A dog's leash is 4 m long and is attached to the corner of a 2 m × 2 m square doghouse at C, as shown. The dog is attached to the other end of the leash, at D. What is the area outside of the doghouse in which the dog can play? (A) 14π m^2 (B) 16π m^2 (C) 20π m^2 (D) 15π m^2 (E) 24π m^2

Answer:

x=110 degrees

y=25 degrees

z=45 degrees

Step-by-step explanation:

direct opposite Angel are equal 110 degrees is equal to Angel x and Angel 25 degrees is equal to y

110 +25=135

180-135=45

Answer:

3 OR 8  hope this helps!

Step-by-step explanation:

The proprtions are  25/10 = 5/2 and 3/4 = 15/20

Proportion is an equation that defines that the two given ratios are equivalent to each other e.g. 1/3 = 3/9

25/10 and 5/2  are proportions:

25/10 = (5×5)/(5×2)      (Divide both the numerator and denominator by 5)

25/10 = 5/2

3/4/10 and 15/20  are proportions:

3/4 = (3×5)/(5×4)      (Multiply both the numerator and denominator by 5)

3/4 = 15/20

Therefore, 25/10 = 5/2 and 3/4 = 15/20 are proprtions

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Now that we know the value of x, we can find the values of DP, PH, and HD:

DP = 17x = 17(0.295) = 5.015

PH = 6x + 5 = 6(0.295) + 5 = 6.77

HD = 20x - 3 = 20(0.295) - 3 = 2.9

Therefore, DP ≈ 5.015, PH ≈ 6.77, and HD ≈ 2.9.

The perimeter of a form is its edge's radius. Learn how to multiply the lengths of a shape's sides to determine its perimeter.

To solve this problem, we need to use the fact that the perimeter of ADPH is 23.5. We know that AD = DP + HD, and we also know the values of DP, PH, and HD in terms of x. So, we can set up an equation using these values and solve for x.

AD = DP + HD

AD = 17x + (20x - 3)

AD = 37x - 3

Perimeter of ADPH = AD + DP + PH + HD

23.5 = (37x - 3) + 17x + (6x + 5) + (20x - 3)

Simplifying the above equation, we get:

23.5 = 80x - 1

Solving for x, we get:

x = 0.295

Now that we know the value of x, we can find the values of DP, PH, and HD:

DP = 17x = 17(0.295) = 5.015

PH = 6x + 5 = 6(0.295) + 5 = 6.77

HD = 20x - 3 = 20(0.295) - 3 = 2.9

Therefore, DP ≈ 5.015, PH ≈ 6.77, and HD ≈ 2.9.

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Answer:

Vertical angles.

Step-by-step explanation:

The function f(x) = x^2-1 when evaluated with 2, gives the value 3.

A function can then be defined as a set of ordered pairs. Function is an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

For the given situation,

Stan evaluated a function with a value and got 3 as the result.

For this statement, we can frame many functions with different inputs.

Let us consider the function,

(1)  \(f(x)=2x-3\)

Now substitute x = 3,

⇒ \(f(3)=2(3)-3\)

⇒ \(f(3)=6-3\\\)

⇒ \(f(3)=3\)

(2) \(f(x)=x^{2} -1\\\)

Now put x = 2,

⇒ \(f(2)=2^{2}-1\)

⇒ \(f(2)=4-1\)

⇒ \(f(2)=3\)

Similarly we can make many functions that has the value 3 as the result.

Hence we can conclude that the function f(x) = x^2-1 when evaluated with 2, gives the value 3.

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Answer:

40

Step-by-step explanation:

tell me if im right

26 city blocks

Hence, the actual distnce between the city Hall and library is 26 city blocks apart

Answer:

38/55

Step-by-step explanation:

the probably is P(A)

2x4+2x5+4x5

11x10

2

8+10+20

55

38/55

Answer:

38/55

Step-by-step explanation:

hope its help

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Answer:

\(x = \frac{k - 14}{5} \\ \)

Step-by-step explanation:

\(5x + 14 = k \\ 5x = k - 14 \\ x = \frac{k - 14}{5} \\ \)

The volume of a solid is found using the curve y = (1/9)x² and the line x=5.  And the volume is found to be 625π/18 cubic units.

A volume of a solid is used to determine how much space a particular object will take. It tells the amount of space that is present in an object. For example, if we consider a cylinder and fill it with water, the amount of water it can hold is the cylinder's volume.

Given the equation is y = (1/9)x² and x=5, y=0; about the y-axis. From the graph, the larger radius R = 5 and the smaller radius r=x=√(9y). Then, the limit is written as follows,

when x=0, y=0

when x= 5,  y = 1/9×(5)²=25/9

Now, the volume is calculated by using the integral as follows,

\(\begin{aligned}V&=\int^{25/9}_0 (\pi R^2-\pi r^2)\;dy\\&=\pi \int^{25/9}_0 ((5^2-(\sqrt{9y})^2)\;dy\\&=\pi \int^{25/9}_0 (25-9y)\;dy\\&=\pi\left[25y-\frac{9y^2}{2}\right]^{25/9}_{0}\\&=\pi\left[25\left(\frac{25}{9}-0\right)-\frac{9}{2}\left(\left(\frac{25}{9}\right)^2-0^2\right)\right]\\&=\pi \left[\frac{625}{9}-\frac{625}{18}\right]\\&=\frac{625 \pi}{18}\end{aligned}\)

The required answer is 625π/18 cubic units.

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Break-even point refers to the level of output, sales, or revenue required for a business to have zero profits or losses. It's the stage where a company covers all of its costs but doesn't make any profits.

Therefore, to calculate break-even point volume, we need to use the following formula:

BEPV = Fixed Costs/ (Revenue per unit - Variable cost per unit)

where BEPV is the break-even point volume Given that the alternative under .

consideration by a company will have fixed costs of $10,000 per month, variable costs of $20 per unit, and revenue of $70 per unit, we can substitute these values in the above formula:BEPV = $10,000/($70 - $20)BEPV = $10,000/$50BEPV = 200 units Therefore, the break-even point volume is 200 units.

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Answer:

d = 4

Step-by-step explanation:

4d - 5 = 11

a) Subtract 5 from both sides.

-5 + 5 = 11 + 5

4d = 16

b) Divide both sides by 4.

4d/4 = 16/4

16/4 = 4

Therefore, you're answer will be 4.

Answer:

4 ; Initial value is (- 1)

Step-by-step explanation:

The rate of change of a linear function is slope of the line.

m = \(\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\)

(0, - 1)

(1, 3)

m = \(\frac{-1-3}{0-1}\) = 4

Initial value is - 1

y = 4x - 1

The equation of the graph is y = 4x - 1 with a rate of change of 4. The initial value of the function is y = -1.

The rate of change is the change of a quantity over 1 unit of another quantity.

Most of the time the rate of change is the change with respect to time.

As per the given graph,

The rate of change or slope of a function is the ratio of the difference of y's and x's coordinates.

Therefore, let's consider two points (0,-1) and  (1,3)

Slope = (3 - (-1))/(1 - 0)

Slope = 4

The y-intercept is -1 so the equation will be y = 4x - 1.

The initial value of function at x = 0 is y = 4(0) - 1 = -1.

Hence "The equation of the graph is y = 4x - 1 with a rate of change of 4. The initial value of the function is y = -1".

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Answer:

252

Step-by-step explanation:

One way we could think about this problem is by grouping the numbers together into pairs: -103+104 would be a pair, -105+106 would be a pair and et cetera up to the pair -199+200.

As you can see, each of these pairs add to 1 (-103+104=1, -199+200=1 etc.), so to solve this problem we can simply find how many of these pairs there are and multiply the number by 1 since each pair will total to 1.

To find how many pairs there are we need to find the number of numbers between 103 and 200 (incl.) and divide it by 2.

200-103= 97 numbers, adding 1 to count the one we started with gives us 98 numbers between 103 and 200 (incl.).

98/2 = 49 pairs of numbers. Since each pair totals 1, 1x49 is the total sum of all these pairs of numbers.

Now we need to address the other two numbers. The sequence started with 101+102 before we looked at the remaining pairs, so to find the sum, we just need to add together 101+102+49.

101+102+49 = 252

Hope this helped!

The system of inequalities which is represented as described in the task content is;

As evident in the task content; the first graph is a solid line increasing from left to right passing through 0 comma negative 3 and 3 comma 0. Hence, the slope of the line is positive and the y-intercept is -3.

Since the region below the line is shaded; the inequality is; y ≤ x - 3.

Also, second is a upward dashed parabola with a vertex at negative 3 comma negative 16 and x-intercepts at negative 1 comma 0 and 7 comma 0. The parabola equation is; y = x² - 6x - 7.

However, since the line is shaded on the outside and dashed; the inequality is; y > x² - 6x - 7.

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Answer:

Step-by-step explanation:

Combine multiplied terms into a single fraction

one-third x minus 2 ⋅ 9 x squared plus negative 4 over 3 end fraction x squared minus 13 x minus 10 plus negative 7 over x end fraction minus 1

1 x over 3 end fraction minus 2 ⋅ 9 x squared plus negative 4 over 3 end fraction x squared minus 13 x minus 10 plus negative 7 over x end fraction minus 1

Multiply by 1

1 x over 3 end fraction minus 2 ⋅ 9 x squared plus negative 4 over 3 end fraction x squared minus 13 x minus 10 plus negative 7 over x end fraction minus 1

x over 3 end fraction minus 2 ⋅ 9 x squared plus negative 4 over 3 end fraction x squared minus 13 x minus 10 plus negative 7 over x end fraction minus 1

Multiply the numbers

x over 3 end fraction negative 2 ⋅ 9 x squared plus negative 4 over 3 end fraction x squared minus 13 x minus 10 plus negative 7 over x end fraction minus 1

x over 3 end fraction negative 18 x squared plus negative 4 over 3 end fraction x squared minus 13 x minus 10 plus negative 7 over x end fraction minus 1

The exponential form of the sine function, sin(wt) = e^(iwt), is derived using Euler's formula and the properties of complex numbers. The exponential form e^(iwt) represents a complex number with a magnitude of 1 and an argument of wt.

To understand how sin(wt) becomes e^(iwt), we can use Euler's formula. Euler's formula states that e^(ix) = cos(x) + i*sin(x), where i is the imaginary unit. By substituting wt for x, we get e^(iwt) = cos(wt) + i*sin(wt).

Now, let's focus on the imaginary part, i*sin(wt). We can isolate the sine function by multiplying both sides of the equation by i: i*e^(iwt) = i*cos(wt) - sin(wt).

Next, we rearrange the equation to solve for sin(wt): sin(wt) = -i*cos(wt) + i*e^(iwt).

Since cos(wt) is a real number, we can express it as the real part of a complex number: cos(wt) = Re(e^(iwt)).

Substituting this back into the equation, we have sin(wt) = -i*Re(e^(iwt)) + i*e^(iwt).

Finally, we can factor out -i to obtain sin(wt) = (1/2i)(e^(iwt) - e^(-iwt)).

This equation represents sin(wt) in terms of complex exponentials, e^(iwt) and e^(-iwt). Notice that the real part of this expression gives us cos(wt).

In summary, sin(wt) can be expressed as sin(wt) = (1/2i)(e^(iwt) - e^(-iwt)), where e^(iwt) represents a complex number with a magnitude of 1 and an argument of wt.

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The answer to the given binary operation is 10012. The binary operation of adding 1112 and 102 will be solved by converting the binary numbers to base 10, performing the addition in base 10, and then converting the result back to base 2.

Converting the binary numbers to base 10, we have 1112 = 7 and 102 = 2. Adding 7 and 2 in base 10 gives us 9. To convert the result back to base 2, we divide 9 by 2 repeatedly until the quotient becomes 0. The remainder in each division gives us the binary digits of the answer. In this case, 9 divided by 2 is 4 with a remainder of 1, and 4 divided by 2 is 2 with a remainder of 0. Therefore, the binary representation of 9 is 1001. Hence, the answer to the given binary operation is 10012.

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Answer:

Step-by-step explanation: ???

According to the question The equilibrium constant \((K_{eq})\) relates the concentrations of reactants and products \(K_{eq} \ for\ 2AB \rightleftharpoons 2A + 2B \ is\ 49.\)This indicates that the equilibrium position favors formation of products.

The equilibrium constant \((K_{eq})\) relates the concentrations of reactants and products in a chemical reaction at equilibrium. In the given reaction,

\(A + B \rightleftharpoons AB, the\ K_{eq}\ is\ 7\).

When considering the reaction \(2AB \rightleftharpoons 2A + 2B\), the stoichiometric coefficients are doubled on both sides. According to the principles of equilibrium, the equilibrium constant for the modified reaction can be obtained by squaring the original \(K_{eq}\).

Therefore, the \(K_{eq}\) for \(2AB \rightleftharpoons 2A + 2B is (K_{eq})^2 = (7)^2 = 49\). This indicates that the equilibrium position favors the formation of products in the double reaction compared to the original reaction.

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Answer:

Coordinate of points = (7 , 0)

Step-by-step explanation:

Given:

Equation of slope;

y – y1 = m(x – x1)

Equation of slope;

y = 3(x – 7)

Find:

Coordinate of points

Computation:

By comparing

y - 0 = 3(x - 7)

So,

y1 = 0

m = 3

x1 = 7

Coordinate of points = (7 , 0)

Answer:

Answer below

Step-by-step explanation:

a) The doubling time for the population of fruit flies is approximately 12.4 hours.

b) The population size will reach 360 after approximately 43.7 hours.

a) To find the doubling time, we can use the exponential growth formula: N = N₀ * 2^(t/d), where N₀ is the initial population size, N is the final population size, t is the time, and d is the doubling time.

Given N₀ = 200, N = 274, and t = 32 hours, we can rearrange the formula to solve for d:

274 = 200 * 2^(32/d)

Solving for d, we find that the doubling time is approximately 12.4 hours.

b) Using the same formula, we can find the time required for the population to reach 360:

360 = 200 * 2^(t/12.4)

Rearranging the formula and solving for t, we find that the population size will reach 360 after approximately 43.7 hours, rounded to the nearest tenth of an hour.

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Answer:

Sin A = 5/13,

Cos A = 12/13,

tan A = 5/12

CSC A = 13/5

Sec A = 13/12

Cot A = 12/5

The agent must be designed to be able to navigate the hexagonal grid, identify when to push or pull a widget, and rotate in the appropriate direction to complete tasks. HExBOT is a term used to describe hexagonal robots designed to solve certain problems or perform specific tasks.

However, designing a HExBOT agent is not always easy, and there are several challenging aspects that must be considered when designing it. These include the hexagonal grid, the asymmetric cost of actions (pushing is more expensive than pulling a widget), and the rotation of the agent. The hexagonal grid is a challenging aspect of designing a HExBOT agent because it is not the traditional rectangular or square grid used in most robot designs. The hexagonal grid is more complex, and it requires the agent to be able to navigate through it while avoiding obstacles and staying on track.

Additionally, the hexagonal grid requires the agent to be able to rotate around a hexagon, which can be challenging for a robot designed for a rectangular grid.The asymmetric cost of actions is another challenging aspect of designing a HExBOT agent. Pushing a widget requires more energy and effort than pulling a widget, so the agent must be designed to take this into account. Additionally, the agent must be able to identify when it is more efficient to push or pull a widget, and it must be able to do so without wasting energy or time.

The rotation of the agent is also a challenging aspect of designing a HExBOT agent. The agent must be able to rotate around a hexagon, which is not always easy to do. Additionally, the agent must be able to identify when it needs to rotate and in which direction it needs to rotate to complete a task or avoid obstacles.In conclusion, designing a HExBOT agent can be challenging due to the hexagonal grid, the asymmetric cost of actions, and the rotation of the agent.

To overcome these challenges, the agent must be designed to be able to navigate the hexagonal grid, identify when to push or pull a widget, and rotate in the appropriate direction to complete tasks.

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Answer:

I hope this is good enough:

Step-by-step explanation:

I dis graph it just use demo's graphing system.

An ogive is used to plot cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class when displaying quantitative data. Option B.

An ogive is a graph that represents a cumulative distribution function (CDF) of a frequency distribution. It shows the cumulative relative frequency or cumulative frequency of each class plotted against the upper limit of the corresponding class. In other words, an ogive can be used to represent data through graphs by plotting the upper limit of each class interval on the x-axis and the cumulative frequency or cumulative relative frequency on the y-axis.

An ogive is used to display the distribution of quantitative data, such as weight, height, or time. It is also useful when analyzing data that is not easily represented by a histogram or a frequency polygon, and when we want to determine the percentile or median of a given set of data. Based on the information given above, option B: "Cumulative frequency or cumulative relative frequency of each class against the upper limit of the corresponding class" is the correct answer.

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Answer:

The initial amount is the starting amount, which would be 14,000.

Step-by-step explanation: