a hydraulic lift (jack) has two pistons, one large and one small. the pistons are at the same elevation. if it is equilibrium, which piston exerts the greatest force

Answer:

The correct answer is - 93.24×10^4 kg/m^3.

Explanation:

Given:

height of cylinder: 50.5 mm

diameter = 52.0

then radius will be diameter/2 = 52/2 = 26

Formula:

Density = mass/ volume

Volume = πr^2h

solution:

Now the volume of a cylinder is v = (22/7)×r^2×h

= 22/7×26×26×50.5

= 107261.59 mm^3  

Now volume in cubic meter V =10.7261 ×10^(-5) m^3

So density d = m/V = 1/(10.7261 ×10^(-5))

Or d = 93.24×10^4 kg/m^3

When a person increases their activity level to gain muscle mass, their nutritional needs change.

The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.

Individual variations exist, so seeking personalized guidance from a professional is recommended.

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Time it takes energy to pass through radiative zone is :  A) 8 minutes

Energy generated in the core of the Sun takes about 8 minutes to pass through radiative zone and reach the top of convective zone. The radiative zone is a layer of the Sun that lies just outside the core and it is characterized by high density and high temperature.

In this zone, energy is transported by photons that bounce around between atoms and ions that make up the plasma of the Sun. This process is known as radiative diffusion and is relatively slow compared to convective transport of energy that takes place in the outer layers of Sun.

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Answer:

A

Explanation:

This experiment did not occur in a closed system

The increase in speed was due to the kinetic energy from one cart transferring to the other. Option (c) is correct.

The system's overall momentum is conserved in this collision situation, but the system's kinetic energy may not be. Kinetic energy may be exchanged between the two carts during the collision. In this scenario, the cart moving 3 m/s to the right gets kinetic energy, whereas the cart moving 2 m/s to the left loses kinetic energy.

According to the principle of momentum conservation, the total amount of momentum before and after a collision is equal. Prior to the collision, the carts have identical masses and opposing velocities, thus their momenta cancel each other out. Even though the momentum is preserved after the impact, it is redistributed across the two carts, causing them to move at various speeds.

Hence, the increase in speed was due to the kinetic energy

from one cart transferring to the other. Option (c) is correct.

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Answer:

The vehicle has a 2000kg mass.

Take a mass's acceleration into account. Use the formula F = m a to determine the force's value. Kilogram-meter/second-squared will be used as the unit of force. The short name for this unit, which is made up of the three basic SI units, is newton.

F= ma

m= F/a

m= 50000/25

m= 2000 kg

According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. The force that propels you forward on your bicycle comes from your leg muscles.

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Answer: All UV can have harmful effects on biological matter (such as causing cancers) with the highest energies causing the most damage.

Explanation:

The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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43.8 m

Explanation:

The only force acting on the car is the frictional force f and since friction is a force that is always directed opposite to the direction of motion, it will have a negative sign. Therefore, we can write Newton's 2nd law as

\(x:\;\;\;\;F_{net} = -f = -\mu N = ma\) (1)

\(y:\;\;\;\;F_{net} = N - mg = 0\) (2)

Substituting Eqn(2) into Eqn(1), we get

\(\Rightarrow a = -\mu g\) (3)

To find the stopping distance x, we are going to use the equation

\(v^2 = v_0^2 + 2ax\)

Initially, the car was moving at \(v_0 = 27\:\text{m/s}.\) When it stopped, its final velocity \(v\) is zero. Using these, as well as Eqn(3) on the equation for v^2, we find that

\(0 = v_0^2 + 2(-\mu g)x \Rightarrow 0 = v_0^2 - 2\mu gx\)

or solving for x,

\(x = \dfrac{v_0^2}{2\mu g} = \dfrac{(27\:\text{m/s})^2}{2(0.85)(9.8\:\text{m/s}^2)}\)

\(\:\:\:\:= 43.8\:\text{m}\)

Answer:

Speed of a child on the rim is 4.25 m/s.

Explanation:

Given;

diameter of the merry-go-round, d = 5.0 m

period of the motion, t = 3.7 s

one complete rotation of the merry-go-round = πd

one complete rotation of the merry-go-round = π(5) = 15.71 m

Speed is given as distance / time

speed of a child on the rim = 15.71 / 3.7

speed of a child on the rim = 4.25 m/s

Therefore, speed of a child on the rim is 4.25 m/s.

Answer:

PRETTY sure its b

Explanation:

Answer:

66.6N

Explanation:

Step one;

given data

the mass of the lamp = 200N

we are told that it is suspended by 3 cables.

Now we know that the weight will be distributed equally on the cables

Step two:

so, let the tension in each cable be T

T+T+T= 200

3T=200

T=200/3

T=66.6N

The tenion on each cable is 66.6N

ANSWER

661.61 kg/m³

EXPLANATION

Given:

• The mass of the mine, m = 190 kg

• The volume of the mine, V = 1.150 m³

• The tension in the chain, T = 5.6x10³ N = 5600 N

Find:

• The density of the fluid, ρ

Let's draw a free-body diagram of this situation first,

If the forces are in equilibrium,

The buoyant force is given by the equation,

Where ρ is the density of the fluid, and V is the submerged volume - in this case, the volume of the mine. We know the magnitude of the tension in the chain and the weight of the mine is,

Replace in the first equation,

Solving for ρ,

Replace with the known values and use g = 9.81 m/s²,

Hence, the density of the fluid the mine is in is 661.61 kg/m³.

Answer:

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

V = 29.49 m/s

Explanation:

Given that,

The mass of a car,\(m_c=2100\ kg\)

The mass of a motorcycle, \(m_m=290\ kg\)

The initial velocity of the car,\(v_c=30i-10j\)

\(|v_c|=\sqrt{30^2+(-10)^2} =31.62\ m/s\)

The initial velocity of the motorcycle,\(v_m=10i+10j\)

\(|v_m|=\sqrt{10^2+10^2} =14.14\ m/s\)

As they stick together. Let V is the speed. So, using the conservation of momentum,

\(m_cv_c+m_mv_m=(m_c+m_m)V\\\\V=\dfrac{m_cv_c+m_mv_m}{(m_c+m_m)}\\\\V=\dfrac{2100\times 31.62+290\times 14.14}{(2100+290)}\\\\V=29.49\ m/s\)

So, the velocity of the stuck together car and the motorcycle after the collision is 29.49 m/s.

The kinetic energy of the block after 6 seconds would be 6,840 J.

The acceleration of the block can be determined using Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration. In this case, the net force is the horizontal force of 80 N, and the mass of the block is 18 kg. Therefore:

F_net = m * a

80 N = 18 kg * a

a = 80 N / 18 kg

a = 4.44 m/s^2

After 6 seconds, the velocity of the block can be determined using the kinematic equation:

v = v_0 + a*t

where v_0 is the initial velocity (which is zero in this case), a is the acceleration, and t is the time.

v = 0 + 4.44 m/s^2 * 6 s

v = 26.64 m/s

The kinetic energy of the block can be calculated using the equation:

KE = (1/2) * m * v^2

where m is the mass of the block and v is its velocity.

KE = (1/2) * 18 kg * (26.64 m/s)^2

KE = 6,840.17 J

Therefore, the kinetic energy of the block after 6 seconds is approximately 6,840 J.

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The see-saw must be balanced by adding a 20N weight to point A.

The gravitational force increases with b. You need a counterbalancing force on the opposite side to bring the beam back into balance. One option is to put a second person on the opposite side of the beam who is the same weight. The seesaw is balanced once the downward pressure is the same on both sides of the beam.

T = F x d

We are given the following information:

A = 20m (distance from point A to the fulcrum)

B = 10m (distance from point B to the fulcrum)

F = 50N (force acting at point B)

Let's start by calculating the torque on the right side of the fulcrum (point B):

T(right) = F x d

T(right) = 50N x 10m

T(right) = 500 Nm

T(left) = F x d

500 Nm = F x 20m

F = 20N

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The electron is a subatomic particle whose electric charge is poor one fundamental price. Electrons belong to the first generation of the lepton particle own family, and are usually concept to be fundamental particles because they have no recognized additives or substructure.

2. The charge on the comb is   -1.6 x 10^-16 C

charge on an electron = -1.6 x 10^-19 C

Number of electron = 1000

total charge =  -1.6 x 10^-19 C x 1000

                   =  -1.6 x 10^-16 C

3. electrons are found in the charged particle is  3000 electrons.

total charge = 4.8 x 10^-16 C

q = ne

n = q/e

n = 4.8 x 10^-16 C / -1.6 x 10^-19 C

  = 3000 electrons

4. q = ne

 n =  5.0 x 10^21 electrons.

q = 5.0 x 10^21 × 1.6 x 10^-19 C

   = 8 x 1000 C

Since 6.25 x 10^18 electrons carry 1C of charge

  5.0 x 10^21 electrons. carry = 1 C

1 electron = 1 C / 6.25 x 10^18

5.0 x 10^21 = (1 C / 6.25 x 10^18)

Total charge =  (1 C / 6.25 x 10^18) x 5.0 x 10^21

                      = 800 C

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The equation of the path of a projectile is y = x(1 - x). Projectile motion is the movement of an object in a parabolic trajectory as a result of being propelled or released under the influence of gravity. A projectile, in simple terms, is any object that is launched into the air, such as a bullet, a baseball, or a rock. It's important to note that the parabolic trajectory is due to the force of gravity acting on the object.

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Answer:

Explanation:

Isaac Newton argued that the geometric nature of reflection and refraction of light could only be explained if light were made of particles, referred to as corpuscles, because waves do not tend to travel in straight lines.

ANSWER:

0.02182 μC

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 1.057 g = 0.001057 kg

Length spring (l) = 5 cm = 0.05 m

spring stretch (x) = 1.932 cm = 0.01932 m

spring stretch + beads (x1) = 0.286 cm = 0.00286 m

The first thing to calculate is the value of the spring constant k, just like this:

When the charged beads are attached in equilibrium, therefore:

The charge of the beads is 0.02182 μC

Answer:

none no work cuz no motion

Explanation:

GOOD LUCK

Answer:

v = 1.98 m / s

Explanation:

Let's analyze this exercise a bit, initially the hanging box is at a height h, which is why it has gravitational power energy, as the system is removing the kinetic energy is zero and just when the box reaches the floor its potential energy has dropped to zero and the three bodies have kinetic energy, also between the box and the horizontal surface there is friction, so there is work. Let's use the relationship between work and energy

starting point. Before starting the movement

         Em₀ = U = m g h

final point. Just before the block hit the floor

         Em_f = K = ½ M v² + ½ I w² + ½ m v²

the speed of the two blocks must be the same to maintain the tension of the rope

The work of the friction force

the friction force opposes the movement so its work is negative

          W = - fr x

the law of equilibrium is the largest block

          N-W = 0

          N = W = Mg

we substitute

         W = - μ M g x

the relationship between the work of the non-conservative force (friction) and the energy is

         W = Em_f - Em₀

        - μ Mg x = ½ M v² + ½ I w² + ½ m v² - mg h

the moment of inertia of a hollow sphere is

         I = ⅔ m_s r²

angular and linear velocity are related

         v = w r

         w = v / r

the distance the horizontal block travels must be the same as the distance the vertical block travels

          x = h

let's substitute

         - μ M g h = ½ (M + m) v² + ½ (⅔ m_s r²) (v/r) ² - m g h

          (- μ M + m) g h = ½ (M + m + ⅔ m_s) v²

          v² = \(\frac{2(\mu \ M + m ) \ g h }{ M +m + \frac{2}{3} m_s}\)

let's calculate

          v² = 2 (-0.15 7.6 +2.4) 9.8 0.61 / (7.6 + 2.4 + 2/3 1.2)

          v = \(\sqrt{\frac{42.32}{ 10.8} }\)

          v = 1.98 m / s

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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Answer:

Please find the answer in the explanation

Explanation:

Given that A 1.0 g plastic bead, with a charge of -6.0 nC, is suspended between the two plates by the force of the electric field between them.

Since it is suspended, it must have been repelled by the bottom negative plate and trying to be attracted to the top plate.

We can therefore conclude that the upper plate, is positively charged

B.) The charge on the positive plate of parallel-plate capacitor is constructed of two horizontal 12.0-cm-diameter circular plates must be less than 6.0 nC

Answer: 0m

Explanation: if you need help with directions just use what I use

N(ever)

W(affles) E(at)

S(oggy)

Try to remember it like how you remembers pemdas, say Never Eat Soggy Waffles

3m east cancels out 3m west

2m north cancels out 2m south

So you’ll remain back where you started once you’re finished

Hope I helped