technician a says a defective pcv valve may cause rough idle operation. technician b says the pcv system depends upon a properly sealed engine to perform correctly. who is correct?

The kind of attack that the PDC Bank application is subjected to due to compromised data is: Adversarial artificial intelligence

Adversarial artificial intelligence is a form of attack on a neural network where a wrong algorithm is entered into the system to deceive the end user.

The aim of this machine learning method is to deceive the end user.

This is what happens to the PDC Bank when its data was compromised in the course of improving the machine learning accuracy.

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In this exercise we have to calculate the formula that will be able to determine the length of the cantilevered, like this:

\(\sigma_{max}C=\frac{M_{max}C}{I}\)

So to determinated the maximum tensile and compreensive stress due to bending we can describe the formula as:

\(\sigma_b = \frac{MC}{I}\)

Where,

So making this formula for the max, we have:

\(\sigma_c=\frac{MC}{I} \\\sigma_T=-\sigma_c=-\frac{MC}{I}\\\sigma_{max}=M_{max}\\\)

With all this information we can put the formula as:

\(\sigma_{max}C=\frac{M_{max}C}{I}\)

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The correct matching would be:

Mass production system -> focuses on manufacturing large and continuous product runs.

Lean manufacturing system -> focuses on the reduction of waste in the manufacturing process.

Agile manufacturing system -> focuses on the ability to adapt to customer and market changes.

Assembly line production system -> focuses on improving worker efficiency by making tasks short and repetitive.

The mass production system emphasizes the production of a high volume of products in a consistent manner. The lean manufacturing system has the objective of minimizing or eliminating waste.

The agile manufacturing system places great importance on accommodating alterations from customers and the market. The assembly line manufacturing technique enhances worker productivity by assigning brief and repetitive tasks.

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Answer:

A series circuit.

The temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

It should be noted that temperature simply means the measure of hotness and coldness in a body

From the given information, H is the enthalpy of gas on the constant pressure line, m is the mass flow rate and U is the internal energy of gas.

Here, the temperature of the gas in the tank is the ratio of heat capacities times the temperature of gas in the constant pressure line.

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Answer:

A misfire code is a type A DTC.

Explanation:

A misfire code is a type A DTC.

A Misfire generate unburned hydrocarbons thereby increasing the load on the catalytic converter. Misfires are due to incomplete combustion or lack of combustion.

Diagnostic Trouble Code (DTC) is a type of code used by the vehicle’s onboard diagnostics (OBD) system to alert when the vehicle has a problem. Type A DTC is the most serious DTC, this are emissions related.  It requests illumination of the MIL after one failed driving cycle and stores a freeze frame DTC after one failed driving cycle.

Answer:

External diameter = 158.15 mm mm

Internal diameter = 59.31 mm

Explanation:

We are given;

Diameter ratio; d_i = ⅜d_o

Where d_i is internal diameter and d_o is external diameter

Power;P = 375 KW = 375000 W

Rotational speed;N = 100 rpm

Max torque is 20% greater than mean torque; T_max = 1.2T_avg

Shear stress;τ = 60 N/mm²

Length; L = 4m = 4000 mm

Angle of twist; θ = 2° = 2π/180 radians

Modulus of rigidity;G = 0.85 X 10^(5) N/mm²

Formula for the power transmitted by the shaft is;

P = 2πNT_avg/60

Plugging in the relevant values, we have ;

375000 = 2π × 100T_avg/60

T_avg = (375000 × 60)/(2π × 100) = 35809.862 N.m = 35809862 N.mm

Since T_max = 1.20T_avg

Thus, T_max = 1.20(35809862) = 42971834.4 N.mm

Checking for strength, we'll use;

τ = Tr/J_p

Or since r = d/2

It can be written as;

τ = T(d_o)/2J_p - - - (1)

Where T is T_max

But Polar moment of inertia of hollow shaft is;

J_p = [π(d_o)⁴ - π(d_i)⁴]/32

Now, we are told that d_i = ⅜d_o

Thus;

J_p = [π(d_o)⁴ - π(⅜d_o)⁴]/32

J_p = (π/32) × d_o⁴(1 - 3⁴/8⁴)

J_p = 0.0926 d_o⁴

Plugging this for J_p in eq 1,we have;

τ = T(d_o)/2(0.0926d_o⁴)

Making d_o the subject gives;

d_o³ = T/(2 × 0.0926τ)

Plugging in the relevant values to give;

d_o³ = 42971834.4/(2 × 0.0926 × 60)

d_o³ = 3867155.7235421166

d_o = ∛3867155.7235421166

d_o = 156.96 mm

Thus, d_i = ⅜ × 156.96 = 58.86 mm

Checking for stiffness, we'll use;

T/J_p = Gθ/L

Again T is T_max

Plugging in the relevant values, we have;

42971834.4/0.0926 d_o⁴ = (0.85 × 10^(5) × 2π/180)/4000

464058686.825054/d_o⁴ = 0.7417649321

d_o⁴ = 464058686.825054/0.7417649321

d_o⁴ = 625614216.5028806

d_o = ∜625614216.5028806

d_o = 158.15 mm

d_i = ⅜ × 158.15 = 59.31 mm

So we will pick the highest valies.

Thus;

d_o = 158.15 mm

d_i = 59.31 mm

Answer:

that answer is correct

Explanation:

This answer is correct because they explained everything they needed.

Answer:

Blue

Explanation:

You want me to overthink it which is why I think the answer should be the most obvious and not the most complicated

Answer and Explanation:

Your favorite primary color is blue because 1. blue is a primary color, 2. There is a lot of blue in the picture, and 3. You outlined the circle in blue.

Ty for the points lol.

#teamtrees #WAP (Water And Plant)

Answer:

stink

Explanation:

By offering a centralized repository for collecting and managing data, databases can considerably improve an organization's data collection process.

It will be very difficult for organizations to function without the use of data base.

Databases are used to store, organize, and access data of any type. They collect information about people, places, or things. That information is gathered in one place so that it may be studied and analyzed. Databases are simply organized collections of data.

Databases allow us to work efficiently with massive amounts of data. They make data updating straightforward and reliable, and they help with accuracy.

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Answer:

c) median

Explanation:

The lanes of traffic on expressways that flow in opposite directions are divided by a median. Thus, the correct answer is option C.

Expressway lane markings are one-of-a-kind, which means they differ on different roads. Parking or stopping on motorways is prohibited unless on the expressway's shoulder. Cloverleaf, diamond, and trumpet interchanges are the three most common types of expressway interchange.

A median separates traffic lanes on motorways that flow in opposite directions. The highway ahead is divided by a physical barrier or median. The "Divided highway" sign indicates that the two opposing lanes of traffic on the highway ahead are separated by some kind of physical barrier or median, such as a guardrail, concrete barrier, or a strip of land.

Therefore, median divides lanes of traffic on expressways that flow in opposite directions.

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scrity añao devid codicie

Answer: Therefore, the annual depreciation for each year using the double-declining-balance method is $228,000 for the first three years, $194,000 for the fourth year, and $0 for the fifth year. The book value at the end of each year is as follows: $422,000 at the end of year 1, $194,000 at the end of year 2, $228,000 at the end of year 3, $0 at the end of year 4, and $80,000 at the end of year 5.

Explanation:  To calculate the annual depreciation using the double-declining-balance method, we first need to calculate the depreciation rate, which is double the straight-line depreciation rate. The straight-line depreciation rate is calculated as follows:

Depreciation rate = (Cost - Salvage value) / Useful life

Depreciation rate = ($650,000 - $80,000) / 5 years = $114,000 per year

Double-declining-balance depreciation rate = 2 x straight-line depreciation rate = 2 x $114,000 = $228,000 per year

Using this depreciation rate, we can calculate the annual depreciation and book value at the end of each year as follows:

Year 1:

Depreciation = $228,000

Book value = Cost - Depreciation = $650,000 - $228,000 = $422,000

Year 2:

Depreciation = $228,000

Book value = Cost - Depreciation = $650,000 - $228,000 - $228,000 = $194,000

Year 3:

Depreciation = $194,000

Book value = Cost - Depreciation = $650,000 - $228,000 - $194,000 = $228,000

Year 4:

Depreciation = $228,000

Book value = Cost - Depreciation = $650,000 - $228,000 - $194,000 - $228,000 = $0

Year 5:

Depreciation = $0

Book value = Salvage value = $80,000

Answer:

456.2 days

Explanation:

Cv = tv x d²/t

For v>69%

We have tv = -0.933log(1-0.65)-0.0851

= 0.4254-0.0851

= 0.340

d² = (19/2)²

= 90.25

Cv = 0.340x90.25/10

= 3.0685mm²/min

At 40% consolidation

Tv = pi/4 x 0.4²

= 0.126

t = Tv x d²/cv

= 0.126x(4000)²/3.0685

t = 656998/60*24

= 456.2days

So it is going to take 456.2 days for a 4-m thick clay layer in the field to undergo 40% consolidation under the same pressure increment.

According to the given question, technician A is correct.

Who are technicians?

A technician is a worker in a technological field who is skilled in the relevant skill and technique and has a practical understanding of the theoretical principles. Technicians are highly skilled professionals who work in nearly every industry. They service, repair, install, and replace various systems and equipment. Technicians typically work in teams with other skilled workers and must be able to read and communicate effectively.

Water fade occurs as a result of water-soaked brake linings acting as a lubricant, lowering the coefficient of friction between the braking surfaces. And technician A says that water fade changes the coefficient of friction between the brake linings and drums until they dry out.

So technician A is correct.

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Hotel Fire Safety Directors are not authorized to order a full building evacuation of guests. Therefore, option (C) is correct.

Hotel Fire Safety Directors are individuals who are responsible for ensuring the safety of guests and employees in the event of a fire emergency in a hotel or other hospitality establishment.

They are typically appointed by the hotel management and must have knowledge of fire safety regulations and protocols, as well as the ability to lead and manage a team during an emergency.

Hotel Fire Safety Directors are responsible for implementing and maintaining the Fire Safety Plan, which includes conducting fire drills, training and supervising the Fire Brigade, and distributing applicable parts of the Fire Safety Plan to all employees. They must also work closely with the local fire department to ensure compliance with local fire safety regulations and protocols.

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The experimental probability of Brandy rolling a strike in the first frame of the next game is 1/5.

Given that Brandy rolls a strike in 2 out of 10 frames in a game, we can calculate the experimental probability of her rolling a strike in the first frame of the next game. Since there are 10 frames in a game, the probability of Brandy rolling a strike in any given frame is 2/10 or 1/5. Therefore, the experimental probability of her rolling a strike in the first frame of the next game is also 1/5. This is based on the assumption that her performance in each frame is independent of the others, and the probability remains constant from frame to frame.

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Answer:

2)

a)  to the right of the dipole    E_total = kq [1 / (r + a)² - 1 / r²]

b)To the left of the dipole      E_total = - k q [1 / r² - 1 / (r + a)²]

c) at a point between the dipole, that is -a <x <a  

      E_total = kq [1 / x² + 1 / (2a-x)²]

d) on the vertical line at the midpoint of the dipole (x = 0)

E_toal = 2 kq 1 / (a ​​+ y)² cos θ

Explanation:

2) they ask us for the electric field in different positions between the dipole and a point of interest. Using the principle of superposition.

This principle states that we can analyze the field created by each charge separately and add its value and this will be the field at that point

Let's analyze each point separately.

The test charge is a positive charge and in the reference frame it is at the midpoint between the two charges.

a) to the right of the dipole

The electric charge creates an outgoing field, to the right, but as it is further away the field is of less intensity

           E₊ = k q / (r + a)²

where 2a is the distance between the charges of the dipole and the field is to the right

the negative charge creates an incoming field of magnitude

           E₋ = -k q / r²

The field is to the left

therefore the total field is the sum of these two fields

           E_total = E₊ + E₋

           E_total = kq [1 / (r + a)² - 1 / r²]

we can see that the field to the right of the dipole is incoming and of magnitude more similar to the field of the negative charge as the distance increases.

b) To the left of the dipole

The result is similar to the previous one by the opposite sign, since the closest charge is the positive one

E₊ is to the left and E₋ is to the right

          E_total = - k q [1 / r² - 1 / (r + a)²]

We see that this field is also directed to the left

c) at a point between the dipole, that is -a <x <a

In this case the E₊ field points to the right and the E₋ field points to the right

                      E₊ = k q 1 / x²

                      E₋ = k q 1 / (2a-x)²

                      E_total = kq [1 / x² + 1 / (2a-x)²]

in this case the field points to the right

d) on the vertical line at the midpoint of the dipole (x = 0)

    In this case the E₊ field points in the direction of the positive charge and the test charge

    in E₋ field the ni is between the test charge and the negative charge,

the resultant of a horizontal field in zirconium on the x axis (where the negative charge is)

                      E₊ = kq 1 / (a ​​+ y) 2

                      E₋ = kp 1 / (a ​​+ y) 2

                      E_total = E₊ₓ + E_{-x}

                      E_toal = 2 kq 1 / (a ​​+ y)² cos θ

e) same as the previous part, but on the negative side

                        E_toal = 2 kq 1 / (a ​​+ y)² cos θ

When analyzing the previous answer there is no point where the field is zero

The different configurations are outlined in the attached

3) We are asked to repeat part 2 changing the negative charge for a positive one, so in this case the two charges are positive

a) to the right

in this case the two field goes to the right

           E_total = kq [1 / (r + a)² + 1 / r²]

b) to the left

            E_total = - kq [1 / (r + a)² + 1 / r²]

c) between the two charges

E₊ goes to the right

E₋ goes to the left

            E_total = kq [1 / x² - 1 / (2a-x)²]

d) between vertical line at x = 0

E₊ salient between test charge and positive charge

           E_total = 2 kq 1 / (a ​​+ y)² sin θ

In this configuration at the point between the two charges the field is zero

Solution :

1. PL \($= \frac{11.53 - 10.49}{10.49 - 4.5} \times 100$\)

       = 17.36 %

2. Liquid limit at 25 number of blows,

  \($LL = \frac{(26-25)\times 49.8 + (25 - 2.17) \times 47.5}{26-17}$\)

       \($= 47.75 $\) %

Since 84 % of the passes the number 200 sieve the soil is immediately fine grained and MI, OI or CI because LL = 47.75 % > 35%

Therefore, the Plasticity index, PI  \($=47.75 - 17.36 = 30.39$\) %

Equation of A-line \($= 0.73 \times [47.75 - 20]$\)

                             \($=20.25 $\) %

Thus the soil lies above the A-line, that is soil is medium compressible clay ---- CI

The bode plot for this inverting 741 based amplifier would show a straight line with a slope of -20 dB/decade starting at the cut off frequency of 1591.55 Hz.

To determine the values of R2 and cut off frequency for the inverting 741 based amplifier with a gain of 100 and input impedance of 1000 ohms (R1), we can use the formula:

Gain = -R2/R1

Rearranging this formula, we get:

R2 = -Gain x R1 = -100 x 1000 = -100,000 ohms

Next, we can calculate the cut off frequency using the formula:

f_cutoff = GBPinverting / (2π x Gain)

Substituting the given values, we get:

f_cutoff = 10^6 Hz / (2π x 100) = 1591.55 Hz

Therefore, the value of R2 is -100,000 ohms and the cut off frequency is 1591.55 Hz.

In a bode plot, the relation between frequency and gain can be depicted by a straight line with a slope of -20 dB/decade. This means that for every increase in frequency by a factor of 10, the gain will decrease by a factor of 100 (i.e. 20 dB). Therefore, the bode plot for this inverting 741 based amplifier would show a straight line with a slope of -20 dB/decade starting at the cut off frequency of 1591.55 Hz.

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I inferred you meant emerging technologies we see today.

Explanation:

1. 3D Printing

A three dimensional printing allows a digital model to be printed (constructed) into a physical object.

A box, an industrial design and many more could be printed within minutes.

2. AI voice recognition devices

Another trend in the tech world is the rise in artificial intelligence been used in voice recognition devices that not only recognize one's voice but also take commands from the user.

This technology allows one to listen to the internet, such as listening to music online.

The tech world is ever changing with new technology beyond one's consumption on the increase daily.

As the distance between two charged objects increases, the strength of the electrical force between the objects decreases.

This is known as Coulomb's inverse square law, which states that the force between two charged objects is inversely proportional to the square of the distance between them.Mathematically, the force between two charged objects is given by the equation F = k * (q1 * q2) / r^2, where F is the force, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges on the two objects, and r is the distance between them.As the distance between the objects increases (r gets larger), the force between them decreases (F gets smaller). Conversely, if the distance between the objects decreases, the force between them increases. Therefore, option (d) is the correct answer.

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Answer:

a) The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

b) The change in diameter of the specimen is  - 0.015 mm

Explanation:

Given the data  in the question;

(a) The amount by which this specimen will elongate in the direction of the applied stress.

First we find the area of the cross section of the specimen

A = \(\frac{\pi }{4}\) d²

our given diameter is 20.5 mm so we substitute

A = \(\frac{\pi }{4}\) ( 20.5 mm )²

A = 330.06 mm²

Next, we find the change in length of the specimen using young's modulus formula

E = σ/∈

E = P/A × L/ΔL

ΔL = PL/AE

P is force ( 46300 N), L is length ( 201 mm ), A is area ( 330.06 mm² ) and E is  elastic modulus (60.5 GPa) = 60.5 × 10⁹ N/m² = 60500 N/mm²

so we substitute

ΔL = (46300 N × 201 mm) / ( 330.06 mm² × 60500 N/mm² )

ΔL =  0.466 mm

Therefore, The amount by which this specimen will elongate in the direction of the applied stress is 0.466 mm

(b) The change in diameter of the specimen. Indicate an increase in diameter with a positive number and a decrease with a negative number.

Using the following relation for Poisson ratio

μ = -  Δd/d / ΔL/L

given that Poisson's ratio of the metal is 0.33

so we substitute

0.33 = -  Δd/20.5 / 0.466/201

0.33 = -  Δd201 / 20.5 × 0.466

0.33 = - Δd201  / 9.143

0.33 × 9.143 =  - Δd201

3.01719 = -Δd201

Δd = 3.01719 / - 201

Δd  = - 0.015 mm

Therefore, The change in diameter of the specimen is  - 0.015 mm

Answer:

The first Machine Process is Turning.

Explanation:plz mark brainliest if i am right

Answer:

I believe its turning.

In Ethernet networking, a collision happens when multiple devices transmit data simultaneously, and their signals overlap. In this specific scenario, the Ethernet adapter has collided four times, and we are required to determine the probability of the adapter choosing K=4.

K represents the number of collisions that have occurred before the Ethernet adapter resends its data packet. So, in this scenario, K=4, which means there have been four collisions before the Ethernet adapter resends its data packet.

The probability of K=4 can be calculated using the following formula:

P(K=4) = p^k (1-p)^(n-k) / nCk

where,

p is the probability of collision.

n is the total number of attempts to send the data packet.

k is the number of collisions.

Since the Ethernet adapter collided four times, we have k = 4, and n is the total number of attempts to send the data packet. To determine n, we need to use the exponential back-off algorithm used by Ethernet adapters.

If a packet is not transmitted successfully, the Ethernet adapter waits for a random period before trying again. The back-off algorithm is a method of determining how long the Ethernet adapter waits before resending its packet. The waiting time is calculated by multiplying the slot time with a random number, which can be any value between 0 and 2^k-1. So, if k = 4, the maximum random delay can be 2^4-1 = 15 times the slot time. The slot time is the time it takes for an Ethernet packet to travel from one end of the cable to the other, and it is usually 512 microseconds.

Therefore, the maximum delay that an Ethernet adapter might randomly select to wait if it has collided 24 times is:

Maximum delay = 15 × Slot time

= 15 × 512 μs

= 7680 μs

Thus, the maximum delay an Ethernet adapter might randomly select to wait if it has collided 24 times is 7680 microseconds.

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