A 25 kg box is being pulled at a constant velocity with a tension force of 65 N. what is the coefficient of friction between the box and the ground?

Answers

Answer 1

The box is in equilibrium, so Newton's second law says

n + (-w) = 0

65 N + (-f ) = 0

where n denotes the magnitude of the normal force, w denotes the weight of the box, and f denotes the magnitude of the friction force.

The box has a weight of

w = (25 kg) (9.80 m/s²) = 245 N

so n = 245 N, too.

The friction force has magnitude

f = 65 N

and is proportional to the normal force by a factor of µ, the coefficient of kinetic friction. So we have

65 N = µ (245 N)   →  µ ≈ 0.26


Related Questions

What do you know about energy and Newton's laws? (5 pts)
What do you wonder about energy and Newton's laws? (5 pts)

Answers

Force is applied to change the kinetic energy of an object.

What is the relationship between energy and Newton's laws?

Energy is closely related to Newton's laws of motion, which describe the behavior of objects in motion.

For instance, the first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity, unless acted upon by an external force.

This law is related to energy because an object in motion has kinetic energy, which is the energy associated with its motion. In order to change the motion of an object, an external force must be applied, which can change the object's kinetic energy.

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An average eardrum has an area of about 5. 0x10-5m2. What is the force in newtons exerted on an eardrum if you are at the bottom of a water-filled pool that is 2. 9 meters deep? (hint: take all pressures into account)

Answers

The force exerted on the eardrum at the bottom of a 2.9m deep water-filled pool is approximately 1.4 x 10^-3 N, taking into account the pressure of the water and the atmosphere.

The pressure at the bottom of the water-filled pool can be calculated using the formula P = rho * g * h, where rho is the density of water (1000 kg/m^3), g is the acceleration due to gravity (9.81 m/s^2), and h is the depth of the pool (2.9 m). Thus, P = (1000 kg/m^3) * (9.81 m/s^2) * (2.9 m) = 28410 Pa. The total force exerted on the eardrum is then the product of pressure and area: F = P * A = (28410 Pa) * (5.0 x 10^-5 m^2) = 1.4 x 10^-3 N. This force takes into account the pressure of the water as well as the atmospheric pressure.

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1. The energy an object has while it is moving is called kinetic energy, or the energy of
A)traction
B)friction
C)magnetism
D)motion

Answers

Answer:

D

Explanation:

I hope this helps :)

Let me know if you want a full explanation

The energy an object has while it is moving is called kinetic energy, or the energy of motion. Thus, the correct option for this question is D.

What do you mean by Kinetic energy?

Kinetic energy may be defined as a type of energy that an object possesses due to its motion. It is defined as the work that is required in order to accelerate a body of a given mass from rest to its stated velocity. It is also known as the energy that is possessed by an object by the virtue of its motion.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles. Any object in motion is using kinetic energy: a person walking, a thrown baseball, a crumb falling from a table, and a charged particle in an electric field are all examples of kinetic energy at work.

Therefore, the energy an object has while it is moving is called kinetic energy, or the energy of motion. Thus, the correct option for this question is D.

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I need to find out number 51.Can you help me ?

I need to find out number 51.Can you help me ?

Answers

v= constant

mass of the cart = 1.5 kg

m2 (added)= 7.5 kg

From a penalty kick, the ball rebounds off the goalkeeper back to the player who took the kick. That player then kicks the ball into the goal. What is the correct restart

Answers

The correct restart is for there to be another kick off taken in this type of scenario.

What is Kick-off in Soccer?

This is a method of restarting play in which the ball is put on the center circle and passed by a player.

Kick offs occur at the beginning of any halves or when a goal is scored during the match which is why it's the most appropriate choice.

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Answer:Kick offs occur at the beginning of any halves or when a goal is scored during the match which is why it's the most appropriate choice.

Explanation:

​The function of the thick outer coverings of insects and reptiles like rattlesnakes in desert biomes is to ____.

Answers

Answer:

Shed

Explanation:

Snakes have to shed, or else their skin will become really crusty and flaky. Especially the ones that live in a desert. The sun destroys their skin, as it isn't as strong as ours.  

what optical effect is essential to the visual experience of motion pictures?

Answers

The optical effect that is essential to the visual experience of motion pictures is known as Persistence of Vision.

Persistence of Vision (POV) is a phenomenon of the eye where an image or object is perceived by the brain for a short period of time after the image or object has been removed from the viewer's sight. The phenomenon occurs because of the retina's temporary retention of visual images even after they have been seen.

The Persistence of Vision enables the human eye to perceive the illusion of motion when viewing a series of still images in rapid succession. This effect is the foundation for the creation of motion pictures. In films, a sequence of still images is displayed in rapid succession (typically at a rate of 24 frames per second) that simulates motion to the human eye, tricking it into believing that the images are moving in a fluid and natural way.

POV is an essential aspect of the visual experience of motion pictures as it allows filmmakers to create an illusion of motion using a series of still images. The human eye is capable of retaining images for a short period of time after they have disappeared from the field of vision, which makes this effect possible.

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A man takes 16 breaths per minute at 18 degree Celsius and 760mmHg. What is the rate of breathing on a mountain top where the temperature is 5 degree Celsius and the pressure is 240

Answers

The new breathing rate on the mountain top would be approximately 12.6 grams of nitrogen per minute.

What is the rate of breathing on a mountain top?

To calculate the new breathing rate at a different altitude with different temperature and pressure, we can use the formula for the Ideal Gas Law:

PV = nRT

where;

P is the pressure, V is the volume, n is the number of molesR is the gas constant, and T is the temperature.

Assuming that the volume of air breathed in and out remains constant, we can rearrange the Ideal Gas Law formula to solve for n/V, which gives us the number of moles of air per unit volume of air:

n/V = P/RT

If we assume that the air being breathed is mostly nitrogen, which makes up about 78% of the atmosphere, we can use the molar mass of nitrogen (28.0134 g/mol) to convert from moles of air to grams of nitrogen.

So the formula for the rate of breathing in grams of nitrogen per minute is:

Rate = (n/V) x (molar mass of nitrogen) x (breathing rate in breaths per minute)

First, we need to convert the pressure from 760 mmHg to 240 mmHg:

P1/T1 = P2/T2

where;

P1 is the initial pressure, T1 is the initial temperature, P2 is the new pressure, and T2 is the new temperature.

Solving for P2:

P2 = P1 x (T2/T1) = 760 mmHg x (5+273.15)/(18+273.15) = 602.5 mmHg

Now we can calculate the new n/V:

(n/V)2 = (P2/RT2) = (602.5 mmHg)/(0.0821 L atm/mol K x 278.15 K) = 0.0268 mol/L

Finally, we can calculate the new breathing rate in grams of nitrogen per minute:

Rate2 = (n/V)2 x (28.0134 g/mol) x (16 breaths/min) = 12.6 g/min

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An object with a charge of -3C is touched to an object with a charge of -1C. What is the new charge on each object?

Answers

After connecting the conducting wire, the spheres will redistribute charges until they both have a charge of -1C.

To determine the new charges on the spheres, we need to consider the principle of charge conservation, which states that the total charge before and after an interaction remains the same.

Let's assume that the spheres have charges Q1 and Q2 initially. In this case, Q1 = -3C and Q2 = +1C.

When a conducting wire is connected between the spheres, charge can redistribute until the system reaches equilibrium. Since the spheres are conducting, charges are free to move within them.

In the final state, the charges on the spheres will redistribute to reach a new equilibrium. Let's assume the new charges on the spheres are Q1' and Q2'.

According to the principle of charge conservation, the total charge before and after the connection remains the same:

Initial total charge = Q1 + Q2 = -3C + 1C = -2C

Final total charge = Q1' + Q2'

Since the total charge remains the same, we can write the equation:

Q1' + Q2' = -2C

Since the spheres are of equal size, we can assume that the charges redistribute equally:

Q1' = -1C

Q2' = -1C

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The question probable may be:

A conducting wire is connected between two conducting spheres of equal size have a charge of -3C and +1C respectively. Find out the new charge on each sphere ?

un paracadutista di massa 70kg scende per 100m a velocità costante.
quanta energia dissipa la resistenza del mezzo?

Answers

Answer:

hakdbkdjsbsjzkkahzjxbdkdj

The ability to use binocular disparity as a depth cue.

Answers

Binocular disparity refers to the slight difference in the images captured by the two eyes, which the brain uses to perceive depth.

The ability to use binocular disparity as a depth cue is essential for proper depth perception in humans and other animals with binocular vision. This cue is particularly important for perceiving depth in objects that are close to the observer. The brain processes the information from both eyes and combines them to create a 3D perception of the world around us. Without the ability to use binocular disparity as a depth cue, individuals may experience difficulties with spatial perception, which can impact daily activities such as driving or playing sports.

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as the carriage passes through the tank, the carriage loses momentum and causes some water to be pushed forwards with a speed of 19 ms-1 in the direction of motion of the carriage.

Answers

The carriage loses momentum as it passes through the tank, causing water to be pushed forwards with a speed of 19 m/s in the direction of the carriage's motion.

When the carriage moves through the tank, it experiences a loss of momentum. Momentum is a fundamental concept in physics that relates to the motion of an object and is defined as the product of its mass and velocity. The change in momentum of the carriage occurs due to external forces acting upon it, such as the resistance from the water in the tank.

As the carriage loses momentum, Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In this case, the action is the loss of momentum by the carriage, and the reaction is the forward push of water with a speed of 19 m/s in the direction of the carriage's motion.

The phenomenon can be explained by the principle of conservation of momentum. As the carriage loses momentum, an equal amount of momentum is transferred to the water in the tank, causing it to move forward with the mentioned speed. This transfer of momentum demonstrates the interaction between the carriage and the water, with the water gaining momentum as the carriage loses it.

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The most distant stars we can currently measure stellar parallax for are approximately Group of answer choices 10,000 parsecs away. halfway across the Milky Way Galaxy. 5 parsecs away. 1,000 parsecs away.

Answers

The most distant stars we can currently measure stellar parallax for are approximately 1,000 parsecs away.

What is a parsec?

A parsec is a unity used to measure distance in the Universe, which is hard to understand with human thinking.

A parsec equals to approximately 3.20 light-years, which is  a small distance in the Universe.

In conclusion, the most distant stars we can currently measure stellar parallax for are approximately 1,000 parsecs away.

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What climate conditions occur during La Niña?
A.stronger prevailing winds and more hurricane activity
B.warmer Pacific waters and warmer winters
C.more hurricane activity and warmer Pacific waters
D.warmer winters and stronger prevailing winds

Answers

Answer:

A. stronger prevailing winds and more hurricane activity

Explanation:

edg2020

Answer:A

Explanation:

An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.

Answers

The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.

To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.

Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.

Using the formula, we can calculate the distance traveled as follows:

d = rt

d = 130 mph × 2.5 hours

Multiplying the rate (130 mph) by the time (2.5 hours) gives us:

d = 325 miles

Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.

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4. The distance s travelled by a particle depends partly on the initial velocity u and time tand partly also on the acceleration a and tim e t. Establish a relationship between the four quantities. ​

Answers

The greater the initial velocity the greater the distance travelled.
The greater the acceleration, the greater the velocity and the shorter the time.

Hope this helps :)

Answer:

S = V0 t + 1/2 a t^2   standard equation

Where S is the distance traveled and V0 the initial speed

Use the information below the answer the following 3 questions.

A 50 kg crate is being dragged across a floor by a force of 225 N at an angle of 40o from the horizontal. The crate is dragged a distance of 5.0 m and the frictional force is 60 N.



Question 2 (2 points)
Question 2 options:
The work done on the crate by the applied force is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 3 (2 points)
Question 3 options:
The work done on the crate by the frictional force is -___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 4 (2 points)
Question 4 options:
The net work done on the crate is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).

Hint: Do not use rounded answers in subsequent calculations

Answers

Answer:

2. 8.62×10² Nm

3. 2.30×10² Nm

4. 6.32×10² Nm

Explanation:

2. Determination of the work done by the applied force.

Force (F) = 225 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fd × Cos θ

Wd = 225 × 5 × Cos 40

Wd = 8.62×10² Nm

3. Determination of the work done by the frictional force.

Frictional Force (Fբ) = 60 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fբd × Cos θ

Wd = 60 × 5 × Cos 40

Wd = 2.30×10² Nm

4. Determination of the net work done.

We'll begin by calculating the net force acting on the crate

Force applied (F) = 225 N

Frictional Force (Fբ) = 60 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 225 – 60

Fₙ = 165 N

Finally, we shall determine the net Workdone. This can be obtained as follow:

Net force (Fₙ) = 165 N

Distance (d) = 5 m

Angle (θ) = 40°

Workdone (Wd) =?

Wd = Fₙd × Cos θ

Wd = 165 × 5 × Cos 40

Wd = 6.32×10² Nm

A ball has a 8 J of kinetic energy and its mechanical energy is 25 J. If the ball has a mass of 3.2 kg, what is its height above the ground?

Answers

Answer:

0.531m

Explanation:

Soln

Mass = 3.2kg

Kinetic energy = 8 J

Mechanical energy = 25 J

Recall,

Mechanical energy = K.E + P.E

But P.E = mass × g × h

where g = acceleration due to gravity = 10ms² and h = height.

Mechanical energy = K.E + mass × g × h

25 = 8 + 3.2×10×h

25 - 8 = 32×h

17 = 32×h

divide both sides by 32

17/32 = h

h = 0.531 metres.

blocks i and ii, each with a mass of 1.0 kg, are hung from the ceiling of an elevator by ropes 1 and 2. what is the force exerted by rope 1 on block 1 when the elevator is traveling upward at a constant speed of 2.0 m/s?

Answers

When the elevator is traveling upward at a constant speed, the net force on each block is zero. Therefore, the force exerted by rope 1 on block 1 is equal in magnitude and opposite in direction to the force of gravity on block 1. The force of gravity on block 1 is given by:

F_gravity = m*g = (1.0 kg)*(9.8 m/s^2) = 9.8 N

Therefore, the force exerted by rope 1 on block 1 is also 9.8 N, upward.

An induced charge is when charged particles can be attracted to neutral objects.
True or false?

Answers

Answer:

the answer is true Induction charging is a method used to charge an object without actually touching the object to any other charged object.

Explanation:

Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough is commonly used with transverse waves!

Answers

Answer:

yes Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough are commonly used with transverse waves!

Explanation:

Light waves are electromagnetic waves that travel at 3.00 x 10^8 m/s. The eye is most sensitive to light having a wavelength of 5.50 x 10^-7 m.
a. Find the frequency of this light wave.
b. Find its period.

Answers

Answer:

a.  Frequency is 5.45 x 10^14 hz

b.   The period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Explanation:

The velocity of an electromagnetic wave is given by the product of the wave's frequency(f) times its wavelength(λ).  

V = λ f     where,

V is the wave speed,

f is the wave frequency,

λ is the wavelength.

To find frequency, rearrange to:

f = V/ λ

Light travels at 3.00x10^8 m/sec.

λ is 5.50 x 10^-7 m

f = (3.00x10^8 m/sec)/(5.50 x 10^-7 m)  meters cancels, secs is on the bottom]

f = (3.00/5.50)*(10^15)  [The base 10 exponent on the bottom ius subtracted from the one on top:  98-(-7)) = 15)  

f = 0.545 x 10^15 1/s or hz

f = 5.45 x 10^14 hz

b.  The period of a wave is the inverse of it's frequesncy.  It is the time it takes for 1 wave to pass.  Invert the frequency:

 Period = 1/f

  Period =  1/(0.545 x 10^15 1/s)

Period = 1.8 x 10^-15 sec  {or 1.8 femptoseconds]

Light waves are electromagnetic waves that travel at 3.00 x 10^8 m/s. The eye is most sensitive to light

What is the change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on the moon

Answers

The 45 kg weight is transported from 2 m to 18 m on the moon, changing its gravitational potential energy by 1,377.6 J.

Calculation-

The formula for gravitational potential energy is-

ΔU = mgh

Plugging in the given values, we get:

ΔU = (45 kg) × (1.62 m/s²) × (18 m - 2 m)

ΔU = 1,377.6 J

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The items on the right side of the equation are called the a. Coefficient c. Reactants b. Subscript d. Products​

The items on the right side of the equation are called the a. Coefficient c. Reactants b. Subscript d.

Answers

Answer:

products

Explanation:

a school bus has stopped to allow children to get off the bus which graph shows the motion of the bus?​

a school bus has stopped to allow children to get off the bus which graph shows the motion of the bus?

Answers

Answer: what is it in

Explanation:

If a bicyclist travels at 15 km/h, how long will it take her to travel 30 km?​

Answers

2 hours to get to 30km

If the x and y coordinate of a particle at any time t is given by X(t) = 7+ + 4t² and y=5t. What is the acceleration of the particle at += 3 sec ​

Answers

The acceleration of the particle at time 3 sec is 8 m/s².

What is the acceleration of the particle?

The acceleration of the particle is the change in velocity of the particle with time and it is calculated as follows;

a = dv/dt

where;

v is the velocity of the particle

v = dx/dt

where;

x is the position of the particle

v (x) = d (7t + 4t² )/ dt = 7 + 8t

v (y) = d (5t)/dt = 5

The acceleration of the particle at time 3 sec is calculated as;

a (x ) = dv(x) / dt = d (7 + 8t) / dt = 8

a (y) = dv(y) / dt = d (5) / dt = 0

Hence, a = 8 m/s²

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The length of the vibrating air column of a simple resonance tube can be altered by adjusting a water level. Resonance is found for a fork of frequency 440 Hz when the length of the air column is 18.8 cm and again when it is 57.3 cm. Explain how each of these positions occurs; calculate the speed of sound in the air in the tube and the position of the next resonance as more water is run out. what would be the corresponding resonance distances if the tube were filled with gas in which the speed of sound is 264m/s​

Answers

The two  corresponding resonance distances  would be:

18.8 cm * (264 m/s) / (8332 cm/s) = 0.15 m57.3 cm * (264 m/s) / (8332 cm/s) = 0.45 m

What are resonance distances?

Resonance distances refer to the lengths of the air column in a resonance tube that result in resonance. Resonance occurs when the pressure variations at the two ends of the air column are in phase, which means that the distance between the two pressure nodes must be equal to an integer multiple of one-quarter wavelength (i.e., one-quarter of the wavelength of the sound wave). The length of the air column that results in resonance is referred to as a resonance distance. When the air column is at a resonance distance, it acts as a standing wave, with both pressure and velocity antinodes at the open end of the tube and pressure nodes and velocity antinodes at the closed end. The resonance distances can be used to calculate the speed of sound in the gas filling the tube.

Calculation of Resonance distance:

For the first resonance, where the length of the air column is 18.8 cm, the distance between the pressure nodes must be equal to one-quarter of the wavelength of the sound wave at a frequency of 440 Hz:

(1/4)λ = 18.8 cm

Knowing the frequency and wavelength, the speed of sound in air can be calculated:

v = fλ

Substituting the values for frequency and wavelength:

v = (440 Hz)(18.8 cm) = 8332 cm/s

For the second resonance, where the length of the air column is 57.3 cm, the distance between the pressure nodes must be equal to three-quarters of the wavelength of the sound wave:

(3/4)λ = 57.3 cm

Solving for wavelength:

λ = (57.3 cm)(4) / 3 = 76 cm

The next resonance distance can be found by adding one-quarter of the wavelength to the previous resonance distance. In this case, the next resonance distance would be:

18.8 cm + (1/4)λ = 18.8 cm + (1/4)(76 cm) = 18.8 cm + 19 cm = 37.8 cm

If the tube were filled with a gas in which the speed of sound is 264 m/s, the wavelength of the 440 Hz sound wave would be:

λ = v / f = (264 m/s) / (440 Hz) = 0.6 m

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The heaviest loads ever raised were part of the offshore Ekofisk complex in the North Sea. The 4.0x 10 kg complex was raised 6.5 m by over a hundred hydraulic jacks. The work done on the complex during the raising was approximately 2.6x 101 J. Suppose the power output of all the jacks was 5.7x 10 W. How long did it take the jacks to raise the complex?​

Answers

Answer:

0.5s

Explanation:

Given parameters:

Mass of the complex  = 4 x 10kg

Distance moved  = 6.5m

Work done  = 2.6 x 10¹J

Power  = 5.7 x 10W

Unknown:

Time taken  = ?

Solution:

Power is the rate at which work is done.

  Power  = \(\frac{work done}{time}\)

  work done  = power x time

        time  = \(\frac{work done }{power}\)

  Insert the parameters;

       time  = \(\frac{260}{570}\)   = 0.5s

If the volume of a container of gas remains constant, what will happen to the pressure of a gas if you increase the temperature?

Answers

Answer:

This example of the effect of volume on the pressure of a given amount of a confined gas is true in general. Decreasing the volume of a contained gas will increase its pressure, and increasing its volume will decrease its pressure.

Explanation:

Hope it helps

Other Questions
Preparing adjusting entries (annual)-depreciation LO4 Mean Beans, a local coffee shop, has the following assets on January 1, 2020. Mean Beans prepares annual financial statements and has a December 31, 2020 year-end. The company's depreciation policy is to use the straight-line method to depreciate its assets. a. On January 1, 2020, purchase equipment costing $20,200 with an estimated life of five years. Mean Beans will scrap the equipment after five years for $0. b. On July 1, 2020, purchase furniture (tables and chairs) costing $21,500 with an estimated life of ten years. Mean Beans estimates that it can sell the furniture for $4,900 after ten years. c. On January 1, 2018, Mean Beans had purchased a car costing $19,250 with an estimated life of eight years. Mean Beans estimates that it can sell the car for $3,850 after eight years. Required: 1-8. For each transaction, calculate the current year annual depreciation expense. 4 a. Annual depreciation expense on equipment b. Annual depreciation expense on furniture c. Annual depreciation expense on car Exercise 3-4 Preparing adjusting entries (annual)-depreciation LO4 1 Mean Beans, a local coffee shop, has the following assets on January 1, 2020. Mean Beans prepares annual financial statements and has a December 31, 2020 year-end. The company's depreciation policy is to use the straight-line method to depreciate its assets. a. On January 1, 2020, purchase equipment costing $20,200 with an estimated life of five years. Mean Beans will scrap the equipment after five years for $0. b. On July 1, 2020, purchase furniture (tables and chairs) costing $21,500 with an estimated life of ten years. Mean Beans estimates that it can sell the furniture for $4,900 after ten years. c. On January 1, 2018, Mean Beans had purchased a car costing $19,250 with an estimated life of eight years. Mean Beans estimates that it can sell the car for $3,850 after eight years. An airplane is traveling at 400 milers per hour. which equation can be used to find the total distance the plane will travel in h hours? When and where did the East India Company initially established Class 9? (The following passage is excerpted from an essay by a twentieth-century American author.) In France, on a rented canal boat, my friends and I gazed in despair at the closed oaken gates of the lock. Wed come to them only seconds after the witching hour of noon, but we were too late. There was no one to open the lock for us; lclusire1 was at lunch, and after lunch she would lay herself down, close her eyes, and nap. At two, but not before, she would emerge refreshed from her square granite house and set the great cogs in motion. We tied the boat up to a spindly bush beside the towpath and waited. And waited. It was high haying season, but the fields lay empty of farmers. The roads lay empty of trucks. France lunched, and then slept. So did Spain. So did much of the civilized world. If wed been differently nurtured we too would have taken a nap, but we were Americans, condemned from the age of four to trudge through our sleepless days. Americans are afraid of naps. Napping is too luxurious, too sybaritic,2 too unproductive, and its free; pleasures for which we dont pay make us anxious. Besides, it seems to be a natural inclination. Those who get paid to investigate such things have proved that people deprived of daylight and their wristwatches, with no notion of whether it was night or day, sink blissfully asleep in midafternoon as regular as clocks. Fighting off natural inclinations is a major Puritan3 virtue, and nothing that feels that good can be respectable. They may have a point there. Certainly the process of falling asleep in the afternoon is quite different from bedtime sleep. Whether this is physiological or merely a by-product of guilt, its a blatantly sensual experience, a voluptuous surrender, akin to the euphoric swoon of the heroine in a vampire movie. For the self-controlled, its frighteninghow far down am I falling? will I ever climb back? The sleep itself has a different texture. Its blacker, thicker, more intense, and works faster. Fifteen minutes later the napper pops back to the Need help with this anyone please A car dealership pays a wholesale price of $14,000 to purchase a car. They sell the car for$16,100. What is the percent mark-up for the car? What happens when an atom forms an ion? Find the slope intercept form of the equation parallel to the line of Y =6x+72 and with coordinates of (8-9).Then find the slope intercept form of the equation Perpendicular to the line Y=5x-1/2 and with the coordinates of (25,-11). "people live interconnected lives and these networks of relationship shape people's occupations" is a: After examining the fossil record, scientists have determined that scorpions today are much smaller than their extinct ancestors. For example, Jaekelopterus rhenaniae, a giant scoprtion species that lived 255 million to 460 million years ago was 2.5 meters long. Which of the following conclusions is supported by this information?A. scorpions living today have increased their numbers since they first appearedB. scorpions in the fossil record are smaller than their descendants areC. scorpions have changed as a result of natural selectionD. scorpions do not appear in their original state in the fossil record What is draculas fate at the end of bram stokers horror novel?. Match the description to the term.1 . transitive verbform the past and past participle by adding ed, d, or t to the present2 . intransitive verba wish3 . subjunctive moodI will have seen4 . future perfect tensenames a receiver5 . regular verbhas no receiver named Maggie Enterprises issued $100,000 of 6%, five-year bonds with interest payable semiannually. Determine the issue price if the bonds are priced to yield (a) 6%, (b) 10%, and (c) 2%. If the two triangles are congruent below, what would be the value of x**Look at the show your work area for the picture** What are some uses we might have for standing waves? how did the early islamic world view science, and what contributions did muslim scholars make to fields such as mathematics, astronomy, and medicine? AV=12.0V11 ohms01 ohmR-2.00MWhat is the equivalent resistance of the circuit shown?23 ohms110 ohmsR = 5.00R4.00 5.02 One Step EquationsSolve for m16 m = -29m=13m=-13m=15m=-45 helpp with this :>!!! determine the number and type of chemical bonds in phosphorus trifluoride (pf3) and cesium selenide (cs2se).