A bowling ball is dropped on a moon from the height of 14 m. The acceleration of gravity on the moon is 4 m/s2. Determine the time it took for the ball to crash at the surface. Round your answer to the nearest whole number.

b. 1 s
c. 4 s
d. 3 s​

The frequency of the sixth overtone would be 576 Hz.

To determine the length of a tube closed at one end, we can use the formula:

L = (v/4f) * (2n - 1)

where L is the length of the tube, v is the speed of sound in air, f is the fundamental frequency, and n is the harmonic number.

Given that the fundamental frequency is 96 Hz, we can substitute the values into the formula:

L = (v/4f) * (2n - 1)

L = (v/4*96) * (2*1 - 1)

L = v/384

To find the length at 0ºC, we need to know the speed of sound at that temperature. The speed of sound in air depends on temperature and other factors. At 0ºC, the speed of sound in dry air is approximately 331.4 m/s.

L = 331.4/384

L ≈ 0.862 m

Therefore, the tube closed at one end should have a length of approximately 0.862 meters when the air temperature is 0ºC.

To find the frequency of the sixth overtone, we multiply the fundamental frequency by six: Frequency of sixth overtone = 96 Hz * 6 = 576 Hz.

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This is because Gravity exists everywhere in the universe.

This is the force of attraction which acts on all matters in the universe. Astronauts appear weightless while in orbiting the Earth because the space shuttle and the astronauts are in free fall around it.

They fall at the same rate as the space shuttle which is why the astronauts appear weightless.

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Astronauts and their spaceship are affected by Earth's gravity in space. Even though Earth's gravitational influence is weaker in orbit than on Earth's surface, they have weight. They don't feel their weight since nothing's pushing back.

Weightlessness means no weight. It's also called zero-G. Weight is the force on a stationary object in a strong gravitational field.

The sensation of weightlessness that astronauts on board the International Space Station enjoy is due to the fact that they are free falling toward the planet Earth. Because the space station and the astronauts are moving at the same rate, there is no external normal force acting upon the body in free fall to balance out the effects of the body's own weight (equal to g).

Therefore, the astronauts and their spaceship continue to have mass and are still affected by the gravitational pull of the Earth.

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Answer:

Explanation:

A(g) + B₂(g) → AB₂(g) is the balanced equations that describes the reaction. Therefore, the correct option is option 3.

An equation for just a chemical reaction is said to be balanced if both the reactants as well as the products have the same number of atoms and total charge for each component of the reaction. In other words, either sides of the reaction have an equal balance of mass and charge.

The piston-cylinder below is depicted before and after a gaseous reaction that is carried out in it at constant pressure: the temperature is 150 K before and 300 K after the reaction. A(g) + B₂(g) → AB₂(g) is the balanced equations that describes the reaction.

Therefore, the correct option is option 3.

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Your question is incomplete but most probably your full question was,  

The piston-cylinder below is depicted before and after a gaseous reaction that is carried out in it at constant pressure: the temperature is 150 K before and 300 K after the reaction.

Which of the following balanced equations describes the reaction?

(1) A₂(g) + B₂(g) → 2AB(g)

(2) 2AB(g) + B₂(g) → 2AB₂(g)

(3) A(g) + B₂(g) → AB₂(g)

(4) 2AB₂(g) → A₂(g) + 2B₂(g)

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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Answer:

7.5 m/s².

Explanation:

From the question given above, the following data were:

Mass (m) of object = 0.6 Kg

Force of friction (Fբ) = 1.5 N

Acceleration (a) =?

Next, we shall determine the force of gravity on the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Acceleration due to gravity (g) = 10 m/s²

Force of gravity (F₉) =?

F₉ = mg

F₉ = 0.6 × 10

F₉ = 6 N

Next, we shall determine the net force acting on the object. This can be obtained as follow:

Force of friction (Fբ) = 1.5 N

Force of gravity (F₉) = 6 N

Net force (Fₙ) =?

Fₙ = F₉ – Fբ

Fₙ = 6 – 1.5

Fₙ = 4.5 N

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass (m) of object = 0.6 Kg

Net force (Fₙ) = 4.5 N

Acceleration (a) of object =?

Fₙ = ma

4.5 = 0.6 × a

Divide both side by 0.6

a = 4.5 / 0.6

a = 7.5 m/s²

Therefore, the acceleration of the object is 7.5 m/s²

Answer:

0.09kg of air

Explanation:

The dimensions of the room are given

change the height to meters by dividing it by thousand.

For the volume multiplying the length,width and height (all should be in the same unit most suitable being meters).

Volume refers to the amount of space inside a box or a object.

The amount of air is equal to the volume.

Answer:

90 m^3

Explanation:

Volume of the room:

    6 m * 5 m * 3 m         =  90 m^3   <=====( I changed 3mm to 3 m)

if  3mm is not a typo mistake

 volume becomes     ( 3 mm = .003 m)

      6 m * 5 m * .003 m   = .09 m^3   ( though unlikely )

Answer:

6s

Explanation:

Assume it is dropped from rest and the gravitational acceleration is 10

By the equation of motion under constant acceleration:

\(s=ut+\frac{1}{2} at^2\)

180 = (0)t+10(t^2)/2

t = 6 or -6 (rejected)

t = 6 s

Answer:

The darts hit the same general area of the board.

Answer: C. The darts hit the same general area of the board.

Explanation: The results of a dart game were precise but not accurate. The accepted value of the game was the center of the dartboard.

Answer:

The switching rate between the steady state and the normal state of a capacitor

Explanation:

This was a hard one! Could only find it in my textbook. Anyways this basically is the rate which the capacitors switches back from steady state and normal state from when it charges and discharges over time. This has many purposes as a special type of diode or any other transistor type device etc etc.

(a) The distance travelled by the hiker is 7.16 km

(b) If the hiker desires to return to his starting point, he should move at 201.71° with respect to east.

Form a right angled triangle with the distance between initial and final points as hypotenuse. The adjacent side will be the total distance travelled on x-direction and the opposite side will be the total distance travelled in y-direction.

Adjacent side = \(x_{2}\) - \(x_{1}\) = 3.05 - ( - 3.6 )

Adjacent side = 6.65 km

Opposite side = \(y_{2}\) - \(y_{1}\) = 5.9 - 3.25

Opposite side = 2.65 km

According to Pythagoras theorem,

\(Hypotenuse^{2}\) = \(Opposite side^{2}\) + \(Adjacent side^{2}\)

\(Hypotenuse^{2}\) = \(2.65^{2}\) + \(6.65^{2}\)

Hypotenuse = √ ( 7.02 + 44.22 )

Hypotenuse = 7.16 km

sin θ = Opposite side / Hypotenuse

sin θ = 2.65 / 7.16

θ = \(sin^{-1}\) ( 0.37 )

θ = 21.71°

This is the angle in which the hiker travelled from initial to final direction. The angle in which the hiker should travel to return to initial point with respect to east is

θ = 21.71° + 180°

θ = 201.71°

Therefore,

(a) The distance travelled by the hiker is 7.16 km

(b) If the hiker desires to return to his starting point, he should move at 201.71° with respect to east.

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A golfer is attempting to reach the elevated green by hitting his ball under a low-hanging branch in one tree A, but over the top of a second tree B. If the launch speed of the golf ball is vo = 115 mi/hr, what launch angle 0 will put the first impact point of the ball closest to the pin. The first impact point of the ball closest to the pin will be approximately 407.5 ft from the launch point.

The equation for the range of a projectile is R = (V0² / g) * sin(2θ)The golfer has to hit the ball under a low-hanging branch in tree A and over the top of tree B to reach the elevated green.

Let's denote the distance between the golfer and the green as d. The range (R) of the projectile will equal the distance to the pin (d) if the ball lands at the same level as it was launched. If the ball has to land at a higher elevation than the launch point, the launch angle must be greater than the optimal angle that maximizes range.

Assuming the golfer is hitting from a horizontal surface (i.e. the ball is launched from the same level as the pin), the launch angle that will give the first impact point of the ball closest to the pin is 60°.At the launch angle of 60°, the distance to the pin (d) will be the range of the projectile (R).The velocity of the golf ball at launch is vo = 115 mi/hr.

The horizontal distance to the pin, which is the range of the projectile, is given by the equation;

R = (V0² / g) * sin(2θ)

where g = acceleration due to gravity = 32.2 ft/s² (let's convert the velocity to ft/s first)

vo = 115 mi/hr = 115 x 5280 ft/hr = 607200 ft/hr ≈ 168666.7 ft/hr

The initial velocity of the projectile, V0 = 168666.7 ft/hr. The optimal angle of launch is given by the equation:θ = 45° (for maximum range)The angle of launch required to achieve the shortest distance to the pin is 60°Let's substitute the values of V0 and θ into the range equation.

To calculate the range of the projectile R = (V0² / g) * sin(2θ)R = (168666.7² / 32.2) * sin(2(60))R ≈ 407.5 ft

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Answer: B. -10 m/s

Explanation:

Answer:The formula distance = (initial velocity * time) + (1/2 * acceleration * time^2) would help. Take the initial velocity as 0 m/s , time as 60 seconds ( convert minutes to SI units) and the acceleration as 1m/s^2. You should get 1.8 km.

Explanation:hope this helps

The vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².

The given parameters;

acceleration due to gravity on moon, g = 1.6 m/s²

The true weight of the rocket is calculated from Newton's second law of motion;

F = ma

Apparent weight on moon = true weight on Earth

mg + ma =  mG

where;

G is the acceleration due to gravity on Earth

m(a + g) = mG

a + g = G

a = G - g

a = 9.8 - 1.6

a = 8.2 m/s²

Thus, the vertical acceleration the rocket should have so that his apparent weight is equal to his true weight on earth is 8.2 m/s².

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The new force is obtained as 228 N since the product of the masses is directly proportional to the force.

From the Newton law of universal gravitation, we can see that the gravitational force that exists between two masses is directly proportional to the product of the masses and inversely proportional to the distance between the masses.

Where the distance between the masses, remain the same, we can see that the new force would be three times the initial force since the the force and the mass are directly proportional.

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Answer:

I think the answer is 0.2 m/s2

Explanation:

Answer:

9.8m/s

Explanation:

Answer: The speed 1934

Answer:

a) Average speed = 200 Km/hr

b) Average velocity = 0 m/s

c) Total distance = 800 Km

d) Total displacement = 0 Km

Explanation:

a) Let the speed of the plane from Addis Ababa to Gamble be represented by \(S_{1}\), and from Gamble to Addis Ababa by \(S_{2}\).

Average speed = \(\frac{S_{1} + S_{2} }{2}\)

\(S_{1}\) = \(\frac{distance}{time}\) = \(\frac{400}{2}\)

        = 200 Km/hr

\(S_{2}\) = \(\frac{distance}{time}\) = \(\frac{200}{1}\)

       = 200 Km/hr

Average speed = \(\frac{200 + 200}{2}\)

        = 200 Km/hr

b) Velocity = \(\frac{displacement}{time}\)

Average velocity = \(\frac{total displacement}{total time taken}\)

Since the plane flies from Addis Ababa to Gamble, then back to Addis Ababa, its total displacement is zero.

So that,

Average velocity = 0 m/s

c) Total distance = 400 Km + 400 Km

                           = 800 Km

d) Total displacement = 400 Km + (-400 Km)

                           = 0 Km

Answer:

I got this question on Ap3x. The answer is Car C...I got it correct

Explanation:

This is because Car C is at the lowest point with the lowest amount of potential energy. Potential energy is stored at it's highest when it has the "potential" to fall, move, or etc. Car C seems to have gone farther down from the high point of the slope, meaning that most of the potential energy transformed into kinetic energy. All in all, Car C has the least potential energy. (Please give Brainliest, or not...your choice but this is the first question that I answered)

The charge on the 6 μF capacitor is 10.29 μC.

What is the charge of capacitor?

The charge of a capacitor is the amount of electric charge stored on its plates due to the potential difference (voltage) between them. The charge is directly proportional to the capacitance and the voltage across the capacitor, according to the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage.

First, we can calculate the equivalent capacitance of the two capacitors connected in parallel:

\(C_{parallel}\)= C1 + C2 = 6 μF + 8 μF = 14 μF

Next, we can calculate the total equivalent capacitance of the circuit, which is the capacitance of the parallel combination in series with the 14 μF capacitor:

1/\(C_{total}\) = 1/ \(C_{parallel}\) + 1/C3

1/\(C_{total}\) = 1/14 μF + 1/14 μF

1/\(C_{total}\) = 1/7 μF

\(C_{total}\) = 7 μF

Using the formula Q = CV, we can calculate the charge on the 6 μF capacitor:

Q = C × V = 6 μF × 12 V / 7 μF = 10.29 μC

Therefore, the charge on the 6 μF capacitor is 10.29 μC.

What is capacitance?

Capacitance is the ability of a capacitor to store electric charge when a voltage is applied across its terminals. It is defined as the ratio of the electric charge stored in the capacitor to the voltage applied to it, and its unit is the farad (F). A capacitor with a high capacitance value can store more charge for a given voltage than a capacitor with a lower capacitance value.

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According to the Keynesian view, manipulating foreign sector spending is not a reliable way to move the U.S. economy toward a more acceptable equilibrium because it does not address the fundamental causes of economic instability.

Keynesian economics focuses on the role of domestic demand in driving economic growth and stability. The government can use fiscal and monetary policy to stimulate aggregate demand and promote full employment. However, changes in foreign sector spending can be unpredictable and beyond the control of domestic policymakers. For instance, an increase in foreign demand for U.S. exports could boost economic growth and employment in the short run, but it may not be sustainable if the foreign demand later decreases. Similarly, a decrease in foreign demand for U.S. exports could have negative short-term effects on the economy, but it may not necessarily lead to a long-term decline. In short, Keynesian economics emphasizes the importance of domestic demand management and stabilizing the economy through government intervention. While changes in foreign sector spending can have some impact on the economy, they are generally seen as unreliable and unpredictable, and therefore not a reliable tool for achieving economic stability in the long run.

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Answer:

The change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

The given parameters;

Current flowing in the wire, I = 4.00 mA

Initial diameter of the wire, d₁ = 4 mm = 0.004 m

Final diameter of the wire, d₂ = 1 mm = 0.001 m

Length of wire, L = 2.00 m

Density of electron in the copper, n = 8.5 x 10²⁸ /m³

The initial area of the copper wire;

The final area of the copper wire;

The initial drift velocity of the electrons is calculated as;

The final drift velocity of the electrons is calculated as;

The change in the mean drift velocity is calculated as;

The time of motion of electrons for the initial wire diameter is calculated as;

The time of motion of electrons for the final wire diameter is calculated as;

The average acceleration of the electrons is calculated as;

Thus, the change in mean drift velocity for electrons as they pass from one end of the wire to the other is 3.506 x 10⁻⁷ m/s and average acceleration of the electrons is 4.38 x 10⁻¹⁵ m/s².

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Explanation:

The changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².

As the electrons traverse one end of the wire to another, their mean drift velocity undergoes a shift of 3.506 x 10⁻⁷ m/s with an average acceleration of 4.38 x 10⁻¹⁵ m/s² in accordance with the following parameters:

- The current flowing through the wire is at 4.00 mA.

- The original diameter of the wire, d₁, measures at 4 mm or 0.004 m.

- Conversely, the final diameter, d₂, displays a measurement of 1 mm or 0.001 m.

- The length of the entire wire is consistent, measuring at 2 meters.

- Notably, the density of electrons present within copper reaches an estimated value of 8.5 x 10²⁸ /m³.

Calculations regarding both initial and final area coverage provided by copper must be explored along with numerical data involving the two varying drift velocities for accurate results.

Thus, we arrive at the change rate of the mean drift velocity between points in the wire as well as the plenitude of electron acceleration achieved after contemplation into the corresponding motion periods.

The conclusion reflects that our measurements find the changing mean drift velocity of the electrons plays out at 3.506 x 10⁻⁷ m/s along with an average acceleration nearing 4.38 x 10⁻¹⁵ m/s².

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For a typical middle-aged woman, there are certain priorities for them such as job stability, kids, and so on, but one factor that is generally not a concern for the average middle-aged woman is how to train for the Olympics

Midlife, the stage of a woman's life between childhood and elder maturity, has been called a time of transition. Women between the ages of 40 and 65 have been the focus of midlife research because they often go through a number of social, psychological, and biological shifts during this time.

Hence, it can be seen that while there are genuine concerns for a middle-aged woman, the answer choice that is generally not a concern for the average middle-aged woman is to become an Olympian.

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If Janine is a typical middle-aged woman, she is likely to be concerned about all of the following things except for one. Identify the option that is generally not a concern for the average middle-aged woman ?

train for the Olympics

have kids

raise a family

The particle follows the path indicated in the figure, hitting the bottom plate. The mass of the particle and the magnitude of the charge on each plate factors determine the time the particle takes to reach the bottom plate.

What occurs when an electrically charged particle moves?

Magnetic force fields are produced by charged particles in motion. Charged particles that are accelerated create shifting electric and magnetic force fields that travel as EM waves. Polarized electromagnetic radiation (EMR) has all electric and magnetic field variations along the same plane.

A charged particle moves because of what?

Charged particles may move in spiral or elliptical patterns as a result of magnetic fields. Protons are kept on circular courses by particle accelerators using magnetic force. When cosmic rays come into contact with an astronomical object or planet's magnetic field, they will travel in spiral patterns.

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The particle follows the path indicated in the figure, hitting the bottom plate. The mass of the particle and the magnitude of the charge on each plate factors determine the time the particle takes to reach the bottom plate.

Magnetic force fields are produced by charged particles in motion. Charged particles that are accelerated create shifting electric and magnetic force fields that travel as EM waves. Polarized electromagnetic radiation (EMR) has all electric and magnetic field variations along the same plane.

Charged particles may move in spiral or elliptical patterns as a result of magnetic fields. Protons are kept on circular courses by particle accelerators using magnetic force. When cosmic rays come into contact with an astronomical object or planet's magnetic field, they will travel in spiral patterns.

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Answer: The ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.

Explanation:

Given: Refractive index of glycerine = 1.473

Refractive index of crystalline quartz = 1.544

Formula used is as follows.

\(2nt = m \lambda\)

For crystalline quartz: \(2n_{q}t_{q} = m \lambda_{q}\)

For glycerine: \(2n_{g}t_{g} = n \lambda_{g}\)

Here, m = n and \(\lambda_{q} = \lambda_{g}\)

So, the ratio of both these values can be written as follows.

\(\frac{2n_{q}t_{q}}{2n_{g}t_{g}} = \frac{m \lambda_{q}}{n \lambda_{g}} = 1\)

So, \(n_{q}t_{q} = n_{g}t_{g}\)

\(\frac{t_{q}}{t_{g}} = \frac{n_{g}}{n_{q}} = \frac{1.473}{1.544}\)

\(\frac{t_{q}}{t_{g}} = 0.954\)

Thus, we can conclude that the ratio of thicknesses of glycerine (refractive index 1.473) to crystalline quartz (refractive index 1.544) is 0.954.