A ball of mass 0.5 kg , initially at rest, acquires a speed of 4 m/s immediately after being kicked by a force of strength 20 N. For how long did this force act on the ball?
(A) 0.01 s
(B) 0.1 s
(C) 0.2 s
(D) 1 s

Kinematics is the branch of physics and a subdivision of classical mechanics concerned with the geometrically possible motion of a body or system of bodies without consideration of the forces involved. :)

Answer:

Kinematics is a branch of mechanics that deals with pure motion, without reference to the masses or forces involved in it.

Explanation:

Ex. X=2t+1 here x is related to t which is time(function of time)

Answer: A/ average velocity=d/t

Explanation:

The average velocity is the displacement divided by change in time Thus it can be written as Ad/At. Hence, option b is correct.

Velocity of an object is the rate of change of  speed of that object. Mathematically it is the ratio of total displacement to the time taken to travel.

Velocity = Displacement/time.

Let a body travelling a distance within a time t have an initial velocity and then changes to a new final velocity then, the measure of net velocity is called its average velocity.

Suppose v1 be the initial velocity and v2 be the final velocity to move a distance d at a time t, then the average velocity is written as follows:

v2 - v1 = d/t.

Therefore, average velocity is written in terms of average distance travelled and change in time thus, option b is correct.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

e. mole

Explanation: wth is a mole

According to unit conversion, all of the following are SI base units except mole.

Unit conversion is defined as a multi-step process which involves multiplication or a division operation by a numerical factor.The process of unit conversion requires selection of appropriate number of significant figures and the rounding off procedure.

It involves a conversion factor which is an expression for expressing the relationship between the two units.A conversion ratio always has value which equals to one which indicates that numerator and denominator have values which are expressed in different units.

It is an easy process which involves unit conversion between the different conversion systems. While unit conversion care needs to be taken regarding accuracy and precision.

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A proton (charge 1.602 * 10-19) moves a distance of d= 0.59 m from point A to point B in a straight line inside a linear accelerator. The electric field of the accelerator is uniform and has a magnitude of 15 MN/C.

i.) The expression for the force on proton is,

F=qE

(1.6⋅10−19 )(1.5⋅10 7)

=2.4⋅10 −12 N

Thus, the force on the proton is 2.4⋅10 −12 N.

ii) The expression for the work done by the field is,

W=qEd

(1.6⋅10 −19)(1.5⋅10 7 )(0.5)

=1.2⋅10 −12J

iii) The expression for the potential difference is,

U=Ed

=(1.5⋅10 7) (0.5)

=0.75⋅10 7 V

Electric potential of a system of point charges?

A point charge's electric potential is V=kQ/r. Electric field is a vector while electric potential is a scalar.

What is the electric potential at a point distance?

Electric potential at point P, located at a distance of r=R2 from the center, where R is the radius of an evenly charged shell with a density of surface charges.

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Answer:

d. such that it never crosses the axis.

Explanation:

A convex lens is type of converging lens. When parallel rays of light pass through a convex lens, the rays which are refracted converge at the principal focus. Focal length is the distance between the principal focus and the centre of the lens.

A light ray, traveling parallel to the axis of a convex thin lens, strikes the lens near its midpoint. After traveling through the lens, this ray emerges traveling obliquely to the axis of the lens such that it never crosses the axis.

Answer: The axial tilt of the Earth

Explanation: The planet is tilted on its north-south axis by 23 degrees, making one hemisphere (out of northern and southern) closer to the sun than the other for half of the year. The hemisphere that's closer to the earth at any point experiences summer, and the one further away experiences winter.

Answer: The difference between the solstices is that one represents the point at which the hemisphere in question is closest to the sun (summer solstice) and furthest away (winter solstice)

If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.

I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.

Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.

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This question involves the concept of  Newton's law of gravitation.

The force of gravity between the two spaceships is "1355.78 N".

According to Newton's Law of Gravitation:

\(F=\frac{Gm_1m_2}{r^2}\)

where,

Therefore,

\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)

F = 1355.78 N = 1.356 KN

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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,

The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.

The distance between spaceships (r) is 35 meters.

It is required to find the Force of gravity between these spaceships.

It is defined as the force which attracts any two masses in the universe.

By Newton's law of Gravitation:

\(\rm F= \frac{Gm_1m_2}{r^2}\)  , Where

\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)

Putting values in the above formula:

\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)

F = 1355.78 N = 1.356  KN

Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.

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The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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Answer: True

Explanation:

Cardiopulmonary resuscitation (CPR) is a medical procedure involving repeated compression of a patient's chest in an attempt to restore the blood circulation and breathing of a person who has suffered cardiac arrest.

Answer:

the work done by the field is positive and the potential energy of the electron field system decreases

Explanation:

This exercise asks to find the work and the potential energy of an electron in an electric field.

Work is defined by

         W = F .d = F d cos θ

the electric force is

          F_e = q E

         W = q E d cos θ

since the charge of the electron is negative the force is in the opposite direction to the electric field

          W = - e E d

we select the direction to the right is positive, point i is to the left of point f,

therefore the work moving from point i to point F has two possibilities

* The electric field lines go from i to f point , so that point i is on the side of the positive charges, so the electron approaches them, This movement is opposite to that indicated

* the field line reaches point i, this implies that the charges are negative, so the electrioc field is then negativeand the electron charge is negative too.  The electron moves away from this point, this is in accordance with the indicated movement

In the latter case the electric field lines go from f to i point, therefore the Work is positive

Now let's examine the potential energy

            ΔU = - q E .d

so we see that this definition is related to work,

            ΔU = -W

Therefore, as the work is positive, the power energy must decrease

When reviewing the different answers, the correct ones are:

the work done by the field is positive and the potential energy of the electron field system decreases

The work done by the electron while moving from point \(i\) to point \(f\) in the direction of uniform electric field is negative and the potential energy of the electron increases.

An electron moves from point i to point f, in the direction of a uniform electric field, then  the potential energy of the electron can be calculated s given below.

\(\Delta V=-qEd\)

Where \(\Delta V\) is the potential energy, \(E\) is the electric field, \(q\) is the charge and \(d\) is the displacement of the electron.

The work done by the electron in the uniform electric field can be calculated as,

\(W = F\times d \times cos\theta\)

Where \(W\)is the work done by electron, \(F\) is the electric force, \(d\) is the displacement of the electron and  for uniform electric field, the value of \(\theta\) is zero.

Hence  \(W=F\times d\times 1\\W=F \times d\)

Electric force  \(F = q E\)

By substituting the value of electric force on the above formula,

\(W = qEd\)

Hence, the relation between the work done the electron in an uniform electric field and potential energy of the electron can be given below.

\(W = -\Delta V\)

The work done by the electron is negative and the potential energy of the electron increases.

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Answer:Magnetic fields from two sources add up as vectors at each point, so the strength of the field is not necessarily the sum of the strengths1. Magnetic fields are vectors, which means they have direction as well as size. Therefore, the sum of two magnetic fields is not simply the sum of their magnitudes2.

Explanation:

Answer:

    x₁ = 3.481 m

Explanation:

In this exercise the acceleration of the dog and the sled are given, for which we can use the kinematic relations.

Let's start by fixing a reference system located on the sled and suppose that it moves to the right, the sled acceleration a₁ = 0.2 m / s, the dog is on the other side of the rope, so if the acceleration is a₂ = -0.5 m / s2, the negative sign indicates that it is moving to the left.

The initial position of the sled is x₁₀ = 0 and the initial position of the dog is x₂₀ = 12.2 m, let's write the expressions for the position

            x₁ = x₁₀ + v₁₀ t + ½ a₁ t²

            x₂ = x₂₀ + v₂₀ t + ½ a₂ t²

in this case the two bodies start from rest so their initial velocities are zero

we substitute the values

           x₁ = 0 + 0 + ½ (0.2) t²

           x₂ = 12.2 + 0 + ½ (-0.5) t²

at the point where the two meet, the position is the same

           x₁ = x₂

          ½ 0.2 t² = 12.2 - ½ 0.5 t²

          (0.1 + 0.25) t² = 12.2

                t = \(\sqrt{ \frac{12.2}{0.35} }\)

                t = 5.9 s

we look for the position of the sled (subscript 1)

            x₁ = ½  0.2  5.9²

            x₁ = 3.481 m

The average highest height of a professional football kick is 189.728 m if the hang time is 4.4 seconds on average.

A person or an object's total duration in the air after leaving the ground is known as their "hang time." From the time anything leaves the ground until it returns, it is measured.

We know,

y= gt²

Here,

y = Average maximum height

g = acceleration due to gravity

t = Average hang time

Given,

Average hang time (t) = 4.4s

Acceleration due to gravity (g) = 9.8 m/s² (assuming)

Inserting these values in the given equation,

y = gt²

  = 9.8×4.4×4.4

  = 189.728 m.

Hence, the average maximum height of the football is 189.728 m.

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Law of conservation of momentum states "The total momentum of all objects interacting with one another remains constant, regardless of the nature of the forces between the objects".

Law of conservation of energy states "Within a closed system, the total amount of energy will remain constant". The equation derived using the Law of conservation of energy is

E =m g H

E = Energy

m = Mass

g = Acceleration

H = Height

The equation derived using the Law of conservation of momentum is

\(m_{1} u_{1} +m_{2} u_{2}\) = \(m_{1} v_{1} + m_{2} v_{2}\)

\(m_{1}\) = Mass of object 1

\(m_{2}\) = Mass of object 2

\(u_{1}\) = Initial velocity of object 1

\(u_{2}\) = Initial velocity of object 2

\(v_{1}\) = Final velocity of object 1

\(v_{2}\) = Final velocity of object 2

Therefore,

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Answer:

maxed out

Explanation:

The value of acceleration is 3 m/s2.

Our body makes every effort to open up our airways. When sneezing, the diaphragm, abdomen, vocal cord, and chest muscles all work together. As a result, the air leaving our lungs accelerates rapidly.

Change in velocity, Δv

Change in time, Δt

Note that

1 km = 1000 m

1 h = 3600 s

Therefore

Δv = (125,000 m/h)*(1/3600 h/s) = 3 m/s2.

Therefore, The value of acceleration is 3 m/s2.

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Option C. The heat absorbed or lost by a substance while it's changing state  correctly describes latent heat

Latent heat is the heat absorbed or lost by a substance while it is changing state.

The latent heat is a type of heat that is transferred during phase change, i.e., while a substance undergoes a change of state.

For example, when ice melts into liquid water, or when liquid water evaporates into water vapor, heat is absorbed from the surroundings.

Latent heat is not associated with a temperature change; rather, it's associated with a change of state.

For instance, the temperature of water remains at 100°C while boiling.

When water is boiling, the latent heat of vaporization is absorbed and utilized to break the hydrogen bonds holding water molecules together to change water from the liquid phase to the gaseous phase.

When the water is boiling, adding more heat won't increase the water's temperature, instead, the extra heat will be absorbed to change the phase of water molecules.

Therefore, the correct answer to the given question is option C: The heat absorbed or lost by a substance while it is changing state.

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We will determine the current as follows:

First, we recall that:

So:

So, the current that a 75-W light bulb draws when connected to 120 V is 0.625 Amps.

Answer:

Explanation:

The time taken can be found by using the formula

\(t = \frac{d}{v} \\ \)

From the question we have

\(t = \frac{210}{36} \\ = 5.8333...\)

We have the final answer as

Hope this helps you

part a.  the wavelength of this wave  is 26 cm

part b. The amplitude (A) of a wave is 9 cm

The wavelength (λ) of a wave is described as the distance between two consecutive points on the wave that are in phase.

In this scenario, the distance between two corresponding points on the wave will be equal to the horizontal distance from crest to trough, which is 26 cm.

Hence, the wavelength of the wave is: λ = 26 cm

The amplitude (A) of a wave is described as the maximum displacement of a particle from its rest position as the wave passes through it.

In this scenario, the vertical distance from crest to trough is 18 cm, which is equal to twice the amplitude.

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We must do 113 J of work to push the crate a distance of 3.00 m up the ramp at constant velocity.

What is constant velocity ?

Constant velocity is a term used to describe the motion of an object that is moving in a straight line with a constant speed. In other words, if an object is traveling at a constant velocity, its speed and direction of motion are both constant and unchanging. This means that the object is not accelerating, which in turn means that the net force acting on it is zero.

It is important to note that constant velocity does not mean that the object is at rest, as it can still be moving at a constant speed. Additionally, if the velocity of an object changes, even if its speed stays the same, it is still considered to be accelerating.

Since the crate is moving at a constant velocity, the net force acting on it must be zero. This means that the force you are applying to push the crate up the ramp must be equal in magnitude and opposite in direction to the force of friction acting on the crate. Using Newton's second law, we can write:

ma = F_push - F_friction

where m is the mass of the crate, a is its acceleration (which is zero since it is moving at constant velocity), F_push is the force you are applying to push the crate up the ramp, and F_friction is the force of kinetic friction acting on the crate.

The force of friction can be found using the coefficient of kinetic friction and the normal force. The normal force is equal in magnitude and opposite in direction to the component of the weight of the crate that is perpendicular to the ramp. Using trigonometry, we can find that:

N = mg cosθ

where g is the acceleration due to gravity and θ is the angle of the ramp. The force of friction is then:

F_friction = kN = kmg cosθ

So we can rewrite Newton's second law as:

ma = F_push - kmg cosθ

Solving for F_push, we get:

F_push = ma + kmg cosθ

The work done by a force is given by:

W = Fd cosφ

where F is the force, d is the distance moved, and φ is the angle between the force and the direction of motion. In this case, the force and the displacement are in the same direction, so φ = 0 and the work done by the pushing force is simply:

W_push = F_push d

Plugging in the given values, we get:

W_push = (ma + kmg cosθ) d

= (20.0 kg)(0 m/s^2 + 0.200(9.81 m/s^2) cos31.0°)(3.00 m)

= 113 J

Therefore, we must do 113 J of work to push the crate a distance of 3.00 m up the ramp at constant velocity.

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Answer:

The greater weight increases the terminal velocity by acting as an extra force against gravity and air resistance.

Answer:

The higher the energy, the shorter the wavelength.

Explanation:

Answer:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=125$.

Step 4: In the same vein, $x\%=125$.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$.

Explanation:

The correct asnwer is D. The permanent magnets cause the metal loop in the

electromagnet to turn.

In an electric motor, the permanent magnets cause the metal loop in the

electromagnet to turn. So, option (D) is correct.

An electrical device that transforms electrical energy into mechanical energy is an electric motor. The majority of electric motors work by creating force in the form of torque imparted to the motor shaft through the interplay of the magnetic field of the motor and electric current in a wire winding.

In an electric motor, their remains a permanent magnet to produce constant magnetic field. When electric current is passed through the conducting loop, it acts ling electromagnet and begins to rotate. Thus an electric motor works. Hence, option(D) is correct.

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Answer:A

Explanation:

Answer:

A. -2.83 x 10-7N

Explanation:

Answer:

The object with the twice the area of the other object, will have the larger drag coefficient.

Explanation:

The equation for drag force is given as

\(F_{D} = \frac{1}{2}pu^{2} C_{D} A\)

where \(F_{D}\) IS the drag force on the object

p = density of the fluid through which the object moves

u = relative velocity of the object through the fluid

p = density of the fluid

\(C_{D}\) = coefficient of drag

A = area of the object

Note that \(C_{D}\) is a dimensionless coefficient related to the object's geometry and taking into account both skin friction and form drag. The most interesting things is that it is dependent on the linear dimension, which means that it will vary directly with the change in diameter of the fluid

The above equation can also be broken down as

\(F_{D}\) ∝ \(P_{D}\) A

where \(P_{D}\) is the pressure exerted by the fluid on the area A

Also note that \(P_{D}\) = \(\frac{1}{2}pu^{2}\)

which also clarifies that the drag force is approximately proportional to the abject's area.

In this case, the object with the twice the area of the other object, will have the larger drag coefficient.

Answer:

A. 7.0 milliseconds

Explanation:

We know the formula: Force = [mass( final velocity - initial velocity )] / time

using the formula:

83 = 0.45 (  1.3 - 0 ) / time

time = ( 0.45 * 1.3 )/ 83

time  = 0.585/83

time = 7.0 milliseconds

The time for the mallet in contact with the ball is 7 milliseconds.

To find the time , the given values are,

Mass = 0.45 kg

Force = 83 N

Final velocity = 1.3 m/s, Initial velocity = 0 m/s.

According to Newton's second law of motion, Force is equal to mass that is multiplied by the acceleration.

F = m.a

where, F - Force

m - Mass

a - Acceleration

Here,  Acceleration = ( Final velocity - Initial Velocity) / ( Time )

Acceleration can be defined as the change in velocity with respect to time.

Force = [mass( final velocity - initial velocity )] / time

Substituting the given values in the formula,

83 = 0.45 (  1.3 - 0 ) / Time

Time = ( 0.45 * 1.3 )/ 83

Time  = 0.585/83

Time = 7.0 milliseconds

Hence, Option A is the correct answer.

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