The direction of the magnetic force is to the right.
What is the magnetic field?The magnetic field is the region in space where the influence of the magnet is felt. The magnetic force is always in the direction of the magnetic field.
We can see from the image, that the direction of the magnetic force is to the right.
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As the amount of charge on either of two charged objects increases, the electric force between the objects decreases.
O True O False
Answer:
False.
Explanation:
provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.
素 Example three
After an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up How far is it
from the take off point?
Solution
Answer:
Let R be the total distance
R²=10.4²+(8.7+2.1)²
R²=10.4²+10.8²
R²=224.8
You square root both sides
R=14.99km
If an airplane takes off, it travels 10.4 km west, 8.7 km north, and 2.1 km up, then using the Pythagorean theorem it is 14.99km from its take-off point.
What is Pythagoras' theorem?Pythagoras' theorem is a fundamental theorem in mathematics that relates to the sides of a right-angled triangle. It states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In equation form, the theorem can be written as:
c² = a² + b²
Where
c =the length of the hypotenuse,
a and b = the lengths of the other two sides.
The theorem is named after the ancient Greek mathematician Pythagoras, who is credited with his discovery and proof. Pythagoras' theorem is widely used in mathematics and has many practical applications in fields such as architecture, engineering, and physics.
Here in the question
We can use the Pythagorean theorem to find the distance from the takeoff point:
Distance = √(West)² + (North+Up)²
Plugging in the given values, we get:
Distance = √(10.4)² +( 8.7 + 2.1)²
Distance ≈ 14.99km
Therefore, the airplane is approximately 14.99km away from the takeoff point.
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Which describes the magnetic field that forms when a wire carries an electric current?
It is in a line perpendicular to the wire.
It is in a line parallel with the wire.
It is in a cylinder around the wire.
It is in a cylinder across the wire.
Answer:
It is in a line parallel with the wire.
Explanation:
trust me
Answer:
b on edge
Explanation:
yes
Select the correct answer from each drop-down menu.
Rocky metallic objects found between the orbits of Mars and Jupiter are(drop down). The largest known of these is(drop down).
Answer:
Blank 1 (asteroids)
Blank 2 (Ceres)
Explanation:
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
What are asteroids?Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]
A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
The correct option from the drop-down menu is asteroids and ceres.
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What are the conditions for a flow to be irotational flow
Answer:
Rotation of a fluid particle can be caused only by a torque applied by shear forces on the sides of the particle. Since shear forces are absent in an ideal fluid, the flow of ideal fluids is essentially irrotational. Generally when the flow is viscid, it also becomes rotational
What is the Momentum of a ball that has a mass of 0.5 kg and a velocity of 20 m/s?
In your business plan, the target market section should clearly identify_____market(s).
A. Both your primary and secondary
B. primary
C. demographic
D. secondary
In your business plan, the target market section should clearly identify both your primary and secondary market(s). The market analysis is basically the target market section of your business plan. It is a thorough examination of the ideal people to whom you intend to sell your products or services.
1. According to its computer, a rocket launched
traveled 1200 m, had an average speed of 100.0
m/s. How-long did the trip take?
Answer:
I think it's = 12 seconds
Explanation:
the formula for speed is:
speed=\(\frac{distance}{time}\) SO, time is equal to:
time=\(\frac{distance}{speed}\)
(sub the numbers in the formula)
distance=1200m, speed=100m/s
time=\(\frac{1200}{100}\)
=12 seconds
Cell phones communicate by means of waves. What are the primary characteristics of those waves that make them suitable for use in cell-phone networks?
A. Long wavelengths
B. Low Frequencies
C. Short Wavelengths
D. High Speed
Answer: Long wavelengths
Explanation:
Mobile phones communicate by transmitting radio waves through a network of fixed antennas called base stations. Radiofrequency waves are electromagnetic fields, and unlike ionizing radiation such as X-rays or gamma rays, can neither break chemical bonds nor cause ionization in the human body.
A football player kicks a ball with an initial velocity of 30 meters per second at an angle of 53° above the horizontal. how long will the ball be in the air for
At time t, the ball attains a height y of
y = (30 m/s) sin(53º) t - 1/2 g t²
where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.
Solve for t when y = 0:
(30 m/s) sin(53º) t - 1/2 g t² = 0
t ((30 m/s) sin(53º) - (4.90 m/s²) t ) = 0
t = 0 or (30 m/s) sin(53º) - (4.90 m/s²) t = 0
We ignore the first solution, since that refers to the moment the ball is kicked.
(30 m/s) sin(53º) - (4.90 m/s²) t = 0
(30 m/s) sin(53º) = (4.90 m/s²) t
t = (30 m/s) sin(53º) / (4.90 m/s²)
t ≈ 4.9 s
how does the statement " silence is golden " relate to ethics in communicating at the workplace.?
Answer:
Being silent most of the time is a good virtue under certain circumstances and environment. It is always advisable to remain quite silent and not be too quick to respond to situations or issues so as to avoid making and saying wrong words.
The ethics in a workplace involves communicating with others with less amount of talking as possible and more of body languages and signs. This is because the workplace is meant to be a serene place.
An airplane takes off at an acceleration of 2m/s2. If it continues accelerating at that rate what will the airplane change in velocity be, in m/s, 60 seconds after take off
The airplane change in velocity be 120 m/sec
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
acceleration = velocity/time
Velocity = acceleration * time
Velocity = 60*2
Velocity = 120 m/sec
The airplane change in velocity be 120 m/sec
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please help meee please please
Answer:
I think it's c but don't know for sure
1. A strobe pattern is made of marks on a piece of paper recorded every 0.1 s. Two adjacent marks near the middle of the pattern are 3.4 cm apart. Use this information to estimate the instantaneous speed at that point.
a wave where particles move parallel to its energy is
Any wave in which the motion of the medium's particles is parallel to the wave's direction is referred to as a longitudinal wave.
Imagine that a slinky is stretched out horizontally across the classroom, and that the left end of the slinky receives a pulse from the left and right vibrations of the first coil. From left to right, energy will start to move through the slinky. The individual coils of the medium will be shifted left and right as the energy moves from left to right. The medium's particles in this instance travel in a direction parallel to the pulse's. A longitudinal wave is this kind of wave. Particle motion is consistently parallel to wave motion in longitudinal waves.
A well-known example of a longitudinal wave is a sound wave moving through air.
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using this free-body diagram, calculate the net force.
The net force of the object using the free body diagram above is 12N, right (option D).
What is net force?Net force is defined as the sum of all the forces acting on an object. Net force can accelerate a mass. Some other force acts on a body either at rest or motion.
The net force is a term used in a system when there is a significant number of forces.
Fnet = F¹+ F² + F³….+ Fn
Where;
F¹, F², F³…Fn are the forces acting on a body
According to this question, a stationary object is given with forces 8N and 10N acting rightward, then force 6N acting leftward.
Fnet = (8 + 10) - 6
Fnet = 18 - 6 = 12N
Therefore, the net force is 12N to the right because it is an unbalanced force.
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cosmic Microwave Background radiation is one piece of supporting evidence for the Big Band Theory. Are these microwaves at the longer or shorter end of the spectrum?
are they long or short?
Answer:
it is long.
Explanation:
I know the answer but I don't know how to explain it
Find the depth in a lake at which the pressure is 173.693 lb/in2.
The depth in the lake of pressure 173.693 lb/in² is 122.45 m.
What is depth?Depth is the distance down either from the top of something to the bottom, or to a distance below the top surface of something.
To calculate the depth in the lake, we use the formula below.
Formula:
h = P/gD........................ Equation 1Where:
h = Depth in the lakeP = Pressure D = Density of waterg = Acceleration due to gravityFrom the question,
Given:
P = 173.693 lb/in² = 1.2×10⁶ N/m²g = 9.8 m/s²D = 1000 kg/m³Substitute these values in to equation 1
h = (1.2×10⁶)/(9.8×1000)h = 122.45 mHence, the depth in the lake is 122.45 m.
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1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.
We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.
The heat lost by the metal is given by
Q1 = m1c1ΔT1
Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.
The heat gained by the ice is given by
Q2 = m2c2ΔT2
Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.
Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2
m1c1ΔT1 = m2c2ΔT2
Solving for c1, we get
c1 = m2c2ΔT2 / (m1ΔT1)
By putting these values we get
c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]
c1 = 0.902 kJ/kg·K
Hence, the specific heat of the metal is 0.902 kJ/kg·K.
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Which of the following does not support the idea of continental drift
A) seafloor spreading
B) magnetic reversals
C) Pangaea
D) Play tectonics
Answer:
B or D
Explanation:
Rex Things dropped his mothers vase out the window of his forth story apartment 18.2 m above the ground. Determine it’s landing speed.
If you let yourself fall from a bridge above the water for .4 seconds your speed is?
Answer:
3.91m/s
Explanation:
We can use the equation h=16t^2 to find the height in feet for a free-falling object. The height from the bridge to the water is h=16(0.4)^2=16(0.16)=2.56 ft
Next, we use the equation v=sqrt(2gh) to determine velocity from vertical height. First we must convert feet to meters as velocity is measured in m/s. 2.56ft is about 0.78 meters. Since h=0.78m from the previous equation and g=9.81m/s^2, then your velocity is v=sqrt(2*9.81*0.78)=sqrt(15.3036)=3.911981595
So, your speed/velocity is approximately 3.91m/s
assignment questions
Answer:
which on a is the question
A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up to be the positive direction, and remember the definition of weight).
The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².
How to calculate acceleration?Acceleration is change of velocity with respect to time (can include deceleration or changing direction).
The acceleration of a body can be calculated by using the following expression;
a = F/m
Where;
a = acceleration (m/s²)F = force (N)m = mass (kg)According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:
a = 4N ÷ 2.55kg
a = 1.57m/s²
Therefore, 1.57m/s² is the acceleration of the object.
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Determine usando ecuación de Bernoulli la Presión P1 necesaria para mantener la condición mostrada dentro del sistema mostrado en la figura, sabiendo que el aceite tiene un s.g =0.45 y el valor de d=90mm.
Answer:
PlROCA
Explanation:
The Olympic record for the men's 400-meter hurdle race is 45.94 seconds. It was set by Karsten Warholm in 2021. His average running speed was 400 = 45.94 28.71 meters per second (distance divided by time equals speed) 1. Make a table and a graph showing how 400 meter race time changes as average speed increases from 2 meters per second to 10 meters per second in steps of one meter per second (in other words, the speed column should go 2, 3, 4, --. 10). Also remember that distance is equal to rate (or speed) times time. d=yt 2. Describe the pattern of change shown in your table and graph 3. Write a rule (equation) showing how to calculate race time, t. for any average speed, s. 4. Which change in speed will reduce rate time the most an increase from 2 to 4 meters per second or an increase from 8 to 10 meters per second? Explain how your answer is illustrated in the shape of your graph.
We are given a distance of 400 meters and we are asked to determine the time to cover this distance for different values of speed. Since we are asked to construct a table, we begin by setting up a column with values of speed that range from 2 meters per second to 10 meters per second, like this:
Now we need to set up another column with the values for time. To do that we will use the fact that the speed is defined as:
\(v=\frac{d}{t}\)Where "v" is speed, "t" is time, and "d" is distance. We can solve for the distance by multiplying both sides by "t":
\(vt=d\)Now we divide both sides by "v":
\(t=\frac{d}{v}\)Now, since the distance is fixed at 400 meters we can replace this value in the equation:
\(t=\frac{400}{v}\)Now we have a relationship that will allow us to determine the value of the time. We just need to replace each of the values on the column for speed into the equation to get the value for the time. Replacing the first value of speed we get:
\(t=\frac{400\text{ m}}{2\text{ m/s}}=200s\)This is the first value for the column of time. The second value is obtained replacing the second value for the speed:
\(t=\frac{400\text{ m}}{3\text{ m/s}}=133.3s\)This is the second value. We continue like this for each of the values and we get the following table:
Now we can plot these values and we obtain the following graph:
3. The rule to calculate race time "t" for any average speed is the one that was determined previously to construct the table, this is:
\(t=\frac{400}{s}\)4. we are asked about the change in time given a change in speed. We can calculate this by subtracting the initial time from the initial speed from the final time at the final speed, this is:
\(\Delta t=t_{v2}-t_{v1}\)Where:
\(\begin{gathered} \Delta t\text{ = change in time} \\ t_{v1}=\text{ time at velocity 1} \\ t_{v2}=\text{ time at velocity 2} \end{gathered}\)Now, the change from 2 to 4 meters per second is the following:
\(\begin{gathered} t_2=200 \\ t_4=100 \end{gathered}\)replacing we get:
\(\Delta t_{2-4}=100-200=-100\)Therefore, the time is reduced in 100 seconds. Now for an increase from 8 to 10 meters per second we get:
\(\begin{gathered} t_8=50 \\ t_{10}=40 \end{gathered}\)Replacing in the formula for change:
\(\Delta t_{8-10}=40-50=-10\)therefore, the time is reduced in 10 seconds. This means that the change from 2 to 4 meters per second will reduce the race time the most. This can be illustrated in the graph as it gets flatter the greater the speed is, meaning that the changes in time are reduced.
5One end of a wire is attached to a ceiling, and a solid brass ball is tied to the lower end. The tension in the wire is 120 N. What is the radius of the brass ball?
Answer:
Explanation:
Force of Tension = (m)(g)
120 = (m)(9.8)
m = volume(density)
120 = (4/3)πr³(0.308)(9.8)
\(\frac{(120)(3)}{(pi)(0.308)(9.8)}\) = r^3
solve
The radius of the brass ball is equal to 6.94 × 10⁻² m when the tension in the wire is 120 N.
What is tension?Tension can be demonstrated as the pulling force transmitted by the means of a string, or a rope or can be described as the action-reaction pair of forces acting at each end of said elements.
The tension in the wire attached to the ceiling will be given by:
T = mg ⇒m = T/g
The radius of the brass ball is given by: \(r =\sqrt[3]{\frac{3V}{4\pi } }\)
The density is given by: ρ = m/V = T/gV
V = T/gρ
Therefore, the expression for the radius can be written as:
\(r =\sqrt[3]{\frac{3T}{4\pi\rho g } }\)
Given the tension in the wire, T = 120 N
The density of the brass is = 8730 Kg/m³
\(r =\sqrt[3]{\frac{3\times 120}{4\times 3.14 \times 8730 \times 9.81 } }\)
r = 6.94 × 10⁻² m
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Translate. The following are your messages to inform categorical syllogisms. Note that they may not be in proper order. Also find and identify the one invalid syllogism.
The syllogisms constructed from the given statements are valid, except for the one syllogism identified as invalid.
Categorical syllogisms are logical arguments that involve two premises and a conclusion, all of which are categorical statements. These statements are formed using categorical propositions that involve classes or categories of objects or concepts.
Let's examine the given statements and identify the valid and invalid syllogisms:
All mumbling is murmuring: This statement indicates that the class of mumbling is entirely contained within the class of murmuring. It can be represented as "All M is M."
All mumbling is nonsensical: This statement suggests that the class of mumbling is entirely nonsensical. It can be represented as "All M is N."
No murmuring is sensical: This statement implies that there is no overlap between the class of murmuring and the class of sensical. It can be represented as "No M is S."
Now, let's construct the syllogisms using these statements:Syllogism 1:
Premise 1: All M is Mumbling
Premise 2: All Mumbling is Nonsensical
Conclusion: Therefore, All M is Nonsensical
This syllogism is valid because it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.
Syllogism 2:
Premise 1: All Mumbling is Murmuring
Premise 2: No Murmuring is Sensical
Conclusion: Therefore, No M is Sensical
This syllogism is also valid as it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.
Syllogism 3:
Premise 1: All Mumbling is Nonsensical
Premise 2: No Murmuring is Sensical
Conclusion: Therefore, No Mumbling is Murmuring
This syllogism is valid as it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.
Invalid Syllogism:
Premise 1: All Mumbling is Murmuring
Premise 2: All Mumbling is Nonsensical
Conclusion: Therefore, All Murmuring is Nonsensical
This syllogism is invalid. It commits the fallacy of undistributed middle, where the middle term (Mumbling) is not properly distributed in either premise, leading to an invalid conclusion.
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Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
A military airplane sometimes needs to refuel in mid-air, and another plane flies above it to add the fuel. If a plane with a mass of 7,800 kg is traveling with a velocity of 30 m/s and refuels by adding an additional 800 kg of jet fuel, what will its new velocity be? (Hint: This is a multi-step problem).
Answer:
See the answers below.
Explanation:
Momentum is defined as the product of mass by velocity, in this way we have the following equation.
\(P=m*v\)
where:
P = momemtum [kg*m/s]
m = mass = 1500 [kg]
v = velocity = 6 [m/s]
\(P = 1500*6\\P=9000 [kg*m/s]\)
Now we have to calculate the momentum of the plane when it travels at 30 [m/s].
\(P_{airplane}=m_{plane}*v_{plane}\\P_{airplane}=7800*30\\P_{airplane}=234000[kg*m/s]\)
Now this same momentum must be conserved, in such a way that the mass is increased but the velocity must decrease for the momentum to be conserved.
\(P=m_{new}*v_{new}\\234000=(7800+800)*v_{new}\\234000=8600*v_{new}\\v_{new}=27.2[m/s]\)
Answer:
1. 9000 kg-m/s
2. 27.2 m/s
which substance do plants use to make energy
Answer:
sugar
Explanation: