If a hypothetical planet were 4 times the mass and 2 times the diameter of the Earth: a. ...your weight would be one-half of that at the Earth's surface b. ...the density of the planet would be twice the Earth's density. c. ...the density of the planet would be the same as the Earth's density. d. ...the density of the planet would be half as much as the Earth's

The law that the above statement in this image describes is the law of conservation of charge (option C).

The law of conservation of charge states that the total amount of electric charge in a closed system must remain constant.

This means that any system that is not exchanging mass or energy with its surroundings will never have a different total charge at any two times.

This law of conservation of charge was first proposed by British scientist William Watson in 1746 and American statesman and scientist Benjamin Franklin in 1747.

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when the astronaut arrives back on Earth, he will be approximately 40 years old.

To solve this problem, we can use the concept of time dilation in special relativity.

Given that the astronaut travels to a planet 10 light-years away and it takes 20 years on Earth for him to reach there, we can calculate his speed. Since the distance is 10 light-years and the time taken is 20 years, we can divide the distance by the time to find the speed.

Speed = Distance / Time
Speed = 10 ly / 20 years
Speed = 0.5 ly/year

Now, the astronaut turns around and comes back to Earth at the same speed. This means that for the return journey, he will also take 20 years on Earth.

Since the total time taken for the round trip is 20 + 20 = 40 years on Earth, we can calculate how much time has passed for the astronaut during this period using time dilation.

According to time dilation, the time experienced by the moving object (the astronaut) is dilated or stretched relative to the stationary observer (Earth). The time dilation factor can be calculated using the formula:

Time dilation factor = 1 / √(1 - (v^2 / c^2))

Where v is the speed of the astronaut and c is the speed of light (approximately 300,000 km/s).

Plugging in the values:

Time dilation factor = 1 / √(1 - (0.5^2 / (300,000^2)))
Time dilation factor ≈ 1 / √(1 - 0.00000000333)
Time dilation factor ≈ 1 / √0.99999999667
Time dilation factor ≈ 1 / 0.999999998335
Time dilation factor ≈ 1.000000001665

Now, we can calculate the time experienced by the astronaut during the round trip:

Time experienced by the astronaut = Time dilation factor * Time on Earth
Time experienced by the astronaut = 1.000000001665 * 40 years
Time experienced by the astronaut ≈ 40.0000000666 years

Therefore, when the astronaut arrives back on Earth, he will be approximately 40 years old.

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The figure given in the question shows a circuit with resistors that are not all in parallel or series. As a result, it will be necessary to determine the equivalent resistance of each group of resistors separately.

The groups of resistors in this circuit are as follows:R2 and R3 are connected in series, and their equivalent resistance can be calculated using the following equation:

R23 = R2 + R3

= 47 Ω + 100 Ω

= 147 Ω

R5 and R6 are connected in series, and their equivalent resistance can be calculated using the following equation:R56 = R5 + R6 = 150 Ω + 47 Ω = 197 ΩR23 and R4 are connected in parallel, and their equivalent resistance can be calculated using the following equation:

1/R234 = 1/R23 + 1/R4

= 1/147 Ω + 1/220 Ω

= 0.0105 ΩR234

= 95.238 Ω

Finally, R1 and R56 are connected in series, and their equivalent resistance can be calculated using the following equation:

R156 = R1 + R56

= 100 Ω + 197 Ω

= 297 Ω

Therefore, the equivalent resistance of the entire circuit is

R = R156 + R234

= 297 Ω + 95.238 Ω

= 392.238 Ω

= 3.92 × 10² Ω (expressed to three significant figures).

Therefore, the equivalent resistance of the circuit is 3.92 × 10² Ω.

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Answer:

40,000 m/s²

Explanation:

The formula is given as Force = mass × acceleration, so then acceleration = Force / mass.

Therefore...

5800 N ÷ 0.145 kg = 40,000 m/s²

Answer:

D. It focuses on the core muscles

Answer:

A. It is a total body exercise

Explanation:

In cardio kickboxing as described by my school is "

The first benefit is the one which we are focusing on because all the other answers are correct but A. Total body exercise is the best answer because it covers all of them as an compendious answer

Also I took the test and got this correct

According to the rules of continuity, if you are following a subject moving through space and the subject exits screen right (the right of the screen), they should enter the next shot from the left side of the screen. This is known as the 180-degree rule and is used to create a sense of spatial coherence between shots.

The 180-degree rule states that the camera should stay on one side of the action, meaning that a character's movement should remain consistent. To explain further, if a character is moving right, they should keep moving right as they move through the various shots. The same applies for movement left, up, and down. If a character moves off screen right, they should enter the next shot from the left. This creates a smooth and logical transition from shot to shot, which helps the audience understand the spatial relationship between characters.

In addition to the 180-degree rule, other aspects of continuity editing are used to create a cohesive narrative. Continuity editing includes matching eyelines (the direction a character is looking in a shot), matching facial expressions, and matching camera angles. All these elements, along with the 180-degree rule, help create a sense of continuity and flow between shots.

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Answer

Explanation: R=p l/A , we are given specific resistance of aluminium in terms of silver.

One minute has 60 seconds, One hour has 60 minutes and one day has 24 hours. Thus, 80 x 60 x 24 = 86,400 seconds in a day.

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To determine the new force of gravity in the first scenario, we can use the formula for gravitational force:

\(Fg = (G * m1 * m2) / r^2,\)

where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.

If we triple the mass of one object and double the distance between their centers, the new force of gravity can be calculated as follows:

New \(Fg = (G * (3m) * m) / (2r)^2.\)

Simplifying this expression, we get:

New Fg = (G * 3m * m) / (4r^2).

Since (3m * m) / (4r^2) is equivalent to (3/4) * (m * m) / (r^2), we can rewrite the equation as:

New \(Fg = (3/4) * (G * m * m) / r^2.\)

Comparing this to the original force of gravity, Fg, we see that the new force is (3/4) times the original force. Therefore, the answer is C) 0.75 Fg.

Regarding the second scenario, for objects in stable orbit, the orbital period is determined by the formula:

\(T = 2π * sqrt(r^3 / (G * M)),\)

where T is the orbital period, r is the distance between the center of the object and the center of the Earth, G is the gravitational constant, and M is the mass of the Earth.

If Satellite B is twice as far from the Earth's center compared to Satellite A, we can say that r_B = 2 * r_A.

Let's compare the orbital periods of the two satellites:

T_B = 2π * sqrt((2r_A)^3 / (G * M)) = 2π * sqrt(8r_A^3 / (G * M)).

T_A = 2π * sqrt(r_A^3 / (G * M)).

Dividing T_B by T_A, we get:

T_B / T_A = (2π * sqrt(8r_A^3 / (G * M))) / (2π * sqrt(r_A^3 / (G * M))).

Simplifying this expression, we find:

T_B / T_A = sqrt(8r_A^3 / (r_A^3)) = sqrt(8) = 2.83.

Therefore, the answer is a) 2.83 times larger.

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When two objects are experiencing gravitational attraction, if you triple the mass of one of the objects and double the distance between their centers, the new force of gravity compared to the old will be 0.75 times the original force (0.75 Fg).The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the force of gravitational attraction between two objects is inversely proportional to the square of the distance between their centers of mass. If you double the distance between two objects, the force of gravitational attraction decreases by a factor of 4 (2^2). On the other hand, if you triple the mass of one of the objects, the force of gravitational attraction increases by a factor of 3.

Therefore, combining these effects, the new force of gravity will be 3/4 or 0.75 times the original force.

Satellite A and Satellite B are both in stable orbit around the Earth, but Satellite B is twice as far from the Earth's center as Satellite A. The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the orbital period of an object in circular motion is dependent on the radius of the orbit. The further an object is from the center of the orbit, the longer it takes to complete one full orbit. Since Satellite B is twice as far from the Earth's center as Satellite A, its radius is also twice as large. The orbital period is directly proportional to the radius, so Satellite B's orbital period will be 2.83 times larger than Satellite A's orbital period.

Therefore, the correct statement is:

The new force of gravity compared to the old will be 0.75 Fg.

The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

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Kepler discovered planets by using a tracking technique called transit. A transit occurs when, as seen from Earth, a planet crosses in front of a star. Transits of terrestrial-sized planets cause only a slight shift in the star's brightness compared to a larger planet.

This technique is based on the fact that a star's brightness will change marginally when an exoplanet transits in front of it. Astronomers can detect the existence of planets by tracking a star's brightness over time and measuring the minute brightness dips that take place when a planet transits across the star's disk. This method can also be used to determine a planet's size and orbital time. Astronomers must observe a star constantly for several weeks or months, depending on the planet's orbital period, in order to spot a transiting planet.

The Kepler mission used a photometer to simultaneously track a wide field of stars in order to increase accuracy. It was the most accurate exoplanet detector ever created, and the information it collected allowed scientists to discover thousands of new exoplanets. Astronomers can now find tiny exoplanets that are in their star's habitable zone and are comparable in size to Earth thanks to the Kepler project.

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Answer:

\(\huge\boxed{50g}\)

Definition:

Half-life- The time taken for half of the radioactive isotopes to decay.

Explanation:

How does radioactive decay work? Radioactive decay is a process by which unstable nuclei become more stable through the emission of alpha or beta particles or gamma rays.

Since a half-life is the time taken for half of the isotopes to decay, we can simply divide the initial mass of 100 grams by 2; this gives us 50 grams.

1) Divide 100g by 2.

\(\frac{100g}{2}=50g\)

Answer:

С. 10.41 Ampere

Explanation:

Given that,

Power, P = 125 watts

Voltage, V = 12 volts

We need to find current. Power in terms of current and voltage is given by :

P = VI, I = current

\(I=\dfrac{P}{V}\\\\I=\dfrac{125\ W}{12\ V}\\\\I=10.41\ A\)

So, the current is 10.41 A.

The major axis is drawn to the longest dimension of an elliptical orbit.The minor axis, on the other hand, is drawn perpendicular to the major axis and represents the shortest dimension of the ellipse.

In an elliptical orbit, the major axis is the line segment that connects the two farthest points of the ellipse. It is also referred to as the longest dimension of the ellipse. The major axis passes through the center of the ellipse and is perpendicular to the minor axis.

The major axis determines the overall size and shape of the elliptical orbit. It represents the maximum distance between the two foci of the ellipse. The foci are the two fixed points within the ellipse, and the sum of their distances to any point on the ellipse remains constant.

By drawing the major axis, we can define the major axis length, which helps determine the size and scale of the elliptical orbit.

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Answer:

a) Eg = 3,060.72 j

b) Ek = 2,080 j

c) Etotal = 5,140.72 j

Explanation:

The given parameters are;

The mass of the person, m = 65 kg

The height of the person, h = 4.8 m

The speed of the person, v = 8.0 m/s

a) The gravitational potential energy, \(E_g\) = m·g·h

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

∴ Eg = 65 kg × 9.81 m/s² × 4.8 m = 3,060.72 j

Eg = 3,060.72 j

b) The kinetic energy, Ek = 1/2·m·v²

∴ Ek = 1/2 × 65 kg × (8.0 m/s)² = 2,080 j

Ek = 2,080 j

c) The constant total Mechanical Energy, Etotal = Eg + Ek

∴ Etotal = 3,060.72 j + 2,080 j = 5,140.72 j

Etotal = 5,140.72 j.

Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

Given:

Voltage input (V) = 30V

Initial speed (w) = 0

Step size (h) = 0.4s

Time at which speed is to be determined (t) = 0.8s

We need to determine the speed (w) at t = 0.8s using Heun's method.

We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)

At t = 0 and w = 0 (initial conditions), we have:

k₁ = 0.02 + 0.06(0) = 0.02

We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)

So, at t = 0.4s and w = 0 (initial conditions), we have:

k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048

So, W₂ = w₁ + (k₁ + k₂)(h/2)

   = 0 + (0.02 + 0.02048)(0.4/2)

   = 0.04048(0.2)

   = 0.008096

Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

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The complete question is:

The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.

Answer:

2 moles

Explanation:

please mark me as brainlest

The mass of one mole of iron sulphide is 88 g. Then the number of moles in 44 g is 0.5 moles.

One mole of a substance is its amount which contains 6.022 × 10²³ atoms. This number is called Avogadro number. One mole of every element contains Avogadro number of atoms.

Similarly one mole of every compound contains Avogadro number of molecules. The mass of one mole of a compound is called its molar mass.

Atomic mass of  Fe = 56 g/mol

atomic mass o S = 32 g/mol

molar  mass of FeS = 56 + 32 = 88 g/mol

Mass of one mole of iron sulphide (FeS) is 88 g. Hence number of moles in 44 g is :

no.of moles = given weight/molar mass

                    = 44 g /88 g/mol = 0.5 mol

Therefore, the number of moles of FeS in 44 g is 0.5.

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Answer:

Over 60N

Explanation:

If the resultant force is equal, the car will not move. In order for the car to move, Becky needs to apply a force that is stronger than 60N, since her dad is already pushing 240 (240+60=300), so anything over 60 from Becky would move the car.

5. All the resistors in this circuit, the 18 Ω resistor included, are in parallel. The voltage drop across each resistor is the same, which is the equivalent to the potential difference of the battery. That is, 36 V [choice K].

6. The ammeter is in series with the branch containing a 12 Ω resistor. Since the voltage drop across this resistor is 36 V, the current in this branch will be I = V/R = (36 V)/(12 Ω) = 3.0 A [choice D].

7. The equivalent resistance of the circuit can be calculated as follows:

1/R = 1/12 + 1/9 + 1/18 = 1/4; thus, R = 4.0 Ω [choice G].

8. Electrical power can be defined as electrical work/time, and electrical work can be given by W = qV. If P = qV/t and q/t = I (charge flowing per unit time is equal to current), then P = VI. From Ohm's law, V = IR, and I = V/R. Substituting V/R for I in the power equation, P = V²/R.

For this circuit, the V = 36 V and R (the equivalent resistance) = 4.0 Ω. So, the power loss in the circuit is P = (36 V)²/(4.0 Ω) = 324 W [choice J].

EAC( Low-energy lightbulb )=18.47 EAC( Conventional lightbulb )=7.33 Conventional lightbulb is cheaper to operate. Option D

To calculate the Equivalent Annual Costs (EAC), we need to consider the initial cost, maintenance costs, and the present value of future costs, taking into account the discount rate.

The EAC (Equivalent Annual Cost) is calculated by summing up the annual costs of the lightbulb over its lifetime, discounted at the real discount rate of 4%.

For the low-energy lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $3.60 + ($2.00 / (1 + 0.04)^1) + ($2.00 / (1 + 0.04)^2) + ... + ($2.00 / (1 + 0.04)^9)

≈ $18.47

For the conventional lightbulb:

EAC = Cost of bulb + Present value of annual electricity cost

= $0.60 + ($7.00 / (1 + 0.04)^1) + ($7.00 / (1 + 0.04)^2) + ... + ($7.00 / (1 + 0.04)^1)

≈ $7.33

Since the EAC for the low-energy lightbulb is $18.47 per year and the EAC for the conventional lightbulb is $7.33 per year, the conventional lightbulb is cheaper to operate assuming a burnt-out bulb is replaced by an identical bulb.

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Answer:

Hey!

Your answer would be option B. Light; heat...

Explanation:

In bioluminescent organisms, the energy is transformed int light energy and less then 20% of the total energy is put into Thermal Radiation!

HOPE THIS HELPS!!

The polarizing angle for sapphire is 59.52 degrees. The polarizing angle for a transparent material is defined as the angle of incidence at which the reflected light is completely polarized perpendicular to the plane of incidence.

At this angle, the reflected light is entirely polarized and no longer contains any unpolarized or partially polarized components.

The polarizing angle can be found using the equation:

tan θp = n

where θp is the polarizing angle and n is the refractive index of the material.

Since the critical angle for total internal reflection for sapphire surrounded by air is given as 34.40, we can use the formula for the refractive index in terms of the critical angle:

n = 1 / sin θc

where θc is the critical angle.

Substituting the given value, we get:

n = 1 / sin 34.40 = 1.671

Now we can use the equation for the polarizing angle:

tan θp = n

tan θp = 1.671

Taking the inverse tangent of both sides, we get:

θp = tan⁻¹ (1.671)

θp = 59.52 degrees

Therefore, the polarizing angle for sapphire is 59.52 degrees.

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The fundamental period (To) of a signal is the smallest T for which it repeats. Frequency (Wo) is the reciprocal of To. Example: To = 0.5s, Wo = 2Hz.

The fundamental period (To) of a periodic signal is the smallest positive value of T for which the signal repeats itself exactly. The frequency (Wo) of a periodic signal is the reciprocal of the fundamental period,

Wo = 1/To.

To find the fundamental period and frequency of a signal, we need to analyze its waveform.

First, let's identify the period of the signal. The period is the horizontal distance between two adjacent peaks (or troughs) of the waveform. If the signal repeats itself exactly, it is periodic.

Once we have identified the period, we can calculate the fundamental period (To) by measuring the distance between two adjacent peaks (or troughs) and taking the smallest positive value.

To calculate the frequency (Wo), we can use the formula Wo = 1/To. Here's an example to illustrate this process:

Let's say the signal waveform repeats itself every 2 seconds. This means the period is 2 seconds.

To calculate the fundamental period (To), we measure the distance between two adjacent peaks (or troughs) and find it to be 0.5 seconds.

Therefore, the fundamental period (To) is 0.5 seconds.

To calculate the frequency (Wo), we use the formula Wo = 1/To. In this case, Wo = 1/0.5 = 2 Hz. So, the fundamental period (To) of the signal is 0.5 seconds and the frequency (Wo) is 2 Hz.

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Answer:

As per Provided Information

we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.

\( \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}\)

Substituting the value and let's solve it

\( \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} \)

Now, let's calculate the force applied to stop the car .

\( \pink{\boxed{\bf \: F = ma}}\)

Substituting the value we get

\( \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N\)

Here , negative sign show that the " Force is acting in opposite direction of the motion"

Therefore,

The lift coefficient CL and the drag coefficient CDi at an angle of attack of 4 degrees are 1.14 and 0.056 respectively.

To calculate the lift coefficient CL and the drag coefficient CDi at an angle of attack of 4 degrees for the given wing, we can use the following equations:
\(CL = 2\pi* (S/b) * (1/(1+(2*S/(b*AR)*tan(0.25*\pi )))) * \alpha\)
where AR is the aspect ratio, which is \(b^2/S\) for a rectangular wing, and alpha is the angle of attack in radians.
Substituting the given values, we get:
AR = \((40^2)/200\) = 8
tan(0.25*π) = 1
\(\alpha\) = 4 * π/180 = 0.07 radians
Therefore, \(CL = 2\pi * (200/40) * (1/(1+(2*200/(40*8)*1))) * 0.07\)
CL = 1.14
Next, we can calculate the drag coefficient CDi using the following equation:
\(CDi = CL^2/(\pi *e*AR)\)
where e is the Oswald efficiency factor, which is assumed to be 0.9 for a symmetric airfoil.
Substituting the given values, we get:
\(CDi = 1.14^2/(\pi *0.9*8)\)
CDi = 0.056
Finally, to use two terms in the series expansion for circulation, we can modify the equation for the circulation as follows: \(r = 2bV[infinity] [A1 sin \phi + A2 sin 2 \phi + A3 sin 3 \phi]\) where A1 and A3 are the two terms used.

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Answer:

I think B but I could be wrong

Explanation:

Michael porter proposed a now widely accepted competitive forces model that includes 5 forces.

Michael Porter's competitive forces model includes five forces, also known as Porter's Five Forces. These five forces are:

The threat of new entrants: The degree to which new competitors can enter the market and compete with existing firms.

The bargaining power of suppliers: The ability of suppliers to increase prices or reduce the quality of goods and services.

The bargaining power of buyers: The ability of buyers to demand lower prices or higher quality goods and services.

The threat of substitute products or services: The degree to which alternative products or services can be used as a substitute for existing products or services.

Rivalry among existing competitors: The intensity of competition among existing firms in the industry.

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Answer:

To find the resulting change in momentum of the system, we need to calculate the momentum of the system before and after the external force is exerted, and then find the difference.

The momentum of a system of particles is the product of the total mass of the system and the velocity of its center of mass. From the graph, we can see that the velocity of the center of mass at t = 2.0 s is approximately 0.8 m/s.

Before the external force is exerted, the momentum of the system is:

p1 = m*v1 = 6.0 kg * 0.8 m/s = 4.8 kg m/s

After the external force is exerted, the velocity of the center of mass changes, and we can estimate it from the graph to be approximately -0.4 m/s at t = 2.0 s + Δt, where Δt is a very short time interval. The momentum of the system after the external force is exerted is:

p2 = m*v2 = 6.0 kg * (-0.4 m/s) = -2.4 kg m/s

The resulting change in momentum of the system is:

Δp = p2 - p1 = (-2.4 kg m/s) - (4.8 kg m/s) = -7.2 kg m/s

Therefore, the resulting change in momentum of the system is -7.2 kg m/s.

Given :

An object with weight 20 N was lifted to 0.5 meters.

To Find :

How high must you lift a 25 Newton book for it to have the same increase in potential energy as the given book.

Solution :

Since both have same potential energy :

\(P.E_2 = P.E_1\\\\W_2h_2 = W_1h_1\)

Putting all given values in above equation :

\(25h_2 = 20\times 0.5\\\\h_2 = \dfrac{20\times 0.5}{25}\\\\h_2 = 0.4\ m\)

Therefore, book with same potential energy is at a height of 0.4 m.

The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N

The gravitaional force between two objects can be obtained by using the following formula:

F = GM₁M₂ / r²

Where

The following data were obtained from he question:

The gravitaional force can be obtained as shown below:

F = GM₁M₂ / r²

F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²

F = 1.63×10³ N

Thus, the gravitational force is 1.63×10³ N

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