Answer:
A
Explanation:
A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you.
How big is the force acting on the wire?
A. 4 N
B. 8 N
C. 12 N
D. 16 N
Answer:16
Explanation:
as F=BIL so by placing value's B is magnetic field 4 and i is current 2A and l is length that js 2 m so answer is
Given: i=10A,B=0.15 T,θ=45
∘
and l=2 m
Force on a current carrying wire of finite length =
F
=l(
i
×
B
)
Hence, magnitude of force, F=Bilsinθ
=0.15×10×2×sin45
∘
=
2
3
N
The largest flowers in the world are the Rafflesia Arnoldii, found in Malaysia. A single flower is almost a meter across and has a mass up to 11.0 kg. Suppose you cut off a single flower and drag it along the flat ground. If the coefficient of kinetic friction between the flower and the ground is 0.39, what is the magnitude of the frictional force that must be overcome?
The magnitude of the frictional force that must be overcome is 42.04 N.
What is the magnitude of the frictional force?
The magnitude of the frictional force that must be overcome is calculated by applying Newton's second law of motion as follows;
Mathematically, the formula for the frictional force is given as;
F = μmg
where;
μ is the coefficient of frictionm is the mass of the flowerg is acceleration due to gravityThe magnitude of the frictional force that must be overcome is calculated as;
F = 0.39 x 11 kg x 9.8 m/s²
F = 42.04 N
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how does thermal energy impact enthalpy
Answer:
The concentrations of the reactants and the products. The temperature of the system. The partial pressures of the gases involved (if any)
Explanation:
A plank AB 3m long weighing 20kg and with center of gravity 2m from the end A carries a load of mass 10kg at the end A it rests on two supports CandD.
1, compute the values of the reaction forces R1 and R2 at C and D.
2, how far from D and on which side of it must a mass of 24kg be placed on the plank so as to make the reactions equal? What are their values.
3,without this 24kg what vertical force applied at B will just lift the plank clear of D? What is then the reaction at C.
The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.
1) R1 and R2 at C and D respectively are given by the equation R2 = (m1 + m2)g - R1, where m1 and m2 are the masses of the plank and load, respectively, and g is the acceleration due to gravity. Hence, substituting values R2 = (20 + 10) × 9.81 - R1 = 294.3 - R1. Now, taking moments about D, the following equation can be obtained: (20 × 1 + 10 × 3)g = R1 × 2 + R2 × 3 = 2R1 + 3 × (294.3 - R1) = 882.9 - R1, from which R1 = 343.7 N and R2 = 294.3 - 343.7 = -49.4 N. Since the support at D can only push the plank upwards and cannot pull it downwards, a negative value for R2 implies that the plank is actually being pulled downwards by an external force. Therefore, the value of R2 is not relevant. 2) The total weight of the plank and the load acting at the end A is 20 + 10 = 30 kg. For the reactions at C and D to be equal, the 24 kg mass must be placed at a distance x from D such that x × 30 = 24 × 6, from which x = 12/5 = 2.4 m. Since the 24 kg mass is being placed to the left of the plank, it will cause the reaction at C to decrease and that at D to increase. Thus, if R is the vertical force applied at B, then taking moments about D gives 20g × 1 - 10g × 3 + R × 6 = 0, from which R = 90 N. Taking moments about C gives R × 3 - 10g × 2 = 0, from which R = 66.3 N. 3) The vertical force applied at B that will just lift the plank clear of D is the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D. The weight of the plank and the load acting at the end A is 20 + 10 = 30 kg, and the weight of the part of the plank that is to the right of D is 24 × 1.6 = 38.4 kg. Therefore, the vertical force applied at B that will just lift the plank clear of D is (20 + 10 + 38.4)g = 686.4 N. The reaction at C is zero because the plank is not being supported there anymore. The reaction at D is the same as the weight of the plank and the load acting at the end A plus the weight of the part of the plank that is to the right of D, which is 20 + 10 + 24 × 1.6 = 61.4 kg.For more questions on acceleration
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2. When things happen the force is said to be ————.
Why is a cell phone more likely to break when dropped from a higher height than a lower one?
A cell phone more likely to break when dropped from a higher height than a lower one because it has more potential energy at high height.
What is potential energy?Potential energy is the energy stored by an object as a result of its position relative to other objects, internal tensions, electric charge, or other reasons.
Potential energy is commonly defined as an object's gravitational potential energy, the elastic potential energy of an extended spring, and the electric potential energy of an electric charge in an electric field. The joule is the SI unit of energy.
Although it has connections to the Greek philosopher Aristotle's concept of potentiality, the word potential energy was coined by the 19th-century Scottish engineer and physicist William Rankine.
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A custodian pulls a vacuum 13.5 m
with a 33.9 N force at a 55.0°
angle, against a 14.2 N friction
force. Find the total work done on
the vacuum.
(Unit = J)
Answer:
Horizontal component of pull = (cos 55 x 33.9) = 19.4N.
Net horizontal force = (19.4 - 14.2) = 5.2N.
Work = (fd) = (5.2 x 13.5) = 70.2 Joules.
Rounded to 1 decimal place throughout.
Explanation:
The total work done on the vacuum is 70.2 J.
What is work done?
Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is a custodian pulls a vacuum 13.5 m with a 33.9 N force at a 55.0° angle, against a 14.2 N friction force.
Horizontal component of pull = (cos 55 x 33.9) = 19.4N.
Net horizontal force = (19.4 - 14.2) = 5.2N.
Work done by vacuum will be
Work =5.2 x 13.5
Work =70.2 J
Thus, the total work done on the vacuum is 70.2 J.
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Newton's Third Law of Motion
Answer:
Whenever one body exerts a force on a second body, the first body experiences a force that is equal in magnitude and opposite in direction to the force that it exerts
Explanation:
Answer: According to Khan Academy "Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Explanation: This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. We sometimes refer to this law loosely as action-reaction, where the force exerted is the action and the force experienced as a consequence is the reaction.
We can readily see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool, as illustrated below.
A swimmer pushes on the wall with her feet, which causes the wall to push back on her feet due to Newton's third law."
Hope this helps ^_^ and have a great day
A car starts at a position of 1 km and moves to a final position of -3 km. What is the total distance traveled by the car?
The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.
What is displacement?Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.
There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider
On the number line, we can see the movement as follows
1 0 -1 -2 -3= 4km
Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.
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Q5) Name the unit for expressing nuclear cross-sections.
Answer:
The unit is the barn, which is equal to 10-28 m^2 or 10-24 cm^2
Explanation:
The standard unit for measuring a nuclear cross section (denoted as σ)
3.) A boat is moving south at 15.0, a passenger is walking north along the boat deck at 4.0 and throws a
rock north at 3.0, what is the velocity of the rock when viewed from the boat and the shore? (2)
An organ pipe of length L has one end closed but the other end open. What is the wavelength of the fundamental node emitted?
a. Slightly smaller than 4 L
b. Slightly larger than 4 L c. Roughly equal to 3/2
d. Slightly larger than 2 L
Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores
Explanation:
Give me the real answer
Answer: 12,339
Explanation:
How high would a 8 kg mass need to be lifted to have a potential energy of 400 J?
Explanation:
Potential Energy = m g h
400 J = 8 kg * 9.81 m/s^2 * h
400 / (8 *9.81) = h = 5.1 m
Force= Mass x Acceleration what law is that
The equation "Force = Mass x Acceleration" represents Newton's second law of motion. This law states that the force acting on an object is directly proportional to its mass and the acceleration it experiences. It can be mathematically expressed as F = ma, where F is the force, m is the mass of the object, and a is the acceleration.
How many times larger is the United States water consumption PER PERSON compared to the World water consumption PER PERSON?
The number of times times larger is the United States water consumption PER PERSON compared to the World water consumption PER PERSON is 100 to 175 gallons of water
How does the United States' use of water compare to that of other countries?Every day, the average American uses 100 to 175 gallons of water. We use almost 4 trillion cubic meters of freshwater annually on a global scale! In some areas, agriculture can use up to 90% of the available freshwater.
Although the water resources in the United States are enormous, they are not limitless. Given that the average American's water footprint, or the total amount of water consumed directly and indirectly, is about twice that of the rest of the world, it is extremely important to save and safeguard this water.
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At night, the moon appear smaller when is overhead then when it is on the horizon. This is an example of
Answer:
the brain's size-distance mechanism changes its perceived size and makes the moon appear very large.
Explanation:
the moon is changing its apparent position in depth while the light stimulus remains constant
7. DRAW A PICTURE TO SHOW WORK.
Brandon buys a new Seadoo. He goes 12
km north from the beach. He jumps
wakes for 6 km to the east. Then chases
a boat 12 km south. He then turns and
goes 3 km to the West. What distance
did he cover? What was his
displacement?
The form of energy that can move from place to place across the universe is
this energy is
hydo
Next
On Earth, the main source of
Answer:
The form of energy that can move from place to place across the universe is electromagnetic energy.
Electromagnetic energy is a form of energy that is produced by the movement of electrically charged particles. It is characterized by its wavelength or frequency and can range from gamma rays, X-rays, ultraviolet (UV) rays, visible light, infrared radiation, microwaves, to radio waves.
A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What is the 3250 kg car’s initial velocity calculated to the nearest tenth? Record your answer in the boxes below. Be sure to use the correct place value.
Answer:
2.1 m/s
Explanation:
According to law of conservation of momentum;
m1u1 + m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the common velocity
Given
m1 = 2150kg
m2 = 3250kg
u1 = 10.0m/s
u2 = ?
v = 5.22m/s
Substitute and get u2
2150(10) + 3250u2 = (2150+3250)5.22
21,500 + 3250u2 = 5400(5.22)
3250u2 = 28,188 - 21500
3250u2 = 6688
u2 = 6688/3250
u2 = 2.1 m/s
Hence the 3250 kg car’s initial velocity has an initial velocity of 2.1 m/s
A diffraction grating, ruled with 300 lines per mm, is illuminated with a white light source at normal incidence.
(i) What is the angular separation, in the third-order spectrum, between the 400 nm and 600 nm lines? [5]
(ii) Water (of refractive index 1.33) now fills the whole space between the grating and the screen. What is the angular separation, in the first-order spectrum, between the 400 nm and 600 nm lines? [5]
the expression for diffraction grating allows to find the results for the questions for the angular separation are:
i) The third order is Δθ = 0.203 rad.
ii) The first order with water is Δθ = 0.046 rad.
The diffraction grating is a system formed by a large number of equally spaced lines whose diffraction is given by the expression.
d sin θ = m λ
Where d is the distance between two lines, θ is the angle of diffraction, the order of diffraction and λ is the wavelength.
i) Let's start by looking for the separation between two lines
Let's use a rule of direct proportions. If there are 300 lines in 1 mm, what distance is there between two lines.
d = 1 lines (1 mm / 300 lines) = 3,333 10⁻³ mm
d = 3.333 10⁻⁶ m
Let's find the angle of diffraction for the third order (m = 3) for each wavelength.
λ₁ = 400 nm = 400 10⁻⁹ m
sin θ₁ = \(\frac{m \ \lambda }{d}\)m λ/ d
sin θ₁ = \(\frac{3 \ 400 \ 10^{-9} }{3.333 \ 10^{-6} }\)
θ₁ = sin⁻¹ 0.3600
θ₁ = 0.368 rad
λ₂ = 600 nm = 600 10⁻⁹ m
sin θ₂ = \(\frac{3 \ 600 \ 10^{-9} }{3.333 \ 10^{-6} }\)
θ₂ = sin⁻¹ 0.5401
θ₂ = 0.571 rad
The angular separation is
Δθ = θ₂ - θ₁
Δθ = 0.571 - 0.368
Δθ = 0.203 rad
ii) In this case, the separation between the network and the observation screen is filled with water.
When the rays leave the network they undergo a refraction process, for which they must comply with the relationship.
\(n_i \ sin \theta_1 = n_r \ sin \theta_r\)
The incident side is in the air, therefore its refractive index is n_i = 1 and when it passes into the water with refractive index n_r = 1.33.
Let's start looking for the incident angles for the first order of diffraction.
m = 1
λ₁ = 400 nm
θ₁ = sin⁻¹ \(\frac{1 \ 400 \ 10^{-9}}{3.33 \ 10^{-6}}\)
θ₁ = 0.120 rad
λ₂ = 600 nm
θ₂ = sin⁻¹¹ \(\frac{1 \ 600 \ 10^{-9} }{3.33 \ 10^{-6}}\)
θ₂ = 0.181 rad
we use the equation of refraction.
\(\theta_r\) = sin⁻¹ (\(\frac{n_i}{n_r} \ sin \ \theta_i\) )
λ₁ = 400 nm
θ₁ = sin¹ (\(\frac{1 sin 0.120}{1.33}\)
θ₁ = 0.090 rad
λ₂ = 600 nm
θ₂ =sin⁻¹ \(\frac{1 sin 0.181}{1.33}\)
θ₂ = 0.1358 rad
The angular separation is
Δθ = 0.1358 - 0.090
Δθ = 0.046 rad.
In conclusion using the relation for the diffraction grating we can find the results for the questions about angular separation are:
i) The third order is Δθ = 0.203 rad.
ii) The first order with water is Δθ = 0.046 rad.
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A car with a proper length of 8.0 m passes by. Calculate the contracted length when the speed of the car is 0.89c.
ANSWER
3.65 m
EXPLANATION
Given:
• The proper length of the car, L₀ = 8.0 m
,• The speed of the car, v = 0.89c
Find:
• The contracted length of the car, L
The length contraction of an object, which is the shortening of the actual length of the object when it is moving relative to the observer's frame, is given by the equation,
\(L=L_0\cdot\sqrt{1-\frac{v^2}{c^2}}\)Replace the known values and solve,
\(L=8.0m\cdot\sqrt{1-\frac{(0.89c)^2}{c^2}}=8.0m\cdot\sqrt{1-\frac{0.89^2c^2}{c^2}}=8.0m\cdot\sqrt{1-0.89^2}\approx3.65m\)Hence, the contracted length of the car is 3.65 m, rounded to the nearest hundredth.
What does the force of friction between two objects in context depend on?
The amount of friction depends on the force pushing the surfaces together. If this force increases, the hills and valleys of the surfaces can come into closer contact. The close contact increases the friction between the surfaces.
Solar radiation at the top of the atmosphere is 1340 W/m2, whereas at the surface this number is reduced to about 700 W/m2. This means that about 640 W/m2 is absorbed by the atmosphere. If the atmosphere extends 80 km above the surface, and the radius of the Earth is 3959 miles, determine how much the temperature would increase in the atmosphere by the absorption of the solar radiation. To find the mass of the atmosphere, use the density of air as 1.225 kg/m3. The specific heat of air is 1000 J/kg oC.The temperature change of a substance can be determined by dT =(rate of energy flow) *(# seconds per day)*(area of earth's surface)/(mass of air*specific heat of air).This calculation assumes that the atmosphere is uniform vertically.
Given
Solar radiation at the top of the atmosphere,
\(Q=1340\text{ W/m}^2\)Solar radiation at the bottom of the atmosphere,
\(Q^{\prime}=700\text{ W/m}^2\)Solar radiation absorbed by the atmosphere is
\(\begin{gathered} \\ P=640\text{ W/m}^2 \end{gathered}\)The time, t=24 hr=24x60x60 s
Specific heat,
\(s=\frac{1000J}{kg^oC}\)The radius of the earth,
\(R_1=3959\text{ miles=6371392.89 metres}\)The length with the atmosphere,
\(R_2=6371392.89+80000=6451392.896m\)To find
Determine how much the temperature would increase in the atmosphere by the absorption of the solar radiation
Explanation
Volume of the atmosphere,
\(\begin{gathered} V=\frac{4}{3}\pi(R_2^3-R_1^3) \\ \Rightarrow V=\frac{4}{3}\pi(6451392.896^3-6371392.89^3) \\ \Rightarrow V=4.13\times10^{19}m^3 \end{gathered}\)Now,
Mass
\(m=1.225\times1000=5.06\times10^{19}=5.06\times10^{19}kg\)Thus the change in temperature is
\(dT=\frac{640\times24\times60\times60\times4\pi(6.37\times10^6)^2}{5.06\times10^{19}\times1000}=0.57^oC\)Conclusion
The change in temperature is
\(0.57^oC\)If the social distancing length between two students is doubled from two metered to four meters, does the gravitational force between the two students increase or decrease?
Explain your reasoning!
Answer:
the gravitational force decreases
what is energy and the characteristics
Energy is a fundamental concept in physics that represents the ability or capacity of a system to do work.
It is a scalar quantity, meaning it has magnitude but no specific direction. Energy exists in various forms and can be converted from one form to another. The characteristics of energy include:
1. Forms of Energy: Energy can exist in different forms such as kinetic energy (energy of motion), potential energy (stored energy), thermal energy (heat), chemical energy, electrical energy, and many more.
2. Conservation of Energy: The law of conservation of energy states that energy cannot be created or destroyed; it can only be transformed from one form to another. The total amount of energy in a closed system remains constant.
3. Transfer and Conversion: Energy can be transferred from one object to another or converted from one form to another. For example, electrical energy can be converted into light energy in a light bulb.
4. Units of Measurement: Energy is typically measured in joules (J) in the International System of Units (SI). Other common units include kilowatt-hours (kWh) for larger quantities of energy and calories (cal) for thermal energy.
5. Energy and Work: Energy is closely related to the concept of work. When work is done on an object, energy is transferred to it or from it, resulting in a change in its energy state.
Understanding the nature and characteristics of energy is crucial in various fields, including physics, engineering, and environmental science, as it plays a central role in explaining and analyzing various phenomena and processes.
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iv. When you use a hand pump to inflate the tires of your bicycle, the pump gets warm after a while. Why? What happens to the temperature of the air in the pump as you compress it? Why does this happen? When you raise the pump handle to draw outside air into the pump, what happens to the temperature of the air taken in? Again, why does this happen?reason
Answer:
The temperature rises because for a given volume of gas, a rise pressure of the gas in pressure results in a proportionate rise in the temperature of the gas
Similarly when the handle is raised to draw air causes a fall in pressure that results in proportionate fall in temperature, for a given volume of gas
Explanation:
From Gay-Lussac's law, states that the pressure of a given mass of gas is directly proportional to its Kelvin temperature, provided that the volume is held constant
Mathematically, the law states that Pressure ∝ Temperature, at constant Volume
Therefore;
P₁/T₁ = P₂/T₂
Similarly, by kinetic theory of gases, we have;
The
\(P = \dfrac{n \cdot MW \cdot v_{rms}^2}{3 \cdot V}\)
\(v_{rms} = \sqrt{\dfrac{3 \cdot R \cdot T}{MW} }\)
Therefore, as in order for the hand pump to inflate the bicycle tires, the air in the pump has to be compressed to force it into the tire, thereby increasing the pressure, of the air in a given volume of the pump which results in the raising of the temperature of the air in the pump, which raises the temperature of the wall of the pump.
The temperature of the air in the pump also falls as the pressure in the pump is reduced by raising the pump handle, to reduce the air pressure inside the pump and and allow air to be taken into the pump.
Write the differences between rest and motion
Answer:
Depends on position
Explanation:
Rest:
A body is said to be at rest, if it does not change its position with respect to its surroundings.
Motion:
A body is said to be in motion, if it changes its position with respect to its surroundings.
The state of rest and motion is relative
A heavy solid disk rotating freely and slowed only by friction applied at its outer edge takes 60 seconds to come to a stop. If the disk had twice the radius and twice the mass, but the frictional force remained the same, the time it would it take the wheel to come to a stop from the same initial rotational speed is
The time the wheel would take for the disk with twice the radius and twice the mass to come to a stop would be 480 seconds.
This is because the moment of inertia, which is the measure of an object's resistance to changes in its rotation rate, depends on both the mass and the radius of the disk. Specifically, the moment of inertia of a solid disk is given by
I = 1/2 * mass * radius^2.
Since the disk in question has twice the mass and twice the radius, its moment of inertia will be 8 times greater than the original disk. This means that it will take 8 times longer for the disk to come to a stop under the same frictional force.
Therefore, the time it would take for the disk with twice the radius and twice the mass to come to a stop is 8 * 60 seconds = 480 seconds.
Therefore, the time the wheel would take to come to a stop from the same initial rotational speed If the disk had twice the radius and twice the mass is 480 seconds.
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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m
For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:
a. The volume is 24 m³.
b. weight is 240,000 N,
c. mass is 24,490 kg, and
d. pressure is 23,530 Pa.
a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:
Volume = Length x Width x Depth
Given:
Length = 4 m
Width = 3 m
Depth = 2 m
Substituting the values into the formula, we have:
Volume = 4 m x 3 m x 2 m
Volume = 24 m³
Therefore, the volume of paraffin in the tank is 24 cubic meters.
b) The weight of the paraffin can be calculated using the formula:
Weight = Volume x Density x Acceleration due to gravity
The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:
Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²
Weight = 240,000 N
Therefore, the weight of the paraffin in the tank is 240,000 Newtons.
c) The mass of the paraffin can be calculated using the formula:
Mass = Density x Volume
Substituting the given values:
Mass = 10,000 kg/m³ x 24 m³
Mass = 24,490 kg
Therefore, the mass of the paraffin in the tank is 24,490 kilograms.
d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:
Pressure = Weight / Area
The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:
Area = 4 m x 3 m
Area = 12 m²
Pressure = 240,000 N / 12 m²
Pressure = 20,000 Pa
Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).
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