A bug walking on the circular rim of a flower
pot completes one lap around the planter in
8.667 s.
If the radius of the planter is 13.9 cm, how
fast was it traveling?

When sunlight strikes a solar panel, the form of energy, it transformed to is thermal energy. The correct option is A.

When the temperature is increased , the body or particle is said to be heating.

When Sun rays strikes any object, it gets heated due to the concentration of rays at one place. The heating refers to the type of energy as thermal energy.

Solar panel is specially designed for converting the Solar energy to heat energy.

So, When sunlight strikes a solar panel, the form of energy, it transformed to is thermal energy.

Thus, the correct option is A.

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When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.

How do sound waves and earthquakes compare?

The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.

In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.

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Given data:

* The height of the Eiffel tower is 320 m.

* The acceleration due to gravity is,

* The initial velocity of the egg in the vertical direction is 0 m/s.

Solution:

By the kinematics equation, the vertical motion of the egg is,

where u is the initial velocity, t is the time taken, and H is the height of the egg,

Substituting the known values

Thus, the time

Answer:

1988

Explanation:

in Louisville

Answer:

8. organelle

Explanation:

9. Epithelial tissue

am i correct?

Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.

Explanation:

Answer:

net force would be 50 N right

Explanation:

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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The speed and displacement are 6.66 m/s and 10 blocks east, respectively. The total distance traveled is larger than the displacement between those two points if an object changes direction while traveling.

Displacement: Is it a distance?

Sometimes people mistakenly believe that distance and displacement are simply two different labels for the same thing. Displacement and distance, however, are two distinct ideas. The overall distance traveled by an object during its voyage will be larger than the displacement if it changes direction.

What does displacement mean in one sentence?

The smallest (straight line) distance between a body's initial location and its final position—represented by an arrow pointing from the starting position to the final position—is referred to as a body's displacement when it moves from one position to another.

Briefing:

speed=10/1.5

         =6.66m/s

displacement=10 block toward east.

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Answer:

The acceleration of the woman is 0.44 m/s²

Explanation:

Given;

mass of the woman, m₁ = 90 kg

mass of the boy, m₂ = 60 kg

The force applied by the boy, f₂ = 40 N

The net horizontal force on the woman = 40 N

Apply Newton's second law of motion to determine the acceleration of the woman;

f = ma

a = f / m

a = 40 / 90

a = 0.44 m/s²

Therefore, the acceleration of the woman is 0.44 m/s²

Answer:

Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.

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Answer:

for question 3 the answer is A.

Explanation:

Pulse is not a part of the body but rather a measurement, same as with strength.

Answer:

When the projectile is launched straight up, there isn't a horizontal ... The initial acceleration was 9.8 m/s2 pointing up, so the acceleration at any other point should be the same.

Explanation:

Hope it helped =)

The maximum altitude that the cannonball will reach if fired straight up at a speed of 25 m/s is; 31.86 m

According to the question;

The cannonball is fired straight up at a speed of 25 m/s

Additionally, the cannonball is fired against the force of gravity.

Consequently, the motion is in the opposite direction of the acceleration due to gravity.

From the equation of motion;

At the maximum altitude, V = 0.

The maximum altitude that it will reach is;

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Answer:

wavelength  4 cm

Explanation:

Answer:

12 cm

Explanation:

Hooke's Law is

F = -kx,

In other words

Force applied to spring = spring constant * length the spring is stretched

Since the length the spring stretches (x) is *directly proportional* to the applied force (in this case, F is the force due to gravity).

When the weight of the block doubles (0.3kg->0.6kg), the stretch doubles as well (6cm -> 12 cm).

a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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Please find attached photograph for your answer. Hope it helps. The option is 3.1 m/s^2. Please do comment whether it is useful or not.

Drag is ignored in projectile predictions because projectiles usually have a relatively short time of flight.

The surface area of the object, the wind speed, as well as the relative velocity of the airplane will affect the drop of relief packages.

The drag force will cause the projectile to take a longer time to land and may cause to land far from its expected drop point.

Drag is a force that acts in opposition to the motion of an object moving through a fluid.

Drag can be thought of as friction in fluids because similar to friction, it acts in an opposite direction of the relative motion of a moving object.

For example, airplanes moving through air experience a drag; ships and boats moving through water experience drag too.

Drag also occurs in projectiles moving through the air. However, because of the relatively short time of flight, it is usually ignored in projectile motion.

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Complete question:

While studying projectile motion, we consider ideal scenarios, where the projectile travels along its trajectory only under the influence of gravity. In real-world situations, however, other forces act on the projectile.

Consider a cargo plane that is dropping relief packages to flood victims. In predicting and studying this motion, we might consider gravity, but ignore the horizontal and vertical forces associated with drag (or air friction). Discuss this simplification. Specifically address these questions:

•Why do we often ignore drag in projectile predictions?

•What conditions (of the object, its surroundings, and its launch) do you think might make drag a significant factor in the relief package drop?

•How would drag affect the projectile's motion if it really were a significant factor in the relief package drop?

Answer:

a. spring constant = 125 N/m

b. This spring is less stiff than the one in Sample Problem A.

Explanation:

P.S - The Sample Problem A is as follows :

Given - Sample Problem A - A load of 45 N attached to a spring that is

            hanging vertically stretches the spring 0.14 m. What is the spring

             constant?

            Suppose the spring in Sample Problem A is replaced with a spring  

            that stretches 36 cm from its equilibrium position.

To find - a. What is the spring constant in this case?

            b. Is this spring stiffer or less stiff than the one in Sample Problem A.

Proof -

As given,

Load = 45 N

Amplitude = 0.14 m

Let the spring constant = k

As we know that,

Load = k (Amplitude)

⇒45 = k(0.14)

⇒k = \(\frac{45}{0.14}\) = 321.43

∴ we get

Spring constant in Sample problem A = 321.43

Now,

a.)

Given, Amplitude = 36 cm = 0.36 m

Let the spring constant = k₁

⇒45 = k₁ (0.36)

⇒k₁ = \(\frac{45}{0.36}\) = 125 N/m

b.)

AS we can see that k₁  < k

⇒ This spring is less stiff than the one in Sample Problem A.

a. spring constant = 125 N/m

b. This spring is less stiff than the one in Sample Problem A.

The spring constant generally shows the stiffness of the spring and is the ratio of the force applied to the deflection of the spring.

It is given in the question that:

Sample Problem A - A load of 45 N attached to a spring that is

hanging vertically stretches the spring 0.14 m.  

Suppose the spring in Sample Problem A is replaced with a spring  

that stretches 36 cm from its equilibrium position.

a. What is the spring constant in this case?

As given,

Load F = 45 N

Amplitude  x= 0.14 m

Let the spring constant = k

As we know that spring force will be

\(F=k\times x\)

\(45=k\times 0.14\)

⇒k = 321.43N/m

∴ we get

Spring constant in Sample problem A is   \(k=321.43\ \frac{N}{m}\)

Now,

Given, Amplitude = 36 cm = 0.36 m

Let the spring constant = k₁

⇒45 = k₁ (0.36)

⇒k₁= 125 N/m

b.) Is this spring stiffer or less stiff than the one in Sample Problem A.

AS we can see that k₁  < k  new spring is less stiff than the one in Sample Problem A.

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Explanation:

According to the law of conservation of energy, energy can neither be created nor destroyed but can be changed from one form to another.

for example : electrical energy can be converted or changed into light energy, sound energy, heat energy etc. this proofs that the law can be trusted because, it has just been proven by the example above that it can be changed and into many forms

Answer:

a wheel and axle and a lever

The wheelbarrow has a wheel and the then the barrow. The wheel is an wheel and axle machine while the other part is a lever.

A simple machine is a device that is used to make work easier. It ensures that less effort is applied to overcome a large load.

The wheelbarrow has a wheel and the then the barrow. The wheel is an wheel and axle machine while the other part is a lever.

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Answer:

The parents and offspring all have phenotype ww. That leaves 100% probability of short wings and 0% long wings.

Explanation:

If long wings are a dominant trait, that means short wings are recessive. If two short winged flies are crossed, each of their phenotypes are ww. Therefore, each of their offspring also have phenotype ww, or short wings.

The projectile launch ratios allow finding the result of whether the ball enters the goal is:  

Parameters given

To find

Projectile launching is an application of kinematics where there is not acceleration on the x-axis and there is gravity acceleration on the y-axis.

In this case, to score the goal, the ball must be at maximum h = 2.5 m when it is at x = 30m, let's find the time, see attachment for a schema.

The components of the initial velocity are:

        cos 24 = \(\frac{v_o_x}{v_o}\)  

        sin 24 = \(\frac{v_{oy}}{v_o}\)

        v₀ₓ = v₀ cos 24

        \(v_{oy}\)  = v₀ sin 24

on the x axis there is no acceleration.

        x = v₀ₓ t

        t = \(\frac{x}{v_o \ cos 24y}\)

Let's  calculate

        t = \(\frac{30}{22 \ cos24}\)  

        t = 1.49 s

Now let's find out at what height for this time

       y = y₀ + \(v_{oy}\)  t - ½ g t²

In general for free -kik the ball is on the floor y = 0

      y = v₀ sin 24 t - ½ g t²

Let's calculate

     y = 22 sin 24 1.49 - ½ 9.8 1.49²

     y = 2.45 m

It indicates that the height of the goal crossbar is 2.5 m, therefore when the ball arrives it is below the height and enters scoring the goal.

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The net work done (in J) required to accelerate a 1500 kg car from 55 m/s to 65 m/s is 3127500 J

First, we shall obtain the initial kinetic energy. Details below:

KE₁ = ½mu²

= ½ × 1500 × 55²

= 41250 J

Next, we shall final kinetic energy. Details below:

KE₂ = ½mv²

= ½ × 1500 × 65²

= 3168750 J

Finally, we shall determine the net work done. Details below:

W = KE₂ - KE₁

= 3168750 - 41250

= 3127500 J

Thus, the net work done is 3127500 J

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Answer:

become fully human is to let down the barriers, to open up. And to discover that every person is beautiful. Under all the jobs they're doing, their responsibilities, there is you.

Explanation:

So to be fully human is the development of the heart and the head, and then we can become one.

Answer:

(a) To calculate the energy in electron volts of an electron with a de Broglie wavelength of 400 nm, we can use the de Broglie wavelength equation:

λ = h / p

where λ is the de Broglie wavelength, h is Planck's constant (6.626 x 10^-34 J s), and p is the momentum of the particle. We can rearrange this equation to solve for the momentum:

p = h / λ

Plugging in the given de Broglie wavelength, we get:

p = (6.626 x 10^-34 J s) / (400 x 10^-9 m)

= 1.6565 x 10^-24 kg m/s

To calculate the kinetic energy of the electron, we can use the formula:

KE = p^2 / (2m)

where m is the mass of the electron (9.109 x 10^-31 kg). Plugging in the momentum we just calculated, we get:

KE = (1.6565 x 10^-24 kg m/s)^2 / (2 x 9.109 x 10^-31 kg)

= 1.423 x 10^-17 J

Finally, we can convert this energy from joules to electron volts (eV) using the conversion factor 1 eV = 1.602 x 10^-19 J:

KE = 1.423 x 10^-17 J / (1.602 x 10^-19 J/eV)

= 88.8 eV

Therefore, the energy in electron volts of an electron with a de Broglie wavelength of 400 nm is 88.8 eV.

(b) To calculate the energy in electron volts of a photon with a wavelength of 400 nm, we can use the formula:

E = hc / λ

where E is the energy of the photon, h is Planck's constant, c is the speed of light (299,792,458 m/s), and λ is the wavelength of the photon. Plugging in the given wavelength, we get:

E = (6.626 x 10^-34 J s) x (299,792,458 m/s) / (400 x 10^-9 m)

= 4.965 x 10^-19 J

Finally, we can convert this energy from joules to electron volts using the conversion factor 1 eV = 1.602 x 10^-19 J:

E = 4.965 x 10^-19 J / (1.602 x 10^-19 J/eV)

= 3.10 eV

Therefore, the energy in electron volts of a photon with a wavelength of 400 nm is 3.10 eV.

Explanation:

The correct answers to the blanks are 1. UP ,2. UP and 3. ZERO

When the cart is initially given a push up the ramp, the direction of the acceleration of the cart is up the ramp. This is because the net force acting on the cart is directed up the ramp, in the same direction as the component of the gravitational force that is parallel to the ramp. As a result, the cart accelerates up the ramp in the same direction as the net force.

When the cart turns around and begins moving down the ramp, the direction of the acceleration of the cart is still up the ramp. This is because the component of the gravitational force that is parallel to the ramp is still directed down the ramp, but the net force acting on the cart is directed up the ramp due to the normal force exerted by the ramp on the cart. As a result, the cart accelerates down the ramp in the opposite direction to the net force, which is up the ramp.

            At the highest point that the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is zero. This is because at this point, the cart is at the highest point on the ramp and has stopped moving. As a result, the velocity of the cart is zero, and therefore the acceleration of the cart is also zero.

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