To calculate the minimum number of bits required to achieve a specific resolution in an analog-to-digital converter (ADC), we can use the formula:
N = log2 (Range/Resolution)
Where N is the number of bits, Range is the maximum voltage range, and Resolution is the desired resolution.
In this case, the maximum voltage range is ±115V. However, it is not specified what resolution you want to achieve. To calculate the minimum number of bits for a specific resolution, please provide the desired resolution in volts. In addition, please provide the number of discrete levels you want to represent in the digital signal.
two technicians are describing how an air-conditioning system gets rid of the heat. Technician A says that heat always flows from the hotter to the colder object. Technician B says that as refrigerant evaporates, it absorbs heat as it changes from a liquid to a gas. which technician is correct?
Based on the information provided by these technicians, both of them are correct.
How does heat flow?According to heating, ventilation, and air conditioning (HVAC), heat in an air-conditioning system generally flows from the hotter object to the colder object.
As the refrigerant evaporates in a small radiator-type unit (evaporator), it absorbs heat as it changes phase from liquid to gas. Also, as the heat is being absorbed by the refrigerant, the small radiator-type unit (evaporator) becomes cold.
In conclusion, we can logically deduce that both of them are correct.
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A typical discounted price of a AAA battery is $0.75. It is designed to provide 1.5 volts and 1.0 amps for about an hour. Now we multiply volts and amps to obtain power of 1.5 watts from the battery. Thus, it costs $0.75 for 1.5 Watt-hours of energy. How much would it cost to deliver one kilo Watt-hour? How does this compare with the cost of energy from your local electric utility at $0.10 per kilo Watt-hour?
Answer:
gh fjh,vx j ahj ds djv dk
Explanation:
doing for points
The Cost of 1 kilowatt hour of energy at the rate of $0.75 per 1.5 watt hour is $500 which is 5000 times greater than the cost of energy at $0.10 per kilowatt hour.
Battery power = Current × Voltage
Cost of 1.5 Watt-hour = $0.75
Converting Energy to Watt - hour :
1 kilowatt = 1000 watt
1 kilowatt hour = 1000 watt - hour
Hence,
Cost of 1 kilowatt - hour = 1000 watt - hour can be calculated thus :
1.5 Watt-hour = $0.75
1000 Watt-hour = c
Cross multiply :
1.5c = $0.75 × 1000
1.5c = 750
c = 750 / 1.5
c = 500
Therefore, cost of 1 kilowatt - hour of energy will be $500
Comparing the cost of Energy at $500 per Kilo-Watt hour to Cost at $0.10:
$500 / $0.10 = 5000
Therefore, the cost of energy at $500 per kilowatt hour is 5000 times greater than cost at $0.10 per kilowatt hour.
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Identify three architectural structures, natural or man made, that have withstood the test of time. describe the geometric shapes that they represent or contain.
The three architectural structures, natural or man made, that have withstood the test of time. describe the geometric shapes that they represent or contain are statues.
How are geometric shapes utilized in architecture?Architects use geometry to take a look at and divide areas in addition to draft specified construction plans. Builders and engineers depend upon geometric concepts to create systems safely. Designers practice geometry (in conjunction with color and scale) to make the aesthetically appealing areas inside. Applying geometry in the layout is unavoidable.
Man-Made systems can consist of seawalls, breakwaters, harbor walls, pontoons and piers, to say a few. These may be crafted from a whole lot of substances now no longer constrained to wood, concrete, or metal, in addition to herbal rock that has been installed vicinity as a sea defence.
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What did 15-year-old jack invent? why?
what was the most important lesson the teams learned when participating in the extreme by design projects?
what tools did the teams use to learn about the problems they were to solve?
what problem that the team asked to solve in this episode? why?
At the age of 15, Jack Andraka invented a new, non-invasive, paper-based test for the early detection of pancreatic cancer. He was inspired to create this device due to the death of a family friend from the disease. He was also motivated by the fact that the majority of pancreatic cancer cases are diagnosed too late for effective treatment.
What was the most important lesson the teams learned when participating in the extreme by design projects?The most important lesson the teams learned when participating in the Extreme by Design projects was the importance of collaborative problem-solving. Working in teams to solve complex problems with the help of mentors and professionals, the teams learned to effectively communicate and trust each other while also understanding the importance of planning and flexibility. This was an invaluable lesson that the teams took with them in their future endeavors.
What tools did the teams use to learn about the problems they were to solve?The teams used a variety of tools to learn about the problems they were to solve. These included research and interviews with experts, visits to relevant sites, analysis of existing data and trends, and the use of digital tools like mapping, 3D modeling, and virtual reality. Additionally, the teams used the design thinking process as a way to think critically and creatively when solving problems.
What problem that the team asked to solve in this episode?In this episode, the team was asked to solve the problem of how to create a sustainable and affordable housing solution for low-income families in San Francisco. This was an important problem because San Francisco is facing an affordable housing crisis, with rising housing costs making it difficult for many people to find a place to live. The team sought to create a solution that would help provide secure housing for those in need.
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A milling circuit consists of a primary SAG mill that is in open circuit. This is then followed by 2 secondary ball mills in parallel. The product from the SAG mill is fed to the ball mills, with the product from the ball mills being combined and classified in cyclones. The underflow from the cyclones is recycled, with the overflow forming the feed to the flotation circuit.
a) Draw the circuit, labelling items.
The milling circuit has a feed rate of 1 500 t/hr. Consider 2 size classes, above and below 75 microns. The feed has 25% passing 75 microns and each of the mills breaks 50% of the material in the feed above 75 microns to below 75 microns. The partition number for the particles above 75 microns is 0.75, while that below 75 microns is 0.25.
b) Carry out a mass balance to calculate the mass rate of both size fraction in each stream. What is the feed rate to each of the ball mills? What is the percentage passing 75 microns in the circuit product/flotation feed? This milling circuit’s feed has 80% passing 1 cm and the final feed to the flotation circuit has 80% passing 60 microns.
The correct answer is a) Here is a diagram of the milling circuit with labels: The product from the SAG mill is fed to the two ball mills in parallel, with the product from the ball mills being combined and classified in cyclones. The underflow from the cyclones is recycled, and the overflow goes to the flotation circuit.
To calculate the mass rate of each size fraction in each stream, we can start with the total feed rate of 1,500 t/hr. Since 25% of the feed is below 75 microns, that means 75% of the feed is above 75 microns. Of that 75%, 50% will be broken down in the SAG mill to below 75 microns, while the remaining 50% will be broken down in the two ball mills in parallel. Therefore: Mass rate of particles above 75 microns in feed = 1,500 x 0.75 = 1,125 t/hr Mass rate of particles below 75 microns in feed = 1,500 x 0.25 = 375 t/hr Mass rate of particles above 75 microns in SAG mill product = 1,125 x 0.5 = 562.5 t/hr Mass rate of particles below 75 microns in SAG mill product = 1,125 x 0.5 + 375 = 937.5 t/hr Mass rate of particles above 75 microns in each ball mill product = 562.5 / 2 = 281.25 t/hr Mass rate of particles below 75 microns in each ball mill product = 375 / 2 = 187.5 t/hr Mass rate of particles above 75 microns in combined ball mill product = 562.5 t/hr Mass rate of particles below 75 microns in combined ball mill product = 375 t/hr + 187.5 t/hr = 562.5 t/hr Mass rate of particles above 75 microns in cyclone overflow = 562.5 t/hr x 0.95 = 534.38 t/hr (assuming a 5% bypass) Mass rate of particles below 75 microns in cyclone overflow = 562.5 t/hr x 0.05 + 375 t/hr x 0.95 = 393.75 t/hr (assuming a 5% bypass) Mass rate of particles above 75 microns in cyclone underflow/recycle = 562.5 t/hr x 0.05 = 28.13 t/hr Mass rate of particles below 75 microns in cyclone underflow/recycle = 375 t/hr x 0.05 + 187.5 t/hr = 205.63 t/hr To calculate the feed rate to each ball mill, we can use the mass rate of particles below 75 microns in the combined ball mill product, which is 562.5 t/hr. Since there are two ball mills in parallel, the feed rate to each ball mill will be: Feed rate to each ball mill = 562.5 t/hr / 2 = 281.25 t/hr Finally, to calculate the percentage passing 75 microns in the circuit product.
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The modifications of superheat and reheat for a vapor power plant are specifically better for the operation which of the following components. Pick one and briefly explain.
a.Condenser
b.Boiler
c.Open feedwater heater
d.Turbine
e.Electric generator
The modifications of superheating and reheat for a vapor power plant are specifically better for the operation which of the following components b.Boiler.
What are the primary additives in the vapour strength cycle?There are 5 steam strength cycles: The Carnot cycle, the easy Rankine cycle, the Rankine superheat cycle, the Rankine reheat cycle and the regenerative cycle.
Central to expertise the operation of steam propulsion is the primary steam cycle, a method wherein we generate steam in a boiler, increase the steam via a turbine to extract work, condense the steam into water, and sooner or later feed the water again to the boiler.Reheat now no longer best correctly decreased the penalty of the latent warmness of vaporization in steam discharged from the low-stress quit of the turbine cycle, however, it additionally advanced the first-rate of the steam on the low-stress quit of the mills via way of means of decreasing condensation and the formation of water droplets inside the turbine.Read more about the Boiler:
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A machine used to shred cardboard boxes for composting has a first cost of $10,000, an AOC of $7000 per year, a 3-year life, and no appreciable salvage value. Assume you were told that the service provided by the machine will be needed for only 5 years, which entails a repurchase and retention for only 2 years. What salvage value, S, is required after 2 years in order to make the 2-year AW value the same as it is for its 3-year life cycle AW? Assume i = 10% per year. Solve using factors and, if assigned, using a spread- sheet and Goal Seek.
Two friends are playing golf. The first friend hits a golf ball on level ground with an initial speed of 47.0 ms at an angle of 35.0∘ above the horizontal.
(a) Assuming that the ball lands at the same height from which it was hit, how far away from the golfer does it land? Ignore air resistance.
(b) The second friend hits another golf ball with the same initial speed as the first, but the initial velocity of the ball makes an angle with horizontal that is greater than 45 degrees. The second ball, however, travels the same horizontal distance as what you found in part (a), and it too lands at the same level from which it was hit. What was the angle in degrees above horizontal of the initial velocity of this second golf ball? Ignore air resistance.
Answer:
A) 211.81 m
B) 65°
Explanation:
We are told that the first friend hits a golf ball on level ground with an initial speed of 47 m/s at an angle of 35° above the horizontal.
Thus;
speed; u = 47 m/s
Projection angle; θ = 35°
A) We want to find how far away from the golfer the ball lands. This is simply the range. Range in projectile motion is given by the formula;
R = (u²•sin 2θ)/g
Plugging in the relevant values, we have;
R = (47² × sin(2 × 35))/9.8
R = 211.81 m
B) We are told that the second ball, travels the same horizontal distance as what is found in part (a).
Thus, R remains 211.81 m
Thus, the angle above horizontal of the initial velocity of this second golf ball will be;
90° - projection angle(θ) = 90 - 35 = 65°
An aluminum block weighing 28 kg initially at 140°C is brought into contact with a block of iron weighing 36 kg at 60°C in an insulated enclosure. Determine the final equilibrium temperature and the total entropy change for this process. The specific heat of aluminum at 400 K is cp = 0.949 kJ/kg·K. The specific heat of iron at room temperature is cp = 0.45 kJ/kg·K.
Answer:
The equilibrium temperature is 109.7°C
The total entropy change for the process is 0.23 kJ/K
Explanation:
The parameters given are;
The initial temperature of aluminium, T₁ₐ = 140°C = 413.15 K
Mass, m₁, of aluminium block = 28 kg
The specific heat of aluminium, c₁, at 400 K = 0.949 kJ/(kg·K)
The initial temperature of iron, T₁ₙ = 60°C = 333.15 K
Mass, m₂, of iron block = 36 kg
The specific heat of iron, c₂, at room temperature = 0.45 kJ/(kg·K)
The heat lost by the aluminium = Heat gained by the iron
The heat lost by the aluminium = m₁ × c₁ × (T₁ₐ - Tₓ)
The heat lost by the aluminium = 28 × 0.949 × (413.15 - Tₓ)
The heat gained by the iron = m₂ × c₂ × (Tₓ - T₁ₙ)
The heat gained by the iron = 36 × 0.45 × (Tₓ - 333.15)
Hence;
28 × 0.949 × (413.15 - Tₓ) = 36 × 0.45 × (Tₓ - 333.15)
26.572 × (413.15 - Tₓ) = 16.2 × (Tₓ - 333.15)
∴ (26.572 + 16.2) × Tₓ = 26.572 × 413.15 + 16.2 × 333.15
42.772·Tₓ = 16375.2518
Tₓ = 382.85 K = 109.7°C
The total entropy change of the process is given by the following relation;
\(\Delta S = \Delta S_{Fe} + \Delta S_{Al}\)
\(=m_{1}c_{1}ln\dfrac{T_{x}}{T_{1n}}+m_{2}c_{2}ln\dfrac{T_{x}}{T_{1a}}\)
\(=28 \times 0.949 \times ln\dfrac{382.85}{413.15}+36 \times 0.45 \times ln\dfrac{382.85}{333.15} = 0.23 \, \dfrac{kJ}{K}\)
an increasingly popular alternative for remote access to web-enabled applications is -based vpns.
SSL based VPNs are becoming a more popular option for remote access to web-enabled applications.
What is SSL based VPN?A Secure Sockets Layer Virtual Private Network (SSL VPN) is a virtual private network (VPN) that uses the Secure Sockets Layer (SSL) protocol to establish a secure and encrypted connection over a less secure network, such as the Internet.Whereas an IPsec VPN allows connections between an authorised remote host and any system within the enterprise perimeter, an SSL VPN allows connections only between authorized remote hosts and specific services provided within the enterprise perimeter.Because OpenVPN is an SSL VPN, it is incompatible with IPSec, L2TP, and PPTP. Because the IPSec protocol is designed to be implemented as a modification to the IP stack in kernel space, each operating system requires its own IPSec implementation.To learn more about SSL refer to :
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A___ remote control can be an advantage to an
operator who is welding close to the power source.
•wireless
•corded
•cable technology
•none of these
Answer:
Wireless
Explanation:
A wireless remote control can be an advantage to an operator who is welding close to the power source. Hence, option A is correct.
What is wireless remote control?An electrical device used to wirelessly and remotely operate another device is a remote control, often known as a remote or clicker. Consumer gadgets, such as television sets, DVD players, and other home appliances, can be controlled by a remote control.
In the current electronic market, remote control systems fall into three primary categories: IR-based systems, RD-based systems, and BT-based systems. the receiver and the remote must be lined up exactly for infrared, also known as IR.
IR, on the other hand, is unable to pass through a number of materials but can operate over a much wider spectrum. This allows the user far greater freedom and control in environments with challenging terrain and obstacles.
Thus, option A is correct.
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Based on the concept that it is better to prevent falls happening in the first place, which of the following safety methods meets that criteria?
Answer:fall arrest harness
Explanation:cuz it’s just right
Nebraska Furniture Mart sells 5,500 chairs of a particular style each year. The chairs are purchased from the factory at a cost of $45. The accounting department has estimated the annual inventory carrying cost rate to be 0. 4. Labor, mail, and receiving costs per order are estimated at $125. Determine the optimal order quantity for Nebraska Furniture Mart
The optimal order quantity for Nebraska Furniture Mart is 6,250 chairs. This can be calculated by using the Economic Order Quantity (EOQ) formula:
EOQ = √(2*Annual Demand*Order Cost) / Carrying Cost
EOQ = √(2*5,500*125) / 0.4
EOQ = 6,250 chairs
What is EOQ?
Economic Order Quantity (EOQ) is a model that helps organizations determine the optimal quantity of goods to order in order to minimize the overall costs associated with inventory management. EOQ models look at the balance between ordering costs, which are the costs associated with placing an order for goods, and holding costs, which are the costs associated with keeping the goods in inventory.
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Is a 10 foot ladder long enough to safely reach a landing that is 9 feet above the adjacent floor
Answer:
Definitely not
Explanation:
You should have 1-2 feet of extra ladder on a flat surface so 1 foot on an adjacent floor is a no no
What is the inconvenient truth about electric vehicles?
While electric vehicles (EVs) offer many benefits over traditional gasoline-powered cars, there are some inconvenient truths about EVs that are worth considering:
Limited driving range: EVs have a limited driving range compared to gasoline-powered cars. Even the most advanced EVs on the market today typically have a range of around 300-400 miles on a single charge. This means that long-distance trips require careful planning and may involve multiple stops for charging.Charging infrastructure: The charging infrastructure for EVs is not yet as idespread or convenient as the gasoline refueling infrastructure. While many public charging stations are available, they may not be located in convenient locations, and charging times can be slow.Upfront cost: The upfront cost of an EV is generally higher than that of a comparable gasoline-powered car. Although the cost of batteries has been declining in recent years, it still represents a significant portion of the total cost of an EV.Battery degradation: Like all batteries, the batteries in EVs degrade over time, which can reduce their driving range and performance.
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If the probability of a bit error is p, what is the probability of a single, double, and triple error in a 10-bit word? Express it in terms of p.
Answer:
single bit error: 10pdouble bit error: 45p²triple bit error: 120p³Explanation:
The probability of n bits being in error is 10Cn × p^n, where ...
10Cn = 10!/(n!(10-n!))
10C1 = 10
10C2 = 45
10C3 = 120
This is the product of the probability that n bits can be in error and the number of ways that n bits can be chosen from the 10 in the word.
n = 1: 10p
n = 2: 45p²
n = 3: 120p³
How many different welding processes are in use?
There are basically five types of welding namely:
a)Gas Metal Arc Welding (GMAW/MIG)
b)Friction welding,
c)ELECTRON BEAM WELDING
d) LASER BEAM WELDING
e) RESISTANCE WELDING
What is welding?
Welding is a fabrication process in which two or more parts are joined together using of heat, pressure, or both to form a joint as the parts cool. materials to be welded include metals, thermoplastics, and wood.
Types of welding processes
a)Gas Metal Arc Welding (GMAW/MIG)
Used mainly for joining metals like stainless steel, nickel, copper alloys, aluminum, titanium, and cobalt.
b)Friction welding
This is a technique used to join materials using mechanical friction. this can be used to join wood, steel, and aluminum.
c)ELECTRON BEAM WELDING
This process uses a mean of high-velocity electrons to combine materials this can be used to join thick sections in the aerospace, automotive, rail, and nuclear power industry.
d)LASER BEAM WELDING
this is used to combine pieces of metal or thermoplastics.
e) RESISTANCE WELDING
This is a process that joins metals by applying pressure and passing a current through them for a period of time.
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# Structure Mechanics.
Draw the internal force (axial force, shear force and moment) diagrams of the frame.
2. A silo (base not included) is to be constructed in the form of a cylinder surmounted by a hemisphere. The cost of construction per square unit
of surface area is twice as great for the for the hemisphere as it is for the cylindrical side wall. Determine the dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum. Neglect the thickness of the silo and waste in construction.
An extremum is a point where the function has its highest or lowest value, and at which the slope is zero.
The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum is as follows;
Height of cylinder = 2 × Radius of cylinderReason:
The given parameters are;
Form of silo = Cylinder surmounted by a hemisphere
Cost of construction of hemisphere per square unit = 2 × The cost of of construction of the cylindrical side wall
Required:
The dimensions to be used if the volume is fixed and the cost of construction is to be kept to a minimum
Solution:
The fixed volume of the silo, V, can be expressed as follows;
\(V = \pi \cdot r^2 \cdot h + \dfrac{2}{3} \cdot \pi \cdot r^3\)
\(h = \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 }\)Where;
h = The height of the cylinder
r = The radius of the cylinder
The surface area is, Surface Area = 2·π·r·h + 2·π·r²
The cost, C = 2·π·r·h + 2×2·π·r² = 2·π·r·h + 4·π·r²
Therefore;
\(C = 2 \times \pi \times r\times \dfrac{V - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } + 4 \cdot \pi \cdot r^2 = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)
\(C = \dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r}\)At the minimum value, we have;
\(\dfrac{dC}{dr} =0 = \dfrac{d}{dr} \left(\dfrac{8 \cdot r^3 \cdot \pi + 6 \cdot V}{3 \cdot r} \right) = \dfrac{16 \cdot r^3 \cdot \pi - 6 \cdot V}{3 \cdot r^2}\)Which gives;
16·π·r³ = 6·V
\(V = \dfrac{16 \cdot \pi \cdot r^3}{6} = \dfrac{8 \cdot \pi \cdot r^3}{3}\)Which gives;
\(h = \dfrac{\dfrac{8 \cdot \pi \cdot r^3}{3} - \dfrac{2}{3} \cdot \pi \cdot r^3 }{\pi \cdot r^2 } = 2 \cdot r\)
h = 2·r
The height of the silo, h = 2 × The radius, 2
Therefore, the dimensions to be used if the volume is fixed and the cost is to be kept to a minimum is, height, h = 2 times the radius
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T/F an array index cannot be of the double, float or string data types.
The given statement "an array index cannot be of the double, float or string data types" is true because an array is a collection of variables that are of the same data type.
Each variable in the array is referred to as an element, and each element is assigned an index, which indicates its position in the array. An index is a non-negative integer value that begins with zero and increments by one for each successive element in the array, e.g. array[0], array[1], array[2], etc.
The length of an array is determined by the number of elements it contains. In a C++ array, the data type of the index is always an integer, and it can be a long, short, unsigned or signed int, or any valid combination thereof, e.g. int x[10];
For example: double arr[5];int i;for(i=0; i<5; i++) { arr[i] = i + 0.5; } This code will cause an error since the index must be an integer. Double, float, or string data types cannot be used as indexes.
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In cold climates, water pipes may freeze and burst if proper precautions are not taken. In such an occurrence, the exposed part of a pipe on the ground ruptures, and water shoots up to 42 m. Estimate the gage pressure of water in the pipe. State your assumptions and discuss if the actual pres- sure is more or less than the value you predicted.
Answer:
411.953 kpa
Explanation:
We have the following assumptions
1. Steady incompressible flow.
2. Burst section water pressure = water main pressure
3. Air and water have negligible friction between them.
Max height = 42 m
Max water density = 277.14k
Density of water
Pwater = 999.8395kg/m
Water gets to 42m because of pressure in the line
P (line) = Pwater * g * h
= 999.8395 x 9.81 x 42
= 411.953Kpa
What is the link between fossil fuel use and flowers blooming earlier in the spring season
Answer:
a warmer earth due to fossil fuel emissions has milder winters and earlier springs
Explanation:
fossil fuels cause global warming which would make the winters less cold and spring and summer hotter.
2. A general needs to take his troops across the river. He spies two boys with a small boat. He commandeers both the boat and the boys. Unfortunately, the boat will only hold two boys or one soldier. Yet he determines a method for getting his troops across. What could it be?
I am so confused, can you explain it?
A 75-kg piano is hosted on a crane and delivered throughout the window of a 6th story apartment (20 meters above ground). What is the potential energy of the piano?
Answer:
14,700 J
Explanation:
PE = Mgh = (75 kg)(9.8 m/s²)(20 m) = 14,700 J
2) Repeated division-by-10 is used to convert decimal numbers to binary numbers. 3) The decimal value of binary 1011 can be determined by evaluating the following expression: 1x 23 + 0 x 22+1 x 21 + 1 x 20 3) 4) The 1's complement of binary 10111 is 01000.
The given statement can be divided into three parts:
1) Repeated division-by-10 is used to convert decimal numbers to binary numbers.
2) The decimal value of binary 1011 can be determined by evaluating the following expression: 1x2³ + 0 x 2² + 1 x 2¹ + 1 x 2⁰ .
3) The 1's complement of binary 10111 is 01000.Solution:1) Repeated division-by-10 is used to convert decimal numbers to binary numbers.The steps are as follows: Divide the decimal number by 2. Write down the binary digit (0 or 1). Continue dividing by 2 until we get to 0. Read the answer as the sequence of binary digits from the last to first (i.e. from the bottom to the top).
2) The decimal value of binary 1011 can be determined by evaluating the following expression: 1x2³ + 0 x 2² + 1 x 2¹ + 1 x 2⁰ .
(1 × 2³) + (0 × 2²) + (1 × 2¹) + (1 × 2⁰) = 8 + 0 + 2 + 1 = 11Hence the decimal value of binary 1011 is 11.3) The 1's complement of binary 10111 is 01000.
The 1's complement of binary number can be calculated as:
Invert all the bits in the binary number(Replace 0 by 1 and 1 by 0).
Therefore, the 1's complement of binary 10111 is 01000.
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- Match the system resources on the left with the descriptions or examples on the right. The system resources may be used once, more than once, or not at all.
-Allows two devices in a computer to send information to each other
-The method used by different system devices to interact with the CPU
-Conduits used by high-speed devices to bypass the CPU and communicate directly with RAM
-Allows a device to request processing time from the CPU
-Each device in a computer must have its own
The system resources match by allows two devices in a computer to send information to each other: Interconnects.The method used by different system devices to interact with the CPU.
How we match the system resources on the left with the descriptions or examples on the right?It seems that the left side of the task is missing, so I will provide a list of possible matches:
- Interrupt
- Bus
- Direct Memory Access (DMA)
- Device driver
- Input/output (I/O) address
The matches on the right side are:
- Bus: Allows two devices in a computer to send information to each other.
- Interrupt: Allows a device to request processing time from the CPU.
- Direct Memory Access (DMA): Conduits used by high-speed devices to bypass the CPU and communicate directly with RAM.
- Device driver: The method used by different system devices to interact with the CPU.
- Input/output (I/O) address: Each device in a computer must have its own.
In summary, the system resources on the left, such as interrupt, bus, DMA, device driver, and I/O address, are matched with their corresponding descriptions or examples, such as allowing devices to request processing time, enabling devices to send information, bypassing the CPU, interacting with the CPU, and requiring each device to have its own I/O address.
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Kevin fixes trucks as a job. The engine is oily. Which set set of equipment should Kevin use to fix the truck?
Answer:
A hammer and a wrench
Explanation:
How does concurrent engineering speed up product development?
A. The product and process are designed using computer-aided design.
B. The product and process are designed in series.
C. The product and process are designed in separate spaces.
D. The product and process are designed simultaneously.
Answer:
The product and process are designed simultaneously
Explanation:
PENN
Which control would be used to manually feed a cutting tool longitudinally across the workpiece?
The carriage handwheel is used to manually position and/or hand feed the carriage in the longitudinal or Z axis.
IamSugarBee
An electric train is moving north at 100 mph and a wind is blowing to the west at 10 mph. Which way does the smoke blow?
there is no smoke its a electric train