A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car? (OP A. 100 kilometers/hour south B. 200 kilometers/hour C. 200 kilometers/hour north 100 kilometers/hour ​

To calculate the height of the cliff and the time it takes for the rock to reach the ground when thrown straight down, we can use the equations of motion.

(a) Height of the cliff:

When the rock is thrown straight up, it reaches its highest point before falling back down. The time it takes for the rock to reach its highest point is equal to the time it takes for the rock to fall back down to the ground.

Using the equation:

s = ut + (1/2)at^2

Where:

s is the distance traveled (height of the cliff),

u is the initial velocity (8.19 m/s),

t is the time (2.32 s),

a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).

Rearranging the equation:

s = ut + (1/2)at^2

s = (8.19)(2.32) + (1/2)(-9.8)(2.32)^2

s = 19.004 - 25.798

s = -6.794 m

Since the height of a cliff cannot be negative, we take the absolute value of the result:

Height of the cliff = |s| = 6.794 m

So, the height of the cliff is approximately 6.794 meters.

(b) Time to reach the ground when thrown straight down:

When the rock is thrown straight down with the same speed, the initial velocity (u) is still 8.19 m/s, but the acceleration due to gravity (a) remains -9.8 m/s^2.

Using the equation:

s = ut + (1/2)at^2

Where:

s is the distance traveled (height of the cliff, which is now negative),

u is the initial velocity (8.19 m/s),

t is the time we want to find,

a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).

Substituting the known values:

-6.794 = (8.19)t + (1/2)(-9.8)t^2

Rearranging the equation:

-6.794 = 8.19t - 4.9t^2

Rearranging further:

4.9t^2 - 8.19t - 6.794 = 0

Solving this quadratic equation, we find two possible values for t: 0.828 seconds and 1.303 seconds. Since we are considering the time it takes to reach the ground, the valid solution is t = 0.828 seconds.

Therefore, when the rock is thrown straight down, it takes approximately 0.828 seconds to reach the ground.

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HERE'S YOUR ANSWER

Explanation:

Antimatter is a material composed of so-called antiparticles. It is believed that every particle we know of has an antimatter companion that is virtually identical to itself, but with the opposite charge. For example, an electron has a negative charge.

Radii is a vital feature of the elements, and it can be useful in determining the characteristics of elements in various chemical and physical processes. The radii of atoms and ions of the same element differ due to their various charge and mass characteristics.

Atomic and ionic radii increase as you move down a group on the periodic table, and decrease as you move across a period from left to right due to increased nuclear charge, making the electrons closer to the nucleus. The size of an atom and ion also changes due to the number of electrons charge, and electronic configuration.In order of increasing radius, the arrangement of \(Ne, F-, O2-, Br-, Rb\) is given as follows:

\(Ne < F- < O2- < Br- < Rb+\)

Rb+ has the smallest radius due to its large nuclear charge and fewer electrons in the valence shell.

As a result, they are larger than Rb+. O2- has more electrons than Ne and is the largest among the given ions and atoms. It is important to note that in certain conditions, the trends in radii may not be valid because of hybridization and other factors. Nonetheless, this arrangement is valid for the given ions and atoms.

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Assuming they have identified a suitable location on Mars with sufficient space, they will need to determine the height, width, and depth of the attraction. Here are some potential dimensions they could consider:

These dimensions are just suggestions, and Marsha and Wes will need to consider their specific goals and constraints in creating the Crater Craze Climber. Additionally, they should consult with experts in engineering and safety to ensure the attraction is structurally sound and safe for visitors.

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B. Doubling The Distance Between Capacitor Plates Will Reduce The Capacitance Two-Fold.  

Capacitor is an electrical device used to store energy. It is composed of two conducting plates separated by an insulating material called the dielectric. When a voltage is applied to the two plates, an electric field forms between them, storing energy in the form of an electrical charge. Capacitors are used in a variety of applications, such as in filter circuits, timing circuits, and power supply circuits.

The capacitance of a capacitor is directly proportional to the area of the plates and inversely proportional to the distance between the plates. Therefore, when the distance between the plates is doubled, the capacitance is halved.

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Uniform line movement

Data:

V = 80km/h

T = 15m = 0.25 h

d = ?

We perform a conversion from minutes to hours.

           15 m * 1 h/60 m = 0.25 h

The formula for uniform motion is:

                      V = d/t

We clear for distance:

                  d = v * t

                  d = 80 km/h * 0.25 h

                  d = 20 km

The distance traveled in that time is 20 km.

Each ball had a momentum of 3 kg m/s before the collision, and

the system of two balls had a total momentum of 0 kg m/s after the collision.

Given,

Each ball has a mass (m) of 1.0 kg.

Each ball moves at a speed (v) of 3.0 m/s.

Momentum (P) = Mass(m) x Velocity (v)

As a result of the identical mass and speed of both balls, the momentum of each ball before the collision would be:

P = mv

P = 1 * 3 kg m/s

P = 3 kg m/s

The momentum of each ball before the collision is 3 kg m/s.

When two identical balls roll in the opposite direction at the same speed with the same mass, their combined momentum would be as follows:

P = m₁v₁ - m₂v₂

P = 1 * 3 - 1 * 3

P = 3 - 3

P = 0 kg m/s

The collision is elastic, thus. The entire momentum before and after the collision is zero (0).

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Answer:

sequence

Explanation:

sequences are the way in which things are ordered, for example: 1, 2, 3, 4 is a sequence:)

The density profile is given by:

ρ(z) = p0 / (RT) - γz / (T)

These profiles provide the temperature, pressure, and density variation with height in an atmosphere with a uniform lapse rate γ, assuming hydrostatic balance and an ideal gas.

To find the temperature profile, pressure profile, and density profile for an atmosphere with a uniform lapse rate γ, we can use the ideal gas law and the hydrostatic balance equation. Let's derive these profiles step by step:

1. Temperature Profile:

Starting with the definition of lapse rate, γ ≡ -dT/dz, we have the following differential equation:

dT = -γ dz

Integrating both sides, we get:

∫dT = -γ ∫dz

T = -γz + C

Where C is the constant of integration. Since we have sea level temperature T0, we can substitute z = 0 and T = T0 into the equation:

T0 = C

Therefore, the temperature profile is given by:

T(z) = T0 - γz

2. Pressure Profile:

We can use the hydrostatic balance equation to derive the pressure profile. The equation states:

dp = -ρg dz

Where dp is the change in pressure, ρ is the density, g is the acceleration due to gravity, and dz is the change in height.

Let's assume the pressure at sea level is p0. Integrating both sides of the equation from p0 to p, and integrating from 0 to z for the height, we get:

∫dp = -∫ρg dz

p - p0 = -∫ρg dz

Since the density ρ is related to pressure by the ideal gas law, ρ = p / (RT), where R is the specific gas constant and T is the temperature, we can substitute this into the equation:

p - p0 = -∫(p / (RT)) g dz

p - p0 = -pg / RT ∫dz

p - p0 = -pgz / RT + C'

Where C' is the constant of integration. Substituting z = 0 and p = p0 into the equation:

p0 - p0 = C'

Therefore, the pressure profile is given by:

p(z) = p0 - pgz / RT

3. Density Profile:

We can use the ideal gas law to derive the density profile. The ideal gas law states:

p = ρRT

Rearranging the equation, we have:

ρ = p / (RT)

Substituting the expression for pressure from the pressure profile equation, we get:

ρ(z) = (p0 - pgz / RT) / (RT)

Simplifying further:

ρ(z) = p0 / (RT) - pgz / (RT^2)

So, the density profile is given by:

ρ(z) = p0 / (RT) - γz / (T)

These profiles provide the temperature, pressure, and density variation with height in an atmosphere with a uniform lapse rate γ, assuming hydrostatic balance and an ideal gas.

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The corresponding pressure p(z) and density rho(z) profiles as per the information given in question is p = e^(-(g/R)ln(T) + C) and ρ(z) = p0((T0 - γz)^(-g/R))/(R(T0 - γz)) respectively.

The temperature profile for an atmosphere with a uniform lapse rate γ is given by T(z) = T0 - γz, where T(z) is the temperature at altitude z, T0 is the temperature at sea level, and γ is the lapse rate defined as the negative derivative of temperature with respect to altitude, γ = -dT/dz.

To find the corresponding pressure profile p(z), we can use the hydrostatic balance equation, which states that the rate of change of pressure with altitude is equal to the product of the density of the gas, the acceleration due to gravity, and the negative derivative of temperature with respect to altitude.

Mathematically, this can be expressed as dp/dz = -ρg, where dp/dz is the rate of change of pressure with altitude, ρ is the density of the gas, and g is the acceleration due to gravity.

Since we have assumed the atmosphere to be an ideal gas, we can use the ideal gas law, which states that the pressure is directly proportional to the product of the density and the temperature.

Mathematically, this can be expressed as p = ρRT, where p is the pressure, ρ is the density, R is the specific gas constant for the gas, and T is the temperature.

Substituting this into the hydrostatic balance equation, we get dp/dz = -(p/R)(g/T)(dT/dz).

To solve this differential equation, we can separate the variables and integrate both sides.

∫dp/p = -∫(g/R)(dT/T)

ln(p) = -(g/R)ln(T) + C

where C is the constant of integration.

Exponentiating both sides, we get p = e^(-(g/R)ln(T) + C)

Using the properties of logarithms, we can simplify this expression as p = e^C(T^(-g/R))

Since T = T0 - γz, we can further simplify the expression as p = e^C((T0 - γz)^(-g/R))

To find the constant of integration C, we can use the sea level temperature and pressure given by T0 and p0, respectively.

At sea level, z = 0, and thus we have p0 = e^C(T0^(-g/R))

Simplifying, we get C = ln(p0/(T0^(-g/R)))

Substituting this value of C back into the expression for p, we get p(z) = p0((T0 - γz)^(-g/R))

Finally, to find the density profile ρ(z), we can use the ideal gas law.

ρ(z) = p(z)/(RT(z))

Substituting the expressions for p(z) and T(z), we get ρ(z) = p0((T0 - γz)^(-g/R))/(R(T0 - γz))

This gives us the density profile ρ(z) for an atmosphere with a uniform lapse rate γ.

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Answer:

\(125\:\mathrm{minutes\: or\: }2.08\bar{3}\: \mathrm{hours}\)

Explanation:

Speed is given by \(s=\frac{d}{t}\), where \(d\) is distance travelled and \(t\) is time. Rearranging this equation, we have \(t=\frac{d}{s}\).

Plugging in our given information:

\(t=\frac{d}{s}=\frac{1500\:\mathrm{km}}{720\:\mathrm{km/h}}=2.08\bar{3}\: \mathrm{hours}\)

Thus, our answer is:

\(2.08\bar{3}\: \mathrm{hours}\cdot \frac{60\:\mathrm{minutes}}{1\:\mathrm{hour}}=\fbox{$125\:\mathrm{minutes}$}\)

Answer:In short yes in long

Explanation:yes all substances can exist in any of these three states. In addition to existing in one of the three states, matter can also undergo a change of state. A change of state occurs when matter is converted from one state to another state for example when a liquid is converted to a gas or a solid is converted to a liquid.

Answer:

\(p = f \div a\)

\(p = \frac{185.6}{ {3}^{2} } = \frac{185.6}{9} = 20.6pa\)

Yes, it is possible to use dimensional physical quantities in a way that results in a dimensionless physical quantity. The process of combining physical quantities to obtain a dimensionless quantity is known as dimensional analysis, and it is widely used in the sciences to help simplify complex systems and equations.

The process of using the dimensions of physical quantities to determine the relationship between them is known as dimensional analysis. In other words, it's a mathematical technique that uses the dimensions of a physical quantity to determine how it relates to other physical quantities.Dimensions of the Efficiency of Heat EngineIn the case of the efficiency of a heat engine, the dimension of heat is [M L² T⁻²] and the dimensions of efficiency is dimensionless,

so it is given as:1 - [Qout/Qin]Therefore, the dimensional formula of efficiency will be: [M L² T⁻²] - [M L² T⁻²] / [M L² T⁻²] = [no dimension] Yes, it is possible to use dimensional physical quantities in a way that results in a dimensionless physical quantity. The process of combining physical quantities to obtain a dimensionless quantity is known as dimensional analysis, and it is widely used in the sciences to help simplify complex systems and equations.The efficiency of a heat engine is given by, = 1 − Qout/Qin, where Qin and Qout respectively are the heat given to the engine and the heat exhausted from the engine.a) Establish the dimensions of the efficiency of a heat engine.The dimension of heat is [M L² T⁻²] and the dimensions of efficiency is dimensionless, so it is given as:1 - [Qout/Qin]Therefore, the dimensional formula of efficiency will be: [M L² T⁻²] - [M L² T⁻²] / [M L² T⁻²] = [no dimension]Explanation:The dimensional analysis is used to simplify complex equations in science. In the case of heat engines, the efficiency is given by the ratio of the heat given to the engine (Qin) to the heat exhausted from the engine (Qout).

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The net vertical force on the caboose (C) is

∑ F[v, C] = F[n, C]  - (1.4 kg) g = 0

where F[n, C] is the magnitude of the normal force exerted by the track on the caboose; so we have

F[n, C] = (2.3 kg) g = 13.72 N

which means the coefficient of kinetic friction µ between the caboose and the track is

F[f, C] = 0.46 N = µ (13.72 N)   ⇒   µ = (0.46 N) / (13.72 N) ≈ 0.034

and presumably the coefficient is the same for the locomotive.

The net vertical force on the locomotive (L) is

∑ F[v, L] = F[n, L] - (2.3 kg) g = 0

where F[n, L] is the magnitude of the normal on the locomotive, so that

F[n, L] = (2.3 kg) g = 22.54 N

and so the locomotive is opposed by a frictional force with magnitude

F[f, L] = µ (22.54 N) ≈ 0.76 N

Taking the locomotive and caboose together, the net horizontal force on the system is

∑ F[h] ≈ - F[f, C] - F[f, L] + F[engine] = (2.3 kg + 1.4 kg) (3.1 m/s²)

Solve for F[engine] :

F[engine] ≈ (3.7 kg) (3.1 m/s²) + 0.46 N + 0.76 N ≈ 13 N

Answer:

True the plastic will float because of the principle of flotation or buoyancy

Explanation:

Buoyancy explains it all!!

Buoyancy  is the upward force/upthrust experienced by a body immersed totally or partially in a liquid.

According to the principle of flotation:

"when a body is totally or partially immersed in liquid it experiences an upthrust which is equal to the volume of fluid displaced"

The plastic will float due to the fact the average density of the total volume of the plastic and the air inside it is less than the same volume of water it is floating in

The correct case clause would be A. Case Is >7.

In a Select Case block, the case clauses are used to check different conditions against a selector value. The selector value is compared with each case clause, and the first matching case clause is executed.

To determine which case clause will be true when the selector value is greater than or equal to 7, we need to consider the available options:

A. Case Is >7: This case clause will be true when the selector value is greater than 7.

B. Case Is = 8: This case clause will be true only when the selector value is exactly 8.

Since we are interested in finding the case clause that matches when the selector value is greater than or equal to 7, option A (Case Is >7) is the correct choice. It covers all values greater than 7, including 8 and any other number greater than 8.

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Answer:

a) ray horizontal and ray leaves his feet

b) The normal line respect to which the angles are measured,

c) The angle x is the reflected angle

d) virtual image,  right image

Explanation:

a) To complete the rays, you must draw a horizontal ray at the height of the man's head, this ray touches the mirror perpendicularly, therefore it bounces in the same direction.

The other ray leaves his feet and touches the mirror at one point, it is reflected with the same angle, by the law of reflection and reaches the eyes of man, the brain creates an extension of this ray and at the point of the floor creates the image point.

b) The normal line is a line perpendicular to the surface with respect to which the angles are measured,

c) The angle x is the reflected angle, which is equal to the incident angle according to the law of reflection

d) The image is formed by the prolongation of the rays of light, therefore it is a virtual image and as it has the same direction of the man it is a right image

D.  The movement that will require the greatest amount of work to be

done is a force of 15n moving an object a distance of 5.0m (75 J).

Work is said to be done when an applied force moves an object over a given distance.

W = Fd

where;

W = 10 x 3 = 30 J

W = 10 x 5 = 50 J

W = 15 x 3 = 45 J

W = 15 x 5 = 75 J

Thus, the movement that will require the greatest amount of work to be

done is a force of 15n moving an object a distance of 5.0m (75 J).

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Answer:

the wavelength is 9.8 meters

Explanation:

We can use the relationship:

Velocity = wavelenght*frequency.

Initially we have:

wavelenght = 4.9m

velocity = 9.8m/s

then:

9.8m/s =  4.9m*f

f = 9.8m/s/4.9m =  2*1/s

now, if the velocity is doubled and the frequency remains the same, we have:

2*9.8m/s = wavelenght*2*1/s

wavelenght = (2*9.8m/s)*(1/2)s = 9.8 m

Answer:

9.8

Explanation:

Answer:

Positive I believe... because if you drop it it is negative so picking up a book means positive. thanks for the points though!

Explanation:

Can I have brainliest please? <3

A heat engine operates by converting thermal energy into mechanical energy. The efficiency of a heat engine is defined as the ratio of the useful work output to the heat absorbed from the hot reservoir.

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Answer:

decrease and neutralize each other

Explanation:

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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The man will hear an intensity of sound more than 50% of the maximum value over a range of distances greater than 5.5 ft from gap in the wall, and he will hear an intensity of sound more than 5% of maximum value over a range of distances greater than 1.9 ft from gap in the wall.

Assuming that sound of frequency 2000 Hz is emitted isotropically from a point source:

\(CI = P/(4\pi r^2)\)

The total distance traveled by the sound wave is:

\(D = (50 + x) + 1.5\)

Using the formula for the intensity of a sound wave:

\(I/I_{max} = [(50 + x) + 1.5]^2 / (50 + x)^2\)

For\(I/I_{max} > 0.05\), we have:

\([(50 + x) + 1.5]^2 / (50 + x)^2 > 0.5\)

\(x > 5.5 ft \ or \ x < -56.5 ft\)

Since x must be positive, the range of values of x for which\(I/I_{max} > 0.05\) :

\(x > 5.5 ft\)

\([(50 + x) + 1.5]^2 / (50 + x)^2 > 0.05\)

Solving for x, we get:

\(x > 1.9 ft \ or \ x < -52.9 ft\)

The range of values of x for which\(I/I_{max} > 0.05\) is:

\(x > 1.9 ft\)

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All objects do have gravity, but the gravitational force between two objects depends on their masses and the distance between them. The force of gravity between two objects decreases rapidly as the distance between them increases.

It's also worth noting that objects need to be very massive and very close together for the gravitational force to become noticeable. For example, two people standing next to each other have a very small gravitational force between them, while two planets orbiting each other have a much stronger gravitational force.

In summary, while all objects have gravity, the gravitational force between objects depends on their masses and the distance between them, and the force of gravity between us and nearby objects is usually too small to have a noticeable effect. The force of gravity between us and the Earth is what keeps us in place and gives us weight.

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The distance at which the crane lift a crate is 0.0781 m.

Distnace is the lenght between two points.

To determine the distance the crane can lift the crate, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the distance is 0.0781 m.

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Given information: The average method reports the following unit data for the forming department. Units completed in the forming department are transferred to the painting department. Production cost information for the forming department follows.

Direct materials:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Direct materials cost = $202,500

Conversion costs:
Units completed during the period = 45,000 units
Ending work in process inventory = 5,000 units
Conversion cost = $189,000

a. Calculation of equivalent units of production for both direct materials and conversion for the forming department:
Equivalent units of production = Units completed during the period + (Ending work in process inventory * Degree of completion)
Direct materials:
Equivalent units of production = 45,000 + (5,000 * 50%) = 47,500 units

Conversion costs:
Equivalent units of production = 45,000 + (5,000 * 60%) = 48,000 units

b. Calculation of the cost per equivalent unit of production for both direct materials and conversion for the forming department:
Cost per equivalent unit of production = Total cost for the period / Equivalent units of production

Direct materials:
Cost per equivalent unit of production = $202,500 / 47,500 units = $4.26 per unit

Conversion costs:
Cost per equivalent unit of production = $189,000 / 48,000 units = $3.94 per unit

c. Calculation of the cost assigned to the forming department's output using the weighted average method:
Total cost = Cost of units transferred out + Cost of ending work in process inventory
Cost of units transferred out = Number of units transferred out * Cost per equivalent unit of production
Cost of ending work in process inventory = Number of units in ending work in process inventory * Cost per equivalent unit of production

Direct materials:
Cost of units transferred out = 40,000 * $4.26 per unit = $170,400
Cost of ending work in process inventory = 5,000 * $4.26 per unit = $21,300
Total cost = $170,400 + $21,300 = $191,700

Conversion costs:
Cost of units transferred out = 40,000 * $3.94 per unit = $157,600
Cost of ending work in process inventory = 5,000 * $3.94 per unit = $19,700
Total cost = $157,600 + $19,700 = $177,300

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When light travels from one medium to another, its speed, direction, and wavelength can change, while its frequency remains constant. These changes are due to differences in the refractive indices of the two media.

As light travels from one medium to another, several of its properties change, including its speed, direction, and wavelength. The speed of light changes because the refractive index of each medium is different, which alters the velocity of the wave. The direction of the light may also change, a phenomenon known as refraction, as it enters a medium with a different refractive index. The amount of refraction depends on the angle of incidence, the angle between the incoming light and the normal line to the surface of the medium. Finally, the wavelength of the light may also change due to the refractive index of the medium, a phenomenon known as dispersion. This results in the separation of white light into its component colors when it passes through a prism or other refracting medium.

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The objective's focal length is roughly -15.31 cm. The converging lens objective is indicated by the negative sign.

The formula for compound microscope magnification can be used to get the focal length of the objective:

M = -(f₀ / fₑ)× (1 + d / f₀)

Where:

M = Magnification of the compound microscope = -4515 (negative sign indicates an inverted image)

f₀ = Focal length of the objective

fₑ = Focal length of the eyepiece = 2.6 cm

d = Distance between the objective and eyepiece = 16 cm

f₀ = -(M * fₑ) / (M + (d / fₑ))

Putting all the given values:

M = -4515

fₑ = 2.6 cm

d = 16 cm

f₀ = -((-4515) × 2.6) / (-4515 + (16 / 2.6))

f₀ ≈ -15.31 cm

Therefore, the objective's focal length would be roughly -15.31 cm and the converging lens objective will be indicated by the negative sign.

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Answer:

D

Explanation:

Because full time 4WD does not allows the driver to select 2WD or 4WD. And part-time 4WD does not includes a differential or viscous coupling that allows the front and rear axles to rotate at different speeds.