Answer:
1120 N
Explanation:
The velocity with which he hits the water can be found with kinematics:
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (-9.8 m/s²) (-9.00 m)
v = -13.3 m/s
Or it can be found with conservation of energy.
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × -9.8 m/s² × -9.00 m)
v = -13.3 m/s
Sum of forces on the diver after he hits the water:
∑F = ma
F − mg = m Δv/Δt
F − (74.0 kg) (9.8 m/s²) = (74.0 kg) (0 m/s − (-13.3 m/s)) / (2.50 s)
F = 1120 N
Pitcher's mounds are raised to compensate for the vertical drop of the ball as it travels a horizontal distance of 18 m to the catcher. (a) If a pitch is thrown horizontally with an initial speed of 32 m/s, how far does it drop by the time it reaches the catcher? (b) If the speed of the pitch is increased, does the drop distance increase, decrease, or stay the same? Explain. (c) If this baseball game were to be played on the Moon, would the drop distance increase, decrease, or stay the same? Explain.
For part a).
Horizontally
v=velocity=32 m/s
d=distance=18m
so we use the next formula to calculate the time
\(v=\frac{d}{t}\)we isolate the time
\(t=\frac{d}{v}\)we substitute the data
\(t=\frac{18}{32}=0.56s\)For the drop distance, we use the next formula
\(d=v_it+\frac{1}{2}gt^2\)where vi is the initial velocity, g is the gravity and d is the distance
vi=0 m/s
g=9.8 m/s^2
t=0.56 s
\(d=0(0.56)+\frac{1}{2}(9.8)(0.56)^2=1.54\)b)
drop distance decreases because it will take less time for the baseball to travel to the catcher.
c)
Drop distance would decrease because the gravity is less on the moon and therefore the ball would not fall as fast
5. The rate at which an organism uses energy, measured in humans at complete
rest.
Answer:
n. Abbr. BMR. The rate at which energy is used by an organism at complete rest, measured in humans by the heat given off per unit time, and expressed as the calories released per kilogram of body weight or per square meter of body surface per hour.
Explanation:
The small piston of a hydraulic lift has an area of 15 cm². A car weighing 45,000 N is placed on the 2500 cm² large piston. How much force is required on the small piston to lift the car?
Explanation:
I believe the answer is 12 N
Pluto was first observed in 1930, and its largest moon, Charon, was discovered in 1978. A few years after Charon’s discovery, astronomers were able to observe a series of eclipses as Pluto and Charon passed in front of one another. By studying how the brightness of Pluto and Charon changed as they eclipsed each other, astronomers were able to measure the masses and radii of both Pluto and its moon. What did these measurements imply about the average densities of Pluto and Charon?
Answer:
The average densities of both matches the expected density for objects made from water ice.
Explanation:
Charon's density is 1.2 to 1.3 g / cm3, while Pluto's density is 1.8 to 2.1 g / cm3. This was discovered in many researches and measurements of these two celestial bodies, with the objective of understanding them and promoting efficient scientific knowledge.
With the measurements of the average densities between pluto and Charon it was possible to conclude several statements about them. Firstly, it is possible to see that the two formed independently and at different times, in addition to indicating the existence of few rocks in charon, which is consistent with the average density of objects made mostly of water ice.
What do electrons in the same shell have in common? AThey have the same amount of energy incorrect answer BThey are all positively charged incorrect answer CThey are all made up of atoms incorrect answer DThey all have neutral charges incorrect answer
Answer:
They have the same amount of energy
Explanation:
Electrons are said to be the subatomic particles that move around the nucleus of an atom. These electrons are negatively charged particles that are seen to be quite smaller than the nucleus of an atom.
The electron shells of these atoms are usually being filled from the inside out with the low-energy shells closer to the nucleus being filled before they can go into the much higher-energy shells that are a bit out
The electrons in the same shell have the same amount of energy and the same principal energy level. The correct answer is (A).
An atom's fundamental energy level, commonly referred to as the energy "shell," is the same for electrons in the same shell. The major energy level, which also controls the electron's typical separation from the nucleus, closely correlates to the electron's energy level.
Electrons within the same shell have the same energy level, although they may have different sublevels or orbitals within that shell.
Therefore, The electrons in the same shell have the same amount of energy and the same principal energy level. The correct answer is (A).
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A skater holds her arms outstretched as she spins at 120 rpm. Part A What is the speed of her hands if they are 140 cm apart? Express your answer with the appropriate units
According to the question the speed of the skater's hands is 528 m/min.
To calculate the speed of the skater's hands, we can use the formula:
Speed = Circumference * Revolutions per minute
Given that the skater's hands are 140 cm apart and she spins at 120 rpm, we need to calculate the circumference of the circle formed by her hands.
The circumference of a circle is given by the formula:
Circumference = 2 * π * radius.
In this case, the radius is half the distance between the skater's hands, which is 140 cm / 2 = 70 cm.
Converting the radius to meters, we have 70 cm = 0.7 m.
Now we can calculate the circumference:
Circumference = 2 * π * 0.7 m = 4.4 m (rounded to one decimal place).
Finally, we can calculate the speed of the skater's hands:
Speed = Circumference * Revolutions per minute
= 4.4 m * 120 rpm
= 528 m/min.
Therefore, the speed of the skater's hands is 528 m/min.
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compare concentric and eccentric contractions. concentric contractions occur when the muscle tension exceeds the load, and the muscle shortens. eccentric contractions occur when the muscle tension is less than the load, and the muscle elongates. concentric contractions consist of equal lengths of time contracting and relaxing. eccentric contractions consist of a longer time relaxing than contracting. concentric contractions occur when the tension produced never exceeds the load, and the muscle does not change length. eccentric contractions occur when the tension produced exceeds the load, and the muscle shortens. concentric contractions occur when the muscle tension is less than the load, and the muscle elongates. eccentric contractions occur when the muscle tension exceeds the load, and the muscle shortens. concentric contractions consist of equal lengths of time contracting and relaxing. eccentric contractions consist of a longer time contracting than relaxing.
In incomplete tetanus, the muscle is producing near-peak tension during rapid cycles of contraction and relaxation. Wave summation refers to the addition of one twitch to another.
What are concentric contractions?
A concentric contraction is a type of muscle activation that causes tension in your muscle as it shortens. As your muscle shortens, it generates enough force to move an object. This is the most popular type of muscle contraction. In weight training, a bicep curl is an easy-to-recognize concentric movement.
During incomplete tetanus, the muscle goes through quick cycles of contraction with a short relaxation phase for each. If the stimulus frequency is so high that the relaxation phase disappears completely, contractions become continuous in a process called complete tetanus. If the frequency of action potentials generated increases to such a point that muscle tension has reached its peak and plateaued and no relaxation is observed then the muscle contraction is described as tetanus.
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explain why changes in both enthalpy (δh) and entropy (δs) determine the spontaneity of a process
Both enthalpy (δh) and entropy (δs) changes are because a process is more spontaneous when entropy and enthalpy are increased.
Explain about the enthalpy (δh) and entropy (δs)?The change inside the disorderedness of a reactant to produce the product is defined by the entropy change of such a reaction, S.
If this change is for the better, it means that the reaction made the system more disorganized. The quantity of heat emitted or absorbed by a reaction maintaining constant pressure is defined by its enthalpy change, or H.A type of energy is enthalpy. A property is entropy. It is a way to gauge a molecule's unpredictability. Entropy can be thought of as a rough indicator of the quality of energy, with lower entropy indicating higher quality. Lower entropy energy is stored in an organized manner (the efficient library).Both enthalpy (δh) and entropy (δs) changes are -
Because a process is more spontaneous when entropy and enthalpy are increased.Positive entropy change reactions are advantageous.Positive enthalpy changes in reactions are advantageous.To know more about the enthalpy (δh) and entropy (δs), here
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what does the values 0.5 for the wave
Answer:
1 mm = 0.1 mV; 5 mm = 0.5 mV (or between 2 dark horizontal lines); 10 mm = 1.0 mV. Heart rate ... QRS complex is a series of wave forms following P wave.
Explanation:
Hoped I helped
How do humans depend on geochemical cycles?
A. to provide clean water, breathable air, and soil that is capable of supporting crops.
B. to provide food and oxygen so organisms can survive
C. to help conserve resources for future use
Answer:
A
Explanation:
Because we need clean water to obtain a healthy diet, need oxygen which plants provide through photosynthesis and soil is important for food.
You own a geotechnical engineering firm in central California and your company has been hired to conduct a slope stability analysis. Consider a 10.0 m-thick mass of regolith (note that this is already measured perpendicular to the slope – so pay attention where you might change the cosine term) sitting on top of a bedrock surface with a slope of 14 degrees. A home is located at the top of this slope (and set back from the edge only 20 m). Upon an initial visit, you determine that the regolith is unsaturated. You also estimate the following additional parameters for this site:
regolith cohesion = 1100 N/m2
regolith angle of internal friction = 15 degrees
density of regolith = 2200 kg/m3 (density of water = 1000 kg/m3 )
a. What is the value for the Factor of Safety? Show your work. Would you consider the slope currently stable? Explain your answer. 4 pts
b. How does the factor of safety change if the water depth increases by 2 m? Does the slope become more or less stable, and by how much? How does this compare to the example above (Part a.)? 3 pts
c. How does the factor of safety change if the angle of internal friction increases by a factor of 2 (this would be the equivalent of changing the material from loose sand to semi-consolidated sediment)? Does the slope become more stable or less stable? 3 pts
d. How does the factor of safety change if the slope is steeper by a factor of 2? Does the material become more or less likely to fail? 3 pts
e. What advice would you give to the homeowners regarding the safety of their home? What remediation can you suggest if any is needed? 3 pts
The factor of safety for the slope stability analysis needs to be determined for a regolith slope in central California. The parameters provided include regolith cohesion, angle of internal friction, and regolith density. The analysis involves evaluating the stability of the slope under different conditions, such as changes in water depth, angle of internal friction, and slope steepness. Recommendations for the homeowners regarding the safety of their homes and potential remediation measures will also be provided.
To calculate the factor of safety, we need to consider the forces acting on the slope. The driving force is the weight of the regolith, which can be calculated by multiplying the density of the regolith by the volume of the slope. The resisting force is the shear strength of the regolith, which is determined by the cohesion and angle of internal friction. The factor of safety is the ratio of the resisting force to the driving force.
a. To determine the factor of safety, we can use the given parameters and calculate the driving force and resisting force. By dividing the resisting force by the driving force, we can obtain the factor of safety. If the factor of safety is greater than 1, it indicates that the slope is stable. If it is less than 1, the slope is considered potentially unstable.
b. If the water depth increases by 2 m, it adds additional weight to the slope, increasing the driving force. This decrease in the factor of safety suggests a less stable slope compared to the initial scenario.
c. If the angle of internal friction increases by a factor of 2, it enhances the shear strength of the regolith. This increase in the factor of safety indicates a more stable slope.
d. If the slope becomes steeper by a factor of 2, it increases the driving force. This decrease in the factor of safety suggests a less stable slope.
e. Based on the analysis, it is important to advise the homeowners that the slope is currently unstable, considering the factor of safety is less than 1. Remediation measures may include slope stabilization techniques such as installing retaining walls, soil reinforcement, or drainage systems to manage water infiltration and reduce driving forces. It is recommended to consult with a geotechnical engineer to develop a comprehensive slope stability plan for the safety of the home.
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Why is vinegar considered a solution?
Answer:
Vinegar is a homogenous mixture of acetic acid and water. As the mixture created has only one phase it is a solution. ... There are no chemical bonds created between water and the acid and it is possible to separate the two without breaking any chemical bonds.
Explanation:
A car traveling 29 mi/h accelerates uniforml for 8.5 s, covering 471 ft in this time.
What was its acceleration? and What is the final velocity at this time?
I know the acceleration is 3.01 ft/s^2 i just need the final velocity in ft/s
Answer:
68.12 ft/s
Explanation:
assuming that the acceleration is correct
Given
a = 3.01 ft/s²
time elapsed, t = 8.5s
initial velocity, u = 29 mi/h = 42.533 ft/s
final velocity, v = we are asked to find this
recall that one of the equations of motions can be expressed as:
v = u + at, where v, u, a and t are defined as above
simply substitute the known values above into the equation;
v = u + at
v = 42.533 + (3.01)(8.5)
v = 68.12 ft/s
Explanation:
We know that :
u = 29 mph = 12.96 m/s
a = 3.01 ft/s^2 = 0.92 m/sec^2
t = 8.5sec
v = u + at
V = 12.96 + 0.92 * 8.5
v( final velocity) = 20.78 m/s = 68.17 ft/s
A woman on a train traveling at 32 m/s. The train passes a factory whose whistle is blowing at 288 Hz. What frequency does the woman hear as the train approaches the factory?
Answer:
0.11 m
Explanation:
speed is equal to wavelength multiplied by frequency
So, 32= w × 288
32/288= 0.11
If a car is traveling 27 meters in 3 seconds, what is its speed?
Answer:
9 m/s
Explanation:
speed = distance ÷ time
27÷3
=9
Water, oil and silver are poured into the vessel
water. The height of the water column is 20 cm. Right Mukh The level of mercury in L is 0.5 cm higher than in Mar On horseback. Find the height of the oil column.
The height of the oil column above the water in the vessel is determined as 2 cm.
Pressure of the vesselThe pressure of the vessel due to water, oil and silver poured into the vessel is determined from mercury column.
let level of mercury = 20 cm + 0.5 cm = 20.5 cm
20.5 cmHg = 205 mmHg
1 mmHg = 133.32 Pa
205 mmHg = 27,330.6 Pa
Height of the liquids in the vesselP = ρgh
where;
ρ is the density of water, oil and silver respectively
ρ = 1000 kg/m³ + 881 kg/m³ + 10,800 kg/m³ = 12,681 kg/m³
h = P/(ρg)
h = (27,330.6) / (12,681 x 9.8)
h = 0.22 m
h = 22 cm
Height of oil columnOil is less dense than water and will float on water.
Height of oil column = 22 cm - 20 cm = 2 cm
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a body falls freely from rest.calculate it's acceleration
Answer:
10 m/s²
Explanation:
Since the body is falling freely from the rest, it will be having an acceleration equal to the acceleration due to gravity.
∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².
Answer:
10 m/s^2 I hope it helps u a lot
A ball is dropped off the side of a bridge after 1.55 seconds how far has it fallen (units=m)
Answer:
d = 11.77 m
Explanation:
Given that,
A ball is droped off the side of a bridge after 1.55 seconds.
We need to find how far it has fallen.
It will fall under the action of gravity. It would mean that a = g = 9.8 m/s²
Let it is fallen at a distance d. d can be calculated using second equation of motion as follows :
\(d=ut+\dfrac{1}{2}at^2\)
Put u = 0 and a = g
So,
\(d=\dfrac{1}{2}\times 9.8\times (1.55)^2\\\\d=11.77\ m\)
Hence, it will fall at a distance of 11.77 m.
Answer:
-11.77!!!! DONNT FORGET NEGATIVE
Explanation:
which of the following is the change in entropy for a reaction calculated using standard entropy values?select the correct answer below:
A. gibbs free energy change
B. standard free energy of formation
C. standard entropy change
D. standard entropy
How would the time of the jump and the horizontal distance traveled change if g were changed, for example if the jump could be repeated with the same initial velocity on a different planet? Select all that apply.) The displacement increases with increased time of the jump. The time of the jump increases when g is smaller. The displacement decreases with increased time of the jump. The time of the jump decreases when g is smaller. Increasing the time of the jump has no effect on the displacement.
The following statements are true: The time of the jump increases when g is smaller. The gravitational acceleration, denoted as g.
The time of the jump decreases when g is smaller.
The time of the jump refers to the duration of the jump, the time it takes for the object to reach the ground.
The gravitational acceleration, denoted as g, affects the time of the jump.
When the gravitational acceleration is smaller (on a planet with lower gravity), the object takes longer to reach the ground, resulting in an increased time of the jump.
Conversely, when the gravitational acceleration is larger (on a planet with higher gravity), the object falls faster, leading to a shorter time of the jump.
The other statements in the options are incorrect:
The displacement (horizontal distance traveled) does not depend on the time of the jump. It is determined by the initial velocity and the angle of projection, but not by the duration of the jump.
Increasing the time of the jump does not have any effect on the displacement. The horizontal distance traveled remains the same as long as the initial velocity and angle of projection are unchanged.
Therefore, the correct statements are:
The time of the jump increases when g is smaller.
The time of the jump decreases when g is smaller.
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The drop time can be calculated as follows: where y is the vertical height of the table and g is the
acceleration due to gravity. How did the calculated drop time compare to the average of your measured drop
times? Find the percent error using the following equation:
What factors might cause the differences?
Answer:
Tt can be calculated by copy
Particle A and particle B are held together with a compressed spring between them. When they are released, the spring pushes them apart and they then fly off in opposite directions, free of the spring. The mass of A is 2.00 times the mass B, and the energy stored in the spring was 121 J. Assume that the spring has negligible mass and that all the stored energy is transferred to the particles. Once that transfer is complete, what are the kinetic energies of each particles?
a ) ans: .............J (particle A)
b) ans: .............. J (particle B)
Let the mass of particle A be denoted as \(m_{A}\)and the mass of particle B as \(m_{B}\). Given that m_A = 2\(m_B\), we can express the total kinetic energy of the system after the energy transfer as follows:
Total kinetic energy = Kinetic energy of particle A + Kinetic energy of particle B
Since all the energy stored in the spring is transferred to the particles, the total kinetic energy is equal to the initial potential energy stored in the spring, which is 121 J. Therefore, we have:
121 J = Kinetic energy of particle A + Kinetic energy of particle B
Now, let's assign variables for the kinetic energies of the particles: \(K_A\) for particle A and \(K_B\) for particle B. We can express the equation as:
121 J = \(K_A\) + \(K_B\)
We also know that the mass of particle A (\(m_A\)) is 2 times the mass of particle B (\(m_B\)), so we can write:
\(K_A\)= (1/2) \(m_A\) \(v_A^2\) (1)
\(K_B\) = \(m_B\\\)\(v_B^2\)(2)
where \(v_A\) and \(v_B\\\) are the velocities of particles A and B, respectively.
Substituting equation (1) and equation (2) into the equation 121 J = \(K_A\) + \(K_B\), we get:
121 J = (1/2) \(m_A v_A^2 + m_B v_B^2\)
Since mA = 2mB, we can rewrite the equation as:
121 J = (1/2) (2\(m_B) v_A^2 + m_B v_B^2\)
Simplifying the equation, we have:
121 J = \(m_B (v_A^2 + v_B^2)\)
We don't have enough information to determine the specific values of \(v_A\) and \(v_B\) or the masses of the particles. Therefore, we cannot calculate the exact kinetic energies of particles A and B. The answers would depend on the specific values of mass and velocity for each particle.
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1. what is the uncertainty of the natural frequency (in hz) due to the uncertainty of the length measurement? (hint: the uncertainty should be less than 1 hz.)
The uncertainty in the length measurement, δL, should satisfy:
δL < (2πL√(L/g))
The uncertainty of the natural frequency due to the uncertainty in the length measurement can be estimated using the formula for the natural frequency of a simple harmonic oscillator, which is given by:
f = 1 / (2π√(L/g))
where f is the natural frequency, L is the length of the oscillator, and g is the acceleration due to gravity. To calculate the uncertainty in the natural frequency, we can use the formula for propagating uncertainties:
δf = (∂f/∂L) * δL
Taking the derivative of the natural frequency formula with respect to L and assuming a small uncertainty δL in the length measurement, we have:
∂f/∂L = -1 / (2πL√(L/g))
Substituting this value into the uncertainty formula, we get:
δf = (-1 / (2πL√(L/g))) * δL
To ensure that the uncertainty is less than 1 Hz, we need to have:
|(-1 / (2πL√(L/g))) * δL| < 1
Therefore, the uncertainty in the length measurement, δL, should satisfy:
δL < (2πL√(L/g))
In practice, to ensure the uncertainty in the natural frequency is less than 1 Hz, it is necessary to have a precise and accurate length measurement with an uncertainty smaller than the calculated value.
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What are the three different types of friction
Group of answer choices
Sliding, static, rolling
Static, smooth, rough
Action, reaction, equal
Ice, sand, table
Answer:
sliding , static , rolling
Explanation:
HOPE IT WILL HELP YOU
In a 30cm by 25cm rectangle, a quadrant of a circle of radius 7cm has been cut away from each corner. What is the perimeter of the part left?
Answer: 98cm
Explanation:
Dimension of rectangle = 30cm by 25cm
Length(l) = 30cm
Width(w) = 25cm
Perimeter of a rectangle = 2(l + w)
Quadrant of circle cut away of each side of the rectangle :
Radius = 7 cm =
That is, the dimension of the triangle reduces by 2 * 7 = 14cm
New length = 30 - 14 = 16cm
New width = 25 - 14 = 11cm
The four corners =( 4 × 2πr ) / 4
2πr = 2 × 22/7 × 7 = 44cm
Perimeter = 2(16cm + 11cm)
= 2(27cm)
Perimeter = 54cm + 44 = 98cm
If there is a closed path for the flow of current, then:A.an electrical circuit exists.B.charge can accumulate in the path.C.at least one switch in the circuit is open.D.there will be no resistance at all to the current.
Given:
There is a closed path for the flow of current.
Answer and explanation:
A correct option is an option (A). Since the path is closed, the current will flow through the circuit.
An option (B) is incorrect because the charge does not accumulate in a closed path.
Option (C) is also incorrect because the path is closed, and the circuit cannot be open.
Option (D) is also an incorrect option because there is always a resistance provided by the metal wire.
why is it not advisable to touch a canvas tent from inside when it is raining?
Answer: When you touch wet canvas, surface tension will draw water to your finger. However, the drop left behind where you touched, like any irregular point on an overhead surface, will draw condensation from inside the tent if it is humid.
Imagine you inherit a farm and now have to purchase fertilizer for the farm. The farm is 340 acres and had corn planted the previous year. You must add fertilizer to the soil before you plant this year's crop. You go to the local fertilizer store and find SuperPhosphate-brand fertilizer. You read the fertilizer bag and can recognize from your high school chemistry class a molecular formula C*a_{3}*P_{2}*H_{14}*S_{2}*O_{21} (you don't understand anything else written on the bag because it is imported fertilizer from Japan). You must decide how much fertilizer to buy for application to your cornfields. If each bag contains 25 kg of fertilizer and costs $54.73, how many bags of fertilizer must you purchase, and how much will it cost you to add the necessary fertilizer to your fields ?
Total Cost is = $107,380 if The farm is 340 acres and had corn planted add fertilizer to the soil before you plant this years' crop.
What is called fertilizer?A fertiliser is a natural or artificial substance containing chemical elements (such as Nitrogen (N), Phosphorus (P) and Potassium (K)) that improve growth and productiveness of plants. Some synonyms include the terms "enrichment" or "plant nutrient".
Why is fertilizer important?Without fertilizers, nature struggles to replenish the nutrients in the soil. When crops are harvested, important nutrients are removed from the soil, because they follow the crop and end up at the dinner table. If the soil is not replenished with nutrients through fertilizing, crop yields will deteriorate over time.
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11
The pilot directs the aircraft to fly due north at 600km/h. A side-wind blows at
100km/h towards the east. What will be the aircraft's resultant velocity? (Give both its
speed and direction)
Explanation:
Given that,
The pilot directs the aircraft to fly due north at 600km/h.
A side-wind blows at 100km/h towards the east.
We need to find the aircraft's resultant velocity. et it be v. It can be calculated as follows :
\(v=\sqrt{600^2+100^2} \\\\v=608.27\ m/s\)
For direction,
\(\tan\theta=\dfrac{600}{100}\\\\\tan\theta=6\\\\\theta=\tan^{-1}(6)\\\\\theta=80.53^{\circ}\)
So, the aircraft's resultant velocity is 608.27 km/h and it is at and angle of 80.53°.
A 11,600 kg railroad car travels along on a level friction less track with a constant speed of 18.0 m/s. A 3,750 kg load, initially at rest is dropped onto the car. What will the car's new speed be?