A hypothetical element consists of four isotopes. Use the information below to calculate the average atomic volume mass of the element. Work must be shown for credits to be given.

Answer:

Sugar was the solute and water was the solvent.

Answer:

Physical Change

Explanation:

Answer:

72 g/L

Explanation:

The dissolved amount of solute is the difference between the amount you have poured and the amount that precipitated:

125 g - 35 g = 90 g

Thus, 90 grams of solute were dissolved in 1.25 liters. The saturation point is the ratio between the grams dissolved and the volume in liters:

saturation point = 90 g/1.25 L = 72 g/L

The naming of compound can be obtained by following the IUPAC principle. This is shown below:

For the 1st diagram:

Thus, the IUPAC name for the compound is: 3,3-dimethylpentane

For the 2nd diagram:

Thus, the IUPAC name for the compound is: pentene

For the 3rd diagram:

Thus, the IUPAC name for the compound is: 2,2,3-trimethylhexane

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The given statement is untrue because even common precipitation can have pH levels below 7. (around 5.7).

A substance's pH scales from 0 to 7, with 0 being the most alkaline and greater than 7 being the most acidic. A typical rainstorm has a pH of about 5.6, making it mildly acidic due to the dissolution of carbon dioxide (CO2) into water to create weak carbonic acid. The pH of acid rain is typically between 4.2 and 4.4.

Natural events like volcanic eruptions can produce acid rain. Yet, human activity is more frequently to blame for acid rain.

Calcium carbonate crystal formation is accelerated by an increase in temperature or the pH of the solution. Calcium carbonate crystal growth is slowed down by the addition of iron, which also accelerates precipitation in the bulk solution.

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The percent ionization of a solution having a pH of 4.35 and an initial weak acid concentration of 0.00019 is 0.00021%.

To calculate this, first calculate the [H3O+] concentration.

This can be done by taking 10 raised to the power of the pH value, which in this case is 10^-4.35 = 3.2x10^-5 M.

Then, calculate the ionization fraction (alpha) using the equation alpha = [H3O+]/[HA], where [HA] is the initial weak acid concentration. In this case, alpha = 3.2x10^-5/0.00019 = 0.00021.

Finally, convert the ionization fraction to percent ionization using the equation Percent Ionization = 100 * alpha.

Thus, the percent ionization of the given solution is 0.00021 * 100 = 0.021%.

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Answer:transfer oxygen through your blood

Explanation:

Answer:

coordinate the muscles that control breathing

hope this helps ⭐

Answer: An ionic bond will be most likely formed between francium and chlorine having an electronegativity difference of 2.46.

Explanation:

Answer:

In 125 grams of feCO3  287.30 g of FeCO3 oxygen is produce

Explanation:

The Balance Chemical Equation is as follow,

                           FeCl₂ + Na₂CO₃    →    FeCO₃ + 2 NaCl

Calculate Mass of FeCl₂ as,

                           Molarity  =  Moles ÷ Volume

Solving for Moles,

                           Moles  =  Molarity × Volume

Putting Values,

                           Moles  =  2 mol.L⁻¹ × 1.24 L

                           Moles  =  2.48 mol

Also,

                            Moles  =  Mass ÷ M.Mass

Solving for Mass,

                           Mass  =  Moles × M.Mass

Putting Values,

                            Mass  =  2.48 mol × 126.75 g.mol⁻¹

                            Mass =  314.34 g of FeCl2

Calculate Mass of FeCO₃ formed as,

According to equation,

          126.75 g (1 mole) FeClZ produces  =  115.85 g (1 mole) FeCO₃

So,

               314.34 g of FeCl₂ will produce  =  X g of FeCO₃

Solving for X,

                    X =  (314.34 g × 115.85 g) ÷ 126.75 g

                     X =  287.30 g of FeCO₃

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The percent yield of CO₂ if a reaction starts with 91.3 g C₃H₆ and produces 87.0 g CO₂ is 30.4%.

To calculate the percent yield of CO₂, you need to first determine the theoretical yield and then use the actual yield (87.0 g CO₂) to find the percent yield.

1. Balance the reaction: C₃H₆ + O₂ → 3CO₂ + 3H₂O

2. Calculate the molar mass of C₃H₆

(3C + 6H) = (3 × 12.01 + 6 × 1.01)

= 42.08 g/mol

3. Calculate the moles of C₃H₆:

(91.3 g C₃H₆) / (42.08 g/mol)

= 2.168 moles C₃H₆

4. Since the ratio between C₃H₆ and CO₂ is 1:3, moles of CO₂

= 3 * 2.168

= 6.504 moles

5. Calculate the molar mass of CO₂ (C + ₂O)

= (12.01 + 2 × 16.00)

= 44.01 g/mol

6. Calculate the theoretical yield:

(6.504 moles CO₂) × (44.01 g/mol)

= 286.2 g CO₂

7. Calculate the percent yield:

(Actual yield / Theoretical yield) × 100

= (87.0 g CO₂ / 286.2 g CO₂) × 100

= 30.4%

Thus, the percent yield of CO₂ in this reaction is 30.4%.

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Answer:

1300cm3.

Explanation:

Step 1:

Data obtained from the question.

Initial temperature (T1) = K

Initial volume (V1) = 650 cm3

Final temperature (T2) = double the original = 2K

Final volume (V2) =..?

Step 2:

Determination of the new volume of the gas.

The new volume of the gas can be obtained by using Charles' law as follow:

V1/T1 = V2/T2

650/K = V2/2K

Cross multiply

K x V2 = 650 x 2K

Divide both side by K

V2 = 650 x 2K /K

V2 = 650 x 2

V2 = 1300cm3.

Therefore, the new volume of the gas is 1300cm3

The new volume of the gas is 1300cm³.

Given:

Initial temperature (T₁) = K

Initial volume (V₁) = 650 cm3

Final temperature (T₂) = double the original = 2K

To find:

Final volume (V₂) =?

Determination of new volume:

V₁/T₁ = V₂/T₂

650/K = V₂/2K

K x V₂ = 650 x 2K

V₂ = 650 x 2K /K

V₂ = 650 x 2

V₂ = 1300cm³

Therefore, the new volume of the gas is 1300cm³.

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Answer:

This means that the wave is bigger because amplitude is the hight of the crest of the wave!

Explanation:

SO IT MEANS THE WAVE IS BIGGER AND TALLER :D

Answer:

a) 1.6

f)7.51

b)3.9

g)9.2

c)3.1

h)41.9

d)1.959

i)0.29

e)5.2

j)1.112

Explanation:

When you are multiplying or dividing the numbers you take the least amount of significant figures and that's how many significant figures your answer will be. Instead of being a super long answer. Hope this helps. Also, sorry it took me a hot minute :)

0.0113 mol Ba(ClO₃)₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structures

Step 1: Define

3.45 g Ba(ClO₃)₂

Step 2: Identify Conversions

Molar Mass of Ba - 137.33 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Ba(ClO₃)₂ - 137.33 + 2(35.45) + 6(16.00) = 304.33 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.011336 mol Ba(ClO₃)₂ ≈ 0.0113 mol Ba(ClO₃)₂

The specific heat of the metal is approximately \(\(0.397 \, \text{J/g°C}\)\). The specific heat capacity of a substance is a measure of how much heat energy is required to raise the temperature of a given amount of the substance by 1 degree Celsius.

In this case, we can use the principle of conservation of energy to determine the specific heat of the metal. First, we need to calculate the heat absorbed by the water in the calorimeter. We can use the equation:

\(\(q_{\text{water}} = m_{\text{water}} \cdot c_{\text{water}} \cdot \Delta T_{\text{water}}\),\)

where \(\(m_{\text{water}}\)\) is the mass of the water, \(\(c_{\text{water}}\)\) is the specific heat of water, and \(\(\Delta T_{\text{water}}\)\) is the change in temperature of the water.

Plugging in the given values, we find:

\(\(q_{\text{water}} = 100.0 \, \text{g} \cdot 4.184 \, \text{J/g°C} \cdot (25.4 - 21.6) \, \text{°C} = 1586.88 \, \text{J}\).\)

Next, we can calculate the heat lost by the metal, which is equal to the heat gained by the water:

\(\(q_{\text{metal}} = -q_{\text{water}}\).\)

Using the equation for heat transfer, \(\(q = m \cdot c \cdot \Delta T\)\), we can rearrange it to solve for the specific heat of the metal, \(\(c_{\text{metal}}\)\):

\(\(c_{\text{metal}} = \frac{{q_{\text{metal}}}}{{m_{\text{metal}} \cdot \Delta T_{\text{metal}}}}\).\)

Plugging in the given values, we find:

\(\(c_{\text{metal}} = \frac{{-1586.88 \, \text{J}}}{{58.6 \, \text{g} \cdot (25.4 - 95.2) \, \text{°C}}} \approx 0.397 \, \text{J/g°C}\).\)

Therefore, the specific heat of the metal is approximately \(\(0.397 \, \text{J/g°C}\)\).

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The substance that is a strong electrolyte in an aqueous solution is KI.

Strong electrolytes are substances that completely dissociate into ions when dissolved in water, resulting in a solution that can conduct electricity well.

KI is an ionic compound, meaning it is made up of a metal (potassium) and a nonmetal (iodide) that are held together by ionic bonds. When KI is dissolved in water, it dissociates into its ions (K+ and I-), which allows the solution to conduct electricity effectively.

The other options are, b. C2H6 (ethane), c. C6H6 (benzene), d. C8H18 (octane), and e. CCl4 (carbon tetrachloride), are all non-electrolytes or weak electrolytes, as they do not dissociate into ions when dissolved in water, and their solutions cannot conduct electricity well.

These substances are composed of nonmetal atoms and are held together by covalent bonds.

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The following statement is true about the given reaction:The statement that is true about the given reaction is:"51g of water is produced for every mole of Na3C6H5O7.

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The first stage of a lunar eclipse:

Penumbral eclipse.

There are 7 stages of a total lunar eclipse. The first one is when the Penumbral eclipse begins. his begins when the penumbral part of Earth's shadow starts moving over the Moon. This phase is usually not feasible to be seen with the naked eye.

The equilibrium constant, K, is a value that indicates the extent to which a reaction will proceed towards products at equilibrium.

If the value of K is greater than 1, it means that the products are favored at equilibrium, indicating that the reaction will proceed more towards products. On the other hand, if the value of K is less than 1, it means that the reactants are favored at equilibrium, indicating that the reaction will proceed more towards reactants.
To determine whether the value of K is greater than 1 or less than 1 for a specific reaction, we need to look at the balanced chemical equation for the reaction and calculate the equilibrium constant using the concentrations or pressures of the reactants and products at equilibrium. Without knowing the specific reaction, we cannot provide a definitive answer.

To determine if the value of the equilibrium constant, K, for the reaction is greater than 1 or less than 1, you need to consider the relationship between the concentrations of products and reactants at equilibrium. The equilibrium constant, K, is defined as the ratio of the concentrations of products to the concentrations of reactants, raised to the power of their respective stoichiometric coefficients.
If K > 1, it indicates that the concentration of products is greater than the concentration of reactants at equilibrium, meaning the reaction favors the formation of products.
If K < 1, it indicates that the concentration of reactants is greater than the concentration of products at equilibrium, meaning the reaction favors the formation of reactants.
In order to justify the value of K for the given reaction, you would need the equilibrium concentrations of the products and reactants or other information that allows you to determine the ratio of product concentrations to reactant concentrations at equilibrium.

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The products of the hydration reaction of 1.6000 grams of norbornene are norborneol and water.

Norbornene undergoes hydration, where water adds across the double bond to form norborneol. The balanced equation for the reaction is not provided, so we assume a 1:1 stoichiometry between norbornene and norborneol.

Given that the molar mass of norbornene is 112.17 g/mol, we can calculate the number of moles of norbornene: moles of norbornene = mass / molar mass = 1.6000 g / 112.17 g/mol ≈ 0.0143 mol.

Since we assume a 1:1 stoichiometry, the number of moles of norborneol produced will also be 0.0143 mol.

Therefore, the products of the hydration reaction of 1.6000 grams of norbornene are approximately 0.0143 moles of norborneol and an equivalent amount of water.

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Answer:

It is approximately equal to the number of protons and neutrons, with a little extra added by the electrons.

Explanation:

Answer:

Number of moles of oxygen = 0.037  mol

Explanation:

Given data:

Total pressure = 98.5 KPa

Partial pressure of nitrogen = 22.0 KPa

Partial pressure of argon = 50.0 KPa

Volume = 3.5 L

Temperature = 25°C (25+273= 298K)

Number of moles of oxygen = ?

Solution:

Total pressure = P(N₂) + P(O₂) + P(Ar)

98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa

98.5 KPa = 72.0 KPa +P(O₂)

P(O₂)  = 98.5 KPa - 72.0 KPa

P(O₂)  = 26.5 KPa

KPa to atm:

26.5 KPa/ 101 = 0.262 atm

Number of moles of oxygen:

PV = nRT

n = PV/RT

n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K  × 298 K

n = 0.917atm.L /24.47atm.L/ mol

n = 0.037  mol

Answer:

It equals 826

Explanation:

Cos that's ur moms weight in pounds

Answer: yes they are

Explanation:

because its so hot and the heat just stays at the bottom

Answer:

DENSITY

Density is defined as mass per unit volume.

d =  

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =  m V  =  433 g 200 c m ³  = 2.16 g/cm³

MASS

d =  m V

We can rearrange this to get the expression for the mass.

m = d×V

Example: If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×  

1.11

g

1

m

L

= 555 g

VOLUME

d =  

m

V

We can rearrange this to get the expression for the volume.

V =  

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×  

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =  

m

d

= 14 830 g ×  

1

c

m

³

19.32

g

= 767.6 cm³

Explanation:

Whenever an electron inside a hydrogen atom transitions from the n-2 towards the n-1 energy level, an ultraviolet kind of photon is released.

The negatively charged neutron star called an electron can either be free or attached to an atom (not bound). One of the three main types of particles in an atom is an electron that is attached to it; the other two were protons and neutrons.

The negatively charged components of an atom are called electrons. All of an atom's electrons combine to form a negatively charged that counteracts that positive charge of a protons inside the atomic nucleus. Compared to all the other components of the universe, electrons are incredibly tiny.

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Hence, the probability that the mean cholesterol level of the sample will be greater than 217 is 0.034. Answer: 0.034.According to the given statement, we have the following data.

mean (μ) = 205 mg/dLstandard deviation

(σ) = 35 mg/dLsample size

(n) = 46(a) Probability that the mean cholesterol level of the sample will be no more than 205.To find this, we will use the z-score formula.z

= (x - μ) / (σ/√n)Here,

x = 205

μ = 205

σ =

35n

= 46Plugging in these values, we get,

z = (205 - 205) / (35/√46)

z = 0Hence, the probability that the mean cholesterol level of the sample will be no more than 205 is 0.5. Answer: 0.5

(b) Probability that the mean cholesterol level of the sample will be between 200 and 210:

To find this, we need to standardize the values and use the z-table.P(z < (210 - 205) / (35/√46)) - P(z < (200 - 205) / (35/√46))P(z < 1.65) - P(z < -1.65) = 0.4495 - 0.0505

= 0.3990Hence, the probability that the mean cholesterol level of the sample will be between 200 and 210 is 0.3990. Answer: 0.3990

(c) Probability that the mean cholesterol level of the sample will be less than 195: To find this, we need to standardize the values and use the z-table.P(z < (195 - 205) / (35/√46))P(z < -2.91) = 0.002Hence, the probability that the mean cholesterol level of the sample will be less than 195 is 0.002. Answer: 0.002

(d) Probability that the mean cholesterol level of the sample will be greater than 217: To find this, we need to standardize the values and use the z-table.P(z > (217 - 205) / (35/√46))P(z > 1.82) = 0.034 Answer: 0.034.

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If the experiment is repeated at the pH 11 level, the enzyme activity will be less than at the pH 9 level.

We can arrive at this answer because:

In this case, we can say that if the experiment is repeated at pH 11, the enzyme activity level will be even lower, since from pH 5 onwards, as the pH rises, the enzyme activity goes down.

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Answer:

180g

Explanation:

So, 10 mole of water will weigh (18x10) = 180g.