanation:

The heat capacity of the coffee cup calorimeter can be calculated using the following formula:

q_calorimeter = q_water + q_water_final

where q_calorimeter is the heat absorbed by the coffee cup calorimeter, q_water is the heat lost by the warm water, and q_water_final is the heat gained by the cold water.

First, calculate q_water:

q_water = m_water * c_water * ΔT

where m_water = 25.0 g is the mass of the warm water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (40.0°C - 29.5°C) = 10.5°C is the change in temperature.

q_water = 25.0 g * 4.184 J/g°C * 10.5°C = 1057.35 J

Next, calculate q_water_final:

q_water_final = m_water * c_water * ΔT

where m_water = 25.0 g is the mass of the cold water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (29.5°C - 20.0°C) = 9.5°C is the change in temperature.

q_water_final = 25.0 g * 4.184 J/g°C * 9.5°C = 967.35 J

Finally, calculate the heat capacity of the coffee cup calorimeter:

q_calorimeter = q_water + q_water_final = 1057.35 J + 967.35 J = 2024.70 J

So the heat capacity of the coffee cup calorimeter is 2024.70 J.

A 25.0 g sample of warm water at 40.0⁰C was added to a 25.0 g sample of water in a Styrofoam coffee cup calorimeter initially at 20.0⁰C. 2024.70 J is the heat capacity of the coffee cup calorimeter.

A physical feature of matter known as heat capacity and thermal capacity is the quantity of heat that must be applied to an object in order to cause a unit change in temperature. Heat capacity is measured in joules per kelvin (J/K), the SI unit. A broad property is heat capacity.

The particular heat capacity, which can be calculated by dividing an object's heat capacity by its mass, is the comparable intense attribute. The molar heat capacity is obtained through dividing the specific heat even by molecular weight of the substance. The heat capacity per volume is gauged by the volumetric heat capacity. The term "thermal mass" is frequently used in civil engineering and architecture to describe a building's ability to hold heat.

q calorimeter = q water + q water final

q water = m ×c water ×ΔT

q water = 25.0 g×4.184 J/g°C ×10.5°C

              = 1057.35 J

q water final = m×c of water × ΔT

q water final = 25.0 g×4.184 J/g°C ×9.5°C

                   = 967.35 J

q calorimeter = q water + q water final

                      = 1057.35 J + 967.35 J

                      = 2024.70 J

Therefore,  2024.70 J is the heat capacity of the coffee cup calorimeter.

To know more about heat capacity, here:

https://brainly.com/question/29766819

#SPJ2

Answer:

129.73 g of CaBr₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CaBr₂ + 2KOH –> Ca(OH)₂ + 2KBr

Next, we shall determine the mass of CaBr₂ that reacted and the mass of Ca(OH)₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaBr₂ = 40 + (80×2)

= 40 + 160

= 200 g/mol

Mass of CaBr₂ from the balanced equation = 1 × 200 = 200 g

Molar mass of Ca(OH)₂ = 40 + 2(16 + 1)

= 40 + 2(17)

= 40 + 34

= 74 g/mol

Mass of Ca(OH)₂ from the balanced equation = 1 × 74 = 74 g

SUMMARY :

From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

Finally, we shall determine the mass of CaBr₂ that react when 48 g of Ca(OH)₂ were produced. This can be obtained as follow:

From the balanced equation above,

200 g of CaBr₂ reacted to produce 74 g of Ca(OH)₂.

Therefore, Xg of CaBr₂ will react to produce 48 g of Ca(OH)₂ i.e

Xg of CaBr₂ = (200 × 48)/74

Xg of CaBr₂ = 129.73 g

Thus, 129.73 g of CaBr₂ were consumed.