Answer:
B and C
Explanation:
A student is trying to identify the composition of a pure metal block by determining its density. The student records the mass of the sample to be 20.0 g. The rectangular block is 1.00 cm x 4.00 cm * 1.40 cm. 7th attempt M See Periodic Table See Hint Calculate the density (in g/cm2). Express your answer to the correct number of significant figures. Answer: g/cm > 6th attempt
The necessary equation to determine the density of the block is "d = 25 g / 8.4 cm".
Define density?The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol, however Latin letter D may also be used. Mass divided by volume is the formula for density in mathematics: display style rho = frac mV. where m is the mass, V is the volume, and is the density.Density is the measure of an object's mass per unit volume. Kilograms per cubic meter (kg/m3) is the SI unit for density.The amount of something per unit of length, area, or volume: as. : the substance's mass per unit volume. given in grams per cubic centimeter is density.To learn more about density refer to:
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The provided metal block will have a density of 3.57 g/cm².
Why is metal density important?A material's specific gravity can be used to comprehend density in terms that are more relatable by measuring a substance's mass per volume. The ratio of a material's density to that of water is known as specific gravity. It is a relative (unitless) way to express how much something weighs.
What causes metals to be dense?Because their atoms are tightly packed together in a tiny area, metals have a high density. Metallic bonding is mostly to blame for this. Strong electrostatic attraction between metal cations and delocalized electrons is known as metallic bonding. As a result, the crystalline lattice structure is arranged in a predictable way.
Calculation:Volume of the given block = 1.00 x 4.00 x 1.40
⇒ Volume = 5.6 cm³
Density = mass/volume
⇒ Density = 20/5.6 = 3.57 g/cm²
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Please make the following calculation and round your
answer to the correct number of significant figures:
103 x 3.327
Answer:
343
Explanation:
Help for brainliest
Answer:
those things that looks like cristals
Draw the resulting molecule if the alkaline were to undergo Hydration. (Points)
When alkene molecule undergoes hydration there is formation of alcohol takes place. In this reaction pi bond is break through single bond.
What is hydration ?Addition of water molecule is called as hydration. Water is added to an alkene during an acid-catalyzed hydration reaction to create alcohol.
A sequential mechanism for the reaction begins with the protonation of the double bond. Since water is a weak acid on its own, protonating the double bond requires the presence of an acid.
Hydration is the process of adding water to alkenes on a net basis. The pi bond in the alkene is broken, the OH bond in the water is broken, and a C-H bond and a C-OH bond are formed as a consequence.
Thus, When alkene molecule undergoes hydration there is formation of alcohol takes place. In this reaction pi bond is break through single bond.
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what is 2100 ÷ 35399 pleasss help me
Answer:
0.0593237097
Explanation:
.Refer to the values in Figure 12.9 in the textbook and calculate the electronegativity difference for each of the following bonds.
1. Si−C
2. P−C
3. S−O
4. C−O
The electronegativity differences for the given bonds are 1. Si-C: 0.7, 2. P-C: 0.4, 3. S-O: 1.0, and 4. C-O: 1.0.
To calculate the electronegativity difference for each of the given bonds, we need to subtract the electronegativity of the bonded atoms. Using the values in Figure 12.9 of the textbook, the electronegativity values for the elements are as follows:
1. Si-C:
The electronegativity of Si is 1.8, and the electronegativity of C is 2.5.
Electronegativity difference = Electronegativity of C - Electronegativity of Si = 2.5 - 1.8 = 0.7.
2. P-C:
The electronegativity of P is 2.1, and the electronegativity of C is 2.5.
Electronegativity difference = Electronegativity of C - Electronegativity of P = 2.5 - 2.1 = 0.4.
3. S-O:
The electronegativity of S is 2.5, and the electronegativity of O is 3.5.
Electronegativity difference = Electronegativity of O - Electronegativity of S = 3.5 - 2.5 = 1.0.
4. C-O:
The electronegativity of C is 2.5, and the electronegativity of O is 3.5.
Electronegativity difference = Electronegativity of O - Electronegativity of C = 3.5 - 2.5 = 1.0.
Therefore, the electronegativity differences for the given bonds are:
1. Si-C: 0.7
2. P-C: 0.4
3. S-O: 1.0
4. C-O: 1.0.
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349+1.10 + 100 =
and i have to put it in sig fig?
Can a molecular formula ever be the same as an empirical formula? Give an example.
Answer:
Different compounds can have the same empirical formula. For example, ethylene C 2 H 4 and propylene C 3 H 6 have the same empirical formula, CH 2. In the same manner, compounds can have the same molecular formula. For example, ethanol and dimethyl ether have the same molecular formula, C 2 H 6.
Explanation:
A woman is found dead on a boat floating in the middle of a lake at 4:30am. There is blunt force trauma to her head but no other discernable damage. She is approximately 30 pounds overweight. She is wearing thermal clothing and a winter jacket, gloves, and hat. Climatological data indicate it was a clear, cold, and windy night with no precipitation. Calculate the time of death based only on a body temperature of 15.6°C (60.8°F)? Now consider the other factors presented. How would each affect this estimation?
Answer:
Dead bodies lose one degree Celsius per hour, which we could deduce that the person died 12 hours ago.
Explanation:
On the other hand, it is very important to take into account that this number of hours is very approximate, since not only does it vary greatly with the environment and the acclimatization of the environment in which the person dies, but also in this specific case, insulating clothing was presented , which made the loss of body heat much more difficult and could easily be more than 12 hours.
The minimum for this particular situation is 12 hours to 24 hours possible postmortem.
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Which of these is a ball and stick model?
6. When cooking an egg and waiting for coagulation, what are two things to look for? (1 point)
When cooking an egg and waiting for coagulation, two things to look for are the firmness of the egg white and the doneness of the yolk.
The egg white should become opaque and set, indicating that it has coagulated properly. The yolk can be cooked to different degrees of doneness, depending on personal preference. For a runny yolk, it should still be soft and slightly jiggly in the center. For a firmer yolk, it should be more set and less jiggly. By observing these two aspects, you can determine the coagulation stage of the egg and achieve the desired texture for your egg dish.
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A dipeptide can be broken into two amino acids by dehydration synthesis.
A dipeptide can be broken into two amino acids by hydrolysis, not by dehydration synthesis. Hydrolysis is the reverse of the dehydration synthesis process. In hydrolysis, water is used to break down a molecule into smaller subunits.
In dehydration synthesis, water is released as a byproduct when two molecules are combined to form a larger molecule. Dipeptides are molecules made up of two amino acids. They can be broken down into individual amino acids through the process of hydrolysis. In hydrolysis, a molecule of water is added to the dipeptide, breaking the bond between the two amino acids and creating two separate amino acids. The opposite process, dehydration synthesis, involves combining two amino acids to form a dipeptide.
During dehydration synthesis, a molecule of water is removed from the amino acids to form a peptide bond between them. This process is used to form larger polypeptides and proteins by combining multiple amino acids in a specific sequence to create a functional protein.
In conclusion, a dipeptide can be broken down into two amino acids through hydrolysis, not dehydration synthesis. Hydrolysis involves the addition of water to break apart a molecule, while dehydration synthesis involves the removal of water to create a larger molecule. Both processes are important for the formation and breakdown of proteins and other biological molecules.
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Calculate the energy of interaction between a lithium ion and a magnesium ion at a distance of 4.55x10^-10 m
Another student suggests putting some cotton wool in the top of the flask.
Suggest why this improves the investigation. *
(1 Point)
Answer:
B proofread the message.
Explanation: Hope this helped
Here are some last minute questions I need help with !
The balanced equations of the reaction are given below:
Overall equation: 2 H_O → H₂O₂ (l)
Equation 1: H_O ---> H_O (g)
Equation 2: H_O (g) → H₂O₂ (g)
Equation 3: H₂O₂ (g) → H₂O₂ (l)
What are balanced chemical equations?A balanced equation is an equation of a chemical reaction in which the number of moles of atoms for all the elements in the reaction is equal on both sides of the reaction.
A balanced chemical equation is obtained from the law of conservation of matter that states matter can not be created or destroyed.
Balancing chemical equations involves the addition of numerical coefficients to the reactants and products.
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How many moles of N20 gas would have a volume of 3.8 L at 460 mmHg and 77°C?
We are given:
Volume of gas = 3.8 L
Pressure = 460 mmHg
Temperature = 77°c = (77+273)K = 350K
Converting the pressure to atm:
Pressure(in atm) = Pressure(in mmHg) / 760
Pressure = 460/760 = 0.6 atm
Finding the number of moles:
using the ideal gas equation:
PV = nRT [where R is the universal gas constant]
replacing the given values in this equation
(0.6)(3.8) = n(0.082)(350)
n = (0.6*3.8)/(0.082*350)
n = 0.08 moles
Acetone and chloroform are two miscible liquids. The chloroform hydrogen is relatively acidic and will hydrogen bond with the carbonyl group of acetone. Is Raoult's law likely to hold true for solutions of acetone and chloroform? Explain your answer.
Raoult's law is not likely to hold true for solutions of acetone and chloroform due to the hydrogen bonding between the two components, which leads to non-ideal solution behavior.
- Raoult's law states that the vapor pressure of a component in an ideal solution is proportional to its mole fraction in the solution. However, in the case of acetone and chloroform, the presence of hydrogen bonding between the two liquids can affect the extent to which Raoult's law holds true.
- The hydrogen bonding between chloroform and acetone would decrease the vapor pressure of each component in the solution, as hydrogen bonding increases the attraction between the molecules and makes it harder for them to escape into the gas phase. As a result, the vapor pressure of the solution would be lower than what would be expected from Raoult's law.
- Therefore, Raoult's law is not likely to hold true for solutions of acetone and chloroform due to the presence of hydrogen bonding. Instead, the solution would exhibit non-ideal behavior and the vapor pressure would be lower than expected.
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how is it that life on earth has changed over million of years yet the Earth has not?
actually environmental science own words please need it now asap guys please help me it’s due today.
How much percent of the earth is water?
Answer:70%
Explanation:
Answer:
71%
Explanation:
71% of the earth is covered by water and oceans hold about 96 percent of the water
according to the video, why should a used chemical container never be refilled? used chemicals may be contaminated, which could cause an unexpected reaction.
Yes, that is correct. A used chemical container should never be refilled because used chemicals may be contaminated, which could cause an unexpected reaction or even a hazardous situation.
Additionally, used containers may have residue from the previous chemical that could react with the new chemical being added, leading to unexpected and potentially dangerous results. It is always recommended to use a clean and properly labeled container for each chemical to ensure safe storage and use.
A chemical container is a device used to store and transport chemicals and other hazardous materials. It is usually made of materials such as plastic, metal, or glass that are resistant to corrosion and chemical reactions with the contents. Chemical containers are designed to be leak-proof and safe to handle, and are often labeled with warnings and safety information to ensure proper use and handling.
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GIVING BRAINLIEST TO WHOEVER ANSWERS THIS!!
What is the density of rod D, in g/cm3 ? Mass is 15 grams and volume is 14 cm3.
A: 2.5 g/cm3
B: 1.4 g/cm3
C: 1.1 g/cm3
D: 0.94 g/cm3
Answer:
The answer is option CExplanation:
The density of a substance can be found by using the formula
\(density = \frac{mass}{volume} \\ \)
From the question we have
\(density = \frac{15}{14} \\ =1.0714285 ...\)
We have the final answer as
1.1 g/cm³Hope this helps you
Which element has a mass number of 32?
a. argon ion
b. silicon ion
C. silicon
d. sulfur
a restriction enzyme recognizes the sequence 5ʹ-gtcatgac-3ʹ and makes staggered cuts. which statement is most likely to be true?
The most likely true statement about a restriction enzyme recognizing the sequence 5ʹ-gtcatgac-3ʹ and making staggered cuts is: "The restriction enzyme produces fragments with sticky ends".
When a restriction enzyme recognizes a specific DNA sequence, it cuts the DNA at or near that sequence. Staggered cuts refer to cuts made at different positions on the two DNA strands, resulting in fragments with overhanging ends. These overhanging ends are often referred to as sticky ends because they can base pair with complementary sequences.
In the given sequence 5ʹ-gtcatgac-3ʹ, the restriction enzyme would recognize and cut between the G and the T bases, resulting in staggered cuts. This would produce fragments with complementary overhangs: 5ʹ-GTCATG-3ʹ and 5ʹ-GTCA-3ʹ. These overhanging ends can then bind or anneal with complementary sequences during DNA manipulation, such as in cloning or DNA ligation reactions.
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Qué sucede al disolver una tableta de ALKA-SELTZER en agua caliente?
Answer:
FREE POINTS CUZ I DON'T UNDERSTAND
Explanation:
Which of the following will not show geometrical isomerism?
a. [Cr(NH3)4Cl2]Cl
b. [Co(en)2Cl2]Cl
c. [Co(NH3)5NO2]Cl2
d. [Pt(NH3)2Cl2]
Among the given complexes, [Co(NH3)5NO2]Cl2 will not show geometrical isomerism. This is because it has an octahedral geometry with five ammine (NH3) ligands and one nitro (NO2) ligand, resulting in no possibility of cis-trans isomerism. The other complexes can exhibit geometrical isomerism due to the presence of different ligands.
The complex compounds that show geometrical isomerism have a different spatial arrangement of ligands around the central metal atom due to the presence of a chiral center. In the given options, only [Pt(NH3)2Cl2] will not show geometrical isomerism as it has only two types of ligands, and the arrangement of these ligands around the central metal atom is symmetrical. On the other hand, [Cr(NH3)4Cl2]Cl, [Co(en)2Cl2]Cl, and [Co(NH3)5NO2]Cl2 all have chiral centers and can exhibit geometrical isomerism.
Your answer: c. [Co(NH3)5NO2]Cl2
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Nowadays it is very important to reduce one's carbon "ootprint" (how much carbon we produce in our daly lifestyles). Mrimiting the use of fossal fuels and instead tosoring to renewable sourchis o ener
Nowadays, it is very important to reduce one's carbon "footprint" (how much carbon we produce in our daily lifestyles). By limiting the use of fossil fuels and instead turning to renewable sources of energy, we can significantly reduce our carbon emissions and mitigate the impacts of climate change.
One way to reduce our carbon footprint is by transitioning to renewable energy sources such as solar, wind, and hydropower. These sources of energy produce minimal greenhouse gas emissions compared to fossil fuels like coal, oil, and natural gas. Installing solar panels on rooftops, utilizing wind turbines, and supporting hydroelectric power can help generate clean and sustainable energy.
Another important aspect is adopting energy-efficient practices and technologies. This includes using energy-efficient appliances, LED lighting, and improving insulation in buildings to reduce energy consumption. Conserving energy in transportation by opting for public transportation, carpooling, biking, or walking can also make a significant difference.
Additionally, reducing waste and promoting recycling and composting can help minimize greenhouse gas emissions. Waste decomposition in landfills produces methane, a potent greenhouse gas. By reducing, reusing, and recycling materials, we can lower our carbon emissions and conserve resources.
Furthermore, making conscious choices in our daily lives can contribute to reducing our carbon footprint. This includes minimizing water usage, eating a plant-based diet or reducing meat consumption, and supporting sustainable and local products.
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in this experiment, you will be heating under reflux. what glassware equipment do you need to set up the apparatus? distillation head, fractionating column, round-bottom flask distillation head, condenser, round-bottom flask round-bottom flask, condenser, drying tube separatory funnel, erlenmeyer flask, beaker
When heating under reflux, you will need the following glassware equipment to set up the apparatus: Round bottom flask, condenser, hot plate, thermometer, adapter, clamps and stands, water supply.
When heating under reflux, you will need the following glassware equipment to set up the apparatus:
1. Round-bottom flask: This is the flask that contains the reaction mixture that needs to be heated.
2. Condenser: This is a glass tube that is attached to the round-bottom flask and has a water jacket around it. The water is circulated through the jacket to cool down the hot vapours and condense them back into liquid form.
3. Heating mantle or hot plate: This is the equipment that provides heat to the round-bottom flask.
4. Thermometer: This is an instrument used to measure the temperature of the reaction mixture.
5. Adapter: This is a glassware piece that connects the condenser to the round-bottom flask.
6. Clamps and stands: These are used to hold the glassware in place during the heating process.
7. Water supply: This is required to run water through the condenser's jacket to cool down the vapours.
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the decomposition of hydrogen peroxide is catalyzed by iodide ion what happen to catalyst concentration
The decomposition of hydrogen peroxide into water and oxygen is a slow process, but it can be catalyzed by iodide ion. The iodide ion acts as a catalyst by lowering the activation energy required for the reaction to occur.
During the reaction, the iodide ion is oxidized to form iodine, which then reacts with hydrogen peroxide to form water and oxygen. The iodine can then react with more hydrogen peroxide to continue the reaction.
The concentration of the catalyst, iodide ion, affects the rate of the reaction. An increase in the concentration of the iodide ion will increase the rate of the reaction, as there will be more catalyst available to facilitate the reaction. Conversely, a decrease in the concentration of the iodide ion will slow down the rate of the reaction.
However, once the reaction has finished, the concentration of the catalyst will remain the same. This is because the catalyst is not consumed in the reaction and can be used again in subsequent reactions. Therefore, the concentration of the catalyst will remain constant as long as there is enough iodide ion present to catalyze the reaction.
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Under a pressure of 862kPa a gas has a volume of 752c * m ^ 3 The pressure is increased, without changing the temperature, until the volume is 624c * m ^ 3 What is the new pressure?
To solve this problem, we can use the gas law equation, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature.
Since we are told that the temperature remains constant, we can simplify the equation to P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the new pressure, and V2 is the new volume.
Plugging in the given values, we get:
P1 = 862 kPa
V1 = 752 c * m^3
V2 = 624 c * m^3
Solving for P2, we get:
P2 = (P1 * V1) / V2
P2 = (862 kPa * 752 c * m^3) / 624 c * m^3
P2 = 1040 kPa
Therefore, the new pressure under a volume of 624c * m^3 is 1040 kPa.
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indicate whether each statement is true or false regarding the regulation of the glomerular filtration rate. 1. regulation is achieved through autoregulation. (click to select) 2. the renal autoregulation involves smooth muscles in the arterioles acting as stretch receptors, thus dilating or constricting the arteriole in response to changes in blood pressure. (click to select) 3. the renal autoregulation involves macula densa cells sending signals to the juxtaglomerular cells to either constrict or dilate the arteriole. (click to select) 4. the tubuloglomerular feedback mechanism involves smooth muscles in the arterioles acting as stretch receptors, thus dilating or constricting the arteriole in response to changes in blood pressure. (click to select) 5. the tubuloglomerular mechanism involves macula densa cells sending signals to the juxtaglomerular cells to either constrict or dilate the arteriole. (click to select)
True. The regulation of the glomerular filtration rate is achieved through autoregulation. True. The renal autoregulation mechanism involves smooth muscles in the arterioles acting as stretch receptors, thus dilating or constricting the arteriole in response to changes in blood pressure.
True. The renal autoregulation involves macula denser cells sending signals to the juxtaglomerular cells to either constrict or dilate the arteriole. False. The tubuloglomerular feedback mechanism involves the macula denser cells detecting changes in the NaCl concentration in the filtrate and sending signals to the afferent arteriole to either constrict or dilate. True. The tubuloglomerular mechanism involves macula denser cells sending signals to the juxtaglomerular cells to either constrict or dilate the arteriole. Overall, the regulation of the glomerular filtration rate involves both autoregulation and tubuloglomerular feedback mechanisms. Autoregulation helps maintain a relatively constant glomerular filtration rate despite changes in systemic blood pressure, while tubuloglomerular feedback helps adjust the glomerular filtration rate in response to changes in the filtrate composition.
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