A car dealership pays a wholesale price of $14,000 to purchase a car. They sell the car for
$16,100. What is the percent mark-up for the car?

The range of the graphed function in this problem is given as follows:

[-9, 9].

The values of y in this function are between -9 and 9, inclusive, hence the range of the function is given as follows:

[-9, 9].

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The function f(x) = -2(4)ˣ⁺¹ +140 represents the number of tokens a child has x hours after arriving at an arcade. The practical domain and range of the function are x ≥ 0 and The practical range of the situation is [140, ∞).

The given function is f(x) = -2(4)ˣ⁺¹+ 140, which represents the number of tokens a child has x hours after arriving at an arcade.

To determine the practical domain and range of the function, we need to consider the constraints and limitations of the situation.

For the practical domain, we need to identify the valid values for x, which in this case represents the number of hours the child has been at the arcade. Since time cannot be negative in this context, the practical domain is x ≥ 0, meaning x is a non-negative number or zero.

Therefore, the practical domain of the situation is x ≥ 0.

For the practical range, we need to determine the possible values for the number of tokens the child can have. Looking at the given function, we can see that the term -2(4)ˣ⁺¹represents a decreasing exponential function as x increases. The constant term +140 is added to shift the graph upward.

Since the exponential term decreases as x increases, the function will have a maximum value at x = 0 and approach negative infinity as x approaches infinity. However, due to the presence of the +140 term, the actual range will be shifted upward by 140 units.

Therefore, the practical range of the situation will be all real numbers greater than or equal to 140. In interval notation, we can express it as [140, ∞).

To summarize:

- The practical domain of the situation is x ≥ 0.

- The practical range of the situation is [140, ∞).

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Answer:

fgfddvgfdgdggggggggggggggggggggggggggggggggg      

fffffgv

Step-by-step explanation:

According to the given information, the value of the surface integral is 8/3.

The space occupied by a two-dimensional flat surface is called the area. It is measured in square units. The area occupied by a three-dimensional object by its outer surface is called the surface area.

The surface integral of a vector field F over a surface S is given by:

∬S F ⋅ dS = ∬R (F ⋅ ru × rv) dA

where R is the parameter domain of the surface S, ru and rv are the partial derivatives of the position vector r(u,v) with respect to u and v, and dA = ||ru × rv|| dudv is the area element on the surface.

In this case, we want to evaluate the surface integral:

∫∫H 4y dA

where H is the helicoid given by the vector parametric equation:

r(u,v) = <u cos(v), u sin(v), v>, 0 ≤ u ≤ 1, 0 ≤ v ≤ 9π.

The position vector r(u,v) has partial derivatives with respect to u and v given by:

ru = <cos(v), sin(v), 0>

rv = <-u sin(v), u cos(v), 1>

The area element is given by:

dA = ||ru × rv|| dudv = ||<cos(v), sin(v), u>| dudv = u dudv

Therefore, the surface integral can be written as:

\($\int\int_H 4y dA = \int_0^{9\pi} \int_0^1 4(u\sin v)u dudv$\\$= \int_0^{9\pi} \sin v \int_0^1 4u^2 du dv$\)

\($= \int_0^{9\pi} \sin v \left(\frac{4}{3}\right) dv$\\$= \left[-\frac{4}{3} \cos v\right]_0^{9\pi}$\)

= 8/3

Hence, According to the given information the value of the surface integral is 8/3.

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By solving a linear equation we will see that there were 6 hours of labor.

We know that the total cost is composed by a fixed amount of $365 plus $89 per hour of labor, so if there are x hours of labor, the total cost will be:

c(x) =  $365 + x*$89

We know that the total cost is $899, then we can write the linear equation:

$899 = $365 + x*$89

$899 - $365 = x*$89

($899 - $365)/$89 = x = 6

So there were 6 hours of labor.

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It can be found by graphing the points given and sketching the parabola. Another point on the graph is (-1, 9) that passes through them. You can move over and up from the vertex and do the same on the opposite side of the line x = -1.

In Mathematics and Geometry, the vertex form of a quadratic function is represented by the following mathematical equation:

f(x) = a(x - h)² + k

Where:

Based on the information provided, the vertex is located at point (2, 0), and this ultimately implies that the axis is represented by the vertical line x = 2 that passes through the vertex.

Additionally, the parabola would be bilaterally symmetric about the above axis, and the mirror image of the point (5, 9) would also be on this parabola.

Therefore, the mirror image would have the same y-coordinate of 9 while the x-coordinate is given by:

x = 2 - (5 -2)

x = -1.

In conclusion, the required point is (-1, 9).

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Complete Question:

The graph of a quadratic function has a vertex (2, 0). One point on the graph is (5, 9). Explain how to find another point on the graph. It can be found by graphing the points given and sketching the parabola. Another point on the graph is (-1, _) that passes through them. You can move over and up from the vertex and do the same on the opposite side of the line x=

Answer:

7 : 14, or simplified, 1 : 2

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

divide by 7 to

Answer:

first angle = 60

second angle = 120

Step-by-step explanation:

Let the first angle  x

Let the second angle = 2x

x + 2x = 180        Supplementary angles = 180 degrees

3x = 180              Divide by 3

3x/3 = 180/3

x = 60

2x = 120

The probability that you select a Jack given that it is a Club P(Jack∣Club) is 1/13.

The probability that you select a Club given that it is a Jack is P(Club∣Jack) is 1/4.

The probability that you select a card that is NOT a Jack given that it is NOT a Club,P(NotJack∣NotClub) is 47/38

The probability that you select a card that is NOT a Club given that is it NOT a Jack is 38/47

The probability that you select a Jack given that it is a Club P(Jack|Club):

There are 4 Jacks in a deck (one for each suit), and since we are given that the selected card is a Club, we only need to consider the 13 cards in the Club suit.

So, the number of favorable outcomes is 1 (the Jack of Clubs), and the total number of possible outcomes is 13 (the number of cards in the Club suit)

P(Jack|Club) = 1 / 13

The probability that you select a Club given that it is a Jack

P(Club|Jack):

P(Club|Jack) = Number of favorable outcomes / Total number of possible outcomes

P(Club|Jack) = 1 / 4

The probability that you select a card that is not a Jack given that it is not a Club

P(NotJack|NotClub):

The number of cards that are not Jacks is 52 - 4 = 48 (since there are 4 Jacks in the deck), and the number of cards that are not Clubs is 52 - 13 = 39 (since there are 13 cards in the Club suit).

P(NotJack|NotClub) = Number of favorable outcomes / Total number of possible outcomes

P(NotJack|NotClub) = (48 - 1) / (39 - 1)

=47/38

P(NotClub|NotJack) = (39 - 1) / (48 - 1)

=38/47

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Answer: 8.8 hours

Step-by-step explanation:

To start off, we’ll make an equation that “connects” both companies:

10 + 4.75h = 21 + 3.5h (we put h to represent the number of hours)

Move all similar terms to one side:

4.75h - 3.5h = 21 - 10

Simplify:

1.25h = 11

h = 8.8

I hope this helps!

R = (ax - p)/(q + bx)

(ax - p) = R(q + bx)

ax - p = Rq + Rbx

ax - Rbx = Rq + p

x(a - Rb) = Rq + p

x = (Rq + p)/(a - Rb)

Answer:

where is the picture

Step-by-step explanation:

Answer:

jeub42hg24h vhrj vjo24 ve4goj

Step-by-step explanation:

Can this quadrilateral be inscribe in a circle

A. Yes because the opposite angles are supplementary.

B. No, because the opposite angles are not supplementary.

C. Yes, because the opposite angles are congruent.

D. No, because the opposite angles are not congruent

ANSWER: D. No, because the opposite angles are not congruent

I believe this is correct, I hope I helped!

Answer:

Step-by-step explanation :

N = number of nickels

D = number of dimes

Q = number of quarters

`

252 = N + D + Q <---- Equation 1

D = 3(N+Q) <---- Equation 2

24.85 = 0.05N + 0.10D + 0.25Q <---- Equation 3

We a have set of three linear equations to solve for three unknowns N, D, and Q.

Rearranging the equations we have :

N + D + Q = 252

3N - D + 3Q = 0

0.05N + 0.10 D + 0.25Q = 24.85

Solving the set of linear equations, we end up with :

N = 49

D = 189

Q = 14

(see the attached images for the entire solution)

Given

To find

we know that

Inserting the value of radius

Answer: A

Step-by-step explanation: You merge the equations, -2x and 2x cancel out, 4y + 1y = 5y, and 12 + (-7) = 5

You'll be left with 5y = 5

Dividing both sides by 5 to isolate the y results in y = 1

Answer:

0.018

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

let x be the number , then

\(\frac{3}{4}\) x = 27 ( multiply both sides by 4 to clear the fraction )

3x = 108 ( divide both sides by 3 )

x = 36

the number is 36, so

\(\frac{2}{9}\) × 36 = 2 × 4 = 8

The two ninths of the number is 8

We know that Three quarters of a number is  \(\frac{3}{4}\)  times of a number

Hence we will assume the number x ,

                     \(\frac{3}{4} of x = 27\)

                     \(x = 27 X \frac{4}{3}\)

                       \(x = 36\)

Now as we know the number is 36

Therefore , the two ninths of the number assumed as y

We will multiply the number 36 by 2 and then divide by 9

Hence,

                           \(y = 36 X \frac{2}{9}\)

                               \(y = 8\)

Thus, the two ninths of the number 36  is 8                            

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The following relation can be used to show the relationship between the confidence level and the sample size

Also,

And,

There fore,

when the value of n is large, the standard error will be low

when the standard error is low margin of error(MOE) will also be low

Hence, if the Margin of error the confidence level will have a larger width

Therefore,

We can say that A confidence level would have a larger width with a small sample size from normal distribution

Final answer is OPTION A

Answer:

7x.

Step-by-step explanation:

Seven times a number = 7x.

An algebraic expression for the given statement is 7x.

The given statement is seven times a number.

We need to write an algebraic expression for the given statement.

An algebraic expression (or) a variable expression is a combination of terms by the operations such as addition, subtraction, multiplication, division, etc.

Given that, use the variable x to represent the unknown number.

Now, seven times a number=7x

Therefore, an algebraic expression for the given statement is 7x.

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Answer: 745 miles

Step-by-step explanation:

You do 65 times 11 plus 30

The measure of the frame in feet of the length and width are 3.667 feet and 2.125 feet respectively.

The unitary method is a method in which you find the value of a unit and then the value of a required number of units.

Given here: The measure of the frame is 8.5 inches and 11 inches

a) if the frame is 4 papers long then we  have the length of the frame as

11×4=44 inches (since he lays the paper along the edge of frame)

We know 1 inch= 0.0833 foot

Thus      44 inches= 3.66667 foot

b) Again if he lays the paper along the short edge than the width of the frame is 3×8.5=25.5 inches

∴25.5 inches= 2.125 feet

Hence, The measure of the frame in feet of the length and width are 3.667 feet and 2.125 feet respectively.

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Answer:

40

Step-by-step explanation:

plugging in a and b will get us:

\(2^{2} + 6^{2} = c^{2}\)

4 + 36 = \(c^{2}\)

40 = \(c^{2}\)

c= \(\sqrt{40\\\)

Answer:

540

Step-by-step explanation:

3/500pairs are defective

there are 20 500's in 10,000

so 20×3=60

60pairs

60pairs × 9.00

=540

Answer:

Step-by-step explanation:

30). \(5^{th}\) degree ( 4 + 1 = 5 ; 1 + 1 = 2 and 2 + 2 = 4 )

31) D) Choice D

Answer:

The degrees of freedom are given by;

\( df =n-1= 5-1=4\)

The significance level is 0.1 so then the critical value would be given by:

\( F_{cric}= 7.779\)

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

Step-by-step explanation:

For this case we have the following observed values:

Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100

For this case the expected values for each day are assumed:

\( E_i = \frac{100}{5}= 20\)

The statsitic would be given by:

\( \chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}\)

Where O represent the observed values and E the expected values

The degrees of freedom are given by;

\( df =n-1= 5-1=4\)

The significance level is 0.1 so then the critical value would be given by:

\( F_{cric}= 7.779\)

If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays

The area of the dish, a, can be represented by the product of its length and width. Thus, we can write:

a = (279/10) cm x (178/10) cm

Simplifying this expression, we get:

a = 4953/100 cm^2

So, the correct equations are:

B) 178/10 x 279/10 = a

and

D) a ÷ 178/10 = 279/10