The box is in equilibrium, so Newton's second law says
n + (-w) = 0
65 N + (-f ) = 0
where n denotes the magnitude of the normal force, w denotes the weight of the box, and f denotes the magnitude of the friction force.
The box has a weight of
w = (25 kg) (9.80 m/s²) = 245 N
so n = 245 N, too.
The friction force has magnitude
f = 65 N
and is proportional to the normal force by a factor of µ, the coefficient of kinetic friction. So we have
65 N = µ (245 N) → µ ≈ 0.26
What do you know about energy and Newton's laws? (5 pts)
What do you wonder about energy and Newton's laws? (5 pts)
Force is applied to change the kinetic energy of an object.
What is the relationship between energy and Newton's laws?Energy is closely related to Newton's laws of motion, which describe the behavior of objects in motion.
For instance, the first law of motion, also known as the law of inertia, states that an object at rest will remain at rest, and an object in motion will remain in motion at a constant velocity, unless acted upon by an external force.
This law is related to energy because an object in motion has kinetic energy, which is the energy associated with its motion. In order to change the motion of an object, an external force must be applied, which can change the object's kinetic energy.
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An average eardrum has an area of about 5. 0x10-5m2. What is the force in newtons exerted on an eardrum if you are at the bottom of a water-filled pool that is 2. 9 meters deep? (hint: take all pressures into account)
The force exerted on the eardrum at the bottom of a 2.9m deep water-filled pool is approximately 1.4 x 10^-3 N, taking into account the pressure of the water and the atmosphere.
The pressure at the bottom of the water-filled pool can be calculated using the formula P = rho * g * h, where rho is the density of water (1000 kg/m^3), g is the acceleration due to gravity (9.81 m/s^2), and h is the depth of the pool (2.9 m). Thus, P = (1000 kg/m^3) * (9.81 m/s^2) * (2.9 m) = 28410 Pa. The total force exerted on the eardrum is then the product of pressure and area: F = P * A = (28410 Pa) * (5.0 x 10^-5 m^2) = 1.4 x 10^-3 N. This force takes into account the pressure of the water as well as the atmospheric pressure.
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1. The energy an object has while it is moving is called kinetic energy, or the energy of
A)traction
B)friction
C)magnetism
D)motion
Answer:
D
Explanation:
I hope this helps :)
Let me know if you want a full explanation
The energy an object has while it is moving is called kinetic energy, or the energy of motion. Thus, the correct option for this question is D.
What do you mean by Kinetic energy?Kinetic energy may be defined as a type of energy that an object possesses due to its motion. It is defined as the work that is required in order to accelerate a body of a given mass from rest to its stated velocity. It is also known as the energy that is possessed by an object by the virtue of its motion.
Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles. Any object in motion is using kinetic energy: a person walking, a thrown baseball, a crumb falling from a table, and a charged particle in an electric field are all examples of kinetic energy at work.
Therefore, the energy an object has while it is moving is called kinetic energy, or the energy of motion. Thus, the correct option for this question is D.
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I need to find out number 51.Can you help me ?
v= constant
mass of the cart = 1.5 kg
m2 (added)= 7.5 kg
From a penalty kick, the ball rebounds off the goalkeeper back to the player who took the kick. That player then kicks the ball into the goal. What is the correct restart
The correct restart is for there to be another kick off taken in this type of scenario.
What is Kick-off in Soccer?This is a method of restarting play in which the ball is put on the center circle and passed by a player.
Kick offs occur at the beginning of any halves or when a goal is scored during the match which is why it's the most appropriate choice.
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Answer:Kick offs occur at the beginning of any halves or when a goal is scored during the match which is why it's the most appropriate choice.
Explanation:
The function of the thick outer coverings of insects and reptiles like rattlesnakes in desert biomes is to ____.
Answer:
Shed
Explanation:
Snakes have to shed, or else their skin will become really crusty and flaky. Especially the ones that live in a desert. The sun destroys their skin, as it isn't as strong as ours.
what optical effect is essential to the visual experience of motion pictures?
The optical effect that is essential to the visual experience of motion pictures is known as Persistence of Vision.
Persistence of Vision (POV) is a phenomenon of the eye where an image or object is perceived by the brain for a short period of time after the image or object has been removed from the viewer's sight. The phenomenon occurs because of the retina's temporary retention of visual images even after they have been seen.
The Persistence of Vision enables the human eye to perceive the illusion of motion when viewing a series of still images in rapid succession. This effect is the foundation for the creation of motion pictures. In films, a sequence of still images is displayed in rapid succession (typically at a rate of 24 frames per second) that simulates motion to the human eye, tricking it into believing that the images are moving in a fluid and natural way.
POV is an essential aspect of the visual experience of motion pictures as it allows filmmakers to create an illusion of motion using a series of still images. The human eye is capable of retaining images for a short period of time after they have disappeared from the field of vision, which makes this effect possible.
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A man takes 16 breaths per minute at 18 degree Celsius and 760mmHg. What is the rate of breathing on a mountain top where the temperature is 5 degree Celsius and the pressure is 240
The new breathing rate on the mountain top would be approximately 12.6 grams of nitrogen per minute.
What is the rate of breathing on a mountain top?To calculate the new breathing rate at a different altitude with different temperature and pressure, we can use the formula for the Ideal Gas Law:
PV = nRT
where;
P is the pressure, V is the volume, n is the number of molesR is the gas constant, and T is the temperature.Assuming that the volume of air breathed in and out remains constant, we can rearrange the Ideal Gas Law formula to solve for n/V, which gives us the number of moles of air per unit volume of air:
n/V = P/RT
If we assume that the air being breathed is mostly nitrogen, which makes up about 78% of the atmosphere, we can use the molar mass of nitrogen (28.0134 g/mol) to convert from moles of air to grams of nitrogen.
So the formula for the rate of breathing in grams of nitrogen per minute is:
Rate = (n/V) x (molar mass of nitrogen) x (breathing rate in breaths per minute)
First, we need to convert the pressure from 760 mmHg to 240 mmHg:
P1/T1 = P2/T2
where;
P1 is the initial pressure, T1 is the initial temperature, P2 is the new pressure, and T2 is the new temperature.Solving for P2:
P2 = P1 x (T2/T1) = 760 mmHg x (5+273.15)/(18+273.15) = 602.5 mmHg
Now we can calculate the new n/V:
(n/V)2 = (P2/RT2) = (602.5 mmHg)/(0.0821 L atm/mol K x 278.15 K) = 0.0268 mol/L
Finally, we can calculate the new breathing rate in grams of nitrogen per minute:
Rate2 = (n/V)2 x (28.0134 g/mol) x (16 breaths/min) = 12.6 g/min
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An object with a charge of -3C is touched to an object with a charge of -1C. What is the new charge on each object?
After connecting the conducting wire, the spheres will redistribute charges until they both have a charge of -1C.
To determine the new charges on the spheres, we need to consider the principle of charge conservation, which states that the total charge before and after an interaction remains the same.
Let's assume that the spheres have charges Q1 and Q2 initially. In this case, Q1 = -3C and Q2 = +1C.
When a conducting wire is connected between the spheres, charge can redistribute until the system reaches equilibrium. Since the spheres are conducting, charges are free to move within them.
In the final state, the charges on the spheres will redistribute to reach a new equilibrium. Let's assume the new charges on the spheres are Q1' and Q2'.
According to the principle of charge conservation, the total charge before and after the connection remains the same:
Initial total charge = Q1 + Q2 = -3C + 1C = -2C
Final total charge = Q1' + Q2'
Since the total charge remains the same, we can write the equation:
Q1' + Q2' = -2C
Since the spheres are of equal size, we can assume that the charges redistribute equally:
Q1' = -1C
Q2' = -1C
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The question probable may be:
A conducting wire is connected between two conducting spheres of equal size have a charge of -3C and +1C respectively. Find out the new charge on each sphere ?
un paracadutista di massa 70kg scende per 100m a velocità costante.
quanta energia dissipa la resistenza del mezzo?
Answer:
hakdbkdjsbsjzkkahzjxbdkdj
The ability to use binocular disparity as a depth cue.
Binocular disparity refers to the slight difference in the images captured by the two eyes, which the brain uses to perceive depth.
The ability to use binocular disparity as a depth cue is essential for proper depth perception in humans and other animals with binocular vision. This cue is particularly important for perceiving depth in objects that are close to the observer. The brain processes the information from both eyes and combines them to create a 3D perception of the world around us. Without the ability to use binocular disparity as a depth cue, individuals may experience difficulties with spatial perception, which can impact daily activities such as driving or playing sports.
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as the carriage passes through the tank, the carriage loses momentum and causes some water to be pushed forwards with a speed of 19 ms-1 in the direction of motion of the carriage.
The carriage loses momentum as it passes through the tank, causing water to be pushed forwards with a speed of 19 m/s in the direction of the carriage's motion.
When the carriage moves through the tank, it experiences a loss of momentum. Momentum is a fundamental concept in physics that relates to the motion of an object and is defined as the product of its mass and velocity. The change in momentum of the carriage occurs due to external forces acting upon it, such as the resistance from the water in the tank.
As the carriage loses momentum, Newton's third law of motion comes into play. According to this law, for every action, there is an equal and opposite reaction. In this case, the action is the loss of momentum by the carriage, and the reaction is the forward push of water with a speed of 19 m/s in the direction of the carriage's motion.
The phenomenon can be explained by the principle of conservation of momentum. As the carriage loses momentum, an equal amount of momentum is transferred to the water in the tank, causing it to move forward with the mentioned speed. This transfer of momentum demonstrates the interaction between the carriage and the water, with the water gaining momentum as the carriage loses it.
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The most distant stars we can currently measure stellar parallax for are approximately Group of answer choices 10,000 parsecs away. halfway across the Milky Way Galaxy. 5 parsecs away. 1,000 parsecs away.
The most distant stars we can currently measure stellar parallax for are approximately 1,000 parsecs away.
What is a parsec?A parsec is a unity used to measure distance in the Universe, which is hard to understand with human thinking.
A parsec equals to approximately 3.20 light-years, which is a small distance in the Universe.
In conclusion, the most distant stars we can currently measure stellar parallax for are approximately 1,000 parsecs away.
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What climate conditions occur during La Niña?
A.stronger prevailing winds and more hurricane activity
B.warmer Pacific waters and warmer winters
C.more hurricane activity and warmer Pacific waters
D.warmer winters and stronger prevailing winds
Answer:
A. stronger prevailing winds and more hurricane activity
Explanation:
edg2020
Answer:A
Explanation:
An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.
The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.
To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.
Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.
Using the formula, we can calculate the distance traveled as follows:
d = rt
d = 130 mph × 2.5 hours
Multiplying the rate (130 mph) by the time (2.5 hours) gives us:
d = 325 miles
Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.
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4. The distance s travelled by a particle depends partly on the initial velocity u and time tand partly also on the acceleration a and tim e t. Establish a relationship between the four quantities.
Answer:
S = V0 t + 1/2 a t^2 standard equation
Where S is the distance traveled and V0 the initial speed
Use the information below the answer the following 3 questions.
A 50 kg crate is being dragged across a floor by a force of 225 N at an angle of 40o from the horizontal. The crate is dragged a distance of 5.0 m and the frictional force is 60 N.
Question 2 (2 points)
Question 2 options:
The work done on the crate by the applied force is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 3 (2 points)
Question 3 options:
The work done on the crate by the frictional force is -___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Question 4 (2 points)
Question 4 options:
The net work done on the crate is ___x102 Nm. (Give your answer with the correct number of sign digs and do not include units).
Hint: Do not use rounded answers in subsequent calculations
Answer:
2. 8.62×10² Nm
3. 2.30×10² Nm
4. 6.32×10² Nm
Explanation:
2. Determination of the work done by the applied force.
Force (F) = 225 N
Distance (d) = 5 m
Angle (θ) = 40°
Workdone (Wd) =?
Wd = Fd × Cos θ
Wd = 225 × 5 × Cos 40
Wd = 8.62×10² Nm
3. Determination of the work done by the frictional force.
Frictional Force (Fբ) = 60 N
Distance (d) = 5 m
Angle (θ) = 40°
Workdone (Wd) =?
Wd = Fբd × Cos θ
Wd = 60 × 5 × Cos 40
Wd = 2.30×10² Nm
4. Determination of the net work done.
We'll begin by calculating the net force acting on the crate
Force applied (F) = 225 N
Frictional Force (Fբ) = 60 N
Net force (Fₙ) =?
Fₙ = F – Fբ
Fₙ = 225 – 60
Fₙ = 165 N
Finally, we shall determine the net Workdone. This can be obtained as follow:
Net force (Fₙ) = 165 N
Distance (d) = 5 m
Angle (θ) = 40°
Workdone (Wd) =?
Wd = Fₙd × Cos θ
Wd = 165 × 5 × Cos 40
Wd = 6.32×10² Nm
A ball has a 8 J of kinetic energy and its mechanical energy is 25 J. If the ball has a mass of 3.2 kg, what is its height above the ground?
Answer:
0.531m
Explanation:
Soln
Mass = 3.2kg
Kinetic energy = 8 J
Mechanical energy = 25 J
Recall,
Mechanical energy = K.E + P.E
But P.E = mass × g × h
where g = acceleration due to gravity = 10ms² and h = height.
Mechanical energy = K.E + mass × g × h
25 = 8 + 3.2×10×h
25 - 8 = 32×h
17 = 32×h
divide both sides by 32
17/32 = h
h = 0.531 metres.
blocks i and ii, each with a mass of 1.0 kg, are hung from the ceiling of an elevator by ropes 1 and 2. what is the force exerted by rope 1 on block 1 when the elevator is traveling upward at a constant speed of 2.0 m/s?
An induced charge is when charged particles can be attracted to neutral objects.
True or false?
Answer:
the answer is true Induction charging is a method used to charge an object without actually touching the object to any other charged object.
Explanation:
Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough is commonly used with transverse waves!
Answer:
yes Compression and rarefaction are commonly used with longitudinal waves. And Crests and trough are commonly used with transverse waves!
Explanation:
Light waves are electromagnetic waves that travel at 3.00 x 10^8 m/s. The eye is most sensitive to light having a wavelength of 5.50 x 10^-7 m.
a. Find the frequency of this light wave.
b. Find its period.
Answer:
a. Frequency is 5.45 x 10^14 hz
b. The period = 1.8 x 10^-15 sec {or 1.8 femptoseconds]
Explanation:
The velocity of an electromagnetic wave is given by the product of the wave's frequency(f) times its wavelength(λ).
V = λ f where,
V is the wave speed,
f is the wave frequency,
λ is the wavelength.
To find frequency, rearrange to:
f = V/ λ
Light travels at 3.00x10^8 m/sec.
λ is 5.50 x 10^-7 m
f = (3.00x10^8 m/sec)/(5.50 x 10^-7 m) meters cancels, secs is on the bottom]
f = (3.00/5.50)*(10^15) [The base 10 exponent on the bottom ius subtracted from the one on top: 98-(-7)) = 15)
f = 0.545 x 10^15 1/s or hz
f = 5.45 x 10^14 hz
b. The period of a wave is the inverse of it's frequesncy. It is the time it takes for 1 wave to pass. Invert the frequency:
Period = 1/f
Period = 1/(0.545 x 10^15 1/s)
Period = 1.8 x 10^-15 sec {or 1.8 femptoseconds]
What is the change in gravitational potential energy of a 45 kg weight that is moved from 2 m to 18 m on the moon
The 45 kg weight is transported from 2 m to 18 m on the moon, changing its gravitational potential energy by 1,377.6 J.
Calculation-The formula for gravitational potential energy is-
ΔU = mgh
Plugging in the given values, we get:
ΔU = (45 kg) × (1.62 m/s²) × (18 m - 2 m)
ΔU = 1,377.6 J
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The items on the right side of the equation are called the a. Coefficient c. Reactants b. Subscript d. Products
Answer:
products
Explanation:
a school bus has stopped to allow children to get off the bus which graph shows the motion of the bus?
Answer: what is it in
Explanation:
If a bicyclist travels at 15 km/h, how long will it take her to travel 30 km?
If the x and y coordinate of a particle at any time t is given by X(t) = 7+ + 4t² and y=5t. What is the acceleration of the particle at += 3 sec
The acceleration of the particle at time 3 sec is 8 m/s².
What is the acceleration of the particle?
The acceleration of the particle is the change in velocity of the particle with time and it is calculated as follows;
a = dv/dt
where;
v is the velocity of the particlev = dx/dt
where;
x is the position of the particlev (x) = d (7t + 4t² )/ dt = 7 + 8t
v (y) = d (5t)/dt = 5
The acceleration of the particle at time 3 sec is calculated as;
a (x ) = dv(x) / dt = d (7 + 8t) / dt = 8
a (y) = dv(y) / dt = d (5) / dt = 0
Hence, a = 8 m/s²
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The length of the vibrating air column of a simple resonance tube can be altered by adjusting a water level. Resonance is found for a fork of frequency 440 Hz when the length of the air column is 18.8 cm and again when it is 57.3 cm. Explain how each of these positions occurs; calculate the speed of sound in the air in the tube and the position of the next resonance as more water is run out. what would be the corresponding resonance distances if the tube were filled with gas in which the speed of sound is 264m/s
The two corresponding resonance distances would be:
18.8 cm * (264 m/s) / (8332 cm/s) = 0.15 m57.3 cm * (264 m/s) / (8332 cm/s) = 0.45 mWhat are resonance distances?Resonance distances refer to the lengths of the air column in a resonance tube that result in resonance. Resonance occurs when the pressure variations at the two ends of the air column are in phase, which means that the distance between the two pressure nodes must be equal to an integer multiple of one-quarter wavelength (i.e., one-quarter of the wavelength of the sound wave). The length of the air column that results in resonance is referred to as a resonance distance. When the air column is at a resonance distance, it acts as a standing wave, with both pressure and velocity antinodes at the open end of the tube and pressure nodes and velocity antinodes at the closed end. The resonance distances can be used to calculate the speed of sound in the gas filling the tube.
Calculation of Resonance distance:
For the first resonance, where the length of the air column is 18.8 cm, the distance between the pressure nodes must be equal to one-quarter of the wavelength of the sound wave at a frequency of 440 Hz:
(1/4)λ = 18.8 cm
Knowing the frequency and wavelength, the speed of sound in air can be calculated:
v = fλ
Substituting the values for frequency and wavelength:
v = (440 Hz)(18.8 cm) = 8332 cm/s
For the second resonance, where the length of the air column is 57.3 cm, the distance between the pressure nodes must be equal to three-quarters of the wavelength of the sound wave:
(3/4)λ = 57.3 cm
Solving for wavelength:
λ = (57.3 cm)(4) / 3 = 76 cm
The next resonance distance can be found by adding one-quarter of the wavelength to the previous resonance distance. In this case, the next resonance distance would be:
18.8 cm + (1/4)λ = 18.8 cm + (1/4)(76 cm) = 18.8 cm + 19 cm = 37.8 cm
If the tube were filled with a gas in which the speed of sound is 264 m/s, the wavelength of the 440 Hz sound wave would be:
λ = v / f = (264 m/s) / (440 Hz) = 0.6 m
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The heaviest loads ever raised were part of the offshore Ekofisk complex in the North Sea. The 4.0x 10 kg complex was raised 6.5 m by over a hundred hydraulic jacks. The work done on the complex during the raising was approximately 2.6x 101 J. Suppose the power output of all the jacks was 5.7x 10 W. How long did it take the jacks to raise the complex?
Answer:
0.5s
Explanation:
Given parameters:
Mass of the complex = 4 x 10kg
Distance moved = 6.5m
Work done = 2.6 x 10¹J
Power = 5.7 x 10W
Unknown:
Time taken = ?
Solution:
Power is the rate at which work is done.
Power = \(\frac{work done}{time}\)
work done = power x time
time = \(\frac{work done }{power}\)
Insert the parameters;
time = \(\frac{260}{570}\) = 0.5s
If the volume of a container of gas remains constant, what will happen to the pressure of a gas if you increase the temperature?
Answer:
This example of the effect of volume on the pressure of a given amount of a confined gas is true in general. Decreasing the volume of a contained gas will increase its pressure, and increasing its volume will decrease its pressure.
Explanation:
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