Answer:
To find the amount of work done by the car as its front is pushed in, you need to know the force that the car exerts on the tree and the distance over which this force is applied. The force that the car exerts on the tree is equal to the change in momentum of the car divided by the time over which this change occurs. The change in momentum of the car is equal to its final momentum minus its initial momentum, and the time over which this change occurs is the time it takes for the car to come to rest.
Since the car has a mass of 1622 kg and a speed of 11 m/s before it hits the tree, its initial momentum is equal to 1622 kg * 11 m/s = 17842 kgm/s. After it comes to rest, the car has a speed of 0 m/s, so its final momentum is 0 kgm/s. The change in momentum of the car is therefore equal to 0 - 17842 = -17842 kg*m/s.
The time it takes for the car to come to rest will depend on the deceleration of the car and the distance over which it decelerates. Since the deceleration of the car and the distance over which it decelerates are not given, it is not possible to calculate the time it takes for the car to come to rest. Without this information, it is not possible to calculate the amount of work done by the car as its front is pushed in.
what volume, in milliliters, will 2.00 g of air occupy if the density is 1.29 g/l?
a. 1.55 x 10^3 ml
b. 3.40 ml
c. 3.72 x 10^ ml
d. 7.57 x 10^2 ml
The volume in milliliters that 2.00 g of air will occupy if the density is 1.29 g/l is 1.55 x 10^3 ml.
The volume of the gas can be calculated by using the following formula: Volume = (mass / density)From the given information, the mass (m) of the gas is 2.00 g, and the density (d) is 1.29 g/L.So, Volume = (mass / density)= 2.00 g / 1.29 g/L = 1.55 LWe need to convert the volume to milliliters because the options are given in milliliters.1 L = 1000 mLTherefore, 1.55 L = 1.55 x 1000 mL = 1,550 mLThus, the volume in milliliters that 2.00 g of air will occupy if the density is 1.29 g/l is 1.55 x 10^3 ml.
Air is a mixture of different gases that mainly consists of 78% nitrogen, 21% oxygen, and 1% other gases such as argon, carbon dioxide, neon, helium, and hydrogen. The density of air is approximately 1.29 g/L at standard temperature and pressure (STP), which is defined as 0°C (273.15 K) and 1 atm (101.325 kPa) of pressure. This means that the mass of 1 L of air is 1.29 g.The volume of the gas can be calculated by using the following formula: Volume = (mass / density)From the given information, the mass (m) of the gas is 2.00 g, and the density (d) is 1.29 g/L.So, Volume = (mass / density)= 2.00 g / 1.29 g/L = 1.55 LWe need to convert the volume to milliliters because the options are given in milliliters.1 L = 1000 mLTherefore, 1.55 L = 1.55 x 1000 mL = 1,550 mLThus, the volume in milliliters that 2.00 g of air will occupy if the density is 1.29 g/l is 1.55 x 10^3 ml.
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A car of mass 800 kg is moving at a uniform velocity of 72 km/hr. Find its
momentum.
[Ans: 16000 kgm/s)
A body of mass 5 kg has momentum of 125 kg m/s. Find the velocity of the body
in motion.
[Ans: 25 mls)
Answer:
hope its helpful to uh...
On his fishing trip Justin takes the boat 12 km south. The fish aren't biting so he goes 4 km North. He follows a school of fish 1 km further north.
What distance did he cover? What was his displacement?
I give Brainliest!
Answer:
Distance: 17 km
Displacement: 7 km
Explanation:
The distance is the total measure of how much he moved.
The displacement is the straight line between the star point and the end point
action and reaction are equal in magnitudeand opposite in direction then why do they not balance each other ?
Because they act on different objects.
Please help!!
If you move 3 meters East and move 4 meters north what is the distance and what is the displacement?
Answer:
Explanation:
The distance will be the total distannce covered during the journey.
If you move 3 meters East and move 4 meters north, then the distance will be calculated as;
Distance = distnace through East+distance through north
Distance = 3m + 4m
Distance = 7m
Displacement is the distance covered in a specified direction. It is the shortest distance covered by me. This can be gotten using the Pythagoras theorem.
d² = 3²+4²
d² = 9+16
d² = 25
d = √25
d = 5m
Hence the displacement of the object is 5metres
3. What is a consideration when forcing interior walls?
A.
C.
D.
The wall coverings often hide interior metal framing.
The walls may be load-bearing and affect structural integrity.
Power tools must be used since all interior walls are reinforced.
Forcing the wall will require firefighters to work in a team of two.
Power tools must be used since all interior walls are reinforced is a consideration when forcing interior walls.
The correct option is C.
What does a load-bearing?The load of the floor or roof construction above them is supported by load-bearing walls, also referred to as "bearing walls." They are made to transfer weight from the roof to the foundation by passing through the flooring. A bearing wall, also known as a load-bearing barrier or a structural wall, supports the entire weight of the home. This wall assists in distributing the weight of the building from the roof to the base, and its loss could lead to the building collapsing.
How is a load-bearing determined?Tom proposes going up to the attic or basement to check which direction the joists run to see if a wall is load-bearing. The wall is still most likely not load-bearing if it runs parallel to the joists.
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The complete question is -
What is a consideration when forcing interior walls?
A-The wall coverings often hide interior metal framing.
B-The walls may be load-bearing and affect structural integrity.
C-Power tools must be used since all interior walls are reinforced.
D-Forcing the wall will require firefighters to work in a team of two.
what is one way that astronomers have actually gotten an idea of the age of the surfaces of terrestrial planets other than the earth? group of answer choices bringing back samples and run radioactive dating tests measuring the thickness of the atmosphere above each surface counting craters looking at the colors different surfaces show
The suitable method to determine the age of the surface of terrestrial planets is the crater counting. Because, as the age of the planet increases, its crater count also increases.
What is crater counting?Crater counting a proper method to estimate the age of a planet's surface. Based on this method an assumption is made that the a piece of new planetary surface doesn't have impact craters.
The rate of accumulation of impact craters increases with the age of the planetary surface. Counting the number craters per given area helps to determine how long they have created there and thus, how long the surface has formed.
Dating of samples with radioactive isotopes is used find the age of rocks. Similarly measuring atmospheric thickness and color analysis does not give an idea about the age of the surface of planets. Hence, option c is correct.
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Pls I need help
Boom pah pah
Four balls are mounted on a low-mass rod of length 0.52 m. Two balls (shown in red on the diagram), each of mass 0.66 kg, are mounted at opposite ends of the rod. Two other balls, each of mass 0.38 kg (shown in blue on the diagram), are each mounted at a distance of 0.13 m from the center of the rod. The rod rotates on an axle through the center of the rod (indicated by the "x" in the diagram), perpendicular to the rod, and it takes 1.0 seconds to make one full rotation. (a) Calculate the moment of inertia of the device about its center. I = ? (b) Calculate the angular speed of the rotating device. w = ? (c) Calculate the magnitude of the angular momentum of the rotating device.
(a) The moment of inertia of the device about its center is approximately 0.279 \(kg\cdot m^2\).
(b) The angular speed of the rotating device is approximately \(\omega=6.28 \frac{rad}{s}\).
(c) The magnitude of the angular momentum of the rotating device is approximately 1.75 \(\frac{kg\cdot m^2}{s}\)
(a) To calculate the moment of inertia of the device about its center, we need to consider the contributions from each component. The moment of inertia of a point mass rotating about an axis is given by the formula:
The moment of inertia of the device about its center is given by the sum of the individual contributions:
\(\[I = I_{\text{{red}}} + I_{\text{{blue}}} + I_{\text{{rod}}}\]\)
For the red balls at the ends of the rod:
\(\[I_{\text{{red}}} = 2 \times (0.66 \, \text{{kg}}) \times (0.26 \, \text{{m}})^2\]\)
For the blue balls:
\(\[I_{\text{{blue}}} = 2 \times (0.38 \, \text{{kg}}) \times (0.13 \, \text{{m}})^2\]\)
The moment of inertia of the rod can be approximated as negligible compared to the masses of the balls.
I=0.279 \(kg\cdot m^2\)
(b) The angular speed of the rotating device can be calculated using the formula:
\(\[w = \frac{2\pi}{T}\]\)
where \(\(T\)\) is the time taken to make one full rotation. In this case, (T) is given as 1.0 second:
\(\[w = \frac{2\pi}{1.0 \, \text{{s}}}\]\)
\(\omega=6.28 \frac{rad}{s}\)
(c) The magnitude of the angular momentum of the rotating device can be calculated using the formula:\(\[L = I \times w\]\)
Substituting the calculated values of (I) and (w), we can find the angular momentum.
L= 1.75 \(\frac{kg\cdot m^2}{s}\)
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The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is
The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.
The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.
Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:
E/B = (NC^(-1))/(NA^(-1) m^(-1))
To simplify this expression, we can cancel out the common units in the numerator and denominator:
E/B = (N/C)/(N/(A m))
Now, let's simplify further by dividing the numerator and denominator:
E/B = (N/C) * (A m/N)
Canceling out the common units:
E/B = (A m)/(C)
Therefore, the unit of E/B is A m/C (ampere meter per coulomb).
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a cruise ship travels directly toward the dock with a velocity of 15 m/s relative to the water. A passenger walks 3 m/s in the same direction as shown in the picture below
Answer:
Explanation:
i believe a if not c
A 795 kg car starts from rest and travels 41 m/s in 3 s.
a) what is the acceleration of the car?
b) how much force did the car engine provide?
The car engine provide force , F = 7242 N. if A 795 kg car starts from rest and travels 41 m in 3.0 s.
What is the definition of a force?In Physics, force is defined as: The push or pull on an object with mass causes it to change its velocity. Force is an external agent capable of changing a body's state of rest or motion. It has a magnitude and a direction.
What is a force in science?In science, the word 'force' has a precise meaning. At this level, it is completely appropriate to describe a force as a push or a pull. A force is not something that an object contains or 'has in it'.
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how does a battery work ?
Answer:
I completely agree with the first person's response.
Explanation:
They deserve Brainliest. Have a great summer.
If a Ferrari, with an initial velocity of 14m/s, accelerates at a rate of 60 m/s^2 for 4 seconds, what will its final velocity be
Answer:
254 m/s
Explanation:
(Vf-Vi) = at
(Vf-14)= 60 (4)
Vf = 254 m/s
A projectile is fired horizontally from a gun that is 58.0 m above flat ground, emerging from the gun with a speed of 170 m/s. (a) How long does the projectile remain in the air
Answer:
t = 3.44 s
Explanation:
We are given;
Fired from rest, and so; u = 0 m/s
Final speed; v = 170 m/s
Height above flat ground; y_o = 58 m
Height at starting point; y = 0 m
Thus, from Newton's equation of motion, we have;
y - y_o = ut - ½gt²
(since it's motion is against gravity)
Plugging in the relevant values, we have;
0 - 58 = 0 - (½ × 9.8 × t²)
-58 = -4.9t²
t² = 58/4.9
t = √(58/4.9)
t = 3.44 s
To win the game, a place kicker met kick a
football from a point 35 m (38.276 yd) from
the goal, and the ball must clear the crombar,
which is 3.05 m high. When kicked, the ball
leaves the ground with a speed of 20 m/s at
an angle of 45.9 from the horizontal.
The acceleration of gravity is 9.8 m/s²
By how much vertical distance does the ball
clear the crowbar?
Answer in units of m.
Answer:
2.08 m (2 d.p.)
Explanation:
Constant Acceleration Equations (SUVAT)
\(\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}\)
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
-------------------------------------------------------------------------------------
When a body is projected through the air with initial speed (u), at an angle of θ to the horizontal, it will move along a curved path.
Therefore, trigonometry can be used to resolve the body's initial velocity into its vertical and horizontal components:
Horizontal component of u (x) = u cos θVertical component of u (y) = u sin θSince the projectile is modeled as moving only under the influence of gravity, the only acceleration the projectile will experience will be acceleration due to gravity.
If the ball is kicked at an initial velocity of 20 m/s from flat ground at an angle of 45.9° then:
Horizontal component of u = 20 cos 45.9°Vertical component of u = 20 sin 45.9° Resolving horizontallyThe horizontal component of velocity is constant, as there is no acceleration horizontally.
Resolving horizontally, taking → as positive:
\(s=35 \quad u=20 \cos 45.9^{\circ} \quad v = 20 \cos 45.9^{\circ} \quad a=0\)
\(\begin{aligned}\textsf{Using} \quad s&=\left(\dfrac{u+v}{2}\right)t\\\\35&=\left(\dfrac{20 \cos 45.9^{\circ}+20 \cos 45.9^{\circ}}{2}\right)t\\35&=(20 \cos 45.9^{\circ})t\\t&=\dfrac{35}{20 \cos 45.9^{\circ}}\\\implies t&=2.51468288...\; \sf s\end{aligned}\)
Therefore, the time is takes for the ball to reach the crossbar is 2.51 s.
Resolving verticallyAcceleration due to gravity = 9.8 ms⁻²
Resolving vertically, taking ↑ as positive:
\(u=20 \sin 45.9^{\circ} \quad a=-9.8 \quad t=2.51468288...\)
\(\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2\\\\s&=(20 \sin 45.9^{\circ})(2.51468288...)+\dfrac{1}{2}(-9.8)(2.51468288...)^2\\s&=36.1171982...-30.9857870...\\\implies s&=5.131411132...\; \sf m\end{aligned}\)
SolutionTo find by how much the ball clears the crossbar, subtract the height of the crossbar (3.05 m) from found the vertical height of the ball at 2.51 s:
\(\implies 5.13141132...-3.05=2.08\; \sf m\;(2 \: d.p.)\)
Therefore, the ball clears the crossbar by 2.08 m (2 d.p.).
LUZUJ ML)
Monique's family is moving to a town where surfing is a popular sport. She has never surfed but is excited to learn. Monique's father suggested
she practice her balance before attempting to surf. Which activity would best help Monique?
Answer:
b. Rollerblading.
Explanation:
Rollerblading involves balances.
A rocket with a mass of 4,235 needs to enter a lunar orbit. To do so, if needs to slow down by 498 m/s. If the engines can provide a force of 2,507, find how long (in seconds) they need to fire to achieve orbital insertion. Your answer should be a whole number.
The time needed to achieve the orbital insertion is 841.3 s.
What is the time needed to achieve orbital insertion?
The time needed to achieve orbital insertion is calculated by applying Newton's second law of motion as follows;
F = ma
where;
a is the acceleration of the rocketm is the mass of the rocketF = m(v/t)
where;
v is the velocity of the rockett is the time needed to achieve orbital insertiont = (mv)/F
t = (4235 x 498) / (2507)
t = 841.3 seconds
Thus, the time needed to achieve the orbital insertion is determined from Newton's second law of motion.
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When catching a baseball, the ball applies a force of 39.6 N to a catcher's glove. If the work done on the catchers glove is 47.5 J what is the recoil (travel of) on the mitt?
Answer:
d = 1.19 m
Explanation:
Given that,
The force applied by the ball, F = 39.6 N
The work done on the catchers glove is 47.5 J
We need to find the distance traveled by the ball. We know that,
Work done, W = Fd
Where
d is the distance traveled
\(d=\dfrac{W}{F}\\\\d=\dfrac{47.5 }{39.6 }\\\\d=1.19\ m\)
So, it will cover 1.19 m.
Hi I don’t understand question and can really use some help! :D
Given
Mass of one of the object is doubled and the distance between the object is doubled.
To find
What happens to the gravitational force
Explanation
The gravitational force is directly proportional to the masses and inversely proportional to the distance between them
Keeping all other parameters constant,
\(F\propto\frac{m}{d^2}\)So when the mass doubles and the distance doubles we have,
\(\begin{gathered} F^{\prime}\propto\frac{2m}{(2d)^2} \\ \Rightarrow F\propto\frac{m}{2d}=\frac{F}{2} \end{gathered}\)Conclusion
A. The gravitational force becomes half as great.
Which is an example of potential energy? a swimmer kicking their legs a car driving on the road an arrow flying at a target a yo-yo in someone’s hand
Answer:
The yo-yo :)
Explanation:
HELP PLZ ASAP!!!!!
Which of the following steps does not take place during cellular respiration?
a
Glucose is broken down.
b
Energy is transferred to cells.
c
Oxygen combines with carbon dioxide.
d
Energy and other products are released.
Answer:
C. Oxygen combines with carbon dioxide
Explanation:
B i o l o g y
Also, oxygen is a reactant and carbon dioxide is a product of cellular respiration that does not combine during this process
Hope it helps
Help me please Which of the following statements best describes the atoms and molecules that make up a glass
filled with water?
O The atoms and molecules of the liquid water are moving, while the atoms and molecules of the glass are not
moving.
The atoms and molecules of neither the liquid water nor the glass are moving.
O The atoms and molecules of the liquid water are not moving, while the atoms and molecules of the glass are
moving.
The atoms and molecules of both the liquid water and the glass are moving.
Answer:
The correct option is;
The atoms and molecules of the liquid water are moving, while the atoms and molecules of the glass are not moving
Explanation:
Matter that exist in the liquid or gaseous state consist of molecules that move freely about in the entire containing medium for gas, while the molecules move freely in the portion of the container occupied by the fluid in the case of liquid fluids
However, the molecules of a solid are fixed within the current shape of the solid and are only free to vibrate within a fixed location and the allow the passage of subatomic particles such as electrons
As such, the glass cup being a solid, consists of molecules fixed in space, while the liquid water consists of molecules which can translate within the portion of the volume of the glass filled with the water.
I need to solve for mass
The mass of the given will be 20kg.
Equation :By using formula,
force = mass x acceleration
mass = force / acceleration
mass = 400 N / 20m/s²
mass = 20 Kg
Acceleration :Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.
Any process where the velocity changes is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because the velocity is both a speed and a direction.
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The terrestrial worlds that may still be geologically active
are:
Choose one:
A. Earth, Venus, and Mercury.
B. Earth, the Moon, and Mercury.
C. Earth and Venus only.
D. Earth only.
The terrestrial worlds that may still be geologically active are Earth and Venus only.
Earth and Venus are the two terrestrial worlds in our solar system that exhibit evidence of ongoing geological activity. Earth is well-known for its active tectonic plate movements, volcanic eruptions, and seismic activity. These processes are driven by the internal heat generated through radioactive decay and convection in the mantle.
Venus, despite its harsh conditions, shows signs of recent volcanic activity and potential tectonic movements. It has lava flows, volcanic domes, and evidence of resurfacing. However, the Moon and Mercury are considered geologically inactive.
The Moon lacks significant volcanic and tectonic processes due to its smaller size and cooling interior, while Mercury's internal activity has mostly ceased, leaving it relatively inactive.
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i) ii) iii) 12 V What is the total resistance of the circuit? 1+1 30+20. - A 26 30 600 What is the current reading of the ammeter? 600=12 What is the power of the 30 ohm resistor? 144 = 48 30 P = √² 12² - 144 R 30 iv) Explain what is meant by the term e.m.f of the battery. 20. Ω > 30. Ω
The answer for (iv) is;
E.M.F of the battery refers to the chemical energy in the battery that is being converted into electrical energy for the flow of electrons to carry current in a circuit.
Match the phrase with word please help!
Phrases:
1.) The amount of work done when jerry carries a box from his house to the moving truck . He exerts a force of 35 N while carrying the box 4 meters
2.) The power resulting from 420 Nm of work being completed in 3 seconds
3.) The amount of work done when Fido carries his toy from the backyard to his crate. He exerts a force of 1.2 N over a distance of 15 m
4.) The power resulting from 120 Nm of work being completed in 20 seconds
A.) 140 joules
B.) 140 Newton-meters
C.) 6 joules
D.) 6 Newton-meters
Answer:
1-B, 2-A, 3-D, 4-C
Explanation:
1. The force exerted is, F = 35 N
Distance the box is moved, d = 4 m
So the amount of work done is, W = F x d
= 35 x 4
= 140 Newton-meters
2. Work done, W = 420 Nm
Time, T = 3 seconds
Therefore, the power required is,
\($P=\frac{W}{T}$\)
\($P=\frac{420}{3}$\)
= 140 joules
3. The force exerted is, F = 1.2 N
Distance the box is moved, d = 5 m
So the amount of work done is, W = F x d
= 1.2 x 5
= 6 Newton-meters
4. Work done, W = 120 Nm
Time, T = 20 seconds
Therefore, the power required is,
\($P=\frac{W}{T}$\)
\($P=\frac{120}{20}$\)
= 6 joules
simple machines are in a mousetrap
Answer:
A mousetrap makes use of a simple machine called a lever.
Explanation:
In a second-class lever the effort force is at the other end, with the load in the middle. In a third-class lever, the load is at the end and the effort force is between the fulcrum and the load. When you set the mousetrap, you are using a second-class lever. Sorry if I get this wrong. I am in 5th grade! ♥
An ideal gas initially at 300 K undergoes an isobaric expansion at 2.50 kPa. If the volume increases from 1.00 m3 to 3.00 m3 and 12.5 kJ is transferred to the gas by heat, what are a. the change in its internal energy and b. its final temperature?
Answer:
a) \( \Delta U = 7.5 kJ \)
b) \(T_{f} = 900 K \)
Explanation:
a) To find the change in its internal energy (U) we need to use the following equation:
\( \Delta U = W + Q \)
Where:
W: is the work done on the system
Q: is the energy transferred into the system by heat = 12.5 kJ
Since we have an isobaric expansion, the work is:
\( W = - P\Delta V = - P(V_{f} - V_{i}) \)
Where:
\(V_{f}\): is the final volume = 3.00 m³
\(V_{i}\): is the initial volume = 1.00 m³
P: is the pressure = 2.50 kPa
\( W = -P(V_{f} - V_{i}) = -2.5 \cdot 10^{3} Pa(3.00 m^{3} - 1.00 m^{3}) = -5.00 \cdot 10^{3} J \)
Now, we can find the change in its internal energy:
\( \Delta U = W + Q = -5.00 \cdot 10^{3} J + 12.5 \cdot 10^{3} J = 7.5 \cdot 10^{3} J \)
b) The final temperature can be found as follows:
\( \frac{V_{i}}{V_{f}} = \frac{T_{i}}{T_{f}} \)
\( T_{f} = \frac{T_{i}*V_{f}}{V_{i}} = \frac{300 K*3.00 m^{3}}{1.00 m^{3}} = 900 K \)
Hence, the final temperature is 900 K.
I hope it helps you!
A chemical reaction is the only way to an
A: Element
B: Pure Substance
C: Mixture
D: Solution
Answer:
B: Pure Substance
Explanation: