Answer:
= (25π - 24) cm²
Step-by-step explanation:
Area of the circle = πr²
= π(5)²
= 25π cm²
Area of ΔOAB = 2(Area of ΔOCB)
AB = 6 cm
OC = 5 - 1 = 4 cm
By applying Pythagoras theorem in ΔOCB,
OB² = OC² + BC²
5² = 4² + BC²
BC² = 25 - 16
BC = √9 = 3 cm
Area of ΔOCB = 1/2 (OC) (BC)
= 1/2 (4) (3)
= 6cm^2
Area of ΔAOB = 2(6) = 12 cm²
Area of ΔAOB = Area of ΔDOE = 12 cm²
Area of shaded region = 25π - (12 + 12)
= (25π - 24) cm²
Charlie dve 208 miles in 4 hours at a constant speed he continues at that speed give the equation that shows the relationship between driving hours
Answer:
52 miles per hour
Step-by-step explanation:
I think you're missing some info, so this is all I can help with right now
Write the quadratic function f(x)=2(x+1)^2-8 in standard for and intercept form.
I know how to write it in standard form- f(x)=2x^2+4x-6
But I don’t know how to write it in intercept form.
Please explain.
The quadratic function f(x)=2(x+1)^2-8 in standard for and intercept form is 2x^2+4x-6 and (x-1)(x+3).
Given:
f(x) = 2(x+1)^2 - 8
= 2(x^2+1+2x) - 8
= 2x^2 + 2 +4x - 8
= 2x^2+4x-6(standard form)
Intercept form:
= 2x^2+4x-6
= (x-1)(x+3)
x-1 = 0
x = 1
x+3 = 0
x = -3
(1,0) and(-3,0).
Therefore the quadratic function f(x)=2(x+1)^2-8 in standard for and intercept form is 2x^2+4x-6 and (x-1)(x+3).
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help me with this pls like omg soooo stressful
Answer:
t =1
Step-by-step explanation:
3t - 18 = 4(-3-3/4t)
Distribute
3t - 18 = -12 -3t
Add 3t to each side
3t -18+3t = -12 -3t+3t
6t -18 =-12
Add 18
6t -18+18 = -12+18
6t = 6
Divide by 6
6t/6 = 6/6
t =1
Answer:
t = 1
Step-by-step explanation:
start by distributing the 4 to whats in the parentheses.
4 (-3 - 3/4t)
-12 - 3t
*helpful tip: if you multiply a fraction by its denominator the product is equal to its numerator
now you have:
3t - 18 = -12 - 3t
add 18 to both sides
3t = 6 - 3t
add 3t to both sides
6t = 6
divide both sides by 6
t = 1
Olga tried to solve an equation step by step.
1/4 (1/3k+9)=6
1/3k=15
k=5
Find Olga's mistake.
If | x + 4 | = 1, what value(s) could x have?
Answer:
-5 and -3 could both work in this situation
Step-by-step explanation
-5 + 4 = -1
| -1 | = 1
-3 + 4 = 1
| 1 | = 1
i need help on questions 4, 5, and 6. please help!
Step-by-step explanation:
4) d = √(3-1)²+(7-(-1))²
=√2²+8² = √4+64 =√68
5) AD=29
AB =2x+4,BC=2x,CD=x
AD = 2x+4+2x+x
29=2x+4+2x+x
29=5x+4
29-4=5x
x=25/5
x=5
AB =2x+4
=2(5)+4 =14
BD = BC +CD
= 2x+x
=2(5)+5 =15
A swimming pool is being drained at a constant rate of 3 inches (depth of the water) per hour. The depth of the water after 5 hours is 32 inches. Write the equation for this function in point slope form.
Answer:
y-32=3(x-5)
Step-by-step explanation:
The swimming pool is being drained at a constant rate of 3 inches per hour, therefore:
The rate of change, Slope, m=3 inches per hourIf the depth of the water after 5 hours is 32 inches.
The depth is the dependent variable(as its values varies with time) while the time is the independent variable, we can write this as a pair (x,y)=(5, 32).
The point slope form of the equation of a line is of the form: \(y-y_1=m(x-x_1)\\(x_1,y_1)=(5,32), m=3\\$Substituting these values, we obtain:\\y-32=3(x-5)\\This is the equation of the function in point slope form.\)
What is the answer and how to do this?
Answer:
a
Step-by-step explanation:
Given :
⇒ P (Sumit) = 1/2
⇒ P (Sujan) = 1/3
⇒ P (Rakesh) = 1/a
⇒ P (total) = 3/4
============================================================
Solving :
⇒ 1/2 × 1/3 × 1/a = 3/4
⇒ 1/6 × 1/a = 3/4
⇒ 2/12 × 1/a = 9/12
⇒ a = 9/2
If the two figures are congruent, which statement is true?
A. BCDA ≅ FEHG
B. ABCD ≅ EFGH
C. BADC ≅ EFGH
D. ADCB ≅ HGFE
Answer:
A
Step-by-step explanation:
the order of letter should resemble the same shape
3(4x-9)+4=2(5x-7)+2
*if it’s a repeating decimal, round to the nearest hundredth (2 decimal places)
Help please .
approximately what percentage of children will score within the average range of iq testing? group of answer choices 20% 37% 68% 85%
The required interval of the given normal distribution using the empirical rule is [100, 140].
The empirical rule formula (also known as a 68 95 99 rule formula) uses data from a normal distribution to determine the first, second, and third standard deviations, which, respectively, differ from the mean value by 68%, 95%, and 99%. Additionally, it shows that 99.9% of the data fall inside the third standard deviation range (either above or below the mean value). The empirical rule formula is described below with cases that have been resolved.
In the question, we are given that IQ scores for adults aged 20 to 34 years are normally distributed according to N(120, 20), and are asked for the range in which the middle 68% of people in this group score on the test.
N(120, 20) signifies a normal distribution with mean, μ = 120, and the standard deviation, σ = 20.
By the empirical formula, 68% of the data lies within one standard deviation from the mean.
Thus, the required interval is [μ - σ, μ + σ] = [120 - 20, 120 + 20] = [100, 140].
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Given the cost function C(x) = 1800 – 700x and the demand function p(x) = 150 - 80x – 35x2, the marginal revenue function is: = a) Odr/dx = 150x – 35x3 b) Odr/dx = 150 – 160x – 105x2 = c) Odr/dx = 1650 - 700x2 – 35x3 d) Odr/dx = 1800x - 700r2
The marginal revenue function is the derivative of the revenue function with respect to the quantity x. Since revenue is equal to price times quantity, we can write the revenue function as R(x) = p(x)*x. Therefore, the marginal revenue function is:
dR/dx = dp/dx * x + p(x) * dx/dx
But dx/dx = 1, so we can simplify the above expression as:
dR/dx = dp/dx * x + p(x)
We are given the demand function p(x) = 150 - 80x - 35x^2, so we can find dp/dx by taking the derivative with respect to x:
dp/dx = -80 - 70x
Substituting this into the expression for the marginal revenue function, we get:
dR/dx = (-80 - 70x) * x + (150 - 80x - 35x^2)
Simplifying this expression, we get:
dR/dx = -35x^2 - 10x + 150
Therefore, the marginal revenue function is:
a) Odr/dx = 150x – 35x3 is not correct
b) Odr/dx = 150 – 160x – 105x2 is not correct
c) Odr/dx = 1650 - 700x2 – 35x3 is not correct
d) Odr/dx = 1800x - 700x2 is not correct
The correct answer is:
dR/dx = -35x^2 - 10x + 150
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You have just signed up for a broadband home internet service that uses coaxial cable. which connector type will you most likely use?
Answer:
F type connector
Step-by-step explanation:
Use an F-type connector for broadband cable connections that use coaxial cable.
The F connector is a coaxial RF connector commonly used for "over the air" terrestrial television, cable television and universally for satellite television and cable modems,
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F type connector
The F-connector is a coaxial RF connector commonly used for "wireless" terrestrial television, cable television, and common for satellite television and cable modems, usually with RG-6/U cable or with RG -59 / U.F connector is also known as threaded connector. There are two main types: 7mm (6.8mm) is the most common and used in coaxial cable, and 5mm connector is used in thin coaxial cable commonly used in satellite system.
The F-connector is an accessory that connects a coaxial cable to an electronic device or wall outlet.
Type F connectors are highly mechanical and electrically stable coaxial screw connectors for cable television (CATV), set-top boxes, cable modems and satellite television applications up to 4 GHz
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WHAT ARE CONGRUENCE LINES
Answer:
Line segments are congruent if they have the same length. However, they need not be parallel. They can be at any angle or orientation on the plane. ... Rays and lines cannot be congruent because they do not have both end points defined, and so have no definite length.
45. You deposit $6000 into an account that earns 3.8% interest compounded annually.
Find the balance of the account after 7 years.
Answer: 7596
Step-by-step explanation:
3.8%x7=26.6%
6000x26.6%=1596
6000+1596=7596
Use the order of operations to simplify the expression.
Answer:
20
Step-by-step explanation:
28 - {8/2 x (6-2)} + (4 - 2) ^ 3
28 - {4 x 4} + 2^3
28 - 16 + 8
12 + 8
20
plsssssszz answerrrrrr
I think this is one of those trick questions!
I'm going to say the answer is... 90°
because it states within the question that ∠A and ∠B are vertical angles
That is my educated guess. I hope it's helpful!
Pls let me know if my answer is incorrect.
solve (2x + 3) - (9x - 3)
Answer:
-7x + 6
Step-by-step explanation:
What is 25.9 rounded to the nearest whole number?
Answer:
26
Step-by-step explanation:
Answer: 26
Step-by-step explanation: When rounding you have to look and see if your number is above or below 5. Let's take your number for example.
25.9
Focus on the decimal point. If you notice, the number after the decimal point is above 5, therefore you should round it off to 26.
Hope it helps ^^
Se tienen baldosas de 20x 25 cm para cubrir el piso de un patio. Determina cuáles son las dimensiones del piso si se tienen 50 baldosas y no sobra ninguna justifica la respuesta y grafica
Answer:
Step-by-step explanation:
Para determinar las dimensiones del piso, debemos considerar la cantidad de baldosas y las dimensiones de cada una. Sabemos que hay 50 baldosas disponibles y que cada una tiene un tamaño de 20x25 cm.
Si multiplicamos el número de baldosas por las dimensiones de cada baldosa, obtendremos el área total que cubren las baldosas en el piso.
50 baldosas * (20 cm * 25 cm) = 50 * 500 cm² = 25000 cm²
El área total que cubren las baldosas es de 25000 cm². Para encontrar las dimensiones del piso, necesitamos determinar las dimensiones de un rectángulo cuyo área sea igual a 25000 cm².
Podemos factorizar 25000 para encontrar sus dimensiones de manera más sencilla. La factorización puede variar, pero en este caso, se puede descomponer en:
25000 = 250 * 100 = 25 * 10 * 100 = 5 * 5 * 2 * 10 * 100
Podemos agrupar estos factores para obtener un rectángulo con dimensiones proporcionales:
5 * 5 = 25
2 * 10 = 20
100 = 100
Por lo tanto, las dimensiones del piso son 25 cm de ancho por 20 cm de largo.
Para visualizar esto en una gráfica, podemos representar el piso como un rectángulo con las dimensiones calculadas de 25 cm x 20 cm.
PLEASE HELP FAST!! HIGH POINTS!
What is the vertex form of the equation?
y = x^2 + 4x - 3
Oy = (x - 2)^2 - 7
Oy = (x + 2)^2-7
Oy = (x - 2)^2 + 7
Oy= (x + 2)^2 + 7
Answer:
he easiest way is: y=ax2+bx+c. axis on symmetry is: aos=−b2a. Vertex is: (aos,f(aos)). c = y-intercept. so your function: y=x2−4x.
Step-by-step explanation:
(This exercise is from Physical Geology by Steven Earle and is used under a CC BY 4.0 license.) Heavy runoff can lead to flooding in streams and low-lying areas. The graph below shows the highest discharge per year between 1915 and 2014 on the Bow River at Calgary, Canada. Using this data set, we can calculate the recurrence interval (R) for any particular flood magnitude with the equation R=(n+1)/r, where n is the number of floods in the record being considered, and r is the rank of the particular flood. There are a few years missing in this record, and the actual number of data points is 95. The largest flood recorded on the Bow River over that period was in 2013, which attained a discharge of 1,840 m3/s on June 21. R; for that flood is (95+1)/1=96 years. The probability of such a flood in any future year is 1/R; which is 1%. The fifth largest flood was just a few years earlier in 2005 , at 791 m3/5. Ri for that flood is (95+1)/5=19.2 years. The recurrence probability is 5%. - Calculate the recurrence interval for the second largest flood (1.520 m3/s in 1932). Express your answer in units of years. - What is the probability that a flood of 1,520 m3/s will happen next year? - Examine the 100-year trend for floods on the Bow River. If you ignore the major floods (the labeled ones), what is the general trend of peak discharges over that time?
The recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.
Using the provided data on the highest discharge per year on the Bow River at Calgary, Canada, we can calculate the recurrence interval (R) for specific flood magnitudes and determine the probability of such floods occurring in the future. Additionally, we can examine the 100-year trend for floods on the Bow River, excluding major floods, to identify the general trend of peak discharges over time.
1) Calculating the Recurrence Interval for the Second Largest Flood (1,520 m3/s in 1932):
To calculate the recurrence interval (R) for the second largest flood, we need to determine the rank of that flood. Since there are 95 data points in total, the rank of the second largest flood would be 94 (as the largest flood, in 2013, is excluded). Applying the formula R = (n + 1) / r, we have:
R = (95 + 1) / 94 = 1.0106 years
Therefore, the recurrence interval for the second largest flood (1,520 m3/s in 1932) is approximately 1.0106 years.
2) Probability of a Flood of 1,520 m3/s Occurring Next Year:
The probability of a flood of 1,520 m3/s happening next year can be calculated by taking the reciprocal of the recurrence interval for that flood. Using the previously calculated recurrence interval of 1.0106 years, we can determine the probability:
Probability = 1 / R = 1 / 1.0106 = 0.9895 or 98.95%
Thus, the probability of a flood of 1,520 m3/s occurring next year is approximately 98.95%.
3) Examination of the 100-Year Trend for Floods on the Bow River:
To analyze the 100-year trend for floods on the Bow River while excluding major floods, we focus on the peak discharges over time. Without considering the labeled major floods, we can observe the general trend of peak discharges.
Unfortunately, without specific data on the peak discharges for each year, we cannot provide a detailed analysis of the 100-year trend. However, by excluding major floods, it is likely that the general trend of peak discharges over time would show fluctuations and variations but with a relatively stable pattern. This implies that while individual flood events may vary, there might be an underlying consistency in terms of typical peak discharges over the 100-year period.
In summary, the recurrence interval for the second largest flood on the Bow River in 1932 is approximately 1.0106 years. The probability of a flood with a discharge of 1,520 m3/s occurring next year is roughly 98.95%. When examining the 100-year trend of peak discharges, excluding major floods, there is likely a general pattern of fluctuations but with overall stability in typical peak discharge values.
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Using a standard deck of cards, find the probability of selecting a jack, replacing the card, and then selecting a king.
please explain
The probability of selecting a jack, replacing the card, and then selecting a king is 1/169
How to determine the probability?In a standard deck of cards, we have:
Total = 52
Jack = 4
King = 4
The probability of each is:
P(Jack) = 4/52
P(King) = 4/52
So, we have:
P = 4/52 * 4/52
Simplify
P = 1/13 * 1/13
Evaluate
P = 1/169
Hence, the probability is 1/169
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Which point has coordinates -4, -3)?
A J
B K
C N
D Q
Answer: K
Step-by-step explanation:
Answer:
Step-by-step explanation:
k
Write the exponential expression
26 squared
Answer:
26²
Step-by-step explanation:
26 x 26 = 676
Mr Castle shares out 48 marbles between Emily
and Asif in the ratio 5: 1
How many marbles does each child get?
Step-by-step explanation:
Hope it will help you a lot.
Graph the line that represents a proportional relationship between ddd and ttt with the property that an increase of 333 units in ttt corresponds to an increase of 444 units in ddd.
What is the unit rate of change of ddd with respect to ttt? (That is, a change of 111 unit in ttt will correspond to a change of how many units in ddd?)
The graph of the line of the proportional relationship is added as an attachment and the unit rate of change of d with respect to t is 8/3
How to graph the line of the proportional relationship between d and tFrom the question, we have the following parameters that can be used in our computation:
The statement is given as:
increase of 3 units in t corresponds to an increase of 4 units in d.
This can be represented using the following ratio
t : d = 3 : 4
Express the above ratio as a fraction
So, we have the following representation
t/d = 3/4
Make d the subject of the equation
So, we have
d = 4/3t
See attachment for the graph of d = 4/3t
How to calculate the unit rateIn part (a) of this solution, we have:
t/d = 3/4
Inverse both sides
d/t = 4/3
This means that:
Slope or Rate = 4/3
Hence, the unit rate of change of d with respect to t is 4/3
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Please show all work and not just the answers.
I hope this helps you
How to solve X + 3 <6
The value of the inequality X + 3 < 6 is x < 3.
What is an inequality?Inequalities are created through the connection of two expressions. It should be noted that the expressions in an inequality aren't always equal. Inequalities implies that the expressions are not equal. They are denoted by the symbols ≥ < > ≤.
Based on the information given, the inequality will be illustrated thus:
x + 3 < 6
Collect like terms
x < 6 - 3
x < 3
The value is x < 3.
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ASAP!!!!!!!!!!! I was absent i need help
The {x} - intercepts and {y} - intercepts for the given tables are mentioned below.
What is intercept?An intercept is the coordinate point where the graph cuts the {x} - axis or {y} - axis.
Given are the tables as shown in the image.
{ 1 } -
{x} - intercept : (3, 0)
{y} - intercept : (0, 16)
{ 2 } -
{x} - intercept : (1, 0)
{y} - intercept : (0, - 2.5)
{ 3 } -
{x} - intercept : (8, 0)
{y} - intercept : (0, - 16)
Therefore, the {x} - intercepts and {y} - intercepts for the given tables are mentioned above.
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