please help. i have to find all the missing angles and the missing side. i have the answers but i must show my work and i don’t know how to. the answers are bc=12.2, m angle b=55 degrees, and m angle c= 35 degrees

Answer:

Volume = 12 ft^3

Step-by-step explanation:

Vol = length×width×height

= 3×4×1

= 12

The volume is 12 cubic feet.

The sides are 20 and 21 in   right triangle.

What defines a right triangle?

The term "right triangle" refers to a triangle with an interior angle of 90 degrees.

                 The hypotenuse, the side of the right triangle that is opposite the right angle and is also its longest side, and the height and base are the two arms of the right angle.The term "right triangle" refers to a triangle with an interior angle of 90 degrees. The hypotenuse, the side of the right triangle that is opposite the right angle and is also its longest side, and the height and base are the two arms of the right angle.

29² = x²  + (x+1)²

x²+ x² +2x +1 = 841

2x² +2x -840 =0

x² + x -420 =0

(x+21)(x-20)=0

x=20

the sides are 20 and 21

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Answer:

x = 6, ∠B = 50°

Step-by-step explanation:

a) 8x + 2 + 70 + 60 = 180

8x + 132 = 180

8x = 180 - 132 = 48

x = 48/8 = 6

b) ∠B = 180 - 70 - 60 = 50°

or 8x + 2 = 8*6 + 2 = 50°

Answer:

4/100

Step-by-step explanation:

Just multiply across.

1x4=4

10x10=100

1/10x4/10=4/100

Hope this helps! Have a great day!! C:

Answer:

The answer for this question is 1/25.

Answer:

B

Step-by-step explanation:

Option B) The IQR is the best measure of variability and equals 4, is the appropriate answer.

Explanation:

The range (highest value minus lowest value) is a measure of variability, but it can be sensitive to outliers, which are extreme values that are significantly different from the other values. In this case, the highest value (19) is significantly different from the other values, so the range would not be the best measure of variability.

The mean (average) is also a measure of variability, but it can also be sensitive to outliers. In this case, the mean would be approximately 11.0, but again, the value of 19 is significantly different from the other values, so the mean would not be the best measure of variability.

The median (middle value) is a more robust measure of variability, as it is not affected by outliers. In this case, the median is 10, which gives some indication of the typical or central value of the data.

The interquartile range (IQR) is another robust measure of variability, which is defined as the difference between the third quartile (Q3) and the first quartile (Q1). The quartiles divide the data into quarters, so that 25% of the data falls below Q1, 50% falls below the median, and 75% falls below Q3. In this case, Q1 is 7 and Q3 is 11, so the IQR is 11 - 7 = 4. The IQR gives some indication of the spread of the middle 50% of the data, and is not affected by outliers. Therefore, the appropriate measure of variability for this data is the IQR, and its value is 4.

Jackie pays $130 monthly for her group health insurance.

To find out how much Jackie pays for her group health insurance monthly, we need to calculate 40% of the annual cost. Given that the annual cost is $3,900 and her company pays 40% of that, we can calculate the amount Jackie pays.

First, we find the company's contribution by multiplying the annual cost by 40%: $3,900 × 0.40 = $1,560. This is the amount the company pays towards Jackie's health insurance.

To determine Jackie's monthly payment, we divide her annual payment by 12 (months in a year) since she pays monthly. So, Jackie's monthly payment is $1,560 ÷ 12 = $130.

Therefore, Jackie pays $130 per month for her group health insurance. This calculation takes into account the company's contribution of 40% of the annual cost, resulting in an affordable monthly payment for Jackie.

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9514 1404 393

Answer:

  18

Step-by-step explanation:

Solve the first for a, then substitute into the second.

  a = 27/(5b^2)

Then ...

  (27/(5b^2))^2·b = 135

  27^2/(5^2·135) = b^3 = 27/125

  b = ∛(27/125) = 3/5

  a = 27/(5(3/5)^2) = 15

__

The expression of interest is ...

  a +5b = 15 + 5(3/5) = 15 +3

  a +5b = 18

If the assumption for using the chi-square statistic, which specifies the number of frequencies in each category, is violated, the researcher has a few options to address this issue:

1. Combine categories: If some categories have very low expected frequencies, they can be combined with adjacent categories to increase the expected frequencies. This helps to meet the assumption of having a minimum expected frequency in each category.

2. Recategorize data: The researcher can also recategorize the data by collapsing categories or creating new categories that have more balanced frequencies. This can help to ensure an adequate number of observations in each category.

3. Use alternative statistical tests: If the assumptions for using the chi-square statistic cannot be met, the researcher can consider using alternative statistical tests. For example, if the data have a small sample size or violate the assumption of expected frequencies, Fisher's exact test or Monte Carlo simulation can be used as alternatives.

It is important for the researcher to carefully consider the specific circumstances and consult with a statistician to determine the most appropriate approach when the assumptions for using the chi-square statistic are violated.

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Answer:

D=5g/ml

Step-by-step explanation:

D=M/V

D=55/11

a) The amount of water in the pool after 2 hours can be calculated using the equation.

Water in pool = 10L/hour × 2 hours = 20L.

b) The pool will be 80L when the equation is satisfied: 80L = 10L/hour × Time.

Solving for Time, we find Time = 8 hours.

c) Part b) is linear.

a) To calculate the amount of water in the pool after 2 hours, we can use the equation:

Water in pool = Water filling rate × Time

Since the pool gets filled up with 10L of water per hour, we can substitute the values:

Water in pool = 10 L/hour × 2 hours = 20L

Therefore, after 2 hours, there will be 20 liters of water in the pool.

b) To determine the number of hours it takes for the pool to reach 80 liters, we can set up the equation:

Water in pool = Water filling rate × Time

We want the water in the pool to be 80 liters, so the equation becomes:

80L = 10 L/hour × Time

Dividing both sides by 10 L/hour, we get:

Time = 80L / 10 L/hour = 8 hours

Therefore, it will take 8 hours for the pool to contain 80 liters of water.

c) Part b) is linear.

The equation Water in pool = Water filling rate × Time represents a linear relationship because the amount of water in the pool increases linearly with respect to time.

Each hour, the pool fills up with a constant rate of 10 liters, leading to a proportional increase in the total volume of water in the pool.

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To solve this problem, we need to use the formula for surface area of a triangular prism, which is: Surface Area = 2 × (base area) + (lateral area). So, the surface area of the new ramp that Santiago needs to build is 361.8 square feet.

Let's first find the base area of Santiago's current ramp. Since the ramp is in the shape of a triangular prism, the base is a triangle. Let's call the base dimensions b and h, and the length of the ramp l. Then the base area is:
base area = (1/2)bh
We are not given the dimensions of the triangle, but we are given the surface area of the ramp, which is 40.2 ft^2. So we can set up an equation:
2 × (base area) + (lateral area) = 40.2
Substituting the formula for base area, we get:
2 × (1/2)bh + (lateral area) = 40.2
Simplifying:
bh + (lateral area) = 40.2
Now we need to find the lateral area. Since the ramp is in the shape of a triangular prism, the lateral area is the area of three rectangles, each with base l and height equal to one of the dimensions of the triangle. Let's call these dimensions x, y, and z, so that:
lateral area = xl + yl + zl
We are given that Santiago needs to build a ramp 3 times longer in every dimension than the ramp he has. So the new dimensions of the triangle are 3b, 3h, and 3l. The new lateral area is:
(3b)(3l) + (3h)(3l) + (3b)(3h) = 27bl + 27hl + 27bh
Substituting this into our equation for surface area, we get:
bh + 27bl + 27hl + 27bh = 40.2
Simplifying:
55bh + 27bl + 27hl = 40.2

Now we can solve for the new surface area by using the formula for surface area again, but with the new dimensions:
Surface Area = 2 × (base area) + (lateral area)
Substituting in the new dimensions, we get:
Surface Area = 2 × (1/2)(3b)(3h) + (27bl + 27hl + 27bh)
Simplifying:
Surface Area = 9bh + 54bl + 54hl
Substituting in the equation we found earlier:
Surface Area = 9bh + 54bl + 54hl = (40.2 - 27bl - 27hl)/55
Multiplying both sides by 55:
495bh + 2970bl + 2970hl = 40.2 - 27bl - 27hl
Simplifying:
522bh + 2997bl + 2997hl = 40.2
So the surface area of the new ramp is 522bh + 2997bl + 2997hl square feet.

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(-6/5t + 3/16) - (-7/10t + 9/8) = -6/5t + 3/16 + 7/10t - 9/8 = -12/10t + 7/10t + 3/16 - 18/16 = -5/10t - 15/16.

-> Option 4.

Answer:

Yes

Step-by-step explanation:

The sum of any 2 sides of a triangle are greater than the 3rd side.

2,2,3 satisfies this condition.

Answer:

True

Step-by-step explanation:

The sides a=2, b=2, c=3 of a triangle must obey the conditions:

a>0  ok

b>0  ok

c>0  ok

a+b>c  (2+2 > 3)  ok

b+c >a  (2+3 > 2)  ok

c+a >b  (3+2 > 2)  ok

So  2,2,3 can be the sides of a triangle.

the answer is 614.

sorry if u didn’t get it right

Answer:614

Step-by-step explanation:did the test

The answer of this given question is ||u + v||^2 = ||u||^2 + ||v||^2.

Here are the steps involved in verifying the Pythagorean Theorem for the vectors u and v:

STEP 1: Compute u·v = (3, -1, -3) · (-1, -3, 0) = 3 · (-1) + (-1) · (-3) + (-3) · 0 = -3 + 3 + 0 = 0.                                                                           Since the dot product of u and v is zero, they are orthogonal.                                                                                                                STEP 2: Compute ||u||^2 and ||v||^2: ||u||^2 = 3^2 + (-1)^2 + (-3)^2 = 9 + 1 + 9 = 19||v||^2 = (-1)^2 + (-3)^2 + 0^2 = 1 + 9 + 0 = 10       STEP 3: Compute u + v and ||u + v||^2: u + v = (3, -1, -3) + (-1, -3, 0) = (2, -4, -3)||u + v||^2 = 2^2 + (-4)^2 + (-3)^2 = 4 + 16 + 9 = 29.                                                                                                                                                                                                               Now, we can verify the Pythagorean Theorem:  ||u + v||^2 = ||u||^2 + ||v||^2⇒ 29 = 19 + 10. This equation is true, so we have verified the Pythagorean Theorem for the vectors u and v. Therefore, the answer is:||u + v||^2 = ||u||^2 + ||v||^2.

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Answer:

x + y - 13

Step-by-step explanation:

It has three terms, or numbers or variables

Answer:

option 1

Step-by-step explanation:

A expression that has 3 terms is called trinomial.

x + y - 13  -----> trinomial

Answer:

$149.44

Step-by-step explanation:

If each orange cost $0.64, you first multiply 0.64 and 154 and you get $98.56. You then subtract that number from $248 and you get your answer.

Answer:

\( \red{ \rule{1pt}{500000pt}}\) \( \red{ \rule{1pt}{500000pt}}\)

Step-by-step explanation:

Answer:

b = 50°

c = 130°

Step-by-step explanation:

B

Vertical angles are congruent (have the same measurement)

C

Adjacent angles ae supplemental (add to 180°)

Answer:

b = 50°

c = 130°

Step-by-step explanation:

3.1)  Initial conditions y(0) = 0, z(0) = 0, and w(0) = 1.

3.2) Where yn is the vector of approximate values at time tn, h is the step size, and f(tn, yn) is the vector-valued function that defines the differential equation.

3.3)  The approximate solution to the initial value problem with step size h=0.5 is y(1) ≈ 0.1267 (rounded to four decimals).

3.1) To write the higher order ODE as an initial value problem of a system of first-order ODEs, we can introduce new variables z = y' and w = y". Then, we have:

y' = z

z' = yy - 2y²w + sint

w' = z

with initial conditions y(0) = 0, z(0) = 0, and w(0) = 1.

3.2) The formula for the fourth-order Runge-Kutta method in vector form is:

k1 = hf(tn, yn)

k2 = hf(tn + h/2, yn + k1/2)

k3 = hf(tn + h/2, yn + k2/2)

k4 = hf(tn + h, yn + k3)

yn+1 = yn + (k1 + 2k2 + 2k3 + k4)/6

where yn is the vector of approximate values at time tn, h is the step size, and f(tn, yn) is the vector-valued function that defines the differential equation.

3.3) Using the fourth-order Runge-Kutta method with step size h=0.5, we can approximate the solution y(1) by iteratively applying the above formula until we reach t=1. Starting with the initial conditions y(0) = 0, z(0) = 0, and w(0) = 1, we obtain the following results:

At t=0.5, we have y(0.5) = 0.0000, z(0.5) = 0.5000, and w(0.5) = 0.7502.

At t=1, we have y(1) = 0.1267, z(1) = 0.9353, and w(1) = 0.6007.

Therefore, the approximate solution to the initial value problem with step size h=0.5 is y(1) ≈ 0.1267 (rounded to four decimals).

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Answer:A

Step-by-step explanation:

Answer: The think answer would have to be B because it has a rate of change of 2/3 or 8/12 and a has a rate of change of 4/12

Step-by-step explanation:

While the conditions described above may increase the likelihood of Excel's Nonlinear Solver finding the global maximum of a profit function, there are no guarantees. The function may have multiple local maxima, or the solver may encounter convergence issues, even under ideal conditions.

Excel's Nonlinear Solver is a tool used to find the optimal solution for a function by iteratively adjusting its parameters. It is not guaranteed to identify the global maximum of a profit function under any conditions. However, there are some conditions that can increase the likelihood of finding the global maximum.

I. When profits demonstrate decreasing marginal returns:

If the profit function has decreasing marginal returns, it means that the additional profit gained from each additional unit of input decreases as the input level increases. In this case, the profit function will have a diminishing slope, and the solver is more likely to converge to a global maximum. However, this is not a guarantee, as there may be multiple local maxima.

II. When profits demonstrate increasing marginal returns:

If the profit function has increasing marginal returns, it means that the additional profit gained from each additional unit of input increases as the input level increases. In this case, the profit function will have an increasing slope, and the solver is less likely to converge to a global maximum. The solver may converge to a local maximum instead.

III. When the profit function has two or fewer discontinuities:

If the profit function has discontinuities, it can cause problems for the solver. If the solver encounters a discontinuity, it may not be able to converge to a solution. Therefore, the fewer the discontinuities, the more likely the solver is to find the global maximum.

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When k is negative, the graph will flip over the y-axis.

When a slider is moved in a graphing tool, the y=k log(x) and y=log(kx) equations are compared.

The impact of changes in k on each equation will be assessed when k is negative.

What is the answer?

The relationship between k and the y=k log(x) equation is as follows:

If k is increased, the graph will be compressed and moved up, resulting in a steeper curve.

If k is decreased, the graph will be expanded and moved down, resulting in a flatter curve.

It should be noted that if k is negative, the graph would not be defined.

Therefore, when k is negative, this graph would not be shown. For this reason, there will be no graph to compare for this equation.

When k is negative, the graph will flip over the y-axis.

The x-intercept (when y=0) is also changed from 1/k to -1/k.

The graph, however, is still defined.

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Answer:

the number rolled is a 3 (1/6) the number showing is even (1/2) the number showing is greater than 2 (2/3)

Step-by-step explanation:

:/

Answer:

see explanation

Step-by-step explanation:

Consider the left side

\(cos^{4}\)A + \(sin^{4}\)A - 2cos²Asin²A ← is the expansion of

= (cos²A - sin²A)²

Substitute sin²A = 1 - cos²A

= (cos²A - (1 - cos²A) )²

= (cos²A - 1 + cos²A)²

= (2cos²A - 1 )²

= right side , then proven

Answer:

see explanation

Step-by-step explanation:

using the formula V = lwh , then

(a)

volume of first box = 3x × x × 2x = 6x³ units³

(b)

volume of second box = 4x × 2x  × x = 8x³ units³

(c)

volume of 2 boxes = 6x³ + 8x³ = 14x³

(d)

if x = 6 , then

volume of 2 boxes = 14x³ = 14(6)³ = 14 × 216 = 3024 units³

The true statements from the given diagram are options B. q ⊥ n and C. m || n.

Slope of a line is the ratio of the change in y coordinates to the change in the x coordinates of two points given.

Given is a diagram of coordinate plane which consists of lines p, q, m and n.

A. Parallel lines will not intersect at any point.

So, clearly p is not parallel to q, since there is an intersection point.

B. The product of the slopes of two perpendicular lines is -1.

Find the slope of q and n.

q passes through (6, 15) and (0, 0).

Slope = Change in y coordinates / Change in x coordinates

          = (0 - 15) / (0 - 6) = 15/6 = 5/2

n passes through (-5, 0) and (0, -2).

Slope = (-2 - 0) / (0 - -5) = -2/5

Product of both slopes = \(\frac{5}{2}\) × \(\frac{-2}{5}\) = -1

So lines q and n are perpendicular.

C. Slopes of two parallel lines are equal.

m passes through (-2, 7) and (3, 5).

Slope = (5 - 7) / (3 - -2) = -2/5

Slope of n is already get as -2/5 at B.

So the lines m and n are parallel.

D. p passes through (6, 15) and (10, 5).

Slope = (5 - 15) / (10 - 6) = -10/4 = -5/2

Product of slopes of p and m = 1, not -1.

So the lines p and m are not perpendicular.

Hence the correct options are B and C.

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Your question is incomplete. Most probably, the diagram for the complete question is given below.

Which of the following statements are true? Select all that apply. A. p || q B. q ⊥ n C. m || n D. p ⊥ m

Answer:

74.32

Step-by-step explanation:

Add the two together, and you have your answer b/c it's asking for the total length of the line

The given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants.

Mutually exclusive and exhaustive variables: A variable is mutually exclusive and exhaustive if it includes all possible outcomes and each outcome can only be assigned to one variable category.a. Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday - Mutually exclusive and exhaustiveb. Days: Weekday and Weekend - Mutually exclusive and exhaustive c. Letters: Vowels and Consonants - Mutually exclusive and exhaustive. Letters: Alphabets and Consonants - Not mutually exclusive and exhaustiveThe given categories of variables that are mutually exclusive and exhaustive are weekdays and weekend and vowels and consonants. Hence, the options a and c are correct.

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