A ball is thrown with velocity 30.m⋅s−1at an angle of 40.º below the horizontal. What is the magnitude of the horizontal component of the velocity? Give your answer to the nearest m⋅s−1 and do not include units with your answer.

equal in magnitude but opposite in direction

A correct equation for the quantities represented in this scenario is

tan Θ=\(\frac{d_{n} }{d_{e} }\).

Now, according to the question,

tanΘ=\(\frac{opp.\: side}{adj.\: side}\)

Now, by the figure mention,

The side opposite to the angle Θ is \(d_{n}\) and the adjacent sides is \(d_{e}\).

The three primary trigonometric functions—Sine, Cosine, and Tangent—are based on a right-angled triangle.

Triangle with the opposite side, adjacent side, and hypotenuse can be declared by:

The terms "opposite" and "adjacent" refer to the angle's opposing and adjacent, respectively.

The long one is "Hypotenuse."

Now, put these values in the formula,

which gives the equation,

tanΘ=\(\frac{d_{n} }{d_{e} }\)

Now, from the options given it is clearly seen that option-1 is correct.

Question: in the town of centralburg (figure 1), which is laid out in a uniform block grid, the grocery store is three blocks east and four blocks north of the post office. which of the following is a correct equation for the quantities represented in this scenario

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Explanation:

The volume of a simple compressible system is not fixed. At a state of equilibrium, there should be uniformity in the entire system.

From the question we have here, these are the correct options:

1. It cannot be a mixture of different substances (e.g. oxygen and nitrogent)

2. It can be composed of any phases of a substance: solid, liquid, and/or gas

3. It's state is specified if given two independent, intensive thermodynamic properties.

A robot can travel to space for a lot less expense than a human.

The mechanical design of planetary rovers, the mechanical design of space manipulators, actuators and sensors of space robots, end-effector/tools of space robots, reconfigurable robots, and robot mobility all contribute to the success of space exploration.

People are able to adapt to unforeseen circumstances and use their imaginations to come up with solutions. This is particularly crucial in space travel, where unforeseen difficulties are likely to appear.

It is possible for humans to carry out scientific studies and experiments in space.

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Although we do not have the necessary information to provide an exact answer, we can confirm that the object will have fallen by a multiple of 9.8 meters due to gravity.

When an object is dropped, its acceleration is determined by gravity. This force applies a constant acceleration of 9.8 meters per second. Therefore, to calculate its speed at distance h, we would need to know the time it has taken the object to reach this point, and use that together with our known acceleration in order to calculate its current speed.

Therefore, we can confirm that in order to calculate the current speed of the object at point h, we require the time taken to reach this point or the value of the distance itself and that the answer will be a multiple of 9.8, due to gravity.

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Answer:

A mixture has particles that cannot be seen but do reflect light. It should be classified as a colloid. A colloid is a mixture in which one substance is suspended throughout another substance.

Explanation:

Answer:

2.753*10^-11N

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

Hence the gravitational force between the asteroid is 2.753*10^-11N

The elevator accelerates upward at an acceleration, then the magnitude of the force is 148.84 N.

The force is the action of push or pull which makes an object to move or stop.

Given the mass of child m =13.9 kg, acceleration a =0.898 m/s², then the force will be given by

F = m(g-a)

F = 13.9 x (9.81 - (-0.898))

F = 148.84 N

Thus, the magnitude of the force is  148.84 N.

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the mass

From the question we have

\(a = \frac{12}{4} \\ \)

We have the final answer as

Hope this helps you

The value of  force b if the magnitude the force is 26N is determined as 24 N.

The value of force is calculated by applying the formula for determining the magnitude of a force as shown below;

The magnitude of a force is calculated as;

F = √ x² + y²

where;

The given magnitude of the force = 26 N

The x component of the force = 10

The y component of the force = b

26 = √ ( 10²  + b² )

26² = 10² + b²

676 = 100 + b²

b² = 676 - 100

b² = 576

b = √ 576

b = 24 N

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According to the give value of the mass of lemonade and change in the temperature, the specific heat capacity of the lemonade is 3.81 J/kg/k.

The formula for the specific heat capacity (C) = Q/ m × ΔT

Q is energy added and the value, which is 334J

m is the mass of the lemonade, which is 300g = 0.3 kg

Δ T is the change in temperature, which is 19°C =(273+19)= 292 K

So, C = 334/ 0.3 × 292

         = 3.81 J/kg/k

So the specific heat capacity of the lemonade is 3.81 J/kg/k.

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Answer:

Did you think you could pull that off-

:I

I live in Japan anyway so.. ウーフ-

Answer:

I=Q/T

2.8=Q/3

8.4C=Q

Explanation:

The average velocity of the car is 37.27 km/h.

The given parameters;

The average velocity of the car is calculated as follows;

\(average \ velocity = \frac{Total \ displacement}{Total \ time}\)

The total displacement of the car is calculated as follows;

\(d = \sqrt{x^2 + y^2} \\\\d = \sqrt{100^2 \ + \ 50^2} \\\\d = 111.803 \ km\)

The average velocity of the car is calculated as follows;

\(v = \frac{111.803}{3} \\\\v = 37.27 \ km/h\)

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Answer:

200 km/hr

Explanation:

Since he goes 80km per hour, multiply this by 2.5 or two and a half hours.

80 x 2.5 = 200 km/hr.

Explanation:

Friction acts between two surfaces in contact only and opposes the movement of one body with respect to another. Therefore friction is a force which opposes the relative motion between two bodies. If a body is moving it is slowed down by frictional force applied on it by the surface on which it is moving.

Gravitational acceleration on the newly discovered planet is calculated to be approximately 26.7 m/s².

The acceleration of an object in free fall within a vacuum is known as gravitational acceleration.

As we know, g = G * M / r²

G is the gravitational constant (6.67 x 10⁻¹¹  N*m²/kg²)

M is the mass of the planet

r is the radius of the planet

Plugging in the given values, we get:

g = (6.67 x 10⁻¹¹ N*m²/kg²) * (7.0 x 10²⁴ kg) / (5600 km)²

g = (6.67 x 10^⁻¹¹  N*m²/kg²) * (7.0 x 10²⁴  kg) / (5600 x 1000 m)²

g ≈ 26.7 m/s²

Therefore, the gravitational acceleration on the newly discovered planet is approximately 26.7 m/s².

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The emergent angle of the first wavelength is 25.53⁰.

The emergent angle of the second wavelength is 26⁰.

The angle each beam leave the the prism is calculated using Snell's law as follows;

\(n_1 si n\theta _1 = n_2 sin\theta_2\)

The emergent angle of the first wavelength is calculated as follows;

\(sin(45) = 1.64sin\theta_1\\\\sin\theta _1 = \frac{sin(45)}{1.64} \\\\sin\theta _1 = 0.431\\\\\theta_1 = sin^{-1} ( 0.431)\\\\\theta_1 =25.53 ^0\)

The emergent angle of the second wavelength is calculated as follows;

\(sin(45) = n_2 sin(\theta_2)\\\\sin(45) = 1.62 sin(\theta_2)\\\\sin(\theta_2) = \frac{sin(45) }{1.62} \\\\sin(\theta_2) = 26^0\)

"Your question is not complete, it seems be missing the following information";

A parallel beam of light containing two wavelengths, λ1 = 465 nm and λ2 = 652 nm, enters the silicate flint glass of an equilateral prism. At what angles, θ1 and θ2, does each beam leave the prism. Use n455nm = 1.64 and n642nm =1.62. The incident angle is 45⁰.

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The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.

The object and image distance formed by the lens is calculated by applying the following lens formula.

v + u = 40 ------- (1)

v/u = 3 ------------ (2)

v = 3u

Substitute v into equation (1);

3u + u = 40

4u = 40

u = 40/4

u = 10 cm

The image distance = 3u

= 3 x 10 cm

= 30 cm

Thus, the object distance is 10 cm and the image distance is 30 cm.

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The time taken by light to go from A to B is approximately 0.000020087 seconds.

The speed of light in a medium is given by:

v = c/n

where c is the speed of light in vacuum and n is the refractive index of the medium.

In medium 1, the speed of light is:

v1 = c/n1 = c/1.33

In medium 2, the speed of light is:

v2 = c/n2 = c/1.51

The distance that light travels in medium 1 is 331 cm, whereas in medium 2, the distance is 151 cm. The time it takes for light to get from point A to point B is the product of the times it takes in mediums 1 and 2.

t = d1/v1 + d2/v2

Substituting the given values, we get:

t = (331 cm)/(c/1.33) + (151 cm)/(c/1.51)

Since the units of speed and distance are not consistent, we need to convert the units to a common unit. We can use meters as the common unit:

t = (3.31 m)/(c/1.33) + (1.51 m)/(c/1.51)

Now, we can use the value of the speed of light in vacuum:

c = 299792458 m/s

Substituting this value, we get:

t = (3.31 m)/((299792458 m/s)/1.33) + (1.51 m)/((299792458 m/s)/1.51)

t = 0.000015065 s + 0.000005022 s

t = 0.000020087 s.

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The coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

To find the limit that the coefficient of static friction places on the minimum time required for a car to accelerate from rest to 60.0 mph (26.8 m/s), we need to consider the maximum acceleration the car can achieve due to the friction between the rear tires and the pavement.

The maximum acceleration can be determined using the formula:

a_max = μs * g

where μs is the coefficient of static friction and g is the acceleration due to gravity (approximately 9.8 m/s²).

In this case, since the car's engine only turns the two rear wheels, the maximum acceleration is limited by the friction force between the rear tires and the pavement.

Now, to calculate the minimum time required to accelerate to 60.0 mph (26.8 m/s), we can use the following kinematic equation:

v = u + a * t

where v is the final velocity (26.8 m/s), u is the initial velocity (0 m/s), a is the acceleration, and t is the time.

Rearranging the equation, we have:

t = (v - u) / a

Plugging in the values, we get:

t = (26.8 m/s - 0 m/s) / a_max

t = 26.8 m/s / (μs * g)

Substituting the given value for the coefficient of static friction (μs ≈ 0.800) and the acceleration due to gravity (g ≈ 9.8 m/s²), we can solve for the minimum time required:

t = 26.8 m/s / (0.800 * 9.8 m/s²)

t ≈ 3.42 seconds

Therefore, the coefficient of static friction places a limit of approximately 3.42 seconds on the minimum time required for the car to accelerate from rest to 60.0 mph (26.8 m/s).

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Explanation:

if u apply more force to an object, it accelerates at a higher rate

Answer:

Explanation:

Sure, I'd be happy to help you with the question!

Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.

So, the function can be written as:

Output = (6 * x) - 80

Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:

x = (6 * x) - 80

Let's solve this equation to find the value of x:

x = 6x - 80

Subtracting 6x from both sides, we get:

x - 6x = -80

Combining like terms, we have:

-5x = -80

Dividing both sides by -5, we find:

x = (-80) / (-5)

Simplifying the expression, we have:

x = 16

Therefore, the input (x) that results in the input being the same as the output is 16.

To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.

Answer:

16

Explanation:

(x*6) - 80 = x

Multiply the parentheses

6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16

Answer:

C.) Quadratic (power)

Explanation: I did the thingy and it worked

its not A or B

Answer:

C) Quadratic (power)

Explanation:

I took the physics exam

The energy input at aphelion (farthest from the sun) is 92% of the intensity at perihelion (closest to the sun) because of the inverse-square law, which states that the intensity of radiation decreases with the square of the distance from the source.

However, the difference in energy input does not solely explain the difference in surface temperature from winter to summer.

Other factors, such as the Earth's axial tilt, atmospheric composition, and cloud cover also play a role in determining the surface temperature.

Evidence from climate models and observations indicate that changes in these factors, especially changes in the number of greenhouse gases in the atmosphere, can have a significant impact on global temperature patterns.

In conclusion, while the inverse-square law affects the intensity of solar radiation, it is not the sole factor in determining surface temperature, and the role of other factors must be considered to fully understand seasonal and climatic variations.

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Answer:

A) W =250J B) Power = 125 J/s  C) Work = 250 J Power = 250 J/s

Explanation:

Work = Force*distance

A:

\(W = 10kg*10m/s^2*2.5m\\W = 250 J\\\)

B:

Power is J/s

Power = 250J/2.0s = 125 J/s

C:

Work stays the same

Power increases to 250 J/s