a 7.00-kg mass is hung from the bottom end of a vertical spring fastened to an overhead beam. the object is set into vertical oscillations having a period of 2.60 seconds. what is the force constant of the spring?

A. The amount of work done by Georgie is 2304 J

B. The time taken for the 60 W light-bulb to glow is 38.4 s

The amount of work done by Georgie can be obtained as follow:

Work done (Wd) = force (F) × distance (d)

= 24 × 96

= 2304 J

Thus, the amount of work done by Georgie is 2304 J

The time required for the light bulb to glow can be obtain as follow:

Time = Work done / power

= 2304 / 60

= 38.4 s

Thus. the time required is 38.4 s

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Complete question:

Georgie was pulling her brother (of mass 26 kg) in a 9.4 kg sled with a constant force of 24 N for one block (96 m).

(A) How much work did Georgie do? Answer in units of J.

(B) How long would a 60 W lightbulb have to glow to produce the same amount of energy expended by Georgie? Answer in units of s.

Answer:

a.) L = 2.64 kgm^2/s

b.) V = 4.4 m/s

Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.

So,

Radius r = 0.6 m

Mass M = 2 kg

Velocity V = 1.1 m/s

Angular momentum L can be expressed as;

L = MVr

Substitute all the parameters into the formula

L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1

the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1

b. If she pulls her arms into 0.15 m,

New radius = 0.15 m

Using the same formula again

L = 2( MVr)

2.64 = 2( 2 × V × 0.15 )

1.32 = 0.3 V

V = 1.32/0.3

V = 4.4 m/s

Her new linear speed will be 4.4 m/s

If the two pucks, which have the same mass, are moving towards each other, the speed and direction of their movements can be used to calculate the final velocity of both pucks.The law of conservation of momentum states that the momentum of an isolated system remains constant if no external forces act on it.

The momentum before the collision is equal to the momentum after the collision in an isolated system.Considering the given values, if Puck 1 is moving to the left at 10 m/s and Puck 2 is moving to the right at 8 m/s, their velocities are opposite. Therefore, they are moving towards each other.When two pucks with the same mass collide, their velocities and momenta are conserved. If both pucks stick together after the collision, their final velocity can be calculated using the following equation:m1u1+m2u2=(m1+m2)vwhere m1, u1, m2, and u2 are the masses and initial velocities of the pucks, and v is their final velocity.

The final velocity of the combined pucks can be found by dividing the total momentum by their combined mass, which is given by:v = (m1u1 + m2u2) / (m1 + m2)In this case, the momentum of Puck 1 is:momentum1 = m x v1where v1 = -10 m/s (because Puck 1 is moving to the left)Similarly, the momentum of Puck 2 is:momentum2 = m x v2where v2 = 8 m/s (because Puck 2 is moving to the right)

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Answer:

Is radiation of sufficient energy to produce ions.

Is radiation of sufficient energy to remove electrons from atoms.

Explanation:

Ionization radiation is a radiation that travels at a high speed, and possesses sufficient speed to knock electrons off of an atom or a molecule, ionizing the atom. Ionization radiation can be made of travelling subatomic particles, or an electromagnetic wave with high energy, usually the types found at the end of the electromagnetic spectrum. Some subatomic particles that produce ionization are alpha particle, beta particles, and neutron. The electromagnetic waves with ionization abilities includes Gamma rays. -rays, and high energy ultraviolet rays.

Answer:

the correct answer is D

Explanation:

Answer: 13.9264J

Explanation: the formula for kinetic energy is ½ mv² so, we need to add our figures to the formula: ½ (17×1.28²) = 13.9264 J.

Answer:

VR = \(\frac{Radius of the wheel}{Radius of the axle}\)

Explanation:

Velocity ratio (VR) of a machine is a term that compares the distance moved by effort put into the machine to the distance moved by the load.

A wheel and axle is a device for lifting of a load through a height. It is made up of two circular parts called wheel and axle. Its velocity ratio (VR) can be determined by:

VR = \(\frac{Radius of the wheel}{Radius of the axle}\)

For a practical wheel and axle, the diameter of the wheel is greater than the diameter of the axle.

c) both direct and alternating current

Because Ampere's Law, a magnetic field is produced whenever an electrical charge is in motion. So, both kind of currents produces a magnetic field when electrical current is flowing through a wire.

Consider two blocks a and b. a is resting on top of b on top of a table. someone (your little brother) comes along and pushes the bottom block out to the left from under the top block. The friction force on the top block acts to the right. When someone (who could be the asker's little brother) pushes block B out to the left from under block A, the friction force on the top block acts to the right.

When an object moves over the surface of another object, the frictional force is the resistance it encounters. The amount of friction that develops between two objects is determined by a variety of factors, including the force pushing the objects together and the coefficient of friction between them. The frictional force always opposes the motion of the object. If you push a book across a table, for example, the frictional force will always act in the opposite direction to the book's motion, causing the book to slow down and eventually come to a halt.

The frictional force on the top block, Block A, acts to the right in this case. Since block B is pushed out from under block A, block A will begin to slide to the left. However, due to friction, there will be a force acting on the right side of block A, opposing the motion to the left, and helping it to maintain its position. Since friction opposes the motion of the object, it will always act in the opposite direction of the object's motion, in this case, to the right.

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Answer:

The correct answer is B.

The astronaut will know due to the light from the explosion.

Explanation:

Sound and vibrations require a medium such as air to travel through. Space, there is no air. Only a vacuum. So sound and vibrations are unable to travel. Light requires no medium to travel. It can go through a vacuum.  

Therefore the Astronaut will see a bright flash of light as it travels from the explosion to outer space. It is also important to note that light can travel very far because nothing else interacts with its wave particles and as such, it cannot be impeded.

Cheers!

Answer:

89km

Explanation:

Don't know how to explain without a pic.

Isooctane is the pure substance, while petrol is a mixture of different compounds.

Based on the given information, isooctane and petrol are being compared in terms of their boiling points. Isooctane, also known as 2,2,4-trimethylpentane, is a pure substance.

It is a hydrocarbon compound and is one of the primary components of gasoline (petrol).

Being a specific compound with a well-defined molecular structure, isooctane has a fixed boiling point, which in this case is stated as 99°C.

On the other hand, petrol refers to a mixture of various hydrocarbons, which can vary in composition depending on its source and the refining processes it undergoes.

Petrol is a complex mixture containing multiple compounds with different boiling points. The given range of boiling points, between 45°C and 95°C, suggests that petrol is composed of several components that vaporize at different temperatures.

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Answer:

Explanation:Potential Energy is the stored energy of an object given its position relative to a body. Gravitational potential energy is one type of potential energy and is equal to the product of the object's mass (m), the acceleration caused by gravity (g), and the object's height (h) as distance from the surface of the ground (the body).

mass m of 3 kilograms falling at gravity g of 9.81 meter per second squared from a height h of 5 meters. Solve for potential energy Pe with the equation PE equals m times g times h

In this example, a 3 kilogram mass, at a height of 5 meters, while acted on by Earth's gravity would have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.

9.81 meters per second squared (or more accurately 9.80665 m/s2) is widely accepted among scientists as a working average value for Earth's gravitational pull. This figure is based on a measure of gravity at sea level at a latitude of 45°.

At higher altitudes, gravity decreases slightly.

The effect of latitude on gravitational force is relevant as gravity increases with increasing distance from the Equator. At the Equator, the Earth's gravity is 9.780 m/s2 and at the poles it is 9.832 m/s2 (source: CRC Handbook of Chemistry and Physics).

Gravitational acceleration (to three significant figures) for other planets and bodies in the solar system is as follows:

 m/s2 gn*

Sun 274 27.9

Mercury 3.70 0.38

Venus 8.87 0.90

Earth 9.81 1.00

Moon 1.62 0.17

Mars 3.71 0.38

Jupiter 24.9 2.54

Saturn 10.44 1.06

Uranus 8.87 0.90

Neptune 11.15 1.14

Pluto 0.58 0.06

(table source: NASA)

*Standard gravity (gn). 1.00gn is equal to 9.80665 m/s2

The target heart rate zone is where you want your exercise heart rate to be. Option B is correct.

The target heart rate zone is a specific range of heart rates that you should aim to achieve during exercise to maximize the benefits of your workout. This range is typically calculated based on a percentage of your maximum heart rate. For example, if your maximum heart rate is 180 beats per minute, your target heart rate zone might be between 120 and 150 beats per minute.

The objective pulse is 50 to 85 percent of your greatest pulse. It is the level at which your heart is pulsating with moderate to extreme focus. To decide your greatest pulse, take 220 and deduct your age. Supporting an exercise at this speed works on cardiorespiratory perseverance.

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The required energy the bell has at the top of a tower, when the height of the bell and mass of the bell are given is calculated to be  17.6 kJ.

The energy in the above case is nothing but the gravitational potential energy.

Gravitational potential energy = m × g × h

where,

m is mass

h is height

g is gravity

Entering the values in the above equation, we have,

P.E = m × g × h = 40 × 9.8 × 45 = 17640 J = 17.6 kJ

Thus, the required energy the bell has at the top of the tower is calculated to be 17.6 kJ.

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Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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The path of the light gets changed and the change in the path of light is obtained from the reflection and refraction process

Light is electromagnetic radiation and travels in space without any medium. It possesses dual nature. The wave nature of light is reflection, refraction, and interference.

The path of light gets changes through the process of reflection and refraction. The incident right after hitting the transparent objects, the light ray moves in the opposite direction. The bouncing back of the light is called Reflection.

When light rays enter from the rarer to denser medium or denser to rarer medium, the path of light gets changed and the speed of the light decreases. This process is called refraction.

The path of light gets changed by using transparent objects like mirrors, lenses, and prism.

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Phase conductors 6 awg and smaller are not permitted to be re-identified as equipment ground conductors using green paint, tape, or other effective means.

Depending on the type of system offered, the grounded conductor of a service is typically a neutral conductor, though it can also be a phase conductor. A grounded phase conductor and no grounded neutral conductor are present in a corner-grounded delta system, for instance. The unbalanced load is returned to the source by the neutral. The conductor that has been purposefully grounded is the grounded conductor. The neutral is the conductor that is purposefully grounded in the majority of wiring systems used in industrial facilities, businesses, and homes. For safety reasons, the grounding conductor is employed. The grounding wire does not carry current under typical circumstances. The grounding wire offers a low resistance channel for the current in a fault situation.

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Answer:

Forces have magnitude and direction.

Explanation:

Force is a vector quantity.

Answer:

490N

Explanation:

W=m×g

W=50×9.8=490N

Answer: a. 126.21secs

b. 12.621 meters.

Explanation:

Given data:

Speed of tortoise = 0.1m/s.

Speed of hare = 2m/s.

Solution:

a. Distance traveled = Speed* Time

Speed of tortoise = 0.1 m/s

Speed of hare = 20*0.1 m/s = 2 m/s

2 minutes = 2* 60 s = 120 s

Let the time taken for the race be t seconds.

• Distance moved by tortoise

= (0.1 /s)* (t s)

= 0.1*t meter

•Hare has run for a time of (t - 120)s.

distance moved by hare

= Speed * Time

= (2 m/s)*(t- 120)s

= (2t - 240) meter.

Since hare is 20 cm (0.2 m) behind the tortoise, therefore

(0.1*t - 0.2) meter

= (2t - 240) meter

0.1*t - 0.2 = 2t - 240

Collect like terms

239.8 = 1.9t

Divide both sides by 1.9

t = 126.21secs

The race lasted for 126.21secs

b. Length of race

= Distance moved by tortoise

= 0.1*126.21 meter

= 12.621 meter

The length of the race is 12.621 meters.

Answer:

All black holes contain singularities, however not all singularities involve black holes. A neutron star may be dense, matter the size of a pinhead can weigh as much as the earth, but there seems to be a mathematical cut-off point beyond which a black hole is formed.

Answer:

1.Latitude forms an inverse relationship with temperature, where regions at lower latitudes have higher temperatures compared to areas at higher latitudes. The lower the latitude, the warmer the region becomes. Conversely, the higher the latitude, the colder the area becomes.

2.Latitude and longitude make up the grid system that helps humans identify absolute, or exact, locations on the Earth's surface. There is a relationship between latitude and temperature around the world, as temperatures are typically warmer approaching the Equator and cooler approaching the Poles.

A) Q1 = (3/2)P1V1[A – 1]

B) W2 = P1V1(In A)

C) W3 = P1V1(1 – A)

The only source of energy for a monatomic ideal gas (such as helium, neon, or argon) is translational kinetic energy.

A) first law of thermodynamics we have;

ΔU = Q – W

Where,

ΔU = change in internal energy

Q = the heat absorbed

W = the work done

the first process occurs at constant volume, the work done is zero:

Thus,

ΔU = Q – 0

ΔU = Q

The change in internal energy is;

ΔU = nCvΔt

where;

n = number of moles of the gas

R =  gas constant,

Cv =  specific heat at constant volume

Δt = change in temperature i.e T2 – T1.

Using the ideal gas law, find an n and Δt

P1V1 = nRT1

n = P1V1/RT1

T1 = P1V1/nR

the specific heat at constant volume is Cv = (3/2)R

From the question, pressure has reached AP1, calculate the temperature T2 by using the ideal gas law;

AP1V1 = nRT2

T2 = AP1 V1/ nR

heat added in terms of p1, V1, and A

Q = ΔU = nCv(T2 – T1)

From earlier

T1 = P1V1/nR

Putting equation of T2 and T1 into the energy equation;

Q = nCv((AP1 V1/ nR) – P1V1/nR)

Q = Cv • P1V1/R (A – 1)

we saw that Cv = (3/2)R. Thus,

Q = (3/2)R • P1V1/R (A – 1)

Q = (3/2)P1V1[A – 1]

B) Here again, work done in step 2 in terms of p1, V1, and A.

The process is an isothermal process because temperature is constant; so work done W = nRT In(V2/V1)

T = T1  (temperature is constant)

From earlier,

n = P1V1/RT1 and

But in this process, it’s

n = P1V1/RT1 and thus,

V2 = nRT2/P1

Also,  T2 = AP1 V1/ nR

V1 = nRT2/AP1

Putting the values into, W = nRT In(V2/V1),

W = (P1V1/RT1) • RT1 • In((nRT2/P1)/(nRT2/AP1)

W = P1V1(In A)

C) In step 3,we have and isobaric process because the pressure is constant.

Work done; W = P(V1 – V2)

V2 is the final volume while V1 is the the initial volume

P is P1 (isobaric process).

From earlier, we saw that,

V1 = nRT2/AP1 and V2 = nRT2/P1

And that T2 = AP1 V1/ nR

Thus,

V1 = V1 and V2 = AV1

Thus, W = P1(V1 – AV1) = P1V1(1 – A)

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I understand that the question you are looking for is "A monatomic ideal gas has pressure p1 and temperature T1. It is contained in a cylinder of volume V1 with a movable piston, so that it can do work on the outside world. Consider the following three-step transformation of the gas: The gas is heated at constant volume until the pressure reaches Ap1 (where A>1). The gas is then expanded at constant temperature until the pressure returns to p1. The gas is then cooled at constant pressure until the volume has returned to V1.

It may be helpful to sketch this process on the pVplane.

How much heat Q1 is added to the gas during step 1 of the process?

Express the heat added in terms of p1, V1, and A.

How much work W2 is done by the gas during step 2?

Express the work done in terms of p1, V1, and A.

How much work W3 is done by the gas during step 3?

If you've drawn a graph of the process, you won't need to calculate an integral to answer this question.

Express the work done in terms of p1, V1, and A."

Answer:

True

Explanation:

For an electric circuit to flow you must have a closed circuit

An electrical circuit that has a complete path for electrons to travel through it is said to be closed. Electrons move through a conductive material, like a wire, in a closed circuit from a power source's negative terminal to the positive terminal and back again. Electric current, which is made up of this electron movement, can be used to carry out tasks like powering an incandescent lightbulb.

The electrons have a continuous path from the negative terminal to the positive terminal and back in a complete circuit. The conductive substance, the power supply, and any additional circuit elements like resistors, switches, or lightbulbs are all included in this path.

As long as the circuit is closed, which means there are no interruptions in the path obstructing the passage of electrons, the flow of electrons will continue.

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