Answer:
The new speed of the ball is 176.43 m/s
Explanation:
Given;
mass of the ball, m = 7 kg
initial speed of the ball, u = 5 m/s
applied force, F = 300 N
time of force action on the ball, t = 4 s
Apply Newton's second law of motion;
\(F = ma = \frac{m(v-u)}{t}\\\\m(v-u) = Ft\\\\v-u = \frac{Ft}{m}\\\\v = \frac{Ft}{m} + u\)
where;
v is new speed of the ball
\(v = \frac{Ft}{m} + u\\\\v =\frac{300*4}{7} + 5\\\\v = 176.43 \ m/s\)
Therefore, the new speed of the ball is 176.43 m/s
When light goes straight through a medium that means it has been
Question 8 options:
absorbed
reflected
transmitted
Answer:
Reflected
Explanation:
During the process of reflection whatever that is sent forth e.g light comes back (reflects)
Answer:
transmitted
Explanation:
took quiz
7. A 1000-kg car comes to a stop without skidding. The car's brakes do 50,000 J of work
to stop the car. Which of the following was the car's velocity when the brakes were
initially applied?
Answer:
10 m/s
Explanation:
Please explain the different ways offense can score and how many points each way is worth? Answer in complete sentences.
Answer:
what sport bruh
Explanation:
Answer:
in wat sport exactly
Explanation:
in eat sport
PLS ANSWERR THIS QUESTION FOR ME !!
Explanation:
20 joule is your answer
Answer:
here
mass m =100kg
distance d=50m
acceleration due to gravity a =10m/s²
work =force×displacement
= ma/d=100×10/50=20joule
Two forces of
411
N and
617
N act on an object. The angle between the forces is
46°.
Find the magnitude of the resultant and the angle that it makes
with the larger force.
Let's first resolve the two forces into their components as shown in the diagram below: The larger force (617 N) makes an angle of 46° with the horizontal axis.
Therefore, the horizontal component will be given by:
H = 617 cos 46°H = 617 × 0.69H = 425.73 N
The vertical component will be given by:V = 617 sin 46°V = 617 × 0.73V = 450.66 NOn the other hand, the smaller force (411 N) makes an angle of (90° - 46°) = 44° with the horizontal axis. Therefore, the horizontal component will be given by:H = 411 cos 44°H = 411 × 0.72H
= 296.52 N
The vertical component will be given by:V = 411 sin 44°V = 411 × 0.67V = 274.47 N The resultant horizontal component, R will be given by:R = 425.73 + 296.52R = 722.25 N The resultant vertical component, R will be given by:R = 450.66 + 274.47R = 725.13 N The magnitude of the resultant, R will be given by:R² = (722.25)² + (725.13)²R = √(522198.06)R = 722.82 N The angle that R makes with the larger force (617 N) will be given by:θ = tan⁻¹(725.13/722.25)θ = 45.23° Therefore, the magnitude of the resultant is 722.82 N and it makes an angle of 45.23° with the larger force.
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A calorie is defined as the amount of energy needed to raise the temperature of one gram of water one degree centigrade. True.
Answer:
True
Explanation:
A battery operating a large flashlight produces a current of 2 amperes in a light bulb that has a resistance of 4 ohms. The voltage of the battery is
a. 0.5 volts.
b. 2 volts.
c. 8 volts.
d. none of the above.
A battery operating a large flashlight produces a current of 2 amperes in a light bulb that has a resistance of 4 ohms. The voltage of the battery is option c) 8 volts.
To determine the voltage of the battery, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R), i.e.,
V = I × R.
In this case, the current is given as 2 amperes and the resistance is given as 4 ohms. Plugging these values into Ohm's Law, we have V = 2 A × 4 \(\Omega\) = 8 volts.
Therefore, the correct answer is c) 8 volts.
The voltage of a battery represents the electric potential difference it provides to the circuit. In this scenario, the battery is operating the flashlight, and the light bulb acts as the resistance in the circuit.
The current flowing through the bulb is determined by the battery's voltage and the resistance. With a current of 2 amperes and a resistance of 4 ohms, the voltage required to sustain this current is 8 volts.
It's important to note that the voltage of the battery is not solely dependent on the current or the resistance. It is the combination of these factors that determines the voltage required to drive the desired current through the circuit.
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If the mass of a box is 200 Kg, with what net force would you use to make the box accelerate 2.4 m/s 2 ?
Answer:
The net force used on the box was 480 N
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = ma
Where a is the acceleration of the object.
The mass of a box is m=200 kg and it's accelerated at a=2.4\ m/s^2 by a net force whose magnitude is:
F = 200 * 2.4 N
F = 480 N
The net force used on the box was 480 N
A vehicle travels for 20 minutes at a speed of 60 km/h. It then travels for 10 minutes at 90 km/h. At
the end of 30 minutes, it covers a distance of Select... v km.
Answer:
120km
Explanation:
it will covered 120km
which wave carries the highest energy?
Answer:
Gamma rays
Explanation:
John accidentally drops his keys off the balcony at his apartment. John's friend Tony just happens to walk by at that moment and picks up the keys to throw them back up to John. If John is 5.33 meters above the sidewalk where Tony is, and Tony throws at 18 m/s at a 40 degree angle above the horizontal, will the keys make it back to John?
Answer:
the keys will make it back to John.
Explanation:
In order to find out if the keys will reach John or not, we can use the formula of projectile motion to find the maximum height reached by the keys:
H = V²Sin²θ/2g
where,
V = Launch Speed = 18 m/s
θ = Launch Angle = 40°
g = 9.8 m/s²
Therefore,
H = (18 m/s)²[Sin 40°]²/(2)(9.8 m/s²)
H = 6.83 m
Hence, the maximum height that can be reached by the projectile or the keys is greater than the height of John's Balcony(5.33 m).
Therefore, the keys will make it back to John.
Yes, Key will surely reach back to John.
Given that;
Velocity v = 18 m/s
θ Angle = 40°
g = 9.8 m/s²
Computation:
By using maximum height formula
H = [v²][sin²θ]/2g
H = (18)²[Sin 40°]²/[(2)(9.8)]
H = 6.83 m
6.83 meter is more then 5.33 meter,
So,
Key will surely reach back to John.
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A stone at rest is dropped from a cliff, and the stone hits the ground after a time of 3 s. What is the stone's velocity when it hits the ground? O
2.94 m/s
3.3 m/s
323 m/s
29.4 m/s
Answer:
The stone is accelerating at 9.8 m/s². If we multiply that by three seconds, we get 29.4 m/s.
a charge is placed 33 cm away from another charge. the charges are both 1.2 x 10^-5 coulombs. what is the force on each other
1.44*10^-3N is the force on each other. when 33 centimeters separates one charge from another charge. They both have charges of 1.2 x 10-5 coulombs.
Charge on the first sphere, q 1 =1.2 x 10^-5 C
Charge on the second sphere, q 2 =1.2 x 10^-5 C
Distance between the spheres, r=30cm=0.3m
F= 4πε
q 1 q 2/ r2
Where, ε 0
= Permittivity of free space 4πε 0
=9×10^9Nm2
F= (0.33) 2
1.2 x 10^-5 * 1.2 x 10^-5 C = 1.44*10^-3N
Hence, force between the two small charged spheres is 1.44*10^-3N.
The charges are of same nature. Hence, force between them will be repulsive.
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What is the mass of an object that has a potential energy of 57J and is 10m above the ground?
Kinetic energy is exchanged when _____ happens?
A) Drip
B) Conversation
C) Contact
D) Boredom
calculate the equilibrium constant at 25°c for a reaction for which \deltaδδg° = -4.22 kcal/mol.
The equilibrium constant (K) at 25°C for the given reaction is approximately 0.000850.
To calculate the equilibrium constant (K) at 25°C for a reaction given the standard Gibbs free energy change (∆G°), we can use the following relationship: ∆G° = -RT ln(K)
Where: ∆G° is the standard Gibbs free energy change (in this case, ∆G° = -4.22 kcal/mol)
R is the gas constant (R = 1.987 cal/(mol·K) or 8.314 J/(mol·K))
T is the temperature in Kelvin (25°C = 298.15 K)
Converting the units of ∆G° to cal/mol: ∆G° = -4.22 kcal/mol × 1000 cal/kcal = -4220 cal/mol
Plugging in the values into the equation: -4220 cal/mol = - (1.987 cal/(mol·K)) × (298.15 K) × ln(K)
Simplifying the equation: ln(K) = (-4220 cal/mol) / [(1.987 cal/(mol·K)) × (298.15 K)]
ln(K) = -7.083
Taking the exponential of both sides to solve for K: K = e^(-7.083)
Calculating the value of K: K ≈ 0.000850
Therefore, the equilibrium constant (K) at 25°C for the given reaction is approximately 0.000850.
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Examine the charge distribution shown a) What will the net force be on a third charge of q3 = -5.0x10-5C , placed at point Z? b) What will the total electric potential energy be if a third charge of q3 = -5.0x10-5C is placed at point Z?
Part A. We are asked to determine the force exerted on a charge placed on point Z. To do that we will use the fact that charges with the same sign will attract each other and charges with a different sign will repel each other. Therefore, we can construct the following free body diagram:
Since q3 and q2 are both negative they repel each other and since q1 is positive this means that q3 and q1 will attract each other.
To determine the magnitude of the forces we will use Coulomb's law:
\(F=k\frac{q_1q_2}{r^2}\)Where:
\(\begin{gathered} k=\text{ Coulomb's constant} \\ r=\text{ distance between the charges} \\ q_1,q_2=\text{ magnitude of the charges} \end{gathered}\)For the force between q1 and q3 we have:
\(F_1=k\frac{q_1q_3}{r_1^2}\)For the force between q3 and q2 we have:
\(F_2=k\frac{q_2q_3}{r_2^2}\)Now, the net force is the difference between F2 and F1 since the force act in different directions, therefore, we have:
\(F=F_2-F_1\)we have taken the left direction to be negative and the right direction to be positive. Now, we substitute Coulomb's law:
\(F=k\frac{q_2q_3}{r_2^2}-k\frac{q_1q_3}{r_1^2}\)We can take "kq3" as a common factor:
\(F=kq_3(\frac{q_2}{r_2^2}-\frac{q_1}{r_1^2})\)The distance from q1 to q3 is:
\(r_1=4m+3m=7m\)The distance from q2 and q3 is:
\(r_2=3m\)Now, we substitute the values:
\(F=(9\times10^9\frac{Nm^2}{C^2})(5\times10^{-5}C)(\frac{4\times10^{-5}C}{(3m)^2}-\frac{4\times10^{-5}C}{(7m)^2})\)Solving the operations:
Solving the operations:
\(F=1.63N\)Therefore, the net force is 1.63 Newtons to the right.
Part B. To calculate the electric potential energy we will use the following formula:
\(U=k\frac{q_1q_2}{r}\)To determine the total energy we add the energy for both pairs of charges, like this:
\(U=k\frac{q_1q_3}{r_1}+k\frac{q_2q_3}{r_2}\)We can take "kq3" as a common factor:
\(U=kq_3(\frac{q_1}{r_1}+\frac{q_2}{r_2})\)Now, we substitute the values:
\(U=(9\times10^9\frac{Nm^2}{C^2})(-5\times10^{-5}C)(\frac{4\times10^{-5}C}{7m}+\frac{-4\times10^{-5}C}{3m})\)Solving the operations we get
\(U=3.42J\)Therefore, the energy is 3.42 Joules.
Which of the following fields of science has more scientific theories and fewer scientific laws?
biology
chemistry
engineering
physics
Answer:
Explanation:
Newton's first law of motion.
Newton's second law of motion.
Newton's law of universal gravitation.
Law of conservation of mass.
Law of conservation of energy.
Law of conservation of momentum
Answer:The answer is A: Biology :)
Explanation:I got it right.
The siren of a fire engine that is driving northward at 31.0 m/s emits a sound of frequency 2160 Hz. A truck in front of this fire engine is moving northward at 19.0 m/s.
A. What is the frequency of the siren's sound that the fire engine's driver hears reflected from the back of the truck (Hz)?
B. What wavelength would this driver measure for these reflected sound waves (m)?
(a) The frequency of the siren's sound that the fire engine's driver hears reflected from the back of the truck is 2243.9Hz.
(b) The wavelength of the reflected sound waves by the listener is 0.143 m.
We use the principle of Doppler's effect to find the results.
What is the Doppler's effect?The Doppler's effect is a phenomenon when the source of a wave and an observer move relative to each other, the frequency heard is not the same with the actual frequency.
The equation of the Doppler's effect is
f₀ = (v + v₀) fs / (v + vs)
Where
f₀ = observer frequency of soundv = speed of sound waves (340 m/s)v₀ = observer velocityvs = source velocityfs = actual frequency of sound wavesNote:
v₀ (-) if it moves away from the sound source.vs (-) if it moves closer to the observer.There are a truck and a fire engine emitting a siren sound moving in the same direction.
The actual frequency, fs = 2160 Hz.The fire engine velocity (source), vs = 31.0 m/s.The truck velocity (observer), v₀ = 19.0 m/s.Determine the frequency and the wavelength of the sound waves heard by the listener in the front!
We have the truck is in front of the fire engine. So, the sound source moves closer and the observer moves away. Then, frequency of the sound waves heard by the observer is
f₀ = (v - v₀)/(v - vs) × fs
f₀ = (340 - 19.0)/(340 - 31) × 2160
f₀ = (321/309) × 2160
f₀ = 2243.9 Hz
The wavelength of the sound waves heard by the observer is
λ₀ = (v - v₀) / f₀
λ₀ = (340 - 19) / 2243.9
λ₀ = 321 / 2243.9
λ₀ = 0.1430545
λ₀ = 0.143 m
Hence,
(a) The observer frequency of sound is 2243.9Hz.
(b) The wavelength of the reflected sound waves by the observer is 0.143 m.
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moment of inertia of an object does not depend on a. angular velocity b. mass distribution
Answer:
Explanation:
The moment of inertia of an object is a property that describes its resistance to rotational motion.
It is determined solely by the mass distribution of the object and the geometry of its shape, and it does not depend on the angular velocity of the object.
This can be seen from the formula for the moment of inertia, which is given by:I = ∫ r^2 dmwhere I is the moment of inertia, r is the distance from the axis of rotation to the mass element dm, and the integral is taken over the entire mass distribution of the object.
The moment of inertia depends only on the mass distribution of the object and how that mass is distributed around the axis of rotation.
This means that even if the object is rotating at different speeds or in different directions, its moment of inertia will remain the same, as long as the mass distribution is unchanged.
two people part company and walk along perpendicular paths. one person walks 1 km/h faster than the other. they are 6 km apart after one hour. we need to find the rate at which each person walks.
The rate at which each person walks is 3.71 km/h and 4.71km/h.
Let's call the rate of speed of the slower person "r" (in km/h). Then the rate of the faster person is "r + 1" km/h.
We know that after one hour, the distance between them is 6 km. This means that the slower person has traveled a distance of "r" km, and the faster person has traveled a distance of "r + 1" km. Since they are walking along perpendicular paths, these distances form the legs of a right triangle, with the distance between them forming the hypotenuse:
r² + (r + 1)² = 6²
Simplifying the left side:
r² + r² + 2r + 1 = 36
Combining like terms:
2r² + 2r - 35 = 0
Using the quadratic formula:
r = (-2 ± √(2^2 - 4(2)(-35))) / (2(2))
r = (-2 ± √(284)) / 4
r ≈ 3.71 km/h or r ≈ -4.71 km/h
We can ignore the negative value since the rate should be positive. So, the slower person walks at a rate of approximately 3.71 km/h, and the faster person walks at a rate of approximately 4.71 km/h (since the faster person walks 1 km/h faster than the slower person).
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if you could dig a hole several kilometers deep the temperature would get colder or warmer?
Answer:
The temperature would get warmer.
Explanation:
It indicates heat from earth’s warm interior surface. The temperature increases for about 25℃ for every single kilometer of depth.
Answer:
Warmer is the answer think
Help me!
1) Identify the correct figure
2)Justify your answer
Someone help me extra points & brainlest
Answer:
75 m
Explanation:
Urgent please!!!!!!!!!!!!!!!!!!!!!!
A program can only create one object of each class.
A. True
B. False
How are objects identified and categorized in space;
list Three(3)
Explanation:
There are several methods to identify and categorize objects in space but the 3 important are:
•Mass/Size
•Revolution
•Gravity
Example:
If you look at the planet Mars you will identify it by many methods but the basic way to indentify it is by looking at it's gravitational pull, Mass and size of the planet and the revolution of the planet around the star.
You can also identify them by looking at their elements present in it (like mars is red due to presence of high amount of iron/red soil in it), and Like Saturn is mostly identified by it's rings. It's not always about planets but it's also about the asteroids, stars, Natural satterlites of planets (like moon) and more.
Hope this helps you
Have a nice day :)
1.Write the Schrodinger equation and general solution. What is the meaning of them? 2.Solve the Schrodinger equation when electron travels in potentials of below two cases. 3. Discuss the tunneling.
1. The Schrödinger equation is a fundamental equation in quantum mechanics that describes the behavior of particles. The general solution represents the wave function of a particle and provides information about its position and momentum.
3.Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically.
1. The Schrödinger equation is a partial differential equation that was developed by Erwin Schrödinger in 1925 as a mathematical formulation of quantum mechanics. It describes how the wave function of a particle evolves over time. The equation takes the form:
Ĥψ = Eψ
Where Ĥ is the Hamiltonian operator, ψ is the wave function, E is the energy of the particle, and Ĥψ represents the operation of the Hamiltonian on the wave function.
The general solution to the Schrödinger equation represents the wave function of a particle. The wave function provides information about the probability distribution of the particle's position and momentum. It contains both real and imaginary components and is typically represented as a complex-valued function.
The wave function, ψ, can be written as a product of a spatial part and a temporal part:
ψ(x, t) = Ψ(x) * Φ(t)
The spatial part, Ψ(x), represents the probability amplitude of finding the particle at position x, while the temporal part, Φ(t), describes how the wave function evolves over time.
The Schrödinger equation and its general solution are essential tools in quantum mechanics, as they allow us to predict the behavior of particles on a microscopic scale. By solving the equation, we can determine the wave function of a particle and calculate probabilities associated with its position and momentum.
2.Case 1: Particle in a Box
In the case of a particle confined to a one-dimensional box, the potential energy is zero within the box and infinite outside of it. This situation can be represented by the following potential function:
V(x) = 0, 0 < x < L
V(x) = ∞, x ≤ 0 or x ≥ L
To solve the Schrödinger equation for this case, we need to find the wave function (Ψ) and the corresponding energy levels (E). The general form of the wave function inside the box is given by:
Ψ(x) = A * sin(kx)
Where A is a normalization constant, and k = (2π/L).
Applying the boundary conditions, we find that the wave function must go to zero at both ends of the box (x = 0 and x = L). This leads to the quantization of the wave vector k:
k = nπ/L, where n = 1, 2, 3, ...
The corresponding energy levels are given by:
E = (ħ²π²/2mL²) * n²
Where ħ is the reduced Planck's constant and m is the mass of the particle.
Case 2: Harmonic Oscillator
In the case of a particle in a harmonic oscillator potential, the potential energy can be described by:
V(x) = (1/2)kx²
Where k is the spring constant. To solve the Schrödinger equation for this potential, we use the harmonic oscillator equation:
- (ħ²/2m) * (d²Ψ/dx²) + (1/2)kx²Ψ = EΨ
The solutions to this equation are given by Hermite polynomials, and the corresponding energy levels are quantized. The wave function for the harmonic oscillator potential can be expressed as a product of a Gaussian function and a Hermite polynomial:
Ψ(x) = (A/π)\(^{(1/4)\) * exp(-αx²/2) * Hₙ(√αx)
Where A is a normalization constant, α = (√(mk/ħ)), and Hₙ is the Hermite polynomial of degree n.
The energy levels in the harmonic oscillator potential are given by:
E = (n + 1/2)ħω
Where n = 0, 1, 2, ... and ω = (√(k/m)) is the angular frequency of the oscillator.
These solutions provide insights into the behavior of electrons traveling in these potential systems, including the quantization of energy levels and the spatial distribution of the wave functions.
3. Tunneling is a phenomenon in quantum mechanics where a particle can pass through a potential barrier even though it does not have enough energy to overcome the barrier classically. This effect arises from the wave nature of particles, as described by the Schrödinger equation.
Tunneling has important implications in various areas of physics, such as nuclear fusion, quantum computing, and scanning tunneling microscopy. It allows for phenomena such as alpha decay, where alpha particles escape from atomic nuclei, and the operation of tunneling diodes in electronic devices.
Overall, tunneling is a fascinating quantum mechanical phenomenon that challenges our classical intuition and plays a crucial role in understanding the behavior of particles in the presence of potential barriers.
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difference between the fertility rate and mortality rate of developed and least development countries
3/3 points.
Answer:
The replacement fertility rate is indeed only slightly above 2.0 births per woman for most industrialized countries (2.075 in the UK, for example), but ranges from 2.5 to 3.3 in developing countries because of higher mortality rates, especially child mortality. pls give brainlest
The free-fall acceleration on the moon is 1.62 m/s2
m
/
s
2
. What is the length of a pendulum whose period on the moon matches the period of a 1.70-m-long pendulum on the earth?
Name two offensive strategies that can be utilized in the game of baseball