A child on a freely rotating merry-go-round moves from near the center to the edge. Will the rotational velocity of the merry-go-round increase, decrease, or not change at all? Explain.a The rotational velocity must increase to conserve angular momentum because the rotational inertia of the merry-go-round will be less with the child near the edge.b. The rotational velocity will not change because there is no change in the mass or the angular momentum of the merry-go-round.c. The rotational velocity must decrease to conserve angular momentum because the rotational inertia of the merry-go-round will be greater with the child near the edge.

Answer: I do not know what your observations were, but objects with a higher mass and objects traveling at a faster velocity have a higher kinetic energy. The reverse is true of course for less KE.

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MM4343

Answer:

Is zero.

Explanation:

I legit just had this question on my homework.

Answer:

Ek = 4250 J

Explanation:

Data:

Formula:

Replace and solve:

It has 4250 Joules of Kinetic Energy.

Greetings.

Answer:

D. 75 watts

Explanation:

brainliest please? i've just answered 3 of your questions and they were all correct! :) i hope i helped!

Answer:

(D) =75 WATTS

Explanation:

p(power)=i(current)×v(voltage)

p = 0.625 × 120

p =75 watts

The angular acceleration of the disc as a function of time is given by α, which is a constant. This assumes a simplified scenario where the angular acceleration remains constant over time for mathematical convenience, although in reality, the angular acceleration of a disc may vary.

To find the angular acceleration of the disc as a function of time, we can differentiate the angular velocity equation with respect to time. In part (c), the angular velocity equation was derived as ω = ω0 + αt, where ω is the angular velocity at time t, ω0 is the initial angular velocity, α is the angular acceleration, and t is the time.

Differentiating this equation with respect to time gives us the rate of change of angular velocity, which is the angular acceleration. Therefore, differentiating ω = ω0 + αt with respect to t, we get dω/dt = d(ω0 + αt)/dt.

Since ω₀ is a constant, its derivative is zero. The derivative of αt with respect to t is α, as α is a constant.

So, dω/dt = 0 + α = α.

Hence, the angular acceleration of the disc as a function of time is given by α. This means that the angular acceleration remains constant over time.

However, it is important to note that in reality, the angular acceleration of a disc is not constant. This model assumes a simplified scenario where the angular acceleration is constant for the sake of mathematical convenience and ease of analysis.

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The resultant force is 12.6N at a bearing of 3°W of N. The direction of motion of the body is the same as the direction of the resultant force, which is 3°W of N.

A triangle of vectors can be used to solve vector addition problems, such as determining the resultant force and direction of motion of a body acted upon by two or more vectors.

Let's use this method to solve the given problem: Two vectors, 10N and 8N, act on a body on bearings 285° and N70°E respectively.

Using the triangle of vectors, we can determine the resultant force and direction of motion of the body.

1. Draw a diagram to scale, showing the two vectors and their respective bearings.

2. Begin by drawing the first vector, 10N, from the origin at bearing 285°.

3. Draw the second vector, 8N, from the end of the first vector at bearing N70°E.

4. Draw the third vector, the resultant force, from the origin to the end of the second vector.

5. Use a protractor and ruler to measure the magnitude and bearing of the resultant force.

The diagram is shown below: Triangle of vectors diagram using the two vectors 10N and 8N, with bearings 285° and N70°E respectively.

The third vector, the resultant force, is drawn from the origin to the end of the second vector.

The magnitude and bearing of the resultant force are found using a protractor and ruler.

6. Measure the magnitude of the resultant force using the ruler.

In this case, the magnitude is approximately 12.6N.

7. Measure the bearing of the resultant force using the protractor.

In this case, the bearing is approximately 3°W of N.

Therefore, the resultant force is 12.6N at a bearing of 3°W of N.

The direction of motion of the body is the same as the direction of the resultant force, which is 3°W of N.

Therefore, the body will move in this direction.

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The equation Jerry should use for the total resistance in a series circuit is R = R₁ + R₂ + R₃.

option A.

In a series circuit, all components are connected end-to-end, forming a single path for current flow.

A series circuit can contain any combination of resistors, capacitors, and inductors.

In a series circuit, the current flowing in each circuit component is the same  and the voltage drop in each circuit component is different.

Based on this, the total formula for the total resistance in a series circuit is given as;

R = R₁ + R₂ + R₃

where;

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Answer:

Ns/Np=1/4

Vs=?

Vp=220V

Ns/Np=Vs/Vp

Vs=Ns/NpxVp=1/4x220=55V

Explanation:

Answer:

Explanation:

Gravitational potential energy is defined as the product between mass, gravity, and height above an arbitrary reference point. If we choose our reference as the ground, then the top of a hill would have a very large potential energy due to the height term being large.

\(U=mgh\)

Answer:

It will be in liquid state loosing it's magnetic property.

Explanation:

Iron melts at 1538°C after loosing it's magnetic property at 770°C.

Gas is the state of the iron ball when it is heated at 2000 degrees Celsius.

An iron ball is in the state of matter known as a gas when heated to a temperature of 2000 degrees Celsius. Iron changes from a solid to a liquid at its melting point, which is about 1538 degrees Celsius, at this extraordinarily high temperature. Beyond its melting point, iron continues to absorb heat until it reaches its boiling point, or around 2862 degrees Celsius, where it turns from a liquid to a gas.

The iron has crossed its melting point but has not yet boiled at 2000 degrees Celsius. As a result, it is liquid, with the iron being in a molten state. Since the iron no longer has a solid structure, it may now flow freely, just like other liquids do.

It's critical to remember that heating iron to such high temperatures involves a lot of energy, and that handling things or materials at such temperatures safely demands tremendous caution. It exists as a solid at lower temperatures, below iron's melting point, and as a gas at higher temperatures, above iron's boiling point.

Hence, gas is the state of the iron ball when it is heated at 2000 degrees Celsius.

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Answer:We have seasons because the earth is tilted (wonky) as it makes its yearly journey around the sun. The Earth's axis is tilted at an angle of 23.5 degrees. This means that the Earth is always "pointing" to one side as it goes around the Sun.

Explanation:

got this from the internet

Answer:

ew so the difference is.. Pollination and Fertilization occur in plants during sexual reproduction.

the difference is Pollination occurs from anthers of stamens to stigma of the ovary and It is a physical process.

fertilizateion is It is the fusion of female and male gametes and It is a genetic and biochemical process.

Explanation:

this was so hard to write out

The potential energy stored in the spring is 2.5 joules.

The potential energy stored in a spring is given by the formula:

PE = (1/2)kx^2

where k is the spring constant and x is the displacement of the spring from its equilibrium position.

In this case, the force acting on the spring is 10 N, which is also equal to the spring's restoring force at its stretched position. Using Hooke's law, we can determine the displacement of the spring:

F = kx

x = F/k = 10 N / 20 N/m = 0.5 m

Now, we can calculate the potential energy stored in the spring:

PE = (1/2)kx^2 = (1/2)(20 N/m)(0.5 m)^2 = 2.5 J

Therefore, the potential energy stored in the spring is 2.5 joules.

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Answer:

v = 17.68 m/s

Explanation:

Given that,

While standing at a crosswalk, you hear a frequency of 510 Hz from an approaching police car.

After the police car passes, its frequency is 460Hz.

We need to find the speed of the police car.

The formula is as follows :

\(v=\dfrac{v_o(f-f')}{f+f'}\)

Put all the values,

\(v=\dfrac{343(510-460)}{510+460}\\\\=17.68\ m/s\)

So, the speed of the police car is 17.68 m/s.

Explanation:

Acceleration and the other term are the same physical phenomenon - just with opposite affects. Acceleration increases velocity, while the other term that begins with the letter "R" reduces.

***(Brainly's language filter is blocking the use of the second term in my answer.)***

Acceleration is defined as the rate of change of the velocity of an object per unit of time...

\(a = \frac{dv}{dt}\)

Acceleration would be a POSITIVE (+) quantity, while the r-word would be negative (-).

Answer:

its c

Explanation:

No number one cutting-edge is required to saturate the class C800 Current Transformer in this scenario.

To determine the number one present-day required to saturate the class C800 Current Transformer (CT), we need to take into account its saturation traits. Typically, the saturation of a CT happens while the primary contemporary reaches a positive stage that causes the magnetic middle to saturate, ensuing in distorted output waveforms.

In this situation, the CT has a ratio of 100/5, which means that for every 1000Amps of number one contemporary, there could be 5Amps of secondary modern. The secondary burden is given as a hundred ohms.

To calculate the primary current required to saturate the CT, we want to consider the burden impedance, which is contemplated to the primary facet of the CT. The meditated burden impedance is calculated with the use of the turns ratio squared:

Reflected Burden Impedance = (Turns Ratio)² * Burden Impedance

In this example, the contemplated burden impedance is:

Reflected Burden Impedance = (1000/5)² * 100 = 400,000 ohms

Now, the number one modern required to saturate the CT can be determined by applying Ohm's Law:

Primary Current = Voltage / Impedance

Since the CT is connected to a present-day supply, the voltage can be taken into consideration as negligible. Therefore, the number one present-day required to saturate the CT is:

Primary Current = 0/ 400,000 = 0 Amps

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Answer: 6.66666667 or 6.66 km per hour

Explanation: (velocity = distance÷time) or (v=d÷t)

When the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

The normal reaction of the box is due to weight of the box acting perpendicular to the ramp.

Fn = Wcosθ

Fn = Wcos(30)

Fn = 0.866W

Fn = W x cos(45)

Fn = 0.7071W

Thus, when the angle of the ramp increases, the weight of the box acting perpendicular to the ramp decreases.

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Answer:

interference, because constructive interference occurred when the wind frequency matched the natural frequency of the bridge

Explanation:

Wave interference occurs when two waves with identical wavelength, velocity, frequency, and amplitude meet each other when the waves travel along with the same medium.

The characteristic of waves that caused the bridge to collapse is interference because constructive interference occurred when the wind frequency matched the natural frequency of the bridge

Answer:

C im pretty sure

Explanation:

Answer: 2.21 m/s

Explanation:

Given

Coin reaches a height of  0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

\(\Rightarrow v^2-u^2=2as\\\)

Putting values

\(\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s\)

Thus, the initial velocity is 2.21 m/s

A drag car starts down a drag strip. If it can accelerate constantly at 17 m/s squared, then its speed after 5 seconds would be 85 meters/second.

There are three equations of motion given by  Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

v = u + at

  = 0 + 17×5

  = 85 m/s

S = ut + 1/2at²

200 = 0 + 0.5×5×t²

2.5t² = 200

t² = 200 / 2.5

t = 8.944 seconds

Thus, the speed of the car after 5 seconds would be 85 m/s and it would take 8.944 seconds to clear a 200-meter drag strip.

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The momentum is directed to the left, the velocity is negative. Therefore, the velocity of the glider is -1.002 m/s to the left.

The momentum of an object is defined as the product of its mass and velocity:

momentum = mass x velocity

In this case, we are given the momentum of the glider, its mass, and its direction of motion. We can use these values to solve for the velocity of the glider.

First, we convert the mass of the glider from grams to kilograms:

mass = 127.8 g = 0.1278 kg

Next, we use the formula for momentum to solve for the velocity of the glider:

momentum = mass x velocity

-0.128 kgm/s = 0.1278 kg x velocity

velocity = (-0.128 kgm/s) / (0.1278 kg)

velocity = -1.002 m/s.

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Explanation:

yan lng po Alam ko

The speed of the object is zero when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.  

The displacement is maximum when the magnitude of the momentum is maximum.

In simple harmonic motion, an object oscillates about its equilibrium position with a constant amplitude. The displacement of the object from its equilibrium position is given by the equation:

displacement = amplitude * sin(ωt + phase)

where amplitude is the maximum distance from equilibrium, ω is the angular frequency of the oscillation, t is time, and phase is the initial phase of the oscillation.

The magnitude of the momentum of the object is given by the equation:

momentum = mass * velocity

where mass is the mass of the object, velocity is its velocity, and ω is the angular frequency of the oscillation.

Therefore, the displacement of the object is maximum when the magnitude of the momentum is also maximum, which occurs when the velocity of the object is at its maximum value.

The kinetic energy of the object is maximum when the displacement is maximum.

In simple harmonic motion, the kinetic energy of the object is given by the equation:

kinetic energy = 1/2 * m *\(velocity^2\)

where m is the mass of the object, velocity is its velocity, and ω is the angular frequency of the oscillation.

Therefore, the kinetic energy of the object is maximum when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.

The acceleration of the object is zero when the displacement is maximum.

In simple harmonic motion, the acceleration of the object is given by the equation:

acceleration = -ω * amplitude * sin(ωt + phase)

where ω is the angular frequency of the oscillation, amplitude is the maximum distance from equilibrium, t is time, and phase is the initial phase of the oscillation.

Therefore, the acceleration of the object is zero when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.

The speed of the object is zero when the displacement is maximum.

In simple harmonic motion, the speed of the object is given by the equation:

speed = amplitude * cos(ωt + phase)

where amplitude is the maximum distance from equilibrium, ω is the angular frequency of the oscillation, t is time, and phase is the initial phase of the oscillation.

Therefore, the speed of the object is zero when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.  

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The correct answer is punt/kickoff

In gridiron football, a drive is started with a kickoff. The "kicking team" often kicks the ball to the "receiving team" of the opposite team during a kickoff. Until the player with the ball is tackled by the kicking team, goes out of bounds, scores a touchdown, or the play is otherwise deemed dead, the receiving team is then allowed to return the ball, i.e., attempt to move it towards the kicking team's end zone. Every half of play, the start of various overtime forms, and after scoring plays all feature kickoffs. At the beginning of each half, following a try, and following a successful field goal, the ball is sent into play through a kickoff.

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Complete question

Happens at the start of the game and after every touchdown. in flag football you may throw or punt the ball. options 1. Interception 2. Fumble

3. Punt/Kickoff  4. Down

Answer:

50 N.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 5 Kg

Coefficient of friction (μ) = 0.36

Normal reaction (N) =?

Next, we shall determine the weight of the body. This can be obtained as follow:

Mass (m) = 5 Kg

Acceleration due to gravity (g) = 10 m/s²

Weight (W) =?

W = mg

W = 5 × 10

W = 50 N

Finally, we shall determine the normal reaction. This can be obtained as follow:

Weight (W) = 50 N

Normal reaction (N) =?

Normal reaction = weight of the body

N = W = 50 N

Thus, the normal reaction acting on the body is 50 N

The vector BR in unit vector notation is:

BR = 8.485 î + 8.485 j

What is Vector?

Vectors can be added together to find the result, which is known as the vector sum. The vector sum can be found using the head-to-tail method, where the tail of one vector is placed at the head of the other vector. The vector sum is the vector that goes from the tail of the first vector to the head of the second vector.

To write the vector BR in unit vector notation, we need to find its components in the i and j directions.

Given that the magnitude of the vector is 12.0 and it makes an angle of 45 degrees with the positive x-axis, we can use trigonometry to find the components.

The x-component (i-direction) of the vector is given by:

Bx = B cos θ = 12.0 cos 45° = 8.485

The y-component (j-direction) of the vector is given by:

By = B sin θ = 12.0 sin 45° = 8.485

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Two weights are connected by a massless wire and pulled upward with a constant speed of 1.50 m/s by a vertical pull P. The tension in the wire is T The relationship between T and P is that T = P + 125N, which is equivalent to answer choice D. The correct answer is D) P=T+25N.

This can be determined by analyzing the forces acting on the system. Since the weights are being pulled upward at a constant speed, the net force acting on them must be zero.
The forces acting on the weights are their respective weights (mg), where m is the mass of the weight and g is the acceleration due to gravity, and the tension in the wire (T). The vertical pull P also acts on the system.
Using Newton's second law (F=ma) and setting the net force equal to zero, we can write:
T - m1g - m2g - P = 0
Solving for T, we get:
T = m1g + m2g + P
Substituting in the given values of m1, m2, and g, we get:
T = 50N + 75N + P
Simplifying, we get:
T = P + 125N

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