what is the approximate atomic mass (in u ) of the daughter atom? ignore recoil of the daughter nucleus.

Answer:

Saturated solution = 180 gram

Explanation:

Given:

Solubility of Z = 60 g / 100 g water

Given temperature =  20°C

Amount of water = 300 grams

Find:

Saturated solution

Computation:

Saturated solution = [Solubility of Z] × Amount of water

Saturated solution = [60 g / 100 g] × 300 grams

Saturated solution = [0.6] × 300 grams

Saturated solution = 180 gram

Answer:

d: All of the above. Have a nice day!

Answer:

The answer is: All of the above

Explanation:

1. The equilibrium constant (Keq) is approximately 0.002 for the reaction A → B with a standard free energy change of -15 kJ/mol.

2. The actual free energy change (ΔG) for the reaction A → B is approximately -27,240 J/mol when [A] = 10 mM and [B] = 0.1 mM.

3. The standard free energy change (ΔGo') for the reaction A + B → C is approximately -10,117.23 J/mol.

1. The equilibrium constant (Keq) can be determined using the equation: ΔGo' = -RT ln(Keq), where ΔGo' is the standard free energy change, R is the gas constant (8.314 J/mol.K), and T is the temperature in Kelvin.

Given that ΔGo' = -15 kJ/mol, we need to convert it to Joules by multiplying by 1000:

ΔGo' = -15 kJ/mol = -15,000 J/mol.

Assuming the temperature is 310 K, we can calculate Keq as follows:

ΔGo' = -RT ln(Keq)

-15,000 J/mol = -(8.314 J/mol.K)(310 K) ln(Keq)

Simplifying the equation:

ln(Keq) = -15,000 J/mol / (8.314 J/mol.K * 310 K)

ln(Keq) ≈ -5.97

Taking the exponential of both sides:

Keq ≈ e^(-5.97)

Calculating Keq:

Keq ≈ 0.002

Therefore, the equilibrium constant (Keq) for the reaction A → B is approximately 0.002.

2. To determine the actual free energy change (ΔG) for the reaction A → B, we can use the equation: ΔG = ΔGo' + RT ln(Keq), where ΔG is the overall free energy change, R is the gas constant (8.314 J/mol.K), T is the temperature in Kelvin, and Keq is the equilibrium constant.

Given that [A] = 10 mM and [B] = 0.1 mM, we can calculate the actual free energy change as follows:

ΔG = -15,000 J/mol + (8.314 J/mol.K)(310 K) ln(0.1/10)

Simplifying the equation:

ΔG ≈ -15,000 J/mol + (8.314 J/mol.K)(310 K) ln(0.01)

Calculating ΔG:

ΔG ≈ -15,000 J/mol + (8.314 J/mol.K)(310 K)(-4.605)

ΔG ≈ -15,000 J/mol - 12,240 J/mol

ΔG ≈ -27,240 J/mol

Therefore, the actual free energy change (ΔG) for the reaction A → B, when [A] = 10 mM and [B] = 0.1 mM, is approximately -27,240 J/mol.

3. To calculate the standard free energy change (ΔGo') for the reaction A + B → C, we can use the equation: ΔGo' = -RT ln(Keq), where ΔGo' is the standard free energy change, R is the gas constant (8.314 J/mol.K), T is the temperature in Kelvin, and Keq is the equilibrium constant.

Given the concentrations at equilibrium: [A] = 2 mM, [B] = 3 mM, and [C] = 9 mM, we can calculate the standard free energy change as follows:

First, let's calculate the ratio of products to reactants based on their concentrations:

[A] = 2 mM, [B] = 3 mM, and [C] = 9 mM

Keq = ([C]^coefficient[C] * [A]^coefficient[A] * [B]^coefficient[B]) / ([A]^coefficient[A] * [B]^coefficient[B])

Keq = (9^1 * 2^0 * 3^0) / (2^1 * 3^1)

Keq = 9 / 6

Keq = 1.5

Now, we can calculate ΔGo' using the equation:

ΔGo' = -RT ln(Keq)

Assuming the temperature is 310 K, and using the gas constant R = 8.314 J/mol.K:

ΔGo' = -(8.314 J/mol.K)(310 K) ln(1.5)

Calculating ΔGo':

ΔGo' ≈ -(8.314 J/mol.K)(310 K)(0.405)

ΔGo' ≈ -10,117.23 J/mol

Therefore, the standard free energy change (ΔGo') for the reaction A + B → C, when the concentrations are [A] = 2 mM, [B] = 3 mM, and [C] = 9 mM, is approximately -10,117.23 J/mol.

1. The equilibrium constant (Keq) is approximately 0.002 for the reaction A → B with a standard free energy change of -15 kJ/mol.

2. The actual free energy change (ΔG) for the reaction A → B is approximately -27,240 J/mol when [A] = 10 mM and [B] = 0.1 mM.

3. The standard free energy change (ΔGo') for the reaction A + B → C is approximately -10,117.23 J/mol.

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Answer:

The element belongs to group 15 of the present periodic table

Explanation:

Isotopes have the same proton number, what differs is that they have different number of neutrons.

Now since the half-sum of their neutrons is 19, the total number of neutrons would be 19 * 2 = 38 neutrons.

Also, their masses add up to be 68, since the total mass equals sum of neutrons and sum of protons, this means that the total number of protons is 68-38 = 30

Since this is equal in both isotopes, this means that the proton number of the element is 30/2 = 15

The atomic number is the number of protons in the nucleus of an atom. Since the atomic number is 15, this element is phosphorus and it belongs to group 15 of the present periodic table

3 moles or 84.03 g of CO produces 3 moles of or 132 g of CO₂. Thus, the mass of CO required to produce 635 g of CO₂ is 404.23 g.

Carbon monoxide  is an inorganic gas produced from the covalent bonding  of carbon with oxygen. When carbon monoxide reacts with metal oxides it produces carbon dioxide.

From the given balanced reaction, 3 moles of CO produces 3 moles of CO₂.

Molar mass of CO = 28.01 g/mol, 3 moles =  (28.01 ×3) 84.03 g

molar mass of CO₂ = 44.01 g/mol , 3 moles = 132 g.

Thus, mass of CO required to produce 635 g of CO₂ is :

= (84.03 × 635 g) /132 g = 404.23 g.

Therefore, the mass of CO required to produce 635 g of CO₂ is 404.23 g.

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Answer:

b is correct method.

Explanation:

Given that,

Volume of tank = 64 liter

We need to find the conversion liter to quarts

Using conversion

\(1\ L=\dfrac{1\ l}{1.057\ quarts}\)

We need to find the conversion quarts to gallons

Using conversion

\(1\ quarts=\dfrac{1\ l}{4\ gallons}\)

We need to find correct method

Using conversion

\(64\ L=\dfrac{1\ L}{1.057}\times\dfrac{1\ gallon}{4\ quarts}\)

Hence, b is correct method.

Given :

Half-life of Iodine , \(t_{0.5}=8 \ days\) .

Initial concentration , \([A_o]=100\ mg\) .

To Find :

The amount of sample remains after 32 days .

Solution :

Rate constant is given by :

\(k=\dfrac{0.693}{t_{0.5}}\\\\k=\dfrac{0.693}{8}\ s^{-1}\\\\k=0.086625\ s^{-1}\)

Now , by rate law :

\([A]=[A_o]e^{-kt}\)

Putting all given values, we get :

\([A]=100\times e^{-(0.086625)\times 32}\\\)

\([A]=6.25\ mg\)

Therefore , the remaining sample after 32 days is 6.25 mg .

Hence , this is the required solution .

When \(NH_4NO_3\) dissolves in water, the enthalpy of the system decreases, and the entropy of the system increases. The increase in entropy is the driving force of the process, causing the solute to dissolve in the solvent. Option A is the correct answer.

When \(NH_4NO_3\) dissolves in water, it undergoes an endothermic process in which heat is absorbed from the surroundings, causing the temperature of the solution to decrease. This suggests that the dissolution process is driven by an increase in the system's entropy, rather than by a decrease in enthalpy.

The enthalpy change of the system can be determined by measuring the heat of the solution, which is the amount of heat absorbed or released when a solute dissolves in a solvent. In the case of \(NH_4NO_3\), the heat of the solution is positive, indicating an endothermic process in which heat is absorbed. This means that the enthalpy of the system decreases when \(NH_4NO_3\) dissolves in water.

The entropy change of the system can be determined by calculating the difference in the entropy of the solution and the sum of the entropies of the separate components (the solute and the solvent) before mixing. In the case of \(NH_4NO_3\) dissolving in water, the increase in the disorder of the system is driven by the release of ammonium ions and nitrate ions into the solvent. The disorder of the system increases because the ions become more dispersed and move around freely in the solution. This increase in entropy is the driving force of the process.

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Complete question:

Which of the following describes the enthalpy and entropy changes of the system when \(NH_4NO_3\) dissolves in water, and which change drives the process?

a) Enthalpy decreases and entropy increases; entropy change drives the process

b) Enthalpy increases and entropy decreases; enthalpy change drives the process

c) Enthalpy decreases and entropy decreases; enthalpy change drives the process

d) Enthalpy increases and entropy increases; entropy change drives the process

The name and chemical symbol of the given element whose electronic configurations are shown is:

a. Germanium and its symbol is Ge.

b. Niobium and its symbol is Nb.

The chemical symbol of an element is the symbol that is used to represent the atom of the element usually based on the name o the element.

The name and chemical symbol of the given element whose electronic configurations are shown is determined as follows:

a.) [Ar]4s¹3d¹⁰4p²5p¹

The atomic number of the element is 32

The element whose atomic number is 32 is Germanium and its symbol is Ge.

b.) [Kr]5s²4d²5p¹

The atomic number of the element is 41

The element whose atomic number is 32 is Niobium and its symbol is Nb.

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Answer:

60m/min

Explanation:

speed = distance/time

           =7200m/120min

           =60m/min

Answer:

60

Explanation:

because 7200 divided by 120 is 60

Answer:

It would be this below.

Explanation:

I am not 100% sure this is write but I did my best this is still kinda hard for me. I just did this a few years ago and i struggled with it but I have been doing better since then.

Hope this helps :))

The atomic numbers of elements with a filled outermost shell are 2, 10, 18, etc.

What are noble gases?

Noble gases are elements on the periodic table with filled outermost shells.

With filled outermost shells, these elements are not able to react in chemical reactions ordinarily.

These elements include Helium (2), Neon (10), Argon (18), etc.

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Answer:

k = [F2]² [PO]² / [P2] [F2O]²

Explanation:

In a chemical equilibrium, the equilibrium constant expression is written as the ratio between the molar concentration of the products over the molar concentration of the reactants. Each species powered to its reaction coefficient. For the equilibrium:

P2(g) + 2F2O(g) ⇄ 2PO(g) + 2F2(g)

The equilibrium constant, k, is:

k = [F2]² [PO]² / [P2] [F2O]²

Answer: 3.6 ml

Hope this helps!

Answer:

Its food for cannibals.

There are 1.5 moles of calcium in 0.5 mole Ca3(PO4)2.

First we need to first find the molar mass of Ca3(PO4)2:

Molar mass of Ca3(PO4)2 = (3 x molar mass of Ca) + (2 x molar mass of PO4)

= (3 x 40.08 g/mol) + (2 x (1 x 30.97 g/mol + 4 x 16.00 g/mol))

= 310.18 g/mol

Next, we can use the following mole ratio:

3 moles of Ca / 1 mole of Ca3(PO4)2

This means that for every 1 mole of Ca3(PO4)2, there are 3 moles of Ca.

Therefore, the number of moles of calcium in 0.5 mole Ca3(PO4)2 is:

0.5 mole Ca3(PO4)2 x (3 moles of Ca / 1 mole of Ca3(PO4)2) = 1.5 moles of Ca

Therefore, there are 1.5 moles of calcium in 0.5 mole Ca3(PO4)2.

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Answer:

0.028%

Explanation:

From the question given above, the following data were obtained:

Accepted value = 4.6026 g

Measured value = 4.6013 g.

Percentage error =..?

Thus, we can obtain the percentage error in the student's reading as follow:

Percentage error = |measured value – accepted value|/accepted value × 100

Percentage error = |4.6013 – 4.6026| / 4.6026 × 100

Percentage error = 0.0013 / 4.6026 × 100

Percentage error = 0.13/4.6026

Percentage error = 0.028%

Therefore, the percentage error in the student's reading is 0.028%

Answer:

7.8286e+23

Explanation:

Use Avogadro's number

Answer: (0.800g BaCl2) / (208.233g BaCl2/mol) =

0.00384 mol BaCl2

Explanation: Hope this helps :)

The number of moles of anhydrous barium chloride is equal to 3.84 ×10⁻³ mol and the number of moles of water is equal to 7.78 ×10⁻³ mol.

A mole can be described as a standard unit that is used to determine the number of atoms, molecules, ions, or other particular particles in the given mass of the substance. The mass of one mole of any chemical element is known as atomic mass and that of any chemical compound is called the molar mass of that compound.

Given the chemical reaction of decomposition of barium chloride:

\(BaCl_2.2H_2O\longrightarrow BaCl_2 +2H_2O\)

Given the mass of the hydrated barium chloride = 0.940 g

The mass of the anhydrous  barium chloride = 0.800 g

The molar mass of the anhydrous barium chloride = 208.23 g/mol

The number of moles (n) of anhydrous barium chloride = 0.800/208.23

n = 3.84 ×10⁻³ mol

The mass of the water = Mass of hydrated barium chloride - anhydrous barium chloride

Mass of water = 0.940 -0.800 = 0.14 g

The number of moles of water = 0.14/18 = 7.78 ×10⁻³ mol

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Answer:

0.071 moles of Na₃PO₄

Explanation:

Given data:

Number of moles of Na₃PO₄ = ?

Number of molecules of Na₃PO₄ = 4.3×10²² molecules

Solution:

1 mole contain 6.022×10²³ molecules

4.3×10²² molecules × 1mol / 6.022×10²³ molecules

0.71×10⁻¹ mol

0.071 mol

The number 6.022 × 10²³ is called Avogadro number.

Avogadro number:

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The given reaction involves an SN1 reaction, where the alkyl halide reacts with water to form an alcohol and hydroxyalkyl radical. SN1 reactions are known to be relatively slow and can lead to the inversion of configuration if the substrate is chiral. Therefore, the best option is (C) SN1 with inversion of configuration.  

In the given reaction, an alkyl halide reacts with water to form an alcohol and hydroxyalkyl radical. This is an example of an SN1 reaction, where the alkyl halide acts as a nucleophile and attacks the carbon atom of the alkyl group. The resulting bond between the alcohol and the hydroxyalkyl radical is a single bond.

Given the information provided, the reaction can be described as follows:The major product of this reaction is an alcohol, so it is likely an SN1 reaction. However, since the reaction involves the formation of a hydroxyalkyl radical, the reaction cannot lead to racemization. Therefore, the best option is (C) SN1 with inversion of configuration.  

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Folded mountains like the himalayan mountains form along the boundary type is the convergent, both continental crust plates.

When two continental crust plates collide, they create folded mountains. This is because continental crust is thicker and less dense than oceanic crust, so when the two plates collide, they cannot easily sink into the mantle. Instead, they push against each other and fold upwards, creating mountain ranges like the Himalayas.

In contrast, when two oceanic crust plates collide (convergent, both oceanic crust plates), one plate typically sinks under the other, creating a subduction zone. When two oceanic crust plates move away from each other (divergent, both oceanic crust plates), new oceanic crust is created at the boundary. When two continental crust plates move away from each other (divergent, both continental crust plates), a rift valley is created. Therefore, the correct answer is convergent, both continental crust plates.

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True. Volatile solvents that act as CNS depressants, such as inhalants, can be found in a wide variety of household products.

Volatile solvents are chemicals that vaporize at room temperature and can be inhaled to produce intoxicating effects. These solvents are commonly found in various household products, including cleaning agents, paint thinners, adhesives, aerosol sprays, and certain fuels. Examples of volatile solvents include toluene, xylene, benzene, and trichloroethylene.

When these volatile solvents are inhaled, they enter the bloodstream through the lungs and quickly reach the central nervous system (CNS). In the CNS, they act as depressants, slowing down the activity of the brain and nerve cells. The effects can include dizziness, disorientation, euphoria, hallucinations, and in severe cases, loss of consciousness or even death.

It is important to note that inhalant abuse, particularly among adolescents and young adults, poses serious health risks and can lead to addiction, organ damage, cognitive impairment, and other long-term consequences. Proper usage and storage of household products containing volatile solvents are crucial to prevent unintended inhalation and protect individuals from the harmful effects associated with their misuse.

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The solubility product of Calcium Carbonate is 15mg/l hence is insoluble in water and the water is under-saturated with respect to calcium.

Calcium Carbonate is only slightly soluble in water. The solubility product is 4.4 × 10⁻⁹, indicating that if equal concentrations of calcium and carbonate are formed only 6.8mg/l of calcium carbonate would be soluble. Thus determined by the data, the water saturation with respect to calcium is under-saturated.

Langelier Saturation Index Complex (LSI) is the indicator of the degree of saturation of calcium carbonate in water.  The under-saturated water effect is the result of the Langelier Saturation Index Complex(LSI) that is negative, hence states that there will be corrosion of pipings.

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The molecule you have provided is not included in your question, so I cannot provide a direct answer.

However, in general, for a molecule to form hydrogen bonds with water, it must have hydrogen atoms that are covalently bonded to highly electronegative atoms such as oxygen, nitrogen, or fluorine. These hydrogen atoms then form hydrogen bonds with the lone pairs of electrons on the water molecules.

Therefore, the number of atoms in a molecule that can form hydrogen bonds with water depends on the presence of such covalently bonded hydrogen atoms and their accessibility to water molecules.

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Answer:

The answer is "It leads to the formation of underground caves"

Explanation:

Texas Hill Land is popular for its rolling hills, good wine, and authentic food. Its Texas Hill Property appeal is no mystery, recognized as being one of the top vacation destinations in the World. Texas Hill Structure is primarily mostly of weak calcareous stone. Calcium may worsen or degrade if exposed to carbon dioxide in rainwater. This practice affects the land of the Texas smoky Mountains leading to the formation of underwater groves.

According to Charle's law, the volume of the given mass of a gas is directly proportional to its absolute temperature provided that the pressure is constant. Mathemically;

where;

V1 and V2 are the initial and final volume of the gas

T1 and T2 are the initial and final temperatures of the gas (in Kelvin)

Given the following parameters:

Substitute the given parameters into the formula;

Therefore the volume of the gas at 20°C is approximately 97.67cm³

Answer:

mannn i told that little brat to stop taking the goldfish outta the box because i want them so he better hope he dies cuz if he dosent imma shove these goldfish down his throat ~respectfully~

Explanation: