When a car is traveling at speed of 30 km per hour. a bug hits the windscreen and goes splat the bug's force on the windshield is equal to the windshield's force on the bug.
Why bug's force on the windshield is equal to the windshield's force on the bug?Bug's force on the windshield is equal to the windshield's force on the bug because the system bug-car maintains its overall momentum during the collision, the change in the car's momentum is equal to and opposes the change in the bug's momentum.
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A car moving at a speed of 20m/s has a kinetic energy of 300,000 J what’s the cars mass
Answer:
1500 kgExplanation:
The mass of the car can be found by using the formula
\(m = \frac{2k}{ {v}^{2} } \\ \)
From the question we have
\(m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ \)
We have the final answer as
1500 kgHope this helps you
The symbol equation for combustion of a hydrocarbon is shown below. What number will go before the oxygen reactant when this equation is balanced?
Answer:
5 Oxygen , 3 Carbon dioxide and 3 water
Answer: the answer is 5
Consider the two-dimensional scalar potential function phi(x, y) = x^3 - 3y^2 x.
(a) Make a plot of the equipotential contours for three positive and three negative values for phi. (b) Find nabla^bar phi.
(c) Show that the nabla^bar phi field lines are given by setting 3x^2 y - y^3 equal to a series of constants. (d) Plot six representative nabla^bar phi field lines. Be sure to indicate the direction of the field and comment on its magnitude. (e) Find nabla^bar middot nabla^bar phi, the divergence of the nabla^bar phi vector field, and show that your field lines of part (d) agree with this divergence.
(a) To make a plot of the equipotential contours for three positive and three negative values for phi, we need to set phi equal to each value and plot the resulting curves. For positive values, we can use phi = 1, 2, 3, and for negative values, we can use phi = -1, -2, -3. The resulting curves are shown in the figure below.
(b) To find nabla^bar phi, we need to take the partial derivatives of phi with respect to x and y. Thus, nabla^bar phi = (3x^2 - 3y^2, -6xy).
(c) To show that the nabla^bar phi field lines are given by setting 3x^2 y - y^3 equal to a series of constants, we need to set the components of nabla^bar phi equal to some constants kx and ky, respectively. Solving for y in terms of x and using the result in the other equation, we get:
3x^2 (ky/kx) - (ky/kx)^3 = y^2
y = ±sqrt(3x^2 (ky/kx) - (ky/kx)^3)
Thus, the field lines are given by the above equation with different values of kx and ky.
(d) To plot six representative nabla^bar phi field lines, we can choose six different values of kx and ky and plot the resulting curves. The direction of the field is given by the direction of nabla^bar phi, which is shown by the arrows in the figure below. The magnitude of the field is proportional to the density of the field lines, with denser lines indicating stronger fields.
(e) To find nabla^bar middot nabla^bar phi, we need to take the divergence of nabla^bar phi. Thus, nabla^bar middot nabla^bar phi = 3x^2 - 6y^2. This agrees with the equation for the field lines we found in part (c), since the constants kx and ky correspond to different values of 3x^2 - y^3.
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Drag the cannon up to a height of around 13m. (Use the tape measure to set the cannon height!)
Choose an initial speed between 10 and 40 m/s. Make sure the angle is 0°.
a. Determine the horizontal and vertical components. Show your equations.
b.
Calculate the range, height (distance) and time in the air. You must show your work
c. Check your work with the program.
Voice
a) The initial horizontal velocity is V = 10m/s and the inital vertical velocity is ZERO as the angle is set at 0°, so no vertical component
b) The time of flight can be calculated using the height given
Equation of motion, h = 0 +\(\frac{gt^2}{2}\)
h=\(\frac{9.8\cdot1.63\cdot1.63}{2}\)
h= 13.01 m
The time of flight can be calculated using the height given
t =\(\sqrt{(2\cdot13\div9.8}\) = 1.6288220358559 sec ≅ 1.63 sec
So now :
the horizontal Range is
R = Vt = 10 × 1.6288220358559
=16.288220358559 ≅16.29 m
The horizontal distance covered by the item during this motion is referred to as the projectile's Range.When an object is projected in a projectile motion, some force is imparted to it. As a result, its starting velocity is fixed. The only acceleration that occurs throughout the motion is in the vertical direction and it results from gravity pulling downward.To know more about horizontal Range visit : https://brainly.com/question/23827445
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is an object that has 3 electrons and 5 protons a positive charge?
Answer:
Hello, Yes i believe it would be a positive charge considering electrons have a negative charge while protons have a positive charge.
Explanation:
What is a light year?
A: the distance light travels in one earth year
B: the time it takes light to travel across the universe
C: the distance light travels in one orbit of the moon
D: the distance light travels from the sun to the earth
Answer:
A: The distance light travels in one year
g two pool balls, each moving at 2 m/s, roll toward each other and collide. suppose after bouncing apart, each moves at 2 m/s. assume the positive direction is to the right. this collision violates conservation of group of answer choices kinetic energy momentum both kinetic and momentum none of the above
This collision violates conservation of both energy and momentum i.e, third option is correct.
According to the law of conservation of momentum, when two bodies collide their total momentum and energy before and after collision are equal.
According to the law of conservation of energy, energy can neither be created nor destroyed. However, it can be transformed from one form to another. It is also known as the first law of thermodynamics.
Given that, the two bodies move with same velocities after collision, means that the law has not been violated since, momentum = mass*velocity (where mass is said to be constant)
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This question will ask you to calculate what fraction of the light from the Sun is intercepted and reflected by the Earth. To get an upper bound let us assume the Earth is perfectly reflective, like it would be if it were covered in clouds. To compute it, compare the cross-section of the Earth (the area of a circle with radius REarth) to the area of a sphere centered on the Sun that has a radius equal to the radius of the orbit of the Earth (meaning, take the ratio of those two numbers). What is the cross-section of the Earth, Au? Select the correct one below: (a) TR Earth (b) 47 REarth (c) R Earth What is the area of a sphere centered on the Sun is with a radius r, Az? Choose the correct one below: (a)tr2 (b) 472 (c) p2 You can easily find sizes and distances on the Internet. Express them in the same units to take a meaningful ratio (meter or kilometers will work best). What is the ratio (A1/A2)? Make sure to have 2 significant digits after the decimal point for the first blank. A1/A2 = x 10
The fraction of light from the Sun intercepted and reflected by the Earth is approximately 4.26 x 10⁻⁵.
To calculate the fraction of light from the Sun intercepted and reflected by the Earth, we need to compare the cross-section of the Earth to the area of a sphere centered on the Sun with a radius equal to the radius of Earth's orbit.
The cross-section of the Earth can be calculated as the area of a circle with radius REarth, which is option (c) R Earth.
The area of a sphere centered on the Sun with a radius r is given by 4πr², where r is the radius of the Earth's orbit. Therefore, the area of the sphere centered on the Sun with a radius equal to the radius of Earth's orbit is 4π(149.6 x 10⁶ km)²= 2.83 x 10²³ m².
The ratio of the cross-section of the Earth to the area of the sphere is A1/A2 = πREarth² / 4πr² = (REarth/r)². Using the radius of Earth's orbit in meters, r = 149.6 x 10⁹ m, and the radius of Earth, REarth = 6,371 km = 6.371 x 10⁶ m, we get A1/A2 = (6.371 x 10⁶ m / 149.6 x 10⁹ m)² = 4.26 x 10⁻⁵.
Therefore, by calculating we can say that the fraction of light is approximately 4.26 x 10⁻⁵.
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A ball starts from rest and reaches a final velocity of 3.3 m/s as it reaches
the bottom of a hill. If it takes 10 s to reach the bottom of hill, what is its
acceleration? *
O 0.25 m/s2
O 0.33 m/s2
O 0.50 m/s2
O 1.33 m/s2
answer
0.33m|s2
Explanation:
v= 3.3m|s
t=10s
\(a = v \t\)
=3.3÷10
=0.33m|s2
Actividad
1: En general, la dificultad para arrancar electrones aumenta de izquierda a derecha en cada periodo de la tabla periódica. Busca en la tabla periódica potasio (K), calcio (Ca) y uranio (U) y basándote en sus posiciones indica cuál de ellos tendrá una función de trabajo más baja y cuál más alta:
Menor función de trabajo:
Mayor función de trabajo:
2.- La energía de un electrón emitido se mide en electrón-voltios(eV). Un electrón con una energía de 1 eV puede superar un campo eléctrico de 1 voltio. En el simulador, aumenta la tensión hasta que encuentres la tensión más alta que todavía permite a los electrones llegar al amperímetro.
Tensión =
El volaje que has encontrado es igual a la energía de los electrones emitidos en eV.
What is the type of radioactive decay represented by the equation above? A. Gamma B. Fusion C. Alpha D. Fission 40. Alberta uses clean coal technology. This means that the coal has a lower i content than coal in other parts of Canada, which results in reduced ii The statement above is completed correctly by the information in row olla sdf to ridW Row i A. sulfur greenhouse gas emissions acid deposition sulfur carbon greenhouse gas emissions acid deposition carbon B. C. D. 29. Which of the following graphs depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth? A. Field Strength (N/kg) C. Field Strength (N/kg) Mass (kg) Mass (kg) B. Field Strength (N/kg) D. Field Strength (N/kg) Mass (kg) CADLC 30. Which of the following sequences of colours represents the changing temperatu from the surface to the atmosphere of the sun? a A. Red, orange, yellow, blue B. Yellow, red, orange, blue C. Orange, yellow, blue, red D. Blue, yellow, orange, red 1. When a star undergoes a blue shift, the star is A. moving away from an observer B. moving towards an observer C. moving parallel to an observer D. stationary Mass (kg)
The sun is Yellow, red, orange, and blue. Therefore option B is correct.
The star is moving toward an observer. Therefore option B is correct.
39. The type of radioactive decay represented by the equation provided Gamma. Therefore option A is correct.
40. The statement is completed correctly by the information which states that the coal in Alberta has a lower carbon content than coal in other parts of Canada, resulting in reduced greenhouse gas emissions.
29. graph B depicts the relationship between gravitational field strength and the mass of the International Space Station orbiting Earth.
30. The correct sequence of colors representing the changing temperature from the surface to the atmosphere of the sun is Yellow, red, orange, and blue. Therefore option B is correct.
1. When a star undergoes a blue shift, it indicates that the star is moving toward an observer. Therefore option B is correct.
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A wave traveling in a string has a wavelength of 35 cm, an amplitude of 8. 4 cm, and a period of 1. 2 s. What is the speed of this wave?.
0.29 m/s is the speed of this wave.
How can we determine a wave's speed?
Given: The wave's traveling wavelength is () = 35 cm
The wave's period (t) is 1.2 seconds.
The wave's frequency is 0.833 Hz.
We must ascertain a wave's wave speed.
Formula for wave speed is 35 x 0.833 (wavelength x frequency).
= 29.167 cm/sec
= 0.29 m/sec
As a result, the wave's speed is 0.29 m/s.
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A 250 Kg cast iron car engine contains water as a coolant. Suppose the temperature of the engine is 35°C when it is shut off. The air temperature is 10°C. The heat given off
by the engine and water in it, as they cool to air temperature is 4. 4x106 J. What mass of water is used to cool the engine?
Approximately 4.188 kg of water is used to cool the engine.
To determine the mass of water used to cool the engine, we need to use the specific heat capacity of water and the formula for heat transfer.
We can assume that the engine and water in it initially had a temperature of 35°C and cooled to 10°C. The temperature difference is ΔT = 35°C - 10°C = 25°C.
The formula for heat transfer is Q = mcΔT, where Q is the heat transferred, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.
We are given Q = 4.4x \(10^{6}\) J and the mass of the engine, so we need to find c for water.
The specific heat capacity of water is 4.18 J/g°C. We can rearrange the formula to solve for the mass of water: m = Q / cΔT. Plugging in the values, we get:
m = 4.4x \(10^{6}\) J / (4.18 J/g°C x 25°C) = 4188 g or 4.188 kg
Therefore, approximately 4.188 kg of water is used to cool the engine.
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Match the following. Match the items in the left column to the items in the right column.
1. March 21
7
North Pole
2. Arctic
vernal equinox
3. December 21
longitude
4. meridians
lowest point on earth
5. September 23
latitude
6. Greenwich, England
South Pole
7. Antarctic
winter solstice
8. Marianas Trench
autumnal equinox
9. parallels
Prime Meridian
10. International Date Line
180th meridian
Answer:
March 21 = Vernal Equinox
Artic = North Pole
December 21 = Winter Solstice
Meridians = Longitude
September 23 = Autumnal Equinox
Greenwich, England = Prime Meridian
Antarctic = South Pole
Marianas Trench = Lowest point on earth
Parallels = Latitude
International Date Line = 180th Meridian
Explanation:
a metal block increases in tempreture from 15 digree to 60 digree when supplied with 13500 j of heat energy
By finding the specific heat, we can expect that the material of the block is copper or silver (or a mix).
Of which type of metal is the block made?We know that we give 13,500 joules of energy to the metal block (which we assume has a mass of 1kg) and the temperature increases from 15°C to 60°C.
Then the increase is:
60°C - 15°C = 45°C
Then this metal has a specific heat of:
H = 13,500j/(45°C*1 kg) = 300 J/°C*kg
So it could be copper, which has a specific heat of 380J/°C*kg or Silver, which has a specific heat of 240 J/°C*kg (or a mix of these two).
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an astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?
Answer:
The answer is
28 kgExplanation:
The mass of an object given it's momentum and velocity / speed can be found by using the formula
\(m = \frac{p}{v} \\ \)
where
m is the mass
p is the momentum
v is the speed or velocity
From the question
p = 280 kg/ms
v = 10 m/s
The mass of the object is
\(m = \frac{280}{10} = 28 \\ \)
We have the final answer as
28 kgHope this helps you
What is the rules/guidelines: of running ?
Throughout the race, sprinters must stay in their allotted lanes and are not permitted to cross them. They begin the 800-meter race in varying positions and have the opportunity to break ahead after the first curve.
How much running is safe per week?Studies show that running at a moderate speed for just just few minutes each day can help reduce your risk of dying from common illnesses including strokes and heart attacks. The same study does, however, also demonstrate that these benefits cease to exist after four hours per week, undermining the necessity of regular long runs.
How long can a novice jog for?Between two and four runs per week, lasting around twenty to thirty minutes (or 2 to 4 miles each), are recommended for new runners. You may be familiar with the 10% Rule, but running more frequently every other week is a superior strategy for increasing your mileage. Your body will be assisted in adjusting to your.
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pls help me to answer this
Answers:
Geography (geo-gra-phy)Location (lo-ca-tion)Coordinates (co-or-di-nates)Landmass (land-mass)Absolute (ab-so-lute)Vicinal (vi-ci-nal)Insular (in-su-lar)Relative (re-la-tive)Note: It's very likely the tile labeled "MAL" should be "NAL", and that "MATES" should be "NATES".
==================================
Explanations:
Geography deals with not only places, but also the people and cultures in those places. That's more of a social or human geography course. Natural geography talks about land formations, volcanos, rivers, etc.I'm not sure there's much to say about this term. It's simply a position in 2D or 3D space depending on context.Coordinates are things like longitude and latitude. Think of the (x,y) points on a grid. Side note: The tile "mates" should be labeled as "nates". Your teacher made a typo. In some dialects, the "co" and "or" are pronounced together; almost sounding like "core". The term "landmass" is exactly what you'd expect it should be: a big chunk of land. When you mention if a person has absolute freedom, then we consider that person having no restrictions of movement/choice/etc. It also refers to something like a local coordinate space talks about the surrounding area, whereas an absolute coordinate space doesn't have to worry about such issues. Eg: a local coordinate could be "go 5 blocks from the store" and an absolute coordinate would be to provide a GPS location. As you can see, the local coordinate space needs the store as an anchor or else it wouldn't make much sense.To be quite honest, I had a bit of a long time to find this answer. I suppose if you are good with words then it shouldn't be too much of a struggle. But I did a reverse dictionary lookup and only focused on three syllable words until I arrived at "vicinal" which is related to "vicinity". Eg: The person was just in the vicinity. Anyways, I haven't really seen this word used too much in everyday language, so that's probably why it took a while for me. I have a feeling your teacher meant to write "NAL" instead of "MAL" as one of the tiles. This appears to be the second time s/he mixed up M's with N's (the first time being "MATES" mixed up with "NATES"; see problem 3). Insular is an adjective referring to a person or group of people cut off from the larger world. Think of a small town where it's hard to reach. Islands are of course like this, but we could have an "island" rural small town or some culture in a remote location that is on a continent somewhere. It doesn't necessarily have to be a literal island surrounded by water. Think of the word "insulate" to help remember "insular". Also, the term "insular" could refer to the deliberate attempt to keep oneself (or one group) closed off from the rest of the world. An example of this is the Amish culture being insular to the American culture surrounding them. If object A is larger than object B, then we say A is relatively large compared to B. This is one example usage of the word "relative".How do food molecules compare to each other?
a physics demo launches a ball horizontally while dropping a second ball vertically at exactly the same time.
if two balls are launched from a height. One is horizontally and other is vertically downwards, then both of the balls will touch the ground exactly at the same time.
When a ball is launched from a height than at some angle then its velocity(v) can be considered as divided into two components: One is vertical and the other is horizontal.
v₁ = vcosθ (horizontal component)
v₂ = vsinθ (vertical component)
Vertical component is always subjected to the acceleration due to gravity. Which is same for every vertical motion. Since the dropping height is same for both the balls, so their travelling time in the vertical downward direction will also be same. So they will touch the ground exactly at the same time.
--The given question is incomplete, the complete question is
"A physical demo launches a ball horizontally while dropping a second ball vertically at exactly same time from same height. Which ball will touch the ground first?"--
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The Keck Telescope has a diameterof 10.0 m. When it is looking atMars, 7.38 1010 m from us, how farapart are the closest objects it couldpossibly resolve? Assume the lighthas wavelength 633 nm.[?] m
Given:
Diameter, D = 10.0 m
Distance, x = 7.38 x 10¹⁰ m
Wavelength, λ = 633 nm
Let's find how far apart the closest objects it could possibly resolve.
First, apply the formula for the angle for angle separation (limit of resolution):
\(\theta=\frac{1.22\lambda}{D}\)Thus, we have:
\(\begin{gathered} \theta=\frac{1.22*633\times10^{-9}}{10.0} \\ \\ \theta=\frac{7.7226\operatorname{\times}10^{-7}}{10.0} \\ \\ \theta=7.7226\operatorname{\times}10^{-8}\text{ rad} \end{gathered}\)Now, to find the distance of the closest objects, we have:
\(d=\theta *x\)Thus, we have:
\(\begin{gathered} d=7.7226\times10^{-8}*7.38\times10^{10} \\ \\ d=5699.28\text{ m} \end{gathered}\)Therefore, the distance of the closest objects is 5699.28 meters.
• ANSWER:
5699.28 m
The structure of an atom consists of
A. a proton surrounded by neutrons
B. a nucleus surrounded by electrons
C. a nucleus containing protons and electrons
D. a "cloud" of protons, electrons, and neutrons
Answer:
the correct answer is C
Explanation:
a nucleus of atom is contain protons and electrons
Of the following numbers: 0.0034 m, 45.6 m, and 1234 m, _____ is the least precise.1) 0.0034 m2) 45.6 m3) 1234 m4) none
ANSWER:
3) 1234 m
STEP-BY-STEP EXPLANATION:
Precision refers to how close two measurements are to one another. The highest number with a significant digit is the most precise, the number that has the most significant figures. Therefore, the less accurate is the opposite.
Which means that in this case, the least precise number is 1234 m.
A marble statue has a mass of 1800 kg and is
384 cm tall.
The density of marble is 2500 kg/m³.
Oliver makes a mathematically similar model
of the statue out of clay.
The model is 48 cm tall and has a density of
1300 kg/m³.
What is the mass of Oliver's model?
Give your answer to 3 significant figures.
Answer:
The answer is 144kg to 3s.f
Explanation:
convert cm to m
48/100=0.48
V=L³
V=0.48³
V=0.110592m³
\(density = \frac{mass}{volume} \)
1300=m/0.110592
m=1300×0.110592
M=144Kg o 3s.f
Can someone one help me please !!!
Answer:
Current in the circuit(I) = 0.5 ampere
Explanation:
Given:
Number of resistors = 2 (10 ohm each)
Series of resistors
EMF = 10 volt
Find:
Current in the circuit(I)
Computation:
Total resistance in series = R1 + R2
Total resistance in series = 10 + 10
Total resistance in series = 20 ohm
Current in the circuit(I) = EMF / Total resistance in series
Current in the circuit(I) = 10 / 20
Current in the circuit(I) = 0.5 ampere
The minute hand of a clock completes one revolution in one hour. There are 3,600 seconds in one hour. Calculate the frequency of the minute hand
The frequency of the minute hand is 1/60 Hz. Given that the minute hand of a clock completes one revolution in one hour and there are 3,600 seconds in one hour.
To calculate the frequency of the minute hand: Frequency of the minute hand = No. of revolutions per secondFirstly, let us calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 secondsIn one hour, the minute hand completes 1 revolution. So, in 1 second, the minute hand completes 1/3600 of the revolution.Now, we can calculate the frequency of the minute hand.
Frequency of the minute hand = No. of revolutions per second Frequency of the minute hand = 1/3600 HzTo calculate the frequency of the minute hand, we can use the following steps: Step 1: Calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 seconds In one hour, the minute hand completes 1 revolution.
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you are running a length of fiber optic cable between two wiring closets. what best describes the cable you are running?
The cable being run between the two wiring closets is most likely a fiber optic cable.
Fiber optic cables are used for high-speed data transmission over long distances. They consist of a core of optically transparent material, such as glass or plastic, surrounded by a cladding material that reflects light back into the core.
The core and cladding are protected by an outer jacket or sheath that provides physical protection and insulation. Fiber optic cables are preferred for long-distance communication because they are less susceptible to interference and signal degradation than copper cables.
They are also able to transmit data at much higher speeds and over longer distances without the need for signal repeaters.
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1.What observations have you made about determining ages of rocks and fossils?
2.How do scientific principles explain your observations and how does it support your claim?
In summary, the observations about determining ages of rocks and fossils are based on scientific principles such as radioactive decay, superposition, and original horizontality.
What is scientific principle?A scientific principle is a fundamental concept or law that explains how the natural world works. It is a statement based on empirical evidence and repeated observations that is widely accepted by the scientific community as a fundamental truth. Scientific principles provide a framework for understanding and explaining natural phenomena, and they form the basis for scientific research and discovery.
Examples of scientific principles include:
The law of conservation of energy, which states that energy cannot be created or destroyed, only transformed from one form to another.
The theory of evolution, which explains how species change over time through natural selection and genetic variation.
The law of gravity, which explains the attraction between objects with mass and their impact on space-time.
The principle of relativity, which explains how the laws of physics are the same for all observers in uniform motion relative to each other.
Scientific principles are subject to change and refinement as new evidence and discoveries are made, but they provide a reliable foundation for scientific inquiry and understanding.
Here,
1. Observations about determining ages of rocks and fossils:
Scientists use a variety of methods to determine the ages of rocks and fossils, such as radiometric dating, relative dating, and stratigraphy.
Radiometric dating involves measuring the decay of radioactive isotopes in rocks or fossils, which provides an estimate of the time elapsed since the material was last heated or exposed to sunlight.
Relative dating involves comparing the ages of rocks or fossils based on their position in relation to one another.
Stratigraphy involves studying the layers of rock or sedimentary deposits to determine the relative ages of the materials.
2. Explanation based on scientific principles:
Radiometric dating is based on the principle of radioactive decay, which is the spontaneous breakdown of atomic nuclei into smaller particles over time. The rate of decay is constant, which allows scientists to use the amount of remaining radioactive material to estimate the time elapsed since the material was last heated or exposed to sunlight.
Relative dating is based on the principle of superposition, which states that the oldest rocks or fossils are found at the bottom of a sequence, while the youngest rocks or fossils are found at the top. By comparing the ages of rocks or fossils in different layers, scientists can determine their relative ages.
Stratigraphy is based on the principle of original horizontality, which states that sedimentary layers are deposited in horizontal layers. By studying the layers of rock or sedimentary deposits, scientists can determine the relative ages of the materials based on their position.
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In the blue sky activity, what color was the light coming out if you were staring directly at the flashlight through the glass?.
The color of light coming out of the flashlight through the glass in the blue sky activity is blue.
In the blue sky activity, when we direct the light of a flashlight through the glass, it helps in scattering the light from the flashlight. Since blue light has a shorter wavelength, it gets scattered more than the red light, which has a longer wavelength. When we look directly at the flashlight through the glass, we see that the color of light coming out is blue.The reason behind it is that the blue light is scattered more and it reaches our eyes from different directions. This is why the blue light dominates the other colors. Thus, when the flashlight's light passes through the glass, it undergoes refraction, and the scattered blue light dominates the other colors.
The color of light coming out of the flashlight through the glass in the blue sky activity is blue. The blue light is scattered more and it dominates the other colors.
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Felix throws a bean bag in the air and catches it 2.98 seconds later.
a. Consider the motion of the bean bag to be a free fall motion. How high does it go?
b. What was the bag's initial velocity?
Answer
A) Time to reach zenith
t
=
2.2
2
=
1.1
s
v
=
u
+
a
t
∴
0
=
u
−
9.8
×
1.1
u
=
10.78
m/s
Explanation: