a 90 gram object moves around a circle whose diameter is 2.56 m at a constant speed off 16 m/s. what is the object acceleration? how much time will take to complete the around?

The heat loss from the object in 13 minutes is \(Q = -1.503684 * 10^{-3} Joules\)

Heat loss can be calculated using this formula:

\(\frac{Q}{t} = oeA(T^{4} _{2} - T^{4} _{1})\\\)

It can be found that:

Q = heat loss in joules

t = time in seconds, 13 minutes = 780seconds

σ = (5.67 x 10⁻8J/s . m² . K⁴)

e = emissivity, 1

A = surface area of 1m²

T₂ = temperature of a room,  296 K

T₁ = temperature of an object, 330 K

Find \(Q\), where \(Q\) = \(\frac{Q}{t} = oeA(T^{4} _{2} - T^{4} _{1})\\\) = \(Q = oeA(T^{4} _{2} - T^{4} _{1}) t\\\)

\(Q = (5.67 x 10^{-8} J/s . m^{2} . K^{4} ) (1) (1) (296 K^{4} - 330 K^{4} ) (780)\\\)

\(Q = -0.001503684J\)

\(Q = -1.503684 * 10^{-3} Joules\)

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The distance traveled in meters is 290m. It can be solved using Newton's Laws of motion.

You can solve this problem by using the formula of

d = 1/2 a t^2

where d is the distance traveled in meters,

a = 20 m/s², and t =7 seconds

Plug-in the data to the formula and solve for the distance traveled after

7 s.

d = 1/2 a t^2

=1/2 × 20 × 7²

= 290m

Hence the dist travelled by the car is 290m

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Answer:

The acceleration due to gravity of Jupiter is 25 m/s^2. means that, Any object dropped near Jupiter's Surface will accelerate downward (towards the Jupiter's surface) at the rate of 25 m/s^2 due to the gravity of Jupiter

Explanation:

hope it's help

Answer:

Explanation:

If any object is dropped from a height above the Jupiter's surface the object will fall towards jupiter's surface with a constant acceleration of 25m/s^2.

A)The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.

B).The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J

C) The rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.

D) The mass of the pulley ismp = (1/2)mpr²/R² =(1/2)(0.020 kg)(0.100 m)²/(0.200 m)² = 0.001 kg = 1 g.r = (1/2)R.

The Atwood's machine shown in Figure 1 consists of two masses mA = 6.50 kg and mB = 3.30 kg. The height of mA above the floor is 0.865 m. When mA hits the floor, its velocity is 1.89 m/s. The pulley has a moment of inertia (1/2)mpr². We have to find the total mechanical energy of the two blocks before they are released, the total mechanical energy when mA hits the ground, the rotational kinetic energy of the pulley just before mA hits the ground, and the mass of the pulley. Let's solve these one by one. Part A The total mechanical energy of the two blocks prior to being released from rest can be found by adding the gravitational potential energy of mA and the pulley to zero.

The equation for gravitational potential energy is mgh. The gravitational potential energy of mA and mB is mAg(h-hB)where h is the height of mA above the floor and hB is the height of mB above the floor. Since the pulley is at the same height as mB, its gravitational potential energy ismBg(h-hB).The gravitational potential energy of mA is6.50 kg × 9.81 m/s² × 0.865 m = 54.33 J.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J,where mp is the mass of the pulley.The total mechanical energy of the two blocks prior to being released from rest is54.33 J + 0 J = 54.33 J.Part BThe total mechanical energy of the two blocks when mA hits the ground can be found by adding the kinetic energy of mA, the kinetic energy of mB, and the rotational kinetic energy of the pulley to the gravitational potential energy of mB and the pulley. The equation for kinetic energy is (1/2)mv². The kinetic energy of mA is(1/2) × 6.50 kg × (1.89 m/s)² = 11.54 J.The kinetic energy of mB is(1/2) × 3.30 kg × 0 m/s² = 0 J, since it is at rest.The gravitational potential energy of mB and the pulley is(3.30 kg + mp) × 9.81 m/s² × 0 m = 0 J.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω²,where R is the radius of the pulley and ω is its angular velocity just before mA hits the ground. We can use the fact that the linear speed of the rope is the same on both sides of the pulley to find ω. The equation for linear speed is v = Rω. When mA hits the ground, its speed is 1.89 m/s. The speed of mB is zero. Since the rope is inextensible, the speed of the rope is also 1.89 m/s.

Therefore, the speed of the pulley is also 1.89 m/s. We can find the angular velocity of the pulley by dividing the linear velocity by the radius.ω = v/R = 1.89 m/s ÷ (0.200 m/2) = 18.9 rad/s.The rotational kinetic energy of the pulley is(1/2) × (1/2)mp × R² × ω² =(1/4)mpR²ω² =(1/4)mp(0.200 m)²(18.9 rad/s)² =(0.178 mp) J.The total mechanical energy of the two blocks when mA hits the ground is11.54 J + 0 J + 0 J + (0.178 mp) J = 11.72 J + (0.178 mp) J.Part CThe rotational kinetic energy of the pulley just before mA hits the ground is(0.178 mp) J.Part DWe can find the mass of the pulley by using the moment of inertia of a disk and the mass of the pulley. The moment of inertia of a disk is (1/2)mr². Therefore,(1/2)mpR² = (1/2)mpr²,where R is the radius of the pulley and r is the radius of gyration of the pulley. The radius of gyration of a disk is (1/2)R.

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a ) The angle between the ropes when the crate is on the ground = 18.4°

b ) Force exerted by Sean and Greg = 260.8 N

c ) Force exerted when the crate is 5.75 ft below them = 354.9 N

a ) The angle between the ropes,

Distance between crate and a person = 33.5 ft

Distance between Sean and Greg = 11 ft

Consider only one person side of the rope and the midway point between Sean and Greg. This forms a right angled triangle.

sin θ = 5.5 / 33.5

θ = \(sin^{-1}\) ( 0.16 )

θ = 9.2°

Angle between the ropes = 2 θ

Angle between the ropes = 2 * 9.2

Angle between the ropes = 18.4°

b ) Force exerted,

Since both ropes pull the same amount of weight for the same amount of distance, their tensions will be equal,

T = T1 = T2

Resolving the tension into its horizontal and vertical component.

\(T_{y}\) = T cos θ

\(T_{x}\) = T sin θ

Since there is not time component mentioned assuming the crate is pulled at a constant velocity. Therefore acceleration will be zero and hence net force in vertical direction will be zero.

m = 115 lb = 52.16 kg

∑ \(F_{y}\) = 0

T cos θ + T cos θ - m g = 0

2 T cos 9.2° = 52.16 * 9.8

T = 511.17 / 1.96

T = 260.8 N

c ) When the crate is 5.75 ft below them,

tan θ = 5.5 / 5.75

θ = \(tan^{-1}\) ( 0.96 )

θ = 43.8°

∑ \(F_{y}\) = 0

T cos θ + T cos θ - m g = 0

2 T cos 43.8° = 52.16 * 9.8

T = 511.17 / 1.44

T = 354.9 N

d ) The force to lift the crate changes as it moves closer to them is because in a shorter cable the horizontal force increases and the vertical force decreases. So it becomes harder to pull as it gets closer to the destination.

Therefore,

a ) The angle between the ropes when the crate is on the ground = 18.4°

b ) Force exerted by Sean and Greg on the ropes when lifting the 115-lb crate off the ground = 260.8 N

c ) Force exerted by Sean and Greg when the crate is 5.75 ft below them = 354.9 N

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Answer:

unfournatletly

Explanation:

i have no clue sorry to waste ur time ill rather not say a answer that will be incorrect.

Answer:

Pluto

Explanation:

Answer:

the answer is the first one.

Explanation:

one way to find out is if you look at the other equations they are mixed matched. For an example a=d/t should be s= d/t.

Answer:

a

Explanation:

i did it

The correct answer isThe astronaut's b) mass remains the same.

The mass of an object remains constant regardless of its position or distance from the center of the Earth. Mass is a measure of the amount of matter in an object and is an intrinsic property. It does not change with the position or location of the object.

On the other hand, the weight of an object can vary depending on its distance from the center of the Earth. Weight is the force experienced by an object due to gravity and is dependent on the mass of the object and the gravitational acceleration at its location.

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As an astronaunt travels from the surface of the earth to a postion that is four times

as far away from the center of the earth, the astronaut's

a) mass decreases

b)

mass remains the same

c) weight increases

d) weight remains the same

Answer:

A mixture is a combination of two or more substances in any proportion. This is different from a compound, which consists of substances in fixed proportions. ... The lemonade pictured above is a mixture because it doesn't have fixed proportions of ingredients.

Explanation:

Laser printers work with the use of heat and positive and negative charges of the plastic ink dots themselves.

Option A is correct.

Heat and both positive and negative charges power laser printers. Text or images are imprinted with a negative charge by the laser on areas of the printer drum. The locations on the drum that have this negative charge attract the dust of plastic ink.

A laser printer operates on the principle of static electricity. By applying an electrical current to the photoreceptor drum at first, corona wire gives it a positive charge. After that, in accordance with the information sent by the computer, the printer projects a tiny laser beam horizontally across the surface.

Incomplete question :

A.Laser printers work with the use of heat and positive and negative charges.

B.The laser etches a negative charge on spots of the printer drum in the form of text or images.

C.The plastic ink dust is attracted to the places on the drum with this negative charge.

What is the charge of the plastic ink dots themselves

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Answer:

Option A

Explanation:

The graph for this problem must depict the following ""Increased allocation of resources to reproduction relative to growth diminished future fecundity."

Hence, the survivor ship must be on the Y axis and the resources on the X axis.

Here the resources include the number of seeds produced.

hence, the higher is the number of seeds (resource), the lower is the survivorship (future fecundity)

Hence, option A is correct

If the participants hadn't been reassigned, age would have been a confounding variable. Option D

A confounding variable is a variable that is associated with both the independent variable and the dependent variable.

In this case, age is associated with both video game playing and mood. Younger people are more likely to play video games, and they are also more likely to have better moods.

If the participants hadn't been reassigned, the difference in mood between the experimental and control groups could have been due to the difference in age, not the difference in video game playing.

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Answer:

thanks you too for boys sweater in parallel and remember word on mangal I can do a few

Explanation:

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Answer:

Explanation:

The label that identifies a rarefaction in a longitudinal wave is B.

In a longitudinal wave, such as a wave in a spring, a rarefaction is an area where the particles of the medium are farther apart than they are in the rest of the wave. This is in contrast to a compression, which is an area where the particles of the medium are closer together than they are in the rest of the wave.

In the given illustration, the area where the rings are further apart is labeled B, so B is the label that identifies a rarefaction. The area where the rings are closer together, labeled A, is a compression. The height of the spring, labeled C, does not correspond to a rarefaction or a compression, and the distance between adjacent areas where the rings are closer together, labeled D, is not related to the concept of rarefactions or compressions.

Answer:

wavelength - C

rarefractions - B

compressions - A

Explanation:

correct on EDGE 2023

Answer:

Explanation:To describe a damped harmonic oscillator, add a velocity dependent term, bx, where b is the vicious damping coefficient.

Answer:

movement generates energy=heat so 50c should be it

Answer:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

Explanation:

Since a sound wave consists of a repeating pattern of high pressure moving through a medium it is sometimes referred to as a pressure wave

Answer:

A sound wave is a pattern of disturbance caused by the movement of energy.

Pressure Waves may refer to one of the two main types of elastic body waves , called seismic waves in seismology.

hope it helps !!~

Answer: 33 miles

Explanation: multiply 3x11 which equals 33

Answer: 33 miles

Explanation:

4.44×\(10^{9}\) kg/s is the rate at which the sun mass is decreasing.

The Sun radiates energy through a process called nuclear fusion, where hydrogen atoms combine to form helium, releasing a tremendous amount of energy in the process. According to Einstein's mass-energy equivalence principle (E=mc²), this energy release corresponds to a decrease in mass.

To calculate the rate at which the Sun's mass is decreasing, we can use the formula ΔE = Δmc², where ΔE is the change in energy, Δm is the change in mass, and c is the speed of light.

Given that the Sun radiates energy at a rate of 4×10^26 W, we can substitute this value into the equation as ΔE and solve for Δm.

ΔE = 4×10^26 W

c = 3×10^8 m/s (speed of light)

Using the equation ΔE = Δmc² and rearranging it, we get Δm = ΔE / c².

Substituting the values, we have:

Δm = (4×10^26 W) / (3×10^8 m/s)²

Evaluating this expression, we find that the rate at which the Sun's mass is decreasing is approximately 4.44×10^9 kg/s.

This calculation demonstrates that the Sun's mass is gradually decreasing as it continuously radiates energy into space, primarily through the process of nuclear fusion in its core.

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Answer:

In a third class lever, the effort is located between the load and the fulcrum. ... If the fulcrum is closer to the effort, then the load will move a greater distance. A pair of tweezers, swinging a baseball bat or using your arm to lift something are examples of third class levers.

Explanation:

Answer:

D

Explanation:

Direction of motion is positive right side

P = mv

P = m (final - initial)

P = 2 ( -1 - 3)

P = 8 Ns

(negative sign ignored)

I hope my answer helps you.

The impulse on the wall with a mass of the ball is 2 kg and the initial speed of wass 3 m/s and the final velocity is 1 m/s is 8 Ns. Hence, option D is correct.

Impulse equals the product of net force and changes in time. Impulse is also equal to the change in momentum. It is also defined as the force applied to an object with a short duration of time. The unit of impulse is Newton. seconds(Ns).

From the given,

mass of the ball (m) = 2kg

The initial speed of the ball (u) = 3m/s

the final speed of the ball (v) = -1 m/s.

Impulse (I) = Momentum (p)

Momentum (p) = mΔv

                         = m(v-u)

                         = 2(-1-3)

                         = 2(-4)

                         = -8.

Thus, the impulse on the wall is 8Ns.

Hence, the correct option is D.

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The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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This is an example of F = ma because the net force applied is directly proportional to the weight (mass) of the basket.

Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.

Mathematically, Newton's Second Law of Motion is given by this expression;

F = ma

Where:

In conclusion, the above scenario is an example of the demonstration of Newton's Second Law of Motion.

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The input to the power station is 5x10^9 W. This means that the power station requires an input of 5x10^9 watts to produce an electrical power output of 1.9x10^9 watts with an efficiency of 38%.

The efficiency of a power station is defined as the ratio of its output power to input power. Therefore, we can use the efficiency and the electrical power output of the power station to calculate its input power as follows:

Efficiency = Output power / Input power

Solving for input power, we get:

Input power = Output power / Efficiency

Substituting the given values, we get:

Input power = 1.9x10^9 W / 0.38

Input power = 5x10^9 W (to two significant figures)

The rest of the input power is lost as heat due to inefficiencies in the power generation process.

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Answer:

The bottom of the cup passes the sound waves to the string, and so on to the other cup. You can hear surprisingly far using a string telephone if help the right way! If the string is kept tight, the sound waves will travel.

Explanation:

Answer:

I HOPE THIS IS CLEAR

Explanation:

Sound waves are basically vibrations. This works as the vibrations from our mouth is gathered in our paper cup and is transferred through the string to the next paper cup. The person holding this cup in their ear receives the vibrations and hear the sound.

The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.

Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.

On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.

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Answer:

-384.22N

Explanation:

From Coulomb's law;

F= Kq1q2/r^2

Where;

K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2

q1 and q2 = magnitudes of the both charges

r= distance of separation

F= 9 ×10^9 × −7.97×10^−6 × 6.91×10^−6/(0.0359)^2

F= -495.65 × 10^-3/ 1.29 × 10^-3

F= -384.22N