a force of 40 n is needed to keep a 10-kg steel box sliding across a level floor with a constant velocity of 8 m/s. what is the net force on the box?
Answers
The net force on the box is 40N.
A net force is what?The net force acting on an object is the result of all pushing and pulling forces acting on the object collectively (the sum). If there is an imbalance in the pushing and pulling forces acting on an object, the object will accelerate in the direction of the net force.
According to Newton's second law, an object's acceleration is inversely proportional to its mass and proportional to both the resultant force and the resultant force.
Force = m × a
40 = 10 × a
a = 40/10
a = 4m/s²
Net force ∑F = m×a
∑F = 10 × 4
∑F = 40N.
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Related Questions
What is the velocity of an 80 kg person skating across the ice with a kinetic energy of 16, 000 joules?
Answers
Answer:
V = 20 m/s
Explanation:
Given the following data;
Mass = 80kg
Kinetic energy = 16,000 joules
To find the velocity;
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
\( K.E = \frac{1}{2}MV^{2}\)
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Substituting into the formula, we have;
16000 = ½*80*V²
16000 = 40V²
V² = 16000/40
V² = 400
Taking the square root of both sides, we have;
V = 20 m/s
to transmit heat sound or electricity through a medium
Answers
Answer:Electrical conduction is the transfer of electrically charged particles through a medium, such as electricity traveling through the power lines in your house. Sound conduction (or acoustic conduction) is the transfer of sound waves through a medium, such as vibrations from loud music passing through a wall.
Explanation: Trust
An airplane lands on the runway at a velocity of 22.7m/s. The plane accelerates at a rate of -3.3m/s2 until it comes to rest. How much time does it take the plane to stop? (round to the nearest tenth).
Answers
Answer:
time = 6.9 s
Explanation:
velocity of the plane v = 22.7 m/s
acceleration of the train a = -3.3 m/s^2
it finally comes to res, final velocity u = 0 m/s
time t = ?
using the equation
v = u + at
substituting, we have
0 = 22.7 + (-3.3)t
0 = 22.7 - 3.3t
3.3t = 22.7
t = 22.7/3.3 = 6.9 s
Identify the type of reaction (combustion, synthesis, decomposition, single replacement, or double replacement) this equation represents.
CH4 + O2 CO2 + H2O
Answers
Answer:
Combustion
Explanation:
how do you get the net force
Answers
The net force on a body is the resultant of all the force acting on the body, which can be calculated by the vector addition of all the forces as the force is a vector quantity.
Generally, the components of the forces in a single direction (x,y, and z) added together, then the resultant of all the forces can be determined which is the net force.
For example if f1, f2,..fn are n forec action on the body as
f1 = a1 i + b1 j + c1 k
f2= a2 i + b2 j + c2 k
fn = an i + bn j +cn k
Then the net force, F, action on the body
F= f1 + f2+ ... +fn
F= (a1 i + b1 j + c1 k) + (a2 i + b2 j + c2 k)+...+(an i + bn j +cn k)
F=(a1+a2+...an)i+(b1+b2+...+bn)j + (c1+c2+...+cn)k which is the net force.
In this way, the net force can be determined.
in a velocity selector, the particles move toward the east, and the magnetic field is directed to the north. what direction should the electric field point?
Answers
The electric field should point towards the west. An electric field is a region of space around a charged object where other charged objects experience a force.
In a velocity selector, the particles are only able to pass through if their velocity is perpendicular to both the magnetic field and the electric field. Since the magnetic field is directed to the north, the electric field must be directed to the west in order to ensure that the particles move in a perpendicular direction to both fields. An electric field is a region of space around a charged object where other charged objects experience a force. The electric field is created by the charged object and is a vector field, meaning it has both magnitude and direction. The strength of the electric field is determined by the magnitude of the charge that creates it and the distance from the charged object. The electric field decreases with distance from the charged object, and its strength can be calculated using Coulomb's law, which relates the force between two charged objects to their charges and the distance between them.
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A car begins from rest and accelerates at a rate of +3.0 m/s^2 for 5.0 seconds.
a. Determine the car's final speed.
b. Calculate the car's average speed during its trip
Answers
Answer:
a)15m/s
b)7.5m/s
Explanation:
a)use the formula for acceleration
b)calculate distance then calculate speed
A train leaves a station traveling north at 45 km/h. 2 hours
later, an express train leaves the same station on a parallel track
traveling north at 75 km/h. How far from the station will the
trains me
Answers
Explanation:
First train has 2 hr * 45 km/hr = 90 km head start
Closing speed between the two trains 745 - 45 = 30 km
to cover the 90 km between them will take 3 hours
and the second train will be at 75 km/hr * 3 hr = 225 km from the station
In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A rider is towed at a constant speed by a rope that is at an angle of 19 ∘
from horizontal. The tension in the rope is 1500 N. The force of the sail on the rider is 30∘
from horizontal
Answers
We may use trigonometry to address this issue by dividing the forces into their horizontal and vertical components.
...... 'S,""" '
T horizontal equals Tension * cos(19°)
T vertical = 1437.61 N
Then, we may determine the tension force's vertical component:
T vertical equals Tension * Sin(19°)
T horizontal = 484.94 N
We can now calculate the horizontal component of the sail's force on the rider:
F horizontal is equal to F sail * cos(30°).
vertical = 25.98 N
Last but not least, we may determine the vertical component of the sail's force on the rider:
F vertical is F sail times sin(30°).
F horizontal = 14.99 N
The net horizontal force must be zero since the rider is not accelerating in the horizontal direction. In light of this, the horizontal component of the tension force and the horizontal component
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which term refers to the amount of energy in a food per unit of weight?
Answers
Answer:
The term that refers to the amount of energy in a food per unit of weight is energy density. Energy density is measured in kilojoules (kJ) or calories (kcal) per gram. Foods with a high energy density, such as nuts, seeds, and oils, provide a lot of energy in a small amount of food. Foods with a low energy density, such as fruits and vegetables, provide a small amount of energy in a large amount of food.
Energy density is an important factor to consider when planning a healthy diet. Foods with a high energy density can help you meet your energy needs without overeating. Foods with a low energy density can help you feel full without consuming too many calories.
Explanation:
The surface of this planet is obscured by an atmosphere of thick clouds and toxic gases. What planetary body is it
Answers
Answer:
Venus....
Explanation:No explanation just simple answers
Please help : fill out table first and then explain
Answers
R3 and R4 are in series, so:
\(R_{eq}1=R3+R4=5+10=15\)R6 and R7 are also in series, so:
\(R_{eq}2=R6+R7=8+7=15\)R5, Req1 and Req2 are in parallel, so:
\(\begin{gathered} \frac{1}{R_{eq}3}=\frac{1}{R_{eq1}}+\frac{1}{R_{eq}2}+\frac{1}{R5} \\ \frac{1}{R_{eq}3}=\frac{1}{15}+\frac{1}{15}+\frac{1}{15} \\ \frac{1}{R_{eq}3}=\frac{3}{15} \\ \frac{1}{R_{eq}3}=\frac{1}{5} \\ R_{eq}3=5 \end{gathered}\)Now, Req 3, R10 and R11 are in series, so:
\(R_{eq}4=R_{eq}3+R10+R11=5+10+15=30\)Now, we can find the total current in that segment using ohm law:
\(\begin{gathered} V=IR \\ I=\frac{V}{R} \\ I1=\frac{V_T}{R_{eq}4}=\frac{240}{30} \\ I1=8A \end{gathered}\)Now, let's find the voltage and the current for R3,R4, R5, R6, R7, R10 and R11
\(\begin{gathered} V1=I1\cdot R_{eq}3=8\cdot5=40V \\ \end{gathered}\)With this value, let's complete one portion of the table:
---------------
Now, R8 and R9 are in series, so:
\(R_{eq}5=R8+R9=20+40=60\)Req5 and Req4 are in parallel, so:
\(\begin{gathered} \frac{1}{R_{eq}6}=\frac{1}{R_{eq}4}+\frac{1}{R_{eq}5} \\ \frac{1}{R_{eq}6}=\frac{1}{30}+\frac{1}{60} \\ \frac{1}{R_{eq}6}=\frac{1}{20} \\ R_{eq}6=\frac{20}{1} \\ R_{eq}6=20 \end{gathered}\)R1 and R2 are in parallel, R12 and R13 are in parallel too, so:
\(\begin{gathered} \frac{1}{R_{eq}7}=\frac{1}{R1}+\frac{1}{R2} \\ \frac{1}{R_{eq}7}=\frac{1}{10}+\frac{1}{10} \\ \frac{1}{R_{eq}7}=\frac{2}{10} \\ R_{eq}7=5 \end{gathered}\)\(\begin{gathered} \frac{1}{R_{eq}8}=\frac{1}{R12}+\frac{1}{R13} \\ \frac{1}{R_{eq}8}=\frac{1}{12}+\frac{1}{60} \\ \frac{1}{R_{eq}8}=\frac{1}{10} \\ R_{eq}8=10 \end{gathered}\)Therefore, the total resistance of the circuit since Req6, Req 7, Req8 and R14 are in series, is:
\(\begin{gathered} R_T=R_{eq}6+R_{eq}7+R_{eq}8+R14=20+5+10+5 \\ R_T=40 \end{gathered}\)And the total current is:
\(I_T=\frac{V_T}{R_T}=\frac{240}{40}=6_{}\)Answer:
A uniform electric field of magnitude E = 480 N/C makes an angle of ? = 60.5 with a plane surface of area A = 3.45 m
2
as in the figure below. Find the electric flux through this surface.
.... N m
2
/C
Answers
The electric flux through the given surface is 1,659.6 N m2/C.
Electric flux is defined as the product of the electric field passing through a surface and the area of that surface. Mathematically, electric flux (Φ) is given by Φ = E · A · cosθ, where E is the electric field strength, A is the area of the surface and θ is the angle between the electric field and the surface.
In the given problem, the electric field strength is E = 480 N/C, the area of the surface is A = 3.45 m2 and the angle between the electric field and the surface is θ = 60.5°.
Using the formula for electric flux, we get:
Φ = E · A · cosθ
Φ = 480 N/C · 3.45 m2 · cos60.5°
Φ = 1659.6 N m2/C
Therefore, the electric flux through the given surface is 1,659.6 N m2/C.
The concept of electric flux is very important in the study of electricity and magnetism. It helps us to understand how electric fields interact with surfaces and how electric charges can be distributed on surfaces.
In this problem, we are given a uniform electric field of magnitude E = 480 N/C that makes an angle of θ = 60.5° with a plane surface of area A = 3.45 m2. We are asked to find the electric flux through this surface.
To solve this problem, we need to use the formula for electric flux: Φ = E · A · cosθ. This formula tells us that the electric flux through a surface depends on the strength of the electric field, the area of the surface and the angle between the electric field and the surface.
First, let's find the component of the electric field that is perpendicular to the surface. This component is given by E⊥ = E · cosθ. Substituting the given values, we get:
E⊥ = 480 N/C · cos60.5°
E⊥ = 240 N/C
Next, we can use this value to calculate the electric flux through the surface:
Φ = E⊥ · A
Φ = 240 N/C · 3.45 m2
Φ = 829.2 N m2/C
However, this is not the final answer. We need to take into account the fact that the electric field makes an angle with the surface. When the electric field is not perpendicular to the surface, the electric flux is reduced by a factor of cosθ. Therefore, we need to multiply our previous result by cosθ to get the final answer:
Φ = E⊥ · A · cosθ
Φ = 240 N/C · 3.45 m2 · cos60.5°
Φ = 1659.6 N m2/C
Therefore, the electric flux through the given surface is 1,659.6 N m2/C.
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hiii please help i’ll give brainliest if you give a correct answer please thanks!
Answers
Answer:
the object will remain at rest
A pendulum is swinging next to a wall. The distance from the bob of the pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.
Answers
The formula of the trigonometric function that models the distance HHH from the pendulum's bob to the wall after t seconds is
H(t) = 15 -6sin(2.5π(t -0.5))
Detailed explanation:
The function can be expressed as the following for the midline M, amplitude A, period T, and time t0 at which the function deviates from the midline:
H(t) = M -Asin(2π/T(t -t0))
The equation is based on the parameters M=15, A=6, T=0.8, and t0 = 0.5.
H(t) is equal to 15 -6sin(2.5π(t -0.5))
What is function?The trigonometric functions in mathematics are real functions that connect the right-angled triangle's angle to the ratios of its two side lengths .In all areas of study that involve geometry, such as geodesy, solid mechanics, celestial mechanics, and many others, they are widely used.
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The correct question is:
A pendulum is swinging next to a wall. The distance from the bob of the swinging pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.
The function has period 0.80.80, point, 8 seconds, amplitude 6 \text{ cm}6 cm6, start text, space, c, m, end text, and midline H = 15 \text{ cm}H=15 cmH, equals, 15, start text, space, c, m, end text. At time t = 0.5t=0.5t, equals, 0, point, 5 seconds, the bob is at its midline, moving towards the wall.
Find the formula of the trigonometric function that models the distance HHH from the pendulum's bob to the wall after t seconds. Define the function using radians.
Force f acts between two charges, q1 and q2, separated by a distance d. if q1 is increased to twice its original value and the distance between the charges is also doubled, what is the new force acting between the charges in terms of f? one quarterf one halff f 2f
Answers
The new force acting between the charges in terms of f given the data from the question is half f
Coulomb's law equationF = Kq₁q₂ / r²
Where
F is the force of attraction K is the electrical constant q₁ and q₂ are two point charges r is the distance apart How to determine the initial force Charge 1 = q₁Charge 2 = q₂ Electric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = dInitial force (F₁) = f =?F = Kq₁q₂ / r²
F₁ = f = Kq₁q₂ / d²
How to determine the new force Charge 1 = 2q₁Charge 2 = q₂ Electric constant (K) = 9×10⁹ Nm²/C²Distance apart (r) = 2dNew force (F₂) =?F = Kq₁q₂ / r²
F₂ = K2q₁q₂ / (2d²
F₂ = 2Kq₁q₂ / 4d²
F₂ = Kq₁q₂ / 2d²
F₂ = ½(Kq₁q₂ / d²)
But
f = Kq₁q₂ / d²
Therefore
F₂ = ½f = half f
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Answer:
C or 1/2
Explanation:
If it takes 726 watts of power to move a mass 36 meters in 14 seconds, then what is the magnitude of the object’s mass?
A. 12. 1 kg
B. 20. 2 kg
C. 28. 8 kg
D. 282 kg
Answers
Answer: The mass of the object if it takes 726 watts of power to move an object 36 m in 14 s is 28.8 kg.
What is mass?
An object's inertia, a fundamental property, is measured by its mass, a fundamental indicator of the volume of substance inside the thing. Definitions of mass can seem circular since it since it such a fund such a fundamental quantity and is challenging to define in terms of another.
It is possible to define every mechanical quantity in terms of mass, length, and time. The SI unit for mass, denoted by the letter m, is the kilogram. While mass is typically thought of as an immutable feature of an item, relativistic mass must be taken into account when traveling at speeds close to the speed of light.
Given:
The Power, p = 726 watt
The Time, t = 14 sec
distance travelled, d = 36 m
Calculate the power by the given formula
p = W / t
p = m * g * h / t ( w = m * g* h)
726 = m * 9.8 * 36 / 14 ( g = 10 m/s^2)
m = 28. 8 kg
Therefore, the mass of the object If it takes 726 watts of power to move an object 36 m in 14 s is 28.8 kg.
Unpolarized light with intensity Io is incident on two polarizing filters. The axis of the first filter makes an angle of α= 60 with the vertical, and the axis of the second filter is horizontal. What is the intensity of the light after it has passed through the second filter?
Answers
The intensity of the light after it has passed through the second filter is I₂ = 0.25Io.
What is the Unpolarized light with intensity?When unpolarized light passes through a polarizing filter, it becomes linearly polarized with an intensity proportional to the cosine squared of the angle between the filter's axis and the polarization direction of the incident light.
In this case, the first filter makes an angle of α = 60° with the vertical. The intensity of the light after passing through the first filter is I₁ = Io * cos²α = Io * cos²60° = Io * 0.25.
The second filter has a horizontal axis, which is perpendicular to the polarization direction of the light transmitted by the first filter. Since the light is already polarized in the vertical direction after passing through the first filter, it will be blocked completely by the second filter. Therefore, the intensity of the light after passing through the second filter is I₂ = 0 * I₁ = 0.
In summary, the intensity of the light after passing through the second filter is zero (0).
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To explore the bottom of a 25-m-deep lake, your friend Tom proposes to get a long garden hose, put one end on land and the other in his mouth for breathing underwater, and descend into the depths. Susan, who overhears the conversation, reacts with horror and warns Tom that he will not be able to inhale when he is at the lake bottom.
Why is Susan so worried?
The pressure at a depth 01 25 m is 3 x 10^5 Pa. This is almost three times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 3.5 x 10^5 Pa. This is almost 3.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2 x 10^5 Pa. This is almost two times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Answers
Answer:
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Explanation:
The depth is h = 25 m
The density of water p = 1000 kg/m^3
Acceleration due to gravity g = 9.81 m/s^3.
Pressure due to a depth is gotten from
P = pgh
P = 1000 x 9.81 x 25 =245250 Pa
==> 2.45 x 10^5 Pa
Approximately 2.5 x 10^5 Pa
Atmospheric pressure = 1.01325 x 10^5 Pa
Dividing the pressure at the bottom of the pond by the atmospheric pressure gives a value of about 2.5,which means that the pressure is 2.5 times the atmospheric pressure.
What physical property of salt allowed you to separate it from the sand?
Answers
Wants to slide his 430g water bottle precisely 12m to land inside a Bull's Eye! If the coefficient of kinetic friction between the bottle and the surface is 0.62, calculate the initial speed he must release the bottle?
Answers
Answer:
Ff = u M g frictional force where u = .62
1/2 M v^2 kinetic energy of water bottle at release
Ff * d = 1/2 M v^2 = u M g d work to stop equals initial kinetic energy
v^2 = 2 u g d = 2 * .62 * 9.8 * 12 = 146 m^2 / s^2
v = 12.1 m/s
Question 28 Marks: 1 Radon is detected in a home through measurment ofChoose one answer. a. geiger rays b. beta particles c. alpha particles d. UV rays
Answers
The correct answer is c. alpha particles. Radon is a radioactive gas that can be found in homes and buildings. It is detected through the measurement of alpha particles, which are emitted by the decay of radon atoms.
This measurement is usually done using a device called a radon detector, which can provide an accurate reading of the radon levels in a home. It is important to regularly test for radon in order to ensure that the levels are safe for occupants.
Radon is detected in a home through the measurement of alpha particles.
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Number of atoms present in 1 mole of oxygen atom
Answers
Answer:
1 mole of every substance has 6.022 × 10^23 particles. This is called Avagadro's constant
a ball is shot straight up into the air from the ground with initial velocity of 49ft/sec. assuming that the air resistance can be ignored, how high does it go?
Answers
When a ball is shot straight up into the air from the ground with initial velocity of 49ft/sec. assuming that the air resistance can be ignored, the maximum height that the ball goes up will be 73.96 ft.
This can be determined by using the kinematic equations for constant acceleration. The kinematic equation that relates the displacement, initial velocity, acceleration, and time is given by:
S = ut + 1/2 at²
where, S is the maximum height the ball goes up, u is the initial velocity of the ball, a is the acceleration of the ball, t is the time taken by the ball to reach maximum height.
Now, the initial velocity of the ball is u = 49 ft/s (given). Since the ball is thrown upwards, the acceleration of the ball will be downwards, i.e., a = -32.2 ft/s² (taken as negative since it is in the opposite direction to the motion)
At maximum height, the final velocity of the ball will be zero. Hence, using the equation, v = u + at, at maximum height, v = 0 and u = 49 ft/s, a = -32.2 ft/s²
Substituting these values in the equation,
v = u + at0
= 49 - 32.2*t
t = 1.52 s.
Now, substituting u, a, and t in the equation,
S = ut + 1/2 at²
S = 49(1.52) + 1/2 (-32.2)(1.52)²
S = 73.96 ft
Therefore, the maximum height that the ball goes up is 73.96 ft.
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246.5ft.
The ball shot straight up into the air with an initial velocity of 49ft/sec will reach a maximum height, before it begins to fall back to the ground. Assuming no air resistance, the ball will reach a maximum height of 246.5ft.
To calculate this, use the formula h = (vi2) / (2g), where vi is the initial velocity and g is the acceleration due to gravity (g = 9.8m/s2).
Plugging in the values given, we get: h = (49ft/sec)2 / (2 * 9.8m/s2) = 246.5ft.
Therefore, the ball will reach a maximum height of 246.5ft.
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A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the building at a speed of 1.6 m/s, which is taken as the given dx/dt, how fast is the length of his shadow on the building decreasing when he is 4 m from the building
Answers
The speed of man when the length of his shadow on the building decreases when he is 4 m from the building will be 0.6 m/sec.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
Distance from spot shines = 12 m away
Height of man,h=2 m tall
Speed of man +1.6 m/s,
Distance from the building = 4 m
Let the height of shadow= y,
CD=x
Height of man=2 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
As the triangle ABD and ECD are similar. The property of the similarity is found as;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24\)
Differentiate the above question with respect to x;
\(\rm x \frac{dy}{dt}+y\frac{dx}{dt}=0 \\\\ x\frac{dy}{dt}= -y\frac{dx}{dt}\)
From the given conditions the man is 4 m from the building the value of the remaining distance x is;
x=12-4
x=8 m
Speed of man:
\(\rm \frac{dx}{dt} = 1.6 \ m/sec\)
On putting all the values we get;
\(\rm \frac{y}{2} = \frac{12}{x} \\\\ xy = 24 \\\\ 8y = 24 \\\\ y= 3\)
The speed of man when the length of his shadow on the building decreases when he is 4 m from the building;
\(\rm \frac{dy}{dt} = - \frac{3}{8} \times 1.6 \ m/sec \\\\\ \frac{dy}{dt} = 0.6 \ m/sec.\)
Hence the value of the speed for the given conditions willl be 0.6 m/sec.
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Help ASAP
Frank uses a bowling ball to demonstrate how energy can cause changes. Which
of the following actions would NOT demonstrate a change caused by applying
energy to the ball?
O He spins the bowling ball with one hand
O He rolls the bowling ball across the floor
O He holds the bowling ball in both hands
He lifts the bowling ball to place it on a shelf.
Answers
Answer:
he holds the ball in both hands
Explanation:
he's not moving the ball
13. What change in state occurs when a liquid changes into a solid?
Answers
Answer:
heat occurs to change into solid
Answer:
It's freezing or solidification
Explanation:
The coldness freezes the water making it a solid, like water to an ice cube. Take Disney's Frozen by example. Elsa has a ice touch, so when she touches water, it becomes a solid.
A diagram is provided.What is the volume of the block of metal?
Answers
Answer:
You need to add a picture:)
when the bells are charged up, the left bell acquires a positive charge, the right bell a negative charge. when this occurs, the nut that is suspended between the two bells experiences a torque (it lines itself up with a line between the two bells) but it doesn't experience a net force. what does this tell us about the charge on the nut? select the best answer from the choices provided.
Answers
Based on the given information, the best option for this is the nut has no net charge. There will be a positive charge on the left side, and an equal negative charge on the right side.
When the left bell has a positive charge and the right bell has a negative charge, the suspended nut experiences a torque and aligns itself between the two bells. Since it doesn't experience a net force, this indicates that the nut must have an equal amount of positive charge on its left side (attracted to the right bell's negative charge) and negative charge on its right side (attracted to the left bell's positive charge), resulting in no net charge for the nut.
To clarify, net charge refers to the overall electrical charge of an object, taking into account the balance between positive and negative charges.
Complete Question
when the bells are charged up, the left bell acquires a positive charge, the right bell a negative charge. when this occurs, the nut that is suspended between the two bells experiences a torque (it lines itself up with a line between the two bells) but it doesn't experience a net force. what does this tell us about the charge on the nut? select the best answer from the choices provided.
O The nut has no net charge. There will be a positive charge on the left side, and an equal negative charge on the night side
O The nut has no net charge. There will be a negative charge on the left side, and an equal positive charge on the right side
O The nut has a net positive charge, concentrated on the right side of the nut
O The nut has a net negative charge, concentrated on the left side of the nut
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CAN SOMEONE PLEASE ANSWER THIS?!?!
Your best friend wants to run a 5K with you next year in next year. you are terribly out of shape so you want to slowly start training to be ready if I have K is 5KM and you have decided to break this distance in the smaller amount you will use to help you train and meet your goal convert five KM to meters to help you reach your training all use any method you prefer provide your answer in the scientific notation in standard form and show your work.
Answers
Answer:
5 km=5 × 10³ m
Explanation:
1 km=1 × 10³ m
Using unitary method,
5 km= 5×10³ m
Hope it helps.