A ball from to a planet that has a gravitational acceleration that double that of Earth How does the gravitational force on the new planel c gravitational force on the ball when on Earth?
Answer:
Explanation:
The gravitational force on the ball when it is on the new planet is double the force on the ball when it is on Earth. The gravitational force on the ball when it is on the new planet is half the force on the ball when it is on Earth.
In the electric of capacitance 4 ,3 and 2 microfaradas, respectively, are connected in senes to a battery of 260 V , calculate the charge?
The total charge in the circuit is 240 microcoulombs.
To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.
In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.
To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.
Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.
Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.
Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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Which technology collects data for weather climate and environmental environmental monitoring from space
Answer:B) satellites
Explanation:
I just took the tests
Consider a vector G pointed 36.9 degrees clockwise from the positive y-axis. The vector's x- component has a value of 3. Find the magnitude of vector G.
A vector quantity has both magnitude and direction, and therefore, can be resolved into components
The magnitude of the vector, G is approximately 5 units
The value of the magnitude of the vector is correct for the following reason:
The given parameters are;
The direction in which the vector, G, is pointed, θ = 36.9° clockwise rotation from the positive y-axis
The x-component of the vector = 3
Required:
To find the magnitude of the vector
Solution:
Let |G|, represent the magnitude of the vector
Given that the angle, is measured from the y-axis, we have;
|G| × sin(θ) = The x-component of the vector
Therefore;
|G| × sin(36.9°) = 3
\(|G| = \dfrac{3}{sin(36.9^{\circ})} \approx 4.9965 \approx 5\)
The magnitude of the vector, G ≈ 5
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How does the paddle and water in this photo demonstrate newtons third law? The action force is the __ against the __. The reaction force is the __ pushing back against the ___.
The action force is the oar against the water.
The reaction force is the water pushing back agrains the oar.
. A steel bar 35mm by 35mm in section and 100mm in length is acted upon by a tensile load of 180KN along its longitudinal axis and 400kN and 300kN along the axes of lateral surfaces as shown in figure 2 below. Determine: (i) change in the dimensions of the bar (ii) change in volume Take E = 205 GPa Poisson's ratio (v) = 0.3
(i) The change in length is 8.78 x 10⁻⁸ m and the change in the width is -2.63 x 10⁻⁸ m
(ii) The change in volume of the bar is 7.53 x 10⁻¹¹ m³.
What is the change in the dimensions of the bar?
The bar undergoes elongation and reduction in cross-sectional area due to the applied loads.
Using the formula for longitudinal strain, we can calculate the change in length (ΔL) as follows:
ΔL = (180 × 10³ N) x (100 × 10⁻³ m) / (205 × 10⁹ N/m²)
ΔL = 8.78 x 10⁻⁸ m
The change in width (Δb) can be calculated using the formula for lateral strain:
Δb = -v x ΔL = -0.3 x ΔL
Δb = -0.3 x 8.78 x 10⁻⁸ m
Δb = -2.63 x 10⁻⁸ m
The change in volume can be calculated as follows:
ΔV = (35 × 10⁻³ m) x (35 × 10⁻³ m) x (ΔL + Δb)
ΔV = (35 × 10⁻³ m) x (35 × 10⁻³ m) x (ΔL - 0.3 x ΔL)
ΔV = (35 × 10⁻³ m) x (35 × 10⁻³ m) x (8.78 x 10⁻⁸m -2.63 x 10⁻⁸ m)
ΔV = 7.53 x 10⁻¹¹ m³
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I need help please will mark brainliest
Answer:
200
Explanation:
20m/s*10sec=200
What are 3 ways a car can accelerate? (CRE)
The three ways a car can accelerate are change in velocity, change in direction, or both.
What is acceleration?The rate of velocity change concerning time is known as acceleration. The acceleration of the object is;
\(\rm a = \frac{v-u}{t}\)
Here,
a is the acceleration
v is the final velocity
u is the initial velocity
t is the period
The three ways a car can accelerate are as follows;
a)Change in velocity.
b)Change in direction
c)Change in both velocity and direction.
Hence, the three ways a car can accelerate are change in velocity, change in direction, or both.
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Suppose the elevator starts from rest and maintains a constant upward acceleration of 2.90 m/s2 . A bolt in the elevator ceiling 3.00 m above the elevator floor works loose and falls. It falls out the instant the elevator begins to move. a.)How long does it take for the bolt to reach the floor of the elevator? b.)Just as it reaches the floor, how fast is the bolt moving according to an observer in the elevator? c.)Just as it reaches the floor, how fast is the bolt moving according to an observer standing on the floor landings of the building? d.)According to an observer in the elevator, how far has the bolt traveled between the ceiling and floor of the elevator? e.)According to an observer standing on the floor landings of the building, how far has the bolt traveled between the ceiling and floor of the elevator?
The correct answer is 2.26 m.
Initial velocity of elevator u =0
Constant upward acceleration of the elevator a= 2.90 m/s²
Height of the bolt from the floor of the elevator h=3.00 m
Initial velocity of the bolt in the elevator u = 0 m/s
Elevator is moves upward with a constant acceleration 2.90 m/s²
so the net acceleration a' = (a+g) m/s²
=( 2.90 + 9.8) m/s²
a' = 12.7 m/s²
Initial velocity of the bolt u = 0 m/s
Distance traveled by the bolt h = 3.00 m
Substitute these values in the equation
h=ut+ 1/2 ( a )t², we get
3.00 = (0)x+1/2 (12.7)(t^2)
3.00 = 6.35 t²
t²= 3.00/6.35
t = 0.68 s
i.e., after 0.68 s the bolt reaches the floor of the elevator.
(b)For the observer in the elevator acceleration
a'=(a+g) m/s²
=( 2.90 + 9.8) m/s²
a'= 12.7 m/s²
Time taken bolt to reach the floor of the elevator t = 0.68 s From the equation v=u+a't we get
v=(0)+(12.7) (0.68)
v = 8.636 m/s
Velocity of the bolt when it reaches the floor of the elevator according to an observer into elevator 8.636 m/s
ii) An observer standing on the floor landings of the buildings: for observer standing on the floor landing, the acceleration of the
bolt
appears a = g m/s²
= 9.8m/s²
Time taken the bolt to reach the floor t = 0.68 s
Initial velocity of the bolt u = 0 m/s
Substitute these values in the equation
v=u+at we get
v=0+(9.8) (0.68 s)
v= 8.636 m/s
Velocity of the bolt when it reaches the floor of the elevator according to
an observer standing on the floor landing = 8.636 m/s
c) i) According to an observer in the elevator in this situation acceleration a= 12.7 m/s²
time t= 0.68 s initial velocity u = 0
substitute these values in the equation 1
s = ut +1/2 at²
We get
s =(0) (0.659)+1/2(12.7 ) (0.68)²
= 2.93 m
Distance traveled by the bolt according to the observer on the elevator 2.93 m
iii)According to an observer standing on the floor landing in this situation
acceleration a=g m/s²
= 9.8m/s²
Time t= 0.68 s
Initial velocity u = 0 m/s Substitute these values in the equation
1 ut + 1/2 at ²,
s=ut+1/2at²
we get
s=(0)+1/2(9.8) (0.68)²
= 2.26 m
Distance traveled by the bolt according to the observer standing on the floor landing 2.26 m.
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If a runner is running at 100 meters per minute at the exact moment they cross the finish line of a race, it is the
instantaneous speed.
O True
O False
Answer:
Hello! Your answer would be, O False
Explanation:
Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby
Answer:
False is the correct answer.
Explanation:
plz mark me as brainliest.
How does something(the big bang) come from nothing by nothing i mean the first universe although we don't know where the first universe is but we do know that nothing can't come from something.
The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.
It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.
Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.
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A T-shirt cannon launches a shirt at 5.30 m/s from a platform height of 4.00 m from ground level. How fast (in m/s) will the shirt be traveling if it is caught by someone whose hands are at 5.20 m from ground level (b) 4.00 m from ground level?
Answer:
(a) the velocity of the shirt is 2.14 m/s
(b) the velocity of the shirt is 5.3 m/s
Explanation:
Given;
initial velocity of the shirt, u = 5.3 m/s
height of the platform above the ground, h = 4.00 m
(a) When the shirt is caught by someone whose hand is 5.20 m from the ground level, the height traveled by the shirt = 5.2 m - 4.0 m = 1.2 m
The velocity at this position is calculated as;
\(v^2 = u^2 + 2(-g)h\\\\v^2 = u^2 - 2gh\\\\v^2 = 5.3^2 - (2\times 9.8 \times 1.2)\\\\v^2 = 4.57\\\\v= \sqrt{4.57} \\\\v = 2.14 \ m/s\)
(b) When the shirt is caught by someone whose hand is 4.00 m from the ground level, the height traveled by the shirt = 4.00 m - 4.00 m = 0 m
The velocity at this position is calculated as;
\(v^2 = u^2 + 2(-g)h\\\\v^2 = u^2 - 2gh\\\\v^2 = 5.3^2 - (2\times 9.8 \times 0)\\\\v^2 = 28.09\\\\v= \sqrt{28.09} \\\\v = 5.3 \ m/s\)
How do meteorites differ from meteors and meteoroids?
Answer:
When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors. When a meteoroid survives a trip through the atmosphere and hits the ground, it's called a meteorite.
Explanation:
Answer: Meteoroid: Small particle from a comet or asteroid orbiting the Sun. Meteor: The light phenomena which results from a meteoroid entering the Earth's atmosphere and vaporizing; this is basically a shooting star. Meteorite: A meteoroid that survives through the Earth's atmosphere and lands on the Earth's surface.
The diameter of the head of a screw nail is 4 cm and its pitch 0.5
cm. If the nail can magnify the applied effort 20 times, calculate
its MA, VR and efficiency.
The MA, VR and efficiency of the screw nail will be 20, 176 and 11.36%, respectively.
What is MA, VR and efficiency?
Mechanical advantage (MR) is the ratio between the load and effort.
Velocity ratio (VR) of a simple machine is the ratio of distance travelled by effort to the distance travelled by the load in the machine.
The efficiency of a simple machine can be defined as the ratio of useful work done by the machine (output work) to the total work put into the machine (input work).
We need to make 14 cm of diameter of the screw. Then, we can solve the problem.
Suppose the effort applied on screw is (E) = x
Then, The force is (F) = 20x
MA = F/E
MA = 20x/x (x and x are cancelled)
MA = 20
Then,
VR = 2πR/ p
VR = 2×22×0.14/7×0.05
VR = 176
and
efficiency = MA/VR × 100
efficiency = 20/176 × 100 = 11.36
Therefore, the efficiency is 11.36.
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What is the biggest agent of erosion?
a tornadoes
b pollution
c gravity
d water
Answer:
D - Water
Explanation:
Material aluminium density km-3 2-7x10² Relative density
The relative density of aluminum is 2.7. This means that aluminum is 2.7 times denser than water, which is the reference substance often used for comparing densities
The relative density (also known as specific gravity) of a material is the ratio of its density to the density of a reference substance. In this case, we are given the density of aluminum as 2.7 x 10^3 kg/m^3.
To find the relative density, we need to compare it to the density of the reference substance. The most commonly used reference substance for relative density is water, which has a density of 1000 kg/m^3.
Relative density = Density of the material / Density of the reference substance.Relative density = (2.7 x 10^3 kg/m^3) / (1000 kg/m^3)
Relative density = 2.7
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A 148 g ball is dropped from a tree 11.0 m above the ground. With what speed would it hit the ground
Answer:
14.68m/s
Explanation:
As per the question, the data provided is as follows
Mass = M = 0.148 kg
Height = h = 11 m
Initial velocity = U = 0 m/s
Final velocity = V
Gravitational force = F
Mass = M
Based on the above information, the speed that hit to the ground is
As we know that
Work to be done = Change in kinetic energy
\(F ( S) = (\frac{1}{2} ) M ( V^2 - U^2 )\)
\(M g h = (\frac{1}{2} ) M ( V^2 - U^2 )\)
\(g h = (\frac{1}{2} ) ( V^2 - U^2 )\)
\(V^2 - U^2 = 2gh\)
\(V^2 - 0 = 2gh\)
\(V = \sqrt{2 g h}\)
\(= \sqrt{2\times9.8\times11}\)
= 14.68m/s
A particle with mass
m = 3.80 kg
accelerates according to
a = (−3.40i + 1.70j) m/s2.
(a) What is the net force acting on the particle? (Express your answer in vector form.)
(b) What is the magnitude of this force?
The net force acting on the particle would be and the magnitude of the force would be -12.92i + 6.49j and the magnitude of the force would be 14.46 Newtons.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The net force on the particle = mass of the particle × acceleration
=3.80*(−3.40i + 1.70j)
= -12.92i + 6.49j
Thus, the magnitude of the net force on the particle would be 14.46 Newtons.
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find the acceleration of the elevator (magnitude and direction).express your answer with the appropriate units. enter positive value if the direction of the acceleration is upward and negative value if the direction of the acceleration is downward.
The acceleration of the elevator is -2.2 m/s2 downwards.
What is Acceleration?Acceleration is a vector quantity that describes the rate of change of an object's velocity over a period of time. It is measured in metres per second squared (m/s2). Acceleration is not the same as speed, which is the rate at which an object moves in a particular direction. Acceleration can be either positive (speeding up) or negative (slowing down) and is caused by an applied force, such as friction or gravity. The acceleration of an object changes with time and is dependent on the object's mass, drag, and the force that is applied to it.
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When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the hole. Does this observation support the theory of light as a wave, or light being made of particles? Explain.
Answer:
support lights as a wave
Explanation:
In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.
The speed of light is 3×10^8 meters per second, which means that light can travel 300 million meters in just one second. How far can light travel in one minute?
Answer:
(1.8 × 10^9) meters in one minute
Explanation:
To determine how far light can travel in one minute, we need to multiply its speed by the number of seconds in a minute.
The speed of light is 3 × 10^8 meters per second.
There are 60 seconds in a minute.
Therefore, the distance light can travel in one minute is:
Distance = Speed × Time
Distance = (3 × 10^8 meters per second) × (60 seconds)
Calculating this, we get:
Distance = 3 × 10^8 meters/second × 60 seconds
Distance = 18 × 10^8 meters
Distance = 1.8 × 10^9 meters
So, light can travel approximately 1.8 billion (1.8 × 10^9) meters in one minute.
laws of vector addition
Answer:
laws ig .
Explanation:
Imagin you have mixed together some sand and salt Based on the venn diagram this mixture would be placed where
Answer:
a
Explanation:
ajjkiikkkkkhglutfgkitfgghiiij
An object moving with uniform acceleration has a velocity of 10.5 cm/s in the positive x-direction when its x-coordinate is 2.72 cm. If its x-coordinate 2.30 s later is ?5.00 cm, what is its acceleration? The object has moved to a particular coordinate in the positive x-direction with a certain velocity and constant acceleration; then it reverses its direction and moves in the negative x-direction to a particular x-coordinate in time t. We are given an initial velocity vi = 10.5 cm/s in the positive x-direction when the initial position is xi = 2.72 cm (t = 0). We are given that at t = 2.30 s, the final position is xf = ?5.00 cm. The acceleration is uniform so that we have the following equation in terms of the constant acceleration a. Xf-Xi=Vit-1/2at^2 Now we substitute the given values into this equation. (___cm)-(___cm)=(___cm/s)(__s)+1/2a(___s)
Answer:
Acceleration = 8.27 cm/s²
Explanation:
We are given;
initial velocity; v_i = 10.5 cm/s
Initial position; x_i = 2.72 cm
Time; t = 2.30 s
final position; x_f = 5.00 cm
To find the acceleration, we will make use of the formula;
x_f - x_i = (v_i * t) - (½at²)
Plugging in the relevant values, we have;
5 - 2.72 = (10.5 × 2.3) - (½ × a × 2.3²)
2.28 = 24.15 - 2.645a
24.15 - 2.28 = 2.645a
2.645a = 21.87
a = 21.87/2.645
a = 8.27 cm/s²
A ball is launched as a projectile with initial speed v at an angle θ above the horizontal. using conservation of energy, find the maximum height hmax of the ball's flight. express your answer in terms of v, g, and θθ.
Answer:
Explanation:
I will us θ as the angle above horizontal as I don't know how to make your chosen symbol for angle.
KEy = PE
½m(vsinθ)² = mgh
h = (vsinθ)²/2g
4. S. crossirostris's wings were made of a delicate flap of skin. If this flap of skin
tore, the animal could not fly. Use this information to explain how
S. crassirostris might have had trouble competing with bird species living during
the Mesozoic era.
Birds underwent significant diversification and adaptation during the Mesozoic epoch, allowing them to develop into effective and adaptable flyers.
What are the birds?The wings of S. crossirostris, also referred to as the "delicate-winged pterosaur," were constructed of a delicate flap of skin called the patagium. This delicate membrane was prone to breaking, unlike the stiff feathers of birds.
In terms of flight prowess and ecological success, S. crossirostris would not have been able to compete with birds due to the restrictions imposed by its delicate wing structure.
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When an elastic object is changed from its original shape:
A:Energy is released
B:Work is done
C:It is ruined
D:It makes a twanging sound
Answer:
deformation : elastic deformation is reversed when the force is removed. inelastic deformation is not fully reversed when the force is removed – there is a permanent change in shape.
Explanation:
tysm
A charged atom is called an ion. An object Which extra positive ions is said to be a _______ object .
Answer:
jeukuruleykeg
Explanation:
jgeegjeyjeyjeyjeykegk
A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How
fast will the man / ball combination be moving after the ball is caught by the man?
Explanation:(2.5kg) (7.5) m/s +70 kg(0) =(2.5kg +70 kg (v3) 18. 75 =72.5 =v3
v3=.26m/s 2.5+70
if the body is floating in a liquid then can we say that the rise in the level of the liquid is equal to the height of the body
Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.
Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.
When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.
This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.