A 5 kg box is lying at rest on a frictionless surface. If you push it with a constant net force of 10 N, how far will it travel over the first 4 s

Answer:

\(0.4x40 \div 0.2 = 80\)

8N

Explanation:

A parasitic plant with yellow, slender and branched stem is called Cuscuta (Amarbel).

hope this helps you.

The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s

Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s

Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.

The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.

Let us first calculate the time by using the formula

h = ut + 1/2gt²

Where

Substitute all the necessary parameters into the formula

52 = 0 + 1/2 × 9.8 × t²

52 = 4.9t²

t² = 52/4.9

t² = 10.6

t = √10.6

t = 3.26 s

The speed at which the rock was initially kicked can be found by

R = Ut

35 = U × 3.26

U = 35/3.26

U = 10.7 m/s

Therefore, rock was initially kicked at a speed of 10.7 m/s

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Answer:

7.8% of the original volume.

Explanation:

From the given information:

Temperature \(T_1\) = 22° C = 273 + 22 = 295° C

Pressure \(P_1\) = 240 kPa

Temperature \(T_2\) = 45° C

At initial temperature and pressure:

Using the ideal gas equation:

\(P_1V_1 =nRT_1\)

making V_1 (initial volume) the subject:

\(V_1 = \dfrac{nRT_1}{P_1}\)

\(V_1 = \dfrac{nR*295}{240}\)

Provided the pressure maintained its rate at 240 kPa, when the temperature reached 45° C, then:

the final volume \(V_2\) can be computed as:

\(V_2 = \dfrac{nR*318}{240}\)

Now, the change in the volume ΔV =  V₂ - V₁

\(\Delta V = \dfrac{nR*318}{240}- \dfrac{nR*295}{240}\)

\(\Delta V = \dfrac{23nR}{240}\)

∴

The required fraction of the volume of air to keep up the pressure at (240) kPa can be computed as:

\(= \dfrac{\dfrac{23nR}{240}}{ \dfrac{295nR}{240}}\)

\(= {\dfrac{23nR}{240}} \times { \dfrac{240}{295nR}}\)

\(= 0.078\)

= 7.8% of the original volume.

Proxima Centauri otherwise known as Alpha Centauri C, is the closest star to our solar system, located about 4.24 light-years away. It was discovered in 1915 by Robert Innes, the director of the Union Observatory in South Africa. Innes identified Proxima Centauri as a possible member of the Alpha Centauri system after noticing that the star had a similar proper motion to Alpha Centauri A and B.

Proxima Centauri was first observed through telescopes, which allowed scientists to study the star's spectra and estimate its distance from Earth. In the following decades, scientists continued to study Proxima Centauri through telescopes, including the Hubble Space Telescope, which provided high-resolution images of the star.

In 2016, the European Southern Observatory announced the discovery of an exoplanet orbiting Proxima Centauri, called Proxima Centauri b. This discovery was made using the radial velocity method, which measures the star's small wobbles caused by the gravitational pull of an orbiting planet.

Despite the advances in our understanding of Proxima Centauri, no spacecraft have ever reached this star. The distance between Proxima Centauri and Earth is so vast that it would take tens of thousands of years to reach the star using current propulsion technology.

One potential solution to this problem is the use of interstellar travel, which would allow humans to travel to Proxima Centauri within a human lifetime. There are several proposed methods for interstellar travel, including using a starship propelled by fusion engines or a massive light sail pushed by a beam of lasers. However, these technologies are still in the theoretical stage and have not yet been developed.

There are also many other challenges that must be overcome in order for humans to travel to Proxima Centauri. For example, humans would need to find a way to protect themselves from the high levels of radiation that they would be exposed to during the journey. They would also need to find a way to provide enough food, water, and other resources to sustain themselves for the duration of the trip.

Overall, while it is theoretically possible for humans to travel to Proxima Centauri, it would be a massive undertaking that would require significant technological advancements and the development of new solutions to many challenges.

Sources of Works Cited include:

"Proxima Centauri." Wikipedia, Wikimedia Foundation, 5 Jan. 2021,

"Proxima Centauri b." Wikipedia, Wikimedia Foundation, 20 Nov. 2020,

"Interstellar Travel." Wikipedia, Wikimedia Foundation, 4 Jan. 2021,

Therefore, the correct answer is as given above

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Answer:

0.114 kg or 114 g

Explanation:

From the diagram attaches,

Taking the moment about the fulcrum,

sum of clockwise moment = sum of anticlockwise moment.

Wd = W'd'

Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.

make W'  the subject of the equation

W' = Wd/d'................ Equation 1

Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm

Substitute these values into equation 1

W' = 0.5047(23.2)/10.5

W' = 1.115 N.

But,

m' = W'/g

m' = 1.115/9.8

m' = 0.114 kg

m' = 114 g

The best explanation of the energy in the circuit is, the energy in the battery was transformed into electrical energy, light energy, and heat energy.

option A is the correct answer

The law of conservation of energy states that the total energy of an isolated system remains constant, that is the total energy of the isolated system is said to be conserved over time.

According to the law of conservation of energy, energy can neither be created nor destroyed but can be converted from one form to another.

For instance, electrical energy can be converted into heat and light energy, mechanical energy can be converted into electrical energy, and vice versa, chemical energy can be converted into light and heat energy.

Thus, when she finds that the battery no longer has a charge, the best explanation of the energy in the circuit would be the energy in the battery was transformed into electrical energy, light energy, and heat energy.

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Answer:

Explanation:

It's A I got this question wrong twice and I got it correct when I clicked A. Hope this helps!

Answer:

Velocity

Explanation:

Velocity equals the original velocity... Plus

the acceleration is multiplied by time.

If the acceleration is multiplied by time then we get velocity as a result, therefore velocity has the same unit.

Pressure is measured as the amount of force applied in the one-meter of area. Pascal is used as the SI unit of it. The amount of pressure can be calculated by dividing the amount of force by the area of force applied. In relation to atmospheric pressure, the pressure is measured. Pressure does not represent any direction, so it comes under a scalar quantity. Many scientific and day-to-day life equipment use pressure principles like gauge meter thermometers in designing cars, ships, and every mechanical part.

We know that acceleration has an SI unit of m /\(s^{2}\) So if we multiply the time with an acceleration whose unit is second we will get m / s which is the unit of velocity.

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Answer:

Explanation:

In this experiment, a block and tackle system was created using two broomsticks, a rope, and two helpers. The rope was tied to one broomstick and wrapped around the other, creating a simple pulley system. When the free end of the rope was pulled, the helpers resisted and the broomsticks did not move.

Next, the rope was woven back over the first broomstick, creating a double pulley. Pulling on the free end of the rope resulted in the broomsticks moving closer together. This demonstrated the mechanical advantage of the block and tackle system.

By adding more loops of rope over the broomsticks, the mechanical advantage was increased further. The force applied to the rope was spread out over a greater distance, resulting in less force required to move the broomsticks.

In summary, the block and tackle system increases mechanical advantage by spreading out the force applied over a greater distance. This is achieved through the use of pulleys and loops of rope, allowing a smaller force to move a larger load.

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

The displacement of the iguana between 3 s and 6 s  is 6.71 meters.

The distance traveled by the iguana between 3 s and 6 s is  8.08 meters.

Distance is the sum of an object's movements, regardless of direction.

The term "displacement" refers to a shift in an object's position.

According to the graph:

The displacement of the iguana between 3 s and 6 s

= √{ (3-6)²+(6-0)²} meters

= 6.71 meters.

The distance traveled by the iguana between 3 s and 6 s

= [ √{ (3-5)²+(6-6)²} +√{ (5-6)²+(6-0)²}] meters

= [2+ 6.08] meters

= 8.08 meters.

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Use the work-energy theorem: the total work done on the 0.80 kg block by the spring to make it come to a stop is equal to the change in the block's kinetic energy.

If we take the block's initial direction of motion to be positive, then the spring does negative work on the block, and

-1/2 k (0.11 m)² = 0 - 1/2 (0.80 kg) (2.2 m/s)²

Solve for the spring constant k :

k = (1/2 (0.80 kg) (2.2 m/s)²) / (1/2 (0.11 m)²) = 320 N/m

We can use the same equation as above to find the distance the 1.40 kg block would travel as it is slowed down by the same spring:

-1/2 (320 N/m) x ² = 0 - 1/2 (1.40 kg) (3.0 m/s)²

Solve for the displacement x :

x = √((1/2 (1.40 kg) (3.0 m/s)²) / (1/2 (320 N/m))) ≈ 0.20 m

Answer:

Explanation:

The difference between step-up and step-down transformer is given below:-

Step-up transformer  

i) It increases the voltage.

ii) It decreases the current strength.

iii) It has a greater number of turns in secondary as compared to the primary.

iv) The wire of primary is thicker than that of the secondary coil.

Step-down transformer

i) It decreases the voltage.

ii) It increases the current strength of the secondary.

iii) It has less number of turns in secondary as compared to the primary.

iv) The wire of the secondary coil is thicker than that of the primary coil.

Explanation:

First find current inorder to get guantity of

charge, current =volts /resistance

After getting current ( I) we take the formula which say current =quantity of charge / unit of time

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:

Theano is considered by some to be the first known woman mathematician. Based on the works that have survived, it is thought that she worked on The Golden Mean and The Golden Rectangle. While her exact life story remains unknown, she is believed to be either the student or wife of Pythagoras, and sometimes both.

True

Answer: False

Explanation: It's a software

ANSWER:

-1.88 cm

STEP-BY-STEP EXPLANATION:

The situation would be the following:

Given:

Object distance (u): -3 cm

Focal distance (f): -5 cm

Using the lens formula, we calculate the distance of the image:

The image distance is -1.88 cm

Answer:

Explanation:

yfdyrdrd

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.

What is Potential Energy?

Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.

The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:

GPE = mgh

Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.

Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:

GPE = mgh

GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)

GPE = 15,998.95 J (joules)

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The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

The polynomial relationship between position and time for the bowling ball is linear.

A linear relationship between two variables is a term used to describe a straight-line relationship between the two variables.

Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b.

From the equation of linear relationship between two variable, the highest power of x is one.

The given equation for position and time;

x(t) = vot + xo

From this given equation, the highest power of t is one, hence it is called linear relationship.

Thus, the polynomial relationship between position and time for the bowling ball is linear.

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Answer:

C

Explanation:

Check for coordinates of the VT graph in C part. The information matches with the table.

Answer:

A

Explanation:

If the object is moving at a constant speed, the object isn't accelerating as the velocity doesn't change.

Answer: C.

Explanation:  plato users

Answer: -0.10m/s

Explanation:

khan academy

Answer:

Answer is (b) Mercury, venus and Mars.

Explanation:

i think b is correct!!

;-) :-) :-) :-)

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Explanation:

Answer:

- the effective lift area for the aircraft is 8.30 m²

- the required engine thrust is 1275 N

- required power is 79.7 kW

Explanation:

Given the data in the question;

Speed V = 225 km/hr = 62.5 m/s

The lift coefficient CL = 0.45

drag coefficient CD = 0.065

mass = 900 kg

g = 9.81 m/s²

a)  the effective lift area for the aircraft

we know that for a steady level flight, weight = lift and thrust = drag

Using the equation for the lift force

F\(_L\) = C\(_L\)\(\frac{1}{2}\)ρV²A = W

we substitute

0.45 × \(\frac{1}{2}\) × 1.21 × ( 62.5 )² × A = ( 900 × 9.81 )

1081.05 × A = 8829

A = 8829 / 1081.05

A = 8.30 m²

Therefore, the effective lift area for the aircraft is 8.30 m²

b) the required engine thrust and power to maintain level flight.

we use the expression for drag force

F\(_D\) = T = C\(_D\)\(\frac{1}{2}\)ρV²A

we substitute

= 0.065 × \(\frac{1}{2}\) × 1.21 × ( 62.5 )² × 8.30

T = 1275 N

Since drag and thrust force are the same,

Therefore, the required engine thrust is 1275 N

Power required;

P = TV

p = 1275 × 62.5

p = 79687.5 W

p = ( 79687.5 / 1000 )kW

p = 79.7 kW

Therefore, required power is 79.7 kW

The distance between two objects of radius 6 cm and 2 cm is zero

To find the distance between two objects with radii of 6 cm and 2 cm, we need to consider the center-to-center distance between the objects and subtract the sum of their radii.

Let's denote the radii of the objects as r1 = 6 cm and r2 = 2 cm.

The distance between the centers of the objects can be represented as d = r1 + r2. Adding the radii ensures that we account for the space occupied by both objects.

Substituting the values, we have d = 6 cm + 2 cm = 8 cm.

Now, to find the actual distance between the objects, we subtract the sum of their radii from the center-to-center distance:

Distance = d - (r1 + r2) = 8 cm - (6 cm + 2 cm) = 8 cm - 8 cm = 0 cm.

The resulting distance is 0 cm, indicating that the objects are in direct contact with each other. This means that their surfaces are touching. When the distance between two objects is zero, it implies that they are overlapping or in physical contact. In this case, since the distance is equal to 0 cm, the two objects are touching each other, with their surfaces coming into contact.

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