a 5-gram particle mass carries a charge of 5 x 10-6 c and is moving in an electric field of 100 v/m. what is the acceleration of the particle? (note on units for electric field: v/m

Answers

Answer 1

The accelaration of the particle is given as 0.1 m/sec^2.

What is Electric Charge and Electric Field ?

An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field.

When put in an electric and magnetic field, a subatomic particle's electric charge leads it to experience force. Protons and electrons are the most prevalent charge carriers for the positive and negative forms of electric charges, respectively.

Force experienced by the particle in the field is

F = Eq = 5 * 10^-6 * 100 = 5 * 10^-4 N

Now we know

F = ma

or, a = F/m = 5 * 10^-4/5 * 10^-3 = .1 m/sec^2

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Related Questions

A motor bike is sitting at the start line. It reaches a speed of 90m/s in 10 seconds. Calculate its acceleration.

Answers

Answer:

9m/s^2

Explanation:

a= dv/dt, 90m/s-0m/s/10s-0s=9m/s^2

Jared is experimenting with a force that is attractive only and the weakest of the fundamental forces. He is experimenting with which force?

electromagnetic
strong
gravitational
weak

Answers

Answer is gravitational !

Answer:

C. gravitational

Explanation:

Took  the test!

L= 1 H and R = 3.9 KQ. V (w) Vi (w) b) Sketch the magnitude of the frequency response function H(w). c) Determine what type of ideal filter is approximated by this circuit. a) Find H (w) = + vi(t) L R + vo(t)

Answers

The circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. To find the frequency response function H(w) for the given circuit, we need to determine the transfer function H(w) = V0(w) / Vi(w), where V0(w) is the output voltage and Vi(w) is the input voltage in the frequency domain.

L = 1 H (inductance)

R = 3.9 KΩ (resistance)

The circuit can be represented by the following equation:

H(w) = (jwL + R) / (jwL + R + 1)

To sketch the magnitude of the frequency response function H(w), we need to plot the magnitude |H(w)| as a function of frequency w.

Taking the magnitude of the transfer function, we have:

|H(w)| = |(jwL + R) / (jwL + R + 1)|

Next, let's analyze the type of ideal filter approximated by this circuit. We can examine the transfer function to determine the filter characteristics.

From the transfer function:

H(w) = (jwL + R) / (jwL + R + 1)

As w approaches infinity, the jwL term dominates the transfer function, and the transfer function becomes:

H(w) ≈ jwL / jwL = 1

This indicates that the circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. It allows low-frequency signals to pass through relatively unattenuated while attenuating high-frequency signals.

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What type of boundary is depicted in the image below?
a.
transform
b.
collisional
C.
convergent
d.
divergent

What type of boundary is depicted in the image below?a.transformb.collisionalC.convergentd.divergent

Answers

I think it’s C or D But im not sure

What seems to happen to the force of interaction between the charged tape and charged rod as the distance between them decreases?

Answers

As the distance between charged tape and charged rod decreases, the force of interaction between them increases.

The force of interaction between the charged tape and charged rod is governed by Coulomb's Law.

This law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

So, as the distance between the charged tape and charged rod decreases, the force of interaction increases.

This is because the charges on the objects are now closer to each other, allowing for a stronger attraction or repulsion, depending on the nature of the charges (like charges repel, opposite charges attract).

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In the apparatus shown above, one end of a string of length L is attached to a block of mass M and the other end is connected to the axle of a motor that rotates, causing the block to move in a circle of radius R at a constant speed vT such that the string makes an angle θ with the vertical. A student wants to use the apparatus to make measurements and create a graph that can be used to estimate the acceleration g due to gravity at the surface of Earth. The student can adjust the motor to achieve different tangential speeds of the block

Answers

Newton's second law allows finding the result for the type of graph to find the gravity acceleration  is:

The student must make a graph of the tangential velocity versus the tangent of the angle and of the slope to find the value of gravity.

                     g = \(\frac{slope}{\sqrt{L} }\)

Oscillatory motion is a simple harmonic motion where the restoring force is proportional to the displacement.

Newton's second law gives a relationship between the net force, the mass and the acceleration of a body, in the attached we can see a free body diagram of the system, let's apply Newton's second law.

                 \(t_y - W =0 \\T_x = m a\)

Since the movement is circular, the acceleration is centripetal.

                \(a = \frac{v^2}{r}\)

Let's substitute.

               \(t_x = m \frac{v^2}{r}\)  

Let's use trigonometry to find the radius of the circle and the stress component.

              sin θ = \(\frac{r}{L}\)  

              r = L sin  θ

             sin θ =  \(\frac{T_x}{T}\)  

             cos θ = \(\frac{T_y}{T}\)  

             Tₓ = T sin θ

             \(T_y\) = T cos θ

Let's substitute.

            T sin θ = \(\frac{m v^2 }{L sin \theta }\)  

            T sin² θ = \(\frac{m}{L} \ v^2\)  

From the other equation.

             \(T_y= W \\T cos \theta = m g\)  

Let's write our system of equations.

            T sin² θ  = \(\frac{m}{L} \ v^2\)  

            T cos θ = m g

We solve the system by squaring the second equation and dividing.

             tan² θ = \(\frac{1}{g^2 L } \ v^2\)  

             L g² tan² θ = v²

             

             v = g \(\sqrt{L}\)  tan θ

Consequently, if the student makes a graph of the velocity versus the tangent of the angle, he obtains a straight line and the slope is:

             slope = g \(\sqrt{L}\)

From this expression you can calculate the acceleration of gravity.

              \(g= \frac{slope}{\sqrt{L} }\)  

In conclusion using Newton's second law we can find the result for the type of graph to find the gravity acceleration  is:

The student must make a graph of the tangential velocity versus the tangent of the angle and of the slope to find the value of gravity.

                 \(g = \frac{slope}{\sqrt{L} }\)  

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In the apparatus shown above, one end of a string of length L is attached to a block of mass M and the

How many centimeters are there in 2.35m?

Answers

Answer:

there are 235cm in 2.35m

who has a iphone (age range 15-19 )

Answers

Hi friend! I have an iPhone. why do you ask????

A truck has a momentum of 5,000 units. What happens to the truck's momentum if the mass is cut in half?

Answers

If the truck is moving with the same velocity, if the mass is cut in half then the momentum of the truck will also reduce to half.

What is momentum?

The momentum of a body can be described as the function of the object's mass and velocity. Momentum (p) can be determined as kinetic energy and is the product of velocity (v) and mass (m).

The momentum of an object can be determined from the mathematical formula:

p = m×v

The momentum of an object is conserved and can be equal to zero if the object is stationary and its velocity of an object is zero.

Given, the truck has a momentum, p = 5000 units

Given that the mass of the truck is reduced to half. Then the new mass of the truck is equal m/2.  If the truck is still moving with the same velocity then the momentum is equal to:

p' = m' ×v

p' = (m/2) ×v

p' = mv/2

p' = p/2

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An object is moving along a straight line at a
constant speed of 20 m/s. How far did the object
travel during the first 4 seconds?
A. 5 m
B. 20 m
C. 40 m
D. 80 m

Answers

The answer for this question is 5 m

If an object is moving along a straight line at a constant speed of 20 meters/second, then the object travels 80 meters during the first four seconds.

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem we have to find out the distance traveled in the first four seconds when If an object is moving along a straight line at a constant speed of 20 meters/second,

The total distance traveled by the object = speed of the object×time

                                                                    =20 meters/second×4 seconds

                                                                    =80 meters

Thus, the correct answer is option D.

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What changes occurred with the introduction of iron during the Iron Age?

Answers

The introduction of iron during the Iron Age brought significant changes to human society, including advancements in tools and weapons, agricultural practices, trade, and social structure.

The introduction of iron during the Iron Age marked a significant shift in human technological development. Iron, being harder and more durable than its predecessor, bronze, led to advancements in tools and weapons.

Iron tools were stronger and could be shaped more easily, allowing for improved agricultural practices and increased productivity. This, in turn, contributed to the growth of civilizations as they were able to produce more food and support larger populations.

Iron also had a profound impact on warfare. Iron weapons, such as swords, spears, and armor, revolutionized military tactics and strategies. They provided greater cutting power and resilience, enabling armies to conquer new territories and establish empires.

The availability of iron also led to the rise of professional warriors and the development of specialized military units.Furthermore, the introduction of iron had significant economic implications.

Iron became a valuable commodity, driving trade and creating new economic opportunities. Iron mines and smelting operations became important centers of production and trade, leading to the growth of urban settlements.

The increased demand for iron also stimulated technological advancements in metalworking and metallurgy.In addition to its technological and economic impact, iron played a crucial role in shaping social structures during the Iron Age.

The production and control of iron were often concentrated in the hands of skilled craftsmen and elites, leading to the emergence of social hierarchies.

Access to iron resources and ironworking skills became markers of power and status, influencing social and political dynamics within communities and societies.

In summary, the introduction of iron during the Iron Age brought about significant changes in tools and weapons, agriculture, trade, and social structure.

Its superior properties and increased availability had far-reaching effects on human civilization, shaping the course of history during this era.

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A cell has a 7.0-nm-thick membrane with a total membrane area of 6.0\times10^{-9}\;{\rm m^2}. Note: the dielectric constant is 9. Part A Q: We can model the cell as a capacitor, as we have seen. What is the magnitude of the charge on each "plate" when the membrane is at its resting potential of -70 {\rm mV}? A: Q= _C (Note 5.3*10^-13C is not the answer) Part B Q: How many sodium ions does this charge correspond to? A: N= _sodium ions

Answers

A. The magnitude of the charge on each plate is 5.4×10⁻¹⁹C.

B. The charge on the membrane corresponds to 3.4 sodium ions.

Part A:

The capacitance of the cell membrane can be calculated using the formula:

C = εA/d

where ε is the dielectric constant, A is the area of the membrane, and d is the thickness of the membrane. Plugging in the given values, we get:

C = (9)(6.0×10⁻⁹ m²)/(7.0×10⁻⁹ m) = 7.7×10⁻¹⁸ F

The charge on each "plate" can then be calculated using the formula:

Q = CV

where V is the voltage across the membrane, which is -70 mV or -0.07 V. Plugging in the values, we get:

Q = (7.7×10^⁻¹⁸ F)(-0.07 V) = 5.4×10⁻¹⁹ C

Therefore, the magnitude of the charge on each "plate" is 5.4×10⁻¹⁹ C.

Part B:

The charge on each "plate" corresponds to the number of sodium ions that have crossed the membrane, since sodium ions carry a positive charge. The charge of one sodium ion is +1.6×10^-19 C. Dividing the total charge on the membrane by the charge of one sodium ion, we get:

N = (5.4×10⁻¹⁹ C)/(1.6×10⁻¹⁹ C/ion) = 3.4 sodium ions

Therefore, the charge on the membrane corresponds to 3.4 sodium ions.

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An object of mass m moves at a constant speed v in a circular path of radius r. The force required to produce the centripetal component of acceleration is called the centripetal force and is given by F = mv2/r. Newton's Law of Universal Gravitation is given by F = GMm/d?, where d is the distance between the centers of the two bodies of masses M and m, and G is a gravitational constant. The speed required for circular motion is v = V GM/r. Use the result above to find the speed necessary for the given circular orbit around Earth.

Answers

speed required for the predetermined elliptical trajectory of the planet is 7908m/s

The speed necessary for the given circular orbit around Earth is given as follows;v = V GM/r.Here is the solution; Given formula:v = V GM/r.We know that the mass of the earth is 5.77 x \(10^(24)\) kg and the radius of the orbit is 6.38 x\(10^6\)m.

The gravitational constant is 6.67 x \(10^-11 m^3/(kg s^2).\)We can now substitute the values into the equation to get the speed:v = V GM/r = V (6.67 ×\(10^( 11)\) Nm²/kg²) (5.97 × \(10^{24}\)kg)/ (6.38  m) = 7908 m/s. Therefore, the speed necessary for the given circular orbit around Earth is 7908 m/s.

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A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a complete circle of radius R. The perpendicular axis through the ring is a z axis, with the origin at the centre of the ring. What is the magnitude of the electric field due to the rod. In terms of R, at nitude maximum?

Answers

The magnitude of the electric field due to the bent rod at the maximum on the z-axis is given by (kQ) / (4πε0 \(R^2)^{ (3/2)}\), where Q is R is the circle's radius, and C is the total charge on the rod.

To find the electric field at a point on the z-axis due to the charged ring, we can use the formula for the electric field due to a uniformly charged ring:

\(E = (kQz) / (R^2 + z^2)^{(3/2)}\)

where k is Coulomb's constant, Q is the total charge on the ring, R is the radius of the ring, and z is the distance of the point on the z-axis from the centre of the ring.

Since the ring has a uniform charge distribution, we can express the total charge on the ring Q in terms of the linear charge density λ, which is defined as the charge per unit length:

Q = λ * 2πR

where 2πR is the ring's circumference.

To find the maximum electric field on the z-axis, we need to find the distance z from the centre of the ring where the denominator of the above equation is minimized. This occurs when z = R, so we can substitute z = R in the equation and simplify:

\(E_{MAX}\) = (kλR) / (4πε0\(R^2)^{(3/2)}\)

where 0 represents the free space permittivity.

We can simplify the expression further by substituting the expression for λ in terms of Q:

λ = Q / (2πR)

\(E_{MAX}\) = (kQ) / (4πε0\(R^2)^{ (3/2)}\)

Therefore, the magnitude of the electric field due to the bent rod at the maximum on the z-axis is given by (kQ) / (4πε0 \(R^2)^{ (3/2)}\), where Q is R is the circle's radius, and C is the total charge on the rod.

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how much work does an elevator motor do to lift a 1300 kg elevator a height of 200 m ?

Answers

The work done by the elevator motor to lift the elevator is given by:

W = mgh

where m is the mass of the elevator, g is the acceleration due to gravity, and h is the height the elevator is lifted.

Plugging in the given values, we get:

W = (1300 kg) x (9.81 \(m/s^2\)) x (200 m) = 2.54 x \(10^6 J\)

Therefore, the elevator motor does 2.54 x \(10^6\) Joules of work to lift the 1300 kg elevator a height of 200 m.

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Hello everyone, I just want to know the formula to solve this problem:

What is the speed of sound at 62°C?

and how to solve this kind of problem? My brain isn't working.. :)​

Answers

Answer:

367 m/s

Explanation:

Use simplified formula:

\(v=331.3\sqrt{1+T/273.15}\) , where T- temperature in Celsius

A solid disk is rolling without slipping on a level surface at a constant speed of 2.50 m/s. (a) if the disk rolls up a 30.0o ramp, how far along the ramp will it move before it stops? (b) explain why your answer in part (a) does not depend on either the mass or the radius of the disk.

Answers

(a) By using the law of conservation of energy, the distance moved by the solid disk along the ramp is 0.96 m.

(b) The answer does not depend on the mass and radius of the disc as these values are canceled when the law of conservation of energy is applied.

What is the law of conservation of energy?

The law of conservation of energy states that the total energy of an isolated system is conserved.

The total initial energy Ei of the disc rolling down an inclined plane is given by the formula,

Ei=1/2*mv^2 + 1/2*Iω^2

where m is the mass of the disc, v is the velocity of the disc, I is the moment of inertia and ω is the angular velocity of the disc.

For a solid disc, I=1/2mr^2, and since it is rolling without slipping, the rolling velocity of the disc will be equal to its translational velocity, that is,

v=ωr or ω=v/r

So using ω=v/r and I=1/2mr^2, it can be written,

Ei=1/2*m(v)^2 + 1/2*(1/2mr^2)(v/r)^2

Ei=1/2*m(v)^2*(1+1/2*)

Ei=3/4*mv^2

If the height covered by the disc is h before stopping, then its final total  energy Ef will be equal to the potential energy, that is,

Ef=m*g*h

From the law of conservation of energy, it can be written,

Ei=Ef

3/4*mv^2=m*g*h

h=3v^2/(4g)

The length of the ramp is then given by the formula,

l=hcosecθ

where θ is the inclination angle. So

l= 3v^2/(4g)*cosecθ

Here g=9.8 m/s^2, v=2.5 m/s  and θ=30.0 degree. Using these values,

l= 3*(2.5 )^2/(4*9.8)*cosec( 30)

l= 0.96 m

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find the molecular formula of the following​

find the molecular formula of the following

Answers

Answer: hello i am a hacker

Explanation:

magnesium sulphate=(24*1)+(32*1)+(16*4)=120                                                             water=H2O=(1*2)+(1*16)=18                                                                                                        carbon dioxide=CO2=(12*1)+(16*2)=44                                                                                     ammonia=NH3=(14*1)+(1*3)=17                                                                                                   alminiumsulphate=AL2(SO4)3=(26*2)+(32*3)+(12*16)=340                                                          hydrogen peroxide=H2O2=(1*2)+(16*2)=34                                                              zinc sulphate=ZNSO4=(65*1)+(32*1)+(16*4)=161

         

besides mars, exobiologists find europa also a good candidate for life. (True or False)

Answers

True. Exobiologists believe that Europa, one of Jupiter's moons, is a good candidate for life beyond Earth. Europa is unique in that it has a subsurface ocean of liquid water underneath its icy surface. This ocean is heated by tidal forces from Jupiter, creating hydrothermal vents and potential habitats for microbial life.

Additionally, Europa's ice crust could protect any potential life from harmful radiation. In recent years, NASA has sent several missions to explore Europa, including the Europa Clipper mission planned for launch in the 2020s. This mission will conduct multiple flybys of the moon and use a suite of scientific instruments to study its ice shell, subsurface ocean, and potential habitability. Overall, while Mars remains a primary focus for astrobiology research, Europa presents a promising target for the search for life beyond our planet.

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A pring of force contant 120 N/m i acted up by a contant force of 240n. Calculate the elatic potential tored in the pring

Answers

A spring of force constant 120 N/m acted up by a constant force of 240N. Then, the elastic potential energy stored in the spring is 240 Nm.

The elastic potential energy stored in the spring is formulated as follows

                                                 PE = ½kx²

Where PE is the elastic potential energy, x is the displacement of the spring from its equilibrium position, and k is the spring force constant.

In this question, the spring force constant is 120 N/m, and the constant force acting on the spring is 240 N. To find the spring displacement, we can use the formula:

F = kx

Where F is the force acting on the spring, x is the displacement, and k is the force constant,

So that:

F = kx

240 N = 120 N/m . x

x = 240 N/120 N/m

x = 2 m

Once x is known, then we can calculate the potential energy of the spring:

PE = ½kx²

PE = ½ (120) (2²)

PE = 60 x 40

PE = 240 Nm

So, the elastic potential energy stored in the spring is 240 Nm.

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A repelling force must occur between two charged objects under which conditions?.

Answers

Answer:

charges of like signs

Explanation:

calculate the wavelength (in m) of a 650.00 hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s.

Answers

The wavelength of a 650.00 Hz sound in air at room temperature and pressure, where the velocity of sound is 344 m/s, is approximately 0.529 m.

What is the wavelength of a 650.00 Hz sound in air at room temperature and pressure?

Sound waves travel through a medium by creating compressions and rarefactions. The wavelength of a sound wave is the distance between two consecutive points that are in phase, such as two compressions or two rarefactions. To calculate the wavelength, we can use the formula: wavelength = velocity of sound / frequency.

In this case, the frequency of the sound is 650.00 Hz, and the velocity of sound in air at room temperature and pressure is 344 m/s. Plugging these values into the formula, we get: wavelength = 344 m/s / 650.00 Hz = 0.529 m.

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If a non-rotating object has no acceleration, then we can say for certain that it is A) in mechanical equilibrium. B) moving at constant non-zero velocity. C) at rest. D) all of the above E)none of the above

Answers

(A)  in mechanical equilibrium is correct option, as there is no net force acting on it. A non-rotating object that has no acceleration can be said to be in mechanical equilibrium.

What is the definition of mechanical equilibrium?

Mechanical Balance When all forces acting on an object of interest are equal to zero, mechanical equilibrium has occurred. The balance of all the forces must exist for this to occur.

What distinguishes mechanical equilibrium from static equilibrium?

A reversible reaction is in a stable state called dynamic equilibrium when the rate of the forward reaction equals the rate of the backward reaction. The reaction has come to an end when there is static equilibrium, sometimes referred to as mechanical equilibrium. Or to put it another way, the system is idle.

Can mechanical equilibrium exist for an object in motion?

When an object's acceleration is equal to zero, it is said to be in mechanical equilibrium. The object is either at rest with no change in position over time or it is traveling at a constant pace in this state. The net force acting on the object is equal to zero since the acceleration is zero.

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pleasee answer asapp!!

A train on a straight track goes in the positive direction for 6.7 km, and then backs up for 3.0 km. What is the distance covered by the train?

A. 3.7km
B. 0km
C. 6.7km
D. 9.7km​

Answers

I think it’s 3.7km
3.7km coz when u minus 6.7 and 3.0 u get 3.7 km

Para el siguiente conjunto de medidas, calcule EL ERROR RELATIVO PORCENTUAL: 1.34 m, 1.35 m, 1.37 m y 1.36 m

Answers

Answer:

Ver explicacion abajo

Explanation:

En este caso para poder calcular el error relativo porcentual, es necesario calcular primero el error absoluto, que se calcula de la siguiente forma:

Error absoluto = Resultado exacto - aproximación

Sin embargo, no tenemos el resultado exacto de las medidas, pero podriamos conocerlo tomando el promedio de estas medidas y este es el que tomaremos como el verdadero resultado de las medidas:

Promedio de medidas = 1.34 + 1.35 + 1.37 + 1.36 / 4

Promedio de medidas = 1.355 m

Ya que tenemos el promedio, podemos calcular el error absoluto de cada medida y luego el error relativo porcentual:

Ea1 = 1.355 - 1.34 = 0.015

Ea2 = 1.355 - 1.35 = 0.005

Ea3 = 1.37 - 1.355 = 0.015

Ea4 = 1.36 - 1.355 = 0.005

Ya que tenemos los 4 errores absolutos, es posible calcular el porcentual:

%error relativo = (Error absoluto / resultado exacto) * 100

Aplicando la expresión con cada uno de los valores tenemos:

%Er1 = (0.015/1.34) * 100 = 1.12%

%Er2 = (0.005/1.35) * 100 = 0.37%

%Er3 = (0.015/1.37) * 100 = 1.09%

%Er4 = (0.005/1.36) * 100 = 0.37%

Espero que te sirva.

A worker pushes a 50kg box on a level floor at constant velocity and moves a distance of 10 m.
a.) If the person pushes it with a force of 850N, what must be the magnitude and the direction of the frictional force on the surface?
b.) How much work is done on the box (1) by the worker and (2) by friction?
c.) How much work is done by the (1) normal force and (2) by gravity?
d.) What is the total work done on the box?

Pls pakisagutan po ng MAAYOS.

Answers

867 Newton  must be the magnitude and the direction of the frictional force  will be opposite to the surface.

F=µN

µ=F/N

µ=50×10÷50×9.8

µ=1.02

f=µF

f=1.02×850N

f=867 N

IIn mechanics, a force is any action that attempts to sustain, modify, or deform a body's motion. It is common practice to utilize Isaac Newton's three laws of motion to illustrate the idea of force in his Principia Mathematica (1687).

Newton's first law states that in the absence of an external force, a body will continue to be in either its resting or equally moving condition along a straight path. According to the second law, when an outside force applies on a body, the body accelerates (changes velocity) in the force's direction.

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How do grasshoppers smell?.

Answers

The grasshoppers smell on the antennae.

Grasshoppers sense contact through organs located in different parts of the body such as antennae and apply on the head serti on the abdomen and receptors on the legs. The gustatory organs are located in the mouth and the olfactory organs are located in the antennae. Grasshoppers have such powerful leaping legs that people sometimes don't realize they also have wings.

While locusts use their jumping ability to gain momentum in the air most grasshoppers have fairly powerful flight abilities and make good use of their wings to evade predators. Locusts are non-venomous and pose no danger to humans. But they have strong jaws! It may be temporarily painful. Most grasshoppers mean rubbing their hind legs against their forewings. Special vertebrae on the inside of the hind legs act like a kind of percussion instrument when in contact with the thickened edges of the wings.

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what was the important discovery that physicists michael faraday and joseph henry made at about the same time

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Physicists Michael Faraday and Joseph Henry made important discoveries in the field of electromagnetism at about the same time during the early 19th century.

They both independently discovered electromagnetic induction, which is the principle behind the operation of electric generators and transformers.

Electromagnetic induction refers to the process of generating an electric current in a conductor by varying the magnetic field around it.

Faraday and Henry separately demonstrated that a changing magnetic field induces an electric current in a nearby conductor.

Faraday's experiments and discoveries in the 1830s laid the foundation for the concept of electromagnetic induction.

He demonstrated that by moving a magnet in and out of a coil of wire, he could generate an electric current in the wire. Faraday's work also led to the development of the first electric generator.

Around the same time, Joseph Henry, an American physicist, independently discovered electromagnetic induction and made similar observations.

He demonstrated that passing an electric current through a coil of wire produced a magnetic field and that stopping or varying the current induced an electric current in a neighboring coil.

Both Faraday and Henry's discoveries were crucial in establishing the relationship between electricity and magnetism and laid the groundwork for the development of electrical technology and power generation.

Their work formed the basis of modern electromagnetism and had significant implications for the advancement of physics and engineering.

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The components of vector A are Ax = + 3.90 and Ay = -4.00. What is the angle measured counterclockwise from the +x-axis to vector A?

Answers

Answer: \(314.28^{\circ}\)

Explanation:

Given

X component of the vector is \(A_x=3.9\)

Y component of the vector is \(A_y=-4\)

From the figure, we can write

\(\Rightarrow \tan x=\dfrac{4}{3.9}\\\\\Rightarrow x=45.72^{\circ}\)

Thus, the angle measured counterclockwise from the x-axis to vector A is

\(360^{\circ}-45.72^{\circ}=314.28^{\circ}\)

The components of vector A are Ax = + 3.90 and Ay = -4.00. What is the angle measured counterclockwise

An electron moving at 4.10 ✕ 103 m/s in a 1.45 T magnetic field experiences a magnetic force of 1.40 ✕ 10−16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers between 0° and 180°. ° (smaller value) ° (larger value)

Answers

ANSWER

\(8.46\degree;\text{ }171.54\operatorname{\degree}\)

EXPLANATION

Parameters given:

Speed of electron, v = 4.10 * 10^3 m/s

Magnetic field, B = 1.45 T

Magnetic force, F = 1.40 * 10^(-16) N

To find the angle that the velocity of the electron makes with the magnetic field, apply the formula for magnetic force:

\(F=qvB\sin\theta\)

where θ = angle

q = electric charge = 1.6 * 10^(-19) C

Make θ the subject of the formula:

\(\begin{gathered} \sin\theta=\frac{F}{qvB} \\ \\ \theta=\sin^{-1}(\frac{F}{qvB}) \end{gathered}\)

Therefore, the angle that the velocity makes is:

\(\begin{gathered} \theta=\sin^{-1}(\frac{1.4*10^{-16}}{1.6*10^{-19}*4.1*10^3*1.45}) \\ \\ \theta=\sin^{-1}(0.1472) \\ \\ \theta=8.46\degree \end{gathered}\)

To find the second angle, subtract the angle from 180 degrees:

\(\begin{gathered} 180-8.46 \\ \\ 171.54\degree \end{gathered}\)

The angles are:

\(8.46\operatorname{\degree};\text{ }171.54\operatorname{\degree}\)

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